What atom has 35 protons and 47 neutrons ?

Answer:

if you search up the periodic table and go to any website it will let you press on the element and it will say if it is a gas,solid or liquid and it might say if it is man made!

Explanation:

i really hope this helps:)

Answer:

A salt metathesis reaction, sometimes called a double displacement reaction, is a chemical process involving the exchange of bonds between two reacting chemical species which results in the creation of products with similar or identical bonding affiliations.

Explanation:

From: Wikipedia

Answer:

Entropy,mass and volume.... I think

Mass is the extensive property of a sample of aluminum. Therefore, option (A) is correct.

The extensive property can be described as a physical property of matter that changes with a change in the size and shape of the matter. Therefore, the extensive property of any substance varies directly with the mass.

Extensive properties are the value of the property of the system that must be equal to the sum of the values of different parts of the system. These properties depend on the amount of matter contained in the system.

Examples of Extensive properties are temperature, pressure, density, boiling point, etc. The ratio of the two extensive properties is an intensive property such as density.

The mass of a sample of aluminum is an example of extensive property as it depends on the amount of aluminum in the given sample. This property of the sample is proportional to the size of the system.

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Your question is incomplete, most probably the complete question was,

Which of the following is an extensive property of a sample of aluminum?

A) Mass

B) Temperature

C) Pressure

D) Density

Answer:

Cs+ and F-

Explanation:

The compound CsF is made up of two elements; Caesium (Cs) and F (Flourine)

Caesium is a metal and would therefore lose electrons - a cation is formed. When Caesium loses a single electron, the ion symbol is given as; Cs+

Flourine is a non metal and would therefore gain electrons - an anion is formed. When Flourine gains a single electron, the ion symbol is given as; F-

Hence the correct option is;

Cs+ and F-

Answer:

flourine

Explanation:

im not sure the answer

The balanced chemical equation for the combustion of ethane gas and oxygen gas is:

C2H6 + 3.5O2 → 2CO2 + 3H2O

where the coefficients represent the stoichiometric coefficients.

(o) To determine the number of moles of carbon dioxide produced from the combustion of 5.35 moles of ethane gas, we first need to determine the limiting reactant. Since oxygen is present in excess, ethane is the limiting reactant. From the balanced equation, we know that 2 moles of CO2 are produced for every 1 mole of ethane combusted. Therefore, 5.35 moles of ethane will produce:

2 moles CO2/mol ethane × 5.35 mol ethane = 10.7 moles CO2

(p) To determine the number of moles of carbon dioxide produced from the combustion of 4.59 moles of oxygen gas, we need to determine the limiting reactant. Since ethane is present in excess, oxygen is the limiting reactant. From the balanced equation, we know that 2 moles of CO2 are produced for every 3.5 moles of oxygen combusted. Therefore, 4.59 moles of oxygen will produce:

2 mol CO2/3.5 mol O2 × 4.59 mol O2 = 2.62 moles CO2

(q) To determine the number of moles of carbon dioxide produced from the combustion of 5.35 moles of ethane gas with 4.59 moles of oxygen gas, we need to determine the limiting reactant. From the balanced equation, we can see that 3.5 moles of oxygen are required to completely combust 1 mole of ethane. Therefore, 5.35 moles of ethane require:

3.5 mol O2/mol ethane × 5.35 mol ethane = 18.725 mol O2

Since we only have 4.59 moles of oxygen, it is the limiting reactant. From the balanced equation, we know that 2 moles of CO2 are produced for every 3.5 moles of oxygen combusted. Therefore, 4.59 moles of oxygen will produce:

2 mol CO2/3.5 mol O2 × 4.59 mol O2 = 2.62 moles CO2

(r) To determine the amount of excess reactant remaining after the reaction described in (q), we need to compare the moles of oxygen required for complete combustion of ethane with the moles of oxygen present. From (q), we know that 5.35 moles of ethane require 18.725 moles of oxygen. Since we only have 4.59 moles of oxygen, we can calculate the amount of excess ethane as follows:

18.725 mol O2 required − 4.59 mol O2 present = 14.135 mol O2 excess

Since ethane and oxygen react in a 2:3.5 ratio, the excess ethane can be calculated as:

2 mol ethane/3.5 mol O2 × 14.135 mol O2 = 8.09 mol ethane excess.

