What does Newton's third law describe?
A. Equal and opposite forces
B. How the amount of mass influences the amount of force needed
to move an object
C. The tendency of moving objects to stay in motion
D. The attractive force between two objects due to their masses

72 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 12 m

To find : -

Speed ( v ) = ?

Formula : -

v = f x λ

v

= 6 x 12

= 72 m/s

Therefore,

the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m is 72 m/s.

The resistor will dissipate 10.0 W when the rms voltage of the emf is approximately 38.7 V.

To find the rms voltage at which the resistor dissipates 10.0 W, we can use the formula for power dissipation in a resistor:

P = (V^2) / R,

where P is the power dissipated, V is the rms voltage, and R is the resistance.

Given that the resistor dissipates 2.15 W at 12.0 V, we can rearrange the formula to find the resistance:

R = (V^2) / P.

Substituting the values, we have:

R = (12.0^2) / 2.15 = 67.16 Ω.

Now, we can use this resistance value and the desired power dissipation of 10.0 W to find the rms voltage:

V = sqrt(P * R).

Substituting the values, we get:

V = sqrt(10.0 * 67.16) = 38.7 V (approximately).

Therefore, the resistor will dissipate 10.0 W when the rms voltage of the emf is approximately 38.7 V.

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Answer:

kelvin is the base unit or SI unit for temperature.

Explanation:

i hope this will help you

Answer:

Temperature.

Explanation:

Mike is swinging from a vine. The net force on Mike will be vertical upward at the bottom of the swing.

A centripetal force is a force that causes a body to move in a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the path's instantaneous center of curvature.

Mike is on a swing, which means he must take a circle course. In a circular motion, centripetal force acts towards the motion's center, allowing it to travel in that direction.

As a result, the net force at each point on the circular part will be towards the center. The direction of net force will be vertical upward at the bottom position.

Therefore, the net force on Mike will be vertical upward at the bottom of the swing

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Answer:

Explanation:

Answer:

A crossroads of trade is a place where many trade routes converge, often leading to the exchange of goods and ideas between different cultures. Historically, cities and towns located at crossroads of trade have been important centers of commerce and cultural exchange. For example, the ancient city of Alexandria in Egypt was a crossroads of trade between Europe, Africa, and Asia, and played a key role in the exchange of goods and ideas between these regions. In modern times, cities such as Dubai and Singapore have become important crossroads of trade due to their strategic location and well-developed infrastructure for transportation and logistics.

The weight of the box is approximately 273.45 N.

To determine the weight of the box, we will consider the equilibrium of forces acting on the box when it is displaced to its final position. At this point, there are three forces acting on the box: the weight (W), tension in the rope (T), and the horizontal force (F = 100 N). These forces can be represented using vectors and trigonometry.

Since the box is in equilibrium, the net force acting on it is zero. Therefore, the horizontal and vertical components of the tension in the rope must balance the horizontal force and the weight of the box, respectively. Using the angle provided (20 degrees), we can calculate the components of the tension in the rope as follows:

Horizontal component: T_horizontal = T * sin(20°)
Vertical component: T_vertical = T * cos(20°)

To balance the forces, we have:
T_horizontal = F => T * sin(20°) = 100 N
T_vertical = W => T * cos(20°) = W

Now, divide the first equation by the second equation:
(T * sin(20°)) / (T * cos(20°)) = (100 N) / W

Simplify the equation using the trigonometric identity tan(θ) = sin(θ) / cos(θ):
tan(20°) = (100 N) / W

Now, solve for W:
W = (100 N) / tan(20°)

W ≈ 273.45 N

The weight of the box is approximately 273.45 N.

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Answer:

Mass is a measure of the amount of matter in an object. Mass is usually measured in grams (g) or kilograms (kg). Mass measures the quantity of matter regardless of both its location in the universe and the gravitational force applied to it. Your mass on the earth and the moon are identical.

Explanation:

In the answer.

The only option II, increasing the mass, would increase the period of the oscillation.

The period of oscillation is defined as the time required for a single oscillation to occur. It is determined by the square root of the mass attached to the spring divided by the spring constant.

The formula for the period is:

T = 2π√m/k

Where T is the period, m is the mass, and k is the spring constant. Therefore, an increase in mass or a decrease in spring constant k would lead to an increase in the period of the oscillation. Only option II would result in an increase in the period of the oscillation.

