Answer:
The solar wind is created by the outward expansion of plasma (a collection of charged particles) from the Sun's corona (outermost atmosphere). This plasma is continually heated to the point that the Sun's gravity can't hold it down. It then travels along the Sun's magnetic field lines that extend radially outward.
which of these lists has all pure substances
a) milk water copper
b) gold oxygen nickel
c) tea sale concrete
d) orange juice with pulp silver soda water
A student left a bar of chocolate in the sun on a hot day. As the chocolate melted, which property changed?
A. its mass
B. its shape
C. its weight
D. its composition
How much force is needed to accelerate a 100 kg car at a rate of 3 m/s
An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the
(A) work done on the object
(B) total force applied to the object
(C) weight of the object
(D)change in kinetic energy of the object
PLEASE HELP ME
Answer:
b
Explanation:
please help :(
3.) What is the physical quantity which
represents the basis of the functioning of a
loudspeaker?
4.) Why doesn't a direct current operate a
loudspeaker?
An object dropped from rest, what will its velocity be after 30 s?
An object dropped from rest, its velocity be 294 m/s in downward direction after 30 s .
Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them.
initial velocity = u = 0
time = t = 30sec
g = acceleration due to gravity = 9.8 \(m/s^{2}\)
using equation of kinematics
v = u - g*t
v = 0 - 9.8 * 30
v = - 294 m/s
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calculate the energy of 1kg of concrete from 20⁰c to 30⁰c
Answer:
9 kilojoules of energy are stored in a kilogram of concrete due to sensible heat.
Explanation:
In this exercise we need to determined the sensible heat store in a kilogram of concrete due to a change in temperature. Sensible heat (\(Q\)), measured in kilojoules, is defined by the following expression:
\(Q = m\cdot c\cdot (T_{f}-T_{o})\) (1)
Where:
\(m\) - Mass, measured in kilograms.
\(c\) - Average specific heat of concrete, measured in kilojoules per kilogram-degree Celsius.
\(T_{o}\), \(T_{f}\) - Initial and final temperatures of concrete, measured in degrees Celsius.
If we know that \(m = 1\,kg\), \(c = 0.9\,\frac{kJ}{kg\cdot ^{\circ}C}\), \(T_{o} = 20\,^{\circ}C\) and \(T_{f} = 30\,^{\circ}C\), then the energy store in a kilogram of concrete is:
\(Q = (1\,kg)\cdot \left(0.9\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C-20\,^{\circ}C)\)
\(Q = 9\,kJ\)
9 kilojoules of energy are stored in a kilogram of concrete due to sensible heat.
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
5. Explain how heating a bar magnet would change its magnetic field.
Heating a bar magnet would weaken its magnetic field. The magnetic field of a bar magnet is caused by the alignment of its magnetic domains. When heated, the thermal energy causes these domains to vibrate and become disordered, which leads to a weakening of the magnet's magnetic field.
This effect is known as thermal demagnetization. In some cases, if the temperature is high enough, the magnet can lose its magnetism entirely and become non-magnetic. However, if the magnet is cooled back down, the domains can re-align and the magnetic field can be restored.
When a bar magnet is heated, the temperature increase causes the magnetic domains within the magnet to become more disordered. This results in a decrease in the overall magnetization of the magnet, thus weakening its magnetic field.
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The angle between the axes of two polarizing filters is 45.0°. By how much does the second filter reduce the intensity of the light coming through the
The second filter reduces the intensity of the light coming through by a factor of (√2/2)² = 0.5 or 50%.
According to the given problem, the angle between the axes of two polarizing filters is 45.0°. By how much does the second filter reduce the intensity of the light coming through? The intensity of the light coming through the second filter can be calculated by using Malus law.
Malus's Law states that the intensity of polarized light passing through an analyzer varies as the square of the cosine of the angle between the axes of the polarizer and analyzer.
Hence, the mathematical expression is given byI = I0cos² θ
Where, I is the intensity of the light after passing through the second filter,
I0 is the initial intensity of light before passing through any filter,
θ is the angle between the axes of the two polarizing filters.
As a result, the second filter reduces the amount of light passing through by a factor equal to the square of the cosine of the angle formed by the two polarising filters' axes.
The cosine of 45° has a value of 1/2 or 2/2.As a result, the second filter significantly reduces the amount of light passing through by (2/2)2 = 0.5 or 50%.
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Example of a solid that sunlines is ( ? )
An example of a solid that sunlines is a billboard.
What is a billboard?A billboard simply refers to a very large board which is usually, frequently and most of the time used for displaying advertisements
So therefore, an example of a solid that sunlines is a billboard
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Reasons why water can not be used as a thermometric substance
Water is not commonly used as a thermometric substance due to its limited temperature range, poor thermal conductivity, density variation, boiling point variation, and susceptibility to impurities
There are several reasons why water is not commonly used as a thermometric substance, such as:
1. Limited temperature range: Water can exist only in the liquid state between 0°C to 100°C at normal atmospheric pressure, which limits its use as a thermometric substance in temperature measurements beyond this range.
