What creates a weather front?

Answer:

\(m_{PbI_2}=18.2gPbI_2\)

Explanation:

Hello,

In this case, we write the reaction again:

\(Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)\)

In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:

\(n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2} *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI} *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI\)

Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:

\(0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI\)

But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:

\(m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2\)

Best regards.

Answer:

Mass PbI2 = 18.19 grams

Explanation:

Step 1: Data given

Volume solution = 99.8 mL = 0.0998 L

mass % KI = 12.0 %

Density = 1.093 g/mL

Volume of the other solution = 96.7 mL = 0.967 L

mass % of Pb(NO3)2 = 14.0 %

Density = 1.134 g/mL

Step 2: The balanced equation

Pb(NO3)2(aq) + 2 KI(aq) ⇆ PbI2(s) + 2 KNO3(aq)

Step 3: Calculate mass

Mass = density * volume

Mass KI solution = 1.093 g/mL * 99.8 mL

Mass KI solution = 109.08 grams

Mass KI solution = 109.08 grams *0.12 = 13.09 grams

Mass of Pb(NO3)2 solution = 1.134 g/mL * 96.7 mL

Mass of Pb(NO3)2 solution = 109.66 grams

Mass of Pb(NO3)2 solution = 109.66 grams * 0.14 = 15.35 grams

Step 4: Calculate moles

Moles = mass / molar mass

Moles KI = 13.09 grams / 166.0 g/mol

Moles KI = 0.0789 moles

Moles Pb(NO3)2 = 15.35 grams / 331.2 g/mol

Moles Pb(NO3)2 = 0.0463 moles

Step 5: Calculate the limiting reactant

For 1 mol Pb(NO3)2 we need 2 moles KI to produce 1 mol PbI2 and 2 moles KNO3

Ki is the limiting reactant. It will completely be consumed ( 0.0789 moles). Pb(NO3)2 is in excess. There will react 0.0789/2 = 0.03945 moles. There will remain 0.0463 - 0.03945 = 0.00685 moles

Step 6: Calculate moles PbI2

For 1 mol Pb(NO3)2 we need 2 moles KI to produce 1 mol PbI2 and 2 moles KNO3

For 0.0789 moles KI we'll have 0.0789/2 = 0.03945 moles PbI2

Step 7: Calculate mass of PbI2

Mass PbI2 = moles PbI2 * molar mass PbI2

Mass PbI2 = 0.03945 moles * 461.01 g/mol

Mass PbI2 = 18.19 grams

Answer:

See explanation

Explanation:

The acid commonly used to acidify KMnO4  is H2SO4. The reason why HNO3  is not used is because HNO3  is itself a strong oxidizing agent. HCl is not used because it can react with KMnO4.

FeSO4 solution is usually prepared fresh when needed because if the solution is prepared and left to stand for sometime, FeSO4  is oxidized to Fe2(SO4)3 by air. Fe III does not give the brown ring test.

Alkali are not stored in glass stopped reagent bottles because very strong alkali can cause the stopper to corrode and fuse to the neck of the bottle making it very difficult to open the reagent bottle.

The volume of the block in cm³ is 1042.73 cm³ and the volume in L is 1.04 L. The density of the block is 0.907 g/ml. The density of the liquid is 0.928 g/ml which is greater than that of the block. Hence, the block will not sink instead it will float on the liquid.

Density of an object is the measure of its mass per unit volume. Hence, it is the ratio of its mass to the volume.

Given, the dimensions of the block

l = 11.1 cm

b = 154 mm= 15.4 cm

h = 0.061 m = 6.1 cm

then volume  = lbh = 15.4  cm ×11.1 cm× 6.1  cm = 1042.73 cm³ = 1042.7 ml.

The volume in L = 1042.7 ml/1000  = 1.04 L.

Density of the block = mass/volume

mass = 946 g.

d = 946 g/1042.7 ml = 0.907 g/ml.

The density of 780 ml liquid of mass 724.1 g  = 724.11 g  /780 ml = 0.928 g/ml.

The density of the block is lower than the density of the liquid. Hence, the block will float on the liquid.

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Answer:

\(m_{O_2}=6gO_2\)

Explanation:

Hello,

In this case, given the reaction:

\(2S+3O_2\rightarrow 2SO_3\)

Thus, for 4.00 g of sulfur (atomic mass = 32 g/mol), we apply the shown 2:3 mole ratio with oxygen (molar mass = 32 g/mol) in order to compute its requirement:

\(m_{O_2}=4.00gS*\frac{1molS}{32gS}*\frac{3molO_2}{2molS}*\frac{32gO_2}{1molO_2}\\ \\m_{O_2}=6gO_2\)

Best regards.

The mass of oxygen would be required is \(6gO_2\)

\(= 4.00 \times \frac{1molS}{32gS} \times \frac{3molO_2}{2molS} \times \frac{32gO_2}{1molO_2} \\\\= 6gO_2\)

Here for 4.00 g of sulfur (atomic mass = 32 g/mol), we used the shown 2:3 mole ratio with oxygen (molar mass = 32 g/mol).

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After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:

ExplaIf the organism was transported to a new ecosystem in the USA, this species will be an invasive species, which will reproduce more, and will not have a specific predator, which may bring an imbalance to the ecosystem.

What are Invasive Species?

Invasive Exotic Species or, simply, Invasive Species is defined as an exotic species that proliferates without control and starts to pose a threat to native species and to the balance of ecosystems that it occupies and transforms in its favor. It can even pose a risk to people.

With this information, we can conclude that caution is needed when introducing a new species into a new ecosystem.

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Answer:

The porosities in dental materials can be of merit and not merit since some dental materials need to be porous in order to reduce their weight and improve their properties and functions, whereas in those (which are the majority) porosities are not Merit, see the properties of the material, the function and can even influence dental rehabilitation.

An example of this is the use of vitreous ionomers, which is a dental material, where when it is spatulated it remains porous, it can give recurrence of infectious caries, since its permeability increases, the best cariogenic microorganisms are filtered and porosity works as a retentive site for these microorganisms that make up the dental biofilm.

In summary, the world of dental materials is very wide, some are resins, other cements, others have metallic claims, etc. To say that the presence of porosity is merit or demerit would be ideal because for some materials this is favorable and for others unfavorable since they are very versatile, with different qualities, different degrees of porosity, different molecules, different coefficients of thermal expansion, some do not set, others do not, some are light-cured, others do not, some withstand more mechanical forces and have more elastic modulus and less porosity, while others do not, and thus with many more variables.

Explanation:

In the manufacture of dental materials, much attention is always paid to what the manufacturer indicates in these indications that come on the reverse side of the material or on a paper inside the material container.

This is important to know, because the manufacturer is the one that indicates the mode of use and working time according to the trademark and the chemical composition of the dental material.

That a dental material in its manufacture is more or less porous, makes its density, weight and volume possibly be affected, there are materials that seek to increase porosity for a certain purpose, while others seek the opposite, depending on the function that is applied, will have more or less pores.

The example we gave above about the vitreous ionomer is an example that indicates that in the case of restorative dental materials where the function is to SEAL the porosity is almost nil, since otherwise it will not seal the cavity that was formed with caries and not the infectious problem would be solved.

On the other hand, in the surgical field of dentistry there are bone grafts or porous macroparticles that are for the purpose of bone replacement, which in order to be integrated need blood vessels that run over these pores, irrigating the area of ​​bone neoformation well, in this case the merit of porosity if necessary and it is essential that they be very porous.

The rate of a reaction is proportional to the some power of the molar concentration of each of the reactants. The order gives us an idea about the kinetics of the reaction.

The order of a reaction is defined as the sum of the powers of the concentration terms of the reactants in the experimentally determined rate equation for the reaction. It is an experimental quantity.

a. The order of the alkene is 1

b. The order of the bromine s 2

c. The overall kinetic order is 3

Since the reaction is third order, the overall rate constant is mol²L⁻²s⁻¹ or M⁻²s⁻¹.

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we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Explanation:

transpiration good luck

Answer:

Transpiration

Explanation:

I took a quiz on the water cycle and this was the correct answer. if I am wrong then I am sorry but I'm pretty sure this is correct.

1. Atomic orbitals are the quantum states of the individual electrons in the electron cloud around a single atom. Specifically, atomic orbitals are the quantum states of the individual electrons in the electron cloud around a single atom.

2. All The Bohr Model has an atom consisting of a small, positively charged nucleus orbited by negatively charged electrons. Here's a closer look at the Bohr Model, which is sometimes called the Rutherford-Bohr Model.

3. According to the de Broglie concept of matter waves, the matter has dual nature. It means when the matter is moving it shows the wave properties (like interference, diffraction etc.) are associated with it and when it is in the state of rest then it shows particle properties. Thus the matter has dual nature.

Benjemin

Answer:

The temperature of this sample changes by 1.052 degrees Celsius

Explanation:

As we know

\(Q = mc\Delta T\)

Where m is the mass of the substance

c is the specific heat of the substance

and \(\Delta T\) is the change in temperature

Substituting the given values in above equation, we get -

\(114.6 = 108.9 * 1 * \Delta T\\\Delta T = 1.052\)degree Celsius

The temperature of this sample changes by 1.052 degrees Celsius

Answer:

The cumulonimbus cloud

Explanation:

The cumulonimbus cloud, or thunderstorm, is a convective cloud or cloud system that produces rainfall and lightning. It often produces large hail, severe wind gusts, tornadoes, and heavy rainfall.

pls mark brainliest

Answer:

cumulonimbus clouds

Explanation:

that's the answer.

The affect of radiation on healthy cells can be reduced when treating cancer by focusing the radiation on the cancerous cells.

These side effects are also known as late side effects, which causes the human healthy cells after some time. The Doctors try to protect the healthy human cells by lowering the power of the radiations as possible. The radiation dose is balanced between being high enough to kill cancer cells, yet low enough to limit damage to healthy cells. If we use the advancement of technology of dose conformity such as IMRT, SBRT, and IGRT, then we can get rid of such dangerous radiations.

So we can conclude that the affect of radiation on healthy cells can be reduced when treating cancer by focusing the radiation on the cancerous cells.

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Answer:

Explanation:

Hey there!

From question;

The molecular mass of NH₄OH is 35.

Avogadro number = 6.023*10²³ molecules.

Then,

From mole concept,

Molecular mass =  Avogadro number

So, 35 grams contains  6.023*10²³ molecules.

1 gram contains \(\frac{ 6.023*10^{23} }{35}\) molecules.

52.1 grams contains \(\frac{6.023*10^{23} }{35} *52.1\) molecules.

Therefore, 52.1 grams contains 8.96*10²³ molecules.

Hope it helps!

The given chemical equation, 2N₂ + 3H₂ <==>2NH3, is an example of a reversible reaction.option A.

The double arrows between the reactants and products indicate that the reaction can proceed in both directions, forming both products and reactants.The reversible reaction, also known as a chemical equilibrium reaction, refers to a chemical reaction that can occur in both forward and reverse directions. It occurs when reactants are converted into products, and the products are also converted back into the original reactants.A reversible reaction can be identified by the symbol “<==>” or “⇌” that appears between the reactants and products in the chemical equation. It denotes that the reaction is in a state of chemical equilibrium. When the reactants and products have achieved equilibrium, the rate of the forward and reverse reactions is equal, and there is no further net change in the amounts of the reactants and products.A combustion reaction is a type of exothermic reaction in which a substance reacts with an oxidizing agent to produce heat and light. A one-way reaction is a type of reaction that occurs in only one direction and cannot be reversed without significant changes to the reaction conditions, such as changing the temperature or pressure.A reversible reaction, unlike a one-way reaction, can occur in both directions and reach equilibrium when the forward and reverse reaction rates are equal.option A.

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Answer:

I₂CL₆

Explanation:

Answer12C1

Explanation:

The type of reaction that will occur if AH is negative and entropy increases is option  A which is a spontaneous reaction .

The spontaneity of any chemical reaction depends on the Gibbs free reaction which is related to entropy change and enthalpy change.ΔG= ΔH-TΔS

Where T is temperature change in kelvin.If AH is negative, entropy will increases which is ΔS. Then the ΔG will depend on the temperature change.

If TΔS is larger than ΔH, the reaction will be spontaneous and ΔG will be negative which means the reaction will move forward without any external input.

When a change in entropy increases with the temperature in the system, the reaction will be spontaneous and this will make the Gibbs free energy to be negative.

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Answer:

Explanation:

The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:

Now we can convert 934.32 g of Ca₃(PO₄)₂ into moles:

Valence electrons are the electrons in the outermost shell of an atom and are responsible for chemical reactions. In a chemical reaction, atoms gain or lose electrons to achieve a stable electron configuration, which is known as the octet rule. The number of valence electrons an atom has determines its chemical reactivity and how it will bond with other atoms. For example, atoms with only a few valence electrons, such as hydrogen, are highly reactive and will readily form chemical bonds, while atoms with many valence electrons, such as noble gases, are relatively unreactive and do not easily form chemical bonds.

Answer:

I dont see the answers

Explanation:

Without hybridization, boron can form 4 bonds

Hybridisation is phenomenon of combining two atomic orbitals to give a new degenerate hybrid orbital which have same energy levels. Hybridization increases the stability of bond formation than unhybridized orbitals. We can predict the shape of molecules by its hybridization.

With hybridization , boron can form 3 bonds.

Hence, without hybridization, Boron donates the lone pair of electrons to form the fourth bond. In addition to that Boron is a second period element hence, which makes it small in size and d-orbitals are unavailable as well. Hence, Boron can only form 4 bonds with hybridization.

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Answer:

See below

Explanation:

No ionic bond can ever be 100% ionic and 100% covalent bonds do not exist either except for those between two identical atoms.

Electron density in covalent bonds shifts toward the more electronegative atom, producing partial charges on each atom creating a dipole.

Electron clouds are easily polarized, affecting the electrical balance of atoms, ions, or molecules. Large negative ions are readily polarized by small positive ions, increasing the covalent character of the bond between them.

The reason why chemical bonds are neither 100% ionic or 100% covalent is because electron transfer or sharing is never complete.

In chemistry there are two bonding extremes in compounds; Ionic bonds and covalent bonds. Ionic bonds involve a transfer of electrons from one atom to another while covalent bonds involves a sharing of electrons between atoms.

However, in a chemical compound, electrons are not completely transferred and electrons are not completely shared. This depends on the electronegativity of each of the atoms involved. Electron transfer or electron sharing in compounds is never complete. Hence, for every compound, there is a certain percentage of each kind of bond present.

According to Linus Pauling, in every ionic bond there is a certain percentage of covalent character and in every covalent bond there is a certain percentage of ionic character.

Therefore, Hcl is not 100% covalent and Nacl is not 100% ionic.

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A pressure of 12.5 atm is required to pop a kernel of popcorn. It's worth noting that this is a very high pressure, and it's the build-up of this pressure that causes the kernel to "pop".

To calculate the pressure required to pop a kernel of popcorn, we need to use the ideal gas law, which relates the pressure (P), volume (V), temperature (T), and number of moles of gas (n) in a system:

PV = nRT

Where R is the universal gas constant. We can assume that the temperature inside the popcorn kernel just before it pops is the same as the temperature in the microwave (100°C or 373 K). We also know that the only gas inside the kernel is water vapor, which has a molecular weight of 18 g/mol.

To calculate the number of moles of water vapor that is produced during the popping of the kernel, we can use the mass of water in the popcorn:

n = m/M

Where m is the mass of water (16.7 g) and M is the molar mass of water (18 g/mol). This gives us:

n = 16.7 g / 18 g/mol = 0.9286 mol

Now we can rearrange the ideal gas law to solve for pressure:

P = nRT / V

Substituting the known values, we get:

P = (0.9286 mol)(0.0821 Latm/molK)(373 K) / 3.1 L

P = 12.5 atm

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Answer:

\( \huge{ \boxed{111.30 \: \: \text{moles}}}\)

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\( \bold{n = \frac{N}{L} \\ }\)

where

n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question.

N = 6.7 × 10²⁵ \( \: H_2SO_4 \: \) molecules

\(n = \frac{6.7 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 111.2956...\)

We have the final answer as.

The given question is not complete, the complete question is:

Suppose a reaction mixture, when diluted with water, afforded 300 mL of an aqueous solution of 30 g of the reaction product malononitrile [CH2(CN)2], which is to be isolated by extraction with ether. The solubility of malononitrile in ether at room temperature is 20.0 g/100 mL, and in water is 13.3 g/100mL. The ratio of these quantities is equal to the partition coefficient, k, which equals What weight of malononitrile would be recovered by extraction of (a) three 100-mL portions of ether and (b) one 300-mL portion of ether? SHOW WORK (Can be written in pen and attached to report). Suggestion: For each extraction, let x equal the weight extracted into the ether layer. In part (a), for the first of the three extractions, the concentration of malononitrile in the ether layer is x/100 and in the water layer is (30-x)/100.

Answer:

The correct answer is 10 grams and 18 grams.

Explanation:

Based on the given question, 20 gram per 100 ml is the solubility of malononitrile in ether, and 13.3 gram per 100 ml is the solubility of malononitrile in water.  

Thus, the ration of the solubility is,  

Solubility in water/solubility in ether = 20/13.3 = 1.50

a) Let w be the weight of malononitrile extracted into water in every extraction. Then the concentration of the ether layer will be w/100. The concentration in the water layer will be 30-w/300. Now the ratio will be,  

Ratio = w/100 / (30-w)/300

1.50 = w/100 * 300 (30-w)

w = 10

Hence, the weight of malononitrile recovered by extraction is 10 grams.  

b) The concentration in the ether layer will be w/300. The concentration in the water layer will be (30-w) / 300. Now the ratio will be,  

Ratio = w/300 / (30-w) / 300

1.50 = w/300 * 300 (30-w)

w = 18

Hence, 18 grams is the weight of malononitrile recovered by extraction.  

Answer:

3p⁶ 4s² 3d²

Explanation:

From the question given above,

The electronic configuration of the element ends with 3p².

Another element having 8 more electrons will have the following electronic configuration as illustrated below:

Step 1:

Complete the 3p orbital by adding 4 electrons:

3p² + 4 electrons = 3p⁶

Step 2:

Fill the 4s orbital. This is so because 4s has a lower energy level compared to 3d.

4s²

Step 3:

Fill the 3d orbital with the remaining electrons i.e 2

3d²

Summary:

The continuation of the electronic configuration of the element with 8 more electrons is:

3p⁶ 4s² 3d²

Considering the electronic configuration, the electronic configuration of the element with 8 more electrons is:  3p⁶ 4s² 3d²

The Electronic Configuration of the elements is the arrangement of all electrons of an element in energy levels and sub-levels (orbitals).  

There are 7 energy levels, in which electrons are distributed, logically in order according to their energy level.

Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4. These 4 sub-levels are called: s, p, d, f.

In the sub-level s there can only be a maximum of 2 electrons, in sub-level p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

In level 1 there is only 1 sub-level, which will be the s. In level 2 there are 2 sub-levels, the s and the p. At level 3 there are 3 sub-levels: s, p and d. And at level 4 there are 4 sub-levels, the s, the p, the d and the f.

Aufbau's principle is a principle of atomic physics, which explains how electrons are accommodated in their orbits around the nucleus of the atom. This principle states that the filling of these orbitals occurs in increasing order of energy, that is, from the orbitals of lower energy to those of higher energy.

In this case, the electronic configuration of the element ends with 3p².  Another element having 8 more electrons.

In first place, you need to complete the 3p orbital by adding 4 electrons:

3p² + 4 electrons = 3p⁶

Then, you need to fill the 4s orbital with 2 electrons. This is so because 4s has a lower energy level compared to 3d.

4s²

Finally, you fill the 3d orbital with the remaining 2 electrons.

3d²

In summary , the electronic configuration of the element with 8 more electrons is:  3p⁶ 4s² 3d²

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Answer:

Calcium Nitrate

Explanation: