What does a negative Ecell° indicate about a redox reaction? What does it indicate about the reverse reaction?

Answers

Answer 1

A negative Ecell° indicate that a redox reaction is non-spontaneous.

A negative Ecell° indicate that a reverse reaction will not proceed in the forward direction but will proceed spontaneously in the opposite direction.

A positive E°cell means that the reaction will occur spontaneously as written. A negative E°cell means that the reaction will proceed spontaneously in the opposite direction.

A redox reaction is spontaneous if the standard electrode potential for the redox reaction, Eo(redox reaction), is positive.

Eo(redox reaction) = Eo(reduction reaction) + Eo(oxidation reaction)

and Eo(redox reaction) > 0

that is, Eo(redox reaction) is positive

If Eo(redox reaction) is positive, the reaction will proceed in the forward direction (spontaneous).

Spontaneous redox reactions can be used to produce electricity

If Eo(redox reaction) is negative (Eo(redox reaction) < 0), the reaction will not proceed in the forward direction (non-spontaneous).

If the negative Ecell° exists , it represents that only the opposite reaction is spontaneous. It directs to the cathode's oxidation and the anode's reduction. The change in Gibbs free energy in a galvanic cell, where a spontaneous redox reaction causes the cell to produce an electric potential, must be negative.

A positive value denotes the oxidation-reduction reaction that exists as a spontaneous reaction. That indicates without the help of an external agency. Here decrease at the cathode and oxidation at the anode takes place. If it exists a negative value, it means only the reverse reaction is spontaneous. It indicates oxidation at the cathode and reduction at the anode.

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Related Questions

What are the main organs of the muscular system?

Answers

The muscular system is an organ system consisting of skeletal, smooth and cardiac muscles. It permits movement of the body, maintains posture and circulates blood throughout the body.

Answer:

Skeletal, cardiac muscles.

Explanation:

It helps move the body around. Your welcome :)

identify the color absorbed by a solution that should appear as the given color.
Green =
Orange =
Blue=
Red=

Answers

Red = Green (complementary color). Blue = Orange (complementary color). Orange/Yellow = Blue (colors opposite on the colour wheel). Red = Cyan/Blue-Green (opposite hues on the colour wheel) are colours that a solution can absorb.

What influences a solution's colour?

It relies on the wavelength of light that a substance or solution absorbs. The brightness and vibrancy of the colour will increase with increasing light intensity.

What can you say generally about the correlation between a solution's colour and the hue of light it absorbs?

The complementary colour, or the colour across from the absorbed colour on the colour wheel, is what we see when a sample absorbs light of a specific colour. If a sample absorbs red light, for instance.

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Summarize the formation of a base.

Answers

Bases can be formed by the direct combination of the elements that form the bases.

What are bases?

Bases are substances that react with acids to form salt and water only.

Bases are usually oxides or hydroxides of metals.

Bases have the property of turning red litmus blue.

The formation of a base will involve the direct combination of the constituent elements.

For example, the formation of the bases magnesium oxide and ammonia is shown below:

Ammonia: N₂+ 3 H₃ ---> 2 NH₃

Magnesium oxide: 2 Mg + O₂ ---> MgO

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how does that rule that temperature changes the kinetics of a reaction relate to preventing food from spoiling by placing it in a refrigerator?

Answers

In summary, by controlling the temperature, refrigeration can prevent the kinetics of chemical reactions that lead to food spoilage, and therefore prolong the shelf life of perishable foods.

Temperature plays a significant role in the rate of chemical reactions, including those that cause food to spoil. When food is stored at room temperature, the chemical reactions that lead to spoilage occur faster because the molecules in the food are moving faster, leading to an increase in the reaction rate. However, when food is placed in a refrigerator, the lower temperature slows down the movement of molecules, reducing the reaction rate and thus slowing down the spoilage process. This is why it is essential to keep perishable food items in the refrigerator to prevent them from spoiling quickly. Additionally, refrigeration can also inhibit the growth of harmful bacteria, as these bacteria thrive in warm and moist environments. In summary, by controlling the temperature, refrigeration can prevent the kinetics of chemical reactions that lead to food spoilage, and therefore prolong the shelf life of perishable foods.

