with 6.0 x 10^13 Watts of power, what is the potential difference across the circuit if the current is 8.0 x 10^6?
Answer:
P = I^2 R = V I
V = P / I = 6.0E13 J/s / 8.0E6 C/s = 7.5E6 J/C = 7.5E6 volts
How does methodology in natural science influence knowledge produced
The cyclist is coasting freely down the hill with a speed of 15 m/s at
m. Determine the resultant normal reaction on the bicycle and the rate of increase in speed at the instant shown. The bicycle and rider have a total mass of 80 kg. Neglect friction, the mass of the wheels, and the size of the bicycle. Y = 0.2e^x, Find N (normal force) and rate of increase in speed
Answer:
785 N
Explanation:
To solve this problem, we can use the principle of conservation of mechanical energy, which states that the total mechanical energy of a system is constant if there are no external forces doing work on the system. In this case, the only force acting on the cyclist is the normal force, which is perpendicular to the surface of the hill and does not do any work. Therefore, the total mechanical energy of the system (cyclist + bicycle) is constant.
The initial total mechanical energy of the system is:
Ei = mgh + (1/2)mv^2
where m is the total mass of the system, g is the acceleration due to gravity, h is the height of the hill, and v is the initial speed of the cyclist.
In this case, the hill has a slope of y = 0.2e^x, so we can use calculus to find the height of the hill:
h = ∫y dx from x = 0 to x = 5
h = ∫(0.2e^x) dx from x = 0 to x = 5
h = 0.2(e^5 - 1)
h ≈ 35.3 m
Substituting the given values, we get:
Ei = (80 kg)(9.81 m/s^2)(35.3 m) + (1/2)(80 kg)(15 m/s)^2
Ei ≈ 30,736 J
The final total mechanical energy of the system is:
Ef = mgh + (1/2)mv^2
where v is the final speed of the cyclist.
Since the cyclist is coasting freely, there is no external force doing work on the system, so the total mechanical energy is conserved:
Ei = Ef
Solving for v, we get:
v = sqrt((2/m)(Ei - mgh))
v = sqrt((2/80 kg)(30,736 J - (80 kg)(9.81 m/s^2)(35.3 m)))
v ≈ 28.5 m/s
The rate of increase in speed is:
v' = (v - 15 m/s)/t
where t is the time interval shown in the problem (not given).
We cannot solve for v' without knowing the value of t.
To find the normal force N, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:
N - mg = 0
where g is the acceleration due to gravity.
Solving for N, we get:
N = mg
N = (80 kg)(9.81 m/s^2)
N ≈ 785 N
Therefore, the resultant normal force on the bicycle is approximately 785 N.
what aspect of the US justice system has its roots in Jewish scripture?
The aspect of the US justice system that has its roots in Jewish scripture is:
the idea that all people are subject to the same rules and laws.
It is the doctrine of "equality before the law." Equality before the law means that every individual is equal in the eyes of the law, whether the individual is a lawmaker, a judge, a law enforcement officer, etc. Equality before the law is also known as equality under the law, equality in the eyes of the law, legal equality, or legal egalitarianism. It is a legal principle that treats each independent being equally and subjects each to the same laws of justice and due process.
Answer:
answer is C
the idea that all people are subject to the same rules and laws
Explanation:
hope this helps!
Intense physical activity that requires little oxygen but uses short bursts of energy is called Anaerobic exercise? True or false 
what do electrons and holes make when they are moving
Answer:
Holes are formed when electrons in atoms move out of the valence band (the outermost shell of the atom that is completely filled with electrons) into the conduction band. (the area in an atom where electrons can escape easily) which happens everywhere in a semiconductor. When an electron and a hole interact and recombine the energy is not transferred into heat energy or thermal vibrations. instead the energy is transferred into an electron within the conduction band which is then promoted to an energy higher in condition band.
Explanation:
So considering that information, electrons and holes make a semiconductor when moving.
If 03.4 kg of water at 69°C is changed into steam at 100°C, how will the energy be used? specific heat capacity of water is 4200J/kg C and latent heat is 2,260 000J/Kg.
A. 7864513 J
B. 8126680 J
C. 329758 J
D. 742976 J
With explanation please
Answer:
The answer is B.
Explanation:
مافيني اشرح
formula for inertia speed
Answer:
The equation of momentum for a linear system is simply P = mv where P = momentum (kg·m/sec or lb·ft/sec); m = mass (kg or lb); and v = velocity (m/s or ft/sec). ... By reducing her inertia (I = mr2 where r has been decreased) her angular velocity, ω, must increase in order for the angular momentum to remain constant.
https://www.gstatic.com/education/formulas2/355397047/en/moment_of_inertia.svg
hope this helps?