The period of oscillation is a function of the mass of the object and the spring constant. If the mass is increased, the period of oscillation increases, and if the spring constant is increased, the period of oscillation decreases. It is also unaffected by the amplitude or air resistance. Thus, only option II, increasing the mass, would increase the period of the oscillation.

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Answer:

Explanation:

The mass of an object given only the force acting on it and it's acceleration can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force in N

a is the acceleration in m/s²

We have

\(m = \frac{20}{2} = 10 \\ \)

We have the final answer as

Hope this helps you

Explanation: The amount of solar energy available varies by location on earth, the time of the day at that location, the season and weather conditions. Rain, fog, and clouds will lower the amount of solar power available to gather and there are fewer hours of sun available in different seasons (winter for North America). To gather solar power, you also need a large area. This can be lessened by conditions such as snow, so that even on a sunny day, covered panels will collect less energy.

Answer:

.

Explanation:

The quantity of solar energy accessible varies by location on the planet, time of day, season, and weather conditions. Rain, fog, and clouds reduce the quantity of solar power available for collection, and various seasons have less hours of sunlight accessible (winter for North America). A big region is also required to collect solar electricity. Conditions such as snow can reduce this, such that even on a sunny day, covered panels will absorb less energy.

The Mechanical energy is equal to the Initial gravitational energy as mechanical energy is stored in the object as gravitational potential energy.

Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another.

An isolated system's total energy is constant regardless of the types of energy present. The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that:

The total energy of the system is conserved in a closed system, also known as an isolated system.

Therefore, in a closed system like the universe, if energy is lost in one area, energy must be gained in a different area of the system by an equal amount. There is no known instance of the conservation of energy being broken, despite the fact that it cannot be proven.

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No, not all waves move through various materials at the same pace. The characteristics of the medium itself, the kind of wave, and the frequency of the wave are only a few of the variables.

that affect how quickly a wave moves through a given medium. Sound waves, for instance, go through various materials at varying rates, depending on the density and elasticity of the medium. In general, solids transmit sound more quickly than liquids or gases do. Similar to how sound waves go through various materials at various rates, depending on the refractive index of the medium. Light waves, for example, constantly travel in a vacuum at a constant speed of around 299,792,458 meters per second (or about 186,282 miles per second). Nevertheless, as they go on.

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The measured specific heat will be less than the actual specific heat if a lower value is gotten than the actual mass.

This is defined as the quantity of heat needed to raise a substance's temperature by 1 degree Celsius.

If a substance has a low specific heat capacity , it loses water easily which makes the mass when measured to be smaller than the actual value.

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Answer:

The change that has to take place inside the power cord in order for the device to function properly include;

The changing of the alternating current (AC) from the electrical outlet to the direct current having a specific voltage and current value with which the device can be powered

Explanation:

A battery powered device makes use of direct current (DC) electric power from a battery, while the power normally given out at an electrical outlet comes as an alternating current (AC) electric power source.

The power cord for battery-powered device, also known as an AC/DC adapter, that allows them to be plugged into electrical outlets converts the AC electric current it obtains from the electrical outlets to DC electrical current of the appropriate voltage and amperage that the device can make use of for electric power to function and for charging the battery which is the power source for the device

Therefore, the change that has to take place in the power cord is the conversion of the electric outlet alternating current (AC) voltage and amperage values, into direct current (DC) of the required voltage and current for the device

ANSWER

Q = 5303.95 kJ

EXPLANATION

We are looking for the energy needed to evaporate 2.35kg of water. Since the water is already at evaporation temperature, which is 100°C, we just have to use latent heat. Also, we just want the steam to be at 100°C, so we don't need to find the energy to change its temperature.

The energy needed to evaporate water of mass m is:

L is the latent heat of the material, in this case water. There are two latent heats, one of fusion and one of vaporization. We have to use the second one, which for water is approximately 2257 kJ/kg

Therefore, to boil 2.35 kg of water at 100°C to steam at 100°C we need:

Answer:

John applied a force of approximately \(795\; {\rm N}\) (on average, rounded) on Lucy.

John slows down to a stop after approximately another \(5.37\; {\rm s}\).

(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Assuming that the surface is level. The normal force on Johnny will be equal to the weight of Johnny: \(N(\text{John}) = m(\text{John})\, g\). Similarly, the normal force on Lucy will be equal to weight \(N(\text{Lucy}) = m(\text{Lucy})\, g\).

