What do the numbers and densities of the craters imply about the relative ages of these two regions of the Moon? Do your results support your working hypothesis? Comment, making sure you include the effects of uncertainties in identifying and including all craters. The number vs the densities of the craters, it looles like the upper mare region is younger than the 3.7, Gyra the age of the cratered highidhds region is between 3.8 Gyr. & 3.9 Gyr. Uncertains in the measurements CMO! from not guessing the Craiters accurately especially the smell ones... 5. Comparing crater densities on a terrestrial world easily leads to statements of relative ages, but relating crater densities to actual ages for the Moon required our sending astronauts there to bring back rocks to be dated based on radioactive isotopes. Based on your results, what are the approximate ages or age ranges for the cratered highlands region and the upper mare region?

Answers

Answer 1

The number and densities of craters on the Moon provide important clues about the relative ages of its different regions. Craters are formed by the impact of meteoroids, asteroids, or comets, and the more craters a region has, the longer it has been exposed to such impacts. Therefore, the region with more craters is generally considered to be older.

In this case, the upper mare region has a lower density of craters than the cratered highlands region, which suggests that it is younger. However, it is important to note that uncertainties in identifying and including all craters can affect the accuracy of this conclusion. For instance, smaller craters may be missed, or some craters may be misidentified as a result of factors such as lighting conditions or image resolution.

Despite these uncertainties, the data from this study suggest that the upper mare region is likely younger than the cratered highlands region. The estimated age range for the highlands region is between 3.8 and 3.9 billion years, while the upper mare region appears to be younger than that. However, it is difficult to provide a precise age range without additional data or samples from the Moon.

It is worth noting that relating crater densities to actual ages for the Moon required the collection of samples from the Moon's surface, which were then analyzed using radiometric dating techniques. These techniques allowed scientists to determine the ages of rocks and other materials on the Moon, and to develop a more precise understanding of the Moon's geological history.

Overall, the data from this study suggest that the upper mare region is likely younger than the cratered highlands region, which supports the working hypothesis that the mare regions are younger than the highlands regions. However, uncertainties in the data mean that additional studies and data collection may be necessary to confirm these conclusions with greater accuracy.

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Related Questions

A student connects a circuit
with a cell, an ammeter, and a
buzzer and listens to the buzzer.
She adds another cell.
Describe and explain what
happens to the current

Answers

Answer:

let the voltages of the cell be V and R the equivalent resistance of the circuit.

 

I1=RV∵ only one cell connected  ;

I2=RV+V=R2V∵ two cells connected in series  ;

I3=RV+RV=R2V∵ two cells connected in parallel ⇒ total current is same as sum of the currents due to each.

Now , 

LHS = 3I3I2=3R2VR2V=3(R24V2) 

RHS = 2I3(I1+I2)=2R2V(RV+R2V)=2R2VR3V=3R2therefore, LHS = RHS   

The volume of a piece of metal of a mass 6 gram is 15cm3. What is the density of the metal piece?

Answers

Answer:

0.4 g/cm^3

Explanation:

The density of an object can be found using the following formula.

d= m/v

where m is the mass and v is the volume.

The mass of the metal is 6 grams and the volume is 15 centimeters^3

m=6 g

v= 15 cm^3

Substitute these into the formula.

d= 6 g/ 15 cm^3

Divide 6 g by 15 cm^3 (6/15=0.4)

d= 0.4 g/ cm^3

The density of the metal is 0.4 grams per cubic centimeter.

Density = (mass) / (volume)

Density = (6 g) / (15 cm³)

Density = (6/15) (g/cm³)

Density = 0.4 g/cm³

This 'metal' has less than half the density of water, and it floats on water !  It cannot be of Earthly origin, and must have been dropped here by aliens.

Either that, or else the metal has been hammered and stretched and beaten out and shaped so that it has an artificially large volume ... something like the way sailing ships are made out of thick plates of steel.

an electrically charged object can be used to attract:

Answers

An electrically charged object can be used to attract any object with an opposite charge.

This is due to the fundamental principle that opposites attract and repel in physics.

Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.

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an object is placed on a ramp and slides to the ground. if the ramp makes an angle of 40 degrees with the ground and the object weighs 25 pounds. find the acceleration of the object

Answers

The acceleration of an object weighing 25 pounds placed on a ramp making a 40-degree angle with the ground is

≈ 6.35 m/s²

Here, convert the weight of the object (25 pounds) to mass (m) using the formula:

weight = mass × gravity.

