Answer:
Potential Energy
why are the most common stars among the most difficult to observe
The most common stars, known as red dwarfs, are difficult to observe because of their low luminosity, small size, and cool surface temperatures.
The most common stars in our universe are red dwarfs, which are small and dim compared to other types of stars. They emit most of their light in the infrared spectrum, making them difficult to observe with visible-light telescopes. Additionally, these stars are often surrounded by dust and gas that further obstructs our view of them. Red dwarfs also have long lifespans, so their evolution and behavior occur over much longer timescales than larger, more luminous stars. All of these factors make it challenging to study red dwarfs and understand their properties, despite their abundance in the universe.
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what was the ethical issue concerning the incidents with eastern airlines and hewlett-packard discussed in the text?
In the text, the ethical issue concerning the incidents with Eastern Airlines and Hewlett-Packard is the violation of trust and responsibility towards their customers and stakeholders.
Eastern Airlines had safety concerns that were overlooked for financial gains, leading to fatal crashes.
On the other hand, Hewlett-Packard engaged in illegal and unethical practices such as spying on their board members, journalists, and employees to maintain control over the company.
Both cases demonstrate the importance of ethical leadership, transparency, and accountability in business
. Companies must prioritize ethical practices over profits to build a sustainable and trustworthy relationship with their stakeholders.
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URGENT!!! Please help me with the questions attached in the image.
The thermal energy lost per hour is 1.8288 x 10⁸ J and the engine absorbs 478,080 kJ (4.78 x 10⁸ J) of thermal energy every hour.
How to determine thermal energy?Use the Carnot efficiency formula to calculate the thermal energy absorbed by the engine per hour:
Efficiency = 1 - (T_cold / T_hot)
where T_cold and T_hot = temperatures of the cold and hot reservoirs in Kelvin.
Calculate the thermal energy absorbed per hour by the engine using the formula:
Thermal energy absorbed per hour = Power output / Efficiency
Convert the temperatures to Kelvin:
T_cold = 30°C + 273.15 = 303.15 K
T_hot = 524°C + 273.15 = 797.15 K
Calculate the efficiency:
Efficiency = 1 - (T_cold / T_hot)
Efficiency = 1 - (303.15 / 797.15)
Efficiency = 0.618
Calculate the thermal energy absorbed per hour:
Thermal energy absorbed per hour = Power output / Efficiency
Thermal energy absorbed per hour = 82 kW / 0.618
Thermal energy absorbed per hour = 132.8 kW
Finally, convert the result to joules:
Thermal energy absorbed per hour = 132.8 kW x 3600 s
Thermal energy absorbed per hour = 478,080 kJ
Therefore, the thermal energy absorbed by the engine per hour is 478,080 kJ or 4.78 x 10⁸ J.
The thermal energy lost per hour by the engine is equal to the thermal energy absorbed per hour minus the power output:
Thermal energy lost per hour = Thermal energy absorbed per hour - Power output
Thermal energy lost per hour = 478,080 kJ - 82 kW x 3600 s
Thermal energy lost per hour = 478,080 kJ - 295,200 kJ
Thermal energy lost per hour = 182,880 kJ
Finally, convert the result to joules:
Thermal energy lost per hour = 182,880 kJ = 1.8288 x 10⁸ J
Therefore, the thermal energy lost by the engine per hour is 1.8288 x 10⁸ J.
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what would happen to convection currents when the heat source is removed
When a heat source is removed, the convection currents that were driven by the heat source will gradually weaken and eventually stop. Convection currents occur when a fluid or gas is heated, causing it to expand and become less dense.