Explanation:
The air flowing over the top of the wing travels
in the same amount of time than the air
flowing beneath the wing.
Answer: Short Answer: NO ( In Most Cases)
Explanation:
If that were true then planes couldn't get off the ground to fly. The front of the wing is cutting/pushing the air. On the top of the wing the air moves faster and on the bottom it moves slower making a upward draft giving the object the ability to fly or glide.
Hand pushes on a table with a force of 35n forward.reaction force
Answer:
como ías
Explanation:
who won the battle of Buxar
Answer:
British East India Company
The battle was fought at Buxar, a "small fortified town" within the territory of Bihar, located on the banks of the Ganga river about 130 kilometres (81 mi) west of Patna; it was a decisive victory for the British East India Company.
The once-popular LP (long-play) records were 12 in. in diameter and turned at a constant 33 1/3 rpm.
The angular speed of the long-play (LP) in rad/s is 3.49rads/s and its period in seconds is 1.80 seconds.
How is angular speed and period calculated?To convert the angular speed from revolution per minutes (rpm) to seconds the following formula is used:
ω = (k revolution/60 seconds) x (2π/1 revolution)
ω = 2πk/60seconds (k x 2π/T in seconds)
where, k = constant in rpm, 33 1/3rpm = 33.3333rpm
ω = 2π33.3333/60 = 209.4374/60
ω = 3.49rad/s
For period in seconds, ω = 2π/T
where, T = period and ω = angular speed, 3.49rad/s
To find T, T = 2π/ω
T = 2π/3.49rad/s
T = 1.80s
Using the formula, ω = 2πk/60seconds, the angular speed in rad/s of the LP is 3.49rad/s and the time period for the records using T = 2π/ω is 1.80s.
The full question is:
The once-popular LP (long-play) records were 12 inches in diameter and turned at a constant 33(1/3) rpm. Find the angular speed of the LP in rad/s and its period in seconds.
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Dory has a mass of 0.5 kg and she is has a net force of 1 N on her as she starts to swim
forward.
Her acceleration is
m/s2
Answer:
a = 2 m/s²
Explanation:
A 75-W light source consumes 75 W of electrical power. Assume all this energy goes into emitted light of wavelength 600 nm. (a) Calculate the frequency of the emitted light. (b) How many photons per second does the source emit? (c) Are the answers to parts (a) and (b) the same? Is the frequency of the light the same thing as the number of photons emitted per second? Explain.
If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be Decreased and the resonant frequency would be unchanged.
What is frequency?Frequency is the rate at which something occurs over a particular period of time or in a given sample.
Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.
It is defined as-
XL= 2πfL
Xc= 1/2πfC
So when reactances are equal we have-
XL=Xc
2πfL= 1/2πfC
f^2=1/4π^2LC
f=1/2π√LC
The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.
The impedance of a parallel LC circuit is:
Z(w)= jL w^2-w^2•/w
In a series LC circuit, when w
, the impedance becomes equal to 0.
Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.
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Bridget is riding her bicycle up a hill. Which statements are correct? Select five options.
Bridget is transferring energy to the bicycle.
The bicycle is using energy to do work.
Bridget has kinetic energy.
The bicycle has potential energy.
Bridget has nuclear energy.
The bicycle has mechanical energy.
Answer:
A,B,C,D, and F are correct
Explanation:
Answer:
Explanation:
A,B,C,D, and F
What happens to the gravitational force between two objects if the distance between them triples?
A. The force increases by a factor of 9
B. The force decreases by a factor of 9
C. The force decreases by a factor of 3
D. The force increases by a factor of 3
When doing a chin-up, a student lifts her body with a force of 400N and a distance of 0.25 meters in 2 seconds. What is the power delivered by the students biceps?
Given:
The student lifts her body with a force F = 400 N
The distance is d = 0.25 N
The time is t = 2 s
To find: The power delivered by student's biceps.
Explanation:
The formula to calculate power is
\(P=\frac{F\times d}{t}\)Substituting the values, the power will be
\(\begin{gathered} P=\frac{400\times0.25}{2} \\ =\text{ 50 W} \end{gathered}\)Final Answer: The power delivered by student's biceps is 50 W.