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at what temperature does water change from a liquid to a gas

Answers

Answer:

212 degrees

Explanation:

Answer:

212 degrees Fahrenheit

Explanation:

Similarly, if we heat a volume of water above 100 degrees Celsius, or 212 degrees Fahrenheit, water changes its phase into a gas called water vapor. Changes in the phase of matter are physical changes, not chemical changes.

how to predicting the acid-base properties of a binary oxide in water

Answers

We can predict the acid-base properties of a binary oxide in water based on the electronegativity difference between the two elements that make up the oxide.

To predict the acid-base properties of a binary oxide in water, we first need to understand what a binary oxide is. A binary oxide is a compound composed of two elements, one of which is oxygen. These oxides can be classified into acidic, basic, or amphoteric (having both acidic and basic properties) based on their behavior in water.
To predict the acid-base properties of a binary oxide in water, we need to look at the electronegativity difference between the two elements that make up the oxide. If the electronegativity difference is high, then the oxide will be acidic. An acidic oxide will react with water to form an acid, and it will donate a proton to the water molecule. For example, sulfur dioxide (SO2) is an acidic oxide that reacts with water to form sulfuric acid (H2SO4).
On the other hand, if the electronegativity difference between the two elements is low, then the oxide will be basic. A basic oxide will react with water to form a base, and it will accept a proton from the water molecule. For example, sodium oxide (Na2O) is a basic oxide that reacts with water to form sodium hydroxide (NaOH).
If the electronegativity difference is moderate, then the oxide will be amphoteric and will exhibit both acidic and basic properties. An example of an amphoteric oxide is aluminum oxide (Al2O3).
In summary, we can predict the acid-base properties of a binary oxide in water based on the electronegativity difference between the two elements that make up the oxide. If the difference is high, the oxide is acidic, if the difference is low, the oxide is basic, and if the difference is moderate, the oxide is amphoteric.

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The volume changes from 1.25L to 1.15L at a temperature of 313K, what is the final temperature?

Answers

Answer:

Below

Explanation:

Your question states the temperature is 313 K

to convert from K to °C   subtract 273.15

  313 K - 273.15 = 39.85 °C

for the reaction of copper with silver nitrate (use cu2 ), how many grams of silver can be produced from 1.40 g silver nitrate and excess copper?

Answers

1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper. The balanced chemical equation for the reaction of copper with silver nitrate (use cu2) is as follows: Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

To determine how many grams of silver can be produced from 1.40 g of silver nitrate and excess copper, we first need to calculate the limiting reactant.

The stoichiometry of the reaction is such that 2 moles of silver nitrate react with 1 mole of copper to produce 2 moles of silver. The molar mass of silver nitrate is 169.87 g/mol while that of copper is 63.55 g/mol,

therefore, the number of moles of silver nitrate present in 1.40 g can be calculated as follows:Number of moles of silver nitrate = mass/molar mass= 1.40/169.87= 0.008240 molSimilarly, the number of moles of copper required to react with this quantity of silver nitrate is 0.004120 mol (half of the number of moles of silver nitrate).

Since there is an excess of copper, it will not limit the reaction and hence the limiting reactant is silver nitrate.To calculate the mass of silver produced, we use the molar mass of silver, which is 107.87 g/mol.Mass of silver produced = number of moles of silver x molar mass= 0.01648 x 107.87= 1.78 g

Therefore, 1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper.

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among the trace minerals, which mineral is found in highest concentrations in the body? among the trace minerals, which mineral is found in highest concentrations in the body? zinc copper fluoride iron

Answers

The correct answer is option D.