The less dense, warm fluid rises while the cooler, denser fluid sinks, creating a circular flow pattern. When the heat source is removed, the fluid or gas will start to cool down. As it cools, its density increases, causing it to become denser than the surrounding fluid or gas. This denser fluid will sink, displacing the warmer fluid that was previously rising. As this process continues, the temperature difference between the fluid layers decreases, resulting in a decrease in the strength of convection currents. Over time, without a heat source to sustain the temperature difference, the fluid or gas will reach thermal equilibrium, where the temperature is uniform throughout. At this point, convection currents will cease entirely, and the fluid or gas will remain still. It's worth noting that the exact behavior of convection currents after the heat source is removed can depend on various factors, such as the specific properties of the fluid or gas, the initial temperature difference, and the presence of other external influences like gravity or external cooling. However, in general, the absence of a heat source will lead to the dissipation and eventual cessation of convection currents.
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Two objects are placed on a scale so that it balances. One object weighs 5 N and is placed 0.5 m from the fulcrum of the scale. The other object is placed 1 m from the fulcrum. How heavy is the other object?
The weight of the other object placed 1 m from the fulcrum that balances the other object is 2.5 N.
Principle of moment
The weight of the second object is determined by applying principle of moment as shown below;
take moment about the pivot,
sum of clockwise moment = sum of anticlockwise moment
F₁r₁ = F₂r₂
5 x 0.5 = F₂ x 1
2.5 N = F₂
Thus, the weight of the other object placed 1 m from the fulcrum that balances the other object is 2.5 N.
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Difference between rest and motion?
Answer:
Rest and motion are relative terms. In simple terms, an object that changes its position is said to be in motion while the opposite action causes an object to be at rest.
Explanation:
you are driving down the highway and a bug splatters on your windshield. which is greater: the force of the bug on the windshield or the force of the windshield on the bug?
The force of the windshield on the bug is greater than the force of the bug on the windshield, by applying Newton's Third Law.
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So when the bug hits the windshield, it exerts a force on the windshield and the windshield exerts an equal and opposite force on the bug. However, since the windshield is much larger and more massive than the bug, the force it exerts on the bug is greater than the force of the bug on the windshield. This means that the force of the bug on the windshield and the force of the windshield on the bug are equal in magnitude but opposite in direction.
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A simple 15.2 cm reflecting telescope can achieve 1 second of arc resolution for visible light. Many radio telescopes study a particular radio wavelength of 21 cm. Complete parts a −d using the above information. a. Use the Raleigh criteron to determine how large a radio telescope aperature must be to achieve this resolution at 21 cm. b. Why must the aperture of a radio telescope be much larger than that of an optical telescope? c. Why is it possible to resolve two predominantly blue stars when the same telescope can not resolve two simarily separated red stars? d. In the galaxy pictures of 5 b, which photograph corresponds to the largest aperture?
a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.
a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:
δθ = 1.22 * (λ / D)
Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.
Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:
D = 1.22 * (λ / δθ)
D = 1.22 * (0.21 m / 1 second of arc)
Calculating the result:
D ≈ 0.27 m
Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.
b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.
Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.
c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).
Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.
Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.
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What is the gravitational force between Saturn and it’s moon
Answer:
The gravitational force between Saturn and it's moon is 1.62 m/s ^2
Explanation:
google it
Answer:
Explanation:
C bro
What type of movement do you think might be responsible for the damage shown in the photo? Write a paragraph that relates the ground movement during an earthquake to wave type.
Based on damage in the photo, it is possible that the movement responsible could be from an earthquake.
How does ground movement in earthquake relate to wave type?Seismic waves spread through the ground in different ways when an earthquake occurs which often results to different types of waves. They includes:
Primary waves: It is the fastest and can travel through solid and liquid materials.Secondary waves: It is slower and can only travel through solid materials.Surface waves: It is the slowest and cause the most damage, as they travel along the surface of the ground and can produce strong shaking.Read more about earthquake
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Fill in the blanks! Please, help me ASAP
I’ll give extra points
Answer:
Please find attached the required filled diagram created with MS Visio
Explanation:
Waves → Are produced by → Vibrating molecules → Which pass energy to → neighboring molecules
Waves → Are → Repeating disturbances → That transfers → Energy → Through → Matter or Space
Waves → that need a → Medium → are called → Mechanical → And can be either → Compressional → Or → Transverse
Two points charges of same charge 2 nc are placed on the x axis at -3cm and 3 cm locations respectively. An electron is initially held stationary on the y axis at 4 cm. If this electron is left free, the speed with which it crosses the origin is
Let P, which is located at a distance of x to the left of the 1nC charge in the picture, have a potential of zero. x=0.33m
What does it mean to be capable?When you suggest something or someone has potential, you're implying that they possess the skills or traits needed to succeed or be of service in the future. The young man is quite promising. Every student is given individualized attention at the school, and every effort is made to help them reach their full potential.
