Both simple diffusion and facilitated diffusion are passive transport mechanisms that do not require energy and move substances from high concentration to low concentration.
Simple diffusion and facilitated diffusion are two types of passive transport mechanisms. Both move substances from high concentration to low concentration without the input of energy. Simple diffusion is a spontaneous process that occurs in liquids and gases. It is the net movement of molecules from high concentration to low concentration until an equilibrium is reached. The movement of water and gases in and out of cells are examples of simple diffusion.
Facilitated diffusion, on the other hand, is the movement of molecules across a membrane from high concentration to low concentration with the help of specific transport proteins. These transport proteins help substances cross the membrane that would otherwise be unable to do so. Glucose, amino acids, and ions are examples of substances that are transported via facilitated diffusion.
In conclusion, simple diffusion and facilitated diffusion both use passive transport mechanisms and move substances from high concentration to low concentration, but facilitated diffusion requires the help of transport proteins to move certain molecules.
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Simple diffusion and facilitated diffusion are passive forms of transport across a cell membrane. Simple diffusion involves direct movement through the lipid bilayer, while facilitated diffusion involves movement through protein channels.
Explanation:Simple diffusion and facilitated diffusion are both passive forms of transport that occur across a cell membrane. They both involve the movement of substances from an area of higher concentration to an area of lower concentration, without the use of energy.
In simple diffusion, substances move directly through the lipid bilayer of the cell membrane. This is possible for small, non-polar molecules such as oxygen and carbon dioxide.
In facilitated diffusion, substances move through specialized proteins called transporters or channels. These proteins provide a pathway for specific molecules to cross the membrane. This process is used for larger or polar molecules such as glucose or ions.
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Need help with this can some please help
Does Cs+ or Ba2+ have a smaller radius
help me plzzzzzzzz it helps a lot
Answer:
D
Explanation:
cracks from temperature changes is a type of physical weathering often known as freezing and thawing
Chymotrypsin has an α-helix that contains 2.5 turns. Approximately how many amino acids are involved in this helix?A. 20.25B. 9C. 13.5D. 3.75E. 2.5
Chymotrypsin has an α-helix that contains 2.5 turns. Approximately 9 amino acids are involved in this helix.
What is chymotrypsin?
The pancreas produces chymotrypsin. Chymotrypsinogen is its precursor. By cleaving peptide bonds in locations Arg15–Ile16, trypsin activates chymotrypsinogen and generates –chymotrypsin. The "oxyanion hole" and the hydrophobic "S1 pocket" are the results of the interaction between the aminic group (-NH3+) of the Ile16 residue and the side chain of Asp194. Additionally, chymotrypsin causes its own activation by cleaving at positions 14, 15, 146, and 148 to create -chymotrypsin, which is both more active and stable than -chymotrypsin. A three-polypeptide molecule with disulfide bonds connecting them makes up the final product.To know more about chymotrypsin, click the link given below:
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which of the following questions would be reasonably answered by performing this week's lab? group of answer choices what is the solubility of iron (ii) oxalate in water? what is the solubility product constant for iron (ii) oxalate? how do the solubility product constants for different iron solutions compare? what is one way to determine the amount of fe2 in a solution?
The question that would be reasonably answered by performing this week's lab is "what is the solubility product constant for iron (II) oxalate?"
The lab may involve measuring the concentration of iron (II) and oxalate ions in a saturated solution of iron (II) oxalate and then using this data to calculate the solubility product constant. The other questions may require different experiments or methods of analysis. For example, determining the solubility of iron (II) oxalate in water may involve measuring the amount of the compound that dissolves in a given volume of water, while determining the amount of Fe2+ in a solution may involve titration or spectroscopic analysis.
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What volume will 106.476 g N, gas at STP occupy?
O 85.1808L
O 170.362L
O 7.60543L
0 3.80271L
Answer:
170.362 L
General Formulas and Concepts:
Atomic Structure
Reading a Periodic TableMolesGas Laws
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 KStoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
Identify variables
[Given] 106.476 g N
[Solve] L N
Step 2: Identify Conversions
[STP] 1 mol = 22.4 L
[PT] Molar Mass of N: 14.01 g/mol
Step 3: Convert
[DA] Set up: \(\displaystyle 106.476 \ g \ N(\frac{1 \ mol \ N}{14.01 \ g \ N})(\frac{22.4 \ L \ N}{1 \ mol \ N})\)[DA] Divide/Multiply [Cancel out units]: \(\displaystyle 170.24 \ L \ N\)a sample of a gas at room temperature occupies a volume of 20.0 l at a pressure of 712 torr . if the pressure changes to 3560 torr , with no change in the temperature or moles of gas, what is the new volume, v2?
The new Volume of gas is L. This result is obtained from Boyal's law of gases behaviour.
In the given question we have,
Consider a Sample of a gas at room temperature,
initial pressure of gas (P₁) = 712 torr
initial volume of sample gas ( V₁ ) = 20.0 L
there is no change in temperature this implies that temperature is constant through out the process.
Final or new pressure of gas (P₂) = 3560 torr
let new Volume of sample gas be V₂ .
Now, we are using the Boyal's law of gases which tells us pressure is inversely proportional to volume. It gives us pressure volume relationship at constant temperature to find out the value of new Volume . So,
P₁ / P₂ = V₁ /V₂ ---(1)
put all the values of variables in equation (1) we get, 712 / 3560 = 20. 0 / V₂
=> V₂ = ( 3560×20 )/ 712 = 100 L.
So, new Volume of sample gas is 100 L.
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Predict the neutral organic product of the reaction. An alkene where carbon 1 is bonded to two methyl groups and carbon 2 is bonded to two hydrogens. This reacts with c h 3 o h and h 2 s o 4 to form the product
The product is an alcohol of formula C2H6O
The reactants described are alkenes having the formula C2H4, and the reactants are methanol and sulfuric acid. This reaction is called an acid-catalyzed hydration reaction, in which water is added to the double bond of an alkene to produce an alcohol.
The product of this reaction is an alcohol of formula C2H6O. The carbon that was attached to the two hydrogens of the alkene is now attached to a hydroxyl group (-OH) and a hydrogen. The carbon that was attached to two methyl groups remains attached to two methyl groups. The overall formula for the product will be C2H6O.
As noted, the reactant is an alkene having the formula C2H4, where carbon 1 is attached to two methyl groups and carbon 2 is attached to two hydrogen atoms. The reactants are methanol (CH3OH) and sulfuric acid (H2SO4). Methanol serves as the solvent for the reaction and also provides a hydroxyl group for addition to alkenes. Sulfuric acid acts as a catalyst for the reaction, protonating alkenes and making them more reactive to nucleophilic attack. The overall reaction can be written as:
C2H4 + CH3OH + H2SO4 -> C2H6O + H2SO4
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Which is not an example of a
parasite/host relationship?
A flea on a dog
A tick on a horse
A toad on a lily pad
A barnacle on a whale
Answer:
A toad on lily pad
Explanation:
have a great day
What will a hurricane do when it hits landfall
A.It will weaken
B.It will get stronger
C.It will not change
(HELP ASAP)
Answer:
A
Explanation:
because it doesn't have the ocean water to gain energy
Hello help pleaseeee
Answer:
1) Non metals
2) The melting point increase as we go down the group.
3) The boiling point also increase as we go down the group.
4) The halogens grow darker as we move down the group.
5) The same happens for Iodine as the boiling point and melting point increase as we go down the group.
6) Bromine is more reactive than Iodine as because the size of iodine is greater than that of Bromine.
7) The size of atoms become bigger and larger.
8) Nucleus of every atoms of different elements contain neutron and proton and the nucleus is covered by shells.
9) Because they are placed vertically second from the right in the periodic table.
queries comment me!!
Answer:
1) Non metals
2) The melting point increase as we go down the group.
3) The boiling point also increase as we go down the group.
4) The halogens grow darker as we move down the group.
5) The same happens for Iodine as the boiling point and melting point increase as we go down the group.
6) Bromine is more reactive than Iodine as because the size of iodine is greater than that of Bromine.
7) The size of atoms become bigger and larger.
8) Nucleus of every atoms of different elements contain neutron and proton and the nucleus is covered by shells.
9) Because they are placed vertically second from the right in the periodic table.
Explanation:
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG' for the following redox reaction. Round your answer to 3 significant digits. 12 (s) + 6H20 (1)+5 Br2 (1) ► 2103 (aq) + 12 H+ (aq)+ 10 Br(aq) kJ xo?
The standard free energy of the above reaction is calculated to be 2247kJ
The standard reaction free energy can be calculated using the formula:
ΔG° = -nF E°
where:
ΔG° is the standard reaction free energy
n is the number of electrons transferred in the balanced redox reaction
F is the Faraday constant (96,485 C/mol)
E° is the standard reduction potential of the half-reactions involved in the redox reaction
First, let's write the two half-reactions for the redox reaction:
Br2 + 2 e- → 2 Br- E° = +1.087 V
12 H2O + 12 e- → 6 H2 + 12 OH- E° = -0.828 V
Since 6 electrons are transferred in the reaction, we need to multiply the second half-reaction by 6 so that the electrons cancel out:
6 (12 H2O + 12 e- → 6 H2 + 12 OH-) E° = -4.968 V
Now we can add the two half-reactions to get the overall balanced reaction:
12 (s) + 6 H2O (l) + 5 Br2 (l) → 2103 (aq) + 12 H+ (aq) + 10 Br- (aq)
The standard reaction free energy can now be calculated:
ΔG° = -nF E°
ΔG° = -(6 mol e-)(96,485 C/mol)(-4.968 V + 1.087 V)
ΔG° = +2,246,749.71 J = +2246.749 kJ
Rounding to 3 significant digits, the standard reaction free energy is:
ΔG° = +2247kJ
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in an experiment to compare thermal conductivity of materials such as iron, lead, aluminium, copper and wood. the arrows on the rocks indicate the extent at which the vaseline applied around the material melted when heat is applied.i. identify each of the materials labeled I,II,III,IV and V using the melting level of the vaselineii. which material had the least melting of the vaseline?iii. give one reason for your answer in (ii) aboveiv. arrange the materials in order of decreasing conductivity of heatv. mention two modes of heat transfer in this experiment
Answer:
The answer is in this link
Explanation:
https://i.makeagif.com/media/7-13-2016/iEDABX.mp4
Item 12 a student mixes 40. Ml of 0. 10mhbr(aq) with 60. Ml of 0. 10mkoh(aq) at 25°c. What is the [oh−] of the resulting solution?
Item 12 a student mixes 40. Ml of 0. 10mhbr(aq) with 60. Ml. The [oh−] of the resulting solution is 0.02.
What is a solution?A solution is a mixture of two or more than two substances.
The reaction is \(\rm HBr + KOH = KBr + H_2O\)
To calculate the OH-
1 mole of HBr reacts with 1 mole of KOH
Moles of HBr = 40 mL × 0.1 M = 4 mm moles
Moles of KOH = 60 mL × 0.1 M = 6 m moles
Moles of [OH-] = 6 - 4 = 2 m moles
Volume of solution = 100 mL
[OH-] = 2mmoles/100 mL = 0.02 M
Thus, the [oh−] of the resulting solution is 0.02.
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Radiation on the _________________ is measured in wavelengths and frequencies.
Answer:
The electromagnetic (EM) spectrum is the range of all types of EM radiation. Radiation is energy that travels and spreads out as it goes – the visible light that comes from a lamp in your house and the radio waves that come from a radio station are two types of electromagnetic radiation. The other types of EM radiation that make up the electromagnetic spectrum are microwaves, infrared light, ultraviolet light, X-rays and gamma-rays
Explanation:
Answer:
Scale
Explanation:
A balloon is filled with helium gas has a volume of 1.0 L at a pressure of 1.0 atm. The
balloon is released and reaches an altitude where the pressure is now 0.4 atm. What is the
new volume of the balloon at this altitude assuming the air temperature has not changed?
Answer:
2.5 LExplanation:
The new volume of the balloon can be found by using the formula for Boyle's law which is
\(P_1V_1 = P_2V_2\)
Since we are finding the new volume
\(V_2 = \frac{P_1V_1}{P_2} \\\)
From the question we have
\(V_2 = \frac{1 \times 1}{0.4} = \frac{1}{0.4} \\ = 2.5\)
We have the final answer as
2.5 LHope this helps you
Proteco Oils Pressed Purity are a range of cold pressed oils ideal for cooking. The high quality oils are extracted from nuts, fruit and seeds. They are flavoursome and are naturally chemical and preservative free. Pressed Purity are one of the few oils on mainstream supermarket shelves which is 100% Australian. They offer a wider range variants than any other oil manufacturer in Australia. Proteco Oils’ state of the art refinery in Kingaroy, South East Queensland is uniquely equipped. With highly specialized equipment for complete oil processing on a large scale. Now, exporting into China and throughout Asia Pacific, this family owned company has grown with the help of Evolve Brand Design
Market Mostly females, 25-60+ years, with a contemporary cooking attitude. These consumers are health conscious, seeking natural and chemical free options for themselves and their family. The secondary target audience are men and women of all ages. This group consider themselves to be gourmet home chefs and are open to new tastes. Communication of the product concept was critical with the initial brand name development. Evolve Brand Design presented a range of concepts and the brand name ‘Pressed Purity’ was chosen. This concept was the winner as it implied the chemical free processing of the raw crops into edible oils. Likewise, the design for the brand is an analogy for pressing the oil from the fruit, nut or seeds using a vice. The Pressed Purity distinctive edge is threefold. Chemical free, 100% natural ingredients and genuinely Australian. Export opportunities have risen due to the third, very important, unique selling point (USP). In addition, they have a wide range of flavours with applications tailored to a range of food preparation methods. From flavourful salad dressing oils to baking and high heat applications like stir-frying and barbeques, Pressed Purity has a solution
Q.2.1 With the use of examples applicable to the case study, explain human resource forecasting. (10)
Q.2.2 Explain the concept of product differentiation in the context of Pressed Purity. (5)
Q.2.3 Recommend a work-study method for Proteco Oil’s refinery. (10)
Q.2.4 Identify and explain the criteria Proteco Oil used for market segmentation. (10)
Q.2.5 Identify the operational process used by Proteco Oil. Justify your choice. (10)
Q.2.1 With the use of examples applicable to the case study, explain human resource forecasting. Human resource forecasting refers to the process of estimating and planning for the future staffing needs of an organization.
Q.2.3 One work-study method that could be recommended for Proteco Oil's refinery is the method of time and motion study.
Q.2.1 It involves analyzing the current workforce, identifying future workforce requirements, and developing strategies to meet those needs. In the case of Proteco Oil's Pressed Purity, human resource forecasting would involve predicting the number and types of employees needed to support the company's growth and expansion.
For example, as Pressed Purity expands its export operations into China and throughout the Asia Pacific region, they would need to forecast the additional human resources required to manage international logistics, distribution, and marketing. This may include hiring employees with expertise in international trade, language skills, and knowledge of the target markets. Human resource forecasting would also consider the need for additional staff at the state-of-the-art refinery in Kingaroy to handle increased production and quality control.
Q.2.2 Product differentiation refers to the process of distinguishing a product from its competitors by highlighting unique features, benefits, or characteristics. In the context of Pressed Purity, product differentiation is evident in several aspects of their offerings.
One example of product differentiation is their focus on being 100% Australian. This sets them apart from other oil manufacturers in Australia who may rely on imported ingredients. By promoting their Australian origin, Pressed Purity appeals to consumers who prioritize supporting local businesses and value the quality associated with Australian products.
Additionally, Pressed Purity emphasizes being chemical and preservative-free. This addresses the growing consumer demand for natural and healthier food options. By positioning their oils as naturally chemical-free, Pressed Purity differentiates themselves from competitors who may not have such a strong emphasis on natural and chemical-free products.
Q.2.3 One work-study method that could be recommended for Proteco Oil's refinery is the method of time and motion study. Time and motion study involves analyzing and improving work processes by observing and measuring the time required to complete specific tasks or activities.
In the context of the refinery, a time and motion study could be conducted to identify any inefficiencies or bottlenecks in the oil processing operations. This could involve observing workers as they perform tasks and measuring the time taken for each step of the process. By analyzing the data collected, the refinery management can identify areas where time can be saved, processes can be streamlined, and productivity can be improved.
For example, the time and motion study may reveal that certain equipment or machinery in the refinery is causing delays or requiring excessive manual labor. Based on these findings, the management can make informed decisions on investing in more efficient equipment or implementing process improvements to optimize productivity and reduce costs.
Q.2.4 Proteco Oil used the following criteria for market segmentation:
Demographic segmentation: The primary target audience for Pressed Purity is mostly females, aged 25-60+ years, with a contemporary cooking attitude. These consumers are health-conscious and seek natural and chemical-free options for themselves and their families. The secondary target audience includes men and women of all ages who consider themselves gourmet home chefs and are open to new tastes.
