What are some examples of chemistry?
plisss

Answer:

true

covalent bonds are between non metals and nonmetals. and they are sharing electrons.

Given

Weight of pottasium fluoride (KF) = 29 gms

To find

Number of moles of pottasium fluoride = ?

Solution

we know that molar mass of KF = 58.0967 g

Now,

\(number \: of \: moles = \ \\ \frac{given \: weight \: of \: subtance}{molar \: mass} \)

Number of moles = 29/58 = 0.5 moles

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Answer: 0.50 mol

Explanation:

if you solve you get choice 3 (0.50)

Nitric oxide and 21.6 grams of \(C_3H_6\)may combine to make roughly 21.62 grams of \(C_3H_3N\).

To determine the approximate mass of acrylonitrile (\(C_3H_3N\)) that can be produced from the given reactants, we first need to write and balance the chemical equation for the reaction. The reaction between \(C_3H_6\)(propene) and nitric oxide (NO) to produce acrylonitrile is as follows:

2 \(C_3H_6\)+ 2 NO -> 2 \(C_3H_3N\)+ 2 \(H_2O\)

From the balanced equation, we can see that the molar ratio between \(C_3H_6\)and \(C_3H_3N\)is 2:2, which simplifies to 1:1. This means that the molar mass of \(C_3H_6\)is equal to the molar mass of \(C_3H_3N\).

To calculate the molar mass of \(C_3H_6\), we sum the atomic masses of carbon (C) and hydrogen (H):

Molar mass of \(C_3H_6\)= (3 × atomic mass of C) + (6 × atomic mass of H)

Using the atomic masses from the periodic table:

Molar mass of \(C_3H_6\)= (3 × 12.01 g/mol) + (6 × 1.01 g/mol) = 42.09 g/mol

Since the molar mass of \(C_3H_6\) is equal to the molar mass of \(C_3H_3N\), the molar mass of \(C_3H_3N\)is also 42.09 g/mol.

Now, let's calculate the number of moles of \(C_3H_6\) and \(C_3H_3N\)using their respective masses:

Number of moles of \(C_3H_6\)= Mass of \(C_3H_6\) / Molar mass of \(C_3H_6\)

= 21.6 g / 42.09 g/mol

≈ 0.514 mol

Number of moles of \(C_3H_3N\)= Number of moles of \(C_3H_6\)(due to 1:1 molar ratio)

≈ 0.514 mol

Finally, to find the mass of \(C_3H_3N\), we multiply the number of moles by its molar mass:

Mass of \(C_3H_3N\)= Number of moles of \(C_3H_3N\)× Molar mass of \(C_3H_3N\)

≈ 0.514 mol × 42.09 g/mol

≈ 21.62 g

Therefore, Nitric oxide and 21.6 grams of \(C_3H_6\)may combine to make roughly 21.62 grams of \(C_3H_3N\).

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The torque on the shaft of a motor can be calculated by dividing the power developed by the angular velocity. In this case, when the motor develops 56,000 watts of power and rotates at 300 rad/s, the torque on the shaft is 186.67 newton-meters (Nm).

The torque (τ) on the shaft can be determined using the formula: τ = P / ω Where: τ = Torque on the shaft (in Nm) . P = Power developed by the motor (in watts) . ω = Angular velocity of the shaft (in rad/s)

Substituting the given values into the formula, we have: τ = 56,000 / 300. τ ≈ 186.67 Nm .Therefore, the torque on the shaft of the motor is approximately 186.67 Nm.



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Out of the given compounds, the one that is not the result of the breakdown of energy-releasing nutrients is glucose.

Glucose is a type of sugar and a primary source of energy for living organisms. It is derived from the breakdown of carbohydrates, such as starches and sugars, through processes like glycolysis and cellular respiration. When these energy-releasing nutrients are metabolized in cells, glucose is produced as a byproduct.

On the other hand, the compounds listed in the question - carbon dioxide (CO₂), water (H₂O), and ATP (adenosine triphosphate) - are all products of the breakdown of energy-releasing nutrients.

Carbon dioxide (CO₂) is released during the process of cellular respiration, where glucose is oxidized to produce ATP and other byproducts. It is a waste product of this energy-producing metabolic pathway.

Water (H₂O) is another byproduct of cellular respiration. When glucose is oxidized, oxygen is consumed, and water is formed as a result of the electron transfer and energy-generating reactions occurring in the mitochondria.

ATP (adenosine triphosphate) is the primary energy currency of cells. It is synthesized during cellular respiration through the breakdown of glucose and other energy-rich molecules. ATP stores and transports chemical energy within cells to be used for various cellular processes.

