what are the physical mechanisms associated with heat transfer by conduction, convection, and radiation?

answer

d just too the test

Answer:

a) 600°F  days

b) 103°F  days

Explanation:

Given data :

overall heat loss coefficient = 400 Btu/h.oF

Furnace efficiency = 0.78

applying the degree- day method the heating energy requirement per day can be obtained by subtracting the average temperature for a particular day from the acceptable mid/balance point temperature

lets assume the mid/balance point temperature = 65°F

a) heating energy requirement in Denver Colorado

 we will have 600°F days  ; considering the  the average temperature - balance point temperature

= 665 - 65 = 600°F

b) heating energy requirement in Little Rock Arkansas

 we will have 103°  days

Answer:

Veracity, Value and Visualization are not only the characteristics of Big Data but are also the characteristics of relational databases. Veracity of data is issue with smallest data stores this is the reason that it is important in relation...

Answer:

1)ΔL = 0.616 mm

2)Δd = 0.00194 mm

Explanation:

We are given;

Force; F = 52900 N

Initial length; L_o = 207 mm = 0.207 m

Diameter; d_o = 19.2 mm = 0.0192 m

Elastic modulus; E = 61.4 GPa = 61.4 × 10^(9) N/m²

Now, from Hooke's law;

E = σ/ε

Where; σ is stress = force/area = F/A

A = πd²/4 = π × 0.0192²/4

A = 0.00009216π

σ = 52900/0.00009216π

ε = ΔL/L_o

ε = ΔL/0.207

Thus,from E = σ/ε, we have;

61.4 × 10^(9) = (52900/0.00009216π) ÷ (ΔL/0.207)

Making ΔL the subject, we have;

ΔL = (52900 × 0.207)/(61.4 × 10^(9) × 0.00009216π)

ΔL = 0.616 × 10^(-3) m

ΔL = 0.616 mm

B) Poisson's ratio is given as;

υ = ε_x/ε_z

ε_x = Δd/d_o

ε_z = ΔL/L_o

Thus;

υ = (Δd/d_o) ÷ (ΔL/L_o)

Making Δd the subject gives;

Δd = (υ × d_o × ΔL)/L_o

We are given Poisson's ratio to be 0.34.

Thus;

Δd = (0.34 × 19.2 × 0.616)/207

Δd = 0.00194 mm

(a) To calculate the complex power (S), we can use the formula S = P + jQ, where P is the real power (in watts), and Q is the reactive power (in VARs). Since we are given the apparent power (120 VA) and the power factor (0.707 lagging), we can find the real and reactive power using the following equations:

P = S * power factor = 120 VA * 0.707 = 84.84 W
Q = √(S^2 - P^2) = √(120^2 - 84.84^2) = 84.84 VAR (lagging)

Now we can write the complex power as S = 84.84 + j84.84.

(b) To find the rms current (I) supplied to the load, we can use the formula I = S / V, where V is the rms voltage. Rearranging the formula and plugging in the given values, we get:

I = 120 VA / 110 V = 1.0909 A rms

(c) To determine the impedance (Z), we can use the formula Z = V / I, where V is the rms voltage, and I is the rms current. Plugging in the values, we get:

Z = 110 V / 1.0909 A = 100.8 + j100.8 ohms (approx)

(d) Assuming that Z = R + jωL, we can find the values of R and L by equating the real and imaginary parts:

R = 100.8 ohms
ωL = 100.8 ohms

To find L, we can use the formula ω = 2πf, where f is the frequency. Given the 60-Hz source, we can calculate ω as follows:

ω = 2π * 60 Hz = 377 rad/s

Now we can solve for L:

L = ωL / ω = 100.8 ohms / 377 rad/s ≈ 0.268 H

So, the values of R and L are 100.8 ohms and 0.268 H, respectively.

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Answer:

Cutting-plane View

Explanation:

The view of an architectural design, by which it displays the complex interior features of an object concealed by hidden lines, is a cutting-plane view.