Psychographic segmentation: Pressed Purity targets consumers who prioritize natural and chemical-free products. By emphasizing the use of 100% natural ingredients and being genuinely Australian, Pressed Purity appeals to health-conscious consumers who value the quality and authenticity of the products they consume. They also cater to gourmet home chefs who are looking for unique and flavorful cooking options.
Geographic segmentation: Initially, Proteco Oil focused on the domestic market in Australia.
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pleaaseeee help im failing so bad3
Gallium is a metallic element in Group III. It has similar properties to aluminium.
(a) (i) Describe the structure and bonding in a metallic element.
Metallic elements exist in a solid-state and they are opaque, have a shiny surface, good conductors of electricity and heat, malleable and ductile, and are dense. The structure of metals is formed by atoms that are held together by metallic bonds. These atoms have loosely bound valence electrons that can be shared between the neighboring atoms.
Therefore, the outermost shells of these atoms are incomplete due to the sharing of valence electrons, forming a lattice structure known as a metallic bond.Metallic elements have a unique crystal structure that occurs in two forms. The most common type of metal crystal structure is the body-centered cubic structure where the atoms are arranged in a cube with one atom located at the center of the cube. The other type of metal crystal structure is the face-centered cubic structure, where each corner of the cube is an atom and there is an additional atom at the center of each face of the cube .Metallic bonding occurs due to the delocalized electrons that exist in the metal structure. The valence electrons from each atom are free to move throughout the entire metal lattice. Therefore, these electrons form a "sea of electrons" that is shared by all the atoms in the lattice. This results in the metal structure having high thermal and electrical conductivity.Metals are known for their ductility and malleability properties. These properties are due to the metallic bonding that exists in the metal structure. Since the valence electrons are shared, they can easily move past one another, allowing the metal to be hammered into different shapes without breaking.The properties of metals vary depending on their structure and bonding. Gallium, being a metallic element in Group III, has similar properties to aluminum. Therefore, it has a similar metallic bond structure with delocalized electrons that provide the metal with its unique properties.For such more question on valence electrons
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What is the molarity of a kci solution containing 0.75 moles of kci in 250 ml of solution (i will give brainliest)
The molarity of the KCI solution is 3 M.
To find the molarity of a KCI solution containing about 0.75 moles of KCI in 250 mL of solution, we need to use the below given formula:
Molarity (M) = moles of solute / liters of solution
Since we know that, the volume of the solution is given in milliliters, we need to convert it to liters by dividing by 1000:
250 mL / 1000 = 0.25 L
Now we can plug in the values:
Molarity (M) = 0.75 moles / 0.25 L = 3 M
Therefore, the KCI solution has the molarity of at most 3 M.
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When solutions of silver perchlorate, AgClO4 (aq) , and ammonium iodide NHI (aq) , are mixed, a solid precipitate forms, indicating a reaction: Which species should appear in the net ionic equation representing the reaction? Select one or more: NH4C1O4 NH4I C1O4 Agl AgC1O4 Ag NH4
The species that should appear in the net ionic equation representing the reaction are Ag⁺, I⁻, and AgI.
First, let's write out the balanced chemical equation for the reaction:
AgClO₄(aq) + NH₄I(aq) → AgI(s) + NH₄ClO₄(aq)
Now, we'll write the total ionic equation:
Ag⁺(aq) + ClO₄⁻(aq) + NH₄⁺(aq) + I⁻(aq) → AgI(s) + NH₄⁺(aq) + ClO₄⁻(aq)
To find the net ionic equation, we remove the spectator ions (ions that do not change during the reaction):
Ag⁺(aq) + I⁻(aq) → AgI(s)
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PLS FAST WILL GIVE BRAINLIEST!!Substance are either ________________ or _______________.
mixture
compounds
gas
properties
elements
Answer:
elements or compounds
help help help help help
What is an action your citizens can take to prevent water waste?
i need help with this so try to help me out please
Can someone help me please I would really appreciated
Explanation:
whats the question. cause I didn't see it
7.8 L =mLDimensional AnalysisRatio:ProportionFormula MethodmLХLx mL=IImL11
answer and explanation
1 L = 1000 mL
and so to determine 7.8L we can o the calculation as follows
x mL = 1000 mL/ 1 L x 7.8 L/1 = 7800 mL/1 = 7800 mL
in a mammalian cell, by how many mv does the nernst potential of an ion increase if the external ion concentration is doubled?