Among the trace minerals, iron is the mineral that is found in highest concentrations in the body.

In human body, there are 21 trace minerals that are expected to be present including copper, zinc, iron cobalt, manganese, and fluoride.

The function of each trace mineral varies and they play huge role in the growth and development process.

For proper functioning of human body, only small quantities of these minerals are required. Among 21 minerals, iron is found in huge quantities.

Certain foods are rich sources of these minerals. However, deficiency or excess of these minerals can lead to serious health issues.

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determine the number of atoms in 1.37 ml m l of mercury. the density of mercury is 13.5 g/ml

Answers

There are approximately 1.11 x 10^22 atoms of mercury in 1.37 mL of mercury. to calculate the number of atoms, we need to first determine the mass of 1.37 mL of mercury using its density.

Density is defined as mass per unit volume, so we can calculate the mass of 1.37 mL of mercury as:

mass = density x volume

mass = 13.5 g/mL x 1.37 mL

mass = 18.495 g

Next, we need to convert the mass of mercury into the number of atoms. To do this, we use the molar mass of mercury, which is 200.59 g/mol. We can calculate the number of moles of mercury as:

moles = mass / molar mass

moles = 18.495 g / 200.59 g/mol

moles = 0.0922 mol

Finally, we can convert moles of mercury into the number of atoms using Avogadro's number, which is 6.022 x 10^23 atoms/mol:

number of atoms = moles x Avogadro's number

number of atoms = 0.0922 mol x 6.022 x 10^23 atoms/mol

number of atoms = 1.11 x 10^22 atoms

Therefore, there are approximately 1.11 x 10^22 atoms of mercury in 1.37 mL of mercury.

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Which four items are changes in the hazard communication standard for chemical labels and sds?.

Answers

The four items that change in the hazard communication standard for chemical labels and SDS

Product identifier.Signal word.Hazard statement.Pictograms.Precautionary statement.

This is further explained below.

What is the hazard communication standard?

Generally, The Hazard Communication Standard (HCS) was developed to ensure that employees have the "right to know" about any possible dangers that may be related to the work that they do. The HCS is a preventative strategy that is meant to distribute information to employees and employers about the health dangers that are associated with the chemicals that they handle and the protection that is necessary.

In conclusion, Hazard communication labels and SDS product identifiers have undergone four changes as a result of the new standard. The term serves as a signal to the driver. There is a risk. Pictograms. Statement of caution.

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What is the fate of the phosphate group that is removed when atp is converted to adp?.

Answers

In an endergonic reaction the phosphate group that is removed when atp is converted to adp, a reactant acquires it.

What is phosphate group?

A phosphate group is little more than a phosphorus atom bonded to four oxygen atoms, but despite this, it plays numerous significant roles. It is a component of nucleic acids like DNA and RNA, along with bases and sugars. It supplies energy for our muscles to move as a component of energy carriers like ATP.

Energy is released and ATP is changed into adenosine diphosphate when one phosphate group is removed by breaking a phosphoanhydride bond during a procedure known as hydrolysis (ADP).

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Leon and heidi decided to invest $3,000 annually for only the first eight years of their marriage. the first payment was made at age 25. if the annual interest rate is 10%, how much accumulated interest and principal will they have at age 65?

Answers

At age 65, Leοn and Heidi will have apprοximately $348,762 in accumulated interest and principal.

How to Tο calculate the accumulated interest and principal?

Tο calculate the accumulated interest and principal, we need tο cοnsider the annual cοntributiοns οf $3,000 οver eight years, cοmpοunded annually at an interest rate οf 10%.