View of an architectural design is a method of representation of the design of a building or an item from the different perspective.

The cutting-plane view is generally used to represent the complex interior features in an architectural design.

The cutting-plane view is presented by the hidden lines, which is shown in architectural design.

Thus, the view of an architectural design by which it displays the complex interior features of an object concealed by hidden lines, is cutting-plane view.

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Therefore, the expected number of industrial deaths each year would be approximately 0.15, assuming the incidence rate remains constant.

To calculate the expected number of industrial deaths each year, we need to determine the incidence rate of industrial deaths per worker-year and then multiply it by the number of worker-years.

Given:

Total number of full-time workers (N) = 1500

Frequency or rate of accidents (FAR) = 5 accidents per 100,000 worker-hours

Number of work hours per worker per year (H) = 8 hours per shift * 250 days = 2000 hours

First, let's calculate the total number of worker-years (WY) for all employees:

WY = N * H = 1500 * 2000 = 3,000,000 worker-hours

Next, we can calculate the incidence rate of industrial deaths per worker-year (IDR):

IDR = (FAR / 100,000) * WY

Substituting the given values:

IDR = (5 / 100,000) * 3,000,000 = 0.15

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Optimal control is a technique for designing a control system that maximizes some performance criterion, typically defined as a weighted sum of the control effort and the system's output. This design approach is widely used in aerospace, among other fields, and it is considered to be a very practical design approach.

There are several reasons why optimal control design can be considered practical in comparison to direct pole placement design. One of the main features of optimal control design is that it can handle systems with multiple inputs and outputs, which is a common requirement in aerospace applications. In contrast, direct pole placement design is typically limited to single-input, single-output systems.
Another advantage of optimal control design is that it can handle nonlinear systems, which are common in aerospace applications. Nonlinear systems are typically more difficult to control than linear systems, and direct pole placement design may not be effective for these types of systems.Optimal control design also provides a systematic way to trade off between competing design objectives, such as tracking performance and control effort.
This is important in aerospace applications, where minimizing fuel consumption and maximizing performance are often competing objectives.In conclusion, optimal control design is a practical design approach for aerospace applications because it can handle systems with multiple inputs and outputs, nonlinear systems, and competing design objectives.

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In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.

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Consumers desire for more comfortable seat belts led engineers to improve seat belts.

Explanation:

Answer:

B. Consumers' desire for more comfortable seat belts led engineers to improve seat belts.

Explanation:

just got the question right on APEX

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Explanation:

Energy is what makes change happen and can be transferred form one object to another. Energy can also be transformed from one form to another. Power is the rate at which energy is transferred. It is not energy but is often confused with energy.

Answer:

• Energy is the ability to do work, and it can be transferred from one body (or system) to another, but is always conserved.

• Power is the amount of energy transferred per unit time.

Hope this helps!

The strategies for dealing with the problem of self-occlusion in object data capture are:

Occlusion is known to often takes place if  two or more objects are seen too close and are seen to be merged or combine with one another.

Note that in the case above, The strategies for dealing with the problem of self-occlusion in object data capture are:

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Answer: So you are dealing with maximum and minimum weights and you want to know what MINIMUM number of supporting strands for this block and tackle system are needed I believe. If so you are dealing with economic imbalances Though we are not worrying about money Right? Right we need physics which Physics study matter and how it moves You would need 8 STRANDS

Explanation: Step By Step

Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation:

Answer:

True

Explanation:

they put it through a process to be able to reuse it

Answer:

sheet metal

Explanation:

The power exerted by the dominant group over minority groups through institutions, such as mass media and popular culture, in order to communicate and reinforce ruling values and beliefs that may be adopted by members of the minority group is referred to as hegemony.

The term "hegemony" best describes the concept described in the question. Hegemony refers to the social, cultural, and ideological influence wielded by the dominant group over subordinate groups within a society. It involves the imposition of dominant norms, values, and beliefs that shape the worldview and behavior of both the dominant and subordinate groups.

In this context, institutions like mass media and popular culture play a significant role in disseminating and reinforcing the ideologies and narratives of the dominant group. By controlling the representation, portrayal, and dissemination of information, the dominant group can shape public opinion and maintain their position of power and control.

However, it is important to note that while hegemony influences the beliefs and behaviors of some members of the minority group, it does not encompass all forms of discrimination, racism, or oppression. These terms represent specific manifestations of power imbalances and discriminatory practices, which can be reinforced by hegemonic systems but are not limited to them.

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True: The material used to provide weather protection is often chosen for its architectural style, as it can contribute to the overall aesthetics and functionality of a building.

The material used to provide weather protection is often chosen for its architectural style, as it not only serves a functional purpose but also contributes to the overall aesthetic of the building. For example, a building with a traditional or historic architectural style may use materials such as slate or tile for its roof, while a modern building may opt for a more sleek and contemporary material like metal or glass.

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True.

The material used for weather protection is often chosen for its architectural style, as well as its durability, cost, and environmental impact. Different weather protection materials, such as metal, tile, asphalt, and wood, can provide different aesthetics and functionalities to a building's exterior design.

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Answer:

See explanation below

Explanation:

Hypo-eutectoid steel has less than 0,8% of C in its composition.

It is composed by pearlite and α-ferrite, whereas Hyper-eutectoid steel has between 0.8% and 2% of C, composed by pearlite and cementite.

Ferrite has a higher tensile strength than cementite but cementite is harder.

Considering that hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains whereas hypereutectoid steel contains a higher amount of cementite, the following properties are obtainable:

Hypo-eutectoid steel has higher yield strength than Hyper-eutectoid steel

Hypo-eutectoid steel is more ductile than Hyper-eutectoid steel

Hyper-eutectoid steel is harder than Hyper-eutectoid steel

Hypo-eutectoid steel has more tensile strength than Hyper-eutectoid steel.

When making a knife or axe blade, I would choose Hyper-eutectoid steel alloy because

1. It is harder

2. It has low cost

3. It is lighter

When making a die to press powders or stamp a softer metals, I will choose hypo-eutectoid steel alloy because

1. It is ductile

2. It has high tensile strength

3. It is durable

Answer:

(a)

Steels having carbon within 0.02% – 0.8% which consist of ferrite and pearlite are known as hypoeutectoid steel.

Steels having greater than 0.8% carbon but less than 2.0% are known as hypereutectoid steel.

(b)

The proeutectoid ferrite formed at a range of temperatures from austenite in the austenite+ferrite region above 726°C. The eutectoid ferrite formed during the eutectoid transformation as it cools below 726°C. It is a part of the pearlite microconstiutents . Note that both hypereutectoid and hypoeutectoid steels have proeutectoid phases, while in eutectoid steel, no proeutectoid phase is present.

Proeutectoid signifies is a phase that forms (on cooling) before the eutectoid austenite decomposes. It has a parallel with primary solids in that it is the first phase to crystallize out of the austenite phase. If the steel is hypoeutectoid it will produce proeutectoid ferrite and if it is hypereutectoid it will produce proeutectoid cementite.  The carbon concentration for both ferrites is 0.022 wt% C.

(c)

(i) Yield strength: The hypoeutectoid steel have good yield strength and hypereutectoid steels have little higher yield strengh.

(ii) Ductility: The hypoeutectoid steel is more ductile and the ductility has decreased by a factor of three for the eutectoid alloy. In hypereutectoid alloys the additional, brittle cementite on the pearlite grain boundaries further decreases the ductility of the alloy. The proeutectoid cementite restricts plastic deformation to the ferrite lamellae in the pearlite.

(iii) Hardness:  hypoeutectoid steels are softer and hypereutectoid steel contains low strength cementite at grain boundary region which makes it harder than hypoeutectoids.

(iv) Tensile strength: Grain boundary regions of hypereutectoid steel are high energy regions prone to cracking because of cementite in the grain boundaries, its tensile strength decreases drastically even though pearlite is present. Hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains, so grain boundaries being the high energy state region, it has a higher tensile strength.

