Answer:
a. Manganese(IV) oxide
b. Mercury(I) chloride
c. Iron(III) nitrate
d. Titanium(IV) chloride
e. Copper(II) bromide
Explanation:
The IUPAC nomenclature is regulated by International Union of Pure and Applied Chemistry which is used in organic chemistry for naming of the organic chemical compounds.
a. Manganese(IV) oxide is IUPAC name of manganesse dioxed . It is an inorganic compound having the formula MnO2.
b. Mercury(I) chloride is IUPAC name of mercurous chloride . It is also known as the mineral calomel and have a chemical formula Hg2Cl2.
c. Iron(III) nitrate is IUPAC name of ferric nitrate . It have a chemical formula Fe(NO₃)₃.
d. Titanium(IV) chloride is IUPAC name of titanium tetrachloride - . It have a chemical formula TiCl4.
e. Copper(II) bromide is IUPAC name of cupric bromide with chemical formula CuBr2 or Br2Cu.
The water solubility of an ester is _____
A) higher for smaller esters due to hydrogen bonding.
B) lower for smaller esters due to hydrogen bonding.
C) nonexistent due to hydrogen bonding.
D) higher for smaller esters due to a lack of hydrogen bonding.
E) lower for smaller esters due to a lack of hydrogen bonding.
Due to an absence of hydrogen bonding, an ester's water solubility is greater for smaller esters. Here option D is the correct answer.
The water solubility of an ester, a type of organic compound with the functional group RCOOR', depends on several factors, including the size and polarity of the ester molecule. Generally, smaller esters are more soluble in water than larger esters due to their lower molecular weight and the presence of polar functional groups.
Although esters can participate in hydrogen bonding with water molecules, this interaction is not strong enough to overcome the hydrophobic effect, which causes nonpolar molecules to aggregate in water.
In addition, the size of the ester molecule can also hinder hydrogen bonding interactions with water. Option B, "lower for smaller esters due to hydrogen bonding," is also incorrect for the reasons mentioned above.
Option C, "nonexistent due to hydrogen bonding," is also incorrect. Esters can dissolve in water to some extent due to their polar carbonyl group, which can interact with water molecules through hydrogen bonding.
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1) What is your Dawn Wall and how are you approaching it? What is the expected outcome? (Or, reflect on a 'Dawn Wall' in your past and discuss how you overcame it.)
2) Describe a few things that Kevin and Tommy had to overcome to realize their goal. (Or, describe what things had to be in order or exist for their goal to be realized.)
How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degrees Celsius and 1.02 atmospheres?
CS2(l) + 3O2(g) yields CO2(g) + 2SO2(g)
2.78 liters
5.95 liters
12.1 liters
11.9 liters
The volume of carbon dioxide produced is approximately (d) 11.9 liters.
To determine the amount of carbon dioxide (C\(O_2\)) produced when 37.8 grams of carbon disulfide (C\(S_2\)) reacts with excess oxygen gas (\(O_2\)), we need to use stoichiometry and the given balanced chemical equation:
C\(S_2\)(l) + 3\(O_2\)(g) → C\(O_2\)(g) + 2S\(O_2\)(g)
First, we calculate the number of moles of C\(S_2\) using its molar mass:
Molar mass of (C\(S_2\)) = 12.01 g/mol (C) + 32.07 g/mol (S) × 2 = 76.14 g/mol
Number of moles of (C\(S_2\)) = mass / molar mass = 37.8 g / 76.14 g/mol ≈ 0.496 mol
From the balanced equation, we can see that the stoichiometric ratio between (C\(S_2\)) and C\(O_2\) is 1:1. Therefore, the number of moles of C\(O_2\) produced will also be 0.496 mol.
Now we can use the ideal gas law to calculate the volume of C\(O_2\) at the given temperature and pressure. The ideal gas law equation is:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
Converting the temperature from Celsius to Kelvin:
T(K) = 28.85°C + 273.15 = 302 K
Using the ideal gas law:
V = nRT / P = (0.496 mol) × (0.0821 L·atm/mol·K) × (302 K) / (1.02 atm) ≈ 11.9 L
The correct answer is 11.9 liters.