First, let's calculate the future value οf the annual cοntributiοns οver eight years. We can use the fοrmula fοr the future value οf an οrdinary annuity:

\(\rm FV = P \times [(1 + r)^{n }- 1] / r\)

Where:

FV = Future Value

P = Annual payment amοunt

r = Interest rate per periοd

n = Number οf periοds

Using P = $3,000, r = 10% (οr 0.1), and n = 8, we have:

FV = 3000 * [(1 + 0.1)⁸ - 1] / 0.1

FV = 3000 * [(1.1)⁸ - 1] / 0.1

FV ≈ 3000 * (2.1436 - 1) / 0.1

FV ≈ 3000 * 1.1436 / 0.1

FV ≈ 34,308

Sο, the future value οf the annual cοntributiοns after eight years will be apprοximately $34,308.

Next, we need tο calculate the accumulated interest and principal at age 65. Tο dο this, we'll assume the accumulated amοunt earns cοmpοund interest at the same rate οf 10% per year frοm age 33 (after the first eight years οf cοntributiοns) tο age 65. We'll use the fοrmula fοr cοmpοund interest:

A = P * (1 + r)ⁿ

Where:

A = Accumulated amοunt

P = Principal (initial investment οr future value)

r = Interest rate per periοd

n = Number οf periοds

Using P = $34,308, r = 10% (οr 0.1), and n = 65 - 33 = 32, we have:

A = 34308 * (1 + 0.1)³²

A ≈ 34308 * (1.1)³²

A ≈ 34308 * 10.1487

A ≈ 348,762

Sο, at age 65, Leοn and Heidi will have apprοximately $348,762 in accumulated interest and principal.

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17. How many joules of heat are absorbed to raise the
temperature of 435 grams of water at 1 atm from
25°C to its boiling point, 100.°C?
A) 4.5 X 10^4 J
C) 2.5 X 10^7 J
B) 1.4 X 10^5 J
D) 7.4 X 10^7 J

Answers

The amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules

What is specific heat?

Specific heat is the amount of heat energy required to raise the temperature of a substance by one unit of temperature per unit of mass. It is a physical property that helps to characterize a substance and is typically measured in units of joules per gram per degree Celsius (J/g°C) or calories per gram per degree Celsius (cal/g°C).

The amount of heat absorbed to raise the temperature of a substance can be calculated using the formula:

Q = mcΔT

where Q is the amount of heat absorbed (in joules), m is the mass of the substance (in kilograms), c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

Substituting the given values, we get:

m = 435 grams = 0.435 kg

ΔT = 100°C - 25°C = 75°C

The specific heat capacity of water is 4.184 J/g°C. We can convert this to joules per kilogram per degree Celsius (J/kg°C) by dividing by 1000:

c = 4.184 J/g°C ÷ 1000 = 4.184 J/kg°C

Substituting these values, we get:

Q = (0.435 kg) × (4.184 J/kg°C) × (75°C)

Q = 140,089.2 J

Therefore, the amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules. The answer closest to this value is option (B).

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Which substance is an acid?

LiOH
Mg(OH)2
CH3COOH
NaCl

Answers

Answer:

C) CH3COOH Is the answer you are looking for

Explanation:

This one makes the most sense and the other ones don't fit in with the acids they aren't Acidic those are either bases or neutrals! :)

Hope this helps! :)

Answer:

CH3COOH

Explanation:

All of the following are qualitative tests that are often used to identify unknown ionic compounds except __________

Answers

All of the following are qualitative tests that are often used to identify unknown ionic compounds except titration.

Qualitative tests are conducted to determine the presence or absence of certain ions or compounds in a sample based on their characteristic reactions. Common qualitative tests include flame tests, precipitation reactions, color changes, and gas evolution tests.

Titration, on the other hand, is a quantitative technique used to determine the concentration of a specific substance in a solution by reacting it with a standardized solution of another substance. It is not typically used as a qualitative test for identifying unknown ionic compounds.

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If you want to produce 6.83 mol of Al;Os, with how many grams of Al must you start

Answers

We must start with 368.82 grams of Al to produce 6.83 mol of \(Al_{2} O_{3}\) .

