What are the zeros of the function g(x) = (x – 3) (x + 2) (x – 4)?

Answer:

D.6x-3

Step-by-step explanation:

we have , (5+4x)+(2x-8)

              =5+4x+2x-8

              =(4x+2x)+(5-8)

              =6x-3

Answer:

no solutions

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

equation of blue line is y = x + 2 , in slope- intercept form

with slope m = 1

equation of red line is y = x - 3 , in slope- intercept form

with slope m = 1

• Parallel lines have equal slopes

then the blue and red lines are parallel.

the solution to the system is at the point of intersection of the 2 lines

since the lines are parallel then they do not intersect each other.

thus the system shown has no solution.

The total number of rabbits bought by Doña Rose for your farm is 4 times the Number of given rabbits.

The number of rabbits bought by Doña Rose for your farm, we need to consider that the given rabbits represent only a quarter of the total number.

the total number of rabbits as 'x'. According to the information, the given rabbits represent a quarter of 'x', which can be expressed as:

Given rabbits = (1/4) * x

To find the value of 'x', we can multiply both sides of the equation by 4

4 * Given rabbits = x

Therefore, the total number of rabbits bought by Doña Rose for your farm is 4 times the number of given rabbits.

the exact value of 'x'. However, we can state that the total number of rabbits bought is four times the number of the given rabbits.

So, if the given rabbits represent 'n' in quantity, the total number of rabbits bought would be 4n.

For more questions on Number .

https://brainly.com/question/26460978

#SPJ8

Answer:

5

Step-by-step explanation:

Answer: C

Step-by-step explanation:

Point D is at -14 on the number line.

In Mathematics, the midpoint of a line segment with two end points can be calculated by adding each end point on a line segment together and then divide by two (2).

Since E is the midpoint of line segment CD, we can logically deduce the following relationship:

Line segment CD = Line segment C + Line segment D

Midpoint E = (point C + point D)/2

By substituting the given points into the equation above, we have the following:

-3 = (8 + D)/2

-6 = 8 + D

D = -6 - 8

D = -14

Read more on midpoint here: brainly.com/question/17918978

#SPJ2

Answer:

8. 10

9. 33

10. which number is greatest? 35

11. which number is least? 9

12. 35, 21, 16, 9

13. 17, 20, 23, 26, 29, 32

14. 2 less than 25 is 23

15. 21 is 3 more than 18

16. 24 = 2 tens and 4 ones

17. 18 = 1 ten and 8 ones

Step-by-step explanation:

The value of x in the proportion is x = 39/8

The proportion is given as:

3/8 =x/13

Cross multiply

8 * x = 3 * 13

Evaluate

8x = 39

Divide by 8

x = 39/8

Hence, the value of x in the proportion is x = 39/8

Read more about proportions at:https://brainly.com/question/1781657

#SPJ1

Answer: 85.7

Step-by-step explanation:

Answer:

Step-by-step explanation:

cos A = \(\frac{\sqrt{8} }{3}\)

Answer:

none of them

Step-by-step explanation:

Answer:

Step-by-step explanation:

                                                   error

Answer:

x ≈ 75.2

Step-by-step explanation:

using the tangent ratio in the right triangle

tan62° = \(\frac{opposite}{adjacent}\) = \(\frac{x}{40}\) ( multiply both sides by 40 )

40 × tan62° = x , then

x ≈ 75.2 ( to the nearest tenth )

Answer:

the slope intercept form is   y = (1/2)x - 1

Step-by-step explanation:

The slope-intercept form is, y = mx + b

We see from looking at the graph that,

at x = 0, y = -1

So, from this we find that b = -1

at x = 2, y = 0,

now, we find the slope m,

using,

\(m = \frac{y_{2} -y_1}{x_2-x_1}\)

Using x_2 = 2, y_2 = 0,

x_1 = 0, y_1 = -1, we get,

m = (0-(-1))/(2-0)

m = 1/2

So, the slope intercept form is,

y = (1/2)x - 1

Using the Allowance Method, the relevant transactions can be completed in the books of Wild Trout Gallery as follows:

1. Allowance for Doubtful Accounts

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance          $56,500

Dec. 31 Bad Debts Expenses                   $55,470

Totals                                        $116,005  $116,005

Accounts Receivable

Accounts                                          Debit               Credit

Jan. 1 Beginning balance           $2,290,000

Jan. 19 Allowance for Doubtful           2,560

Jan. 19 Cash                                                            $2,560

Apr. 3  Allowance for Doubtful                                14,670

July 16  Allowance for Doubtful                              19,725

July 16  Cash                                                             6,575

Nov. 23  Allowance for Doubtful         4,175

Nov. 23 Cash                                                             4,175

Dec. 31  Allowance for Doubtful                             25,110

Dec. 31   Sales Revenue            8,020,000

Dec. 31   Cash                                               $8,944,420

Dec. 31 Ending balance                                 $1,299,500

Totals                                        $10,316,735 $10,316,735

3. Expected net realizable value of the accounts receivable as of December 31 = $1,243,000 ($1,299,500 - $56,500)

Allowance for Doubtful Accounts ending balance = $40,100 ($8,020,000 x 0.5%)

Allowance for Doubtful Accounts

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance           $40,100

Dec. 31 Bad Debts Expenses                  $39,070

Totals                                        $99,605   $99,605

4. a. Bad Debt Expense for the year = $39,070

4.b. Balance for Allowance Accounts = $40,100

4.c. Expected net realizable value of the accounts receivable = $1,259,400 ($1,299,500 - $40,100)

Data Analysis:

Jan. 19 Accounts Receivable $2,560 Allowance for Uncollectible Accounts $2,560

Jan. 19 Cash $2,560 Accounts Receivable $2,560

Apr. 3 Allowance for Uncollectible Accounts $14,670 Accounts Receivable $14,670

July 16 Cash $6,575 Allowance for Uncollectible Accounts $19,725 Accounts Receivable $26,300

Nov. 23 Accounts Receivable $4,175 Allowance for Uncollectible Accounts $4,175

Nov. 23 Cash $4,175 Accounts Receivable $4,175

Dec. 31 Allowance for Uncollectible Accounts $25,110 Accounts Receivable $25,110

Accounts Receivable ending balance = $1,299,500

Allowance for Uncollectible Accounts ending balance = $56,500

Learn more: https://brainly.com/question/22984282

Answer:

It would be A hope this helpdd

Step-by-step explanation:

x<2

x={1,0,-1,-2,-3,-4,-5,.......}

Step-by-step explanation:

For Part A:

Refer to the photo for an explanation on how to graph z=x+y+24 and how to set up the first integral. I will not explain how to do the other five but I have placed them beneath....

\(\int\limits^{24}_0 {} \,\int\limits^{z-24}_0 {} \,\int\limits^{z-y-24}_0 {} \, 1dxdydz \\\\\)

Where limits are, \(0\leq x\leq z-y-24\\0\leq y\leq z-24\\0\leq z\leq 24\)

\(\int\limits^{-24}_0 {} \,\int\limits^{y+24}_0 {} \,\int\limits^{z-y-24}_0 {} \, 1dxdzdy\\\\\)

Where limits are, \(0\leq x\leq z-y-24\\0\leq z\leq y+24\\0\leq y\leq -24\)

\(\int\limits^{24}_0 {} \,\int\limits^{z-24}_0 {} \,\int\limits^{z-x-24}_0 {} \, 1dydxdz\\\\\)

Where limits are,\(0\leq y\leq z-x-24\\0\leq x\leq z-24\\0\leq z\leq 24\)

\(\int\limits^{-24}_0 {} \,\int\limits^{x+24}_0 {} \,\int\limits^{z-x-24}_0 {} \, 1dydzdx\\\\\)

Where limits are, \(0\leq y\leq z-x-24\\0\leq z\leq x+24\\0\leq x\leq -24\)

\(\int\limits^{-24}_0 {} \,\int\limits^{-y-24}_0 {} \,\int\limits^{x+y+24}_0 {} \, 1dzdxdy\\\\\)

Where limits are, \(0\leq z\leq x+y+24\\0\leq x\leq -y-24\\0\leq y\leq -24\)

\(\int\limits^{-24}_0 {} \,\int\limits^{-x-24}_0 {} \,\int\limits^{x+y+24}_0 {} \, 1dzdydx\)

Where Limits are, \(0\leq z\leq x+y+24\\0\leq y\leq -x-24\\0\leq x\leq -24\)

For Part B:

All the above limits equal the same volume. So I will just solve for one of the limits.

Evaluate, \(\int\limits^{24}_0 {} \,\int\limits^{z-24}_0 {} \,\int\limits^{z-y-24}_0 {} \, 1dxdydz \\\\\)

\(\int\limits^{24}_0 {} \,\int\limits^{z-24}_0 {} \, (x]^{z-y-24} _0){} dydz \\\\\)

\(\int\limits^{24}_0 {} \,\int\limits^{z-24}_0 {} \, [(z-y-24)-0]{} dydz \\\\\)

\(\int\limits^{24}_0 {} \,\int\limits^{z-24}_0 {} \,z-y-24{} dydz \\\\\)

\(\int\limits^{24}_0 {} \,[0-\frac{y^{2} }{2} -0]{} dz \\\\\)

\(\int\limits^{24}_0 {} \,\frac{y^{2} }{2} ]^{z-24} _{0} {} dz \\\\\)

\(\int\limits^{24}_0 {} \,[(\frac{(z-24)^{2}}{2})-0] {} dz \\\\\)

\(\int\limits^{24}_0 {} \,[\frac{z^2}{2}-288] {} dz \\\\\)

\([\frac{z^3}{6}-288z]^{24} _{0} {} \\\\\)

\([(\frac{24^3}{6}-288(24))-0] {}\)

\((4608-6912)=-2304\\\)

Answer: -2304

Answer:

24.5

Step-by-step explanation:

All you have to is Multiply 3 1/2 by 7

3 1/2 x 7= 24.5

If a rectangular prism has a length of 2 meters, a width of 4 meters, and a height of 2 meters. The volume of the prism is 16 cubic meters.

The volume of a rectangular prism is given by the formula:

Volume = length x width x height

Substituting the given values, we get:

Volume = 2 meters x 4 meters x 2 meters

Simplifying this expression, we get:

Volume = 16 cubic meters

Therefore, the volume of the prism is 16 cubic meters.

Learn more about volume here:https://brainly.com/question/27710307

#SPJ1

The value of the car after 3 years is $79, 000

To determine the value, we have to use the formula;

Value = Initial value × (1 - Depreciation rate)ⁿ

Substitute the values given, we get;

Remaining value after 3 years = $100,000 × (1 - 0.10)³

Expand the bracket, we get;

Value after 3 years = $100,000 × (0.90)³

Find the cube value and substitute, we have;

Value after 3 years = $100,000 × 0.729

Multiply the values, we have;

Value after 3 years = $72,900

Learn more about depreciation at: https://brainly.com/question/1203926

#SPJ1

The detailed answer of this question is:

P(X > 100 | X > 50)=0.455

Given that X follows an exponential distribution, we know that the probability density function (PDF) of X is given by:

f(x) = λe^(-λx) for x ≥ 0

where λ is the rate parameter of the distribution.

We are given that P(X < 50) = 0.25. Using the cumulative distribution function (CDF) of X, we can write:

P(X < 50) = 1 - e^(-λ*50) = 0.25

Solving this equation for λ, we get:

λ = -ln(0.75)/50 ≈ 0.0278

Now, we are asked to find P(X > 100 | X > 50). Using the definition of conditional probability, we can write:

P(X > 100 | X > 50) = P(X > 100 and X > 50) / P(X > 50)

= P(X > 100) / P(X > 50)

= e^(-λ100) / e^(-λ50)

= e^(-λ*50)

Substituting the value of λ, we get:

P(X > 100 | X > 50) = e^(-0.0278*50) ≈ 0.455

Therefore, the probability that a high-risk driver will have an accident after 100 days given that they have not had an accident for the first 50 days is approximately 0.455.

To know more about Exponential Function visit:

https://brainly.com/question/28596571

#SPJ4

Answer:

A, B, E

Step-by-step explanation:

Notice that A, B, and E all maintain their common ratios, while C and D do not.

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

Know more about the domain here:
https://brainly.com/question/30096754

#SPJ8

Answer:

12.5

10

Step-by-step explanation:

10(1/2+3/4)

5+7.5

12.5

10(1/2)+(8(3/4)-1)

5+(6-1)

5+5

10

Answer: you need to add

Step-by-step explanation: I would ask your teacher to help you understand the lesson.  

Answer:

is 50

Step-by-step explanation:

..

Answer:

50 mgghh*gffh CD d yuh hgcft

The new drug appears to reduce epileptic seizures since the rerandomized mean differences are close to the mean difference found between the two groups studied.

The rerandomized mean differences are:

1.2, 2.4, 1.8, 1.3, 2.1, 0.9, 1.5, 0.7, 2.1, and 2.3.

Several of these values are close to the observed mean difference of 1.8, which suggests that the observed difference could be due to chance alone.

Read more on mean differences here:https://brainly.com/question/30047307

#SPJ1