What contributes to the better resolution of the Hubble telescope.

Given:

Speed of the toy car max speed = 15 m/s

Time taken before the battery dies = 30 minutes.

Let's find how far the car went.

To find the distance the car travelled, aply the formula:

Where:

Speed = 15 m/s

time = 30 min

Convert the speed to meters per hour

Convert the time to hour.

Where:

1 hour = 60 mins = 3600 seconds

Thus, we have:

• Speed in m/h:

• Time in hour:

To find the distance, we have:

Therefore, the toy car travelled 27000 meters.

ANSWER:

27000 meters.

Answer: the marble would take 0.9 seconds

(a) under the assumption that all radio waves that hit the ground are entirely absorbed and that neither the atmosphere nor any other objects absorb. Therefore, the intensity 32.0 km away is approximately 7.72 × 10⁻⁶ W/m² and the maximum electric field strength at a distance of 32.0 km is approximately 2.54 × 10⁻⁴ V/m.

(a) Intensity (I) is defined as the power per unit area:

I = P/A

Half of the power will be spread over the surface area of a hemisphere, so the effective area (A) is:

A = 2πR²

Using the given radius:

A = 2π(32,000 m)² = 2π(1.024 × 10⁹ m²) = 2.048π × 10⁹ m²

Now we can calculate the intensity:

I = P/A = 50,000 W / (2.048π × 10⁹ m²) = 7.72 × 10⁻⁶ W/m²

(b) Maximum Electric Field Strength (E): I = (c × ε₀/2) × E²

We can rearrange the equation for intensity and solve for E:

E² = (2I) / (c × ε₀)

E = √((2I) / (c × ε₀))

Using the values:

E = √((2 × 7.72 × 10⁻⁶ W/m²) / (3.00 × 10⁸ m/s × 8.85 × 10⁻¹² C²/(N·m²)))

Calculating this expression, we find:

E = 2.54 × 10⁻⁴ V/m

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Answer:

Yes your correct.

Explanation:

Answer:

Primero, definimos el desplazamiento como la distancia entre la posición final y la posición inicial.

Así, si comenzamos abajo, luego subimos la escalera, y luego bajamos, la posición final y la posición inicial serán la misma

por lo que el desplazamiento es igual a cero.

La medida recorrida es el espacio total recorrido.

Es decir, si entre el principio y el final de la escalera hay una distancia D.

La persona que sube y baja, recorre esta distancia dos veces.

Entonces cuando una persona sube y baja la escalera, la medida de su trayectoria será 2*D.

a) Sketching the influence lines for the force in members BE, BC, and DA in a truss bridge requires a visual representation. Influence lines show the variation of forces in a structure due to the movement of a load.

Please refer to structural engineering resources or software for accurate sketches and graphical representations of the influence lines for these specific members in a truss bridge. These resources will provide detailed illustrations based on the structural dimensions, member properties, and load positions. Influence lines are valuable tools for structural engineers as they help identify critical load positions, assess the structural response, and determine the maximum forces experienced by different members. Please consult reliable structural engineering references, textbooks, or appropriate software that specifically address truss bridge analysis and design to obtain accurate sketches of the influence lines for members BE, BC, and DA. These resources will provide the necessary diagrams and detailed explanations based on the specific truss bridge configuration and load positions.

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Answer: 1200kg

Explanation:

KE = (1/2)mv^2

103kJ = 103000J

103000J = (1/2) * m * (13.1m/s)^2

Solve for m

A car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

A car has a kinetic energy of 103 kJ. The speed of the car is 13.1 m/s,

The kinetic energy of the car = 1/2 × mass × velocity

                                     103000 =0.5 × mass × (13.1) ²

The mass of the car = 1200 Kilogram

Thus, if a car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.

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Answer:

Explanation:

In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory.

Answer:

Cold temps. . .

Explanation:

Hope it helps!