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The compound [Fe(SCN)(OH2 )5 ] 2 can be detected in the reaction of [Co(NCS)(NH3 )5 ]2 with Fe2 (aq) to give Fe3 (aq) and Co2 (aq). What does this observation suggest about the mechanism
Answer:
Explanation:
It is observed that the compounds are likely to be coordination compounds whereby SCN(thiocyanate) appears to be an ambidentate ligand possessing two(2) nucleophilic centers i.e sulphur and nitrogen.
The addition process of \(\mathbf{Fe^{2+}}\) since it is an oxidizing agent that produces \(\mathbf{Fe^{3+}} \ and \ \mathbf{Co^{2+}}\) complex in solution.
Thus;
\(\mathbf{[Co(NH_3)_5(NCS)]^{+2}+[Fe(H_2O)_6]^{+2} \to [Fe(SCN) (H_2O)_5]^{+2}+ [Co(H_2O)_6]^{+2}}\)
From above; the electron transfer reaction showcases an oxidation-reduction (redox) reaction.
Which energy transformations happen when the students close the switch on the circuit and the blades of the fan begin to spin?
Answer: When we switch on a fan, the fan converts a significant portion of the electrical energy into kinetic energy of the fan blades. Some part of electric energy is converted into heat. energy transformation will be:-
Electrical energy → Kinetic energy
Explanation:
What is this organic compound?
Please asap!!
3,3-dimethylhexane is the nomenclature of the compound
two isotopes of potassium are k-37 and k- 42
In the ground state, it should be noted that the the number of valence electrons the K-42 isotope has is only one valence electron.
How to illustrate tye valence electrons?In the first group of the periodic table is potassium. It has a valence shell with one electron.
We can assume that potassium only has one electron on its valence shell because it belongs to group 1. The isotope is irrelevant because the only distinction between isotopes is the number of neutrons present in their nuclei.
In summary, it should be noted that K-42 only possesses one valence electron.
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Two isotopes of potassium are K-37 and K-42. How many valence electrons are in an atom of K-42 in the ground state?
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
I NEED HELP WItH THIS 5th GRADE QUESTION ITS VERY VERY EASY no Links PLZ and I will Report any useless AWnser PLZ HELP WILL mARK AS BRAINLIST AND Will giVE 1000 Points if correct Answer
How is the mass of a solid measured?
By estimating
With a beaker
With a ruler
With a scale
Answer:
A Beaker or graduated cylinder
Explanation:
Place the solid into the graduated cylinder. Measure the amount of water in the graduated cylinder. The product is the solid's mass wich i mean by that is what number the water level is at.
Answer:
Beaker
Explanation:
Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) chloride precipitate. What was the molar concentration of chloride ions in the solution (in mol/L)?
Answer:
[Cl⁻] = 0.016M
Explanation:
First of all, we determine the reaction:
Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)
This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:
PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps
Initial x
React s
Eq x - s s 2s
As this is an equilibrium, the Kps works as the constant (Solubility product):
Kps = s . (2s)²
Kps = 4s³ = 1.7ₓ10⁻⁵
4s³ = 1.7ₓ10⁻⁵
s = ∛(1.7ₓ10⁻⁵ . 1/4)
s = 0.016 M
Timmy and his dad are throwing rocks into the pond. The rocks that Timmy's dad throws go farther and faster. Which of
Newton's 3 Laws is demonstrated in this sccenario?
Newton's 1st Law
Newton's 2nd Law
Newton's 3rd Law
none of Newton's laws are demonstrated in this scenario
What will increased temperature in a reaction cause
1 Particles in a reaction to move more slowly
2 Particles in a reaction to move faster
3 Particles in a reaction to generate more electrical ions
4 Particles in a reaction to lose more electrical ions
6.3 gram of HNO3 as mass of nitrate
Moles of HNO 3
= 6.3/63 = 0.1 moles
HNO3 has 1 atom of H , 1 atom of N , 3 atoms of O
No of atoms = moles of molecule × atomicity of atom × avogadro number
No of atoms of H =0.1×1×6.023×10^23
= 6.023×10^22
No of atoms of N =0.1×1×6.023×10^23
= 6.023×10 ^22
No of atoms of O =0.1×3×6.023×10 ^23
= 18.069×10 ^22
what is the periodic tabil mostly made of ___i_
Answer:
Chemical elements.
If 1.60 g of steam at 100.0 ∘C condenses into 40.5 g of water, initially at 28.0 ∘C, in an insulated container, what is the final temperature of the entire water sample? Assume no loss of heat into the surroundings.
is atomic number is the same as element number?
please me if yes or no please
Answer:
Yes
Explanation:
becuz every atom of the same element is identical. The number of protons in every atom is equal and the atomic number is equal too and every atom of the same element has the same atomic number.
\(\color{7851A9}I\) \(\color{7851A9}hope\) \(\color{7851A9}it\) \(\color{7851A9}helps!\) ^-^
Answer:
the answer is yes
Explanation:
pls mark as brainliest the first one who have an explanation
Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 35. g of hydrochloric acid is mixed with 73.0 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.
Answer:
No mass of HCl could be left over by the chemical reaction because is the limting reactant and it is all consumed.
Explanation:
Our reactants are: HCl and NaOH
Products are: NaCl and H₂O
This is a neutralization reaction that can also be called an acid base reaction, an acid and a base react to produce water and a neutral salt, in this case where we have strong acid and base.
Ratio is 1:1. We convert mass to moles:
35 g . 1 mol / 36.45 g = 0.960 moles of HCl
73 g . 1 mol / 40 g = 1.82 moles of NaOH
As ratio is 1:1, for 0.960 moles of HCl we need 0.960 moles of NaOH and for 1.82 moles of NaOH, we need 1.82 moles of acid.
As we only have 0.960 moles of HCl and we need 1.82 moles, no acid remains after the reaction goes complete. HCl is the limiting reactant, so the acid, it is all consumed.
What is the blood alcohol level in mass percent if 8.33 mL of 0.04988 M K2Cr2O7 is required for titration of a 9.9950 g sample of blood?
The blood alcohol level in mass percent is 0.0956% if 8.33 mL of 0.04988 M \(K2Cr2O7\) is required for titration of a 9.9950 g sample of blood.
To calculate the blood alcohol level in mass percent, we need to first determine the amount of ethanol present in the blood sample. This can be done by using a redox titration with potassium dichromate \((K2Cr2O7)\), which oxidizes the ethanol to acetic acid.
The balanced chemical equation for the reaction is:
\(C2H5OH + 2Cr2O7^2- + 16H+ → 2CO2 + 4Cr^3+ + 11H2O\)
From the balanced equation, we can see that the stoichiometric ratio between \(K2Cr2O7\) and ethanol is 2:1. Therefore, the moles of ethanol in the blood sample can be calculated as:
moles of ethanol = 0.5 × moles of \(K2Cr2O7\)
The moles of \(K2Cr2O7\)can be determined from its concentration and volume used in the titration:
\(moles of K2Cr2O7 = 0.04988 mol/L × 8.33 × 10^-3 L = 4.15 × 10^-4 mol\)
Substituting this value into the equation above, we get:
moles of ethanol = 0.5 × 4.15 × 10^-4 mol = 2.075 × 10^-4 mol
The mass of ethanol in the blood sample can be calculated from its molar mass:
\(mass of ethanol = 2.075 × 10^-4 mol × 46.07 g/mol = 9.551 × 10^-3 g\)
Finally, the blood alcohol level in mass percent can be titration calculated as:
mass percent = mass of ethanol / mass of blood sample × 100%
mass percent = \(9.551 × 10^-3 g / 9.9950 g × 100%\)
mass percent = 0.0956%
Therefore, the blood alcohol level in mass percent is 0.0956%.
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The [H3O+] of a solution with pH = 8.7 is
The [H3O+] of a solution with pH = 8.7 is approximately 1.995 x 10^-9 M.
What is ph solution ?
The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm (base 10) of the concentration of hydronium ions, [H3O+], in the solution. Mathematically, pH is expressed as:
pH = -log[H3O+]
where [H3O+] is the concentration of hydronium ions in moles per liter (M) of the solution. pH values range from 0 to 14, where a pH of 7 is considered neutral. A pH value less than 7 indicates acidity, while a pH value greater than 7 indicates basicity or alkalinity. The pH scale is logarithmic, meaning that a change of one unit in pH represents a ten-fold change in the concentration of hydronium ions. For example, a solution with a pH of 3 has ten times more hydronium ions than a solution with a pH of 4.
