Answer:
The definition of atom: The Atom is the basic unit of matter.
Types of atoms: There are 3 types of atoms, protons, neutrons, and electrons.
Some commercially available algaecides for swimming pools claim to contain 7% copper. Could the method used in this experiment to analyze for the amount of copper be adapted to determine if the 7% copper claim is correct on a 25 mL sample of algaecide? Explain in detail and include mention of any additional information that would be needed to answer this question
Answer:
Explanation:
7% copper implies 7 w/v%(weight/volume %) of copper. This implies a 100 mL algaecide arrangement contains 7 grams of copper. Henceforth we have a thought of the measure of copper that ought to be available in a given example of algaecide. Indeed, even a 1 mL algaecide test is sufficient to discover the percentage of copper in it. so a 25mL sample of algaecide must have around 1.75g of copper.A fiber reinforced-epoxy composite has an upper Young’s Modulus of Ec = 11.5 GN/m2. Calculate the volume fraction of the fibers (Vf) if the fiber Young’s modulus is Ef = 80 GN/m2 and the epoxy Young’s modulus is Em = 5GN/m2.
The volume fraction of the fibers (\(V_f\)) in the fiber-reinforced epoxy composite is approximately 8.67%.
The volume fraction of the fibers (\(V_f\)) in the fiber-reinforced epoxy composite can be calculated using the rule of mixtures. The equation for the overall Young's Modulus (E) of the composite is given by:
\(\[ E = V_f \cdot E_f + (1 - V_f) \cdot E_m \]\)
Given:
\(\( E_c = 11.5 \, \text{GN/m}^2 \)\)(upper Young's Modulus of the composite)
\(\( E_f = 80 \, \text{GN/m}^2 \)\)(Young's Modulus of the fibers)
\(\( E_m = 5 \, \text{GN/m}^2 \)\) (Young's Modulus of the epoxy)
We can rearrange the equation to solve for (\(V_f\)):
\(\[ 11.5 \, \text{GN/m}^2 = V_f \cdot 80 \, \text{GN/m}^2 + (1 - V_f) \cdot 5 \, \text{GN/m}^2 \]\)
\(\[ 11.5 \, \text{GN/m}^2 = 80 V_f \, \text{GN/m}^2 + 5 \, \text{GN/m}^2 - 5 V_f \, \text{GN/m}^2 \]\)
\(\[ 6.5 \, \text{GN/m}^2 = 75 V_f \, \text{GN/m}^2 \]\)
\(\[ V_f = \frac{6.5 \, \text{GN/m}^2}{75 \, \text{GN/m}^2} \]\)
\(\[ V_f \approx 0.0867 \text{ or } 8.67\% \]\)
By determining the volume fraction of the fibers, we can better understand the composition and properties of the composite material. This information is crucial in designing and optimizing composite structures for specific applications, as it allows for tailoring the mechanical properties based on the desired performance requirements.
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2. What element is steel mainly
composed of?
A Iron
B. Carbon
C. Manganese
D. Silver
Answer:
Carbon
Explanation:
Steel is an alloy of iron and carbon. Stainless steels are steels containing at least 10.5% chromium, less than 1.2% carbon and other alloying elements
Answer: B
Explanation:Steel is an alloy of iron and carbon.
show that the following language is decidable: {〈g〉 : g is a cfg and there exists a string that is in l(g) and has at least one a terminal} hint: modify the algorithm for ecfg
The language is decidable.
{〈g〉 : g is a CFG and there exists a string that is in L(G) and has at least one a terminal}.
algorithm to decide the language:
Given: Language is
{〈g〉 : g is a CFG and there exists a string that is in L(G) and has at least one a terminal}.
We need to show that the language is decidable. Let L be a context-free language generated by a CFG
G = (V, T, P, S).
We have to decide whether there exists at least one string in L which contains at least one 'a' terminal. Let S1 be a new start symbol with a production rule of the form S1 → S. We can add a new terminal symbol 'b' which is not present in the original grammar. We can also add new production rules as follows:
S1 → S|bS → a|b|Sa|SS|AS|BBSS → a|b|Sa|SS|AS|BBAS → a|b|Sa|SS|AS|BBBB → a|b|Sa|SS|AS|BB|ε
The following is the algorithm to decide the language.
1. Input: Context-free grammar G.
2. Construct a new grammar G' from G using the above production rules.
3. Construct the CYK table for all strings of length 1 to n, where n is the length of the longest string in the grammar.
4. If there exists a cell in the CYK table such that it contains S1 and a terminal 'a', then the language generated by G contains at least one string which has at least one 'a' terminal. Otherwise, the language generated by G does not contain any string which has at least one 'a' terminal.
