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What one would notice from the picture depend on the view point and the perspective of the person because different people looking at this elephant would notice a different thing according to their perception.
What is perspective?Perspective refers to how one views things. It is a method of art that modifies the size or depth of an item on paper. Farm owners' perspectives on a shortage of rain are an illustration of perception. In a picture, the train tracks appear to curve into the horizon as an illustration of perspectives.
For the person looking from the front elephant's teeth would appear like a spear, for the person looking at its leg would imagine a tree , for the person on the ladder the big structure of the elephant would appear like a wall,the person looking from the back on its tail would imagine it as a rope.
Thus, perspective is very crucial when we are looking at different things from different angles.
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Related Questions
The __________ might say that government action need only have a reasonable relation to the achievement of a legitimate government purpose to be constitutional.
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The rational basis test might say that government action need only have a reasonable relation to the achievement of a legitimate government purpose to be constitutional.
How does the rational basis test determine the constitutionality of government action?The rational basis test is a legal standard used by courts to evaluate the constitutionality of government action. Under this test, the government action is considered constitutional if it has a reasonable relationship to a legitimate government purpose.
In other words, the government must demonstrate that there is a rational basis for its action and that it is not arbitrary or discriminatory. Unlike stricter scrutiny tests, such as strict scrutiny or intermediate scrutiny, the rational basis test is more deferential to the government and allows for a wider range of justifications for the action.
It is often applied in cases involving economic regulations or social policies where fundamental rights or suspect classifications are not at issue.
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11) a truck with momentum 40,000 kg * m/s comes to rest and then reverses direction and now has momentum of -40,000 kg * m/s. what is the change in momentum
Answers
The change in the momentum of the truck is 80000 kg-m/s. If the truck comes to rest and then reverse its direction.
Momentum(p) of an object is nothing but the product of the mass(m) and the velocity(v). Momentum is used to calculate the applied force by a moving object that changes its state of motion. As the rate of change of momentum is equal to the force. Change of momentum for a very short time is known as the impulse. Momentum is a vector quantity.
Change in momentum(Δp) = initial momentum(p₁) - final momentum(p₂)
Initial momentum, p₁ = 40000 kg-m/s
Final momentum, p₂ = -40000 kg-m/s
Δp = 40000 - (-40000) = 80000 kg-m/s
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I have two charges of +4 x 10-5 C. If they are 0. 5 m apart, what is the electric force between them?
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Coulomb's law, states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them, can be used to compute the electric force.
The equation is: F = k * (q1 * q2) / r^2
where F is the electric force, k is Coulomb's constant (9 x 10^9 N * m^2 / C^2), q1 and q2 are the charges, and r is the distance between them. So, in this case, the electric force between the two charges of +4 x 10^-5 C would be:
F = (9 x 10^9 N * m^2 / C^2) * ((+4 x 10^-5 C) * (+4 x 10^-5 C)) / (0.5 m)^2
F = (9 x 10^9 N * m^2 / C^2) * (16 x 10^-10 C^2) / (0.5 m)^2
F = (9 x 10^9 N * m^2 / C^2) * (16 x 10^-10 C^2) / (0.25 m^2)
F = 36 x 10^9 N. So the force between the two charges is 36 x 10^9 N.
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I need the explanation too, if possible.