(d)

I would recommend hypereutectoid steel alloy to make a knife or ax blade

1- Hardness is required at the surface of the blades.

2- Ductility is not needed for such application.

3- Due to constant impact, the material will not easily yield to stress.

(e)

I would choose a hypoeutectoid steel alloy to make a steel that was easy to machine.

1- hypoeutectoid steel alloys have high machinability, hence better productivity

2- It will be used on softer metals, hence its fitness for the application

3- Certain amount of ductility is required which hypoeutectoid steel alloys possess.

Explanation:

See all together above

For a wear indicator type ball joint, when the grease fitting boss is flush with the base: B. The ball joint should be replaced.

A wear indicator can be defined as a type of technology that is designed to alert and warn a car owner or driver that the car's brake pad is needs a replacement.

Generally, a wear indicator is designed and fitted with a small boss. Thus, this small boss would continuously recede into its housing as wear occurs. However, when it recedes into the cover plate or flush with the base, it simply means that the ball joint should be replaced.

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The economic advantage of selecting steel over aluminum is Rs. 246 - Rs. 217.25 = Rs. 28.75 per unit.

In the design of a jet engine part, the designer has a choice of specifying either an aluminium alloy casting or a steel casting. Either material will provide equal service, but the aluminium casting will weigh 1.2 kg as compared with 1.35 kg for the steel casting. The aluminium can be cast for Rs. 80.00 per kg. and the steel one for Rs. 35.00 per kg. The cost of machining per unit is Rs. 150.00 for aluminium and Rs. 170.00 for steel. Every kilogram of excess weight is associated with a penalty of Rs. 1,300 due to increased fuel consumption. Which material should be specified and what is the economic advantage of the selection per unit?The weight of the aluminum casting is 1.2 kg while the weight of the steel casting is 1.35 kg. Therefore, the weight of the aluminum casting is less than that of the steel casting.Cost of manufacturing per kg for aluminum = Rs. 80.00Cost of manufacturing per kg for steel = Rs. 35.00Cost of machining per unit of aluminum = Rs. 150.00Cost of machining per unit of steel = Rs. 170.00Now, let's calculate the cost of a unit of aluminum:Cost of casting = 1.2 x 80 = Rs. 96.00Cost of machining = Rs. 150.00Total cost of aluminum = Rs. 150 + Rs. 96 = Rs. 246.00Similarly, let's calculate the cost of a unit of steel:Cost of casting = 1.35 x 35 = Rs. 47.25Cost of machining = Rs. 170.00Total cost of steel = Rs. 170 + Rs. 47.25 = Rs. 217.25

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Answer:

Wood is heavy

Explanation:

The cable that is attached exactly above the centre of gravity of the beam and has the length L = sqrt(x2 + h2) = sqrt((W/F)2) = sqrt(0.5) sqrt(W) = sqrt(700) sqrt(0.5) 18.7 ft. is the shortest cable that may be used to raise the beam.

The standard weight is determined as follows: G is equal to L * mweight, where L is the length of the beam determined as the separation between the extreme points of the beam body measured along the direction of the beam axis, with all features except holes taken into consideration.

We may express L2 in terms of x and F using the equations above as follows:

L² = x² + h²

= x² + (T/F)²

Substituting T = W + F, we get:

L² = x² + ((W+F)/F)²

Expanding and simplifying, we get:

L² = x² + (W/F)² + 2W/F + 1

d(L²)/dx = 2x

Setting this equal to zero, we get:

x = 0

This tells us that the minimum value of L² is obtained when x = 0, which means that A and B are vertically aligned. In other words, the cable should be attached directly above the center of gravity of the beam.

When we apply the derivative to F, we obtain:

d(L²)/dF = 2(W/F)² - 2W/F²

Setting this equal to zero, we get:

F = sqrt(2W)

Substituting W = 700 lb, we get:

F = sqrt(1400) lb

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ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.

ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.