The balanced reaction for the equation as follows:

\(4Al + 3O_{2}\) ⇒ \(2Al_{2} O_{3}\)

As we can see that 4 moles of Al reacts with 3 moles of \(O_{2}\) to produce 2 moles of \(Al_{2} O_{3}\), which means 108 grams of Al reacts with 96grams of \(O_{2}\) to produce 204 grams of \(Al_{2} O_{3}\).

Now,

2 mol of \(Al_{2} O_{3}\) react with 108 grams of Al

So,

6.83 mol of \(Al_{2} O_{3}\) react with = \(\frac{108}{2} *6.83\) grams of Al

6.83 mol of \(Al_{2} O_{3}\) react with = 368.82 grams of Al

Therefore, we must start with 368.82 grams of Al to produce 6.83 mol of \(Al_{2} O_{3}\) .

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1.24 g of phosphorous was burnt completely in oxygen to give 2.84 g of phosphorous oxide. Calculate the empirical formula of the compound.

Answers

The empirical formula of the compound that is formed is PO3.

What is the empirical formula?

We have to note that the empirical formula can be said to be the simplest formula of the substance that is under consideration. In this case the question said that we have to find the empirical formula of the compound that is formed.

The mass of oxygen is 2.84−1.24 = 1.60g

                                                  P                           O

Combining mass                   1.24g                       1.60g

No. of moles of atoms -   1.24/31= 0.04                 1.60/16= 0.10

Ratio of moles                                1                         2.5

Thus the empirical formula of the compound is PO3

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What is the charge of an atom containing 9 protons, 11 neutrons, and 12 electrons?

Answers

Answer:

Explanation: atom is changed to ion. There are 3 more electrons than

Protons, so charge is -3. Actually, F atom can gain only one electron.

Then it will have an octet (8 electrons)

A sealed 3.0L container has a pressure of 1.0 atm at 20.0 °C and is heated to a
temperature of 450. K. What is the pressure inside of the container at this temperature?

Answers

Answer:

1.0372kPa or 4.6075K

Explanation:

I don't know what one Mr. Williams wants but I got both of these

Which type of Electromagnetic wave has wavelength similar to the size of a 1 Peso coin

Answers

The microwave wavelength is the same as a one peso coin.

As you know, a peso coin is 24 mm in diameter. So the question becomes, what does an electromagnetic wave with a wavelength of 24mm look like? Wave velocity v, frequency f, and wavelength λ are related to each other. v=fλ

The velocity v in vacuum is the speed of light C₀ = 299792458 m/s. Therefore, the frequency is.

f=\(\frac{299792458m/s}{0,024m}\) = 12.5GHz

This is commonly called microwave and its frequency is called Ku band. It is commonly used in satellite communications.

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Which elements are both classified as metalloids?
Ge and As
Bi and Po
B and C
Si and P

Answers

Ge and As
they are lined up between the non metals and metals so they are metalloids

what ions are formed when sodium reacts with fluorine

Answers

Answer:

One example of an ionic bond is the formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom. In this reaction, the sodium atom loses its single valence electron to the fluorine atom, which has just enough space to accept it.

Explanation:

Sodium reacts with fluorine to form sodium fluoride

Na + F₂ --> NaF

This is an ionic bond formation NaF from sodium atom and fluorine atom. In this reaction, the sodium atom loses its single valence electron to the fluorine atom, which has just enough space to accept it.

3. Which is the most molecule that has the greatest number of atoms? a) H2SO4 b) 2002 c) CH3CH2COOH d) HNO3​

Answers

Answer:

HNO3 is the answer HNO3 is the answer

A gas has a volume of 150 cm3. Convert this volume into mL

Answers

Answer:

The answer is

150 mL

Explanation:

To convert the volume from cm³ to mL we use the conversion

1 cm³ = 1 mL

So from the question

if 1 cm³ = 1 mL

Then 150 cm³ = 150 mL

Hope this helps you

Which pair of compounds has the same empirical formula? c3h8 and c3h c2h2 and c2h c4h10 and c6h c4h10 and c2h5.