What sort of example might that be?Everything that is possible is a possibility. Doctors are very excited about the possible benefits of the new medication. It is said by opponents that the factory would threaten the environment. The institution's potential for growth. According to some, he might seek office.
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How many neutral points due to a bar magent?
Answer:
Two
Explanation:
A neutral point is a point in the magnetic field of a bar magnet where the resultant magnetic field intensity is zero
The neutral point is formed in the region of the combined magnetic field where the magnetic field from the bar magnet is balanced by the horizontal component from the Earth's magnetic field
Two neutral points are formed adjacent to the north and south poles of a bar magnet when the south pole of the bar magnet points in the magnetic north pole of the Earth with the north pole of the bar magnet pointing towards the south pole of the Earth's magnetic field
Two neutral points are also formed on the west and eastern facing sides of a bar magnet when the north pole of the magnet is pointing to the magnetic north of the Earth's magnetic field and the south pole of the bar magnet points south
Therefore, two neutral points are formed for each orientation of the bar magnet when placed horizontally in the Earths magnetic field with the poles of the magnet facing the North and South poles direction of the Earth's magnetic field.
Question 5: Which object traveled at a faster speed? (Make sure to show your
work!!)
Object A: 65 miles in 13 minutes
Object B: 125 miles in 25 minutes
Answer: objects A and B have the same speed.
Explanation:
Speed = distance divided by time.
Object A: 65 miles in 13 minutes
Speed (A) = 65 miles divided by 13 minutes
Speed (A) = 5 miles per minute
Object B: 125 miles in 25 minutes
Speed (B) = 125 miles divided by 25 minutes
Speed (B) = 5 miles per minute
Thus, objects A and B have the same speed.
Listed in the Item Bank are individual steps that need to be ordered. To find out more information about steps, some have more details
available when you click on them. Drag and drop the steps in the proper order by placing each in its corresponding open rectangle. Be sure
that the earliest step is placed next to the number 1.
Answer:
radio
microwave
Infrared
Visible
Ultraviolet
X-ray
Gamma ray
I hope this helps you a little bit
The kinetic energy of a compact car moving at 100 km/h is 2.9 x 105 J. To get an idea of the amount of energy needed to heat water, how many liters of water would 2.9 x 105 J of energy warm from room temperature (20.0°C) to boiling (100.0°C)?
0.8 liters of water would 2.9 x 105 J of energy warm from room temperature (20.0°C) to boiling (100.0°C).
The particular heat capacity (symbol c) of a material in thermodynamics is the heat capacity of a sample of the substance divided by the mass of the sample, also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of mass of the substance to generate one unit of temperature increase. Specific heat capacity is measured in joules per kelvin per kilogramme, or J⋅kg−1⋅K−1.The heat required to increase the temperature of 1 kilogramme of water by 1 K, for example, is 4184 joules, hence the specific heat capacity of water is 4184 J⋅kg−1⋅K−1
Given,
Energy, Q = 2.9 x 10⁵ J
specific heat of water, c = 4182 J/kg°C.
change in temperature ΔT = 100-20 = 80°C
according to formula,
Q = mcΔT
2.9 x 10⁵ = m × 4182 × 80
m = 0.8 kg = 0.8 liter
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There is a 5mA flowing through an 18k register. What is the voltage drop?
The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.