Multiply normal force by the coefficient of kinetic friction to find the friction on each person:

\(f(\text{John}) = \mu_{k}\, N(\text{John}) = \mu_{k}\, m(\text{John})\, g\).

\(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\).

Again, because the surface is level, the net force on each person after the first \(1.0\; {\rm s}\) will be equal to the friction. Divide that the net force on each person by the mass of that person to find acceleration:
\(\displaystyle a(\text{John}) = \frac{\mu_{k}\, m(\text{John})\, g}{m(\text{John})} = \mu_{k}\, g\).

\(\displaystyle a(\text{Lucy}) = \frac{\mu_{k}\, m(\text{Lucy})\, g}{m(\text{Lucy})} = \mu_{k}\, g\).

(Note that the magnitude of acceleration is independent of mass and is the same for both John and Lucy.)

\(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\).

In other words, after the first \(1\; {\rm s}\), both John and Lucy will slow down at a rate of \(1.962\; {\rm m\cdot s^{-2}}\).

To find the speed of Lucy immediately after the first \(1.0\: {\rm s}\), multiply this acceleration by the time \(t = 8.0\; {\rm s}\) it took for Lucy to slow down to \(0\; {\rm m\cdot s^{-1}}\):

\(\begin{aligned}& (8.0\; {\rm s})\, (1.962\; {\rm m\cdot s^{-2}}) \\ =\; & (8.0)\, (1.962)\; {\rm m\cdot s^{-1}} \\ =\; & 15.696\; {\rm m\cdot s^{-1}}\end{aligned}\).

Thus, in the first \(1.0\; {\rm s}\), Lucy accelerated (from \(0\; {\rm m\cdot s^{-1}}\)) to \(15.696\; {\rm m\cdot s^{-1}}\).

The average acceleration of Lucy in the first \(1.0\; {\rm s}\) would be \((15.696) / (1) = 15.696\; {\rm m\cdot s^{-2}}\). Multiply this average acceleration by the mass of Lucy to find the average net force on Lucy during that \(1.0\; {\rm s}\):

\(\begin{aligned}F_{\text{net}}(\text{Lucy}) &= m(\text{Lucy})\, a \\ &= (45)\, (15.696)\; {\rm N} \\ &= 706.320\; {\rm N}\end{aligned}\).

This net force on Lucy during that \(1.0\; {\rm s}\) is the combined result of both the push from Johnny and friction:

\(F_{\text{net}}(\text{Lucy}) = F(\text{push}) - f(\text{Lucy})\).

Since \(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\):

\(\begin{aligned}F(\text{push}) &= F_{\text{net}}(\text{Lucy}) + f(\text{Lucy}) \\ &= F_{\text{net}}(\text{Lucy}) + \mu_{k}\, m(\text{Lucy})\, g \\ &= (706.320) \; {\rm N}+ (0.2)\, (45)\, (9.81)\; {\rm N} \\ &= 706.320\; {\rm N} + 88.290\; {\rm N} \\ &=794.610\; {\rm N}\end{aligned}\).

In other words, Johnny would have applied a force of \(794.610\; {\rm N}\) on Lucy.

By Newton's Laws of Motion, when Johnny exerts this force on Lucy in that \(1.0\; {\rm s}\), Lucy would exert a reaction force on Johnny of the same magnitude: \(794.610\; {\rm N}\).

Similar to Lucy, the net force on Johnny during that \(1.0\; {\rm s}\) will be the combined effect of the push \(F(\text{push})\) and friction \(f(\text{John}) = \mu_{k}\, m(\text{John})\, g\):

\(\begin{aligned}F_{\text{net}}(\text{John}) &= F(\text{push}) - f(\text{John}) \\ &= F(\text{push}) - \mu_{k}\, m(\text{John})\, g\\ &= 794.610\; {\rm N} - (0.2)\, (65)\, (9.81)\; {\rm N} \\ &= 667.080\; {\rm N}\end{aligned}\).

Divide net force by mass to find acceleration:

\(\begin{aligned}\frac{667.080\; {\rm N}}{65\; {\rm kg}} \approx 10.2628\; {\rm m\cdot s^{-2}}\end{aligned}\).

