Answers:
1. Chemistry
2. Cold
3. Heat
4. Protons and neutrons
5. Positive
6. Neutral
7. True
8. Nucleus
9. Protons
10. Nobel gasses
11. Dmitri Mendeleev
12. the bottom of the square
13. True
14. Helium
To what temperature would 12.3g of He have to be cooled to fit a 34.0 l tank at 1.17 atm?
The ideal gas law may be used to calculate the temperature at which 12.3 g of He would need to be cooled to fit a 34.0 l tank at 1.17 atm. According to this rule, the ideal gas constant multiplied by the number of moles in the gas equals the product of an ideal gas's pressure, volume, and temperature.
In order to solve for temperature, we may thus rearrange the equation. PV = nRT, where P is for pressure, V is for volume, n is for moles, R is for the ideal gas constant, and T is for temperature, is the equation. By multiplying both sides of the equation by the inverse of P and dividing both sides by nR, we may find the value of T.This results in the formula T = PV/nR.
The values for P, V, and nR can be substituted for the predetermined conditions. The volume is 34.0 l and the pressure is 1.17 atm. By dividing the mass, 12.3 g, by He's molar mass, 4.00 g/mol, the amount of moles of He may be computed. 0.0821 L*atm/K*mol is the ideal gas constant. Plugging these values into the equation gives us a temperature of about -267.7 K.
Learn more about temperature at:
https://brainly.com/question/11464844
#SPJ1
Report the answer to the appropriate number of significant figures
Answer: 8.979
Explanation:
What are three things that living things need to live
water, food, and air.
Additionally:
Shelter and clothes
A one electron species, X m, where m is the charge of the one electron species and X is the element symbol, loses its one electron from its ground state when it absorbs 3.49 x 10-17 J of energy. Using the prior information, the charge of the one electron species is:_____________
a. +8
b. +2
c. +3
d. +1
e. +4
Answer:
Option C
Explanation:
From the question we are told that:
Difference in energy \(\delta E =3.49 * 10^{-17} J\)
The Ground state Difference in energy at n=1
\(\delta E_g = 2.18 * 10^{-18} × Z^2\)
Generally the equation for Difference in energy is mathematically given by
\(\delta E=\delta E_g\)
Therefore
\(3.49 * 10^{-17} = 2.18 * 10^{-18} * Z^2\)
\(Z^2=16\)
\(Z=4\)
Therefore
Charge on element Z Q_Z
\(Q_Z= Atomic\ no\. of\ element - No.\ of\ electrons\ of\ element\)
\(Q_Z =4-1\)
\(Q_Z=+3\)
Option C
Which hypothesis is most supported by astronomers?
A- The universe is currently expanding and will continue to expand.
B- Stars could burn out, causing the universe to become dark and cold.
C- Gravity could pull galaxies back together, causing a reverse of the big bang.
D- Dark energy will pull the universe together to form a massive black hole.
HURRY!!
Answer:
option A is the most supported hypothesis by astronomers
If Phosphorus, P, gained 3 electrons, the net ion charge would be
+5
-5
+3
-3
Answer:
-3
Explanation:
Phosphorus becomes phosphide with a -3 charge
how many grams of water are needed to react with 71.0g CaN2?
Answer:
1
Explanation:
Mass of
C
a
C
N
2
= 75.0 g
From the equation,
C
a
C
N
2
(
s
)
+
3
H
2
O
(
l
)
→
C
a
C
O
3
(
s
)
+
2
N
H
3
(
g
)
1 mol of
C
a
C
N
2
reacts with 3 moles of water to give calcium carbonate and ammonia.
Number of moles of
C
a
C
N
2
,
n
=
G
i
v
e
n
m
a
s
s
M
o
l
a
r
m
a
s
s
Molar mass of
C
a
C
N
2
= 92.11 g/mol
Therefore,
n
C
a
C
N
2
=
75
g
92
.11
g
/
m
o
l
=
0
.814
m
o
l
Moles of water =Therefore,
n
C
a
C
N
2
=
75
g
92
.11
g
/
m
o
l
=
0
.814
m
o
l
Moles of water =
3
×
0
.814
m
o
l
e
s
=
2
.442
m
o
l
e
s
Mass of water needed;
=
m
o
l
e
s
o
f
w
a
t
e
r
×
m
o
l
a
r
m
a
s
s
o
f
w
a
t
e
r
=
2
.442
m
o
l
×
18
g
/
m
o
l
=
43
.956
g
Thus, 43.96 g of water is needed to react with 75 g of
C
a
C
N
2
.
What’s the answer for this question which i have posted can I know the answers as possible
The change in internal energy = 2.701 x 10² kJ
Further explanationGiven
Heat absorbed by system = 1.69 x 10² kJ
Work done on system = 1.011 x 10² kJ
Required
The change in Internal energy
Solution
We can use the first law of Thermodynamics :
\(\tt \Delta U=Q+W\)
The sign rules for heat and work are set as follows:
• The system receives heat, Q +
• The system releases heat, Q -
• The system does work, W -
• the system accepts work, W +
Heat absorbed/receive heat from surrounding = Q+
Work done on the system = W+
and input the given values
\(\tt \Delta U= 1.69\times 10^2+1.011\times 10^2\\\\\Delta U=\boxed{\bold{2.701\times 10^2~kJ}}\)
a sample of nitrogen gas exerted a pressure of 1 atmosphere when kept in a container of volume 300cm3 in a refrigerator at a temperature of 3C. the gas is transferred to a larger container and allowed to reach a temperature of 25C and a pressure of 0.8 atmosphere. what is the volume of the larger container
Answer:
We can use the combined gas law to solve this problem:
(P1V1/T1) = (P2V2/T2)
where:
P1 = 1 atm (pressure of nitrogen gas in the first container)
V1 = 300 cm^3 (volume of the first container)
T1 = 3°C + 273.15 = 276.15 K (temperature of the nitrogen gas in the first container, converted to Kelvin)
P2 = 0.8 atm (pressure of nitrogen gas in the second container)
V2 = ? (volume of the second container, what we want to find)
T2 = 25°C + 273.15 = 298.15 K (temperature of the nitrogen gas in the second container, converted to Kelvin)
Plugging in the values, we get:
(1 atm x 300 cm^3) / 276.15 K = (0.8 atm x V2) / 298.15 K
Simplifying and solving for V2, we get:
V2 = (1 atm x 300 cm^3 x 298.15 K) / (0.8 atm x 276.15 K)
V2 = 1309.5 cm^3
Therefore, the volume of the larger container is approximately 1309.5 cm^3.
What is the partial pressure of helium gas in a mixture that contains 8.00 grams of helium and 8.60 mol argon gas with a total pressure of 48.0 torr?
Multiple Choice
9.06 torr
15.2 torr
23.1 torr
38.9 torr
Answer:
\(P_{He}=9.06torr\)
Explanation:
Hello there!
In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:
\(P_{He}=x_{He}P_T\)
Whereas the mole fraction of helium is calculated by firstly obtaining the moles and then the mole fraction:
\(n_{He}=8.00g\frac{1mol}{4.00g}=2.00mol\\\\ x_{He}=\frac{n_{He}}{n_{He}+n_{Ar}} \\\\ x_{He}=\frac{2.00mol}{2.00mol+8.60mol}\\\\x_{He}=0.189\)
Then, we calculate the partial pressure as shown below:
\(P_{He}=0.189 *48.0torr\\\\P_{He}=9.06torr\)
Best regards!
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
Why doesn't the red line showing the IR spectrum emitted from the earth's surface match the blue line showing the expected IR spectrum from a 300˚C object?
-Some of the light emitted is used to heat building.
-Molecules in the atmosphere such as CO2 and H2O absorb the radiation.
-Contrails from airplanes absorb the radiation cause the dip at 14 micrometers.
-IR radiation at 14 micrometers is not actually emitted by the earth's surface.
The red line showing the IR spectrum emitted from the earth's surface does not match the blue line showing the expected IR spectrum from a 300˚C object because:
Molecules in the atmosphere such as CO₂ and H₂O absorb the radiation; option B.What is IR spectroscopy?IR spectroscopy studies Infrared (IR) light in the electromagnetic spectrum.
Sensors are used by thermal detection systems, also known as infrared detection systems, to detect radiation in the infrared region of the electromagnetic spectrum.
In order to create an electronic signal, an infrared camera must first detect the thermal energy or heat, that the scene being seen emits. After processing this signal, an image is created.
Learn more about IR spectroscopy at: https://brainly.com/question/29493769
#SPJ1
Fill in the blank with the correct answer to complete the sentence.
Word bank
size
velocity
distance
time
Momentum increases with an increase in mass and
Explanation:
momentum increases with an increase in mass and velocity
What makes a compound
polar?
Answer:
Polar molecules occur when two atoms do not share electrons equally in a covalent bond. ... If the electronegativity difference between the atoms is greater than 2.0, the bond is ionic. Ionic compounds are extremely polar molecules.
Explanation:
In heating and melting curves of water, what is the melting point?
