what are the y-intercept and the slope of the line represented in the graph? (i will give most brainly to whoever answers)

The frequency of scores falling into this interval is 11. Therefore, 11 students scored at least 1,800 but less than 2,000.

A frequency distribution is a way to organize and present data by grouping it into intervals or classes and showing how many observations fall into each interval.

In this case, the data given represents the raw scores of thirty students who took the SAT on the same Saturday.

To create a frequency distribution, we can group the data into classes of 1,400 up to 1,600, 1,600 up to 1,800, 1,800 up to 2,000, and so on.

To create this frequency distribution, we can use the Excel data file provided and create a histogram. The histogram will show the frequency of scores falling into each class or interval.

The interval 1,800 up to 2,000 will contain the scores 1,800, 1,810, 1,820, 1,830, 1,840, 1,870, 1,900, 1,910, 1,950, 1,950, 1,980, and 2,000.

To find how many students scored at least 1,800 but less than 2,000, we need to add up the frequencies in this interval.

In conclusion, creating a frequency distribution helps to organize and summarize data. By grouping the data into intervals or classes, we can better understand the distribution of the data and answer questions related to it.

In this case, we were able to determine how many students scored at least 1,800 but less than 2,000 by using the frequency distribution created.

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The line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1, 1), and the line segment from (1,1) to (0,1) is equal to 2/5.

What is integral?

The value obtained after integrating or adding the terms of a function that is divided into an infinite number of terms is generally referred to as an integral value.

To evaluate the line integral using Green's theorem, we need to find a vector field F = (P, Q) such that ∇ × F = Qₓ - Pᵧ, where Qₓ represents the partial derivative of Q with respect to x, and Pᵧ represents the partial derivative of P with respect to y.

Let's consider F = (P, Q) = (x²y², xy).

Now, let's calculate the partial derivatives:

Qₓ = ∂Q/∂x = ∂(xy)/∂x = y

Pᵧ = ∂P/∂y = ∂(x²y²)/∂y = 2x²y

The curl of F is given by ∇ × F = Qₓ - Pᵧ = y - 2x²y = (1 - 2x²)y.

Now, let's find the line integral using Green's theorem:

∫[C] (Pdx + Qdy) = ∫∫[R] (1 - 2x²)y dA,

where [R] represents the region enclosed by the curve C.

To evaluate the line integral, we need to parameterize the curve C.

The arc of the parabola y = x² from (0, 0) to (1, 1) can be parameterized as r(t) = (t, t²) for t ∈ [0, 1].

The line segment from (1, 1) to (0, 1) can be parameterized as r(t) = (1 - t, 1) for t ∈ [0, 1].

Using these parameterizations, the region R is bounded by the curves r(t) = (t, t²) and r(t) = (1 - t, 1).

Now, let's calculate the line integral:

∫∫[R] (1 - 2x²)y dA = ∫[0,1] ∫[t²,1] (1 - 2t²)y dy dx + ∫[0,1] ∫[0,t²] (1 - 2t²)y dy dx.

Integrating with respect to y first:

∫[0,1] [(1 - 2t²)(1 - t²) - (1 - 2t²)t²] dt.

Simplifying:

∫[0,1] [1 - 3t² + 2t⁴] dt.

Integrating with respect to t:

[t - t³ + (2/5)t⁵]_[0,1] = 1 - 1 + (2/5) = 2/5.

Therefore, the line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1,1), and the line segment from (1,1) to (0,1) is equal to 2/5.

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Answer:

You have putted 35 points lol but then they take that 10 points away so in total you get 25 points and get that 10 points if you get the brainliest...

Step-by-step explanation:

Answer:

554,000

Step-by-step explanation:

that is the answer

Emma earns $554,064.80  in total in the first 11 years of her career

We are to determine the future value of $39,000 each year for 11 years given the growth rate of 5%

The formula for calculating future value:

FV = P (1 + r)^n

Where :

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

First year =  $39,000

Second year = 39,000 x (1.05) = $40,950

Third year = 39,000 x (1.05)^2 = $42,997.50

Fourth year = 39,000 x (1.05)^3 = $45,147.38

Fifth year = 39,000 x (1.05)^4 = $47,404.75

Sixth year = 39,000 x (1.05)^5 = $49,774.99

seventh year = 39,000 x (1.05)^6 = $52,263.74

eighth year = 39,000 x (1.05)^7 = $54,876.93

ninth year = 39,000 x (1.05)^8 = $57,620.78

tenth year = 39,000 x (1.05)^9 = $60,501.82

eleventh year = 39,000 x (1.05)^10 = $63,526.91

Sum of the earnings for the first eleven years = $554,064.80

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Answer:

| 4x - 6 | = - 6

Step-by-step explanation:

The absolute value function always produces a positive value.

| 4x - 6 | = - 6 ← negative value is not possible

Answer:

The first one

Step-by-step explanation:

For the second one x is equal to 11 bc -2 minus 11 is 9 which is a solution

The third one x is equal to 0 which is a solution

The last one x is equal to 4 which is a solution

There are no solution for the first on bc it does not equal to -6

Correct me if this is wrong

Answer:

aₙ= 4n+11

Step-by-step explanation:

the sequence 15, 19, 23, 27

is AP with the first term 15 and

the common difference 19-15=23-19=27-23= 4

aₙ= a₁+(n-1)d

aₙ= 15+(n-1)*4= 15+4n- 4= 4n+11

aₙ= 4n+11

The  area of the triangle is equal to: Area = (|A| x |B| x sin(θ))/2

To calculate the area of a triangle with 3 vectors, we will use the vector triple product formula. This formula states that the area of the triangle is equal to the magnitude of the cross product of two of the vectors divided by two.

Let's say we have three vectors A, B, and C. The area of the triangle is then equal to the magnitude of the cross product of vector A and B, divided by two.

The magnitude of the cross product of A and B can be calculated as follows:

Magnitude of (A x B) = |A| x |B| x sin(θ)

Where |A| and |B| are the magnitudes of vectors A and B, and θ is the angle between them.

Therefore, the area of the triangle is equal to:

Area = (|A| x |B| x sin(θ))/2

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a. Approximately 84.13% of the boxes weigh more than 22.4 ounces.

b. Approximately 4.78% of the boxes weigh less than 21.3 ounces.

a. To find the percentage of boxes weighing more than 22.4 ounces, we need to calculate the area under the normal distribution curve to the right of 22.4. We can use the z-score formula to standardize the value. The z-score is calculated as (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation. In this case, the z-score is (22.4 - 23.5) / 1.1 ≈ -1. The corresponding area to the right of the z-score -1 can be looked up in the standard normal distribution table or calculated using software, which is approximately 0.8413. Therefore, approximately 84.13% of the boxes weigh more than 22.4 ounces.

b. Similarly, to find the percentage of boxes weighing less than 21.3 ounces, we calculate the area under the normal distribution curve to the left of 21.3. The z-score is (21.3 - 23.5) / 1.1 ≈ -2. The corresponding area to the left of the z-score -2 can be looked up in the standard normal distribution table or calculated using software, which is approximately 0.0228. However, since we want the percentage of boxes weighing less than 21.3 ounces, we subtract this value from 1 to get approximately 0.9772 or 97.72%. Therefore, approximately 4.78% of the boxes weigh less than 21.3 ounces.

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The probability that every even number appears at least once before the first occurrence of an odd is 1/20.

Given:

A fair 6-sided die is repeatedly rolled until an odd number appears.

There are 6! ways to order the 6 numbers and 3!(3!) ways to order the evens in the first three spots and the odds in the next three spots.

so the probability = 3!*3! / 6!

= 3!*3! / 6*5*4*3!

= 3*2*1 / 6*5*4

= 6*1 / 30*4

= 6/120

= 1/20

Therefore the probability that every even number appears at least once before the first occurrence of an odd is 1/20.

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Answer:

879

Step-by-step explanation:

84 |73836          

1738-672=663

663-588=756

The answer choice which represents a true statement with respect to the functions is; Choice C; The graphs of g(x) and f(x) both have end behaviors that go in the same direction.

It follows from the task content that the functions given are;

f(x) = 3|x+14|

g(x)= x³ + 3x-14

h(x)=3*x +1

i(x) = log4(x - 1).