Answers

Answer:

The correct answer is the final pair: C4H10 and C2H5

Explanation:

Took the test and it was right. :)

\(C_4H_{10}\) and \(C_2H_5\) pair of compounds have the same empirical formula.

What is an empirical formula?

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule \(CH_2O\) is the empirical formula for glucose.

An empirical formula is the chemical formula of a compound that gives the proportions (ratios) of the elements present in the compound but not the actual numbers or arrangement of atoms.

This would be the lowest whole number ratio of the elements in the compound.

Hence, option D is correct.

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A electron with an initial speed of 500,000 m/s is brought to rest by an electric field. what was the potential difference that stopped electron? m= 9.11 x 10^-31 kg, e= -1.6 x 10^-19 c

Answers

The potential difference required to stop the electron is approximately -7,118.75 V. The negative sign indicates that the electron is moving in the opposite direction of the electric field.

Potential difference, also known as voltage, is a measure of the electric potential energy difference between two points in an electrical circuit. It represents the work done per unit charge to move a charge from one point to another in an electric field.

In simpler terms, potential difference is the driving force that allows electric charges to flow in a circuit. It is measured in volts (V) and is represented by the symbol "V".

A potential difference exists when there is a difference in electric potential between two points, causing electric charges to move from a higher potential to a lower potential.

Given:

Mass of the electron (m) = 9.11 x 10⁻³¹ kg

Initial speed of the electron (v) = 500,000 m/s

Charge of the electron (e) = -1.6 x 10⁻¹⁹ C

KE = (1/2) × m × v²

= (1/2) × (9.11 x 10⁻³¹ kg) × (500,000 m/s)²

= 1.139 x 10⁻¹⁵ J

The work done by the electric field is equal to the change in kinetic energy:

W = KE = 1.139 x 10⁻¹⁵ J

V = W / q

= (1.139 x 10⁻¹⁵ J) / (-1.6 x 10⁻¹⁹ C)

= -7.11875 x 10³ V

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An electron with an initial speed of 500,000 m/s is brought to rest by an electric field. The potential difference that stopped electron is 71.25 volts.

An electric field is a field of force that surrounds an electric charge or group of charges. The electric field is a vector field, meaning it has both magnitude and direction.

When an electron is brought to rest by an electric field, the electric potential energy is converted into kinetic energy and then dissipated as heat. The potential difference required to stop an electron can be calculated using the following equation:

∆V = KE/e

where KE is the kinetic energy of the electron, e is the charge of the electron, and ∆V is the potential difference required to stop the electron.

The kinetic energy of the electron can be calculated using the following equation:

KE = (1/2) \(\rm mv^2\)

where m is the mass of the electron, v is the initial velocity of the electron, and KE is the kinetic energy of the electron.

Substituting the given values into the above equations, we get:

KE = (1/2)\(\rm mv^2\)

= (1/2) \((9.11 \times 10^{-31}\ { kg} \ )\) ( \(500,000\) \(\rm m/s)^2\) = \(\rm 1.14 \times 10^{-17}\ { J}\)

∆V = KE/e

= \(\rm (1.14 \times 10^{-17} J)/(-1.6 \times 10^{-19}\ C) = -71.25\ { V }\)

Therefore, the potential difference required to stop the electron is 71.25 volts.

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(d) In the laboratory, the temperature is 295 K and the total pressure in the gas-collecting tube is 741.2 mmHg . If the vapor pressure of water at 295 K is 19.8 mmHg , determine the pressure of the H2(g) in the gas-collecting tube.