Since the standard acceleration due to gravity (g) is approximately 9.81 m/s², we can find the mass in kilograms (kg) using the conversion factor: 1 pound = 0.453592 kg:

  Mass (m) = (25 pounds) × (0.453592 kg/pound) ≈ 11.3398 kg

Then, calculate the gravitational force acting on the object parallel to the ramp using the formula:

F parallel = m × g × sin(θ)                           where, θ is the angle between the ramp and the ground.

F parallel = (11.3398 kg) × (9.81 m/s²) × sin(40°)

                   ≈ 71.992 N

Now, determine the acceleration (a) using Newton's second law, F = ma:

  a = F parallel / m

  a = (71.992 N) / (11.3398 kg) ≈ 6.35 m/s²

So, the acceleration of the object sliding down the ramp is approximately 6.35 m/s².

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at aphelion, if the gravity between earth and the sun (as well as other planets) suddenly vanished, which way would earth move initially?

Answers

Our planet's land-filled northern half is tilted toward the Sun at aphelion. Land has a lower heat capacity than water because it warms up more quickly for a given amount of sunshine.

As a result, the northern hemisphere of our planet is more effectively warmed by sunlight. Normally, the June Solstice is followed by the aphelion by around two weeks of heat capacity. As was already mentioned, celestial bodies do not move in perfectly circular orbits. aphelion describes them. The heavenly bodies must therefore pass through a location of our planet, where they are both farthest from and closest to the sunshine.

The amount of heat capacity to produce a unit change in an object is known as the heat capacity or thermal capacity of a sunshine.

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How many unit vectors are there for which cos alpha = 1/2 and cos beta = 1/2, where alpha and beta are angles made with x-axis and y-axis respectively.

Answers

There are two unit vectors for the given values of cos α and cos β where alpha and beta are angles made with x-axis and y-axis respectively.

It is given that,

cos α = 1/2

cos β = 1/2

We know the relation between cos α, cos β and  cos γ as,

cos²α + cos² β + cos² γ = 1

Putting the known values in the above equation, we have,

1/4 + 1/4 + cos² γ = 1

1/2 + cos² γ = 1

cos² γ = 1/2

cos γ = ± 1/√2

So, two values of cos γ are possible.

Thus, two unit vectors are possible. One corresponding to the direction cosines 1/2, 1/2, 1/√2 and other corresponding to the direction cosines 1/2, 1/2, -1/√2.

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To be effective, why must agreement aimed at preventing or reducing ozone depletion be international?
I have to get it done.. it's pass due

Answers

To be effective, there must be must agreement aimed at preventing or reducing ozone depletion by the international government and the various international organizations.

What is pollution?

It can be defined as the origination of the contaminant substance that poisonous or harmful to our natural environment.

The Montreal Protocol is an international agreement that was established to safeguard the earth's atmosphere by gradually banning the manufacturing and use of chemicals that damage the ozone layer (ODS).

Thus, For an agreement between the different international organizations and the international government to be effective, it must be targeted at avoiding or mitigating ozone depletion.

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hey guys, is this question for a series circuit or for parallel?
And, just so you know, E.m.f stands for electro-motive force​

hey guys, is this question for a series circuit or for parallel?And, just so you know, E.m.f stands for

Answers

Answer:

I need help with the same question

Explanation:

Jose applies a force of 20 N North, Johnny applies a force of 10 N West and Janie applies a force of 25 N south on a heavy dresser. Find the resultant force on the dresser.

Answers

Answer:

Resultant force of the given forces: approximately \(11.2\; {\rm N}\) at approximately \(53^{\circ}\) west of south.

Explanation:

The resultant force of these forces will be:

\(25\; {\rm N} - 20\; {\rm N} = 5\; {\rm N}\) to the south (the \(20\; {\rm N}\) force to the north partially balances the \(25\; {\rm N}\) force to the south), and\(10\; {\rm N}\) to the west.

Refer to the diagram attached. The resultant \(5\; {\rm N}\) force to the south and the \(10\; {\rm N}\) force to the west are perpendicular to each other, forming the two legs of a right triangle. The hypotenuse of this right triangle will be the net effect of these two forces.

Apply Pythagorean's Theorem on this triangle to find the magnitude of this net effect:

\(\begin{aligned}(\text{length of hypotenuse}) &= \sqrt{10^{2} + 5^{2}} \approx 11.2\end{aligned}\).

Hence, the magnitude of this net effect will be approximately \(11.2\; {\rm N}\).

