What does silver 505.

The molarity of the NaOH(aq) solution is 0.156 M.

The balanced equation for the reaction between sulfuric acid and sodium hydroxide is H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l). From the balanced equation, it can be deduced that the mole ratio of NaOH to H₂SO₄ is 2:1. Hence, the moles of H₂SO₄ reacted = Molarity of H₂SO₄ × Volume of H₂SO₄ used in liters = 0.220 M × 0.03230 L = 0.007106 moles.

Using mole ratio, the moles of NaOH reacted = 2 × 0.007106 = 0.01421 moles. Molarity of NaOH = Moles of NaOH / Volume of NaOH used in liters= 0.01421 moles / 0.04630 L = 0.306 M or 0.156 M (rounded off to three significant figures). Thus, the molarity of the NaOH(aq) is 0.156 M.

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Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

Answer:

25-54-46-36 619-73 77-88-50

Answer:

C

Explanation:

.........................

98.684 ml of 95% ethanol solution and 26.316 ml of water are required to prepare 125 ml of 75% ethanol solution.

What is a solution?

A solution is a uniform mixture of two or more components with particles smaller than one nanometer.

There are many different types of solutions, such as soda water, salt-and-sugar solutions, and others. In a solution, each component appears as a separate phase. The distribution of the particles is uniform, or there is particle homogeneity. This explains why the full contents of a soft drink bottle have the same flavour.

Let x ml of the 95% ethanol solution be the volume.

According to the law of conservation of mass, the amount of ethanol in x millilitres of 95% ethanol solution is equivalent to the amount in 125 millilitres of 75% ethanol solution.

⟹M1 V1 =M 2 V 2

In this instance: M 1 = 0.95, V 1 = x ml, M 2 = 0.75, V 2 = 125 ml, and V 1 = 98.684 ml.

But [V 2] = 125 ml for the ultimate volume.

Therefore, 98.684 ml of 95% ethanol solution and 26.316 ml of water are required to prepare 125 ml of 75% ethanol solution.

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To determine a reagent that can oxidize Cr to Cr2 but not Sn to Sn2, we need to consider the reduction potentials (also known as redox potentials) of these elements. The reduction potential indicates the tendency of a species to gain electrons and undergo reduction.

In this case, we want a reagent that has a higher reduction potential than Cr but a lower reduction potential than Sn. By doing so, the reagent will be able to oxidize Cr (acting as an oxidizing agent) but not Sn since Sn's reduction potential is higher than that of the reagent. Based on this criterion, one suitable reagent is acidified potassium dichromate(VI) (K2Cr2O7/H2SO4).

K2Cr2O7/H2SO4 is a commonly used oxidizing agent in various chemical reactions. In an acidic medium, it undergoes reduction and transfers oxygen atoms to the element being oxidized. The relevant reaction for this scenario can be represented as follows:

3Cr + K2Cr2O7 + 8H+ → 4Cr2+ + 2K+ + 7H2O

In this reaction, Cr is oxidized from the +3 oxidation state to the +6 oxidation state, forming Cr2+. However, the acidified potassium dichromate(VI) reagent does not possess sufficient strength to oxidize Sn. The reduction potential of Sn is lower than that of Cr, making it less prone to undergo oxidation by this reagent.

It is worth noting that the selection of appropriate reagents for oxidation or reduction reactions depends on the specific requirements of a reaction. Other reagents with higher reduction potentials than Cr, such as potassium permanganate (KMnO4), could also be considered as alternatives. However, the acidified potassium dichromate(VI) reagent mentioned above is a widely used and effective choice for oxidizing Cr without affecting Sn.

Remember to always consult reliable sources, reference materials, or your teacher to ensure the accuracy and relevance of specific reagents for a given reaction, as the field of chemistry is vast and continually advancing.

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Answer: c extracting oil

Explanation:

Saudi Arabia is known for there huge oil market

If the original cell density in a sample if 2.79 x 106 cfu/ml, \(10^{-1}\) mL or 0.1 mL. which sample volume should yield a countable plate.

To determine the sample volume that should yield a countable plate, we need to estimate the number of colonies that will grow on the plate. A countable plate is one that has between 30 and 300 colonies.

Assuming we want to use a standard Petri dish with a diameter of 90 mm, the surface area of the plate is:

\(Area = \pi * (diameter/2)^2 = 3.14 * (90/2)^2 = 6351 mm^2\)

To estimate the number of colonies that will grow on the plate, we need to dilute the original sample to a concentration that will yield between 30 and 300 colonies. A common dilution factor used in microbiology is \(10^{-6\), which means we will dilute the original sample by a factor of 1 million.

The calculation for dilution is:

\(C_1V_1 = C_2V_2\)

where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.