Explanation:
The melting point is the temperature and pressure at which the solid water will change into a liquid. That state change at 1 atm happens at 0 °C.
melting point = 0 °C = 273.15 K
Answer: the melting point is 273.15 K. Option A.
Silicon is a key component of electronic devices. This element is a(n)__, a type of element also called a(n)__.
Answer:
Metalloid ; semiconductor
Explanation:
At standard temperature and a pressure of 613 kPa, a sample of Cl₂ gas has a volume of 39.2 liters. How many grams of gas are in the
sample?
There are 0.144 grams of Cl₂ gas in the sample if at standard temperature and a pressure of 613 kPa, a sample of Cl₂ gas has a volume of 39.2 liters.
What is gas constant?The gas constant, denoted by the symbol R, is a physical constant that appears in the ideal gas law equation. The ideal gas law is an equation of state that describes the behavior of an ideal gas in terms of its pressure, volume, temperature, and the number of moles of gas present. The equation is:
PV = nRT
where P is the pressure of the gas, V is its volume, n is the number of moles of gas, T is its absolute temperature, and R is the gas constant.
To determine the number of grams of Cl₂ gas in the sample, we need to use the ideal gas law equation:
PV = nRT
where P denotes pressure, V denotes volume, n denotes the number of moles of gas, R denotes the gas constant, and T denotes temperature in Kelvin.
First, we need to convert the pressure to units of Pa:
613 kPa = 613,000 Pa
Next, we need to convert the volume to units of m³:
39.2 L = 0.0392 m³
The gas constant R is equal to 8.31 J/(mol K), and the temperature is assumed to be standard temperature, which is 273 K.
Now, we can rearrange the ideal gas law equation to solve for n:
n = PV/RT
Substituting the given values, we get:
n = (613,000 Pa)(0.0392 m³)/(8.31 J/(mol K) * 273 K)
Simplifying, we get:
n = 0.00203 mol
Finally, we can use the molar mass of Cl₂, which is 70.9 g/mol, to convert the number of moles to grams:
mass = n * molar mass
mass = 0.00203 mol * 70.9 g/mol
mass = 0.144 g
To know more about gas constant, visit:
https://brainly.com/question/30859506
#SPJ1
The sample of Cl₂ gas has a mass of approximately 0.095 grams.
What is Temperature?
Temperature is a measure of the average kinetic energy of the particles in a substance or system. It determines the direction of heat flow between two objects in contact, with heat flowing from the object with a higher temperature to the one with a lower temperature until they reach thermal equilibrium. The SI unit of temperature is the kelvin (K), which is defined based on the triple point of water, where the temperature is 273.16 K. Other common temperature scales include Celsius and Fahrenheit.
To solve this problem, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
First, we need to convert the pressure to the correct units. 613 kPa is equal to 6.13 × 10^4 Pa. We also need to convert the volume to cubic meters, since that is the SI unit of volume. 39.2 liters is equal to 0.0392 cubic meters.
Next, we need to rearrange the ideal gas law to solve for n:
n = PV/RT
We can look up the value of R: it is equal to 8.31 J/(mol·K).
Now we can substitute in the values we know:
n = (6.13 × 10^4 Pa)(0.0392 m^3)/(8.31 J/(mol·K) × 298 K)
Simplifying, we get:
n = 0.00134 mol
Finally, we can convert from moles to grams by multiplying by the molar mass of Cl₂. The molar mass of Cl₂ is approximately 70.9 g/mol.
mass = n × molar mass
mass = 0.00134 mol × 70.9 g/mol
mass = 0.095 g
Learn more about Temperature from given link
https://brainly.com/question/26866637
#SPJ1
1. Before starting, make a prediction: If substances B and C are both in the gas phase and are at the same energy level, which of the two substances will need to have more energy transferred out in order to change to the liquid phase? Substance B or substance C? Explain your answer.
Answer:
Substance C
Explanation:
Substance C would be the answer because Substance C has a lower attraction level. Because of this, it takes more energy to take out of in order to become a liquid.
For the following reaction: ΔHo = 178.3 kJ; ΔSo = 159.0 J/K
CaCO3(s) ↔ CaO(s) + CO2(g)
i. What is ΔGo at 1000 oC?
ii. What is the value of Kp at 1000 oC for this reaction?
The change in free energy is -24107 J. The equilibrium constant is 2.3.
What is the change in free energy?We know that the change in free energy of a reaction can be used to obtain the equilibrium constant of the reaction. On the other hand, we know that change in free energy can be obtained from the enthalpy and the entropy as follows;
ΔGo = ΔHo - T ΔSo
ΔGo = Change in free energy
ΔHo = change in enthalpy
T = temperature change
ΔSo = Change in entropy
Then;
ΔGo = 178.3 * 10^3 - (1273 * 159)
ΔGo = 178300 - 202407
ΔGo = -24107 J
Then we have;
ΔGo = -RTlnKp
R = gas constant
T = temperature
Kp = Rate constant
Thus;
Kp = ΔGo / -RT
Kp = -24107 /-(8.314 * 1273)
Kp = 2.3
Learn more about rate constant :https://brainly.com/question/20305871
#SPJ1
At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. You may want to reference (pages 641 - 644) section 15.6 while completing this problem. Part a if the initial concentration of no is 0.175 m, what is the equilibrium concentration of no? how is the quadratic equation set up i cannot get the right values
Which option gives an object's volume in SF units?
O
A. 4.3 kg
B. 2.6 m3
C. 5.5 K
D, 3.4L
SUBMIT
Answer:
The correct answer is:
2.6 m3 (B)
Explanation:
SF unit stands for Stowage factor unit. Stowage factor is the volume occupied by one unit of mass (weight) when stowed in cargo space. SF expresses the unit in cubic meters (m³) or cubic feet. SF is a unit of measurement that indicates how much space (volume) a particular unit of cargo occupies in a ship's cargo compartment
Calculate the empirical formula for each of the following substances. (Express answer as a chemical formula) 1) 2.90 g of Ag and 0.125 g of N 2) 2.22 g of Na and 1.55 g of S 3) 2.11 g of Na, 0.0900 g of H, 2.94 g of S, and 5.86 g of O 4) 1.84 g of K, 0.657 g of N, and 2.25 g of O
Answer:
1) Ag3N
2)Na2S
3)NaHSO4
4) KNO3
Explanation:
We divide each mass by the element's relative atomic mass
1) 2.90/108-Ag, 0.125/14-N
0.027-Ag, 0.0089-N
Divide by the lowest ratio
0.027/0.0089-Ag, 0.0089/0.0089 N
3-Ag, 1-N
Empirical formula- Ag3N
2)2.22/23-Na, 1.55/32-S
0.097-Na, 0.048-S
Divide by the lowest ratio
0.097/0.048-Na, 0.048/0.048-S
2-Na, 1-S
Empirical formula- Na2S
3) 2.11/23-Na, 0.0900/1-H, 2.94/32-S,5.86/16-O
0.09-Na, 0.09-H, 0.09-S,0.366-O
Divide by the lowest ratio
0.09/0.09-Na, 0.09/0.09-H, 0.09/0.09-S, 0.366/0.09-O
1-Na, 1-H, 1-S, 4-O
Empirical formula- NaHSO4
4)1.84/39, 0.657/14-N, 2.25/16-O
0.047-K, 0.047-N, 0.14-O
Divide through by the lowest ratio
0.047/0.047-K, 0.047/0.047-N, 0.14/0.047-O
1-K, 1-N, O-3
Empirical formula- KNO3
Which of the following is the correct statement of law of conservation of matter?
According to the principle law of conservation of mass, matter cannot be created or destroyed.
What law governs the conservation of matter?According to the Law of Conservation of Matter, even when matter transforms into a different form, the amount of matter remains constant. Although it may occasionally appear that matter vanishes during a scientific experiment, this law informs us that matter does not magically appear or vanish; rather, it only transforms from one form to another.
What is the mass Mcq conservation law?A chemical reaction neither creates nor destroys atoms.Only the products are produced after the reactants' atoms have been rearranged. Therefore, mass remains constant during a chemical process.
To know more about law of conservation visit:-
https://brainly.com/question/24131537
#SPJ4
HELP PLEASE PLEASE PLEASE. Can anyone tell me how to separate the following mixture
A) ethanol in water
B) boiling the mixture of chloride crystals with water
C) pure water from muddy water
D) sodium chloride in water
E) sodium carbonate in water
F) chlorophyll from leaves
G) mixture of acetic acid and alcohol
H) serum from blood sample
I) kerosene from water
J) ammonium chloride in sand
I NEED CORRECT ANSWERS ONLY.
HURRY UP PLEASE. I WILL MARK AS BRAINLIEST
A) Ethanol in water: Distillation.
B) Boiling the mixture of chloride crystals with water: Evaporation.
C) Pure water from muddy water: Filtration.
D) Sodium chloride in water: Evaporation or Crystallization.
E) Sodium carbonate in water: Filtration or Evaporation.
F) Chlorophyll from leaves: Extraction using a suitable solvent like ethanol.
G) Mixture of acetic acid and alcohol: Distillation.
H) Serum from blood sample: Centrifugation.
I) Kerosene from water: Separatory funnel or Decantation.
J) Ammonium chloride in sand: Sublimation or Dissolving in water and Filtration.
A) Ethanol in water: Distillation can be used to separate ethanol from water based on their different boiling points.
B) Boiling the mixture of chloride crystals with water: By heating the mixture, the water will evaporate, leaving behind the chloride crystals.
C) Pure water from muddy water: Filtration can be used to separate the solid particles (mud) from the water.
D) Sodium chloride in water: Evaporation can be used to separate sodium chloride from water by heating the mixture until the water evaporates, leaving behind the salt.
E) Sodium carbonate in water: Filtration can be used to separate solid sodium carbonate from water, similar to muddy water.
F) Chlorophyll from leaves: Extraction using a suitable solvent like ethanol or acetone can be used to separate chlorophyll from leaves.
G) Mixture of acetic acid and alcohol: Distillation can be used to separate the mixture based on their different boiling points.
H) Serum from blood sample: Centrifugation can be used to separate the serum, which is the liquid part of blood, from the solid components like cells.
I) Kerosene from water: Separatory funnel or decantation can be used to separate the immiscible liquids by pouring off the top layer (kerosene) from the bottom layer (water).
J) Ammonium chloride in sand: Sublimation can be used to separate ammonium chloride by heating the mixture, causing the ammonium chloride to vaporize and then condense back into solid form in a cooler region, leaving the sand behind.
Know more about Sublimation here:
https://brainly.com/question/16789108
#SPJ8
vbvjkkkp[kpojsdbfoijaefoibhfeboqi
Answer:
sdfhioupsdfiuhikdfjsdfhsdksdflk";d089sdfojskdfk
pls give brainlyest
Explanation:
200 IQ intellectual right here ^^
How do you calculate the number of protons, neutrons, and electrons in an element?
Answer:
The first thing you will need to do is find some information about your element. Go to the Periodic Table of Elements and click on your element. If it makes things easier, you can select your element from an alphabetical listing.
Number of Protons = Atomic Number
Number of Electrons = Number of Protons = Atomic Number
Number of Neutrons = Mass Number - Atomic Number
For krypton:
Number of Protons = Atomic Number = 36
Number of Electrons = Number of Protons = Atomic Number = 36
Number of Neutrons = Mass Number - Atomic Number = 84 - 36 = 48
Explanation:
hope this helps, have a good day :-)
What is the volume of 1g of ice in cm3?
Answer:
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
Explanation:
Electrons further from the nucleus are partially shielded from the pull of the nucleus.
True
False
3. A graph of the cooling curve of a pure substance is plotted. When is the graph level with the time axis?(2)
A. Never
B.At the melting point only
C.At the boiling point only
D.At both the melting point and the boiling point
A substance's cooling curve is a graph representing the change in temperature over time as it is allowed to cool. The gradient of the cooling curve is influenced by the heat capacity, thermal conductivity, and ambient temperature of the material. The correct option is A.
The rate of cooling for a sample with a known composition is measured in order to map the phase boundaries on a phase diagram. As the sample (or some piece of it) starts to go through a phase change, the rate of cooling will alter. When the temperature-time curve changes slope, these "breaks" will be visible.
In the cooling curve, the graph never meet with the time axis.
Thus the correct option is A.
To know more about cooling curve, visit;
https://brainly.com/question/9680530
#SPJ1
What type of mutation occurred?
Original: ATT CAC
Mutated: ATC CAC
substitution (point)
insertion (addition)
deletion
Answer:
Insertions are mutations in which extra base pairs are inserted into a new place in the DNA. Deletions are mutations in which a section of DNA is lost, or deleted..Germline mutations occur in gametes. Somatic mutations occur in other body cells.Chromosomal alterations are mutations that change chromosome structure.Point mutations change a single nucleotide.Frameshift mutations are additions or deletions of nucleotides that cause a shift in the reading frame.Deletion is a type of mutation involving the loss of genetic material. It can be small, involving a single missing DNA base pair, or large, involving a piece of a chromosome.Base substitutions are the simplest type of gene-level mutation, and they involve the swapping of one nucleotide for another during DNA replication. For example, during replication, a thymine nucleotide might be inserted in place of a guanine nucleotide.Silent mutations are base substitutions that result in no change of the amino acid or amino acid functionality when the altered messenger RNA (mRNA) is translated. For example, if the codon AAA is altered to become AAG, the same amino acid – lysine – will be incorporated into the peptide chain..