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When we arrange the objects in increasing strength of gravitational attraction, the following results:
Electron-butterflyElectron-dogButterfly-rockRock-dogHow do I arrange the objects in increasing order?To arrange the objects in increasing strength of gravitational attraction, we shall determine the gravitational force between each pair oif the objects. Details below:
For electron-dog:
Mass of electron (M₁) = 9.11×10⁻³¹ KgMass of dog (M₂) = 20 KgDistance apart (r) = 1 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 9.11×10⁻³¹ × 20) / 1²
F = 1.22×10⁻³⁹ N
For butterfly-rock:
Mass of butterfly (M₁) = 5.0×10⁻⁴ KgMass of rock (M₂) = 8 KgDistance apart (r) = 1 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.0×10⁻⁴ × 8) / 1²
F = 2.67×10⁻¹³ N
For electron-butterfly:
Mass of electron (M₁) = 9.11×10⁻³¹ KgMass of butterfly (M₂) = 5.0×10⁻⁴ KgDistance apart (r) = 1 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 9.11×10⁻³¹ × 5.0×10⁻⁴) / 1²
F = 3.04×10⁻⁴⁴ N
For rock-dog:
Mass of rock (M₁) = 8 KgMass of dog (M₂) = 20 KgDistance apart (r) = 1 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 8 × 20) / 1²
F = 1.07×10⁻⁸ N
From the above calculations, we have the gravitational attraction as:
Electron-dog = 1.22×10⁻³⁹ NButterfly-rock = 2.67×10⁻¹³ NElectron-butterfly = 3.04×10⁻⁴⁴ NRock-dog = 1.07×10⁻⁸ NThus, arranging in increasing order, we have:
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A home uses about 4*10^11 power joules of energy each year. In many parts of the United States there are about 3000 h of sunlight each year. How much energy from the sun falls on one square meter each year? If the solar energy can be converted to useful energy with an efficiency of 20%, how large an area of converters would produce the energy needed by the home?
Answers
Answer:
The Sun transfers in each second and amount of 1367J per square meter, so in hour it can transfer:
E = 60*60*1367 J/h*m2 = 4,921,200 J/h*m^2.
in one year, we have 3000h*4,921,200 J/h*m^2. = 14,763,600,000 Joules per square meter.
Now, only 20% of this can be used as energy, so the amount that can be used is:
E = 0.2* 14,763,600,000 J/m^2 = 2,952,720,000 J/m^2
Now, we want to find the number X of square meters such:
X*2,952,720,000 J/m^2 = 4x10^11 J
X = ( 4x10^11 J)/(2,952,720,000 J/m^2) = 135.5 m^2
So you only need around 135.5 square metters per house.
The population of bobcats in northern Arizona since 2008 can be modeled using the function b(t) = –0.32t2 + 2.7t + 253.
Answers
Answer:
In the given function b(t), the variable t represents the number of years after 2008. The domain of this function is . The range more than 258.7 would not make sense. The graph of the function is always continuous
The given function b(t) shows the population of bobcats in northern Arizona since 2008. Therefore the variable t represents the number of years after 2008.
Since t represents the number of years after 2008, which is either positive or zero, therefore the domain of this function is .
The given function is a quadratic function and the coefficient of is negative, so it is a downward parabola. The range above the y-coordinate of the vertex doesn't make any sense.
The vertex of parabola is defined by .
Vertex of the given function is (4.2,258.7).
Thus, the range more than 258.7 would not make sense for this function.
Since the given function is a polynomial function and polynomial functions are always continuous, therefore the graph of the function is always continuous
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A sphere with a charge q is fixed at the bottom left corner of the right triangle shown in the figure. Points P and R are at the location shown. A test charge is place at point P, and the charge-sphere system has potential energy U0. If the test charge is then moved to point R, what will the potential energy of the charge-sphere system be?
Answers
Answer:
the final potential energy of this system is 3U0/10
Explanation:
We are given
charge at left end and another test charge at point p
Potential energy is given by = \(\frac{k*Q1*Q2 }{R}\)
where k is electrostatics constant = \(9 *10^9\)
Q1 = first charge , Q2= test charge
R= distance between charges
potential at point p
U0 = k*Q1*Q2 /3 ⇒ kq1q2 = 3U0 ..............1
now the test charge moves to point R
using Pytahgoreou theorem
R(distance) = \(\sqrt{8^2 + 6^2}\) = 10
New Potential energy
U1 = kq1*q2 / 10
substituting kq1q2 = 3U0 from 1
U1 = 3U0/10
So this is the final potential energy of this system.
If you go twice as fast, your kinetic energy becomes.