Answer:

m2 = 13950 [kg]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which is defined as the product of mass by velocity, and can be determined by means of the following expression:

P = m*v

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now that momentum is conserved, we need to analyze the conditions before the collision and after the collision. In this way we must propose the following equation:

ΣPbefore = ΣPafter

(m1*v1) + (m2*v2) = (m1+m2)*v3

where:

m1 = mass of the railroad car = 9300 [kg]

v1 = velocity of the railroad car before the collision = 15 [m/s]

m2 = mass of the box car [kg]

v2 = velocity of the boxcar before the collision = 0 (the car is at rest)

(m1 + m2) = combined mass of the cars, they stick together after the collision [kg]

v3 = combined velocity of the cars after the collision = 6 [m/s]

(9300*15) + (m2*0) = (m1+m2)*6

139500 = (6*9300) + 6*m2

83700 = 6*m2

m2 = 13950 [kg]

The mass of the second railroad car which was initially at rest is 13950kg.

Given the data in the question;

Mass of railroad car2; \(m_2 = \ ?\)

Since railroad car2 was initially at rest,

After the strike, the wo cars stick together and moved

To determine the mass of the second railroad car, we use conservation of linear momentum:

\(m_1u_1 + m_2u_2 = (m_1 + m_2 )v\)

We substitute our given values into the equation

\((9300kg * 15m/s) + ( m_2 * 0 ) = ( 9300kg + m_2 )6m/s\\\\9300kg * 15m/s = ( 9300kg + m_2 )6m/s\\\\139500kg.m/s = 55800kg.m/s + ( m_2 * 6m/s )\\\\139500kg.m/s - 55800kg.m/s = m_2 * 6m/s\\\\83700kg.m/s = m_2 * 6m/s\\\\m_2 = \frac{83700kg.m/s}{6m/s} \\\\m_2 = 13950kg\)

Therefore, the mass of the second railroad car which was initially at rest is 13950kg.

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Answer:

a. 1.062 × 10⁻⁹ C/m² b. 5.472 × 10⁵ C c. 7.685 × 10⁹ V d. -210.12 V e. 4.972 × 10³ N f. F the electric force is much less than the gravitational force F₁ of the earth on the moon.

Explanation:

a. The surface charge density D = ε₀E where E = 120 N/C

D = ε₀E = 8.854 × 10⁻¹² F/m × 120 N/C = 1.062 × 10⁻⁹ C/m²

The charge density is positive since the electric field is positive or directed downwards. Only a positive charge could direct an electric field out of itself.

b. Since the surface charge density is uniform over the planet and charge, Q = DA where A = area of earth = 4πr² where r = radius of earth = 6.4 × 10⁶ m.

So Q = DA

= 1.063 × 10⁻⁹ C/m² × 4π × (6.4 × 10⁶ m)²

= 5.4715 × 10⁵ C

≅ 5.472 × 10⁵ C

c. The earth's electric potential due  to this charge Q is V = Q/4πε₀r

= 5.472 × 10⁵ C ÷ (4π × 8.854 × 10⁻¹² F/m × 6.4 × 10⁶ m)

= 5.472 × 10⁵ C ÷ 712.081 × 10⁻⁶ F

= 0.07685 × 10¹¹ V

= 7.685 × 10⁹ V

= 7.685 GV

d. Since V = Q/4πε₀r, and we are going to be dealing with a small change in length compared to r, we differentiate V to get the differential change in potential.

So, dV/dr = -Q/4πε₀r²

dV = -Qdr/4πε₀r² ,dr = 1.75 m

dV = -5.472 × 10⁵ C × 1.75 m ÷ [4π × 8.854 × 10⁻¹² F/m × (6.4 × 10⁶ m)²]

dV = -9.576 × 10⁵ Cm ÷ 4557.318 Fm

dV = -210.124 V

dV ≅ -210.12 V

e. Let Q₁ = charge on moon and Q₂ = charge on earth. Given that Q₁ = 0.273Q₂, the force of attraction between earth and moon is F = Q₁Q₂/4πε₀R² where R = distance between earth and moon = 3.844 × 10⁸ m