Let's assume we want to plate 0.1 mL of the diluted sample on the plate. We can calculate the dilution factor as follows:

\(C_1V_1 = C_2V_2\)

\((2.79 * 10^6 \ cfu/mL) * V_1 = (2.79 *\ 10^6 \ cfu/mL) * 10^{-6} * 0.1 mL\\V_1 = 0.1 mL / 10^{-6} = 10^5 mL\)

This means we need to take 0.1 mL of the \(10^{-6\) diluted sample (which is equivalent to \(10^5\) times diluted) and plate it on the agar surface.

To check if this sample volume will yield a countable plate, we can estimate the number of colonies that will grow on the plate:

Number of colonies = (CFU/mL) × (plated volume) × (reciprocal of dilution factor)

Number of colonies = \((2.79 * 10^6 cfu/mL) * 0.1 mL * 10^6 = 279 colonies\)

This is within the range of 30 to 300 colonies, so a sample volume of 0.1 mL should yield a countable plate.

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Answer:

Hope this may help you

The classification of the metals is;

Main group/ representative metals - Tl

Main group non metal - Se, Rn

Main group metalloid - As

Transition metal - Mo

Inner transition metal - Ru, Eu

The periodic table is a classification of elements according to their atomic numbers. We know that elements are arranged in the periodic table in order of increasing atomic numbers of the elements.

Let us now classify each element as required;

Main group/ representative metals - Tl

Main group non metal - Se, Rn

Main group metalloid - As

Transition metal - Mo

Inner transition metal - Ru, Eu

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475.021, f.s., refers to the Florida Statute (f.s.) for driver's license suspensions and revocations. This particular statute deals with the suspension of licenses for drivers who fail to pay court fines, costs, and fees.

The statute states that failure to pay the required court fees within 30 days will result in the suspension of the driver's license.

After 90 days, the suspension becomes permanent until the fees are paid. In summary, the mysterious glyph is trying to tell you about the legal statute in Florida regarding the suspension of driver's licenses for non-payment of court fees, fines, and costs.

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Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

Answer:

The solubility of sodium hydroxide decreases with increase of temperature. Equilibrium constant of an exothermic reaction decreases with increase of temperature. Due to this less heat is produced in the reaction and the effect of increased temperature is nullified.

One possible drawback to moist-heat cookery is that color, flavor, vitamins and minerals may leach out and be lost in the liquid.

What is cooking with moist heat?

Liquid or steam is used in moist heat cooking to deliver heat to the food. Poaching, steaming, and braising are three common methods. Each os the moist heat cooking method uses heat in the form of liquid or vapor to slowly cook food and loosen connective tissue.

Numerous nutrients, including vitamins and minerals, are lost when food is cooked using moist heat because these nutrients stay in the liquid that they were originally cooked in. Taste is lost when food is boiled since it also stays in the liquid.

Question:

One possible drawback to moist-heat cookery is that _______ may leach out and be lost in the liquid.

a.color

b.flavor

c.vitamins

d.minerals

e.all the above

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The hydroxide ion concentration of an aqueous solution of 0.522 M hypochlorous acid is 8.772 x 10^-11 M.

To find the pOH of an aqueous solution of 0.522 M acetylsalicylic acid, we need to first write the ionization equation for the acid:

HC9H7O4 (aq) + H2O (l) ↔ H3O+ (aq) + C9H7O4- (aq)

The acid dissociation constant (Ka) for acetylsalicylic acid is not given, so we cannot use it to directly calculate the [H3O+] concentration. However, since acetylsalicylic acid is a weak acid, we can assume that the amount of [H3O+] produced by the ionization is small compared to the initial concentration of the acid, and can be neglected in the concentration calculation. Therefore, we can assume that the [H3O+] concentration is approximately equal to the initial concentration of the acid, and use the concentration of the acid to calculate the [OH-] concentration:

[H3O+] = [HC9H7O4] = 0.522 M

Kw = [H3O+][OH-] = 1.0 x 10^-14

[OH-] = Kw/[H3O+] = 1.0 x 10^-14 / 0.522 = 1.917 x 10^-13 M

pOH = -log[OH-] = -log(1.917 x 10^-13) = 12.717

Therefore, the pOH of the aqueous solution of 0.522 M acetylsalicylic acid is 12.717.

To find the hydroxide ion concentration of an aqueous solution of 0.522 M hypochlorous acid, we first need to write the ionization equation for the acid:

HClO (aq) + H2O (l) ↔ H3O+ (aq) + ClO- (aq)

The acid dissociation constant (Ka) for hypochlorous acid is 3.5 x 10^-8, so we can use it to calculate the [H3O+] concentration:

Ka = [H3O+][ClO-]/[HClO]

[H3O+] = sqrt(Ka*[HClO]) = sqrt(3.5 x 10^-8 x 0.522) = 1.14 x 10^-4 M

Now, we can use the [H3O+] concentration to calculate the [OH-] concentration:

Kw = [H3O+][OH-] = 1.0 x 10^-14

[OH-] = Kw/[H3O+] = 1.0 x 10^-14 / 1.14 x 10^-4 = 8.772 x 10^-11 M

[OH^-]= 8.772 x 10^-11 M

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Hydronium ion  [H₃O⁺ ]  concentration of pure water at room temperature is 1 × 10⁻⁷ M.

