Answers
1- measure the mass of the container
2- measure the volume of the liquid
3- measure the combined mass of the liquid and the container.
4-determine the mass of the liquid alone
5-divide the mass by the volume.
Related Questions
At 25 degrees Celsius, 50g of sugar is soluble in 100ml of water. If I add 55g of sugar to
25-degree water, what will my solution look like and what will the ratio of dissolved to
undissolved solute be? If I heat up the solution, what will my solution look like and what will
the ratio of dissolved to undissolved solute be? If I then slowly cool the mixture to 25 degrees
again, what will my solution look like and what will the ratio be? Finally, if I add one seed
crystal to the mixture, what will my solution look like and what will my ratio be?
Answers
At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.
If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.
When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.
If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.
Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.
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what is the kinetic energy of a 3kg ball that is rolling at 2 meters per second
Answers
Answer:
6 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 3 \times {2}^{2} \\ = \frac{1}{2} \times 3 \times 4 \\ = 3 \times 2\)
We have the final answer as
6 JHope this helps you
Question 10 of 10
Stacy set up three vials on a hot plate. He poured the same amount of liquid
into each of the vials, and then he turned on the hot plate. Which physical
property is he most likely testing?
OA. Hardness
OB. Surface tension
O C. Boiling point
OD. Melting point
Answers
Answer:C
Explanation:
C. Boiling point
Stacy is most likely testing the boiling point of the liquid in each vial. By heating the vials on the hot plate, he is increasing the temperature of the liquid and observing when it begins to boil. Boiling point is a physical property of a substance that is affected by factors such as pressure and temperature. It is the temperature at which the vapor pressure of the liquid is equal to the pressure exerted on the liquid by its surroundings. Therefore, by testing the boiling point of the liquid, Stacy can determine its identity or purity.
When a protonated epoxide is attacked by water, the nucleophile attacks from the ___________ in an __________ process.
Answers
When a protonated epoxide is attacked by water, the nucleophile attacks from the "top" or "front" of the epoxide ring in an "S_N2" substitution nucleophilic bimolecular process.
What is protonated epoxide ?
A protonated epoxide is a molecule that contains an epoxide ring (a three-membered ring consisting of two carbon atoms and one oxygen atom) that has been protonated, or had a hydrogen ion (H+) added to it.
The protonation of an epoxide ring can occur in the presence of an acidic medium, such as a strong acid like sulfuric acid (H2SO4) or hydrochloric acid (HCl).
In acidic conditions, the lone pair of electrons on the oxygen atom of the epoxide ring can interact with the positively charged hydrogen ion, resulting in the formation of a protonated epoxide.
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Place the conjugate bases of the following acids in descending order of basic strength.
Answers
The descending order of the strength of the conjugate bases of the given acids is as follows:
H₂OHBrOHClOHNO₃What are conjugate bases?Conjugate bases are substances formed when an acid donates its proton.
The strength of the conjugate bases formed from an acid is the inverse of the acid dissociation constant, Ka, of the acid.
The acid dissociation constant, Ka, of the given acid are given below:
The acid dissociation constant, Ka, of hypobromous acid, HBrO, is 2.3 * 10⁻⁹
The acid dissociation constant, Ka, of trioxonitrate (v) acid, HNO₃ is 2.4 * 10¹
The acid dissociation constant, Ka, of water, H₂O, is 1.8 x 10⁻¹⁶
The acid dissociation constant, Ka, of Hypochlorous acid, HClO, is 3.0 x 10⁻⁸
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5. The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures
Answers
There are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.
To determine the number of water molecules in the given volume of water, we need to use the relationship between mass, volume, and molar mass of water.
First, we need to find the mass of water in the bottle:
Mass = Density * Volume
Mass = 0.967 g/mL * 499.8 mL = 483.9 g
Next, we need to convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.
Moles = Mass / Molar mass
Moles = 483.9 g / 18.015 g/mol = 26.88 mol
Finally, we can calculate the number of water molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.
Number of molecules = Moles * Avogadro's number
Number of molecules = 26.88 mol * (6.022 x 10^23 molecules/mol) = 1.62 x 10^25 molecules
Therefore, there are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.
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What volume of 0.900% w/v saline solution can be prepared from 0.300 L of a 3.00% w/v saline solution available in stock?
Answers
Percentage denotes a quantity per million ( ppm, where a part for a solution is a unit of mass (g, g, g, kg, et.) or capacity (L, mL, L, etc.). The quantity expressed in percent solutions
What stage is a solution in?
When the solvent makes up a significant portion of the combination, as is frequently the case, the solution typically has the condition of the solvent. The concentration of a solution, which measures how much solute is present in a specific volume of solution or solvent, is one crucial parameter. When water is one of the solvents, the phrase "aqueous solution" is used.
What material is dissolving in the solution to create a solution?
A solute is the material that dissolves in a solvent to create a solution. It is less prevalent in the solution than the solvent. A solvent is a substance that is present in a solution that dissolves a solute. It is more prevalent than the solute in solution. If we use a saltwater solution.
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nitrous acid, hno2, is a weak acid. its weak acid dissociation reaction, written using the h3o convention, is:
Answers
Nitrous acid is a weak acid dissociation reaction, written using the H30 convention, is: HNO2 + H30 (where is used as the equilibrium symbol).
nitrous acid is an inorganic compound having the formula HNO3. It is a powerfully corrosive mineral acid. Although the material is colorless, older samples could have a yellow tint from nitrogen oxide decomposition. Most commercially available nitric acid has a 68% concentration in water. When the solution contains more than 86% HNO3, nitric acid flares. Depending on how much nitrogen dioxide is present, fuming nitric acid can also be categorized as red fuming nitric acid at concentrations above 86% or white fuming nitric acid at concentrations above 95%.
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Sample Response: Matter is any substance that has
mass and takes up space. It can be identified using
physical properties such as density. Matter can change
states, which can be measured as boiling and melting
points. It can also be identified based on chemical
properties such as reactivity, flammability, and
composition.
What did you include in your response? Check all that
apply.
Matter is any substance that has mass and takes up
space.
Matter can be identified using physical properties
such as density and the boiling and melting points.
Matter can be identified based on chemical
properties such as reactivity, flammability, and
composition.
Done
Answers
The responses that can be included are : matter is any substance that has mass and takes up space, matter can be identified using physical properties, such as density and the boiling and melting points, matter can be identified based on chemical properties such as reactivity, flammability, and composition.
Matter is any substance that has mass and takes up space. This is a fundamental characteristic of matter, distinguishing it from non-material entities. Matter can be identified using physical properties such as density. Density is the measure of how much mass is contained in a given volume of a substance. Additionally, the boiling and melting points of matter can also be used to identify it. These points represent the temperatures at which matter changes from one state to another (e.g., from a solid to a liquid or from a liquid to a gas). Matter can also be identified based on its chemical properties. Chemical properties include reactivity, which refers to how a substance interacts with other substances; flammability, which indicates the ability to burn or ignite; and composition, which refers to the types and proportions of elements or compounds present in a substance. These characteristics and properties help scientists categorize and understand different forms of matter, enabling them to study and manipulate it for various purposes, such as in chemistry, physics, and engineering.
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2KCIO3 -> 2KCI + 302
For the reaction shown here, calculate how many moles of reactants are needed to produce 96 grams of oxygen gas as a product.
A) 1
B) 2
C) 3
D) 4
Answers
Moles of oxygen
Given mass/molar mass96/323mol2 mol reactants required for 3mol O_2
So our answer is 2
A nearby pond has what appears to be steam coming off of it after a cold front passes through. What is it?
a. evaporation
b. sublimation
c. vaporization
d. condensation
Answers
Answer:
a. evaporation .