Let \(\theta\) denote the angle between this resultant force and west. In this right triangle:

\(\begin{aligned} \tan(\theta) &= \frac{(\text{opposite})}{(\text{adjacent})} \\ &= \frac{5\; {\rm N}}{10\; {\rm N}} \\ &= \frac{1}{2}\end{aligned}\).

\(\begin{aligned} \theta &= \arctan\left(\frac{1}{2}\right) \approx 27^{\circ}\end{aligned}\).

Hence, the angle between this resultant force and south will be approximately \((90^{\circ} - 27^{\circ}) = 63^{\circ}\). This resultant force will be at approximately \(63^{\circ}\) west of south.

Jose applies a force of 20 N North, Johnny applies a force of 10 N West and Janie applies a force of

a common procedure for increasing the moisture con- tent of air is to bubble it through a column of water. the air bubbles are assumed to be spheres, each having a radius of 1 0 mm, and are in thermal equilibrium with water at 298 k. determine how long the bubble should remain in the water to achieve a vapor concentration at the center that is 90% of the maximum possible (saturation) concentration. assume that the air is dry when it enters the column of water and that the air inside the small bubble is stagnant. the vapor pressure of water versus temperature is available from many sources, including the steam tables.

Answers

To achieve 90% of maximum vapor concentration, the bubble should remain in water for a calculated time.

"How long for bubble to reach 90% vapor concentration?"

To determine the time required for a bubble to achieve 90% of the maximum vapor concentration, we need to consider the diffusion process. The diffusion rate can be described by Fick's law, which states that the rate of diffusion is proportional to the concentration gradient. In this case, the concentration gradient will be between the water surface and the center of the bubble.

First, we need to calculate the maximum possible vapor concentration at the given temperature of 298 K using the vapor pressure of water. Once we have this value, we can calculate 90% of it.

Next, we can calculate the diffusion coefficient for water vapor in air using available data. The diffusion coefficient depends on temperature, pressure, and the molecular properties of the substances involved.

Using Fick's law, the diffusion rate can be calculated as the product of the diffusion coefficient and the concentration gradient. We can assume a steady-state diffusion process, which means the rate of vapor entering the bubble is equal to the rate of diffusion out of the bubble.

Finally, we can determine the time required for the bubble to reach 90% of the maximum vapor concentration by dividing the distance from the surface to the center of the bubble by the diffusion rate.

Overall, the calculation involves determining the maximum vapor concentration, finding the diffusion coefficient, calculating the diffusion rate, and finally, determining the time required for the bubble to achieve 90% of the maximum concentration.

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A student holds two iron magnets, one in each hand. The south pole of one magnet is pointed toward the south pole of the other magnet. As the magnets get closer to each other, they will–
A-attract more strongly.
B-attract more weakly.
C-repel more strongly.
D--repel more weakly.

Answers

repel more weakly.........

you attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 v no matter what you do and there is an h on the screen. what's going on?

Answers

The multimeter is probably broken and you should give it to your instructor/TA is used to measure the electric potential difference, but the value stays at 0.00 v no matter what you do and there is an h on the screen.

What is a multimeter?

A multimeter is an electronic instrument used to measure electrical properties such as voltage, current, and resistance. It is also known as a multi-tester, VOM (volt-ohm-milliammeter), or DMM (digital multimeter). Multimeters are an essential tool for electricians and other technicians, as they allow for accurate and precise measurements of various electrical values. Multimeters are available in a range of styles and designs, from basic models to more advanced versions with additional features.This means that the multimeter is not taking any readings and is displaying the last measured value. You may need to press the "hold" button on the multimeter to turn it off and allow it to take new readings.

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3. You attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 V no matter what you do and there is an H on the screen. What's going on?

The multimeter is probably broken and you should give it to your instructor/TA.You probably plugged in the wires incorrectly. Try using the 10A and V ports.Someone pressed the "Hold" button. If you press it again, the multimeter should work correctly.Someone pressed the "Handheld" button. The multimeter will only work if you hold it in your hand while using it.

Mass is a measure of the amount of
matter in a substance. Which of the
following is TRUE about mass?
A. Mass can be measured using a triple beam balance.
B. Mass and volume can be measured using a
graduated cylinder.
C. Mass and length can be measured using a ruler.
D. Mass and temperature can be measured using a
thermometer.

Answers

Answer:

A

Explanation:

Can read mass precisely, commonly reading error of +0.05g

Mass is a measure of the amount of matter in a substance.  Mass can be measured using a triple beam balance. Hence option (A) is correct.

What is mass?

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has. The kilograms serves as the unit of mass in the International System of Units (SI).

The conservation of mass principle states that no matter how an object's component pieces are rearranged, the object's overall mass remains constant. If a body splits into parts, the mass also splits into pieces, therefore the original mass is equal to the sum of the masses of the individual fragments. Alternatively, if two or more particles are combined, the mass of the resulting composite equals the total of the masses of the individual particles. This rule is not always accurate, though.

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Room temperature is about 77°F. Which temperature is an equivalent temperature?

Answers

Answer:25

Explanation:

Formula(77°F − 32) × 5/9 = 25°C

Answer: The answer is C. 298 K

Explanation:

A new version of the starship rocket has a length of 50 m. It is designed to travel at 0.4 c. What would be the length of the craft traveling at that speed? Group of answer choices 46 m 53 m 49 m 50 m

Answers

The length of the starship rocket as observed by the observer would be approximately 54.5 m.

The closest answer choice is B, 53 m.

What would be the length of the craft traveling at that speed?

According to special relativity, the length of an object moving at a high velocity relative to an observer will appear shorter than its rest length. This effect is known as length contraction.

The formula for length contraction is:

L = L0 / √(1 - v²/c²)

where;

L0 is the rest length of the object,

v is its velocity relative to the observer,

c is the speed of light, and

L is its observed length.

In this case, the rest length of the starship rocket is 50 m and its velocity relative to the observer is 0.4 c. Plugging these values into the formula, we get:

L = 50 / √(1 - (0.4c)²/c²)

L = 50 / √(1 - 0.16)

L = 50 / √(0.84)

L = 50 / 0.917

L ≈ 54.5 m

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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.

If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?

Answers

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

What is the sound's velocity?

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

Briefing:

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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What is the weight of a bear that has a mass of 550 kg

Answers

Answer:

a female polar bear weighs 550 kg

Answer:

So female bear weighs 550 kg

Explanation:

which are cardiovascular drug classes? select all that apply

Answers

Cardiovascular drug classes are Beta-blockers, Diuretics, Calcium channel blockers, and ACE inhibitors. The correct answer is options are A, B, D, and F.

Cardiovascular drug classes refer to categories of medications specifically designed to treat conditions related to the cardiovascular system. These medications target various aspects of cardiovascular health, such as blood pressure regulation, heart rhythm management, and the prevention of clot formation. Several recognized cardiovascular drug classes include:A) Beta-blockers: These drugs block the effects of adrenaline on the heart and blood vessels, reducing heart rate and blood pressure.B) Diuretics: Also known as water pills, diuretics help eliminate excess fluid from the body, reducing fluid buildup and decreasing blood pressure.D) Calcium channel blockers: These medications relax and widen blood vessels, improving blood flow and reducing blood pressure. They also help regulate heart rate.F) ACE inhibitors: ACE (angiotensin-converting enzyme) inhibitors lower blood pressure by blocking the production of a hormone that narrows blood vessels.Therefore, the correct options for cardiovascular drug classes are A) Beta-blockers, B) Diuretics, D) Calcium channel blockers, and F) ACE inhibitors. These medications play crucial roles in managing cardiovascular conditions and promoting overall heart health.

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The correct question would be as

Which of the following are cardiovascular drug classes? Select all that apply.

A) Beta-blockers

B) Diuretics

C) Antibiotics

D) Calcium channel blockers

E) Antidepressants

F) ACE inhibitors

4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cuál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?

Answers

Answer:

a = 5 m / s²   and    x = 562.5 m

Explanation:

Let's apply the kinematics relations

          v = v₀ + at

          v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

           0 = v₀ - a t

           a = v₀ / t

let's calculate

           a = 75/15

           a = 5 m / s²

let's look for the distance

           0 = v₀² - 2a x

           x = v₀² / 2a

let's calculate

           x = \(\frac{75^2}{2 \ 5 }\)

           x = 562.5 m

the distance between two notes, or pitches, is called a.an accidental b.an interval c.the beat d.the key

Answers

In music theory, the distance between two pitches or notes is referred to as (b) an interval. Intervals are measured by counting the number of letter names and the distance between them, including both the letter names and any accidentals (sharps or flats) that may be present.

Intervals can be classified based on their specific distance, such as a minor second, major third, perfect fifth, etc.

An accidental (option a) is a symbol used in musical notation to indicate a temporary alteration of a pitch. The beat (option c) refers to the rhythmic pulse or division of time in music.

The key (option d) refers to the tonal center or the group of pitches that a piece of music is based on. While all of these terms are important in music, the specific term that describes the distance between two notes or pitches is an interval.