Due to the amphiprotic nature of water, the auto ionization process can result in the formation of both an OH⁻ ion and  H₃O⁺ ion.

              H₂O +   H₂O   →  H₃O⁺  +  OH⁻

Equilibrium constant K can be:    k =  aH₃O⁺  ×  aOH⁻/   aH₂O

where a represents a activity of species. Water is the solvent and the solution is presumed to be diluted. Hence the activity of the water is approximated by the activity of pure liquid water, which is defined having value of 1.

One water molecule act as an acid and other water molecule act as a base in this process. As a result, this reaction can be referred to as both the \(K_{a\) and the \(K_{b}\)of water. However, the term \(K_{w\) of water is most frequently  term used.

                                   \(K_{W}\) = [H₃O⁺ ]  [OH⁻]

At a temperature of 25 °C, pure liquid water is in equilibrium with the  hydronium and hydroxide  ions and their concentrations are equal.

            [H₃O⁺ ]   =   [OH⁻]    =    1 × 10⁻⁷ M  

              \(K_{w\) =    (1 × 10⁻⁷)   ×   (1 × 10⁻⁷)   =   1 × 10⁻¹⁴ M

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Answer:

102 C

Explanation:

An atom which an electron moves from the first to the third shell atom absorbs more energy.

An atoms may occupy different energy states . The energy states are discrete , that means they occur at specific values only. Therefore an atom can only move to a new energy level if it absorbs or emits an amount of energy that exactly corresponds to the difference between two energy levels.

The lowest possible energy levels that the atom can occupy is called ground state.The energy levels which is higher to the ground state is called excited state.

The more energy absorb when electron move from first to third because in this second energy level have to pass to reach at third energy level.

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The intermediate is stabilised by fluorene electronegativity, which removes the electrons from the meisenheiner complex's negative charge, allowing the process to proceed more quickly.

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Answer:

the products are more stable than the reactants

Explanation:

After 24 days, you will have 1/2 kg

It's a common occurrence for radioactive isotopes to spontaneously decay over time, shedding their radioactive atoms. The period of time it takes for any sample of an element to be reduced to half its initial amount is known as the half-life of a radioactive isotope. The differential equation

dNdt=kN(t)

describes the decay of such radioactive isotopes, where N(t) is the number of radioactive atoms of the element that are still present at time t and k is the decay constant.

The solution to the aforementioned differential equation is N(t) = N (0)ekt, where N (0) is the initial sample's initial number of atoms.

Keep in mind that the natural logarithm has the identity

a ln n=a ln n.

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In 0.75 moles of caffeine, there are a total of 6 carbon atoms, 7.5 hydrogen atoms, 3 nitrogen atoms, and 1.5 oxygen atoms.

To determine the total number of atoms in 0.75 moles of caffeine, we need to consider the molecular formula of caffeine, which is C8H10N4O2. The molecular formula provides the ratios of each element present in the compound. By multiplying the number of atoms in each element by the corresponding coefficient in the molecular formula, we can calculate the total number of atoms. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms in each molecule of caffeine. Multiplying these values by 0.75 moles will give us the total number of atoms in 0.75 moles of caffeine.

The molecular formula of caffeine, C8H10N4O2, provides the number of atoms for each element present in one molecule of caffeine. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

To calculate the total number of atoms in 0.75 moles of caffeine, we need to multiply the number of atoms for each element by the coefficient in the molecular formula, and then multiply that by the number of moles (0.75 moles).

For carbon (C): 8 atoms x 0.75 moles = 6 atoms (since there are 8 carbon atoms in one molecule of caffeine).

For hydrogen (H): 10 atoms x 0.75 moles = 7.5 atoms (since there are 10 hydrogen atoms in one molecule of caffeine).

For nitrogen (N): 4 atoms x 0.75 moles = 3 atoms (since there are 4 nitrogen atoms in one molecule of caffeine).

For oxygen (O): 2 atoms x 0.75 moles = 1.5 atoms (since there are 2 oxygen atoms in one molecule of caffeine).

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Macromolecules, the molecules of life, include all of the following except trace elements and is therefore denoted as option C.

This is referred to as a very large molecule which are important to biophysical processes and examples include carbohydrate, nucleic acids etc which are involved in the provision of energy and cell division respectively in the cells of the organism.

Trace element on the other hand is referred to as the type of element whose concentration is very low and some are non essential which means their deficiency don't cause any serious effect on the body system and examples include selenium , cobalt etc.

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The options are:

Answer: C

Explanation:

Answer:

B. Holding spores

Explanation:

B is the answer

Answer:

200

Explanation:

got it right on the test

Answer:

200

Explanation:

Answer:

93.5 moles N₂

Explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

Answer:

93.5 moles N₂

Explanation:

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

Explanation:

By eating half cooked meat