The additional power the lens must provide in order to focus clearly on an object at the standard near point (0.25 m) is 4 Diopters.
To calculate the additional power the lens must provide to focus clearly on an object at the standard near point (0.25 m), we'll use the lens power formula:
Power (P) = 1 / Focal Length (f)
In this case, we need to find the focal length required for clear focus at the standard near point (0.25 m). Since the object is at a distance of 0.25 m from the lens, the required focal length (f) is:
f = 0.25 m
Now we can plug this value into the lens power formula to find the additional power needed:
P = 1 / f
P = 1 / 0.25 m
P = 4 Diopters
So, In order to focus clearly on an object at the standard near point (0.25 m), the lens needs to have an additional 4 diopters of power.
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The additional power required to focus clearly on an object at the standard near point is: -7.11 D
The standard near point is the closest distance at which a person with normal vision can focus on an object, which is typically taken to be 25 cm or 0.25 m.
To find the additional power the lens must provide, we need to calculate the power required to focus at the near point, and then subtract the power of the lens with a focal length of 9.00 cm.
The power of a lens is given by the formula:
P = 1/f
where P is the power of the lens in diopters (D) and f is the focal length of the lens in meters.
For an object at the near point of 0.25 m, the required power is:
P = 1/0.25 = 4 D
The power of the given lens is:
P = 1/0.09 = 11.11 D
Therefore, the additional power required to focus clearly on an object at the standard near point is:
4 D - 11.11 D = -7.11 D
The negative sign indicates that the lens must be diverging, or concave, to provide the additional power required to focus at the near point.
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please help i'm going to throw up from stress
Water at 20.0 °C is mixed with 120.0 g of ethyl alcohol at 10.0 °C in a thermally insulated container. If the final mixture has a temperature of 16.0 °C, how much water was added?
No links istg
Answer:
Explanation:
First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.
120.g = .1200 kg of ethyl alcohol. Now for the formula:
\(t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})}\) where spheat is specific heat.
Filling that horrifying-looking formula in with some values:
\(16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)}\) and
\(16.0=\frac{83640x+2928}{4182x+292.8}\) and
16(4182x + 292.8) = 83640x + 2928 and
66912x + 4684.8 = 83640x + 2928 and
1756.8 = 16728x so
x = .105 kg and the amount of water added is 105 g
How long will it take a peron on a kateboard to travel 45 m and attain a peed of 7 m/ from ret ?
Here, a denotes acceleration, t denotes time, and u and v denote beginning and ultimate velocities, respectively. u = v + at.
Can you use a skateboard to travel?In carry-on luggage, skateboards are permitted. If there are any size or weight limits, please check with your airline additional forbidden itemsSkateboards that fit under seats do not need to be under bags or covers, but they must be stored with their wheels up to prevent rolling. A skateboard must be packed in a bag or have the wheels covered if it is to be stored in an overhead container (trash bag is acceptable).As the skateboarder comes to a stop, his final velocity will be zero. To calculate the value of time, replace the necessary values (t).0 m/s = 45 m/s + 7 m/s t t = 6.42 s.
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HELP PLEASE! Part 1:
Make a graph of each set of data. For the first set, plot the start location data on the x-axis and the box's average slide distance on the y-axis. For the second set of data, plot the mass of the marble on the x-axis and the average distance the box slides on the y-axis.
Four start locations were chosen for this experiment. Why was the potential energy of the marble different at each location?
What happened to the potential energy as the ball rolled down the ramp?
Why did the box slide backwards when the marble hit it?
What kind of energy did the box have as it was sliding? Where did this energy come from?
What is the relationship between the marble's starting position and the distance the box slid?
Part 2:
All the marbles started at the 40-cm mark in this experiment. Were their potential energies the same? Why or why not?
Comparing the marbles, was there any difference in the average amount that the box slid after catching the marble? What is the relationship?
Do all of the marbles have the same amount of kinetic energy at the end of the ramp?
Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.
Summarize the conclusions that you can draw from this experiment. Use the questions above to guide your ideas.