From the functions given above, it follows that the range of f(x) is all positive real numbers and has an ending behaviour as function g(x) as their ending behaviour indicates ascending slope (positiv slope).

Hence, The graphs of g(x) and f(x) both have end behaviors that go in the same direction.

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Answer:

3

Step-by-step explanation:

That sentence tells us that when you add 9 to Craig's age, the answer is 41 therefore you are simply adding those two and you'll get the equation:

\(c\ +\ 9\ =\ 41\)

The probability that Mia is on time to exactly one of the classes is 0.5

Given that

probability of she is late for the art class (x)= 0.5

probability of she is late for the calculus class(y) = 0.4

the probability of she is not late for the art class (z)= 1 - x = 1 - 0.5 =0.5

the probability of she is not late for the calculus class(p)= 1 - y = 1 - 0.4 = 0.6

the probability that Mia is on time to exactly one of the classes =

Probability of arriving (late for Calculus and on time for Art)) or (late for Calculus and on time for Art)

= (x × p) + (y × z)

=(0.5 × 0.6) +(0.4 × 0.5)

=0.3+0.2

= 0.5

The probability that mia is on time to exactly one of the classes = 0.5

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To use the squeeze theorem, we need to find two other sequences that "squeeze" the given sequence and have the same limit. First, notice that for any positive integer n, we have:\(0 < 4n/n! < 4/(n-1)!\). The limit of the given sequence 4n/n! is 0.

This is because \(0 < 4n/n! < 4/(n-1)!\) and \(4n = 4 x 3 x ... x 2 x 1 x n, so 4n/n! = (4/n) x (3/(n-1)) x ... x (2/2) x (1/1) = 4/(n-1)!.\) Now, we can see that: \(0 < 4n/n! < 4/(n-1)!\)

Taking the limit as n approaches infinity, we have:\(0 ≤ lim (4n/n!) ≤ lim (4/(n-1)!) = 0\)  By the , the limit of the given sequence 4n/n! is 0. For finding the limit, squeeze theorem is very useful.

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The answer is (C) 0.054. 

Regularly a binomial probability issue, where we are captivated by the probability of getting five left-handers in a course of 93 understudies, given that the probability of an individual being left-handed is 0.15.

The condition for the binomial probability spread is:

P(X = k) = (n select k) * \(p^k * (1 - p)^(n - k)\)

where:

P(X = k) is the likelihood of getting k triumphs (in our case, k left-handers)

n is the general number of trials (in our case, the degree of the lesson, 93)

p is the probability of triumph on each trial (in our case, the probability of an individual being left-handed, 0.15)

(n select k) is the binomial coefficient, which speaks to the number of ways of choosing k objects from a set of n objects.

Utilizing this condition, able to calculate the probability of finding five left-handers in a lesson of 93 understudies:

P(X = 5) = (93 select 5) * \(0.15^5 * (1 - 0.15)^(93 - 5)\)

P(X = 5) = 0.054

Consequently, the answer is (C) 0.054. 

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Answer: Your answer is correct

Step-by-step explanation: The last answer is incorrect because the line has a positive slope and shows a positive association.

(a) The graph of the linear functions is as attached.

(b) The equation of the linear function in slope-intercept form is; y = x

(c) The equation of the transformed function in slope-intercept form is;

y = x + 2 and y = x - 3

Functions are defined as the relationship between sets of values. For example, in the function; y = f(x), for every value of x there exists a set of y values.

x is the independent variable.

y is the dependent variable.

If the linear function is; y = x,

The equation of the transformation in slope-intercept form is given as;

For translation of 2 units up, we have;

y = x + 2

For a translation of 3 units down, we have;

y = x - 3

Thus, the required graph has been attached and the solution is determined.

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After considering the given data we conclude that the answer for the given sub question regarding combination are
a) the number of different groups of 10 employees that can be selected is 14,307,292
b) the number of possible groups of 10 employees that consist only of employees who either take public transit or drive to work is 77
c) employees who take public transit is 66
d) employees who drive to work is 11
e) employees that do not include anyone who takes public transit is 184,756
f) employees that do not include anyone who drives to work is 352,716
g) employees that consist of at least one person who drives to work is 14,054,576
h) employees that consist of at least one person who drives to work is 14,054,576
i) employees that consist of 5 people who take public transit and 5 people who drive to work is 365,904
j) employees that consist of 4 people who take public transit, 3 people who drive to work, and 3 people who do neither is 6,270,840

a) This is a combination problem, where the order of selection does not matter. The formula for the number of combinations of n objects taken r at a time is \(nCr = n! / (r! * (n-r)!)\), where n is the total number of objects and r is the number of objects being selected. In this case, there are 32 employees and we want to select 10 of them, so the number of different groups of 10 employees that can be selected is:
\(32C10 = 32! / (10! * (32-10)!) = 14,307,292\)

b) We can add the number of groups that consist only of employees who take public transit to the number of groups that consist only of employees who drive to work. To find the number of groups that consist only of employees who take public transit, we can choose 10 employees from the 12 who take public transit. Similarly, to find the number of groups that consist only of employees who drive to work, we can choose 10 employees from the 11 who drive to work. Therefore, the number of possible groups of 10 employees that consist only of employees who either take public transit or drive to work is:
\(12C10 + 11C10 = 66 + 11 = 77\)

c) We can choose 10 employees from the 12 who take public transit, so the number of possible groups of 10 employees that consist entirely of employees who take public transit is:
\(12C10 = 66\)

d) We can choose 10 employees from the 11 who drive to work, so the number of possible groups of 10 employees that consist entirely of employees who drive to work is:
\(11C10 = 11\)

e) We can choose 10 employees from the 20 who either drive to work or do neither, so the number of possible groups of 10 employees that do not include anyone who takes public transit is:
\((20C10) = 184,756\)
f) We can choose 10 employees from the 21 who either take public transit or do neither, so the number of possible groups of 10 employees that do not include anyone who drives to work is:
\((21C10) = 352,716\)

g) We can subtract the number of possible groups of 10 employees that do not include anyone who takes public transit from the total number of possible groups of 10 employees. Therefore, the number of possible groups of 10 employees that consist of at least one person who takes public transit is:
\(32C10 - 20C10 = 14,122,536\)

h) We can subtract the number of possible groups of 10 employees that do not include anyone who drives to work from the total number of possible groups of 10 employees. Therefore, the number of possible groups of 10 employees that consist of at least one person who drives to work is:
\(32C10 - 21C10 = 14,054,576\)

i) We can choose 5 employees from the 12 who take public transit and 5 employees from the 11 who drive to work. Therefore, the number of possible groups of 10 employees that consist of 5 people who take public transit and 5 people who drive to work is:
\(12C5 * 11C5 = 792 * 462 = 365,904\)

j) We can choose 4 employees from the 12 who take public transit, 3 employees from the 11 who drive to work, and 3 employees from the 9 who do neither. Therefore, the number of possible groups of 10 employees that consist of 4 people who take public transit, 3 people who drive to work, and 3 people who do neither is:
\(12C4 * 11C3 * 9C3 = 495 * 165 * 84 = 6,270,840\)
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Answer:

1075.25

Step-by-step explanation:

subtract the 15 percent using freindly percents

Answer:

Step-by-step explanation:

The answer is option 3

Answer:

Option 3

Step-by-step explanation: Hope this helps :-)

1. Moving at constant, you are at equilibrium and the restorative force of the scale balances your weight. So the scale exerts a force of 490 N and reads 50.0 kg.

2. The elevator is now moving up and slowing down, so its acceleration is pointing opposite the direction of motion, and Newton's second law says the net force is

F - 490 N = (50.0 kg) (-4.9 m/s²)

where F is the magnitude of the force due to the scale. Solve for F to get

F = 490 N - (50.0 kg) (4.9 m/s²) = 245 N

and the scale would read (245 N)/g = 25 kg. This should make sense; your inertia will cause your body to "want" to continue moving up at the same speed while the elevator slows down, and this relieves some of the upward force needed to keep your body moving with the elevator.