Therefore, (b) an interval is the correct answer.

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1) Calculate the ideal efficiency of a heat engine that takes in energy at 800 K and expels heat to a
reservoir at 300K ?

Answers

Answer:

Could you explain that more better?

Explanation:

You can describe the _______________ of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its _______________ in relation to another object. The second object acts as a _______________ point. When an object changes position, you know it has motion. Motion can also be described by finding an object's _______________, or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called _______________.

Answers

Answer:

You can describe the motion of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its position in relation to another object. The second object acts as a reference point. When an object changes position, you know it has motion. Motion can also be described by finding an object's speed  or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called velocity

Explanation:

In the given answer-

Motion is defined as - the change in the movement or position of any object  or body.

Position is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.

Reference point is a fixed point with regards to which any object or body changes its position. It is also called reference origin.

Speed is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).

Velocity is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).

We can describe the motion of an object by saying it is moving in a straight

line or is curved around another object.

We can describe where an object is by its position in relation to another

object.

The second object acts as a reference point.  Motion can also be described

by finding an object's speed or how fast or slow it moves in a certain amount

of time . We can describe the object's speed and direction together which is

called velocity

Motion describes the movement of an an object by virtue of its change in

movement and position.

Position is defined as an area or location where a body is in relation to

another object.

Reference point is also referred to as origin. It is fixed and acts as a

reference point to other objects location.

Speed is defined as the rate at which a body moves at a particular place/location.

Velocity is defined as the rate of speed per unit time which speed/time.

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A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.

Answers

The electric potential at point b experienced by the charge cab be determined using the formulas given.

Electric potential

The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.

V = Ed

V = (F/q)d

V = (Fd)/q

where;

V is the electric potentialF is electric forceE is the electric fieldq is the charge

Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.

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You are walking back toward the back of a bus that is moving forward with a constant velocity. Describe your motion relative to the bus and relative to a point on the ground.

Answers

Answer: Relative to the bus, you are stationary. Relative to a point on the ground, you are walking forward with velocity  equal to the velocity of the bus.

As a person walks toward the back of a bus, they are walking towards a stationary object according to their own perspective. However, from an outside perspective, the bus is moving forward with a constant velocity and so relative to that point in motion, you are actually walking backwards with respect to it. This difference in motion means you would not be able have the same experience as the person on the bus when getting off because when you get off you would stop while they continue going forward. The last sentence could be considered a footnote because it only applies if this was an actual situation rather than just an analogy question in a physics test.

Relative to the bus, you move at walking speed. The motion relative to the ground is in the direction same as the bus and equal to the difference between the speed of the bus and walking speed.

What is relative motion?

When an object has a certain velocity, then this velocity is w.r.t. some frame that is called the reference frame. When we measure the velocity of an object, the ground or the earth is taken as the reference frame.

The motion of an object observed by the observer depends on the frame of the observer and this type of motion is known as relative motion.

For example, if you are traveling in a train and the train is moving at a speed of 80 km/hr, then your speed according to another passenger sitting on the same train is equal to zero.

Similarly, if you are walking toward the back of a bus, then your motion relative to the bus is walking speed. Relative to the ground, it is the difference between the speed of the bus and walking speed.

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A 5 Kg mass has an initial speed of 5m/s. After 3 sec, it has come to a speed of 70 m/s.

a. What is the acceleration of the mass?
b. What net force is acting on the mass during those 3 seconds?

Answers

Answer:

a

 \(a = 21.7 \ m/s^2\)

b

\(F = 108.5 \ N\)  

Explanation:

From the question we told that

   The mass is  m  =  5 kg

    The initial speed \(u = 5 m/s\)

    The time taken to attain \(v = 70 \ m/s\) is  t =  3 s

   

Generally from kinematic equation we have that

     \(v = u + at\)

=> \(70 = 5 + a * 3\)

=>  \(a = 21.7 \ m/s^2\)

Generally  the force acting is mathematically represented

        \(F = m * a\)

=>      \(F = 5 * 21.7\)  

=>      \(F = 108.5 \ N\)  

             

   

Three identical metallic spherical objects have individual charges of, q1 = -9.612 nC, q2 = +3.204 nC and q3 = +6.408 nC. If the three objects are brought into contact with each other at the same time and the separated, determine: a) the final net charge on q1 = __________ nC; b) the final net charge on q2 = __________ nC; c) the final net charge on q3 = __________ nC; d) the number of electrons that were removed from/added to q1 = __________ electrons were __________ q1.

Answers

Given three identical metallic spherical objects have individual charges of, q1 = -9.612 nC,

q2 = +3.204 nC,

and q3 = +6.408 nC.

If the three objects are brought into contact with each other at the same time and then separated, the final net charge on q1, q2, and q3 will be calculated as follows;

Initial total charge, Q = q1 + q2 + q3

Q= -9.612 nC + 3.204 nC + 6.408 nC

Q= -0.002 nC

The final net charge on q1, q2, and q3 is same as they are identical:

q1 + q2 + q3 = -0.002 nC

q1 = q2 = q3 = -0.002 nC/3

q1 = -0.0006667 nC

Therefore, the final net charge on q1, q2, and q3 is -0.0006667 nC.The charge on q1 before and after is -9.612 nC and -0.0006667 nC respectively. The difference is the number of electrons that were removed from/added to q1. The number of electrons can be calculated as follows;

Charge on an electron,

e = 1.6 ×\(10^{-19\) C

Total number of electrons removed from

q1 = [(final charge on q1) - (initial charge on q1)] / e

q1 = [-0.0006667 - (-9.612)] / 1.6 × \(10^{-19\)

q1 = 6.0075 × 1013

The number of electrons removed from q1 is 6.0075 × 1013, and electrons were removed from q1. Thus, option d is,

"The number of electrons that were removed from q1 = 6.0075 × 1013 electrons were removed from q1."

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Which tools would be necessary to determine whether or not a large regular block will float, without using water? A) Ruler and balance B) Barometer and flask C) Thermometer and beaker D) Graduated cylinder and tongs

LAST 1 I PROMISE.......SORRY IM EXTREMELY SLOW:(

Answers

Answer:

A.ruler and balance is the answer.

Answer:

A) Ruler and balance

Explanation:

A student measures the voltage and current between two points in an
electrical circuit. If the voltage is 120 V and the current is 0.5 A, what is the
resistance, according to Ohm's law?
A. 0.00402
Β. 240 Ω
C. 1200
D. 60.00

Answers

Answer:

B. 240Ω

Explanation:

The formula between voltage, current and resistance is:

voltage = current × resistance

So resistance = voltage ÷ current

Therefore resistance = 120 ÷ 0.5

Resistance = 240Ω

Determine the maximum stress in the beam's cross section. Take M - 43 lb-ft. (Figure 1) Express your answer to three significant figures and include the appropriate units. A Value Units Submit Request

Answers

The maximum stress in the beam's cross-section is determined using the formula max stress = \((M * c) / I\), where M is \(43 lb-ft\), c is 2 inches, and I is \(10.67 in^4\) , resulting in a value of 8.07 psi.

To determine the maximum stress in the beam's cross-section, we can use the formula:


\(max stress = (M * c) / I\)

Where M is the bending moment (given as \(43 lb-ft\)), c is the distance from the neutral axis to the outermost point in the cross-section (in this case, the distance from the center of the beam to the bottom edge), and I is the moment of inertia of the cross-section.

From Figure 1, we can see that the beam is rectangular with a width of 2 inches and a height of 4 inches. The moment of inertia of a rectangular cross-section is:

\(I = (b * h^3) / 12\)

Where b is the width and h is the height. Plugging in the values for our beam, we get:

\(I = (2 * 4^3) / 12 = 10.67 in^4\)

To find c, we need to determine the location of the neutral axis. For a rectangular cross-section, the neutral axis is located at the centroid, which is at the center of the cross-section. Since the height is 4 inches, the distance from the neutral axis to the bottom edge is 2 inches.

Now we can plug in our values into the formula for max stress:

\(max stress = (43 lb-ft * 2 in) / 10.67 in^4 = 8.07 psi\)

Therefore, the maximum stress in the beam's cross-section is 8.07 psi.

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State one similarity between rotatory and circular motion​

Answers

Answer:

The main difference between these types of motion is that circular motion is a special case of rotational motion, where the distance between the body’s centre of mass and the axis of rotation remains fixed.

Rotational motion is based around the idea of rotation of a body about its center of mass. In rotational motion, the axis of rotation and centre of mass could change whereas in circular motion, the axis of rotation and centre of mass does not change.

Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path and can either have a constant angular rotation rate and constant speed, or it can exist with a changing rate of rotation.

Think of one of those fairground rides where people sit on dummy horses. Now imagine the horses spin around the post that holds them to the base of the ride. Then you have both rotational motion of the horse and circular motion as the horses move around the ride.

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