2 times smaller
4 times smaller
2 times bigger
4 times bigger
Answers
Answer:
Our kinetic energy becomes 4 times bigger
Find the direction of the sum ofthese two vectors:BW TOT60.0 °85.0 mA
Answers
We are given two vectors and we are asked to determine the direction of their sum. To do that we will rewrite them on coordinates form. For vector A, since it is a horizontal vector it only has an x-coordinate equivalent to its magnitude, like this:
\(A=(85,0)\)For vector B we will use the following formula:
\(B=(\lvert B\rvert\cos \theta,\lvert B\rvert\sin \theta)\)Replacing the values:
\(B=(101\cos 60,101\sin 60)\)Solving the operations
\(undefined\)The heights of mature pecan trees are approximately normally distributed with a mean of 42 feet and a standard deviation of 7.5 feet. What proportion of pecan trees are between 43 and 46 feet tall? (A) 0.1501 (B) 0.2969 (C) 0.4470 (D) 0.5530 (E) 0.7031
Answers
The proportion of pecan trees between 43 and 46 feet tall is 0.1501.
What is the z-score?The z-score formula is given by:
z = (x - μ) / σ
Where:
x is the given value (height)
μ is the mean of the distribution (42 feet)
σ is the standard deviation of the distribution (7.5 feet)
For 43 feet:
z(43) = (43 - 42) / 7.5 = 0.1333
For 46 feet:
z(46) = (46 - 42) / 7.5 = 0.5333
Subtracting the smaller value from the larger value gives us the proportion between the two heights.
Using the standard normal distribution table, we find:
P(z < 0.1333) ≈ 0.5530
P(z < 0.5333) ≈ 0.7031
Therefore, the proportion of pecan trees between 43 and 46 feet tall is: 0.7031 - 0.5530 = 0.1501.
Thus, the correct answer is (A) 0.1501.
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A train car With a mass of 1650kg is moving east at 2m/s. It collides with an identical train car, Which is stationary. What will the result velocity of the combinad train cars be if the colisión is perfectly ineslastic
Answers
Answer:
the combined train cars will be moving east at a speed of 1 m/s after the perfectly inelastic collision.
Explanation:
First, we can calculate the initial momentum of the first train car before the collision:
p1 = m1v1 = 1650 kg * 2 m/s = 3300 kgm/s east
Since the second train car is stationary, its initial momentum is zero:
p2 = m2*v2 = 0
The total momentum before the collision is therefore:
p_total = p1 + p2 = 3300 kg*m/s east
After the collision, the two train cars stick together and move as one, so we can treat them as a single object with a combined mass of 2*m1 = 3300 kg. Let's call the final velocity of the combined train cars v_final.
The conservation of momentum tells us that the total momentum after the collision is also p_total, so we can write:
p_total = m_total * v_final
Substituting in the values we have:
3300 kg*m/s east = 3300 kg * v_final
Solving for v_final, we get:
v_final = 1 m/s east
So the combined train cars will be moving east at a speed of 1 m/s after the perfectly inelastic collision.
square steel bar with an ultimate strength of 58 ksi can hold how much load in tension before breaking? A. 29 Kips B. 11.39 Kips C. 14.5 Kips D. None of the above ਦੇ 15. Internal Stresses The best way to increase the moment of inertia of a cross section is to add material: A. Near the center B. On all sides of the member At as great a distance from the center as possible D. In a spiral pattern 16. Internal Stresses: The formula for calculating maximum internal bending stress in a member A. Is bending moment divided by section modulus 8. Is bending moment times section modulus C Requires complex computer computations D. None of the above 17. Internal Stresses: An A36 steel bar has a precise yield strength of 36 Ksi. It will yield when: A Bending stresses exceed 36 ksi B. Bending stresses exceed 1.5 3G Ksi C. Ultimate stress is reached D. All of the above 18. Internal Stresses: For a horizontal simple span beam of length 1 that is loaded with a uniform load w, the maximum shear will: A. Occur adjacent to the support points B. Be equal to the twice vertical reaction at the support C. Be equal to w 1/4 D. All of the above 19. Internal Stresses: For a horizontal simple span beam that is loaded with a uniform load, the maximum moment will: A. Occur adjacent to the support points B. Be equal to the twice vertical reaction at the support C Be equal to w"1"1/8 D. None of the above
Answers
To determine the maximum load a square steel bar can hold in tension before breaking, we need to consider the ultimate strength of the material. Given that the ultimate strength of the steel bar is 58 ksi (kips per square inch), we can calculate the maximum load as follows:
Maximum Load = Ultimate Strength x Cross-sectional Area
The cross-sectional area of a square bar can be calculated using the formula: Area = Side Length^2
Let's assume the side length of the square bar is "s" inches.