Therefore, out of the given compounds, glucose is not the result of the breakdown of energy-releasing nutrients but rather a molecule that is broken down to release energy.

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A current of 2.41 A is required to produce 91.6 g of chromium metal from chromium(VI) oxide in 12.4 hours.

The calculation to determine the required current to produce a certain amount of chromium metal from chromium(VI) oxide involves using Faraday's law, which relates the amount of substance produced to the current and time. The molar mass of Cr2O3 is 151.99 g/mol, and the reduction of Cr2O3 to Cr involves the transfer of six electrons per mole.

Using these values and Faraday's constant (96,485 C/mol e-), we can calculate the required current as follows:

Calculate the number of moles of Cr2O3:

91.6 g / 151.99 g/mol = 0.603 mol

Calculate the amount of charge needed to reduce the Cr2O3:

6 mol e- / mol of Cr2O3 x 0.603 mol x 96,485 C/mol e- = 350,409 C

Calculate the current required:

350,409 C / (12.4 h x 3600 s/h) = 2.41 A

Therefore, a current of 2.41 A is required to produce 91.6 g of chromium metal from chromium(VI) oxide in 12.4 hours.

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Answer:

in general, as the temperature increases, the solubility of gases in water decreases and the solubility of most solids in water increases.

The formula for Lead(II) silicate is PbSiO3.

Lead(II) silicate is a ternary ionic compound consisting of three different elements: lead (Pb), silicon (Si), and oxygen (O).

The first element, lead (Pb), has a 2+ charge, meaning it has lost two electrons and has a net positive charge.

The second element, silicon (Si), has a 4+ charge, and the third element, oxygen (O), has a 2- charge. To form a neutral compound, the charges of the cations and anions must balance each other.

To determine the formula of Lead(II) silicate, we need to balance the charges of the cations and anions.

Since the lead ion has a 2+ charge and the silicate anion has a 2- charge, we need two lead ions to balance one silicate anion.

The silicate anion, SiO3, has one silicon atom and three oxygen atoms. The 4+ charge of the silicon ion balances the 2- charge of the three oxygen ions.

Therefore, the formula for Lead(II) silicate is PbSiO3.

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Answer:

Helium has the largest first ionization energy.

Explanation:

The correct net ionic equation for the given reaction is option 3: 2OH⁻ + Fe²⁺ → Fe(OH)₂(s).

In a net ionic equation, we only include the species that actively participate in the reaction. The reaction shows that 2 moles of KOH (potassium hydroxide) react with 1 mole of FeCl₂ (iron(II) chloride) to form 2 moles of KCl (potassium chloride) and 1 mole of Fe(OH)₂ (iron(II) hydroxide) as a solid precipitate.

Breaking down the reaction into its ionic form, we have:
2KOH (aq) + FeCl₂ (aq) → 2KCl (aq) + Fe(OH)₂ (s)

The ionic equation can be further simplified by separating all the ions:
2K+ (aq) + 2OH⁻ (aq) + Fe²⁺ (aq) + 2Cl⁻ (aq) → 2K⁺ (aq) + 2Cl⁻ (aq) + Fe(OH)₂ (s)

In the net ionic equation, we eliminate the spectator ions (ions that are present on both sides of the equation and do not actively participate in the reaction), which are K⁺ and Cl⁻. Therefore, the net ionic equation is Option 3:
2OH⁻ (aq) + Fe²⁺ (aq) → Fe(OH)₂ (s)

This equation shows the actual chemical change occurring during the reaction, with hydroxide ions reacting with iron(II) ions to form a solid precipitate of iron(II) hydroxide.

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Answer:

The answer is D.

Explanation:

Including soluble fiber into your diet can lower cholesterol levels.

The catalyst BamH1 will cut the DNA as follows:

Species A: AATTG | GCCTAATTAATTCG | GCCTAG

Species B: AATTCCTACG | GCCTAGCCTTTAATT

Restriction endonucleases or restriction enzymes are enzymes that cleave DNA into pieces at or close to particular recognition regions inside molecules called restriction sites.

EcoRI, BamH1, and smaI are some examples of restriction endonucleases.

BamHI is a type II restriction enzyme that recognizes the DNA sequence "GGATCC" and cuts the DNA at in between G and G.

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Bile salts would not be as effective if they were exclusively polar molecules instead of amphiphilic molecules.

Bile salts would not be as effective because amphiphilic molecules, like bile salts, have both hydrophilic (water-loving) and hydrophobic (water-fearing) regions, which allow them to function effectively in the digestion and absorption of fats. The main function of bile salts is to emulsify fats in the small intestine. Emulsification is a process that breaks down large fat globules into smaller droplets, increasing their surface area and making them more accessible to digestive enzymes, like lipase.

The amphiphilic nature of bile salts is crucial in this process, as their hydrophobic regions interact with fats while their hydrophilic regions interact with the watery environment of the small intestine. If bile salts were exclusively polar molecules, their ability to interact with and emulsify fats would be greatly diminished. Polar molecules tend to dissolve well in water, but they have limited interaction with nonpolar substances, like fats. Consequently, the emulsification of fats would be significantly less efficient, leading to incomplete digestion and absorption of fats and fat-soluble vitamins.

In conclusion, the amphiphilic nature of bile salts is essential for their role in the digestive system. If they were exclusively polar molecules, their effectiveness in emulsifying and digesting fats would be severely compromised.

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Flowchart for the separation and recovery of benzoic acid and naphthalene:

1. Extract benzoic acid from the mixture by steam distillation.

2. Vacuum distillation is used to separate the two components.

3. After separation, naphthalene is recovered as a solid.

4. Benzoic acid is recovered as an oily liquid.
   

Benzoic acid(C6H5-COOH) is a weak acid with a pKa value of 4.2, while naphthalene is neutral, neither acidic nor base. To separate and recover these two components, steam distillation is first used to extract benzoic acid from the mixture. Then, vacuum distillation is used to separate the two components. Naphthalene is recovered as a solid, while benzoic acid is recovered as an oily liquid.

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Answer:

Explanation:

Part A

2 Al + 3 Cl_2 ==>  2 AlC_3

Part B

The balanced equation tells you for every 2 mols of Al you will produce 2 mols of AlCl_3

Find the mass of 1 mol of AlCl_3

Mass Al =                    27

Mass 3Cl = 3*35.5 = 106.5         Add

Mass 1 mol AlCl_3 = 133.5

Answer: 2 mols of AlCl_2 = 267.0 grams

The total binding energy for lithium is 39.25 Mev

The binding energy per nucleon for lithium is 5.61 Mev / nucleon

    Binding energy is the total energy required for the breakdown of a nucleus to its component nucleons

    Total binding energy is the amount of energy released when the atom is formed from its constituent electron, protons and neutrons.

The given mass are lithium is 7.016004 u  and hydrogen is 1.007825

There are 3 hydrogen and 4 neutrons

To calculate the Total binding energy

3 ( 1.0782) +  4 ( 1.008665 ) = 7.058135 u

Mass of neutron is 1.008665 u

1 atomic mass unit is 931.5 Mev

TBe = ( 7.058135 - 7.016004 ) × 931.5

       = 39.25 Mev

Total binding energy is 39.25 Mev

BE= 39.25 / 7

    = 5.61 Mev / neucleon

Hence, The total binding energy is 39.25 Mev.

             The binding energy is 5.61 Mev / neucleon.

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The standard cell potential at 25°C for the given redox reaction is 0.47V.

The standard cell potential, Eo, for the given redox reaction can be calculated using the formula:

Eo = Eo(cathode) - Eo(anode)

where

Eo(cathode) is the standard reduction potential of the cathode (Cu2+ in this case) and

Eo(anode) is the standard oxidation potential of the anode (Pb in this case).

Given Eo for Cu2+(aq) + 2e ⇒ Cu(s) is 0.34V, and Eo for Pb2+(aq) + 2e- --> Pb(s) is -0.13V.

Substituting these values in the formula, we get:

Eo = Eo(cathode) - Eo(anode)

= 0.34V - (-0.13V)

= 0.47V

Therefore, the standard cell potential at 25°C for the given redox reaction is 0.47V.

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the standard cell potential at 25 oC, Eo or Eocell, for the given reaction is 0.47 V

For the above reaction, the standard cell potential, Eo or Eocell, can be computed using the following formula:

Eocell is defined as Eored(cathode) - Eored(anode)

Cu2+(aq) + 2e- --> Cu(s) is the standard reduction potential of the cathode, while Pb2+(aq) + 2e- --> Pb(s) is the standard reduction potential of the anode.

Inputting the values provided yields:

Eocell is defined as Eored(cathode) - Eored(anode)

Eocell = 0.34 V − (-0.13 V)

Eocell = 0.47 V

Therefore, 0.47 V at 25 oC is the standard cell potential, also known as Eo or Eocell, for the reaction in question.

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The rate at which a gas with a molar mass of 100 would diffuse under the same conditions is approximately 93.75 mL/min.

The rate of diffusion of a gas is inversely proportional to the square root of its molar mass, according to Graham's Law of Diffusion. Therefore, we can use Graham's Law to determine the rate at which a gas with a molar mass of 100 would diffuse under the same conditions.

Graham's Law states that the ratio of the rates of diffusion of two gases is equal to the square root of the ratio of their molar masses. In this case, we can set up the following equation:

(rate of methane) / (rate of unknown gas) = sqrt(molar mass of unknown gas / molar mass of methane)

Substituting the given values into the equation, we have:

(30 mL/min) / (rate of unknown gas) = sqrt(16 g/mol / 100 g/mol)

Simplifying the equation, we find:

(rate of unknown gas) = (30 mL/min) * sqrt(100 g/mol / 16 g/mol)

Calculating the expression on the right-hand side, we get:

(rate of unknown gas) = (30 mL/min) * sqrt(6.25)

Therefore, the rate at which a gas with a molar mass of 100 would diffuse under the same conditions is approximately 93.75 mL/min.

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Answer:

It reacts by fizzing and wearing away/dissolving the rock.

Explanation:

Answer: A molecule of hydrochloric acid, for example, is composed of a hydrogen atom and a chlorine atom. When these molecules dissolve into water, they separate into a positively charged hydrogen ion and a negatively charged chlorine ion. ... Only some of the molecules of weak acids disassociate when added to water.

Explanation:

We must take into account the suggested mechanism mentioned in your previous mail in order to anticipate the rate equation for the reaction between chlorine atoms (Cl) and ozone (O3):

ClO + O3 Cl + 2O2 (rapid step), step 1.

Step 2 (slow step): ClO + Cl Cl2 + O2.

The whole response can be expressed as follows:

2O3 → 3O2

By taking into account the rate-determining step, which is the slowest step in the suggested mechanism, we may formulate the rate equation for the total reaction. It is Step 2 in this instance:

Rate = k[ClO][Cl]

Where:

k is the rate constant for the reaction

[ClO] is the concentration of ClO

[Cl] is the concentration of Cl

Rate = k[ClO][Cl]

Where: [ClO] is the concentration of ClO [Cl] is the concentration of Cl, and k is the reaction's rate constant

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1) balanced chemical equation

\(2\ C_{4}H_{10}_{(g)}\ +\ 13\ O_{2}_{(g)}\ ->\ 10\ H_{2}O_{(g)}\ +\ 8\ CO_{2}_{(g)}\)

2) convert mass of CO₂ to moles

\(=71.9g\ CO_{2}\ x\ \frac{1\ mol\ CO_{2}}{44.01g\ CO_{2}} \\\\=1.633719609\)

3) multiply by molar ratio

\(=1.633719609\ mol\ CO_{2}\ x\ \frac{2\ mol\ C_{4}H_{10}}{8\ mol\ CO_{2}}\\\\=0.4084299023\)

4) convert moles of C₄H₁₀ to mass

\(=0.4084299023\ mol\ C_{4}H_{10}\ x\ \frac{58.14g\ C_{4}H_{10}}{1\ mol\ C_{4}H_{10}}\\\\=23.74611452\)

= 23.7 grams of C₄H₁₀ is needed to produce 71.9 grams of CO₂

Answer:

here hope it helps

Explanation:

covalent bonds

The statement "Cross interactions between components of a mixture are represented by the ideal mixture model." is False.

The ideal mixture model represents interactions between components of a mixture as zero. According to the ideal mixture model, the energy of a mixture of gases is determined entirely by the kinetic energy of the individual molecules in the mixture.

A binary solution is a mixture of two pure components. An ideal solution is one in which the behavior of each component is ideal, implying that the intermolecular forces between the different molecules are identical, as are the intermolecular forces between the like molecules. In this case, the interactions between the molecules in the solution would be identical to the interactions between the molecules in the pure liquids.

The model that represents cross interactions between components of a mixture is the non-ideal mixture model. Non-ideal mixtures are mixtures in which the intermolecular forces between the components vary from one component to the next.

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The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.

The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):

E = V * Q

Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):

Q = E / V

Substituting the given values, we have:

Q = 64 MJ / 330 V

To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:

Q = (64 * 10^6 J) / 330 V

Calculating the division:

Q ≈ 193,939.39 Coulombs

Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.

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Answer:

Explanation:

If you look at an atom as a whole, it is electrically neutral and possesses no overall charge.  The nucleus consists of Protons and neutrons, Protons have a positive charge and neutrons have no charge on them.

Hence, the nucleus of an atom is positively charged and is generally surrounded by one or more electrons.

The electrons on the other hand have a negative charge on them.  

The sign convention for proton (+1), neutron(0) and electron(-1). The nucleus is very heavy but is very small compared to the overall size of an atom.            

An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. The positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. I hope this helped.