Given:
Current (I) = 5 mA = 5 * 10^(-3) A
Resistance (R) = 18 kΩ = 18 * 10^(3) Ω
Using Ohm's Law, we can calculate the voltage drop (V):
V = I * R
= (5 * 10^(-3) A) * (18 * 10^(3) Ω)
= 90 V
Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
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1. What mass can be lifted by the hydraulic press if it is known that the are:
of the small piston is 48cm and that of the large piston is 1440cm, and
the force acting on the small piston can be as large as 1000N. (use g =
10m/s)
C. 3000kg
B. 30kg
D. 30,000kg
A. 300kg
Answer:
Answer: C. 3000kg
Explanation:
Hydraulic Jack
It's a device that is used to lift heavy loads by applying force via a hydraulic cylinder.
Since the internal pressure on the liquid of the jack is constant, the following relation applies:
\(\displaystyle \frac{F_1}{A_1}=\frac{F_2}{A_2}\)
Where
F1 = Force applied in one end of the jack
A1 = Area of the cylinder of the same end
F2 = Force applied in the other end of the jack
A2 = Area of the cylinder of the other end
If we assume the force is being applied on side 1, then the force on side 2 is calculated by solving for F2:
\(\displaystyle F_2=\frac{F_1.A_2}{A_1}\)
We have F1=1000N, A1= 48~cm^2, A2= 1440~cm^2, thus:
\(\displaystyle F_2=\frac{1000.1440}{48}\)
\(F_2 = 30000 ~N\)
Since we need to know the mass that can be lifted by that force, we use the formula:
W = m.g
Where W is the weight of the mass and g= 10~m/s^2. Since the weight is equal to the force exerted by the jack:
\(\displaystyle m=\frac{W}{g}=\frac{30000}{10}\)
m = 3000 Kg
Answer: C. 3000kg
how are polar and nonpolar molecules similar and different?
Answer:
Polar molecules occur when there is an electronegativity difference between the bonded atoms. Nonpolar molecules occur when electrons are shared equal between atoms of a diatomic molecule or when polar bonds in a larger molecule cancel each other out.
Explanation:
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what is the new volume in milliliters, of a 4.00 ml sample of air at 0.875 atm and 250.5 °c that is compressed and cooled to 305 torr and 185 °c?
The new volume of the air sample is approximately 8.71 mL , we can use the combined gas law, which relates the initial and final conditions of temperature, pressure, and volume.
The combined gas law equation is:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Given:
P1 = 0.875 atm
V1 = 4.00 mL
T1 = 250.5 °C + 273.15 (convert to Kelvin)
P2 = 305 torr (convert to atm)
T2 = 185 °C + 273.15 (convert to Kelvin)
Let's plug in the values and solve for V2:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
(0.875 atm * 4.00 mL) / (250.5 °C + 273.15 K) = (305 torr * V2) / (185 °C + 273.15 K)
Now, let's convert the units to be consistent:
(0.875 atm * 4.00 mL) / (523.65 K) = (0.402 atm * V2) / (458.15 K)
Cross-multiplying:
(0.875 atm * 4.00 mL) * (458.15 K) = (0.402 atm * V2) * (523.65 K)
Simplifying:
3.50 atm·mL·K = 0.402 atm * V2
Dividing both sides by 0.402 atm:
V2 = (3.50 atm·mL·K) / (0.402 atm)
V2 ≈ 8.71 mL
Therefore, the new volume of the air sample is approximately 8.71 mL.
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a 94.0 a current circulates around a 2.40-mm -diameter superconducting ring what is the on axis magnetic field
The value of B depends on the distance z from the center of the ring, and it will increase as z gets closer to the ring.
The magnetic field on the axis of a circular loop carrying a current I can be calculated using the Biot-Savart law, which states that the magnetic field at a point is directly proportional to the current flowing through the loop and inversely proportional to the distance between the point and the loop.
For a circular loop of radius r, the magnetic field on its axis at a distance z from the center can be calculated as:
\($B = \frac{\mu_0 I}{2}\frac{r^2 + z^2}{\sqrt{r^2 + z^2}^3}$\)
where μ₀ is the permeability of free space.