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Answer:

1 mol Be

Explanation:

First look at periodic table. Be (Beryllium) has an atomic mass of 9.012

1 mole of Be atoms = 9.012 g Be (this is your conversion factor)

Start with what you are given: 9.01 b Be. Then look at the periodic table. Be has an atomic weight of 9.012g. In order to cancel out the g place how you see here, cross out the g and your are left with mole Be on top. divide 9.01 by 9.012 to get .99977807. round that to 1 mol Be

\((\frac{9.01 g Be}{1} )(\frac{1moleBe}{9.012 gBe} )=.99977807 moleBe\)

Answer:

CATION

Explanation:

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion. If it loses an electron, it becomes positively charged and is known as a cation.

In some plants such as Cactuses, the stem is flattened and green and carries out the function of the leaf. Such a stem, adapted for the manufacture of food is called phylloclade. The leaves here are reduced or modified into spines to lessen the transpiring surface.

At equilibrium, the concentrations of the reactants and products remain constant over time, although the individual molecules are continuously interconverting. The concentration of water must be 0.227 M for the mixture to be at equilibrium.

To determine whether the concentration of water (H₂O) will increase, decrease, or remain the same as equilibrium is established, we need to compare the given concentrations of reactants and products with their stoichiometric coefficients in the balanced equation.

The balanced equation for the reaction is:

CH₃CO₂H + C₂H₅OH -> CH₃CO₂C₂H₅ + H₂O

Let's analyze each mixture (a-d) and determine the change in the concentration of water:

(a) [CH₃CO₂C₂H₅] = 0.22 M, [H₂O] = 0.10 M, [CH₃CO₂H] = 0.010 M, [C₂H₅OH] = 0.010 M

In this mixture, the concentration of water remains the same because the given concentrations are in equilibrium.

(b) [CH₃CO₂C₂H₅] = 0.22 M, [H₂O] = 0.0020 M, [CH₃CO₂H] = 0.0020 M, [C₂H₅OH] = 0.10 M

The concentration of water decreases because its initial concentration is higher than the equilibrium concentration.

(c) [CH₃CO₂C₂H₅] = 0.88 M, [H₂O] = 0.12 M, [CH₃CO₂H] = 0.044 M, [C₂H₅OH] = 6.0 M

The concentration of water increases because its initial concentration is lower than the equilibrium concentration.

(d) [CH₃CO₂C₂H₅] = 4.4 M, [H₂O] = 4.4 M, [CH₃CO₂H] = 0.88 M, [C₂H₅OH] = 10.0 M

The concentration of water remains the same because the given concentrations are in equilibrium.

To determine the concentration of water for a mixture to be at equilibrium with [CH₃CO₂C₂H₅] = 3.0 M, [CH₃CO₂H] = 0.10 M, and [C₂H₅OH] = 6.0 M, we need to set up an expression using the equilibrium constant (K) and the concentrations of the other species:

K = [CH₃CO₂C₂H₅] / ([CH₃CO₂H] * [C₂H₅OH] * [H₂O])

We can rearrange the equation to solve for [H₂O]:

[H₂O] = [CH₃CO₂C₂H₅] / (K * [CH₃CO₂H] * [C₂H₅OH])

Substituting the given concentrations:

[H₂O] = 3.0 M / (2.2 * 0.10 M * 6.0 M)

Simplifying the expression:

[H₂O] = 0.227 M

Therefore, the concentration of water must be 0.227 M for the mixture to be at equilibrium.

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Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

Answer: D?  

Explanation: The mitochondrion (plural mitochondria) is a membrane-bound organelle found in the cytoplasm of eukaryotic cells. It is the power house of the cell; it is responsible for cellular respiration and production of (most) ATP in the cell.

The freezing point of the solution made by dissolving 1.63 g of urea in 40.8 g of water is -0.15124°C.

The freezing point of a solution is a measure of the amount of a solute that has been dissolved in a solvent. The freezing point depression of a solution is the difference between the freezing point of the pure solvent and the freezing point of the solution.

Calculating freezing point depression.