In this experiment, marbles were rolled down a ramp to determine the relationship between potential and kinetic energy and how it affects the distance a box will slide.
How did the potential energy differ?The potential energy of the marbles differed based on their starting location, with higher locations possessing more potential energy. As the marbles rolled down the ramp, their potential energy decreased while their kinetic energy increased.
When the marble hit the box, it transferred its kinetic energy to the box, causing it to slide backward. The results showed that the higher the marble's potential energy, the further the box slid.
Additionally, the larger the mass of the marble, the greater its kinetic energy and the further the box slid. Overall, the hypotheses for each experiment were confirmed by the data collected.
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HELP MEEEEEEEEE! what is the frequency corresponding to a period of 5.91 s? Answer in units of Hz
Answer:
frequency = 1/Period
= 1/5.91s
= 0.169204Hz
The figure below shows a ball on a curved surface. The ball is released at point A. At which point does the ball have maximum gravitational potential energy?
Answer:
Point A
Explanation:
Because it reaches maximum height
A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c
Answer:
We can use Coulomb's law to solve this problem:
F = k * q1 * q2 / r^2
where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.
We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:
q2 = F * r^2 / (k * q1)
Substituting the values we have:
q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)
Simplifying:
q2 = 8.65 x 10^5 C
Therefore, the magnitude of the other charge is 8.65 x 10^5 C.
A 93kg fullback, running at 8.2m/s, collided in midair with a 127 kg defensive tackle moving in the opposite direction. Both players end up with zero speed.
Answer:
Explanation:
The collision between the 93kg fullback and the 127kg defensive tackle is an example of an inelastic collision. In an inelastic collision, the total kinetic energy of the system is not conserved as some of the energy is transformed into other forms such as heat or sound. The resulting final speed of both players would be 0m/s, indicating that they have come to a stop after the collision.
What is the meaning of the word solar in the article "Fire Up the Sun"?
relating to electricity
caused by the sun
caused by heat
relating to power
Answer:
B) Caused by the Sun
Explanation:
If you look at a picture of a solar system, you will see the sun in the middle. The sun is the powerhouse of the solar system. So that means that the sun is the biggest star and can provide enough light to reach earth and keep it lit.
The meaning of the word solar in the article "Fire Up the Sun" is caused by the sun so, option B is correct.
What is sun?The sun is the star that the earth and the other planets in the solar system orbit. With more than 99 percent of the system's total mass, it is the dominant body. A portion of the tremendous quantity of energy coming from the Sun powers the light and heat that keep Earth habitable for life.
The sun is in the center of a solar system if you look at a picture of one. The solar system's center of gravity is the sun. This indicates that the sun is the largest star and that it can illuminate the earth and keep it bright.
The Sun is a G2 V star, which means that it has a surface temperature of roughly 5,800 kelvins (K), making it the second-hottest star in the yellow G class.
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When a closed loop of wire experiences a changing magnetic field a voltage and therefore current is produced. This is the basis for...
Answer: The answer is an electric generator
Explanation:
I just took the quiz and I thought it was an electric motor but the correct answer was an electric generator.
This concept of closed loop wire experiences a changing magnetic field and flowing of current is related to the Faraday's law of electromagnetic induction.
Why there is a current flow whenever there is a change in magnetic field in a closed loop of wire?When ever there is a bar magnet inside the wire and the magnet moves relative to the wire there will be an EMF generated in the coil and current can be flown.
similarly by reversing the process if the magnet remains stationary and the coil is moved then again the emf and the current generated in the coil which is called as electromagnetic induction.
This is the basic principle of transformers,generators,motors .
Thus when a closed loop of wire experiences a changing magnetic field a voltage and therefore current is produced.
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why are there so few top level consumers in massachusetts?
I don't really know the question but they either went extinct or resources, anything could happen
A bullet is fired from a rifle with an initial velocity of 300 m/s at an angle of 25 degrees from the horizontal.