F = Q₁Q₂/4πε₀R²  

= 0.273Q²/4πε₀R²

= 0.273 × (5.472 × 10⁵ C)²/ [4π × 8.854 × 10⁻¹² F/m × (3.844 × 10⁸ m)²]

= 8.1744 × 10¹⁰ C²/1644.054 Fm × 10⁴

= 0.004972 × 10⁶ N

= 4.972 × 10³ N

= 4.972 kN

f. The gravitational force between earth and moon F₁ = Gm₁m₂/R² where m₁ = mass of moon = 7.3 × 10²² kg and m₂ = mass of earth = 5.97 × 10²⁴ kg.

F₁ = 6.67 × 10⁻¹¹ Nm²/kg² × 5.97 × 10²⁴ kg × 7.3 × 10²² kg/(3.844 × 10⁸ m)²

= 290.685 × 10³⁵ Nm²/14.776 × 10¹⁶ m²

= 19.67 × 10¹⁹ N

= 1.967 × 10²⁰ N

≅ 2 × 10²⁰ N

Since F₁/F = 1.967 × 10²⁰ N/4.972 × 10³ N = 3.95 × 10¹⁶ ≅ 4 × 10¹⁶.

F the electric force is much less than the gravitational force F₁ of the earth on the moon.

Answer:

See the answer below.

Explanation:

The weight of the table should be equal to the weight of the table plus the weight of the book.

\(w_{table}=m_{table}*g\\w_{table}=200*9.81\\w_{table}=1962[N]\)

And for the book

\(w_{book}=m_{book}*g\\w_{book}=50*9.81\\w_{book}=490.5[N]\)

And the total weight

\(w = w_{table}+w_{book}\\w=1962+490.5\\w = 2452.5 [N]\)

For the system to be in balance, the reaction force exerted by the table on the book must be equal to the weight of the book. This force in physics is known as the normal force.

\(N_{force} = w_{book}\\N_{force}=490.5[N]\)

The power is generated by the machine that lifts the 50 kg box a

distance of 15 m in 8 seconds is 918.75 W (2nd option)

We'll begin by obtaining the work done by the machine in lifting the box. Details below:

Wd = mgh

Wd = 50 × 9.8 × 15

Wd = 7350 J

Finally, we shall determine the power generated. Details below:

P = Wd / t

P = 7350 / 8

P = 918.75 W

Thus, the power generated is 918.75 W (2nd option)

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Answer:

The combination of cells in which the negative terminal of a first cell is connected with the positive terminal of second cell and the negative terminal of a second cell is connected to the positive terminal of a third cell and so on is known as series combination of cells.

Explanation:

hope this helps to u

Answer:

Battery.

When traveling twice as fast your kinetic energy is increased by four times.

Kinetic energy is the energy that can be seen as the motion of an item or a subatomic particle. It is also known as the energy of motion. Kinetic energy is a property that is shared by all moving objects and particles. To calculate the kinetic energy, we can use this following formula:

KE = ½ m × v²

Where:

M = mass of the body

V = velocity of the body

In this case, we are given that:

KE = ½ m × (2 × v)²

KE = 4 (½ × m × v²)

KE = 4 times initial KE

Therefore, the kinetic energy increases four times as the speed doubles.

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The curve showing the minimum amplitude at which sounds can be detected at each frequency is known as the frequency response curve.

A frequency response curve is a graphical representation of the output of a system in response to input signals at different frequencies. It shows how a system responds to signals of different frequencies, and is often used in the analysis and design of filters, amplifiers, and other electronic circuits.

In general, a frequency response curve shows the magnitude and phase of the system's output signal relative to its input signal, as a function of frequency. The magnitude response shows the ratio of the output signal amplitude to the input signal amplitude, expressed in decibels (dB), while the phase response shows the difference in phase between the output and input signals, expressed in degrees.

Frequency response curves can be plotted for a wide variety of systems, including electronic filters, loudspeakers, and human hearing. In the case of a loudspeaker, for example, the frequency response curve shows how the speaker reproduces different frequencies of sound. Ideally, a speaker should produce the same sound level across the entire range of audible frequencies, but in practice, different speakers have different frequency response curves, and may be more or less accurate at reproducing certain frequencies.

Frequency response curves are often used to design and optimize electronic circuits, such as filters, to achieve desired frequency responses. For example, a low-pass filter is designed to pass low-frequency signals while attenuating high-frequency signals, and its frequency response curve will show the amount of attenuation at different frequencies. By adjusting the filter's component values, the frequency response curve can be tailored to meet specific design requirements.

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Answer:

1.55

Explanation:

that it is the standard refractive index.

Answer:

C

Explanation:towards Erin

The rope will move towards Erin because, the force between them is unbalanced and the more force is exerted by Erin. Hence, the displacement will occur on the greater force side.

Force is an external agent acting on a body to change its motion or to deform it. The net force acting on the body depends on the direction and magnitude of all  the force acting on it.

If two equal forces acts on the body from the same side they add up together and the net force is their sum. If the forces are acting from the opposite sides, they will cancel each other and is said to be balanced.

Here, two forces from the side is un balanced by a force from the opposite side. Hence, the greater force from Erin will make the rope displaced towards her side. Thus, option C is correct.

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Electric field and magnetic field has both the attractive and repulsive character.

Electric field is defined as the region surrounding a charged particle, in which it experiences an electric force.

Here,

Electric field and magnetic field has both the attractive and repulsive character.

Both electric and magnetic fields obey the inverse square law.

Stationary charges produce electric field, whereas moving charges produce magnetic field.

Electric field is associated with two kind of charges, positive and negative, whereas magnetic field is associated with two magnetic poles, north and south.

Both electric field and magnetic field are associated with principle of superposition.

Hence,

Electric field and magnetic field has both the attractive and repulsive character.

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Answer:

La ecuación de onda lineal para una función f(x, t) se escribe como:

\(\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}\)

Donde c es una constante que depende de la velocidad de propagación de la onda.

En este caso, tenemos:

\(f(x) = A*e^{-i*(k*x - w*t + \phi)}\)

Recordar que la derivada de la exponente es tal que:

\(k(x,y) = A*e^{c*x + n*y}\\dk/dx = c*A*e^{c*x + n*y}\)

Entonces las derivadas de f van a ser:

\(\frac{df}{dt} = (i*w)*f(x)\)

\(\frac{d^2f}{dt^2} = (i*w)^2*f(x) = -(w)^2*f(x)\)

\(\frac{df}{dx} = (-i*k)*f(x)\)

\(\frac{d^2f}{dx^2} = (-i*k)^2*f(x) = -k^2*f(x)\)

Entonces podemos reescribir la ecuación de onda como:

\(\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}\)

\(-(w)^2*f(x) = c^2*(-k^2*f(x))\)

Ahora podemos simplemente definir c^2 = (w/k)^2 y vemos que la ecuación de onda se cumple.

1.24% percentage of parts will not meet the weight specs amd the sample means will fall between 25.046 and 25.354 ounces.

a. To determine the percentage of parts that will not meet the weight specifications, we need to calculate the probability of a part weighing less than 24.7 ounces or more than 25.7 ounces. First, we need to calculate the z-scores for these values using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. For 24.7 ounces:

z1 = (24.7 - 25.2) / 0.20 = -2.50

For 25.7 ounces:

z2 = (25.7 - 25.2) / 0.20 = 2.50

Using Table-A (Z-score table), we can find the area under the standard normal curve corresponding to these z-values. From the table, the area to the left of -2.50 is 0.0062, and the area to the right of 2.50 is also 0.0062. Therefore, the total probability of a part not meeting the weight specs is:

P(z < -2.50 or z > 2.50) = P(z < -2.50) + P(z > 2.50) = 0.0062 + 0.0062 = 0.0124

So, the percentage of parts that will not meet the weight specs is .

b. To determine the values within which 99.74% of the sample means will fall, we need to calculate the margin of error for a sample mean. The margin of error is given by the formula:

E = z * (σ / sqrt(n))

where E is the margin of error, z is the z-score corresponding to the desired level of confidence (in this case, 99.74% corresponds to a z-score of 2.75), σ is the standard deviation, and n is the sample size.

Plugging in the values:

E = 2.75 * (0.20 / sqrt(10)) ≈ 0.154

The range of sample means will be within ±E of the population mean. Therefore, the values within which 99.74% of the sample means will fall are:

25.2 ± 0.154 = (25.046, 25.354)

So, for samples of size 10, 99.74% of the sample means will fall between 25.046 and 25.354 ounces.

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Answer: 1/10th of its weight on Earth.

Explanation: Let's assume that the weight of the object on Earth is W, and the gravitational acceleration on Earth is g. We know that weight is given by the formula:

W = m * g where m is the mass

If the gravitational attraction on another planet is 1/10th of Earth's pull, then the gravitational acceleration on that planet will be:

g' = g/10

Using the same formula for weight, the weight of the object on the new planet will be:

W' = m * g'

Substituting the value of g' in the equation above, we get:

W' = m * (g/10)

W' = (m/10) * g

Therefore, the weight of the object on the new planet will be 1/10th of its weight on Earth.

W' = (100/10) N = 10 N

So, the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10th of Earth's pull would be 1/10th of its weight on Earth.

Answer:

440

Explanation:

1 mile =1760 yards

0.25 miles =?

\( \frac{0.25 \times 1760}{1} \)

=440 yards

In order to compare the numbers, let's put all of them into the decimal form:

We can see that the greater one is 26.8 (all other numbers are close to 2, and this one is close to 27).

The numbers in decrescent order are:

26.8, 271%, 2.62, 2 2/5, 2.26.

Answer:

26.8

Explanation:

2.26 < 2.4 < 2.62 < 271/100 = 2.71 < 26.8

Answer:

b. a chair on a floor

Explanation:

All of the other objects are in motion, the jet is flying so it is not at rest, the rabbit is also moving, and a ball hit by a bat is also in motion

Answer:

It is directly proportional to the charge

Explanation:

Hope this helps : )

Answer:

4

Explanation:

TRUST ME AND I AM SORRY IF RONG

Answer:

The real answer should be 1391. Considering the mass x acceleration

For a successful final touch of a construction venture, key stakeholders consisting of the consumer/proprietor, architect/layout group, and creation contractor are crucial. Risk management is necessary to perceive and mitigate capacity risks, ensuring project success and minimizing disruption

The 3 important stakeholders for the development of a new mall in Alexandra are:

During the construction of an avenue in a particular network, the network is represented by:

Local Authorities: The local authorities, which include the municipal or city council, represent the community's pastimes. Their duties consist of engaging with the network to apprehend their needs and issues associated with the road construction project.

Before any sort of Civil Engineering mission is executed, the subsequent steps want to be taken to ensure the viability of the challenge:

The hierarchy of running for a contractor sporting out the development of a bridge typically consists of the subsequent degrees:

To draw the bar chart (also referred to as a Gantt chart) for a 50 km street creation undertaking with a duration of 10 days, the chart could represent the obligations and their respective intervals. However, a standard bar chart for an avenue creation undertaking may also include duties including surveying, excavation, laying subbase, paving, and street markings, amongst others.

The horizontal axis represents the timeline (in days), and the vertical axis represents the responsibilities. Each undertaking is represented with the aid of a horizontal bar that suggests its length.

Question 2 (10):

2.1 Risk control is vital in a venture for the following motives:

Overall, change management is important for figuring out, analyzing, and responding to risks in a systematic and proactive manner. It enables ensuring task success by using lowering uncertainties and maximizing opportunities for task delivery within the preferred parameters.

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