What are polymers?Group of answer choicesIt synthesizes cholesterolA type of functional groupMolecules containing repeated unitsIonic compound

Answer:

c) H2O and HSO4-

Explanation:

The dehydration of 2-methylcyclohexanol occurs in the presence of H2SO4. Recall that acids are proton donors in solution; the equilibrium shown below is then set up,

H2SO4(aq)  +  H2O(l) ⇄H3O^+(aq) + HSO4^-(aq)

The species H2O and HSO4- are two proton acceptors in the system. According to the Brownstead- Lowry definition, a base is a proton acceptor in solution.

Hence H2O and HSO4- are bases present in the dehydration of 2-methylcyclohexanol.

Answer:If you are sedentary (little or no exercise) : Calorie-Calculation = BMR x 1.2.

If you are lightly active (light exercise/sports 1-3 days/week) : Calorie-Calculation = BMR x 1.375.

Explanation:

Answer:

V = 364500 L, 476.748 yard³

Explanation:

Given that,

The dimensions of a room are 10 meters wide by 15 meters long and 8.0 ft high.

l = 10 m, b = 15 m, h = 8 ft = 2.43 m

The volume of the room is :

V = lbh

So,

V = 10×15×2.43

V = 364.5 m³

As 1 m³ = 1000 L

364.5 m³ = 364500 L

Also, 1 m³ = 1.30795 yard³

364.5 m³ = 476.748 yard³

Hence, this is the required solution.

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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Changes or mutations in genes can lead to changes in proteins through their impact on the genetic code and subsequent protein synthesis.

Genes carry the instructions necessary for the production of proteins, which are essential for various cellular functions. Mutations can occur spontaneously or due to factors such as environmental exposures, errors during DNA replication, or genetic predispositions.

Mutations can take various forms. Substitution mutations involve the replacement of a single nucleotide base with another, potentially altering the codon sequence in the gene. This change can result in the incorporation of a different amino acid during translation, leading to an altered protein structure and function.

Insertion or deletion mutations involve the addition or removal of nucleotides in the gene sequence. These mutations can disrupt the reading frame, causing a shift in the codon sequence downstream. As a consequence, the resulting protein can have an entirely different amino acid sequence, often resulting in a non-functional or severely impaired protein.

Mutations in regulatory regions of genes can also impact protein production. These regions control gene expression by influencing the binding of transcription factors. Alterations in these regulatory elements can lead to changes in the amount of protein produced, affecting cellular processes.

Overall, mutations in genes can result in changes to proteins by modifying the genetic code. These changes can affect protein structure, function, stability, and interaction with other molecules, ultimately impacting cellular processes, development, and disease susceptibility.

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The moles of Cl₂(g) will be present at equilibrium is 3.94 × 10⁻⁴ mol

To determine the number of moles of Cl₂(g) at equilibrium, we need to use the given equilibrium constant (Kₑ) and the initial concentrations of CO(g) and COCl₂(g).

Given:

[CO(g)] = 0.3500 mol

[COCl₂(g)] = 0.05500 mol

Kₑ = 1.2 × 10²

The balanced equation for the reaction is:

CO(g) + Cl₂(g) ⇌ COCl₂(g)

Let's denote the number of moles of Cl₂(g) at equilibrium as x. At the start, we have [Cl₂(g)] = 0 mol, but it will change by x at equilibrium.

Using the equilibrium expression, we can write:

Kₑ = [COCl₂(g)] / ([CO(g)] * [Cl₂(g)])

Plugging in the values:

1.2 × 10² = [COCl₂(g)] / (0.3500 * [Cl₂(g)])

To solve for [Cl₂(g)], we need to isolate it on one side of the equation:

[Cl₂(g)] = [COCl₂(g)] / (0.3500 * Kₑ)

Now, let's substitute the given values:

[Cl₂(g)] = 0.05500 / (0.3500 * 1.2 × 10²)

[Cl₂(g)] ≈ 3.94 × 10⁻⁴ mol

Therefore, approximately 3.94 × 10⁻⁴ moles of Cl₂(g) will be present at equilibrium.

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The question was Incomplete, Find the full content below:

Starting with 0.3500 mol CO(g) and 0.05500 mol COCl₂(g) in a 3.050-L flask at 668 K, how many moles of Cl₂(g) will be present at equilibrium

CO(g) + Cl₂(g) ⇄ COCl₂(g)  Ke 1.2 x 10^{2} at 668 K

Answer:

The moon is required to make a wave.

The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as

molar mass=33.29g

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Therefore

n=(0.50)(15.)/0.082*623

n=0.147mol

Hence for clorine

n=0.441mol

Given the reaction

Kr+2cl2---->KrCL4

Hence

molar mass=225.60*0.147

molar mass=33.29g

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The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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Answer:

the total number of protons and neutrons in a nucleus.

The mass number, also called atomic mass number or nucleon number, is the total number of protons and neutrons in an atomic nucleus. It is approximately equal to the atomic mass of the atom expressed in atomic mass units.

Jonathon's experiment produced 24.5 grams of Al(OH), which is less than the predicted amount of 26.0 grams of AKOH. The discrepancy could be due to measurement errors, incomplete reaction.

What is discrepancy?

To determine the cause of the discrepancy, Jonathon should first review his experimental procedure and make sure that all measurements and calculations were performed accurately. He should also check that the reactants were mixed thoroughly and that the reaction was allowed to proceed to completion. If any errors or inconsistencies are identified, Jonathon should correct them and repeat the experiment to obtain more accurate results.

If the experimental procedure was carried out correctly and the discrepancy cannot be attributed to measurement errors, Jonathon should consider the possibility of impurities in the reactants. Even small amounts of impurities can affect the outcome of a chemical reaction, so it is important to use high-quality, pure chemicals in experiments whenever possible.

Overall, the most important thing for Jonathon to do in this situation is to carefully review his experimental data and methodology, and to identify any potential sources of error or uncertainty. By doing so, he can improve the accuracy and reliability of his results and draw more meaningful conclusions from his experiment.

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Explanation:

First write down the basic chemical equation with the reactants and products,

\(\text{P}_4+\text{ Cl}_2\to\text{ PCl}_3\)

Balancing the chemical equation*,

\(\text{P}_4 (s) + 6 \text{Cl}_2 (g) \to 4 \text{PCl}_3 (l)\)

\(\color{blue}\text{Note: To balance any chemical equations, we should ensure the number of atoms of each elements are the same on both the product and reactant side.}\)

\(\color{blue}\text{The phosphorous molecule has 4 P, but the }\text{PCl}_3\text{ molecule on the product side only has one P atom. Therefore, we need 4 }\text{PCl}_3\text{ molecules to balance.}\)

\(\color{blue}\text{But that will mean we have }4\cdot 3=12\text{Cl atoms on the product side. So we need 6 }\text{Cl}_2 \text{ molecules on the reactant side.} \)

Answer:

Explanation:

Iron(III) oxide gets mixed with elemental carbon and heated to make elemental iron and carbon dioxide.

2Fe₂O₃   +    3C    =    4 Fe   +    3 CO₂

2 x 160       3 x 12       4 x 56

320 gram of iron ( iii ) oxide requires 36 g of carbon for reduction

1 kg of iron will require 36 / 320 g of carbon

carbon required = 36 / 320 g

= .1125 g

= .113 g rounding off to 3 significant fig .

b )

320 gram of iron ( iii ) oxide produces  224  g of iron  after  reduction

1 g of iron will produce 224 / 320 g of iron

iron produced = 224 / 320 g

= 0.700 g .

Answer:

4.285714286

Explanation:

15lb divided by 3.5 months

Claim 1: Yes, there probably will be a lunar eclipse of the moon of Kepler-47c during a year.

Claim 2: No, there probably won't be a lunar eclipse of the moon of Kepler-47c during a year.

Kepler-47c is a moon orbiting Kepler-47 AB, a binary star system. This implies that the moon's light varies on a regular basis as it circles the two stars. These changes in light might result in a lunar eclipse.

Lunar eclipses occur when the moon passes through the Earth's shadow. While Kepler-47c circles two stars, it is still subject to Earth's gravitational pull and may pass into its shadow.

Lunar eclipses occur on a regular basis, with two to four eclipses occurring on average per year. Given the frequency of lunar eclipses, Kepler-47c is likely to see at least one lunar eclipse every year.

Evidence to support this claim 2:

Lunar eclipses occur when the moon passes through the Earth's shadow. While Kepler-47c is in the Earth's gravitational field, it is not on the same orbital plane as the Earth.

While Kepler-47c circles two stars, its orbit is not known to be stable. Variations in Kepler-47c's orbit may reduce the likelihood of a lunar eclipse.

While lunar eclipses are common, they are not uniformly distributed throughout the year. The locations and motions of the Earth, moon, and sun govern the timing and frequency of lunar eclipses.

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1234567891011121314151617181920

Answer:

a) ²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b) the Q-value of this reaction is 5.789 MeV

c) the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

Explanation:

a)

The decay equation for the alpha decay is expressed as;

²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b)

Calculate the Q-value (in MeV) of this reaction.

Q = Mparent - Mdaughter -Mg

Q = MRa - MRn -Mg

= 224.020202 - 220.011384 - 4.00260305

= 0.00621495 amu

= 5.789 MeV

therefore the Q-value of this reaction is 5.789 MeV

c)

Energy of alpha particle is expressed as;

E∝ = MQ / ( m + M)

now this is the maximum energy available for the daughter, ²²⁰Rn going to the ground state;

The energy of the alpha particle gives;

E∝  = 220(5.789) / ( 4 + 220) = 5.69 MeV

as given in the question,The other less frequent alpha occurring 5.5% of the time leaves the daughter nucleus in an excited state of 0.241 MeV above the ground state.

Therefore the energy of this alpha is

E∝ = 5.69 - 0.241 = 5.449 Mev

Therefore the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

d)

Sketch of the nuclear decay scheme have been uploaded along side this answer.

(a)\(^{224}Ra_{_{88}}=^4\alpha_{_2}+^{220}Rn_{_{86}}+Q\)

(b) the Q-value of the reaction is 5.789 MeV

(c) The alpha particles have energies of 5.69 MeV and 5.449 MeV

(a) The alpha decay of the radioisotope 224Ra is given by:

         \(^{224}Ra_{_{88}}=^4\alpha_{_2}+^{220}Rn_{_{86}}+Q\)

(b) The Q-value  of a reaction is given by:

Q = {mas of reactants - mass of products}c²

\(Q = [M_{224Ra} - M_{\alpha} - M_{220Rn}]c^2\)

Q = (224.020202 - 220.011384 - 4.00260305) amu.c²

Q = 0.00621495 × 931.5 MeV   ( since 1 amu.c² = 931.5 MeV)

Q = 5.789 MeV

(c) The energy of the alpha particle is expressed as;

E(α) = MQ / ( m + M)

it is the maximum energy available for the daughter nucleus, ²²⁰Rn going to the ground state.

If the daughter nucleus is at rest then all the energy is carried by the alpha particle.

The energy of the alpha particle is:

E(α)  = 220(5.789) / ( 4 + 220) = 5.69 MeV

Now, for the alpha particle occurring 5.5% of the time and leaving the daughter nucleus in an excited state of 0.241 MeV :

The energy of this alpha particle is

E(α) = 5.69 - 0.241 = 5.449 Mev

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The correct answer is B) the size of an orbital.

The n quantum number, also known as the principal quantum number, is an integer value that determines the energy level and size of an orbital in an atom. The value of n ranges from 1 to infinity, with higher values of n corresponding to higher energy levels and larger orbitals.

The size of an orbital is determined by the distance between the electron and the nucleus. As the value of n increases, the distance between the electron and the nucleus increases, and the size of the orbital increases as well. This means that orbitals with higher values of n have more volume and can hold more electrons.

The other quantum numbers are associated with other properties of the electron orbitals. The l quantum number is associated with the shape of an orbital, the m quantum number is associated with the orientation of an orbital in space, and the spin quantum number is associated with the spin of an electron.

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A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.

Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.

Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.

Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.

Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.

The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.

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\(\\ \sf\longmapsto 9.63\times 10^{-2}m=9.63\times 10^{-2}\times 10^{-9}m=0.0963\times 10^{-9}m=0.0963nm\)

\(\\ \sf\longmapsto 6.02\times 10^3ks=6.03\times 10^6s\)

\(\\ \sf\longmapsto 8.9\times 10^8\mu g=8.9\times 10^4cg\)

\(\\ \sf\longmapsto 4.12\times 10^{-4}Mg=4.12\times 10^{-1}g=0.412g\)

\(\\ \sf\longmapsto 7.33\times 10^{-2}Tl=7.33\times 10dL=73.3dL\)

\(\\ \sf\longmapsto 0.73kL=0.73(1000)L=730L\)

\(\\ \sf\longmapsto 5.93cm^3=0.00000593m^3\)

\(⇒9.63 \times {10}^{ - 2} m = 9.63 \times {10}^{ - 2} \times {10}^{9} = 9.63 \times {10}^{ 7} nm \\ \)

\(⇒6.02 \times {10}^{3} ks = 6.02 \times {10}^{3} \times {10}^{3} = 6.02 \times {10}^{6} s \\ \)

\(⇒8.9 \times {10}^{8} \mu g = 8.9 \times {10}^{8} \times {10}^{ - 4} = 8.9 \times {10}^{4}cg \\ \)

\(⇒4.12 \times {10}^{ - 4} mg = 4.12 \times {10}^{ - 4} \times {10}^{3} = 4.12 \times {10}^{ - 1}g \\ \)

\(⇒7.33 \times {10}^{ - 2} TL = 7.33 \times {10}^{ - 2} \times {10}^{13} = 7.33 \times {10}^{ 11} dL\\ \)

\(⇒0.73kL = 0.73 \times {10}^{3} = 730L\)

\(⇒5.93cm {}^{3} = 5.93 \times 10 {}^{6} = 5.93 \times 10 {}^{6}m {}^{3} \\ \)

\(⇒498.82cg = 498.82 \: \times 10 = 4988.2 \: cg \\ \)

Answer:2

Explanation: Acids do indeed conduct electricity (Love the one peice pfp btw)

Answer:

1.E25 it is the answer the answer to mass of 1×10^25 molecules of water​

Explanation:

this is just EXPLINATION find your answer using this

first divide the number of molecules by Avogadro's number 6.022*10^25

you will

l get no. of Moles of water

multiply the no. of Moles with mass of 1 Mole of water 18g per mole

if get answer you comment

you should try on your own you will understand better

The concept VSEPR theory is mainly based on the arrangement of electron groups. This theory is generally used to predict the geometry of the molecules.

The Valence shell electron pair repulsion theory is based on the assumption that valence shell electron pairs repel each other and are oriented in space as far apart as possible to minimize mutual repulsion.

Each group around the central atom is designated as a bonding pair or non-bonding pair. For example BeF₂ is a two electron group in which the number of bond pairs on the central 'Be' atom is two.

Similarly the molecule BCl₃ is a three electron group, the number of electron pairs on the 'Be' atom is 3.

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Based on the data shown in the graph, the rate of reaction is directly proportional to the temperature of a reaction.

The speed at which a chemical reaction occurs is called the reaction rate or rate of reaction. The rate of a reaction is proportional to the increase in product concentration per unit time and the decrease in reactant concentration per unit time.

The rate of a reaction is affected by the following:

the temperature of the reaction - the rate of reaction is directly proportional to the temperature of a reaction. Hence, the rate of a reaction increases with an increase in temperature.

presence of a catalyst - the rate of a reaction increases with the addition of a catalyst. A catalyst speeds up the rate of a reaction.

the surface area of the reactants - the rate of a reaction increases with an increase in the surface area of the reactants,

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Answer:

At higher temperatures, chemical reactions occur more quickly.

Explanation:

edmentum

Answer:

International Union of Pure and Applied Chemistry (IUPAC) justified ways how to name organic compounds [ hydrocarbons ].

Oxygen has only a molecular name which is dioxide

\( \huge \mathrm{Answer࿐ }\)

The formation of Ionic bond involves Transfer of electrons.

Correct answer is A.) transfer of electrons

_____________________________

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2.5 moles of oxygen will be produced.

A stoichiometric problem can be characterized by two features: the information given in the problem and the information to be solved called the unknown. Both the given and the unknown can be reactants, both products, or one can be a reactant and the other a product. Quantities of substances can be expressed in moles. However, in laboratory situations, it is common to determine the amount of a substance by determining the mass of the substance in grams. The amount of gaseous substance can be expressed in terms of its volume. This concept focuses on the type of problem where both the given quantity and the unknown quantity are expressed in moles.

The molar ratio is a conversion factor that relates the molar amounts of any two substances in a chemical reaction. The numerical value of the conversion factor is obtained from the coefficients of the balanced chemical equation.

For the given reaction:

2H₂O₂ → 2H₂O + O₂

This reaction indicates that the mole ratio of H₂O₂ to O₂ is 2:1 i.e. for every two moles of H₂O₂ one mole of O₂ is produced.

So, for 5.0 moles of hydrogen peroxide, moles of oxygen will be half of 5.0, which is 2.5 moles.

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Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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