If an ocean wave takes 2 minutes to generate one full cycle, from crest to crest, then we will call this the frequency of the wave. What would its period be
Answer:
Explanation:
The period of the wave will be 2 minutes
frequency = 1 / period
= 1 / 2
= .5 per minute
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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A 45-mH inductor is connected to an ac source of emf with a frequency of 250 Hz and a maximum emf of 20 V. If the voltage across the inductor is +20 V at time t = 0, what is the voltage at time t = 2.0 ms? Assume the phase constant is zero.
Answer:
-20v
Explanation:
Data provided in the question as per the given situation
L = 45 mH
f = 250 Hz
V_o = 20V
Based on the above information, let us assume voltage across inductor be V at t
So,
\(V = 20 sin (2 \pi \times 250\times t + \frac{\pi}{2})\)
t = 2 ms
Now
The voltage at time t = 2.0 ms is
\(V_1 = 20 sin (500\times 2\times 10^{-1} \times \pi + \frac{\pi}{2})\)
\(= 20 sin(\pi + \frac{\pi}{2} )\)
= -20 volt
= -20v
We simply solved the above equation so that the correct voltage could come
The the voltage at time (t) = 2.0 ms is equal to -20 Volts.
Given the following data:
Inductance = 45-mH to H = 0.045 HenryFrequency = 250 HzMax. emf = 20 VTime = 2.0 ms to s = 0.2 secondsTo determine the the voltage at time (t) = 2.0 ms:
In an AC source, the voltage across the inductor is given by the formula:
\(V = Esin(2\pi ft + \frac{\pi}{2} )\)
When time (t) = 2.0 ms:
\(V = 20sin(2\pi \times 250 \times 0.002+ \frac{\pi}{2} )\\\\V = 20sin(\pi + \frac{\pi}{2} )\\\\V = 20sin(270)\\\\V=20 \times -1\)
Voltage = -20 Volts.
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An ideal gas held at constant pressure has its temperature changed by a factor of 2.53x. By what factor does its volume increase or decrease?
In order to calculate the change in volume, we can use the relation below:
\(\frac{P_iV_i}{T_i}=\frac{P_fV_f}{T_f}\)If the pressure remains the same and the temperature increases by 2.53x, we have:
\(\begin{gathered} \frac{P\cdot V_i}{T}=\frac{P\cdot V_f}{2.53T}\\ \\ V_i=\frac{V_f}{2.53}\\ \\ V_f=2.53V_i \end{gathered}\)Therefore the volume also changes by a factor of 2.53.
Identify two factors that determine the state of matter
the kinetic energies of the particles (atoms,molecule,or ions)that make up up a substance. kinetic energy tends to keep the particles moving apart.
the attractive inter molecular forces between particles that tends to draw the particles together.
An air puck of mass 0.030 kg is tied to a string
and allowed to revolve in a circle of radius 1.2
m on a frictionless horizontal surface. The
other end of the string passes through a hole
in the center of the surface, and a mass of
2.7 kg is tied to it, as shown. The suspended
mass remains in equilibrium while the puck
revolves on the surface. What is the magnitude of the force that
maintains circular motion acting on the puck?
The acceleration due to gravity is 9.81 m/s^2 answer in Newtons.
Part 2: What is the linear speed of the puck?
Answer in units of m/s.
9.8 N is the magnitude of the force that maintains circular motion acting on the puck.
32.53 m/sec is the linear speed of the puck.
What is force?The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. An item does not have a force inside of it or within it. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
As we know, from free body diagram, when the system is in equillibrium, the force acting on the puck on the table is as follows:
When the air puck of mass is revolving round the circle, then the tension (T) in the top string and the bottom of the string is same.
F = T
F = 9.8 N
Now, calculate the velocity of the puck:
From the given data, the air puck moves in a circular path. Hence, the tension in the top string is equal to the centripetal force acting on the puck.
Thus, the expression for the tension in the top string is as follows:
T = mv² / R
The velocity of the puck is as follows:
Mg = mv² / R
v² = MgR / m
v² = (2.7 × 9.8 × 1.2 ) / 0.030
v² = 1058.4
v = \(\sqrt{1058.4}\)
v = 32.53 m/sec
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A disk is rotating with an angular velocity function given by ω=Kt+L. What is the angular acceleration of the disk at t=T ?
Answer:
Angular acceleration of the disk ∝ = K
Explanation:
Given that;
Angular velocity function given by ω = Kt + L
Angular acceleration of the disk at t=T is = ?
Now,
Angular velocity;
ω = Kt + L
Angular acceleration is;
∝ = dω / dt
= \(\frac{d}{dt}\) ( Kt + L )
At t = T
∝ = K
Because ∝ is not dependent on t
Therefore
Angular acceleration of the disk ∝ = K
What new question occurred to scientists after they discovered that the
ocean floor was not flat?