2. Poor thermal conductivity: Water has a low thermal conductivity compared to some other substances, which can result in slower heat transfer rates and inaccuracies in temperature measurements.
3. Density variation: The density of water decreases with increasing temperature between 0°C to 4°C, which means that the volume of water expands as it is heated. This makes it difficult to obtain accurate readings when measuring temperatures near or below 4°C.
4. Boiling point variation: The boiling point of water changes with variations in atmospheric pressure, which can introduce inaccuracies in temperature measurements.
5. Susceptibility to impurities: Water is susceptible to impurities, such as dissolved minerals, which can affect its physical properties, including its boiling and freezing points.
Therefore, while water is an important substance in many areas of science and technology, it is not commonly used as a thermometric substance due to its limited temperature range, poor thermal conductivity, density variation, boiling point variation, and susceptibility to impurities.
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Yellow lines in the absorption spectrum of mercury vapor correspond to photons with an energy of about 2 eV. What can you conclude about the electron energy levels in mercury atoms?
A.
There must be energy levels with a difference of about 4 eV.
B.
There must be energy levels with a difference of about 2 eV.
C.
There must be energy levels with a difference of about 1 eV.
D.
There must be energy levels with no difference in energies.
Yellow lines in the absorption spectrum of mercury vapor correspond to photons with an energy of about 2 eV, it is concluded that the electron energy levels in mercury atoms are such that there must be energy levels with a difference of about 2 eV, which is in option B.
What is the absorption spectrum?Yellow lines in the absorption spectrum of mercury vapor correspond to photons with an energy of about 2 eV, which indicates that the electrons in the mercury atoms are absorbing photons with an energy equal to the energy difference between two energy levels in the atoms.
Hence, it is concluded that the electron energy levels in mercury atoms are such that there must be energy levels with a difference of about 2 eV, which is in option B.
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Please help me with this (20 points)
Answer:
1. troposphere
2. troposphere (still)
3. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere.
4.The stratosphere is where you'll find the very important ozone layer. The ozone layer helps protect us from ultraviolet radiation (UV) from the sun. In fact, the ozone layer absorbs most of the UV radiation the sun sends to us. Life as we know it wouldn't be possible without this layer of protection.
5. It contains the ozone, which protects Earth from the sun's radiation. Why aren't there many meteors in the troposphere? They burn up before they reach the troposphere.
Explanation:
1.The troposphere is the atmospheric layer closest to the planet and contains the largest percentage (around 80%) of the mass of the total atmosphere. Temperature and water vapor content in the troposphere decrease rapidly with altitude.
2.The layer closest to Earth's surface is the troposphere, reaching from about seven and 15 kilometers (five to 10 miles) from the surface. The troposphere is thickest at the equator, and much thinner at the North and South Poles.
3. Explained in the answer.
4. Explained in the answer.
5. Explained in the answer.
Athletes who compete in downhill skiing try to lose as little energy as possible. A skier starts from rest at the top of a 75 m hill and skis to the bottom as fast as possible. When she arrives at the bottom, she has a speed of 25 m/s. a) Calculate the efficiency of the skier. b) Draw an energy flow diagram for this situation.
The efficiency of the skier is 86%
(a) The efficiency of the skier can be calculated by finding the ratio of the mechanical energy at the top of the hill to the mechanical energy at the bottom of the hill.
The mechanical energy of an object can be defined as the sum of its kinetic energy and its potential energy.
In this case, the skier starts from rest, so her initial kinetic energy is zero.
Her initial potential energy can be calculated using the formula:
mgh = (75 m)(9.8 m/s²)(63 kg)
= 45,765 J
where
m = the mass of the skier,
g = the acceleration due to gravity,
h = the height of the hill.
Using the principle of conservation of energy, we know that the skier's mechanical energy at the bottom of the hill must be equal to her mechanical energy at the top of the hill, so her final kinetic energy is given by:
K = (1/2)mv²
= (1/2)(63 kg)(25 m/s)²
= 39,375 J
Her final potential energy is zero, since she is at ground level, so her mechanical energy at the bottom of the hill is equal to her final kinetic energy:
K = 39,375 J
Therefore, the efficiency of the skier is given by the ratio of her mechanical energy at the bottom of the hill to her mechanical energy at the top of the hill:
Efficiency = K/mgh
= 39,375 J/45,765 J
= 0.86 or 86%
(b) Here's an energy flow diagram ,
[Skier at Rest] ------(1)------> [Gravitational Potential Energy]
|
|
|
|
V
[Gravitational Potential Energy] ----(2)-----> [Kinetic Energy]
|
|
|
|
V
[Kinetic Energy] --------(3)-------> [Air Resistance/ Frictional Heat]
Skier at Rest: At the top of the hill, the skier starts with no kinetic energy but possesses gravitational potential energy due to being at an elevated position.Gravitational Potential Energy: As the skier descends the hill, the gravitational potential energy decreases. This energy is converted into kinetic energy, increasing the skier's speed.Kinetic Energy: As the skier reaches the bottom of the hill, the gravitational potential energy is fully converted into kinetic energy. The skier's speed is at its maximum, indicated by a value of 25 m/s.Air Resistance/Frictional Heat: As the skier moves through the air and encounters friction with the snow, some of the kinetic energy is converted into heat due to air resistance and frictional forces. This energy is dissipated into the surroundings.Learn more about the efficiency:
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Why is the plastic shopping bag transparent
Answer:
they are transparent to see the content of goods inside but at the same time what cause it to be transparent is because of the fact that they are created with low-density polyethylene and polypropylene, which are transparent polymers.
All of the noble gases have _______ electrons in their outer shell
Answer:
8
Explanation:
All noble gasses have 8 electrons in their outer shell
Need help with physics.
Question: A 65 kg child riding a Ferris wheel has a tangential speed of 9.5 m/s. Find the magnitude of the centripetal force on the child if the distance from the child to the axis of the wheel is 20 m.
The centripetal force : F = 293.3125 N
Further explanationGiven
mass = 65 kg
v = 9.5 m/s
r = 20 m
Required
the centripetal force
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
\(\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}\)
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
Input the value :
F = 65 x 9.5² / 20
F = 293.3125 N
A velocity-time graph shows how ____ changes over time.
A point charge q1=5. 00μC is held fixed in space. From a horizontal distance of 8. 00 cm, a small sphere with mass 4. 00×10−3kg and charge q2=+2. 00μC is fired toward the fixed charge with an initial speed of 35. 0 m/s. Gravity can be neglected.
What is the acceleration of the sphere at the instant when its speed is 27. 0 m/s
According to the given statement , the acceleration of the sphere at the instant when its speed is 27.0 m/s.
We can use the principles of electrostatics and kinematics. a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
1. Determine the electric force between the two charges:
- The electric force between two charges can be calculated using Coulomb's Law:
F = k * |q1 * q2| / r².
- In this case, q1 = 5.00 μC and q2 = +2.00 μC. The distance between them, r, is the horizontal distance of 8.00 cm (which is 0.08 m).
- The constant k is 9.00 x 10⁹ N * m^2 / C².
- Plugging in the values, we get F = (9.00 x 10^9 N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)².
2. Calculate the net force acting on the sphere:
- At any instant, the net force acting on the sphere is the sum of the electric force and the force due to gravity.
- However, in this case, gravity can be neglected, as stated in the question.
- Therefore, the net force acting on the sphere is equal to the electric force between the two charges.
3. Calculate the mass of the sphere:
- The mass of the sphere is given as 4.00 x 10⁻³ kg.
4. Apply Newton's second law:
- Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = m * a.
- In this case, the net force acting on the sphere is the electric force between the charges.
- Plugging in the values, we get (9.00 x 10⁹ N * m^2 / C²) * |5.00 μC * 2.00 μC| / (0.08 m)² = (4.00 x 10⁻³ kg) * a.
5. Solve for the acceleration:
- Rearranging the equation, we have a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
- Evaluating the expression, we find the value of acceleration.
By following these steps, you can find the acceleration of the sphere at the instant when its speed is 27.0 m/s.
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Which space rock is easiest to study and what do we typically learn from
them?
Which best explains how Selena can correct her error? She can change the magnets so like poles are facing each other. She can change the arrows so they show current traveling in opposite directions on the sides of the loop. She can change the arrows so they show the magnetic field reversing direction between the magnets. She can change the magnetic poles so they are both on one side of the loop.
Complete question is;
Selena drew a diagram to show how current moves in a loop of wire that is placed between two magnets. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire with green arrows at its ends away from the magnets pointing away from the magnets. Red arrows point from N to S. Which best explains how Selena can correct her error?
A) She can change the magnets so like poles are facing each other.
B) She can change the arrows so they show current traveling in opposite directions on the sides of the loop.
C) She can change the arrows so they show the magnetic field reversing direction between the magnets.
D) She can change the magnetic poles so they are both on one side of the loop.
Answer:
B) She can change the arrows so they show current traveling in opposite directions on the sides of the loop.
Explanation:
Since the direction of the arrows point north and south whereas the magnets are east and west, it means the arrows are not pointing in the correct direction. To correct it she will have to make sure the arrows are pointing in opposite directions of the magnet via the sides of the loop.