Doubling the external ion concentration in a mammalian cell would increase the Nernst potential of the ion by approximately 58 mV.
How to find the external ion concentration on the Nernst potential of an ion in a mammalian cell?The Nernst equation describes the relationship between the concentration gradient of an ion across a membrane and the membrane potential required to maintain equilibrium for that ion. The equation is as follows:
\(E = (RT/zF) * ln\)(\([ion]outside/[ion]inside)\)
where:
E is the Nernst potential (membrane potential at which the ion is at equilibrium)
R is the gas constant
T is the absolute temperature
z is the valence of the ion
F is the Faraday constant
[ion]outside is the concentration of the ion outside the cell
[ion]inside is the concentration of the ion inside the cell
ln is the natural logarithm function
Assuming the valence (z) and temperature (T) remain constant, if the external ion concentration is doubled, the Nernst potential of the ion will increase by approximately 58 mV at room temperature (25°C). This can be calculated using the Nernst equation:
E2 = (RT/zF) * ln([ion]outside x 2/[ion]inside)
E1 = (RT/zF) * ln([ion]outside/[ion]inside)
Subtracting E1 from E2, we get:
ΔE = E2 - E1 = (RT/zF) * ln([ion]outside x 2/[ion]inside) - (RT/zF) * ln([ion]outside/[ion]inside)
ΔE = (RT/zF) * ln(2)
ΔE = (8.314 J/mol·K * 298 K / (1 * 96,485 C/mol)) * ln(2)
ΔE ≈ 58 mV
Therefore, doubling the external ion concentration in a mammalian cell would increase the Nernst potential of the ion by approximately 58 mV.
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write molecular and net ionic equations for the successive neutralizations of each acidic hydrogen of sulfurous acid
Sulfurous acid is a weak acid with the molecular formula H2SO3. It has two acidic hydrogen atoms, which can be sequentially neutralized. The successive neutralizations of each acidic hydrogen of sulfurous acid are as follows:
First acidic hydrogen: H2SO3 + NaOH → NaHSO3 + H2O
The molecular equation is H2SO3 + 2NaOH → Na2SO3 + 2H2O
The net ionic equation is H2SO3 + 2OH- → SO32- + 2H2O
Second acidic hydrogen: NaHSO3 + NaOH → Na2SO3 + H2O
The molecular equation is HHSO3 + NaOH → Na2SO3 + H2O
The net ionic equation is HSO3- + OH- → SO32- + H2O
Overall reaction: H2SO3 + 2NaOH → Na2SO3 + 2H2O
The molecular equation for the overall reaction is H2SO3 + 2NaOH → Na2SO3 + 2H2O
The net ionic equation for the overall reaction is H2SO3 + 2OH- → SO32- + 2H2O
In summary, the molecular and net ionic equations for the successive neutralizations of each acidic hydrogen of sulfurous acid are given above.
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3.
a) Using the five-step method, predict the predominant Bronsted-Lowry acid base
reaction when solutions of perchloric acid and sodium dihydrogen phosphate are
combined.
b) Identify one conjugate acid-base pair from the reaction equation.
c) Predict whether the equilibrium will favour the formation of the reactants or
products. Support and explain your answer.
Answer:
a) The predominant Brownstead-Lowry acid- base is perchloric acid
b) A conjugate acid base pair is HClO4 and ClO4^-
c) forward reaction is favored and equilibrium position lies towards the far right
Explanation:
The molecular equation is;
HClO4(aq) + NaH2PO4(aq) -----> H3PO4(aq) + NaClO4(aq)
The net ionic equation of the reaction is;
H^+(aq) + H2PO4^-(aq) ----> H3PO4(aq)
The predominant Brownstead-Lowry acid- base is perchloric acid .
A conjugate acid base pair is HClO4 and ClO4^-
Since the both species; perchloric acid and sodium dihydrogen phosphate are both highly soluble in water yielding ions and also dissociate to a large extent in solution, the forward reaction is favoured leading to the formation of phosphoric acid. Remember that phosphoric acid does not easily dissociate in solution hence the forward reaction is faster than the reverse reaction and the equilibrium position lies towards the far right.
in this image of a volcano, which letter represents lava
Answer:
d
Explanation: