Whar is an example of a transversal?​

Answer:

Your didnt explain enough this isnt possible to solve

Step-by-step explanation:

For x-intercept:

put y=0

0=-7x+3

7x=3

x=3/7

points(3/7,0)

For y-intercept:

x=0

y=-7(0)+3

y=3

points(0,3)

Yes, the number, 4225, is a perfect square because it can be expressed as square of 65 which is a whole number, i.e., 4225 = 65².

In mathematics, a square number or perfect square is an integer that is the product of some integer with itself. For example, 25 is a square number, it is equals to 5² and can be written as 5×5. A perfect square always represented as second power of a number. Perfect Square Formula : Let us consider if N is a perfect square of a whole number x, then it can be written as N = product of x and x = x². So, the perfect square formula is, N = x². We have a number 4225. Now, we resolve 4225 into prime factors, we get, 4225 = 5×5×13×13 = 5×13×5×13

= 65×65 = (65)²

Hence, the square of 65 results 4225. Therefore, 4225 is a perfect square.

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Answer:

D

Step-by-step explanation:

Answer:

-63

Step-by-step explanation:

\[x²-3x+18\]

discriminant=b²-4ac=(-3)²-4*1*18=9-72=-63

Answer:

\(\boxed {\boxed {\sf -63}}\)

Step-by-step explanation:

The discriminant is the portion of the Quadratic Formula that is under a square root. It helps us identify if a function has 2,1, or 0 solutions.

The quadratic formula is:

\({x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}\)

where the quadratic is: ax²+bx+c

The part under the square root is just:

\(b^2-4ac}\)

We are given the quadratic:

x² -3x+18

Therefore,

Substitute the values into the formula for the discriminant.

\((-3)^2-4(1)(18)}\)

Solve the exponent.

\(9-4(1)(18)}\)

Multiply.

\(9-72\)

Subtract

\(-63\)

Since the discriminant is negative, there are no real solutions. There are imaginary solutions though.

The measure of the central angle that was used when cutting the pizza to the nearest tenth is 0.7 radians.

We are given that

Diameter of pizza =d=18 inches,

hence radius of circular pizza =r\(=\frac{\mathrm{d}}{2}=\frac{18}{2}=9$\) inches,

Also, the arc length of a slice of pizza =L=6.5 inches.

Since we know that

Equation 1 where \($\theta$\) is measured in radians.

\(& =\frac{6.5}{9} \\\)

\(& =\frac{65}{90} \\\)

\(& =\frac{13 \times 5}{18 \times 5} \\\)

\(& =\frac{13}{18} \\\)

\(& =0.7 \text { radians }\end{aligned}\)

Therefore,  the measure of the central angle to the nearest tenth is 0.7 radians.

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Answer:

B.

Step-by-step explanation:

34-15 goes into paratheses because it goes first.

Then multiply by 4.

(34 - 15) x 4

Hope this helps!

If you get this right, giving me brainliest would mean a lot! Thanks!

Answer: d. Mean, median and mode are all equal.

Step-by-step explanation:

The graph of the logarithmic function represented by the table would be a curve that passes through the given points. The domain of the function is all positive values of x, and the range is all real numbers.

The graph of the logarithmic function will be a curve passing through the points given in the table. The domain of the function is all positive values of x, and the range is all real numbers.

The table represents a logarithmic function f(x). The x-values in the table are the inputs to the function, and the y-values are the outputs.

Looking at the table, we can see that as x increases, y also increases, indicating that the function is increasing.

To graph the function, we plot the given points and connect them with a smooth curve. The curve will approach the y-axis but will never touch it, as the logarithm of 0 is undefined. The graph extends infinitely in the positive x-direction.

The domain of the function is all positive values of x since the logarithm is only defined for positive inputs. In inequality notation, we can express the domain as x > 0. In interval notation, the domain is (0, ∞).

The range of the function is all real numbers. As x approaches infinity, y also approaches infinity. As x approaches 0, y approaches negative infinity. Therefore, the range is (-∞, ∞) in interval notation. In set-builder notation, we can express the range as {y | y ∈ ℝ}.

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The cost of admission for this family is $39.75. Another way I could have solved this world problem is by adding the cost of admission for two adult together with the cost of admission for a child.

In order to solve this word problem, we would assign variables to the cost of admission for each senior citizen, each adult, and each child, and then translate the word problem into algebraic equation as follows:

From the information provided, we have the following parameters:

Cost of admission for each adult = $15.75.

Cost of admission for each child = $8.25.

For a family of two adult and 1 child, a linear equation which models the situation is given by:

Total cost of admission = 2a + c

Substituting the given points into the formula, we have;

Total cost of admission = 2($15.75) + $8.25

Total cost of admission = $31.5 + $8.25

Total cost of admission = $39.75.

Total cost of admission = $15.75 + $15.75 + $8.25

Total cost of admission = $39.75.

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Complete Question:

The cost of admission to the Baytown zoo is $ 10.50 for each senior citizen,$15.75 for each adult ,and $8.25 for each child. A family of two adult and 1 child plan to spend the day at the Baytown zoo, how much does admission for the family cost?

Part B

Describe another way you could solve the problem.

The parent equation would be y=x^2 because that is the parent equation of a quadratic function. ;)

This is the UML diagram for the development of the program, in which Shapes 2D is the superclass and Circle, Square, Triangle, Rectangle, Rhombus, and Parallelogram are subclasses.

​​​​​​​This is the program in C++ demonstrating the above classes.

#include<iostream>

using namespace std;

class shapes

{

public:

   string name;

   string color;

   virtual void getAttributes()=0;

};

class Circle: public shapes

{

public:

   float radius;

   Circle(string n,string c, float r)

   {

       name=n;

       color=c;

       radius=r;

   }

   float getPerimeter()

   {

       return(2*(3.142)*radius);

   }

   float getArea()

   {

       return((3.142)*(radius*radius));

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Square:public shapes

{

public:

   float side;

   Square(string n,string c, float s)

   {

       name=n;

       color=c;

       side=s;

   }

   float getPerimeter()

   {

       return(4*side);

   }

   float getArea()

   {

       return(side*side);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Triangle:public shapes

{

public:

   float base;

   float height;

   float side1;

   float side2;

   float side3;

   Triangle(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter side1\n";

       cin>>side1;

       cout<<"Enter side2\n";

       cin>>side2;

       cout<<"Enter side3\n";

       cin>>side3;

       return(side1+side2+side3);

   }

   float getArea()

   {

       cout<<"Enter base\n";

       cin>>base;

       cout<<"Enter height\n";

       cin>>height;

       return((0.5)*base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rectangle:public shapes

{

public:

   float length;

   float breadth;

   Rectangle(string n,string c, float l,float b)

   {

       name=n;

       color=c;

       length=l;

       breadth=b;

   }

   float getPerimeter()

   {

       return(2*(length+breadth));

   }

   float getArea()

   {

       return(length*breadth);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rhombus:public shapes

{

public:

   float diagonal1;

   float diagonal2;

   float side;

   Rhombus(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter Side\n";

       cin>>side;

       return(4*side);

   }

   float getArea()

   {

       cout<<"Enter diagonal 1\n";

       cin>>diagonal1;

       cout<<"Enter diagonal 2\n";

       cin>>diagonal2;

       return((0.5)*diagonal1*diagonal2);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Parallelogram:public shapes

{

public:

   float base;

   float height;

   Parallelogram(string n,string c, float b,float h)

   {

       name=n;

       color=c;

       base=b;

       height=h;

   }

   float getPerimeter()

   {

       return(2*(base+height));

   }

   float getArea()

   {

       return(base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

int main()

{

   int choice;

   while(1)

   {

       cout<<"\n\nEnter your choice :";

       cout<<"\n1 for Circle\n";

       cout<<"2 for Square\n";

       cout<<"3 for Triangle\n";

       cout<<"4 for Rectangle\n";

       cout<<"5 for Rhombus\n";

       cout<<"6 for Parallelogram\n";

       cin>>choice;

       system("cls");

       switch(choice)

       {

       case 1:

           {

               float r;

               cout<<"Enter radius\n";

               cin>>r;

               Circle c("Circle","Yellow",r);

               c.getAttributes();

               cout<<"Perimeter : "<<c.getPerimeter()<<endl;

               cout<<"Area : "<<c.getArea()<<endl;

           }break;

       case 2:

           {

               float side;

               cout<<"Enter side\n";

               cin>>side;

               Square s("Square","Red",side);

               s.getAttributes();

               cout<<"Perimeter : "<<s.getPerimeter()<<endl;

               cout<<"Area : "<<s.getArea()<<endl;

           }break;

       case 3:

           {

               Triangle t("Triangle","Green");

               t.getAttributes();

               cout<<"Perimeter : "<<t.getPerimeter()<<endl;

               cout<<"Area : "<<t.getArea()<<endl;

           }break;

       case 4:

           {

               float l,b;

               cout<<"Enter Length and breadth\n";

               cin>>l>>b;

               Rectangle r("Rectangle","Blue",l,b);

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 5:

           {

               Rhombus r("Rhombus","Purple");

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 6:

           {

               float b,h;

               cout<<"Enter base\n";

               cin>>b;

               cout<<"Enter height\n";

               cin>>h;

               Parallelogram p("Parallelogram","Pink",b,h);

               p.getAttributes();

               cout<<"Perimeter : "<<p.getPerimeter()<<endl;

               cout<<"Area : "<<p.getArea()<<endl;

           }break;

       }

   }

}

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Answer:

502$

Step-by-step explanation:

4*125.50=502

Answer:

1

Step-by-step explanation:

The difference of 12 and 9 is 12 - 9 = 3

Then 3 ÷ 3 = 1

Answer: 10

Step-by-step explanation:

first solve for x, 3x+10=4x-15

x=25

now solve both equations to find two of the angles

angle 1: 85 angle 4:85

now add the two angles and subtract them from 180, 85+85=170. 180-170=10

angle 7 is 10

Part A:  The amount of unearned interest is $3,225.

Part B: The amount needed to repay the loan using the Rule of 78 is $8,443.75.

Part C: To support our answers to Part A and Part B, the total interest that Christopher would have paid, which is 3,900$. the amount needed to repay the loan using the Rule of 78, which is $8,443.75.

What is an interest?

To determine the amount of unearned interest, we need to find out how much interest Christopher would have paid if he made all 24 payments.

First, we can calculate the total amount he would have paid if he made all 24 payments:

Total amount paid = 475 x 24 = 11,400$

Next, we can subtract the amount borrowed from the total amount paid to find the total interest:

Total interest = Total amount paid - Amount borrowed

Total interest = 11,400$ - 7,500$

Total interest = 3,900$

Since Christopher paid off the loan after 18 months instead of 24 months, he did not pay the full amount of interest he would have paid if he made all 24 payments. The unearned interest is therefore:

Unearned interest = Total interest - (Number of remaining payments / Total number of payments x Total interest)

Unearned interest = 3,900 - (6 / 24 x 3,900)

Unearned interest = 3,225$

Therefore, the amount of unearned interest is $3,225.

What is repay?

Part B:

To determine the amount needed to repay the loan using the Rule of 78, we need to calculate the proportion of the total interest that has been earned by the lender up to the point when Christopher repays the loan.

The Rule of 78 is a method of allocating interest charges based on the sum of the digits of the loan term. In this case, since the loan term is 24 months, the sum of the digits is:

1 + 2 + ... + 4 + 5 = 15

We can use this sum to calculate the proportion of the total interest earned by the lender up to the point when Christopher repays the loan:

Proportion of earned interest = (Number of payments made / Total number of payments) x (Sum of digits of loan term / Total sum of digits)

Proportion of earned interest = (18 / 24) x (15 / 120)

Proportion of earned interest = 0.09375

The total interest paid is 3,900$, so the amount needed to repay the loan using the Rule of 78 is:

Amount needed to repay loan = Amount borrowed + Total interest x Proportion of earned interest

Amount needed to repay loan = 7,500$ + 3,900$ x 0.09375

Amount needed to repay loan = 8,443.75$

Therefore, the amount needed to repay the loan using the Rule of 78 is $8,443.75.

Part C:

To support our answers to Part A and Part B, we calculated the total interest that Christopher would have paid if he made all 24 payments, which is 3,900$. We also calculated the unearned interest, which is the difference between the total interest and the interest that Christopher actually paid when he paid off the loan early.

Using the Rule of 78, we calculated the proportion of the total interest earned by the lender up to the point when Christopher repaid the loan, which is 0.09375. We then used this proportion to calculate the amount needed to repay the loan using the Rule of 78, which is $8,443.75.

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The information is not enough to prove that triangles DEF and OPQ are congruent through SAS, as we need two equal side lengths and one angle measure.

The Side-Angle-Side (SAS) congruence theorem states that if two sides of two similar triangles form a proportional relationship, and the angle measure between these two triangles is the same, then the two triangles are congruent.

The parameters given for this problem are given as follows:

As we are given only one side, instead of the two sides needed, we have that the information given is not enough to prove that the two triangles are congruent by the SAS congruence theorem.

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The answers to all the subparts are shown:

(A) So, we know that: 1 liter = 10 decilitre

So, the consumption of the fuel = 60 - 34 = 26 litres.

(B) Cost of 60 liters of fuel if 1 liter is € 1.45:

(C) Liters of fuel he could buy from € 58:

Therefore, the answers to all the subparts are shown:

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The correct question is given below:
Giorgio fills up his car which is 60 liters. After a certain distance, 340 deciliters remained in the tank.

(A) How many liters did it consume?

(B) How much did you spend if 1-liter costs € 1.45?

(C) How many liters of petrol can you buy for € 58?

Answer:

find the cordinates of each letter or number then find witch is greater or less than when your answering it

Step-by-step explanation: