What are the terms that descripe these values for the element oxygen?

Answer:

Its D and E

Explanation:

i took the test and the other guy who answered gave u half of the answer

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The information which can be inferred about the Sun according to the graph include:

This is defined as a pictorial representation of data in an organized manner.

From the graph, we can infer that the Sun has an intermediate temperature and is less brighter than most stars.

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Answer:

b. pH=12

Explanation:

Step 1: Given data

Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M

Step 2: Write the reaction for the dissociation of NaOH

NaOH is a strong base that dissociates according to the following equation.

NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)

The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.

Step 3: Calculate the pOH

pOH = -log [OH⁻] = -log 0.01 = 2

Step 4: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -2 = 12

Answer:

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)

Explanation:

Which ONE of the following is an oxidation–reduction reaction?

A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.

B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.

C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.

D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. C is reduced and H is oxidized.

Answer: improvements in nutrition

Explanation:

Answer:Look at the graph above. Human population increased dramatically at certain times. The graph begins 10,000 BC, although you can't really see the line. Population starts to rise perceptibly at around 1800 BC. The numbers begin to rise dramatically about 200 years ago. What causes these changes

Explanation:

Answer:

It's made from dairy.

Explanation:

Answer:

83

Explanation:

3X + 2Y → 5C + 4D

2 moles of Y will produce 5 moles of C

33.0 moles of Y will produce: 33.0 x 5/2 = 82.5 or 83 moles of C

Equivalence point is dependent on stoichiometry of balanced reaction of acid and base. Stoichiometry only considers number of mols involved, not strength of reactants involved.

To ascertain how much of a specific drug is present in a sample, an experiment called a b is done. A diprotic acid is one that has a two-proton (H+) capacity per molecule. Two equivalence points—points at which the number of moles of acid and base are equal—are present when a diprotic acid is titrated with NaOH. When all of the acids have been neutralised, the first equivalence point is reached; meanwhile, the second equivalence point is reached when the surplus base has been neutralised. The amount of NaOH solution required to go from the first equivalence point to the second equivalence point is twice the amount required to travel from the first equivalence point to the first equivalence point.

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When a cylinder is filled to a volume of 3.50 L at 760 mmHg with chlorine gas. The volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

Boyle's law is generally a gas law which states that "a gas's pressure and volume are inversely proportional when the temperature is kept constant, as volume increases, pressure falls and vice versa".

Mathematically,

P₁V₁ = P₂V₂

P₁ = 760 mmHg = 101.32 kPa

V₁ = 3.50 L

P₂ = 50 kPa

V₂ = ?

Substituting the values we get,

101.32 × 3.50 = 50 × V₂

⇒ V₂ = (101.32 × 3.50)/50

⇒ V₂ = 7.0924 L

Hence, the volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

by using this formula you will get it

Explanation:

number of mole = number of particles÷ Avogadro's number

n=3.51×10^23÷ 6.02×10^23

n = 0.58 moles

Answer: 16.01

Explanation:(16x.9963) +(20x.0037)

Answer:

In Addition To Its Oxidizing Abilities, The Hypochlorite Ion Has A Relatively High Affinity For ... It is also the active ingredient that forms when swimming pool water is treated with chlorine.

The equation that can be able to complete the reaction as it has been shown is option C

Free energy takes into account both the enthalpy (heat content) and entropy (degree of disorder) of a system. It provides a measure of the system's ability to do useful work or drive chemical reactions.

The formula for calculating free energy is:

G = H - TS

where:

G is the Gibbs free energy

H is the enthalpy (heat content) of the system

T is the temperature in Kelvin

S is the entropy (degree of disorder) of the system

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Answer:

Meteoroids

Explanation:

Meteoroids are the elements of the universe that have the smallest diameter among all elements, reaching less than 1 km in diameter. They are any rocky or metallic body, which exists in space and does not reach more than 100 meters. It is common for meteoroids to fall to earth, but their impact is not as destructive as the impact of other space bodies, due to their tiny size.

20.0M

Given the following parameters;

Moles of solute = 0.5moles

Volume of the solvent = 25mL = 0.025L

Required parameter

Molarity of the resulting solution

The formula for calculating the molarity of the solution is expressed as:

n is the moles of solute

v is the volume of solvent

Substitute the given parameters into the formula to have:

Therefore the molarity of the resulting solution is 20.0M

The new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa

Boyle's law states that "volume of a given quantity of gas is inversely proportional to its pressure  as long as temperature remains constant.

It is expressed as;

P₁V₁ = P₂V₂

Given the data in the question;

To determine the new pressure as the piston is at the top of the cylinder, we substitute our given values into the expression above.

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.0067107atm × 0.6250L ) / 0.0600L

P₂ = 0.629194188Latm / 0.0600L

P₂ = 10.4865698atm

P₂ = 1062.55kPa

Therefore, the new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa

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We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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The number of moles of the sodium chlroide from the calculation is 0.11 moles.

We can connect a substance's mass to its particle count using the concept of a mole. A material's molar mass, which is measured in grams per mole, is the mass of one mole of that substance. One mole of carbon-12 atoms, for instance, weighs 12 grams according to its molar mass of 12 grams/mol.

We have that;

Number of moles = Mass/molar mass

mass = 6.37 grams

Molar mass =  58.5 g/mol

Number of moles = 6.37 g/58.5 g/mol

= 0.11 moles

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There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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Answer:

Nuclear energy produces radioactive waste

A major environmental concern related to nuclear power is the creation of radioactive wastes such as uranium mill tailings, spent (used) reactor fuel, and other radioactive wastes. These materials can remain radioactive and dangerous to human health for thousands of years

Explanation:

The groupings of atoms/ions listed below should be sorted from largest to smallest in terms of atomic radius:

Ga > Ge > As.

Br⁻ > Kr > Rb⁺

Atomic radius is commonly defined as the total distance between an atom's nucleus and the electron's outermost orbital.

For, Ga (Galium), Ge ( Germanium), and As (Arsenic) the order of these elements are - Ga > Ge > As.

Next, for Br⁻ (Bromide ion), Kr (Krypton), and Rb⁺ (Rubidium ion) the order of these elements are - Br⁻ > Kr > Rb⁺.

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here's your answer..

Answer:

Disulfur decafluoride

Explanation:

Disulfur decafluoride is the correct answer.

Your mom

Explanation:

The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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