1. Calculate the horizontal and vertical components of the velocity
2. Calculate the time spent in the air
3. Calculate the maximum height
4. Calculate the horizontal distance
Answer:
1. The horizontal component of the velocity is approximately 271.89 m/s
The vertical component of the velocity is approximately 126.79 m/s
2. The time the bullet spends in the air is approximately 25.85 seconds
3. The maximum height reached by the bullet is approximately 819.35 meters
4. The horizontal distance is approximately 7028.36 meters
Explanation:
The initial velocity of the bullet = 300 m/s
The angle at which the bullet was fired, θ = 25° from the horizontal
1. The horizontal component of the velocity vₓ = The component of the velocity in the x-direction
vₓ = v × cos(θ)
Substituting gives;
vₓ = 300 × cos(25°) ≈ 271.89 m/s
The vertical component of the velocity \(u_y\) = The component of the velocity in the y-direction
\(v_y\) = v × sin(θ)
Substituting gives;
\(u_y\) = 300 × sin(25°) ≈ 126.79 m/s
2. The time the bullet takes to maximum height, t = 1/2 × The time the bullet spends in the air
The following is the relevant kinematic equation for the vertical motion of the bullet;
v = u - g × t
Where;
\(v_y\) = The final velocity vertical velocity = (0 at maximum height)
\(u_y\) = The initial vertical velocity ≈ 126.79 m/s
g = The acceleration due to gravity = 9.81 m/s²
t = The time in flight of the bullet
Substituting gives;
0 = 126.79 - 9.81 × t
t ≈ 126.79/9.81 ≈ 12.924 s
The time the bullet spends in the air = 2 × The time the bullet takes to maximum height
∴ The time the bullet spends in the air ≈ 2 × 12.924 ≈ 25.85
The time the bullet spends in the air ≈ 25.85 seconds
3. The maximum height reached is given from the following kinematic equation;
\(u_y\)² = 2 × g × h
Where;
h = The maximum height reached by the bullet
∴ h = \(u_y\)²/(2 × g)
h = 126.79²/(2 × 9.81) = 819.35
The maximum height reached by the bullet = h = 819.35 meters
4. The horizontal distance travelled by the bullet = Horizontal component of the velocity of the bullet × The time the bullet spends in the air
∴ The horizontal distance travelled by the bullet = 271.89 × 25.85 ≈ 7028.36
The horizontal distance travelled by the bullet ≈ 7028.36 meters.
A linear elastic spring can be compressed 10. 0 cm by an applied force of 5. 0 N. A 4. 5
kg crate of apples, moving horizontally at 2. 0 m/s collides with the spring. What will be
the maximum compression of the spring?
The maximum compression of the spring is 0.6 m.
Spring constantThe spring constant of the spring is calculated as follows;
F = kx
k = F/x
k = (5)/(0.1)
k = 50 N/m
Maximum compression of the springThe maximum compression of the spring is calculated as follows;
U = K.E
¹/₂kx² = ¹/₂mv²
x² = (mv²)/(k)
x = √(mv²)/(k)
x = √(4.5 x 2²)/(50)
x = 0.6 m
Thus, the maximum compression of the spring is 0.6 m.
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Assume no loss of energy to friction. If a 270 kg roller coaster is 96.8 meters tall and has an initial velocity of zero, what will the velocity be at the bottom?
ANSWER
43.56 m/s
EXPLANATION
Given:
• The roller coaster's mass, m = 270 kg
,• The roller coaster's height, h = 96.8 m
,• The roller coaster's initial velocity, v₀ = 0 m/s
Unknown:
• The roller coaster's final velocity at the bottom of the hill, v
By the law of conservation of energy, the total mechanical energy of the roller coaster at the top of the hill must be equal to its total mechanical energy at the bottom. If no energy is lost to friction, then we only have gravitational potential energy and kinetic energy,
\(PE_o+KE_o=PE_f+KE_f\)The height where the roller coaster starts its motion is with respect to the bottom of the hill. This means that at the bottom of the hill, we could say that its height is zero and, therefore, it has no gravitational potential energy.