ΔTf = Kf * molality

Where:

ΔTf is the change in freezing point (in K)

Kf is the freezing point depression constant (in K/m)

Molality is the ratio of moles of solute to kilograms of solvent (m)

We must first determine the solution's molality:

1.63 g of urea (molecular weight = 60.06 g/mol) is equivalent to 0.0271 moles of urea:

0.0271 moles / 40.8 g of water = 0.000661 moles/g

Next, we can calculate the change in freezing point:

ΔTf = Kf * molality

ΔTf = 1.86 K/m * 0.000661 moles/g

ΔTf = 0.00124 K

Finally, we can calculate the new freezing point of the solution:

273.15 K - 0.00124 K = 272.99876 K

Converting from Kelvin to Celsius:

272.99876 K - 273.15 = -0.15124°C

Therefore, the freezing point of the solution made by dissolving 1.63 g of urea in 40.8 g of water is -0.15124°C.

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The speed of the particles rises with the temperature of the solid, liquid, or gas. The particles slow down with decreasing temperature.

A liquid can turn into a solid if it is cooled down far enough.

The average kinetic energy of the molecules falls as a liquid cools.

The liquid eventually turns into a solid when the quantity of heat removed is sufficient to cause the molecules to be attracted to one another.

Freezing is the process of transitioning from a liquid to a solid.

It loses thermal energy when the liquid cools. Its constituent particles therefore decelerate down and converge.

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Answer:

No, not all are harmful.

Explanation:

There are bacterias that are harmful, yes, but millions, maybe even billions are helpful. Probiotics, healthy bacteria, as some like Lactobacilli and Bifidobacterium. There are a lot more, but just these two examples are helpful. Lactobacili is helpful with your digestive system. Bifidobacterium is geared towards your mouth and the vaginal area of women in mammals, like humans.

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I hope this helps!

-No one

7.98 grams of \($\mathrm{Fe}_2 \mathrm{O}_3$\) are produced if 10.7 grams of\($\mathrm{Fe}(\mathrm{OH})_3$\) are reacted.

To calculate the number of moles, we use the equation:

Number of moles \($=\frac{\text { Given mass }}{\text { Molar mass }}$\)

Putting values in equation 1 , we get:

Moles of\($\mathrm{Fe}(\mathrm{OH})_3=\frac{10.7 \mathrm{~g}}{106.87 \mathrm{~g} / \mathrm{mol}}=0.100 \mathrm{~mol}$\)

The chemical equation for the reaction is

\($2 \mathrm{Fe}(\mathrm{OH})_3 \rightarrow \mathrm{Fe}_2 \mathrm{O}_3+3 \mathrm{H}_2 \mathrm{O}$\)

By Stoichiometry of the reaction:

2 moles of \(\mathrm{Fe}(\mathrm{OH})_3$ produce $=1$\)mole of\($\mathrm{Fe}_2 \mathrm{O}_3$\)

So, 0.100 moles of \(\mathrm{Fe}(\mathrm{OH})_3$ produce $=\frac{1}{2} \times\) 0.100=0.05 \(\mathrm{~mol}$\) of \($\mathrm{Fe}_2 \mathrm{O}_3$\)

Mass of \(\mathrm{Fe}_2 \mathrm{O}_3=$ moles $\times$\) Molar Mass $=0.05\(\mathrm{~mol} \times 159.69\) \(\mathrm{~g} / \mathrm{mol}=7.98 \mathrm{~g}$\)

Hence 7.98 grams of \($\mathrm{Fe}_2 \mathrm{O}_3$\) are produced if 10.7 grams of\($\mathrm{Fe}(\mathrm{OH})_3$\) are reacted.

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Answer:

If you can identify the species that was being oxidized, its species that contains the element on the other side is the reducing agent.

For example, in the equation Zn + Cu2+ --> Zn2+ + Cu, the zinc was oxidized, making Zn the reducing agent.

The low concentration of phosphates in soil solution can be attributed to factors such as adsorption, precipitation, and immobilization.

Phosphates (PO₄³⁻) are an essential nutrient for plant growth, and their availability in soil solution is crucial for plant uptake. However, several factors contribute to the low concentration of phosphates in the soil solution:

1. Adsorption: Phosphates have a strong affinity for soil particles, particularly clay and organic matter. They can readily adsorb onto the surfaces of these particles, reducing their concentration in the soil solution and making them less accessible to plants.

2. Precipitation: Phosphates can react with cations, such as calcium (Ca²⁺) and iron (Fe³⁺), to form insoluble compounds like calcium phosphate or iron phosphate. These precipitates further decrease the concentration of phosphates in the soil solution.

3. Immobilization: Soil microorganisms and organic matter can immobilize phosphates by incorporating them into their biomass. This immobilization process temporarily removes phosphates from the soil solution, limiting their availability to plants.

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Answer:

Empirical formula = K₂SO₄

The name of the compound is Potassium tetraoxosulfate (vi)

Explanation:

Percentage composition of the elements:

Potassium = 44.82%

Sulfur = 18.39%

Oxygen = 36.79%

Mole ratio of the elements:

Potassium = 44.82/39 =1.15

Sulfur = 18.39/32 = 0.57

Oxygen = 36.79/16 = 2.29

Dividing by the smallest ratio in order to obtain the simplest ratio

Potassium = 1.15/0.57 =2

Sulfur = 0.57/0.57 = 1

Oxygen = 2.29/0.57 = 4

Therefore, the mole ratio of Potassium : Sulfur : Oxygen = 2:1:4

Empirical formula = K₂SO₄

The name of the compound is Potassium tetraoxosulfate (vi)

The empirical formula for the given compound has been \(\rm \bold{K_2SO_4}\).

The empirical formula has been the simplest whole-number ratio of the atoms of each element present in the compound.

The atoms of K can be given by:

Atoms = \(\rm \dfrac{Percentage}{Molecular\;mass}\)

The atoms of K = 1.15

The atoms of S = 0.57

The atoms of O = 2.29

To obtain the whole number ratio, the atoms have been divided by the smallest atom number i.e. 0.57.

The atoms of K = 2

The atoms of S = 1

The atoms of O = 4

Thus, the empirical formula for the given compound has been \(\rm \bold{K_2SO_4}\).

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a. CaO (calcium oxide) will form a basic solution when dissolved in water.

b. SO₂ (sulfur dioxide) will form an acidic solution when dissolved in water.

c. Cl₂O (dichlorine monoxide) will form an acidic solution when dissolved in water.

a. CaO (calcium oxide) is a metal oxide. When it reacts with water, it undergoes hydrolysis to form calcium hydroxide (Ca(OH)₂), which is a strong base. The reaction can be written as:

CaO + H₂O → Ca(OH)₂

b. SO₂ (sulfur dioxide) is a non-metal oxide. When it dissolves in water, it forms sulfurous acid (H₂SO₃) through a series of reactions with water molecules. Sulfurous acid is a weak acid, resulting in an acidic solution. The reaction can be represented as:

SO₂ + H₂O → H₂SO₃

c. Cl₂O (dichlorine monoxide) is also a non-metal oxide. It reacts with water to produce hypochlorous acid (HClO), which is a weak acid. This leads to the formation of an acidic solution. The reaction can be written as:

Cl₂O + H₂O → 2HClO

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Three body systems that are reacting in this scenario are the immune system, nervous system, and integumentary system. When Angela is stung by a bee, her immune system recognizes the bee venom as a foreign substance and triggers an immune response.

The immune system releases antibodies and immune cells to neutralize the venom and prevent further harm. The swelling and pain in her arm are manifestations of the immune system's response to the bee sting.

Nervous System: The nervous system is responsible for transmitting signals and coordinating responses in the body. In this case, when Angela is stung, sensory receptors in her skin detect the pain and send signals to her brain through the peripheral nervous system. The brain then interprets the signals and generates a pain sensation, allowing Angela to become aware of the sting.

Integumentary System: The integumentary system includes the skin, which acts as a barrier between the body and the external environment. When Angela is stung, the bee's stinger pierces her skin, causing a localized injury. The swelling in her arm is a result of increased blood flow and inflammation as the body's response to the injury.

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To use the titration curve for a weak acid to calculate the pH of a 0.150 M solution of that acid, you would need to know the pKa value of the acid and the volume of the titrant added during the titration.

To calculate the pH of a 0.150 M solution of a weak acid using the titration curve, follow these steps:

1. Identify the weak acid and its corresponding Ka value (acid dissociation constant). The titration curve should provide this information or you can find it in a reference table.

2. Write the chemical equation for the dissociation of the weak acid (HA) in water:
HA + H₂O ⇌ H₃O⁺ + A⁻

3. Set up an equilibrium table (ICE table) to represent the initial concentrations, the change in concentrations, and the equilibrium concentrations of the species involved:
   [HA] [H₃O⁺] [A⁻]
I: 0.150    0       0
C: -x        x       x
E: 0.150-x   x       x

4. Write the expression for the Ka using the equilibrium concentrations:
Ka = ([H₃O⁺][A⁻])/([HA])

5. Substitute the expressions from the equilibrium table into the Ka expression:
Ka = (x^2)/ (0.150-x)

6. Solve for x, which represents the [H₃O⁺] concentration at equilibrium. Since the weak acid is only slightly dissociated, you can assume that x is much smaller than 0.150, and the equation simplifies to:
Ka = (x^2)/0.150

7. Calculate the pH of the solution using the equilibrium [H₃O⁺] concentration:
pH = -log₁₀([H₃O⁺])

Following these steps will help you calculate the pH of a 0.150 M solution of a weak acid using the titration curve.

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for the duration of reconstruction of the Statue of Liberty, Teflon spacers were positioned between the iron skeleton and the copper plates that cover the statue because if you want to shield the iron metal from being oxidised by way of the copper metal on coming in touch with environment, teflon spacers is placed between the iron skeleton and the copper metallic.

These spacers separate the copper and iron metals. Prevention of touch stops the electrons from transferring from one steel to any other, it prevents reduction and oxidation to occur. This save you corrosion of the iron steel.

Teflon or PTFE spacers are frequently used to acquire specific spacing among additives and/or substances. To obtain a quote for ptfe spacers fill out Boker's rapid quote form and publish applicable manufacturing prints.

PTFE spacers are often used to gain specific spacing among additives and/or substances.

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Answer:

15.0°C

Explanation:

hope it helps

Heat Capacity

The heat capacity of a substance can be defined as the amount of heat required to change the temperature by a given amount the SI unit is joules per kelvin

The energy absorbed by the water is 105 joules

Given data:

mass of water = 5 grams

Change in temperature = 10 degrees from 15 degrees

The expression for the Quantity of heat is given by

Q = m x c x Δθ

Where m =mass

c = specific heat capacity and

Δθ = change in temperature

c = 4.2J/g/degrees

Q = 5 x 4.2 x (15 - 10)

Q = 5 x 4.2 x 5

Q = 105Joules

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Answer:

1

Explanation:

Hydrogen bonding causes a high surface tension

Hydrogen bonds existing only in the solid state refers to the false statement about water.

This is a compound which consists of hydrogen and oxygen and is  referred to as a universal solvent.

Its solid state is less dense than its liquid state  and the hydrogen bonds exists in various states of matter thereby making option 2 the most appropriate choice.

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Answer:

n = 2

l = 1

m = 1

s = +1/2

Explanation:

₇N tiene la configuración electrónica;

1s2 2s2 2p3

Esto implica que este último electrón tiene los siguientes números cuánticos;

n = 2

l = 1

m = 1

s = +1/2

Este último electrón estará en un orbital de 2pz como lo muestran los números cuánticos enumerados anteriormente.

Answer: 1024 sodium ions

Explanation: The mathematical equation, N = n × NA, can be used to find the number of atoms, ions or molecules in any amount (in moles) of atoms, ions or molecules: 10 moles of helium atoms = 10 × (6.022 × 1023) = 6.022 × 1024 helium atoms. 10 moles of sodium ions = 10 × (6.022 × 1023) = 6.022 × 1024 sodium ions. (that took long)

The empirical formula represents the simplest whole number ratio of atoms in a compound. To identify the empirical formula, we need information about the composition of the compound in terms of the elements present. Among the given answer choices, the correct empirical formula is B. b4h10, representing the compound boron tetraboride.

To determine the empirical formula, we consider the ratios of the different elements present in the compound. Let's evaluate the answer choices:

A. b2cl2: This represents a compound with boron (B) and chlorine (Cl). The ratio of boron to chlorine is 2:2, simplifying to 1:1. The empirical formula for this compound would be BCl.

B. b4h10: This compound consists of boron (B) and hydrogen (H). The ratio of boron to hydrogen is 4:10, which simplifies to 2:5. Thus, the empirical formula for this compound is B2H5.

C. na2po4: This compound includes sodium (Na), phosphorus (P), and oxygen (O). The ratio of sodium to phosphorus to oxygen is 2:1:4, which is already in its simplest form. Therefore, the empirical formula for this compound is Na2PO4.

D. al2cl6: This compound contains aluminum (Al) and chlorine (Cl). The ratio of aluminum to chlorine is 2:6, which simplifies to 1:3. Hence, the empirical formula for this compound is AlCl3.

Among the given answer choices, the compound with the empirical formula B2H5 is the correct option.

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