what are the chemical symbols for carbon aluminium hydrogen oxygen and sodium
​

Answer:

true

Explanation:

I believe the answer i chose because the earths atmosphere is mostly made up of different things that causes the earth to interact with human life and also interacts with what's in the atmosphere like energy oxygen carbon dioxide and all the stuff like that i hope its right.

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

Bicycle riders could accelerate/ increase their speed in various ways

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The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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These forces can be seen as a free-body image where we compress the book to a point. The force vectors are then positioned so that their tails are of the vectors point with in plane of the interaction.

Choosing the structure within which the rules of motion will be applied is the first stage. Finding the forces at work on the given software or particle for interest is the second stage. The full body diagram must be drawn in the third phase.

The height of the arrow serves as a symbol for a vector's magnitude. An indication of a scale, such as 1 cm = 5 miles, is made, and the arrow is drawn at the appropriate length using the selected scale. The precise direction is shown by the arrow.

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Answer:

A) F = 21.134 N

B) a = 3180.76 × 10^(24) m/s²

Explanation:

A) We are given;

Mass of alpha particle; m = 4.0026 u

Now, 1u = 1.66 × 10^(-27) kg

Thus; m = 4.0026 × 1.66 × 10^(-27)

Distance apart; r = 6.60 × 10^(−15) m

Charge on the alpha particle is;

q = 2e = 2 × 1.6 × 10^(-19) C

Formula for the force between the two alpha particles is;

F = kq1.q2/r²

k = 8.99 × 10^(9) N.m²/C²

q1 = q2 = 2 × 1.6 × 10^(-19) C

F = 8.99 × 10^(9) × (2 × 1.6 × 10^(-19))²/(6.60 × 10^(−15))²

F = 21.134 N

B) acceleration is given by;

a = F/m

Thus; a = 21.134/(4.0026 × 1.66 × 10^(-27))

a = 3180.76 × 10^(24) m/s²

Answer:

Explanation:

a)

To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.

b)

The amount of energy given up can be calculated as follows:

\(_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)\)

where;

\(M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u\)

Therefore, from the reaction (1);

\(Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}\)

From the second reaction:

\(Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}\)

The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.

= 2π/(4π÷m)

= m/2

Displacement after 0.56 s = 0.008×cos(50π×0.56s)

=1.75×10^(-4) m

Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.

Calculate:

I) the distance between 2 consecutive nodes

ii) the amplitude after 0.565s

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Explanation:

The vertical displacement of the wave is measured from the

equilibrium to the crest and is called the frequency.

crest to the trough and is called the amplitude.

trough to the trough and is called the wavelength.

equilibrium to the crest and is called the amplitude.

HØPÊ ĮŤ ÌŠ helpful

Answer:

An ohmic conductor is defined as one which obeys ohm's law that is V ∝ I where is the voltage and is the current. There must be a linear graph. Silver is an example of an ohmic conductor as the graph for silver is a linear graph. Silver and copper are some examples of ohmic conductor

The heat required to chill 116 g of water from 85°C to 15°C is 33,242.08 J. (or 33.24 kJ).

The moving of minuscule particles known as atoms, molecules, or ions in solids, liquids, and gases produces heat energy. The amount of heat required to cool a substance can be calculated using the formula:

Q = m × C × ΔT

where Q is the heat absorbed or released (in joules), m is the mass of the substance (in grams), C is the specific heat capacity of the substance (in joules per gram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

For water, the specific heat capacity is 4.184 J/g°C.

Using this formula, we can calculate the amount of heat released when cooling 116 g of water from 85°C to 15°C as:

Q = m × C × ΔT

Q = 116 g × 4.184 J/g°C × (85°C - 15°C)

Q = 116 g × 4.184 J/g°C × 70°C

Q = 33,242.08 J

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Answer:

To convert nanometers (nm) to picometers (pm), you need to multiply the value by 1,000. Therefore, to convert 12 nanometers to picometers, you would perform the following calculation:

12 nm * 1,000 pm/nm = 12,000 pm

So, 12 nanometers is equal to 12,000 picometers.

The two phrases that describe the critical thinking skills used in the pursuit of science are options B and E. Analyzing  observations of a comet's velocity to estimate when it will pass by the sun again and writing detailed description of comet.

Critical thinking skills are very important in scientific investigations and data interpretations. Thinking on an observation or scientific backgrounds of a phenomenon and solving complex problems and sorting it eventually leads to the accurate conclusions for the problem.

Here, the estimation of velocity of a comet for its passage around sun will involve critical thinking and use of some theoretical knowledge as well. Gathering of people's opinion or searching history or for fund does nor need any critical thinking.

Making a description of comet through he observation by telescope also need some critical thinking. Therefore, options B and E are correct.