Cross-sectional Area = s^2
Substituting the values into the formula:
Cross-sectional Area = (s)^2
Maximum Load = Ultimate Strength x Cross-sectional Area
Maximum Load = 58 ksi x (s)^2
The answer cannot be determined without knowing the specific dimensions (side length) of the square bar. Therefore, the correct answer is D. None of the above, as we do not have enough information to calculate the maximum load in tension before breaking.
Regarding the additional statements:
The best way to increase the moment of inertia of a cross-section is to add material at as great a distance from the center as possible.
The formula for calculating maximum internal bending stress in a member is bending moment divided by the section modulus.
An A36 steel bar will yield when bending stresses exceed 36 ksi.
For a horizontal simple span beam loaded with a uniform load, the maximum shear will occur adjacent to the support points.
For a horizontal simple span beam loaded with a uniform load, the maximum moment will occur adjacent to the support points.
These statements are all correct.
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What is the electric field 6.44 m from the centre of the terminal of a Van de Graaff with a 9.82 m charge, noting that the field is equivalent to that of a 3.811C charge at the centre of the terminal?
Answers
The electric field at 6.44 m from the center of the terminal of a Van de Graaff generator with a 9.82 mC charge is 1530 N/C.
Electric field is a measure of the force that an electric charge experiences when it is placed in an electric field. The electric field at a point in space is proportional to the charge at that point and inversely proportional to the square of the distance from the point to the source of the field.
In this case, the electric field at 6.44 m from the center of the terminal of the Van de Graaff generator is equivalent to the field produced by a 3.811 C charge at the center of the terminal.
Using the formula for electric field, E = kQ / r^2, where E is electric field, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), Q is the source charge (3.811 C), and r is the distance from the source (6.44 m), we can calculate the electric field to be 1530 N/C.
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what would happen to our vision if the lens of our eyes were concave? defend your answer NO LINKS!!!
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If the lens of our eyes were concave, we would not be able to see. We would be blind. This is because our eyes form a visual image on the same side of the lens at the object being viewed. Thus, a concave lens would result in the visual image focusing in front of the eye, not the retina inside the eye. This would mean that no signals would be sent to the brain, and vision would not be possible.
below are diagrams for the bright line spectra of four elements and the spectrum of a mixture of unknown gases.which elements are in the unknown?
A) Li
B) H
C)He
D)Na
Answers
The elements which are in the unknown according to the diagram given is He and is therefore denoted as option C.
What is a Spectra?This is referred to as a type of graph which shows the intensity of light being emitted over a range of energies and it varies with properties such as wavelength or frequency. When light is passed through a prism, band of colors are usually observed which signifies light spectrum with the plural being spectra.
In the diagram given , the element He and the unknown have the most similar spectra observed as a result of the lines which fall in almost the same range and place and it makes it the most likely component of the mixture of unknown gases.
This is therefore the reason why option C was chosen as the most appropriate choice.
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What is the name for this timeboxed iteration?
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Scrum teams typically use brief iterations to get fast feedback from a variety of customers at a particular time.
This time-boxed iteration is referred to in Scrum as a Sprint, and it typically lasts one week. A timeboxed iteration is a time-restricted period during which the team concentrates on a single objective and creates a new piece of software. This is a sprint in the Scrum methodology where the team works toward the sprint goal specified in the sprint planning. A timebox is a set amount of time during which a person or a team works to achieve a common objective. Timeboxing is a tool used in agile project management to keep work moving quickly and on schedule. It is also an important part of Scrum.