5. Halt.
The language is decidable.
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what food has monosaccharides starches but no proteins or lipids
Answer:
Pasta contains all of these different carbohydrates in varying proportions.
Explanation:
Calculate the ph of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions.
The pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.
What is pH?pH is defined as the concentration of the hydrogen bond which is released or gained by the species in the solution which depicts the acidity and basicity of the solution.
What is pOH?pOH is defined as the concentration of the hydronium ion present in solution.
pOH value is inversely proportional to the value of pH.
pH value increases, pOH value decreases and vice versa.
Given,
Total H+ ions = 2.95 ×10^(-12)M
Calculation of pHpH = -log[H+]
By substituting the value of H+ ion in given equation
= log(2.95× 10^(-12) )
= 13.5
Thus we find that the pH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions is 13.5.
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A rock has a mass of 40 grams. When analyzed the rock is found to contain 10 grams of a radioactive material and 30 grams of a stable product. How many half-lives old is the rock?
please explain too :) i will give brainliest
Answer:
Explanation:
The half-life of a radioactive material is the time it takes for half of the material to decay. We can use this fact to determine how many half-lives old the rock is.
First, we need to find out how much of the radioactive material is left in the rock. We know that the rock has a mass of 40 grams, and 10 grams of that mass is the radioactive material. If we assume that all of the decay products (the stable product) are still in the rock, then the remaining mass of the radioactive material is:
10 grams * (1/2)^(number of half-lives)
where the factor (1/2) represents the fraction of the radioactive material that decays in each half-life.
We can rewrite this equation as:
(10 grams)/(40 grams) = (1/2)^(number of half-lives)
Solving for the number of half-lives, we get:
number of half-lives = log2(10/40) = log2(0.25) ≈ -2
This means that the rock is about 2 half-lives old. Since we can't have a negative number of half-lives, we can say that the rock is about 2 half-lives old or approximately 2 times the half-life of the radioactive material.
Answer:
The radioactive material in the rock undergoes radioactive decay, meaning that it spontaneously decays over time, transforming into another element and releasing radiation. The rate of decay is measured by the half-life, which is the amount of time it takes for half of the radioactive material to decay.
Since the rock contains 10 grams of radioactive material and 30 grams of stable product, we know that it originally contained a total of 40 grams of material. This means that half of the original material has decayed, since 20 grams of radioactive material would have decayed into 10 grams of stable product.
Since we know that one half-life has passed, we can use the formula N = N0(1/2)^(t/t1/2) to solve for t, the time that has passed in terms of the half-life. Here, N is the current amount of radioactive material, N0 is the original amount, t is the time that has passed, and t1/2 is the half-life.
Plugging in the values we know, we get:
10 = 40(1/2)^(t/t1/2)
Simplifying, we get:
1/4 = (1/2)^(t/t1/2)
Taking the logarithm of both sides, we get:
log(1/4) = (t/t1/2)log(1/2)
Solving for t/t1/2, we get:
t/t1/2 = log(1/4)/log(1/2) = 2
So, the rock is two half-lives old.
50 pts don't dare to answer wrong or just write irrelevant.
answer must be with explanation. would mark brainliest.
Answer/Explanation:
Part 1 and 3: Test tube 4. The hot water and Acid added to the substance makes it much more reactive, which is the reason why the new substance is bubbling. Hot water allows the particles in a chemical reaction have enough force and more chances to go through actual reaction process. This also caused it to create the most bubbles.
Part 2 and 4: Test tube 1 had the least amount of chemical reactivity. Cold water slows down the amount of times a particle in the substance hits another. This reduces the chance of it reacting and the strength of it's reaction. Test tube 1 was also missing the citric acid. Since acids have low pH it is very reactive with other particles with substances that contain less than 8 valence electrons. Without the acid it doesn't have ad much urge to react with. The lower the pH the better reactivity.
the pka of lactic acid is 3.86. what is the ph of a buffer in which the lactic acid and sodium lactate have equimolar concentration?
The pH of the buffer in which the lactic acid and sodium lactate have equimolar concentration is equal to the pKa of lactic acid, which is 3.86.
How to solve for the pHThe acid dissociation constant for lactic acid is given as pKa = 3.86, so Ka can be calculated as:
Ka = 10^(-pKa) = 10^(-3.86) = 1.87 x 10^(-4)
Substituting these values into the Henderson-Hasselbalch equation, we get:
pH = pKa + log([base]/[acid])
pH = 3.86 + log(x/x)
pH = 3.86
Therefore, the pH of the buffer in which the lactic acid and sodium lactate have equimolar concentration is equal to the pKa of lactic acid, which is 3.86.
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How many moles of SiO2 are in 15.5g
The number of moles in 15.5g of silicon dioxide is 0.258moles.
How to calculate number of moles?The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
moles = mass ÷ molar mass
Moles is the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities.
Molar mass of silicon dioxide is 60.08 g/mol
moles = 15.5g ÷ 60.08g/mol
moles = 0.258moles
Therefore, 0.258moles is the amount of moles in 15.5g of silicon dioxide.
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oli is studying a reversible reaction of 2S= T + U which is process in a CSTR. The input rate for feed is 100 cfh (with Cso=1.5 lbmol/ft3). The k for forward reaction is 10 and the ke=16. The required equilibrium conversion is 80%.
Other information:
CT=CU= ½(1.5-CS)
-rS=k[(Cs)2 – 0.25(1.5-Cs)2/ke]
a.) What do you think is the reactor size?
b.) how may reactor should be for it to be arranged in series, If we design an arrangement of vessels having 1/10 the size?
a) The volume of the reactor V0 using the mass balance equation and then use the rate of reaction equation to calculate the reactor size is 66.67 ft³ b) 10 reactors are required for the process to be arranged in series.
Given information:
Rate of feed =100 cfh
Cso=1.5 lbmol/ft³
Forward reaction rate, k=10
Equilibrium constant, Ke=16
Equilibrium conversion= 80%
CT=CU= ½(1.5-CS)
-rS=k[(Cs)² – 0.25(1.5-Cs)²/ke]a) Reactor size calculation:
Let’s use the mass balance equation for the process taking place in the Continuous Stirred Tank Reactor,
Therefore, F = V_0 (C_s)_o
Where, F is the flow rate
V_0 is the volume of the reactor(C_s)_o is the concentration of the reactant initially
This is a reversible reaction that occurs in a Continuous Stirred Tank Reactor or a CSTR. It follows the reaction equation of 2S ⇆ T+U .
Using equilibrium data, we know that the required conversion is 80%. That is, Xeq=0.8Using the equilibrium data equation, we can relate the concentrations of T, U, and S as follows:
[T][U]/[S]²= Ke=16Where,[T], [U] and [S] are the molar concentration of the respective species.
Now, let's use the rate equation for the forward reaction to relate the concentration of S to the rate of the reaction.-r_S=k[(C_S)²-0.25(1.5-C_S)²/Ke]
Now, applying the steady-state assumption, dC_S/dt=0, and considering the fact that CT=CU=0.5(1.5-CS), we can substitute (C_S) with C_T and simplify the rate equation.-r_S=k[((C_T)²-0.25(1.5-C_T)²/Ke)]
Now we can calculate the rate of reaction from the rate equation.
-r_S=k[((C_T)²-0.25(1.5-C_T)²/Ke)]=k[((0.5(1.5-C_T))²-0.25(1.5-0.5(1.5-C_T))²/Ke)]
We can find the volume of the reactor V0 using the mass balance equation and then use the rate of reaction equation to calculate the reactor size.
Therefore,V0=F/(C_S)_o=100/(1.5)=66.67 ft³
So, the reactor size is 66.67 ft³.b) For a given feed rate and the size of the reactors, we can calculate the number of reactors required for the process to be arranged in series using the following equation: N=V1/V2
where, V1 and V2 are the volumes of the reactor in the series.
So, if we want to design an arrangement of vessels having 1/10 the size, we can calculate the size of each reactor in the series.V2=V1/10=6.667 ft³
Now, we can find the number of reactors using the equation: N=V1/V2=66.67/6.667=10
Thus, 10 reactors are required for the process to be arranged in series.
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During a phase change, the addition of thermal energy will result in the temperature of a substance (increasing / remaining constant) as the electrostatic forces of the particles are overcome
Answer:
During a phase change, the addition of thermal energy will result in the temperature of a substance remaining constant as the electrostatic forces of the particles are overcome.
Phase changes occur when a substance changes from one state of matter to another, such as from a solid to a liquid or from a liquid to a gas. During a phase change, the thermal energy being added to the substance is used to overcome the electrostatic forces that hold the particles together, rather than being used to increase the kinetic energy of the particles. As a result, the temperature of the substance remains constant until the phase change is complete.
For example, when a solid is being melted into a liquid, the thermal energy being added is used to break the bonds between the particles in the solid. As a result, the temperature of the solid remains constant until all of the bonds have been broken and the substance has completely melted. Similarly, when a liquid is being vaporized into a gas, the thermal energy being added is used to overcome the attractive forces between the particles in the liquid, resulting in a constant temperature until the phase change is complete.
Explanation:
mark brainliest please
What type of contamination do peroxides produce?
Answer:
The main hazard related to organic peroxides are their fire and explosion hazards. ... It is the double oxygen of the "peroxy" group that makes organic peroxides both useful and hazardous. The peroxy group is chemically unstable. It can easily decompose, giving off heat at a rate that increases as the temperature rises.
Explanation:
What is the control in the experiment?
Answer:
C. the amount of drug x given to mice
Help .. question
In order to properly represent the reaction, the equation should be
The amounts of atoms on each side of the
sign should be equal.
\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)
Here's the complete statements ~
In order to properly represent the reaction, the equation should be Balanced
The amounts of atoms on each side of the Arrow sign should be equal.
How many liters of nitrogen would be needed to react with 93.0 liters of hydrogen using the balance
equation below:
N2 + 3H2 → 2NH3
Answer:
7NH
Explanation:
Another way to make prints visible is to apply certain chemicals. What aspect of a fingerprint chemically reacts with each of the following? a. ninhydrin b. cyanoacrylate c. silver nitrate d. iodine fuming
When iodine combines with amino acids or carbohydrates in the presence of heat, iodine fuming results.
Thus, the correct option is D.
What are carbohydrates?Numerous foods, both good and bad, contain carbohydrates, such as bread, beans, milk, popcorn, potatoes, cookies, spaghetti, soft drinks, corn, and cherry pies.
They can take on various shapes as well. Starches, fibers, and sugars are the most prevalent and plentiful types.
Your body uses carbohydrates as its primary energy source to power your kidneys, heart, brain, muscles, and central nervous system.
As an illustration, fiber is a type of carbohydrate that promotes healthy digestion, makes you feel full, and lowers blood cholesterol levels.
Sugars (such as fructose, glucose, and lactose) and starches, which are present in foods like starchy vegetables, grains, rice, breads, and cereals, are the two main types of carbs.
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State the main points of Dalton’s atomic theory. Which parts were found to be erroneous? Explain why they are
The main points of Dalton's atomic theory is Atoms are not indivisible and all atoms of an element are not identical.
What are the Postulates of Dalton's atomic theory?Atoms are the minuscule, indivisible building blocks of all stuff.
A certain element's atoms are all the same mass, size, and other characteristics. Nevertheless, the characteristics and mass of atoms from various elements varies.
Atoms are eternal and cannot be generated or destroyed. Atoms also can not be separated into smaller particles.
Compounds can be created by combining atoms of various elements in specific whole-number ratios.
In chemical reactions, atoms can be joined, separated, or rearranged.
What is the drawbacks of Dalton's atomic theory?The fact that an atom may be further divided into protons, neutrons, and electrons disproves the idea that it is indivisible. The smallest particle that participates in chemical processes is an atom, nevertheless. Dalton asserts that the atoms of the same element are identical in every way.
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a claim about arrangements of electrons and properties within a family elements
A claim about the arrangements of electrons and properties within a family of elements is described below:
elements in the same family have the same number of outermost shell electronselements in the same family have similar chemical properties due to them having the same arrangements of electronsWhat are families of elements?Families of elements refer to elements that are found in the same group in the periodic table.
Elements that belong to the same family have the same arrangement of electrons.
The families of elements are found in the vertical columns knowns as groups. They have the same physical properties because they have the same number of e; electrons in their outermost shell.
For example, elements belonging to group 1 have one valence electron and show similarity in their chemical properties.
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A sample of gas has a volume of 5.0 L and a pressure of 2.92 atm. If the final volume is 5.7 L, what is the final pressure of the gas?
Answer: 2.56140351 atm
The equation we use is Boyle's law,
P1V1 = P2V2
where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume.
To obtain the final pressure of the gas(P2), use the equation
P2 = \(\frac{P1V1}{V2}\)
so P2 = \(\frac{2.92 * 5}{5.7}\) = 2.56140351 atm.
The final pressure of the gas = 2.56140351 atm.
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After hockey practice, Carissa and Keenan were playing a game where they were pushing some objects to get them to crash. They were using a cone and two different pucks—a black one with more mass for Crash 1 and a blue one with less mass for Crash 2. They want to know what happened to the cone. Use the information from the diagram to answer. In which crash did the cone experience a stronger force? How do you know?
The crash where the cone experience a stronger force is option D because: Crash 1: the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.
Does it take a stronger force to slow something down?The ball is drawn back to Earth by gravitational force. The ball returns to Earth as a result of friction. The ball is forced back toward Earth by magnetic force.
A puck's velocity changes when a player makes contact with it when it is still. He causes the puck to speed up, in other terms. The hockey stick's force, which causes the acceleration, is responsible. The velocity grows as long as this force is in motion.
Therefore, the force applied to an object must be larger than what is required for a progressive slowing down if the object must be slowed down quickly. For instance, a bicycle's brakes will slow or stop it more quickly the more force is given to it.
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See full question below
After hockey practice, Carissa and Keenan were playing a game where they were pushing some objects to get them to crash. They were using a cone and two different pucks—a black one with more mass for Crash 1 and a blue one with less mass for Crash 2. They want to know what happened to the cone.
Use the information from the diagram to answer.
In which crash did the cone experience a stronger force? How do you know?
answer choices
There was no force on the cone. In both crashes, only the hockey puck experienced a force.
The diagram doesn’t tell you anything about the force on the cone. It only gives information about the force on the pucks.
It was the same force in both crashes; the hockey puck changed speed by the same amount in each crash, so the force on the cone was the same each time.
Crash 1; the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.
for each of the pairs given, predict which acid is stronger i) h2s and h2se ii) hbro2 and hbro3 iii) h2seo3 and hbro3
HBrO3 makes it the stronger acid.
For each of the pairs given, the stronger acid is as follows:
i) Between H2S and H2Se, H2Se is the stronger acid. This is because Se is larger and less electronegative than S, allowing for easier ionization of the hydrogen atom.
ii) Between HBrO2 and HBrO3, HBrO3 is the stronger acid. The additional oxygen atom in HBrO3 increases its acidity due to the increased electron withdrawing effect, which stabilizes the conjugate base.
iii) Between H2SeO3 and HBrO3, HBrO3 is the stronger acid. This is because Br is more electronegative than Se, and the higher oxidation state of Br in HBrO3 leads to a stronger electron withdrawing effect, enhancing acidity.To predict which acid is stronger in each pair given, we can compare the electronegativity of the central atom in each acid. The more electronegative the central atom, the stronger the acid.
i) H2S and H2Se: Se is more electronegative than S, so H2Se is the stronger acid.
ii) HBrO2 and HBrO3: Br is in the same oxidation state in both acids, but HBrO3 has one more oxygen atom which increases its electronegativity, making it the stronger acid.
iii) H2SeO3 and HBrO3: Se is again more electronegative than Br, but the effect of the additional oxygen atom in .
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for naoch3 identify each bond as polar covalent nonpolar covalent or ionic
The bond between Na and O in NaOCH3 is ionic. The bond between O and C in the molecule is polar covalent, and the bonds between C and H in the molecule are nonpolar covalent.
The NaOCH3 molecule is composed of three different types of bonds: Na-O, O-C, and C-H. The bond between sodium and oxygen is an ionic bond. Sodium is a metal and oxygen is a non-metal, and their electron configuration difference results in a transfer of electrons from sodium to oxygen. This results in the formation of sodium and oxygen ions, Na+ and O-, respectively. The O-C bond is a polar covalent bond, where the electron pair is shared between the two atoms but not equally. Oxygen is more electronegative than carbon, resulting in an uneven distribution of electrons, causing the bond to be polar. The C-H bond is a nonpolar covalent bond, as carbon and hydrogen have similar electronegativity values and thus the electron pair is shared equally between them.
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Complete question:
For NaOCH3, identify each bond as polar covalent, nonpolar covalent or ionic; NaO, OC, and CH.
a solution is made by dissolving 4.50 g of nacl in enough water to make 70.0 ml of solution. what is the concentration of sodium chloride in units of weight/volume percent?
To calculate the weight/volume percent concentration of sodium chloride in the solution, we need to determine the mass of sodium chloride and the volume of the solution.
Given to us is:
Mass of sodium chloride (NaCl) = 4.50 g
Volume of solution = 70.0 ml
First, we need to convert the volume of the solution from milliliters to liters:
Volume of solution = 70.0 ml = 70.0 ml × (1 L / 1000 ml)
Volume of solution = 0.070 L
Next, we can calculate the weight/volume percent concentration using the formula:
Weight/volume percent = (Mass of solute / Volume of solution) × 100
Plugging in the values:
Weight/volume percent = (4.50 g / 0.070 L) × 100
Weight/volume percent = 64.29%
Therefore, the concentration of sodium chloride in units of weight/volume percent is approximately 64.29%.
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1. Consider NH3.If it dissolves in water(i) NH3 + H20 + NHẤ4+ H2O(ii)NH3 + H2O → NH+3 + OH-(iii) NH3 + H2O + NH+4+ OH-(iv) NH3 + H2O → NH+4+ OH-Which represents the dissolution of NH3 in water(a) i(b) ii (c) iii (d) iv (e) iii and iv2. HOA2+H20 . → H3O+ + OA-CIn this reaction:(i) OA c is the conjugate base of H2O(ii)OA-c is the conjugate base of HOAc (iii) H3O+ is theсconjugate base of HOA.(iv) H3O+ is the conjugate acid of H2O(a) i(b) ii (c) iii (d) iv (e) none3. Arrange the following according to increasing acid strength(i) Ka= 2.5 + 10-15(ii) Ka= 9.0 + 10-9(iii) pKa= 7.5(iv) % dissociation =100(a) iv, iii, ii, i2(b) ii, I, iii, iv(c) i, iii, iv, ii(d) i, ii, iii, iv(e) iii, iv, ii, i2
1. Ammonia is a colorless gas with a chemical formula of NH3, when it comes in contact with water, it will be transformed into Ammonium ion and it will produce one hydroxide ion, and this is why Ammonia will present a more basic (pH) behavior, the reaction that represents this behavior is:
NH3 + H2O -> NH4+ + OH-
Number 4 is the only one that represents it well
Number 3 has the same reaction but since there is a plus sign instead of an arrow, I consider it wrong.
sample of gas occupies a volume of 57.4 ml . as it expands, it does 119.9 j of work on its surroundings at a constant pressure of 783 torr . what is the final volume of the gas?
The final volume of the gas is approximately 57.242 mL.
To find the final volume of the gas, we can use the equation for work done by a gas at constant pressure:
Work = -PΔV
Where:
Work is the work done by the gas on its surroundings (given as 119.9 J),
P is the pressure of the gas (given as 783 torr), and
ΔV is the change in volume.
Since the pressure is constant, we can rearrange the equation to solve for ΔV:
ΔV = -Work / P
Plugging in the values:
ΔV = -119.9 J / (783 torr)
We need to convert the pressure from torr to atm to maintain consistent units:
ΔV = -119.9 J / (783 torr * (1 atm / 760 torr))
ΔV = -0.158 L
The negative sign indicates that work is done on the gas, causing it to expand. To find the final volume, we add the change in volume to the initial volume:
Final Volume = Initial Volume + ΔV
Final Volume = 57.4 mL + (-0.158 L)
Final Volume = 57.4 mL - 0.158 mL
Final Volume = 57.242 mL
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How many electrons do carbon and oxygen share?
I-0-I
:0:
Intro
Done
oxygen has 6 valence electrons and 2 electrons and carbon has 4 electron
Answer:
4!!!!!!!!!!
Explanation:
i got it right
How many grams of HCl are present in 3 L of 0.75 M solution?
The grams of HCl are present in 3 L of 0.75 M HCl solution found to be 82g.
What is the same as molarity?
The amount of moles of a solute divided by the volume of the solution measured in litres is known as molarity. Molarity is described as follows: moles of solute/liters of solution M, or moles/liter, is the sign for molarity.
molecular mass of HCl => 36.458 g/mol
molarity = grams of HCl/molecular mass x volume
0.75 x 3 x 36.458 = grams of HCl
=> 82g
Why is molarity temperature independent?The molality of a solutions does not vary with temperature and molarity is indirectly correlated to temperature because molality is defined as a function of the mass of the solvent, not its volume. Volume rises as temperature does.
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How many grams of HCl are present in 3 L of 0.75 M HCl solution?
The property of a mineral splitting evenly along a flat surface is.
Answer:
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What is the molar concentration a a 12 % sodium chloride solution (MW 58.5)
The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.
First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.
In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.
To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.
We can start by calculating the number of moles of sodium chloride in 12 grams:
Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride
Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles
Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:
Volume of solution = mass of solution / density
Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L
Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:
Molar concentration = moles of solute / volume of solution
Molar concentration = 0.205 moles / 0.1 L = 2.05 M
Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
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