What ensures the correct phasing of the steering column U-joints when being reassembled after servicing?
Select one:
O a. Marking steering wheel position
O b. Numbering the U-joints
O c. Match marking the steering shafts
O d. Marking miter box position

Answers

Answer 1

The process of phasing involves parallel alignment of the universal joint yokes on the drive shaft's two ends (also known as the double u-joint). Unless the joints are...

What do you call a double u-joint?

A double universal joint with a length-adjustable middle part is a telescopic drive shaft. commonly known by the names driving shaft or cardan shaft. There are two varieties of U-joints: ball and trunnion and cross and roller types. Most often utilized, the cross and roller design allows the driving shaft to bend. The drive shaft can flex and can move both backwards and forwards with the ball and trunnion type, which is less usually utilized. With two joints at one end (usually the transfer case) and one joint at the other, certain drivelines use a "double cardan," or constant velocity (CV). As a result of the two joints splitting the angle, more

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Related Questions

Question 1 Conduct a risk assessment for the following tasks performed on ships: - Cleaning liquid cargo spilled from a container carrying dangerous goods (Class 5). - Entering confined space to rescue an injured crew member (sprained ankle). The students should: i) Identify all associated risks ii) Classify the risks under the following risk estimation framework: iii) Develop strategies to mitigate the identified risks. No word limit. [20 Marks]

Answers

Identify risks: Cleaning hazardous liquid spills (medium likelihood, major severity), confined space rescue (high likelihood, moderate severity). Mitigate risks with PPE, training, protocols, and proper ventilation.

Step 1: Identify all associated risks:

a) Cleaning liquid cargo spilled from a container carrying dangerous goods (Class 5):

- Exposure to hazardous chemicals or substances in the spilled cargo.

- Risk of chemical burns or respiratory problems due to inhalation or contact with the dangerous goods.

- Slippery surfaces leading to falls and injuries.

- Fire or explosion risks if the spilled cargo is flammable or reactive.

b) Entering confined space to rescue an injured crew member (sprained ankle):

- Lack of oxygen or presence of toxic gases in the confined space.

- Risk of physical injuries due to confined space hazards such as uneven surfaces, low visibility, or falling objects.

- Difficulty in accessing and rescuing the crew member due to limited space.

Step 2: Classify the risks under the risk estimation framework:

The risk estimation framework can vary, but a commonly used approach is to assess risks based on their likelihood and severity. For each identified risk, assign a rating for likelihood (e.g., low, medium, high) and severity (e.g., minor, moderate, major).

Example:

- Cleaning liquid cargo spilled from a container carrying dangerous goods:

 - Likelihood: Medium

 - Severity: Major

- Entering confined space to rescue an injured crew member:

 - Likelihood: High

 - Severity: Moderate

Step 3: Develop strategies to mitigate the identified risks:

a) Cleaning liquid cargo spilled from a container carrying dangerous goods:

- Provide appropriate personal protective equipment (PPE) to workers involved in the cleanup.

- Train workers on proper handling and disposal procedures for hazardous materials.

- Implement spill containment measures and cleanup protocols.

- Conduct regular inspections and maintenance of containers to minimize the risk of spills.

b) Entering confined space to rescue an injured crew member:

- Assess the confined space for hazardous conditions and ensure proper ventilation before entry.

- Use a buddy system and have a standby person outside the confined space for communication and assistance.

- Equip the rescue team with appropriate PPE, including gas detectors, harnesses, and rescue equipment.

- Establish emergency response procedures and provide training to crew members on confined space rescue techniques.

It is important to note that risk assessment should be conducted by qualified professionals who have expertise in ship operations and safety regulations. The strategies mentioned above are general recommendations and may need to be tailored based on specific ship and task requirements. Regular reviews and updates of risk assessments should be conducted to ensure ongoing safety and compliance.


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Tech A says that air tools and equipment require a regular application of a lubricating oil to reduce wear and tear. Tech B says that some compressed air systems use an inline water trap that needs to be drained periodically. Who is correct?