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A 230 v mains powered electrical drill draws a current of 2.5 A calculate the power of the drill at use
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a gold ingot weighs 5.50 lbs. if the density of gold is 19.31 g/cm3, and the length and width of the ingot are 12.0 cm and 3.00 cm respectively, what is the height of the ingot?
Answers
If the density of gold is 19.31 g/cm3, and the length and width of the ingot are 12.0 cm and 3.00 cm respectively,The height of the ingot is h = 3.59 cm.
Calculation :-
Mass is the product of volume and density.
Given Data
ρ=19.31 g/cm³
m=5.50 lbs
=5.50×453.592370 g
=2494.758035 g
l=12.0 cm
b=3.0 cm
h=? cm
V=lbh
m=Vρ
⇒(lbh)ρ=m
⇒h=m/lbρ
=2494.758035 / (12)(3)(19.31)
=3.58875 cm
Therefore, the height of the ingot is h=3.59 cm
Height is a measure of vertical distance, either vertical distance (the height of something or someone) or vertical position (the "height" of a point). For example, "This building is 50m high" or The altitude of the plane in flight is about 10,000m.
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the current is 0.08A calculate the amounts of charge passing a point in the circuit in 2 minutes
Answers
Answer:
Charge is 9.6 Coulombs
Explanation:
- From definition of current, current is rate of flow of charge in a circuit
\(current = \triangle(charge) \\ \\ current = \frac{charge}{time} \\ \\ { \boxed{ I = \frac{Q}{t} }}\)
- From the question above,
I is 0.08AQ is ?? (needed)t is 2 mins = (2 × 60) = 120 s\(0.08 = \frac{Q}{120} \\ \\ Q = 120 \times 0.08 \\ \\ Q = 9.6 \: C\)
If a dog ran at 5m/s,how far would it run in 45 s?
Answers
Answer:
225 meters
Explanation:
45*5 or 225 meters.
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vector may be zero .why?
Answers
Answer:
We define a vector as an object with a length and a direction.With no length, the zero vector is not pointing in any particular direction, so it has an undefined direction.
Explanation:
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A runner is moving at a speed of 8. 8m/s rounds a bend with a radius of 25m
Answers
Answer:
Explanation:
To solve this problem, we need to use the formula for centripetal force:
F = (mv^2) / r
Where:
F = centripetal force
m = mass of the object
v = velocity of the object
r = radius of the circular path
Assuming the mass of the runner is 70 kg, we can plug in the given values and solve for the centripetal force:
F = (70 kg)(8.8 m/s)^2 / 25 m
F ≈ 217.6 N
Therefore, the centripetal force required to keep the runner moving in a circular path with a radius of 25 m and a speed of 8.8 m/s is approximately 217.6 N.
A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
Lars is balancing equations with his study group. He is unsure about one equation because each member of the study group came up with a different answer. Which is the proper way to balance the equation Ca(OH)2 + H3PO4 → Ca3(PO4)2 + H2O?
Answers
Follow my lead or ur answer is very wrong
a proton traveling vertically upward (out of the page) experiences a magnetic force directed north. the direction of the magnetic field is .
Answers
A proton moving out of another page vertically encounters a magnetic pull that points north. The magnetism is moving southward.
What is a magnet, please?A magnet is any object that generates its own magnetic field and interacts with other magnetic fields. A magnet has two poles, this same north pole and indeed the south pole. The magnetic field of a magnet is depicted by field lines that start at its north pole but stop at its south pole.
What is in a magnet?Most permanent magnets have iron, chromite, or cobalt as their principal metals. Cobalt, nickel, and aluminum are combined to form the alloy known as Alnico.
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Your younger brother tells you about a television show he watched where humans ride dinosaurs instead of cars. He says he wishes he could go back to the time when people lived with dinosaurs. Based on what you learned in this activity, what do you tell him?