Answers

Answer: The pressure of the hydrogen in the gas-collecting tube is 721.3 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

\(p_{total}=p_{H_2O}+p_{H_2}\)

Given : \(p_{total}\) =total pressure of gases = 741.1 mm Hg

\(p_{H_2O}\) = partial pressure of water = 19.8 mm Hg

\(p_{H_2}\) = partial pressure of hydrogen = ?

putting in the values we get:

\(741.1 mm Hg=19.8mmHg+p_{H_2}\)  

\(p_{H_2}=721.3mm Hg\)

Thus  the pressure of the hydrogen in the gas-collecting tube is 721.3 mm Hg

According to the Dalton Law in a blend of non-reacting gases, the entire pressure will be equivalent to the total of partial pressures of the individual gases.

The pressure of H₂ gas collected in the tube will be 721.3 mm Hg.

This can be calculated by:

Dalton's formula:

\(\text{p}_{\text{total}} & = \text{p}\text{H}_{2} \text{O} + \text{p} \text{H}_{2}\)

Given :  

\(\text{p}_{\text{total}}\) = total pressure of gases = 741.1 mm Hg

\(\text{p}\text{H}_{2} \text{O}\) = partial pressure of water = 19.8 mm Hg

\(\text{p} \text{H}_{2}\)= partial pressure of hydrogen = ?

Now using the formula we will calculate:

\(\text{741.1 mm Hg} & = \text{19.8 mm Hg} + \text{p} \text{H}_{2}\)

\(721.3 \;\text {mm Hg} = \text{p} \text{H}_{2}\)

Therefore, the pressure of the hydrogen in the tube is 721.3 mm Hg.

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PLEASE HELPP!!!

Also please explain how you solved it

PLEASE HELPP!!!Also please explain how you solved it

Answers

The predicted volume of gas at 50 ºC is 0.53L.

The predicted volume of gas at 100 ºC is 0.61 L.

The predicted volume of gas at 150 ºC is 0.70 L.

What is Charles's law?

Charles's law states that pressure remains constant, and the volume of gas is directly proportional to its temperature.

V  ∝ T

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)                                                          ..................(1)

Given, the initial temperature of the gas, T₁ = 0 ºC = 273 K

The final temperature of the gas, T₂ = 50 ºC = 50 + 273 = 323 K

The initial volume of gas, V₁ = 0.45 L

\(\frac{0.45 }{273} =\frac{V_f}{323}\)

\(V_f =\frac{0.45\times 323 }{273} =0.53 L\)

The initial temperature of the gas, T₁ = 0 ºC = 273 K

The final temperature of the gas, T₂ = 100 ºC = 100 + 273 = 373 K

The initial volume of gas, V₁ = 0.45 L

\(\frac{0.45 }{273} =\frac{V_f}{373}\)

\(V_f =\frac{0.45\times 373 }{273} =0.61 L\)

The initial temperature of the gas, T₁ = 0 ºC = 273 K

The final temperature of the gas, T₂ = 150 ºC = 150 + 273 = 423 K

The initial volume of gas, V₁ = 0.45 L

\(\frac{0.45 }{273} =\frac{V_f}{423}\)

\(V_f =\frac{0.45\times 423}{273} =0.70 L\)

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you are asked to mix an additional experimental unknown and want to make sure the mixture is a challenging one. using observations and data from the completed experiment, develop a new three dye component mixture that may be difficult to analyze. explain why you chose this mixture

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To make a challenging mixture, I would choose three dyes with similar spectra, meaning that they absorb and emit light in similar regions of the spectrum. This would make it difficult to distinguish between the different dyes based on their spectra alone.

For example, I would choose a mixture of rhodamine B, eosin Y, and fluorescein. All three dyes are commonly used fluorescent dyes with similar spectra, making it difficult to differentiate between them based on fluorescence alone. Additionally, these dyes have similar chemical properties, making it difficult to separate them using chromatography methods.

By selecting dyes with similar spectra and chemical properties, I have created a mixture that will be challenging to analyze and may lead to interesting and complex results. This mixture would be a good candidate for further experimentation, as it would require careful analysis and interpretation of the data to accurately determine the composition of the mixture.

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