Answers

Incomplete question. The options read;

A. Tech A

B. Tech B

C. Both A and B

D. Neither A nor B.

Answer:

C. Both A and B

Explanation:

Technician B is correct because the technician highlighted valid reasons why draining the compressed air systems is important.

For example, since this system helps to absorb moisture or oil from storage areas they thus need to be drained periodically in other to allow for more absorption space.

Also, the reasons mentioned by Technician A are of course correct because it is generally believed that the application of lubricants such as oil helps to reduce wear and tear.

In low speed subsonic wind tunnels, the value of test section velocity can be controlled by adjusting the pressure difference between the inlet and test-section for a fixed ratio of inlet-to-test section cross-sectional area.
a. True
b. false

Answers

Answer:

Hence the given statement is false.

Explanation:

For low-speed subsonic wind tunnels, the air density remains nearly constant decreasing the cross-section area cause the flow to extend velocity, and reduce pressure. Similarly increasing the world cause to decrease and therefore the pressure to extend.

The speed within the test section is decided by the planning of the tunnel.  

Thus by adjusting the pressure difference won't change the worth of test section velocity.

Answer:

The given statement is false .

If a digital multimeter displays 000 when reading amperage, what should the technician do to get a more accurate reading

Answers

Answer:

Use a non digital multimeter.

Explanation:

If a digital multimeter displays "000" when reading amperage, the technician should adjust the multimeter to a higher amperage range.

Why should the technician do this?

This is because "000" typically indicates that the current being measured is too low for the current range selected on the multimeter.

By switching to a higher amperage range, the technician can get a more accurate reading and ensure that the multimeter is properly measuring the current in the circuit under test.

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to do you blur text in google docs

Answers

Answer:

I dont think you can blur text in google docs

A DC servomotor has a torque constant of 0.075 N-m/A and a voltage constant of 0.12 V/(rad/sec). The armature resistance is 2.5 Ohm. A terminal voltage of 24 V is used to operate the motor. Determine:
a) the starting torque generated by the motor just as the voltage is applied.
b) the maximum speed at a torque of zero.
c) the operating point of the motor when it is connected to a load whose torque characteristic is proportional to speed with a constant of proportionality = 0.0125 N-m/(rad/sec).

Answers

Answer:

The answer is below

Explanation:

Given that:

\(k_t=torque\ constant=0.075\ Nm/A\\\\k_v=voltage\ constant=0.12\ V/(rad/sec)\\\\R_a=armature \ resistance=2.5 \Omega\\\\V_t=terminal\ voltage=24\ V\\\\a)The \ starting\ current\ I_a\ is\ given \ as:\\\\I_a=\frac{V_t}{R_a} =\frac{24}{2.5} =9.6\ A\\\\The \ starting\ torque(T)\ is:\\\\T=k_tI_a=0.075*9.6=0.72\ N.m\)

b) The maximum speed occurs when the terminal voltage and back emf are equal to each other i.e.

\(V_t=e_b=k_v\omega\\\\\omega=\frac{V_t}{k_v}=\frac{24}{0.12} =200\ rad/s\)

c) The load torque is given as:

\(T_L=0.0125\Omega\\\\The\ motor\ torque \ is:\\\\T=k_t(\frac{V_t-k_v\omega}{R_a} )\\\\but\ T = T_L,hence:\\\\0.0125\omega=0.075(\frac{24-0.12\omega}{2.5} )\\\\0.03125\omega=1.8-0.009\omega\\\\0.04025\omega=1.8\\\\\omega=44.72\ rad/sec\\\\N=\frac{60\omega}{2\pi} =\frac{60*44.72}{2\pi} =427\ rpm\)

Two circular rods support the 3800 lb weight of a space heater in a warehouse. Each rod has a diameter of 0. 375 in and carries 1/2 of the total load. Compute the stress in the rods

Answers

Answer:

Force carried by each rod, F = 3800 / 2 = 1900 lb

Cross-sectional area of each rod,  A = pi ( d^2) / 4

A = pi * 0.375 * 0.375 / 4 = 0.1104 in^2

Stress in each rod = F / A = 1900 / 0.1104

= 17.21 * 1000 psi

= 17.21 ksi

Explanation:

help

When diagnosing a vehicle, when does the customer concern need to be verified before making repairs to the vehicle?

Answers

With a professional, do an automotive diagnostic

Verification and confirmation in

Step 1. This step in the vehicle diagnostic process enables the expert to look for potential issues.

Step 2: Identify the issue.

Step 3: Area isolation.

4. Make repairs.

The final step is a check.

Diagonosis: What is it?

the procedure of determining a diagnosis, disease, or injury based on its indications and symptoms. To aid in the diagnosis, testing like blood tests, imaging tests, and biopsies may be done in addition to a physical examination and health history.

Using a computer scan tool, the repairman will obtain the diagnostic issue code data from the computer. A fully qualified technician can more correctly identify and address the issue by using this information.

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Using a computer scan tool, the repair technician will retrieve the diagnostic trouble code information from the computer. A properly trained technician can use this information to more accurately locate and repair the problem.

What is the vehicle diagnosis process ?

As part of the standard operating procedure, many experts recommend that shops perform a pre-scan of all vehicle computer modules, as well as a scan after the vehicle is repaired (SOP). This is not only good business practice, but it also helps to communicate with the customer about potential vehicle flaws that may not have been part of the customer's original concern.

Pre-scan: This entails gaining access to all vehicle modules and downloading any or all stored Diagnostic Trouble Codes (DTCs), including pending codes. Any DTCs that have been stored will be recorded on the work order, and if they are related to a customer, it may be necessary to notify the customer and obtain approval before proceeding with the repair.

Post Scan: After the vehicle has been repaired and before it is released to the customer, a full module scan is performed to ensure that another DTC was not set during the repair in addition to the repair. procedure for repair The results of this follow-up scan should also be documented on the repair order so that they can be added to the driving history.

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time complexity of merge sort

Answers

Answer:

The correct answer is "\(O (n\times Log n)\)". A further explanation is given below.

Explanation:

Throughout all the three instances (worst, average as well as best), the time complexity including its Merge sort seems to be \(O (n\times Log n)\) as the merge form often splits the array into two halves together tends to linear time to combine multiple halves. As an unsorted array, it needs an equivalent amount of unnecessary capacity. Therefore, large unsorted arrays are not appropriate for having to search.

Define water hammer. Give four effects of water hammer.​

Answers

Answer:

Water Hammer is a knocking sound in an water pipe which occurs when the tap is turned off briskly

Explanation:

in an aircraft with a 12-volt electrical system, what would a voltmeter reading of 12.4 volts indicate about the system if the reading was increasing slowly? decreasing slowly?

Answers

In an airplane with a 12-volt electrical system, a voltmeter reading of 12.4 volts indicates that the battery is completely charged and the electrical system is operational.

If the voltmeter reading steadily increases, it might mean that the alternator or generator is operating and charging the battery. The gradual increase in voltage might indicate that the alternator is not supplying enough current to properly charge the battery or that there is some resistance in the electrical system.

If, on the other hand, the voltmeter reading gradually decreases, it may indicate that the battery is draining or that there is an issue with the alternator or generator. A steadily falling voltage measurement might be the result of a malfunctioning regulator, a bad battery, or excessive power consumption in the electrical system.

It is essential to monitor the voltmeter readings regularly during the flight to ensure that the electrical system is functioning correctly. Any significant changes in the voltage readings should be investigated immediately to prevent any potential safety hazards.

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Why is OM considered an internal function? How is OM an integral
part of SCM?
Please provide three examples

Answers

OM is considered an internal function because it focuses on managing internal operations within an organization. It is integral to supply chain management (SCM) as it ensures efficient coordination of activities and resources across the supply chain.

Operations Management (OM) is considered an internal function because it primarily deals with managing the internal processes and activities of an organization. It involves planning, organizing, and controlling the production and delivery of goods and services. OM focuses on optimizing resources, improving productivity, and enhancing quality within the organization. It encompasses various areas such as capacity planning, inventory management, production scheduling, and quality control, among others.

OM is an integral part of Supply Chain Management (SCM) because it plays a crucial role in coordinating and synchronizing activities across the entire supply chain. SCM involves the flow of materials, information, and funds from suppliers to manufacturers, distributors, retailers, and ultimately, to customers. Effective OM ensures that the operations within each stage of the supply chain are well-managed, ensuring smooth and efficient flow of products and services. For example:

1. Capacity Planning: OM helps in determining the capacity requirements at each stage of the supply chain. It ensures that the production capacity aligns with demand forecasts, preventing overstocking or understocking of products.

2. Inventory Management: OM enables efficient inventory management practices, including determining optimal inventory levels, implementing just-in-time (JIT) techniques, and reducing stockouts or excess inventory. This synchronization helps maintain a streamlined supply chain.

3. Quality Control: OM ensures that quality standards are established and maintained throughout the supply chain. By implementing quality control measures at each stage, from sourcing raw materials to delivering finished goods, it ensures customer satisfaction and reduces the risk of disruptions in the supply chain due to quality issues.

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Raven is adding FSMO roles to domain controllers in the domain1.com forest. The forest contains a single domain and three domain controllers, DC1, DC2, and DC3. DC1 contains a copy of the global catalog, and all three domain controllers have the latest version of Windows Server 2019 installed. Which of the following is a best practice that Raven should follow? She should use DC2 or DC3 as the Domain Naming Master. B She should create the Domain Naming Master role on DC1. She should create three Domain Naming Master roles, one for each domain controller. She does not need to create the Domain Master role because DC1 contains a copy of the global catalog.

Answers

The best practice that Raven should follow is to use DC2 or DC3 as the Domain Naming Master of the following is a best practice that Raven should follow. The correct option is A.

The management of the addition or deletion of domains from the forest is the responsibility of the Domain Naming Master. For redundancy and fault tolerance, it is advised to split the FSMO roles among several domain controllers.

Since DC1 already has a copy of the global catalog, it is advantageous to choose a different domain controller (DC2 or DC3) as the Domain Naming Master to disperse the workload and guarantee high availability. This ensures that the forest's operations may continue even if one domain controller goes offline and prevents the creation of a single point of failure.

Thus, the ideal selection is option A.

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A bar of mild steel has a diameter of 75 mm and is placed inside a hollow aluminum cylinder ofinternal diameter 75 mmand external diameter 100 mm; both bar and cylinder are the same length. Theresulting composite bar is subjected to an axial compressive load of 1000 kN. If the bar and cylindercontract by the same amount, calculate the stress in each. The temperature of the compressed compositebar is then reduced by 150Cbut no change in length is permitted. Calculate the final stress in the bar and the cylinder if E(steel)= 200,000 N/mm^2, E(aluminum)= 80,000 N/mm^2, coefficient of linear expansion for steel= 0. 0000012/C and coefficient of linear expansion for aluminum= 0. 000005/C

Answers

According to the question: the Stress in cylinder is 1813 N/mm^2.

What is cylinder?

A cylinder is a three-dimensional geometric shape with two circular bases, one at each end, connected by a curved surface. The curved surface is a straight line connecting the two circular bases and is called the side or lateral surface. The two circular surfaces that make up the cylinder are called the bases.

The initial stress in the bar and cylinder can be calculated using the following equation:
Stress = Load / (Area of bar x Area of cylinder)
Stress in bar = 1000 kN / (π*(75/2)^2 * π*(75/2)^2) = 2300 N/mm^2
Stress in cylinder = 1000 kN / (π*(75/2)^2 * π*(100/2)^2) = 1875 N/mm^2
The final stress in the bar and cylinder can be calculated using the following equation:
Stress = (Load + Change in Length * Modulus of Elasticity * Coefficient of Linear Expansion * Change in Temperature) / (Area of bar* Area of cylinder)
Stress in bar = (1000 kN + (75 mm * 200000 N/mm^2 * 0.0000012/C * -150C)) / (π*(75/2)^2 * π*(75/2)^2) = 2250 N/mm^2
Stress in cylinder = (1000 kN + (75 mm * 80000 N/mm^2 * 0.000005/C * -150C)) / (π*(75/2)^2 * π*(100/2)^2) = 1813 N/mm^2

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some connecting rods have ____ to help lubricate the cylinder wall or piston pin.

Answers

Answer:

some connecting rods have spit holes

Some connecting rods have crankshaft to help lubricate the cylinder wall or piston pin.

What are crankshaft?

A crankshaft is a mechanical component that converts reciprocating motion in a piston engine into rotational motion.

The crankshaft is a rotating shaft with one or more crankpins that drive the pistons via the connecting rods.

Reduced fuel economy is one issue you'll face if your car's crankshaft isn't working properly. The reason for this is that your vehicle's fuel injectors will not efficiently direct gas to the engine.

The connecting rods' big ends are lubricated with oil that travels up an oilway drilled through the crankshaft.

From the main bearings to the big end bearings, oil is pushed. It will lubricate the cylinder walls in some engines by passing through a passage drilled in the connecting rod.

Thus, the answer is crankshaft.

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PLEASE HURRY!!!!
Which of the following can be inferred about Bill in the following scenario?

Bill has graduated and obtained a job as a geographer. He develops environmental models to analyze soil and water issues for a chemical company.

A) Bill studied environmental geography.
B) Bill earned a bachelor’s degree.
C) Bill earned a graduate degree.
D) Bill earned a certification in GIS technology.

Answers

I want to say your answer is C) Bill earned a graduate degree. I am so sorry if it is wrong! Hope this answer helps though! HAVE A GREAT REST OF YOUR DAY!!

A TCP sender is sending a full window of 216 Bytes over a 1 Gbps channel that has a 20msec round trip time. a. The link utilization is ____ 2.6 ____% b. The maximum throughput is_____ 3276800 ____Bytes/sec

Answers

The link utilization is  2.6% b. The maximum throughput is 3276800 Bytes/sec

How do I calculate network link utilization?On Windows, it is calculated by multiplying the outcome by 400 after dividing the Network Interface(*)Bytes/sec performance counter by the Current Bandwidth. These calculations are required to convert between bits and bytes and to account for full duplex.A corporation can achieve revenue maximisation after throughput is maximised by eliminating inefficiencies, allowing inputs and outputs to flow in the most appropriate way. Throughput and a company's production capacity are closely tied, and management might make various assumptions about capacity.

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When choosing a respirator for your job, you must conduct a
test.

Answers

Answer: A fit test. Either qualitative or quantitative.
You could use a fit test.


I hope this helps.

The proposed grading at a project site will consist of 25,100 m3 of cut and 23,300 m3 of fill and will be a balanced earthwork job. The cut area has an average moisture content of 8.3%. The fill will be compacted to an average relative compaction of 93% based on a maximum dry unit weight of 18.3 kN/m3 and an optimum moisture content of 12.9% obtained from the modified Proctor test. Compute the volume of water in kiloliters that will be required to bring these soils to the optimum moisture content.

Answers

We can use the formula for the moisture content of soil to solve for the volume of water required:

M = ((Ww / Ws) x 100)%

where M is the moisture content, Ww is the weight of water, and Ws is the weight of solids.

First, let's find the weight of solids for the cut area:

Ws = V x γ

where V is the volume and γ is the unit weight.

Ws = 25,100 m3 x 1.8 t/m3 x 1000 kg/t

Ws = 45,180,000 kg

Next, let's find the weight of solids for the fill area:

Ws = V x γ

where V is the volume and γ is the unit weight.

Ws = 23,300 m3 x 18.3 kN/m3 x 1000 N/kN

Ws = 425,190,000 N

Now, let's find the weight of water required for the cut area:

M = ((Ww / Ws) x 100)%

0.129 = ((Ww / 45,180,000) x 100)%

Ww = 58,402 kg

Finally, let's find the weight of water required for the fill area:

M = ((Ww / Ws) x 100)%

0.129 = ((Ww / 425,190,000) x 100)%

Ww = 548,991 kg

To find the total volume of water required, we need to convert the weight of water to volume using the density of water:

ρ = 1000 kg/m3

For the cut area:

Vw = Ww / ρ

Vw = 58,402 kg / 1000 kg/m3

Vw = 58.4 m3

For the fill area:

Vw = Ww / ρ

Vw = 548,991 kg / 1000 kg/m3

Vw = 548.991 m3

Therefore, the total volume of water required to bring the soils to the optimum moisture content is approximately 607.4 m3 or 607.4 kiloliters.

An insulated vertical cylinder Contains 0.1 kg Argon gas with the help of a frictionless non- conducting piston as shown in the figure . The mass of the piston is 5kg and initially rest on the bottom of the cylinder. The cylinder connected to nitrogen tank at 100 bar to a pipeline fitted with the valve The valve is opened and nitrogen slowly enters the cylinder. During this process the piston is lifted and to height of 10cm by Nitrogen gas. The initial pressure and temperature of argon are 300K and 1 bar. The final temperature of argon gas is 320K for argon R = 0.208 kJ/kgK and r = 1.67 Find the net work done by the Nitrogen

Answers

The net work done by the Nitrogen in lifting the mass and the pressure is; W_n = 0.6257 kJ

What is the net work done?

We are given;

Mass of argon; m_a = 0.1 kg

mass of piston; m_p = 5 kg

Pressure 1; p₁ = 100 kPa

Temperature 1; T₁ = 300 K

Temperature 2; T₂ = 320 K

Ideal gas constant; R = 0.208 kJ/kg.K

γ = 1.67

Since the reaction is adiabatic and slowly reversible, then we will use the formula; PV^(γ) = C

Thus, work done by argon is;

W_ar = [m_a * R(T₁ - T₂)]/(γ - 1)

W_ar = [0.1 * 0.208(300 - 320)]/(1.67 - 1)

W_ar = -0.6028 kJ

Work done by nitrogen will be;

W_n = |W_ar| + (m_p * g * m_a)/1000

W_n = 0.6028 + (5 * 9.81 * 0.1)/1000

W_n = 0.6257 kJ

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During one eight-hour shift, 750 non-defective parts are desired from a fabrication operation. The standard time for the operation is 15 minutes. Because the machine operators are unskilled, the actual time it takes to perform the operation is 20 minutes, and ,on average, one-fifth of the parts that begin fabrication are scrapped. Assuming that each of the machines used for this operation will not be available for one hour of each shift, determine the number of machines required.

Answers

Answer:

No. of Machines Required = 47

Explanation:

First, we calculate the number of parts that can be manufactured by one machine during the shift. For that purpose, we use following formula:

No. of Parts Manufactured by 1 Machine = Total Operating Time/Time taken to perform Operation

where,

Total Operating Time = 8 h - 1 h = (7 h)(60 min/h) = 420 min

Time taken to perform operation = 20 min

Therefore,

No. of Parts Manufactured by 1 Machine = 420 min/20 min

No. of Parts Manufactured by 1 Machine = 21

Now, we will calculate the no. of non-defective parts manufactured by 1 machine. Since, it is given that one-fifth of the parts manufactured by machine are defective. Therefore, the non-defective parts will be: 1 - 1/5 = 4/5 (four-fifth).

No. of Non- Defective Parts Manufactured by 1 Machine = N = (4/5)(21)

N = 16.8 = 16 (Since, the 17th part will not be able to complete in time)

So, the no. of machines required to produce 750 non-defective parts is given by:

No. of Machines Required = No. of non-defective parts required/N

No. of Machines Required = 750/16

No. of Machines Required = 46.9

No. of Machines Required = 47 (Since, 46 machines will not be able complete the job)

A river has an average rate of water flow of 59.6 M3/s. This river has three tributaries, tributary A, B and C, which account for 36%, 47% and 17% of water flow respectively. How much water is discharged in 30 minutes from tributary B?

Answers

Answer:

50421.6 m³

Explanation:

The river has an average rate of water flow of 59.6 m³/s.

Tributary B accounts for 47% of the rate of water flow. Therefore the rate of water flow through tributary B is:

Flow rate of water through tributary B = 47% of 59.6 m³/s = 0.47 * 59.6 m³/s = 28.012 m³/s

The volume of water that has been discharged through tributary B = Flow rate of water through tributary B * time taken

time = 30 minutes = 30 minutes * 60 seconds / minute = 1800 seconds

The volume of water that has been discharged through tributary B in 30 seconds = 28.012 m³/s * 1800 seconds = 50421.6 m³

Using the relations that you have defined for the hospital software system, normalize your relations into first, second, and third normal form. First, you must describe the changes required to your relations to meet the standard of first 1NF and then 2NF and lastly 3NF. Then, you should provide an Entity Relationship diagram that is in 3NF. All attributes, entities, keys, and relationships should be included and labeled.
Hint: Remember that in the hospital software system, the "Patient" relation includes "medicines" attribute and the "Appointment" relation includes "allergies" attribute. Allergies describe a list of any known allergies and medicines describe a list of medicines prescribed for a patient.

Answers

Hospital software system entities: Doctor Patient Appointment

Into the first normal form (1NF) relations:

Multiple values cannot be present in the first Normal form; otherwise, it is violated.

Therefore, avoid the group of values and create a new table with related values.

Doctor, patient, and appointment information are the relations in the hospital administration system, without duplicate entries or repeated values.

Into the second normal form (2NF) relations:

The following To qualify, normal form must satisfy the initial normal form criterion.

The 1NF in the table doesn't need to have candidate-dependent key values.

The table is separated into sections to prevent prime qualities.

Ensure that Doctor, patient, and Appointment are in main key and that 2NF is in a partial dependency condition.

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which technique is used to locate profiles when xraying quora?

Answers

The technique used to locate profiles when x-raying Quora is called "OSINT" (Open Source Intelligence). OSINT is a method of gathering information from publicly available sources to obtain insights and intelligence about individuals, organizations, or other entities.

When x-raying Quora, OSINT techniques involve leveraging various search engines, social media platforms, and online directories to discover and analyze profiles associated with Quora users. This may include searching for specific keywords, usernames, or other identifying information related to the target profiles.

OSINT helps in locating profiles on Quora by utilizing the information shared by users publicly on the platform or on other websites that might be indexed by search engines. By employing advanced search operators and techniques, researchers can uncover hidden or non-obvious profiles, gather additional details about users, and potentially identify connections between individuals.

Overall, OSINT provides a valuable approach to locating profiles when x-raying Quora by leveraging publicly available information to gather insights and understand the online presence of individuals on the platform.

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distillation technologies

Answers

Advanced distillation technologies

2.1. Heat integrated distillation column (HIDC) ...

2.2. Membrane distillation (MD) ...

2.3. Cyclic distillation. ...

2.4. Cryogenic distillation. ...

2.5. Reactive distillation column.

Which of the following tasks might a civil engineer perform during a project’s construction phase in a design-build approach? (Select all that apply.)


Work with construction management to solve specific problems as they arise.

Draw up the contracts for construction management.

Ensure compliance with safety standards.

Provide information on design changes.

Answers

Answer:

Draw up the contract for construction management.

Answer:

Work with construction management to solve specific problems as they arise.

Ensure compliance with safety standards.

Explanation:

Write the distributeCurrentPlayerTokens method. The tokens are collected and removed from the game board at the current player's position. These tokens are distributed, one at a time, to each player, beginning with the next higher position, until there are no more tokens to distribute

Answers

The distribute Current Player Tokens method for the tokens are collected and removed from the game board at the current player's position is stated in code in Java below:

Why do we use public void?

The Java application's main method is created by using the keyword public static void main. The program's primary method, it is what all others are called. For difficult command-line processing, it accepts parameters but cannot return values. Both generate a void method (a method with no return value), but only the public void method is accessible to classes outside the one that created it. Only the class in which the private method is contained may utilise it. It is a keyword that is employed to indicate that a method returns nothing. The main() method's return type is void because it doesn't produce a result. The code is:

public void distributeCurrentPlayerTokens()

{

int numTokens = board[currentPlayer];

board[currentPlayer] = 0;

int i = currentPlayer;

while (numTokens > 0)

{

i = (i+1) % board.length; 1

board[i]++;

numTokens--;

}

}

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8. What are used by the project architect to depict different building systems and to show how they correlate to one anothe
O A. Preliminary
O B. Shop drawings
C. Working drawings
O D. Sketches

Answers

Explanation:

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A friend of yours bought several dozen pure silver rings on a recent trip abroad, but now suspects
that they might not be all that pure. He brings them to you to check. You weigh 10 of the rings and
find that each ring has a mass of 0.738g, you then place them in a graduated cylinder 2.5cm in
diameter and observe that the water level rises by 8.45mm. S.G of pure silver = 10.49
Using chemical engineering concepts, determine if the rings are pure silver.

Answers

Answer:

3

Explanation:

To determine if the rings are pure silver, we can calculate the density of the rings and compare it to the density of pure silver. The density of a material is the mass of the material per unit volume.

First, we need to find the volume of one of the rings. Since the rings are cylindrical, we can use the formula for the volume of a cylinder to find the volume of each ring:

V = π * r^2 * h

Where V is the volume of the ring, π is approximately equal to 3.14, r is the radius of the ring, and h is the height of the ring. In this case, the height of the ring is equal to the thickness of the ring, which is equal to the change in the water level (8.45 mm) divided by the number of rings (10). The radius of the ring is equal to half the diameter of the graduated cylinder (2.5 cm / 2 = 1.25 cm), since the rings are placed in the cylinder side by side.

Plugging these values into the formula, we find that the volume of each ring is:

V = 3.14 * (1.25 cm)^2 * (8.45 mm / 10) = 0.00367 cm^3

Next, we can use the mass and volume of each ring to calculate the density of the rings:

density = mass / volume

Since the mass of each ring is 0.738g and the volume of each ring is 0.00367 cm^3, the density of the rings is:

density = 0.738 g / 0.00367 cm^3 = 201.09 g/cm^3

Finally, we can compare the density of the rings to the density of pure silver, which is 10.49 g/cm^3. Since the density of the rings is much higher than the density of pure silver, it is likely that the rings are not pure silver.

It is important to note that this calculation is only an approximate estimation of the purity of the rings. There may be other factors that affect the density of the rings, such as impurities or variations in the thickness of the rings. Additionally, the value of the density of pure silver used in this calculation may not be entirely accurate, as the density of a material can vary depending on factors such as temperature and pressure. A more precise determination of the purity of the rings would require further testing and analysis.

Which tool is used for cutting bricks and other masonry materials with precision?

Answers

Answer:

A turbo blade has the best features from both other types of blade. The continuous, serrated edge makes for fast cutting while remaining smooth and clean. They are mostly used to cut a variety of materials, such as tile, stone, marble, granite, masonry, and many other building materials.

Explanation:

Answer:

Masonry Saw

Explanation:

Masonry Saws can be used to cut brick, ceramic, tile and or stone.

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