In other words, Johnny accelerated at a rate of approximately \(10.5406\; {\rm m\cdot s^{-2}}\) during that \(1.0\; {\rm s}\). Assuming that Johnny was initially not moving, the velocity of Johnny right after that \(1.0\; {\rm s}\!\) would be:

\((0\; {\rm m\cdot s^{-1}}) + (10.2628\; {\rm m\cdot s^{-2}})\, (1.0\; {\rm s}) = 10.2628\; {\rm m\cdot s^{-1}}\).

After the first \(1.0\; {\rm s}\), the acceleration of both John and Lucy (as a result of friction) would both be equal to \(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\). Divide initial velocity of Johnny by this acceleration to find the time it took for Johnny to slow down to a stop:

\(\displaystyle \frac{10.2628\; {\rm {m\cdot s^{-1}}}}{1.962\; {\rm m\cdot s^{-2}}} \approx 5.23\; {\rm s}\).

Answer:

John applied a force of approximately \(795\; {\rm N}\) (on average, rounded) on Lucy.

John slows down to a stop after approximately another \(5.37\; {\rm s}\).

(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Assuming that the surface is level. The normal force on Johnny will be equal to the weight of Johnny: \(N(\text{John}) = m(\text{John})\, g\). Similarly, the normal force on Lucy will be equal to weight \(N(\text{Lucy}) = m(\text{Lucy})\, g\).

Multiply normal force by the coefficient of kinetic friction to find the friction on each person:

\(f(\text{John}) = \mu_{k}\, N(\text{John}) = \mu_{k}\, m(\text{John})\, g\).

\(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\).

Again, because the surface is level, the net force on each person after the first \(1.0\; {\rm s}\) will be equal to the friction. Divide that the net force on each person by the mass of that person to find acceleration:
\(\displaystyle a(\text{John}) = \frac{\mu_{k}\, m(\text{John})\, g}{m(\text{John})} = \mu_{k}\, g\).

\(\displaystyle a(\text{Lucy}) = \frac{\mu_{k}\, m(\text{Lucy})\, g}{m(\text{Lucy})} = \mu_{k}\, g\).

(Note that the magnitude of acceleration is independent of mass and is the same for both John and Lucy.)

\(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\).

In other words, after the first \(1\; {\rm s}\), both John and Lucy will slow down at a rate of \(1.962\; {\rm m\cdot s^{-2}}\).

To find the speed of Lucy immediately after the first \(1.0\: {\rm s}\), multiply this acceleration by the time \(t = 8.0\; {\rm s}\) it took for Lucy to slow down to \(0\; {\rm m\cdot s^{-1}}\):

\(\begin{aligned}& (8.0\; {\rm s})\, (1.962\; {\rm m\cdot s^{-2}}) \\ =\; & (8.0)\, (1.962)\; {\rm m\cdot s^{-1}} \\ =\; & 15.696\; {\rm m\cdot s^{-1}}\end{aligned}\).

Thus, in the first \(1.0\; {\rm s}\), Lucy accelerated (from \(0\; {\rm m\cdot s^{-1}}\)) to \(15.696\; {\rm m\cdot s^{-1}}\).

The average acceleration of Lucy in the first \(1.0\; {\rm s}\) would be \((15.696) / (1) = 15.696\; {\rm m\cdot s^{-2}}\). Multiply this average acceleration by the mass of Lucy to find the average net force on Lucy during that \(1.0\; {\rm s}\):

\(\begin{aligned}F_{\text{net}}(\text{Lucy}) &= m(\text{Lucy})\, a \\ &= (45)\, (15.696)\; {\rm N} \\ &= 706.320\; {\rm N}\end{aligned}\).

This net force on Lucy during that \(1.0\; {\rm s}\) is the combined result of both the push from Johnny and friction:

\(F_{\text{net}}(\text{Lucy}) = F(\text{push}) - f(\text{Lucy})\).

Since \(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\):

\(\begin{aligned}F(\text{push}) &= F_{\text{net}}(\text{Lucy}) + f(\text{Lucy}) \\ &= F_{\text{net}}(\text{Lucy}) + \mu_{k}\, m(\text{Lucy})\, g \\ &= (706.320) \; {\rm N}+ (0.2)\, (45)\, (9.81)\; {\rm N} \\ &= 706.320\; {\rm N} + 88.290\; {\rm N} \\ &=794.610\; {\rm N}\end{aligned}\).

In other words, Johnny would have applied a force of \(794.610\; {\rm N}\) on Lucy.

By Newton's Laws of Motion, when Johnny exerts this force on Lucy in that \(1.0\; {\rm s}\), Lucy would exert a reaction force on Johnny of the same magnitude: \(794.610\; {\rm N}\).

Similar to Lucy, the net force on Johnny during that \(1.0\; {\rm s}\) will be the combined effect of the push \(F(\text{push})\) and friction \(f(\text{John}) = \mu_{k}\, m(\text{John})\, g\):

\(\begin{aligned}F_{\text{net}}(\text{John}) &= F(\text{push}) - f(\text{John}) \\ &= F(\text{push}) - \mu_{k}\, m(\text{John})\, g\\ &= 794.610\; {\rm N} - (0.2)\, (65)\, (9.81)\; {\rm N} \\ &= 667.080\; {\rm N}\end{aligned}\).

Divide net force by mass to find acceleration:

\(\begin{aligned}\frac{667.080\; {\rm N}}{65\; {\rm kg}} \approx 10.2628\; {\rm m\cdot s^{-2}}\end{aligned}\).

In other words, Johnny accelerated at a rate of approximately \(10.5406\; {\rm m\cdot s^{-2}}\) during that \(1.0\; {\rm s}\). Assuming that Johnny was initially not moving, the velocity of Johnny right after that \(1.0\; {\rm s}\!\) would be:

\((0\; {\rm m\cdot s^{-1}}) + (10.2628\; {\rm m\cdot s^{-2}})\, (1.0\; {\rm s}) = 10.2628\; {\rm m\cdot s^{-1}}\).

After the first \(1.0\; {\rm s}\), the acceleration of both John and Lucy (as a result of friction) would both be equal to \(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\). Divide initial velocity of Johnny by this acceleration to find the time it took for Johnny to slow down to a stop:

\(\displaystyle \frac{10.2628\; {\rm {m\cdot s^{-1}}}}{1.962\; {\rm m\cdot s^{-2}}} \approx 5.23\; {\rm s}\).

Answer:

Sin θ = θ     is a useful approximation up to about 10 deg

Sin 10 = .174

10 / 360 * 2 π = .175      where 2 π = 360 deg in a circle (no of radians)

Answer:

12500 kg-m/s

Explanation:

Momentum = mv

                  = 500 * 25 =

Answer: b

Explanation:

Ec= (1/2)m × v^2

By the formula, you can see that the bigger the mass, the bigger the Cinetic Energy.

b: b; its mass is smaller

Between ball B and ball C, ball B has LESS potential energy because its mass is smaller.

A potential energy, stored energy that depends upon the relative position of various parts of a system. A spring has more potential energy when it is compressed or stretched.

Potential energy is given by formula.

\(P.E= m*g*h\)

Since, P.E is directly proportional to mass. Thus, the ball having smaller mass will have the less P.E.

Thus, option b is correct.

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The statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

The average temperature throughout the year is higher in location B then that of location A. The temperature is typically warmer near the equator and is typically cooler near the polar regions.

But some factors such as elevation, precipitation and ocean currents might affect the climate pattern. This change in temperature between equator and polar regions is due to the fact that equatorial regions receive more light and energy from the Sun than the polar regions.

Therefore, the statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

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Answer:

ya daddy is my zaddy

Explanation:

In order to use the efficiency of a car engine in an optimal way, a maximum engine speed of 2500 RPM for shifting is recommended for gas engines.

A car's fuel efficiency is determined by how well it converts the energy in its fuel into kinetic energy for movement.

Most of the time, it's advisable to maintain a speed below 2500 rpm for economic reasons.

Range of 2000-2500 rpm is the best for shifting as

1) It is the most favorable range for the engine due to economic reasons.

2) It saves fuel.

3) It also keeps the engine heavy.

After this range, the economy usually declines.

Even though moving gears doesn't significantly affect engine life due to technological developments, but shifting for gas engines is recommended at 2000-2500 rpm.

Hence, 2500 rpm is the maximum engine speed recommended for gas engines for shifting.