Explanation:
In this case, given the described situation, we should take into account that there are two types of liquid-gas phase transitions, evaporation and vaporization, which occur in totally different way.
Firstly, evaporation is a superficial phenomena, it means that it occurs at the surface of the liquid only whereas the vaporization is a bulk phenomena, which means that it occurs along the whole volume of liquid.
In such a way, we can infer that cold steam stream flowing over the pond has the capacity to strip or remove liquid water molecules in the pond and take them to the vapor phase, which means that the answer is a. evaporation .
Best regards.
module 9 lesson 4: colligative properties slide 2: colligative properties when you add a to a , the properties of the resulting are different than those of the pure . these different properties are called . definition: colligative properties do not depend on , but they do depend on the . 3 colligative properties are: slide 3: number of solute particles ionic compounds break into their when they in solution, whereas compounds stay together as molecules. what is the number of particles a solute breaks into known as? what is the symbol? the the number of particles in the the greater the difference will be for the of the solution compared to the solvent. slides 4
Answers
The number of particles a solute breaks into is known as the van't Hoff factor (i) and is represented by the symbol i.
Colligative properties are properties of a solution that depend on the concentration of solute particles, but not on the nature of the solute. Three colligative properties are:
1. Lowering of freezing point: when a solute is added to a solvent, the freezing point of the resulting solution is lower than that of the pure solvent.
2. Elevation of boiling point: when a solute is added to a solvent, the boiling point of the resulting solution is higher than that of the pure solvent.
3. Osmotic pressure: solutions have an osmotic pressure, which is the pressure required to prevent the flow of solvent into the solution through a semipermeable membrane.
When an ionic compound dissolves in a solvent, it breaks into its individual ions, whereas non-ionic compounds stay together as molecules. The number of particles a solute breaks into is known as the van't Hoff factor (i) and is represented by the symbol i. The greater the van't Hoff factor, the greater the difference will be for the colligative properties of the solution compared to the solvent.
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Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
Answers
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
Answers
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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Phosphine contains 91.1 % P an 8.9% H. Water contain 88.8% of O and 11.2% of H.Phosphorus tetraoxide contains 56.4% of and 43.6% of O.Show that these data illustrate law of reciprocal proportions.
Answers
According to the law of reciprocal proportions, they should combine in the ratio of 10.24:7.92:1.29 by mass.
What is the law of reciprocal proportions ?According to the law of reciprocal proportions when two elements join to form more than one compound, the weights of one element that combine with a fixed weight of the another are in a ratio of small whole numbers.
In phosphine, phosphorus = 91.1 parts and hydrogen = 8.9 parts
So, 8.9 pads of hydrogen combine with phosphorus = 91.1 parts .
1 part of hydrogen combine = 91.1 / 8.9
= 10.24 parts
Similarly,
for water 88.8 / 11.2
= 7.92 parts of hydrogen
For Phosphorus tetra oxide
= 56.4 / 43.6
= 1.29 parts
Thus, According to the law of reciprocal proportions, they should combine in the ratio of 10.24:7.92:1.29 by mass.
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which of the following lewis diagrams best represents the bonding in the N2O molecule, considering formal charges? justify your answer.
Answers
The best diagram to represent N2O is the second diagram.
The Lewis diagram is used to represent the way two or more atoms bond. This is possible by using lines to represent bonds and dots to represent electrons.
In the case of the molecule N2O bonding occurs in the following way:
A triple bond is formed between the nitrogen atoms, which means, in the Lewis diagram the nitrogen atoms are connected with three lines.The oxygen atom connects to one of the nitrogen atoms.The nitrogen atom that is not connected to the oxygen will have 2 electrons represented by dots because the number of valence electrons is 5, but three were used in the triple bond.The oxygen atom will have 6 electrons represented by dots, which are equal to the number of valence electrons.Learn more about Lewis diagram in: https://brainly.com/question/9436176
Which coefficients correctly balance the equation below
AI+CuSO - -> AI2(SO4)3+Cu
Answers
Answer:
Explanation:
In order to balance the equation, the coefficients in front of each element must be equal on both sides of the equation. Here's one way to balance the equation:
2 AI + 3 CuSO4 ---------------> 2 AI2(SO4)3 + 3 Cu
This means that for every 2 atoms of AI and 3 molecules of CuSO4, you'll get 2 molecules of AI2(SO4)3 and 3 atoms of Cu.
The frequency of a radio wave was measured to be (9.3x10^8) Hz What is the energy of the radio wave in kilojoules (kJ)?
1 Hz = 1 s–1
h = 6.626 x 10-34 J.s
Answers
The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.
What is a wave?The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.
Thus;
We know that;
Frequency of the wave = 9.3x10^8 Hz
Plank's constant = 6.626 x 10^-34 J.s
E = hf
E = energy of the wave
h = Plank's constant
f = frequency of the waves
E = 9.3x10^8 Hz * 6.626 x 10^-34 J.s
= 6.2 * 10^-25 J
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A compound is 60.00% carbon, 5.75% hydrogen, and 34.25% oxygen. Determine the empirical formula of the compound.
Answers
Answer:
The empirical formula of the compound is C2H5O.
Determine whether each of the examples represents a colligative property or a non-colligative property. boiling point elevation Choose... color Choose... freezing point depression Choose... vapor pressure lowering Choose... density Choose...
Answers
Answer:
boiling point elevation - colligative property
color - non-colligative property
freezing point depression - colligative property
vapor pressure lowering - colligative property
density - non-colligative property
Explanation:
A colligative property is a property that depends on the number of particles present in the system.
Freezing point depression, boiling point elevation and vapour pressure lowering are all colligative properties of solutions.
Colour and density do not depend on the number of particles present hence they are not colligative properties.
The boiling point elevation, freezing point depression, and vapor pressure lowering are colligative properties. And color and density are non-colligative properties.
Explanation:
The colligative properties are the properties depending upon the number of particles of solute not on the nature of the solute.Example of colligative properties:Vapor pressure loweringElevation boiling pointDepression in freezing pointOsmotic pressureThe non-colligative properties are the properties depending upon the nature of solute and solvent.Example of non-colligative properties :ViscositySurface tensionDensitySolubilitySo, from this, we can conclude that boiling point elevation, freezing point depression, and vapor pressure lowering are colligative properties. And color and density are non-colligative properties.
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the conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism: if the concentrations of both -och3 and acetyl chloride were increased 2 times, what would happen to the rate of the reaction?
Answers
The rate of reaction between acetyl chloride and methyl acetate will increase, as the reactants will often increase the rate of reaction.
What is the rate of reaction?This happens because methyl acetate and acetyl chloride particles react at larger concentrations, causing more collisions and speeding up the reaction.
Since they are more liberated to collide and react with one another, the presence of more acetyl chloride and methyl acetate particles in a given volume increases the likelihood of a collision. This increases the number of successful collisions per unit of time and, consequently, the reaction's rate.
Therefore, the rate of reaction will increase.
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How many oz of a 2% axis solution and how many oz of a 10% axis solution must be mixed to make 48oz of a 7% acid solution?
Answers
84 oz of 2% acid solution and 48-84 = -36 oz of 10% acid solution must be mixed to make 48 oz of a 7% acid solution.
What is an acid solution?An acid solution is described as a liquid mixture that occurs when hydrogen ions are released when combined with water.
We have that x oz of 2% acid solution be mixed with (48-x) oz of 10% acid solution.
The total amount of acid in the 2% solution is 2% * x oz = 0.02x oz.
The total amount of acid in the 10% solution is 10% * (48-x) oz = 1 * (48-x) oz.
The total amount of acid in the 48 oz mixture is 0.02x oz + 1 * (48-x) oz = 0.07 * 48 oz = 3.36 oz.
Hence we can calculate that :
0.02x + 1 * (48-x) = 3.36 and solve for x
0.02x + 48 - x = 3.36
0.02x - x + 48 = 3.36
Adding x to both sides:
0.02x + 48 = 3.36 + x
Subtracting x from both sides:
0.02x + 48 - x = 3.36
Dividing both sides by 0.02:
x = 84 oz
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A + B = AB is an example of a ________reaction
Answers
Answer:
A + B = AB is an example of a synthesis reaction
Explanation:
Assignment Your Unde a professor in a University has Sent you an touration 6 his Inaugural lectore wate a letter to him, showing appreciation for him on halind gesture and Congratulating! his achievements So far
Answers
In this letter, express gratitude to your uncle, a university professor, for his invitation and congratulate him on his achievements.
Here are the steps to be followed:
Express gratitude and appreciation: Begin the letter by expressing your gratitude for your uncle's kind gesture in inviting you to his inaugural lecture. Show genuine appreciation for his thoughtfulness in including you in such an important event.
Congratulate your uncle on his achievements: Extend your heartfelt congratulations to your uncle for his accomplishments thus far. Acknowledge his hard work, dedication, and commitment to becoming a professor at the university. Highlight specific achievements or milestones that you find particularly impressive.
Share your excitement and anticipation: Express your excitement and anticipation about attending his inaugural lecture. Let your uncle know that you are looking forward to being a part of this significant moment in his career and witnessing his expertise in action.
Offer support and encouragement: Offer words of encouragement and support for your uncle's future endeavors. Let him know that you are proud of him and believe in his continued success. Encourage him to keep pursuing his passion and making a positive impact in his field.
Close the letter with warm regards: End the letter with a closing remark and warm regards. You can use phrases such as "Best regards," "With love," or "Sincerely," followed by your name.
Proofread and revise: Before finalizing the letter, review it for any errors or areas that may need improvement. Ensure that the tone is respectful, appreciative, and heartfelt.
Send the letter: Once you are satisfied with the letter, send it to your uncle either via traditional mail or email, depending on your preferred method of communication.
By following these steps, you can write a thoughtful and appreciative letter to your uncle, expressing your gratitude for his invitation and congratulating him on his achievements.
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What type of chemical reaction is this? CH4 + O2 + CO2 + H20 ?
Answers
Answer:
combustion reaction. hope this helps!
To what temperature should you heat a sample of air initially at 315K to increase its volume by 25% ?
Answers
The sample of air should be heated to 252 Kelvin (K) to increase its volume by 25%.
It is possible to determine the temperature to which the sample of air should be heated by using the concept of the ideal gas law. PV = nRT is the ideal gas law, and it relates the pressure (P), volume (V), number of moles (n), temperature (T), and gas constant (R). we can focus on the relationship between volume and temperature since the number of moles and pressure are assumed to be constant.
By showing the increase in volume as a percentage (25%), we can make the equation (V+0.25V)/T = V/T, where V represents the initial volume of the air.
On making the equation simple, we find Tfinal / Tinitial = 1.25.
To solve for Tfianal, the final temperature,
Tfinal = Tinitail / 1.25
On substituting the initial temperature value of 315K into the equation, we will be getting;
Tfinal = 315K / 1.25
Tfinal = 252K
Hence, the sample of air should be heated to 252 Kelvin (K) in order to increase its volume by 25%.
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What will happen when these mutations can no longer be killed by
antibiotics?
Answers
Answer:
Antibiotic resistance happens when the germs no longer respond to the antibiotics designed to kill them. That means the germs are not killed and continue to grow. It does not mean our body is resistant to antibiotics.
What is bonding all about in chemistry?
Answers
Answer:
It is like about a attraction between atoms, molecules, and more.
Does anyone know Chemistry
Answers
Answer:
so so
Explanation:
this your question?? <_>
The smallest quantity of energy that can be released is called an
A photon
B quantum
C electron
D atom
Answers
Answer:
Quantum is the correct answer.
Explanation:
PennFoster