Also, we know that the roller coaster starts from rest, so its initial kinetic energy is zero. The equation above reduces to,
\(PE_o=KE_f\)Replace with the expressions for each of these kinds of energy,
\(m\cdot g\cdot h=\frac{1}{2}\cdot m\cdot v^2\)The mass is on both sides of the equality, so it cancels out,
\(g\cdot h=\frac{1}{2}v^2\)Solving for v,
\(v=\sqrt[]{2\cdot g\cdot h}\)Replace with the known values. The acceleration due to gravity is 9.8 m/s,
\(v=\sqrt[]{2\cdot9.8m/s\cdot96.8m}\approx43.56m/s\)Hence, the velocity of the roller coaster at the bottom is 43.56 m/s.
Which piece of evidence from the paage bet upport the idea that foret promote rainfall
"Planting more trees brings rain because plants transpire" is the piece of evidence from the page that support the idea that forest promote rainfall.
What is transpiration?Water is moved through a plant during transpiration, and it is evaporated from aerial parts of the plant, such as leaves, stems, and flowers. Even though plants need water to survive, only a small portion of the water absorbed by their roots is actually utilised for cellular growth and metabolism.
Transpiration and guttation cause the remaining 97-99.5% to be lost. In most plants, the undersides of the foliage have more of the tiny pores known as stomata that decorate the surface of leaves.
The guard cells that surround the stomata are responsible for opening and closing the pore, as are their stomatal accessory cells. Transpiration occurs through the stomatal apertures and is regarded as a "cost" of the stomata opening, which allows the diffusion of carbon dioxide gas from the atmosphere for photosynthesis.
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Two persons are applying forces on two opposite sides of a moving cart. The cart still moves with the same speed in the same direction. What do you infer about the magnitudes and direction of the forces applied?Explain.
Explanation:
If two persons are applying forces on two opposite sides of a moving cart and the cart still moves with the same speed in the same direction we can infer that the magnitudes of the forces applied by the two persons are equal and the direction of the forces is opposite to each other.
This is because of Newton's First Law of Motion which states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. In this case the cart is already in motion and is moving in a straight line. The forces applied by the two persons are external forces acting on the cart. Since the cart is moving with the same speed and in the same direction we can infer that the forces applied by the two persons are equal in magnitude and opposite in direction.
This is also known as the principle of action and reaction which is the third law of motion. According to this law for every action there is an equal and opposite reaction. In this case the action is the force applied by the two persons on the cart and the reaction is the force exerted by the cart on the two persons in the opposite direction.
you have been hired to design a family-friendly see-saw. your design will feature a uniform board of mass m and length l that can be moved so that the fulcrum (pivot) is a distance d from the center of the board. this will allow riders to achieve static equilibrium even if they are of different masses, which is typical. you have decided that each rider will be positioned so that his/her center of mass will be a distance xoffset from the end of the board when seated, as shown. a child, seated on the right, has mass m , and an adult, seated on the left, has a mass that is a multiple n of the mass of the child. calculate all torques relative to the position of the fulcrum, and treat counterclockwise toques as positive.
The torque due to the child's weight is nmgx_offset, and the torque due to the adult's weight is -mnmg(x_offset + d), where n is the multiple of the child's mass for the adult rider, m is the mass of the child, g is the acceleration due to gravity, x_offset is the distance of the child's center of mass from the end of the board, and d is the distance of the fulcrum from the center of the board. The total torque is the sum of these two torques.
Mass of the child (m)
Mass of the adult (n * m, where n is the multiple of the child's mass)
Acceleration due to gravity (g)
Distance of the child's center of mass from the end of the board (x_offset)
Distance of the fulcrum from the center of the board (d)
To achieve static equilibrium, the total torque acting on the see-saw must be equal to zero. The torque due to the child's weight is given by nmgx_offset, where n is the multiple of the child's mass for the adult rider, m is the mass of the child, and x_offset is the distance of the child's center of mass from the end of the board.
The negative sign in front of mnmg(x_offset + d) is because the adult is seated on the left side of the fulcrum, causing a clockwise torque. The total torque is the sum of these two torques, which must be equal to zero for static equilibrium.