Answer:
The answer is B
Explanation: Good luck on the test!
What is the momentum of a 31.2 kg object traveling at a velocity of 2.1 m/s?
Answer:
p = 65.52 kg m/s
Explanation:
p = m × v
p = 31.2 × 2.1
p = 65.52 kg m/s
Question
Type your response in the box,
What are some of the mental and physical health risks associated with a sedentary lifestyle?
Answer:
one for physical is that your muscles will seize up or cramp when you try to move. one for mental is that if your always sitting down you will most likely become stressed or get depression
Explanation
the reason your muscles cramp is from lack of exercise form sitting they get used to that position and want to stay that way. then theres the deprestion ive had it it aint fun nor is stress ive had that too
1. A record with a radius of 0.3m spins in a clockwise circle with a centripetal
acceleration of 4.7 m/s2. How long does it take the record to make one revolution?
(Hint: Find tangential velocity first!)
Solve for the linear/tangential speed:
a = v²/r
where a = centripetal acceleration, v = speed, and r = radius.
4.7 m/s² = v²/(0.3 m)
v² = (0.3 m) (4.7 m/s²)
v ≈ 3.96 m/s
For every time the record completes one revolution, a fixed point on the edge of the record travels a distance equal to its circumference, which is 2π (0.3 m) ≈ 1.88 m. So if 1 rev ≈ 1.88 m, then the angular speed of the record is
(3.96 m/s) (1/1.88 rev/m) ≈ 7.46 rev/s
Take the reciprocal of this to get the period:
1 / (7.46 rev/s) ≈ 0.134 s/rev
So it takes the record about 0.134 seconds to complete one revolution.
Find the period of an ideal spring, with a spring constant of 3.58 N/m, oscillating with 0.15kg mass attached.
The period of an ideal spring with a spring constant of 3.58 N/m and a 0.15 kg mass attached is approximately 1.285 seconds.
We will use the formula for the period of a simple harmonic oscillator to find the period of an ideal spring with a spring constant (k) of 3.58 N/m and a mass (m) of 0.15 kg
T = 2π√(m/k)
Here, T represents the period, which is the time taken for one complete oscillation. In this case, k = 3.58 N/m and m = 0.15 kg.
Now, we can plug the given values into the formula:
T = 2π√(0.15 kg / 3.58 N/m)
T ≈ 2π√(0.0419 s²)
T ≈ 2π × 0.2047 s
T ≈ 1.285 s
Therefore, 1.285s (approximately) seconds is the period of the ideal spring with a spring constant of 3.58 N/m and a 0.15 kg mass attached.
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During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
collides head-on with a 120-kg lineman moving westward with a speed of 8 m/s.
The two players collide and stick together, moving at the same velocity after the
collision. Determine the post-collision velocity of the two players.
Answer:
-1.24 m/s
Explanation:
Total momentum before collision = total momentum after collision
Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).
Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back 6 m/s (east), velocity of line back = -8 m/s (west). Hence:
Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s
The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.
Let velocity after collision be v, hence:
The total momentum after collision = (112 + 120)v = 232v
Total momentum before collision = total momentum after collision
-288 = 232v
v = -288 / 232
v = -1.24 m/s
Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).
PLEASE HELP!!! What is the name of ionic bond Mgo? What is the name of covalent bond CH4 (pretend the 4 is a subscript for the H only)
In an oscillating LC circuit, the maximum charge on the capacitor is qm. Determine the charge on the capacitor, q, and the current through the inductor, I, when energy is shared equally between the electric and magnetic fields. Express your answers in terms of qm, L, and C.
Answer:
a. q = qm/√2 b. qm/√(2LC)
Explanation:
a. Charge on the capacitor
Let U₁ = energy in inductor and U₂ = energy in capacitor and U = total energy in circuit.
So, U₁ + U₂ = U.
Since the energy is shared equally between the capacitor and inductor, U₁= U₂,so
2U₂ = U
and U₂ = U/2
Now U₂ = q²/2C where q is the charge on the capacitor with capacitance C and
U = (qm)²/2C where qm is the maximum charge on the capacitor.
Since U₂ = U/2,
Substituting the values for U₂ and U, we have
q²/2C = [(qm)²/2C]/2
q² = (qm)²/2
taking square-root of both sides, we have
q = qm/√2
b. The current in the inductor
Since the energy in the capacitor equals the energy in the inductor,
1/2LI² = 1/2q²/C where L is the inductance of the inductor and I the current through it.
I² = q²/LC
taking square-root of both sides, we have
I = q/√LC
substituting the value of q from above, we have
I = qm/√2 ÷ √LC
I = qm/√(2LC)
Why is the speed of different sounds in a single medium remain the same though wavelength is different?
Answer:
I think it's because the refractive index of that medium is constant