In this case, the current I = 94.0 A and the diameter of the ring is 2.40 mm, which means the radius r of the ring is 1.20 mm = 0.00120 m.
The magnetic field on the axis of the ring at a distance z can be calculated as:
\($B = \frac{\mu_0 I}{2}\frac{r^2 + z^2}{\sqrt{r^2 + z^2}^3}$\)
\($B = \left(4\pi \times 10^{-7} \frac{T \cdot m}{A}\right) \frac{94.0,A}{2}\left(\frac{0.00120,m}{2}^2 + z^2\right)^{-3/2}$\)
\($B = (2\pi \times 10^{-6},\mathrm{T})(0.0003606 + z^2)^{-3/2}$\)
Therefore, the magnetic field on the axis of the ring is given by
\($B = (2\pi \times 10^{-6},\mathrm{T})(0.0003606 + z^2)^{-3/2}$\)
The value of B depends on the distance z from the center of the ring, and it will increase as z gets closer to the ring.
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how do the kinetic energy of each of the following objects compare to one another? i. object of mass 2 kg traveling at constant velocity of 2.5 m/s in the x x direction ii. object of mass 1 kg traveling at constant velocity of 5 m/s in the x x direction iii. object of mass 1 kg traveling at constant velocity of 3 m/s in the x x direction and -4 m/s in the y y direction
Kinetic energy of each of the following objects compared like K₃ = K₂ > K₁ or K₃ = K₂ = K₁.
Kinetic energy of an object of mass, m and speed, v is
K = 1/2 mv²
(1) Given, m = 2kg, v = 2.5m/s
So, K = 1/2 mv²
K₁ = 1/2 × 2×(2.5)²
K₁ = 6.25 J
(2) Given, m = 1kg, v = 5m/s
K = 1/2 mv²
K₂ = 1/2 × 1×(5)²
K₂ = 12.5 J
(3) Given, m = 1kg, Vx = 3m/s, Vy= 4m/s
v = \(\sqrt{Vx^{2} + Vy^{2} }\)
v = 5m/s
K = 1/2 mv²
K₃ = 1/2 × 1×(5)²
K₃ = 12.5 J
Hence, K₃ = K₂ > K₁ or K₃ = K₂ = K₁ .
Kinetic energy is the type of energy which is due motion of an object. Kinetic energy is the product of half of mass and velocity square. Its unit Joule and is represented by J.
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-- (
2)
(iii) In an experiment using this circuit, an ammeter reading
was 0. 75 A.
The calculated value of the resistance of resistor Rwas 16 0.
What is the voltmeter reading?
Answer:
In order to determine the voltmeter reading in this experiment, we need to use Ohm's Law, which states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance. The equation is:
V = I * R
Where:
V = voltage (measured in volts)
I = current (measured in amperes)
R = resistance (measured in ohms)
Given that the ammeter reading was 0.75 A and the resistance of resistor R was 160 ohms, we can substitute these values into the equation:
V = 0.75 A * 160 ohms
V = 120 V
Therefore, the voltmeter reading is 120 V.
A object has a mass of 13 Kg . - 17 Calculate the mass of this object on the surface of Jupiter . ( The gravity of Jupiter is 26 N / kg )
Explanation:
It is given that,
Mass of an object is 13 kg
We need to find the mass of this object on the surface of Jupiter.
The mass of an object is the amount present in it. It it independent of location. It mass remains the same at Jupiter as well. Its does not depend on the gravity on that surface.
Hence, its mass will remain 13 kg on the surface of Jupiter.
Suppose the ac voltage across and ac current through a circuit component both have frequency 10 rad/s. what is the frequency of the instantaneous power waveform?
The frequency of the instantaneous power waveform in this circuit component is 10 rad/s.
The frequency of the instantaneous power waveform in this circuit component would also be 10 rad/s. In an AC circuit, the instantaneous power is given by the product of the instantaneous voltage and current.
Since both the voltage and current have a frequency of 10 rad/s, the frequency of the instantaneous power waveform will be the same.
To understand this, let's consider a sinusoidal voltage waveform and a sinusoidal current waveform. The power at any instant is given by the product of the voltage and current at that instant.
Since both waveforms have the same frequency, the product of the two waveforms will also have the same frequency.
Therefore, the frequency of the instantaneous power waveform in this circuit component is 10 rad/s.
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What is the formula of snell descartes on the refraction?
The relationship between the angles of incidence and refraction when a light ray passes across the boundary between two media with differing refractive indices is described by Snell-Descartes law.
Snell's law
n₁sinθ₁ = n₂sinθ₂
In the following equation, n1 and n2 stand for the refractive indices of the two media. θ₁ for angle of incidence (the angle between the incident ray and the normal to the boundary), and θ₂ for angle of refraction (the angle between the refracted ray and the normal to the boundary). Sometimes referred to as Snell-Descartes law, in its mathematical form.
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(T/F) gravity is an attractive force that decreases as the mass of an object increases.
The ecliptic crosses the celestial equator on the celestial sphere at points called.
The ecliptic crosses the celestial equator on the celestial sphere at points called equinoxes.
The celestial equator is a circle projected onto the sky's celestial sphere halfway between the celestial poles and perpendicular to the celestial axis.
The ecliptic, on the other hand, is the circle across which the apparent path of the Sun appears to travel over the course of a year on the celestial sphere.
In the sky, the celestial equator and the ecliptic intersect each other. These intersections are known as the equinoxes.
The vernal equinox is the intersection point of the Sun's path with the celestial equator, which occurs around March 20th or 21st each year.
Summary: The points where the ecliptic crosses the celestial equator on the celestial sphere are known as equinoxes. The vernal equinox occurs around March 20th or 21st each year, while the autumnal equinox occurs around September 22nd or 23rd each year. They are important reference points in astronomy and are used in creating calendars and astrological charts.
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Wegner's idea of plates moving was not accepted until it was determined how they could move. it is now thought that plates move due to ______________ in the earth's mantle.
Wegner's idea of plates moving was not accepted until it was determined how they could move. It is now thought that plates move due to convection currents in the Earth's mantle.
Convection currents are the movement of heat within a fluid, such as the Earth's mantle, which is made up of hot, molten rock. The heat from the Earth's core causes the rock in the mantle to heat up and become less dense, causing it to rise. As it rises, it cools and becomes denser, causing it to sink back down. This constant movement of the mantle creates convection currents, which are thought to be the driving force behind the movement of the Earth's plates.
In summary, Wegner's idea of plate movement was not accepted until it was determined that convection currents in the Earth's mantle were the driving force behind the movement of the plates.
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when does the bird have the most potential energy when it dives into a oceran
The bird has the most potential energy when it is at the highest point of its dive into the ocean.
1. Potential energy is the energy possessed by an object due to its position or state.
2. In this case, we are considering the potential energy of a bird diving into the ocean.
3. The potential energy of an object depends on its height and mass.
4. When the bird is at the highest point of its dive, it has the maximum potential energy.
5. As the bird dives deeper into the ocean, its height decreases, resulting in a decrease in potential energy.
6. At the moment the bird reaches the surface of the water, its potential energy is at its minimum, as it is at its lowest height.
7. The potential energy is converted into kinetic energy as the bird accelerates towards the water.
8. Kinetic energy is the energy possessed by an object due to its motion.
9. When the bird enters the water, its potential energy is completely converted into kinetic energy.
10. The bird continues to possess kinetic energy as it moves through the water.
11. Once the bird comes to a stop in the water, its kinetic energy is reduced to zero.
12. At this point, the bird's potential energy is also zero, as it is at its lowest height and not in motion.
13. Therefore, the bird has the most potential energy when it is at the highest point of its dive into the ocean.
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