Mathematically, the torque equation can be written as:
nmgx_offset - mnmg(x_offset + d) = 0
Simplifying, we get:
nmgx_offset - mnmgx_offset - mnmgd = 0
Combining like terms, we obtain:
mnmgd = nmgx_offset
Finally, solving for d, we get:
d = x_offset/n
Therefore, the distance of the fulcrum from the center of the board (d) is equal to the distance of the child's center of mass from the end of the board (x_offset) divided by the multiple of the child's mass for the adult rider (n).
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A physicist observes that a cannonball shot horizontally from a cannon travels 1.000 m before falling to the ground. Which of the following statements correctly explains this observation using Newton's laws?
O Objects tend to remain in the state of motion they are in unless acted upon by an unbalanced force. Friction and gravity acted on the cannonball, slowing it down and slamming it into the ground
O Objects at rest tend to remain in their cument state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion
The force on the cannonball produced by the cannon was less than the force of friction on the cannonball, causing the cannonball to slow down and fall to the ground.
O The force on the cannonball produced by the cannon exactly equaled the force of friction on the cannonball, balancing the forces and causing it to fall to the ground.
The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.
According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.
Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.
Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.
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An unstrained horizontal spring has a length of 0.31 m and a spring constant of 190 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.039 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.
The possible algebraic signs of the charges are both a- positive (+0.139 C) or both negative (-0.139 C)
b- magnitude of the charges is approximately 0.139 C, which is equivalent to 19.5 μC.
The calculation to determine the possible algebraic signs and magnitude of the charges:
Spring constant (k) = 190 N/m
Displacement of the spring (x) = 0.039 m
Using Hooke's Law, we can calculate the force exerted by the spring:
Force (F) = k * x
F = 190 N/m * 0.039 m
F ≈ 7.41 N
Now, using Coulomb's Law, we can determine the magnitude of the charges:
q₁ * q₂ = F * r² / k
Since the charges have equal magnitudes, we can write q₁ = q₂ = q.
q * q = 7.41 N * (0.31 m)² / 190 N/m
q² = 0.0192 C²
Taking the square root of both sides, we find:
q ≈ ± √(0.0192 C²)
q ≈ ± 0.139 C
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A rocket is launched straight up with a velocity of 7.59. What would be the velocity when it lands?
Answer:
the same as the initial launch velocity (7.59 m/s)
Explanation:
vf^2 = vi^2 + 2ad
d = displacement = 0, so vf^2 = vi^2, so vf = vi = 7.59m/s
How many tons of paper did Americans recycle in 2018? _______________. Show your work below:
Answer:
46 million tons
Explanation:
i dont know what im suppose to explain
when you stand in front of a convex mirror, the image you see is a. real and upright. b. real and inverted. c. virtual and inverted. d. real and inverted if your distance from the mirror is greater than two focal lengths. e. virtual and upright.
when you stand in front of a convex mirror, the image you see is
e. virtual and upright.
convex mirror:
A mirror that has a curved reflecting surface is said to be curved. Convex (bulging outward) or concave surfaces are both possible (recessed inward).
Convex mirrors have curved surfaces that protrude outward toward the source of light. Instead than being used to focus light, this protruding surface simply reflects it outward.
Convex mirrors include, but are not limited to, those used as calling bells, optical devices, and vehicle rear-view mirrors.
Parallel light rays strike a convex mirror, reflect outward, and move away from an imagined focal point in a straight line (F). When a ray reaches that tiny area of the surface, it still reflects at the same angle.
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Which step can ordinary people take to minimize the effects of earthquakes and volcanoes and prevent the loss of human life
The step which ordinary people can take to minimize the effects of earthquakes and volcanoes and prevent the loss of human life is through awareness and warning systems by the appropriate authorities.
What is Earthquake?This is referred to as the process which involves the sudden shaking of the ground as a result of the passage of seismic waves through Earth's rocks.
Its effect with that of volcanoes can be reduced by creating the necessary awareness and warning systems so that the citizens adopt land use practices and building codes best suited for areas prone to this type of condition.
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A charge (uniform linear density = 8.8 nC/m) lies on a string that is stretched along an x axis from x = 0 to x = 3.1 m. Determine the magnitude of the electric field at x = 5.2 m on the x axis.
Answer:
answer= 73.1256 \(i\)
Explanation:
The electric charge linear density is equal to 8.8 x\(10^{-9}\)
the length of the string is 3.1m
The magnitude of the electric field at the length of the string equal to 5.2 meters can be calculated with the formula ;
- E = λ / 4πε₀ [ \(l\) / α ( α +
Solution:
E = 8.8 x\(10^{-9}\) / 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ] \(i\)
= 1018.0995 [0.07183] \(i\)
= 73.1256 \(i\)
Anyone knows the answer to this?
It shows the graph of a car's acceleration and its asking what's the acceleration around 6 seconds and 7 seconds.
Answer:
B 7.5mph/s
Explanation:
use change in y/ change in x
which one is deposition plz help
1. Your wet hair dries after a few minutes
2. The mirror gets fogged up when you breathe on it
3. Liquid glass cools and hardens
Deposition is when a gaseous state changes to solid state by escaping liquid state. So I think it is 3. Liquid glass cools and hardens
what are the two ways in which technical debt relates to velocity
Technical debt relates to velocity in two ways: Slowing down velocity and Accelerating velocity.
Technical debt is an important concept for developers to understand, as it can directly affect the velocity of their projects. On one hand, technical debt can slow down velocity by increasing the amount of time spent on maintenance and rework, as well as by introducing complexity that can reduce productivity.
On the other hand, it can also be used to accelerate velocity, as making quick, short-term fixes can reduce the need for more in-depth refactoring and, as a result, speed up the project timeline. Ultimately, it is essential to understand how technical debt can influence velocity and be prepared to navigate the complexities it can introduce.
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A cart of mass m is moving with speed v on a smooth track when it encounters a vertical loop of radius r, as shown above. the cart moves along the inside of the entire loop without leaving the track. all frictional forces are negligible.Which of the following must be true for the cart to remain on the track when it is at point P?
Therefore for cart to stay here on track when it arrives at point P, the net force applied to it must be greater or equal than for the heaviness of the cart.
Describe force.The force is an impact that has the power to alter an object's motion. A mass-containing object's velocity can be altered by a force. An obvious way to describe force is as a pushed or a pull. A vector quantity is called a force since it has both strength and the direction.
Which force is the most crucial?The strongest force in existence is thought to be the strong force. The gravitation, weak, and electromagnetism forces come after it in lowest to highest.
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Select all the correct answers.
Which situations describe an elastic collision?
A. Two glass marbles bounce off each other.
B. Rodrick flops onto his sofa and sinks into the cushion.
C. A tossed water balloon flattens when it lands on the grass.
D. A bowling ball knocks over five pins.
Answer:
A and d
Explanation:
Answer:
answer in picture
Explanation:
Why dose a solid change to a liquid when heat is added
Answer: molecules heat up under different ranges of heat causing bonds to break down but depends on the solid. There are different melting points.
Explanation:
matter falling in the gravitational field of a central mass can form a hot, charged fluid. the fluid matter orbiting some stars radiates infrared light, but the matter orbiting black holes emits x-rays. which of the following explains this discrepancy? the matter orbiting black holes must: a. be hotter than the matter orbiting stars. b. be colder than the matter orbiting stars. c. have lower kinetic energy than the matter orbiting stars. d. exhibit higher viscosity than the matter orbiting stars.
The matter orbiting black holes must be hotter than the matter orbiting stars. Correct answer: letter A.
As matter falls into a black hole, it is subject to extreme gravitational forces which compress the matter and heat it up. This heated matter can then emit X-rays, which are much more energetic than the infrared light emitted by matter orbiting stars.
In addition to the extreme gravitational forces, the matter around black holes is also subject to strong magnetic fields. These fields can accelerate particles to near the speed of light, producing powerful jets of matter and energy. These jets are also much brighter in X-rays than the infrared light emitted from stars. This further explains why the matter orbiting black holes emits X-rays, while the matter orbiting stars emits infrared light.
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