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According to the information, the mass of the rock is found to be 2 kg.

Potential energy may be defined as a type of stored energy that depends upon the relative position of various parts of a system. This energy is held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

According to the question, the potential energy is calculated with the help of the following formula:

where, P.E = 1960 J, g = 9.8 m/sec, and height = 100 m, mass = ?

mass = P.E / g × h = 1960/980 = 2 kg.

Therefore, the mass of the rock is found to be 2 kg.

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The value of the unknown resistance is approximately 44750 Ω.

In a balanced Wheatstone bridge, the ratio of the resistances in the two arms of the bridge is equal to the ratio of the resistances in the other two arms. That is:

R1/R2 = R3/R4

where R1, R2, R3, and R4 are the resistances in the four arms of the bridge.

In this problem, the resistances in three of the arms of the bridge are all exactly 500 Ω. Let the resistance in the fourth arm (the unknown resistance) be denoted by R. The voltage across the galvanometer is zero in a balanced Wheatstone bridge, so the current through the galvanometer is also zero.

Using Ohm's law, the current through the entire circuit is given by:

I = V/(R1 + R2 + R3 + R4)

where V is the voltage of the battery, and R1, R2, R3, and R4 are the resistances in the four arms of the bridge.

The voltage drop across the 500 Ω resistances is given by:

V_500 = (500/(500+500+R)) * V

The voltage drop across the unknown resistance R is also given by:

V_R = (R/(500+500+R)) * V

Since the voltage across the galvanometer is zero, the current through the unknown resistance R is equal to the current through the 80 Ω galvanometer. Using Ohm's law, we can write:

I_R = V_R/R = I_galvanometer = 0.08 μA

Substituting the expressions for the voltages and the current into the equation for the total current, we get:

V/(500+500+500+R) = 0.08 μA

Solving for R, we get:

R = (V/0.08 μA) - 1500 Ω

Substituting the given values, we get:

R = (3.7 V)/(0.08 μA) - 1500 Ω

R = 46250 Ω - 1500 Ω

R = 44750 Ω

Therefore, the value of the unknown resistance is approximately 44750 Ω.

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Answer:

which items are matter?

battery , mobile phone

Answer:

Alfred Wegener

Explanation:

If the weather patterns in your location are severe or there is a tornado or something, then there are some safety measures that you can take till the condition does not get normal.

A cumulonimbus cloud and the earth are both in contact with a rapidly spinning column of air known as a tornado. There is no place that is safe from a tornado; it is one of nature's most destructive powers. A tornado's winds, which may reach speeds of over 300 mph, have the power to uproot trees, damage well-built buildings, and turn common objects into deadly missiles. Being ready and vigilant during a tornado is essential to ensuring your safety.

Some measures to take while in Severe Weather conditions or tornados specifically :

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Answer:

Explanation:

Actually you do get pulled toward the cow. It's just the acceleration is so small you probably did not notice.

Answer:

Explanation:

When a pencil 10 cm long is placed vertically 100 cm from a lens of focal length +50 cm, image is formed at a distance of 50 cm from the lens. The image is inverted and is 50 cm tall.

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

Answer:

354 m/s

Explanation:

For the second overtune (Third harmonic) of an open pipe,

λ = 2L/3................................ Equation 1

Where L = Length of the open pipe, λ = Wave length.

Given: L = 1.75 m.

Substitute into equation 1

λ = 2(1.75)/3

λ = 1.17 m.

From the question,

V = λf.......................... Equation 2

V = speed of sound in the room, f = frequency

Given: f = 303 Hz.

Substitute into equation 2

V = 1.17(303)

V = 353.5

V ≈ 354 m/s

Hence the right answer is 354 m/s

Answer:

The charges are q₁  = 2 × 10⁻⁸ C and  q₂ = 3 × 10⁻⁸ C

Explanation:

Here is the complete question

Two identical tiny balls have charge q1 and q2. The repulsive force one exerts on the other when they are 20cm apart is 1.35 X 10-4 N. after the balls are touched together and then represented once again to 20cm, now the repulsive force is found to be 1.40 X 10-4 N. find the charges q1 and q2.

Solution

The force F = 1.35 × 10⁻⁴ N when the charges are separated a distance of r = 20 cm = 0.2 m is given by

F = kq₁q₂/r₁²

q₁q₂ = Fr₁²/k

q₁q₂ = 1.35 × 10⁻⁴ N × (0.2 m)²/9 × 10⁹ Nm²/C² = 0.054/9 × 10⁻¹³ C² = 0.006 × 10⁻¹³ C² = 6 × 10⁻¹⁶ C²

q₁q₂ = 6 × 10⁻¹⁶ C² (1)

When the charges are brought together, the charge is now q = (q₁ + q₂)/2

The new repulsive force F = 1.406 × 10⁻⁴ N  at a distance of r₂ = 20 cm = 0.2 m is then

F₂ = kq²/r₂²

q² = F₂r₂²/k = 1.406 × 10⁻⁴ N × (0.2 m)²/9 × 10⁹ Nm²/C² = 0.00625 × 10⁻¹³ C² = 6.25 × 10⁻¹⁶ C²

q² = 6.25 × 10⁻¹⁶ C²

q = √(6.25 × 10⁻¹⁶) C

q = 2.5 × 10⁻⁸ C

(q₁ + q₂)/2 =  2.5 × 10⁻⁸ C

(q₁ + q₂) = 2 × 2.5 × 10⁻⁸ C

q₁ + q₂ = 5 × 10⁻⁸ C (2)

q₁  = 5 × 10⁻⁸ C - q₂  (3)

Substituting equation (3) into (1), we have

(5 × 10⁻⁸ C - q₂)q₂ = 6 × 10⁻¹⁶ C²

Expanding the bracket, we have

(5 × 10⁻⁸ C)q₂ - q₂² = 6 × 10⁻¹⁶ C²

So, q₂² - (5 × 10⁻⁸ C)q₂ + 6 × 10⁻¹⁶ C² = 0

Using the quadratic formula to find q₂

\(q_{2} = \frac{-(-5 X 10^{-8} )+/- \sqrt{(-5 X 10^{-8} )^{2} - 4X1X6 X 10^{-16} } }{2X1}\\ = \frac{5 X 10^{-8} )+/- \sqrt{25 X 10^{-16} - 24 X 10^{-16} } }{2}\\= \frac{5 X 10^{-8} )+/- \sqrt{1 X 10^{-16} } }{2}\\= \frac{5 X 10^{-8} )+/- 1 X 10^{-8} }{2}\\= \frac{5 X 10^{-8} + 1 X 10^{-8} }{2} or \frac{5 X 10^{-8} - 1 X 10^{-8} }{2}\\= \frac{6 X 10^{-8} }{2} or \frac{4 X 10^{-8}}{2}\\= 3 X 10^{-8} C or 2 X 10^{-8} C\)

q₁  = 5 × 10⁻⁸ C - q₂

q₁  = 5 × 10⁻⁸ C - 3 × 10⁻⁸ C or 5 × 10⁻⁸ C - 2 × 10⁻⁸ C

q₁  = 2 × 10⁻⁸ C or 3 × 10⁻⁸ C

So the charges are q₁  = 2 × 10⁻⁸ C and  q₂ = 3 × 10⁻⁸ C

The maximum bending stress in the beam can be calculated using the equation: σmax = Mc/I

A statement claiming the equivalence of two expressions is known as an equation. It is typically expressed using mathematical symbols, and can be used to solve for unknown values. An equation can also be used to describe any physical or logical relationship between two or more items. Equations often involve variables, which are symbols that represent unknown values, and can help to express the behavior of a system.

Where M is the moment at the point where the stress is to be calculated, c is the distance from the neutral axis to the point where the stress is to be calculated, and I is the second area moment of inertia of the beam.
For a rectangular beam with a base of 3 inches and a height of 6 inches, the second area moment of inertia is I = (3*6^3)/12 = 27 in^4
Assuming the support at B exerts a uniformly distributed reaction on the beam, the maximum bending moment M = (Reaction * Length^2)/8 = (500 * 6^2)/8 = 1,875 in-lb.
Therefore, the maximum bending stress in the beam is σmax = (1,875 * 6)/27 = 350 psi.

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Answer:

1.  SG  

true

=2.689

2. The object is probably some sort of minerals and rocks such as Feldspar, Corals, Beryl, etc.

Explanation:

Given:

mass in the air= 0.0675 kg

mass in water= 0.0424 kg

The specific gravity of the object will be 2.6892. It is the ratio of the density of the given fluid and the standard fluid.

Density is specified as the mass divided by the volume. It is represented by the unit of measurement as kg/m³.

The mass of the object in air;

m=Vρ₀

m=0.0675 kg

Buoyant force on the object;

B= Vρₐg

For equilibrium;

N+B=m₀g

n=m₀g-Vρₓg

N/g=m₀-Vρₓ

N/g=0.0424 kg

\(\rm \frac{V\rho_0}{V\rho_x} =\frac{0.0675 }{m_0-0.0424 \ kg} \\\\ \frac{\rho_0}{\rho_x} =\frac{0.0675}{0.0675-0.0424} \\\\ \frac{\rho_0}{\rho_x} =2.6892\)

Hence, the specific gravity of the object will be 2.6892.

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Answer:

50m/s

Explanation:

Divide 500 by 10 and keep same variables m/s. Hope this helps!