Answers
A rock group is playing in a bar. Sound emerging from the door spreads uniformly in all directions. The intensity level of music is 40. 4 dB at a distance of 4. 97 m from the door. At what distance is the music just barely audible to a person with a normal threshold of hearing? Disregard absorption
Answers
Disregard absorption. The threshold of hearing is 10^-12 W/m2.The formula used to calculate the intensity of sound isI = I₀(r₀ / r)², Where I₀ = 10^-12 W/m² r₀ = 1 m, and r = distance from the source of sound. A decibel level of 40.4 dB indicates that the sound's intensity level is 10^ (40.4/10) times more than the threshold of hearing.
I = I₀ × 10^(dB/10)I = 10^-12 × 10^(40.4/10)I = 2.512 × 10^-8 W/m².
Let, x be the distance from the door where the sound's intensity level is barely audible.
I₀(r₀ / x)² = 2.512 × 10^-8W/m²(r₀ / x)² = 2.512 × 10^-8 / I₀(r₀ / x)² = 2.512 × 10^-8 / 10^-12(r₀ / x)² = 2.512 × 10^4r₀² / x² = 2.512 × 10^4x² = r₀² / 2.512 × 10^4x = r₀ / sqrt(2.512 × 10^4)x = (1 m) / sqrt(2.512 × 10^4)x = 0.02 m or 2 cm.
Therefore, the distance at which the music is just barely audible to a person with a normal threshold of hearing is 2 cm from the door.
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A block of mass 60kg measures 6cm by 5cm by 4cm. Calculate i) The maximum pressure it can exert. The minimum pressure. ii) A block of mass 60kg measures 6cm by 5cm by 4cm . Calculate i ) The maximum pressure it can exert . The minimum pressure . ii )
Answers
Answer:
4.9 is the answer
Explanation:
pressure is force divided by area
force = mass x acceleration due to gravity
= 60kg x 9.8 m/s
area = length x width x height
=6 x 5 x 4
= 120
pressure = 588/120
= 4.9 pascal
The correct answer for the value of (i) Maximum pressure is \(24.5 \dfrac{N}{cm^2}\)(ii)Minimum pressure is \(19.6 \dfrac{N}{cm^2}\).
Given:
Weight of the block: \(60\) kg
Dimensions of the box: \(6 *4* 5\)
Value of gravitational constant: \(9.8\) m/s²
Now,
\(Pressure = \dfrac{Force}{Area}\)
\(Force = mass*accelaration\)
\(= 60 * 9.8\)
\(= 588 N\)
Minimum pressure is when area is maximum:
\(= \dfrac{588}{6*5}\\\\= 19.6 \dfrac{N}{cm^2}\)
Maximum pressure when area is minimum:
\(= \dfrac{588}{6*4} \\\\= 24.5 \dfrac{N}{cm^2}\)
Maximum and minimum pressure are \(24.5 \dfrac{N}{cm^2}\) and \(19.6 \dfrac{N}{cm^2}\) respectively.
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2. State law of conservation of
momentum and apply conservation of
momentum in elastic collision of two
objects.
Answers
Answer:
In collisions between two isolated objects Newton's third law implies that momentum is always conserved. In collisions between two isolated objects momentum is always conserved. Kinetic energy is only conserved in elastic collisions.
Explanation:
Diana raises a 1000 N piano using a set of pulleys. She use 250 N force to pulls in 20.0 m of rope. What is the distance
Answers
Using a set of pulleys, Diana hoists a piano weighing 1000 N. To draw in 20.0 m of rope, she applies 250 N of force. The separation is 5m.
given,
Load force = 1000 N
Effort distance = 20.0 m
Effort force=250N
If this were an ideal machine, we could calculate the force Diana applied as follows:
The equation that follows links load force to effort force for a perfect machine;
Effort force × effort distance = Load force × Load distance
When we enter the parameters into the formula, we get;
Load distance = Effort force × effort distance/Load force
=250×20/1000
= 5 m
Load distance = 5 m
In mechanics, force is any action that tends to maintain or alter the motion of a body or distort it. The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, as stated in his Principia Mathematica (1687). Newton's first principle states that a body at rest or moving at a uniform rate in a straight line will remain in that state until some force is applied to it. The second law states that when an external force acts on a body, it causes an acceleration (change in velocity) of the body in the direction of the force.
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