The pH of a solution is defined as the negative logarithm (base 10) of the concentration of hydronium ions, [H3O+], in the solution. The mathematical expression for this relationship is:
pH = -log[H3O+]
We can rearrange this equation to solve for [H3O+]:
[H3O+] = 10^(-pH)
Substituting the given pH value of 8.7 into this equation, we get:
[H3O+] = 10^(-8.7)
Using a calculator or logarithmic tables, we find that:
[H3O+] = 1.995 x 10^(-9) M
Therefore, The [H3O+] of a solution with pH = 8.7 is approximately 1.995 x 10^-9 M.
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What is the name of the compound Si5F7?
A. Pentasilicon hexafluoride
B. Sulfur fluoride
C. Pentasilicon heptafluoride
D. Silicon fluoride
Answer:
i think sulfur fluoride
Identify the substance that has formula mass of 133.5amu.
(a) MgCI
b)SCI
c)BCI
D) AICI
The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.
To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.
(a) MgCl2:
The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).
Mg: atomic mass = 24.31 amu
Cl: atomic mass = 35.45 amu
Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu
(b) SCl:
The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).
S: atomic mass = 32.07 amu
Cl: atomic mass = 35.45 amu
Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu
(c) BCl:
The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).
B: atomic mass = 10.81 amu
Cl: atomic mass = 35.45 amu
Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu
(d) AlCl3:
The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).
Al: atomic mass = 26.98 amu
Cl: atomic mass = 35.45 amu
Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D
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22 Agas that is collected by upward delivery is likely to be A heavier than air B insoluble in water C lighter than air D Soluble in water
Answer:
joib
Explanation:
7.5 L of a gas at 2 ATM and a temperature of 75°C is changed and volume to 3.4 L and a pressure of .5 ATM what is the new temperature
Answer:
Explanation:
Combined Gas Law
T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C
If 6.92 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction? C5H12+8O2⟶6H2O+5CO2
If 6.92 mol of C₅H₁₂ reacts with excess O₂, number of moles of CO₂ will be produced by the following combustion reaction is 34.6 mol.
The balanced reaction is given as:
C₅H₁₂ + 8O₂ ---> 5CO₂ + 6 H₂O
Moles of C₅H₁₂ = 6.92 mol
1 mole of C₅H₁₂ produces 5 moles of CO₂
therefore , 6.92 mol of C₅H₁₂ = 5 × 6.92 mol
= 34.6 mol of CO₂
number of moles of CO₂ = 34.6 mol
Thus, If 6.92 mol of C₅H₁₂ reacts with excess O₂, number of moles of CO₂ will be produced by the following combustion reaction is 34.6 mol.
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2. Show the calculation supporting the claim that atmospheric pressure near sea level corresponds to the pressure exerted by a column of mercury that is about 760 mm high. Considering the density of mercury = 13.6 g/cm³.
The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm.
To calculate the pressure exerted by a column of mercury, we can use the formula:
Pressure = density * gravity * height
Given:
Density of mercury = 13.6 g/cm³
Height of the mercury column = 760 mm = 76 cm
Acceleration due to gravity = 9.8 m/s²
First, we need to convert the height of the mercury column from centimeters to meters:
Height = 76 cm * (1 m / 100 cm) = 0.76 m
Now, we can calculate the pressure:
Pressure = 13.6 g/cm³ * 9.8 m/s² * 0.76 m
To ensure consistent units, we need to convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³):
Density = 13.6 g/cm³ * (1 kg / 1000 g) * (1 cm³ / (1e-6 m³))
Density = 13600 kg/m³
Plugging in the values into the pressure formula:
Pressure = 13600 kg/m³ * 9.8 m/s² * 0.76 m
Pressure = 99992.8 Pa
We can express the pressure in terms of atmospheric pressure:
1 atm = 101325 Pa (approximately)
To compare the pressure with atmospheric pressure, we can convert 99992.8 Pa to atm:
Pressure in atm = 99992.8 Pa / 101325 Pa/atm
Pressure in atm ≈ 0.987 atm
The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm. Since atmospheric pressure near sea level is approximately 1 atm, this calculation supports the claim that atmospheric pressure near sea level is equivalent to the pressure exerted by a column of mercury about 760 mm high.
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A 14.579 g sample of CaCl2 was added to 28.016 g of K2CO3 and mixed in water. A 3.558 g yield of CaCO3 was obtained.
What is the limiting reagent?
Answer:
CaCl3 is the limited reagent
Explanation:
The greater your capacity to love, the greater your capacity to feel the pain.
Answer:
that's true
Explanation:
What volume (in L) of 1.20 M FeCl₂ would be required to obtain 0.850 moles of Cl⁻ ions?
Therefore, the volume of 1.20 M FeCl₂ required to obtain 0.850 moles of Cl⁻ ions is 0.354 L.
What is Moles?
One mole of a substance is defined as the amount of that substance that contains the same number of entities, such as atoms, molecules, or ions, as there are in 12 grams of carbon-12. This number, known as Avogadro's number, is approximately 6.022 x 10²³.
The molecular formula for FeCl₂ shows that it contains 2 chloride ions (Cl⁻) for each FeCl₂ molecule. Therefore, the number of moles of Cl⁻ ions is twice the number of moles of FeCl₂.
Given that we want to obtain 0.850 moles of Cl⁻ ions, we can calculate the number of moles of FeCl₂ required as follows:
moles of FeCl₂ = 0.850 moles Cl⁻ ions / 2 = 0.425 moles FeCl₂
To calculate the volume of 1.20 M FeCl₂ required to obtain 0.425 moles, we can use the formula:
moles = concentration (in M) x volume (in L)
Rearranging this formula to solve for volume, we get:
volume (in L) = moles / concentration (in M)
Substituting the values we have, we get:
volume (in L) = 0.425 moles / 1.20 M = 0.354 L
Therefore, the volume of 1.20 M FeCl₂ required to obtain 0.850 moles of Cl⁻ ions is 0.354 L.
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(NH4) (OH) is compound soluble or insoluble?
An inorganic fungicide, microbiocide, and herbicide is ammonium hydroxide. It is very soluble in water and non-volatile.
In Ammonium hydroxide Ammonium Chloride, which hydroxide is insoluble?Because of its extremely high solubility product, magnesium hydroxide, also known as Magnesium hydroxide, is insoluble in Ammonium hydroxide. Nevertheless, when Ammonium Chloride is present, the following reaction occurs, and the magnesium hydroxide dissolves.
Why does water include Ammonium hydroxide?Ammonia is dissolved in water to form ammonium hydroxide (Ammonium hydroxide). The substance, also known as ammonia or ammonia water, is used as a cleaner and in the production of plastics, rubber, fertiliser, and textiles. It is a clear, colourless liquid with a strong to barely detectable ammonia odour.
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A reaction between liquid reactants takes place at in a sealed, evacuated vessel with a measured volume of . Measurements show that the reaction produced of sulfur hexafluoride gas. Calculate the pressure of sulfur hexafluoride gas in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round your answer to significant digits.
Answer:
0.41 atm
Explanation:
A reaction between liquid reactants takes place at 10.0 °C in a sealed, evacuated vessel with a measured volume of 5.0 L. Measurements show that the reaction produced 13. g of sulfur hexafluoride gas. Calculate the pressure of sulfur hexafluoride gas in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round your answer to 2 significant digits.
Step 1: Given data
Temperature (T): 10.0 °CVolume of the vessel (V): 5.0 LMass of sulfur hexafluoride gas (m): 13. gStep 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 10.0 °C + 273.15 = 283.2 K
Step 3: Calculate the moles (n) of SF₆
The molar mass of SF₆ is 146.06 g/mol.
13. g × 1 mol/146.06 g = 0.089 mol
Step 4: Calculate the pressure (P) of SF₆
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T/V
P = 0.089 mol × (0.0821 atm.L/mol.K) × 283.2 K/5.0 L = 0.41 atm