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Take into account that any conversion factor can be written as a fraction in which you have the equivalence in the numerator and denominator.

b. 1 mile = 1.61 kilometer

By using the abbreviated form mi as mile and km as kiometer, you can write:

c. 4 cups = 1 quart

To find the range of values required for the capacitor (C) in the tuning circuit of an AM radio, we can use the formula for the resonance frequency of an LC circuit:f = 1 / (2π√(LC))

Given:
Inductance (L) = 0.250 mH
Minimum frequency (f_min) = 550 kHz
Maximum frequency (f_max) = 1650 kHz
We need to find the range of capacitance (C) values that allow the circuit to resonate within this frequency range.
For the minimum frequency:
550 kHz = 1 / (2π√(0.250 mH * C_min))
√(0.250 mH * C_min) = 1 / (2π * 550 kHz)
0.250 mH * C_min = (2π * 550 kHz)^(-2)
C_min = (2π * 550 kHz)^(-2) / 0.250 mH
Similarly, for the maximum frequency:
1650 kHz = 1 / (2π√(0.250 mH * C_max))
√(0.250 mH * C_max) = 1 / (2π * 1650 kHz)
0.250 mH * C_max = (2π * 1650 kHz)^(-2)
C_max = (2π * 1650 kHz)^(-2) / 0.250 mH
Calculating these values will give us the range of capacitance required for the tuning circuit.
Please note that I'm providing the general approach to calculate the range of capacitance based on the given parameters. You can substitute the values into the formulas and perform the calculations to obtain the specific range.

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The drift mobility of electrons in copper is approximately -0.53 m²/Vs

To calculate the drift mobility of electrons in copper, we can use the equation:

μ = -Rn/(G * e)

where:

μ = drift mobility of electrons

Rn = resistivity of the material

G = conductivity of the material

e = elementary charge (1.602 x 10^-19 C)

Given:

Rn = -0.85 *\(10^{-8}\)Ωm²/A

G = 1.0 * \(10^8\)A/m²

e = 1.602 * \(10^{-19}\) C

Substituting the values into the equation:

μ = (-0.85 *\(10^{-8}\)Ωm²/A) / (1.0 * \(10^8\) A/m² * 1.602 * \(10^{-19}\)C)

μ ≈ -0.85 * \(10^{-8}\) Ωm²/A / 1.602 * \(10^{-11}\) Ωm²/C

μ ≈ -0.53 m²/Vs

Therefore, the drift mobility of electrons in copper is approximately -0.53 m²/Vs

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The child's near point is 37.9 cm when wearing the glasses with a prescription of 0.870 D and a distance of 1.95 cm from the eye.

The glasses prescription of 0.870 D indicates that the child has a refractive error of 0.870 diopters. This means that the child's eye is not able to focus light properly on the retina, resulting in blurry vision.

The glasses correct this refractive error by providing an additional refractive power of 0.870 D.

To find the child's near point, we can use the formula:

1/f = 1/v - 1/u

where f is the focal length of the eye, u is the distance of the near point from the eye, and v is the distance of the object from the eye.

For an unaided eye, the near point is normally 25 cm, so we can assume that u = 25 cm.

We need to find the value of v, which is the distance of the glasses from the eye.

The problem gives us the distance of the glasses from the eye, which is 1.95 cm.

However, we need to convert this to meters to be consistent with the unit of focal length, which is meters.

So, v = 0.0195 m.

Substituting the values in the formula, we get:

1/f = 1/v - 1/u

0.870 D = (1/0.0195 m) - (1/0.25 m)

Simplifying the equation, we get:

f = 0.28 m

The focal length of the child's eye is 0.28 meters.

We can now use this value to find the near point using the same formula:

1/f = 1/v - 1/u

1/0.28 m = 1/v - 1/0.25 m

Solving for v, we get:

v = 0.379 m

Converting this value to centimeters, we get:

v = 37.9 cm

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Answer:

Gravitational force will be 16 times more.

Explanation:

we know;

Gravitational force (F) = (Gm1m2)/d^2

when mass of each is doubled and distance between them is halved;

F= (G2m1×2m2)/(d/2)^2

=(4Gm1m2)/(d^2/4)

=4×4(Gm1m2)/d^2

=16(Gm1m2)/d^2

=16F

Since the motor develops a 100 V back emf (electromotive force) at its normal operating speed, its current is 1.67 A.

The relation between current (I), voltage(V), and resistor (R) in a direct current circuit is:

V = I . R

At start:

V = 120 V

I = 10 A

Hence, we can find the equivalent resistor:

R = V/ I = 120 / 10 = 12 Ohm

When the motor is running, it develops 100 V back emf.

Therefore, the net voltage is

= 120 V - 100 V = 20 V

and hence, the current:

I = 20 / 12 = 1.67 A

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