O A. Are there bathtubs that have shapes similar to that of the Mid-
Atlantic Ridge?
OB. Why is the ocean floor not flat and smooth like the bottom of a
bathtub?
C. How much cable will it take to go from North America to England?
OD. How deep is the ocean?
Answer:
b
Explanation:
The answer is B. Why is the ocean floor not flat and smooth like the bottom of a bathtub?
Scientists were surprised to find that the ocean floor was not a flat and featureless plain, but rather had mountains, valleys, and other geological features. This discovery raised questions about how these features formed and what processes were involved. Scientists began to investigate the causes of these features, such as plate tectonics and volcanic activity, and how they might have shaped the ocean floor over millions of years. Understanding the complex and dynamic nature of the ocean floor has since become an important area of study in earth science and oceanography.
7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
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your sister has gained admission into your former school write a letter giving her information about the school and advise her to behave well while in school
Answer:
Find the letter below.
Explanation:
5183 Richmond Avenue,
Houston City,
Texas, U.S.A.
16th November 2020.
Dear Jane,
I received with joy the news of your admission into Texas City High School, my alma mater. This is a big feat and evidence of your hard work and commitment to your academics. To excel in this school, there are certain points which I would like you to note.
First, this is a new phase of your life and it would be important for you to clearly keep your purpose for going to school in mind. Your foremost purpose is to study and gain the needed knowledge that would help you in life.
Secondly, the school is a very sociable environment with lots of interesting activities such as sports, dancing, literary groups, and so many others. Find a group that appeals to you and participate actively in it. Extracurricular activities would help you socialize with your mates and teachers. It would also help you meet interesting people who might later serve some useful purpose in your life after graduation.
The teachers at Texas City High School are very kind and willing to help you excel in your academics and other chosen fields. Be sure to respect them and meet them when you have difficulties in any area of concern. There are also counselors that guide you and help you to remain on the path to excellence.
My dear Jane, life in Texas City High School would not always be rosy as there are bullies in school who would want to intimidate you or get you into fights. Avoid them by all means. Be cordial to all. Report any cases of harassment to the relevant authorities for they are seasoned in handling such matters maturely.
The cafeteria is also an interesting feature of the school. There you can find different kinds of snacks that I know you would love given how much you love snacks. I would only recommend that you make healthier choices so that you do not become overweight or fall ill due to overindulgence in unhealthy meals.
My dear baby girl, be assured of my love and kind wishes as you move on to this next stage of your life. Always know that I am here to give you my advice when you need it. Be a good girl my dear sister. Do have a lovely time at school.
Yours lovingly,
Queen Walters.
Electricity & Magnetism
4
Electricity can be used to produce powerful forces.
What type of energy is electricity converted to in an electromagnet?
A. sound energy
B.
heat energy
C. light energy
D. magnetic energy
I’ve been struggling with this question, help!
The masses of the two objects MA and MB in the binary system are 4 Mo respectively.
How can the masses of the binary systems be calculated?The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.
Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:
MA + MB = 8 Mo
We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:
d(A to B) / d(Binary System) = 1/3
We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:
d(A to B) + d(B to binary system) = d(Binary system)
Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):
d(A to B) + 1/3d = d(Binary system)
3d(A to B) + d = 3d(Binary system)
Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:
3d(A to B) + d = 3(d(A to B) + d(B to binary system))
2d(A to B) = 2d(B to binary system)
d(A to B) / d(B to binary system) = 1
So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:
MA = MB
Substituting this into the first equation, we get:
2MA = 8 Mo
MA = MB = 4 Mo
Therefore, the mass of each object is 4 Mo.
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An optical fibre consists of a fused quartz core surrounded by cladding with a refractive index of 1.35. Considering the fused quartz’s refractive index to be 1.55, calculate the numerical aperture of the fibre.
Since the refractive index of the core is higher than that of the cladding, light in the core striking the cladding boundary at an angle steeper than the critical angle is reflected back into the core by total internal reflection.
What is refractive index?The numerical aperture (n12 - n22 = NA2) can be provided to find the refractive index of the cladding. The formula for determining the number of reflections in an optical fiber is: Number of reflections =lx=l3d= 2203106=57735 57000.Due to the helical nature of the optical path, this type of optical fiber works only if the wavelength is significantly smaller than the core radius. This means that the core of a step-index fiber has a constant refractive index.Since the refractive index of the core is higher than that of the cladding, light in the core striking the cladding boundary at an angle steeper than the critical angle is reflected back into the core by total internal reflection.to learn more about refractive index from the given link:
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