3. With the elevator in free fall, Newton's second law gives

F - 490 N = (50.0 kg) (-9.8 m/s²)   ⇒   F = 0 N

and the scale would read 0 kg. Now you're falling with the elevator; the scale doesn't have to counteract your weight anymore.

Answer:

x=1/2

Step-by-step explanation:

7x−6=3+x−5−2x

Step 1: Simplify both sides of the equation.

7x−6=3+x−5−2x

7x+−6=3+x+−5+−2x

7x−6=(x+−2x)+(3+−5)(Combine Like Terms)

7x−6=−x+−2

7x−6=−x−2

Step 2: Add x to both sides.

7x−6+x=−x−2+x

8x−6=−2

Step 3: Add 6 to both sides.

8x−6+6=−2+6

8x=4

Step 4: Divide both sides by 8.

8x /8 = 4 /8

x= 1 /2

Answer:

0

Step-by-step explanation:

We need to factor the GCF (Greatest Common Factor).

The resulting term is a product of the GCF and the original expression divided by the GCF.

In our example, the GCF is equal to X + 2.

I'm not sure if its 0

But mine is "0"

Answer:

1

Step-by-step explanation:

assuming your points are (0,3) and (-3,0) you would "rise" 3 and "run" 3 to get from one point to the next on a graph, making your rise over run (aka slope) 3/3 which is equal to 1.

Answer:

Step-by-step explanation:

I jus sacrificed for you, the answer is 3 1/8

Aisha must have used 4 blocks of clay in all, as 3 blocks of clay would not have been enough and 4 blocks would be more than enough.

In mathematics, an expression is a combination of numbers, variables, and mathematical operations that represents a value or a quantity. Expressions can contain arithmetic operators such as addition, subtraction, multiplication, and division, as well as functions and constants.

Aisha used 2.5 pounds of clay to make the mugs (2 1/2 = 5/2) and 1.5 times as much clay for the teapot, which means she used 1.5 x 2.5 = 3.75 pounds of clay for the teapot.

Therefore, Aisha used a total of 2.5 + 3.75 = 6.25 pounds of clay.

Since each block of clay weighed 2 pounds, Aisha used 6.25 / 2 = 3.125 blocks of clay.

However, since she cannot use a fraction of a block of clay, Aisha must have used 4 blocks of clay in all, as 3 blocks of clay would not have been enough and 4 blocks would be more than enough.

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A long-term movement up or down in a time series is called a trend. A trend represents the general direction of a time series over a longer period of time. It helps to identify the overall pattern or behavior of the data.

For example, let's say we are analyzing the sales of a product over several years. If the sales consistently increase over time, we can say there is an upward trend. On the other hand, if the sales consistently decrease, there is a downward trend.

Trends are important because they can help us understand and predict future behavior of the time series. By identifying trends, we can make informed decisions and forecasts. Trends can also be useful in identifying cycles and seasonality in the data.

In summary, a long-term movement up or down in a time series is called a trend. It represents the overall direction of the data over a longer period of time and helps in making predictions and forecasts.

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To check the if a table represents a linear function we have to find the rate of change between the first two ordered pairs can be compared to the rate of change between the first and last ordered pairs to see if they are the same.

Well, a straight line is proportional to a linear function (on a graph). And the answers to the numbers can't be the same. If the X input is 5, for instance, and the Y output is 7, then Another non-linear X input of 5 and Y output of 8 follows.

The terms "linear function" in mathematics apply to two different but related ideas: A polynomial function of degree zero or one that has a straight line as its graph is referred to as a linear function in calculus and related fields.

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Answer:

1.33

Step-by-step explanation:

The value of the angles x,y, and z is 73 degrees,88 degrees, and 55 degrees.

We have given that,

Two overlapping triangles

Here we have the angle Z and 52

The sum of the all angle in a triangle is 180 degrees.

Therefore we have

The Z+43+52+40=180

Z+125=180

Z=55

Therefore in a triangle degree 52 degrees and 40 degree

y+52+40=180

y+92=180

y=180-92

y=88 degrees

For the angle x, we have

x+15+40+52=180

x+107=180

x=180-107

x=73

The value of the angles x,y, and z is 73 degrees,88 degrees, and 55 degrees.

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