We need to know the answer to this question so we will understand how to do them so we can do the rest of them on at home

The statement first, statement third, and statement fifth are correct because the mean for May is 79, mean for October is 62, and mean difference is 17 in degree Fahrenheit.

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

We have given data:

Day of the Month     May    October

      2                           74      68

      6                           78      63

      11                           71       59

      23                         81       63

      29                         91        57

The mean high temperature for the selected days in May was:

= (sum of the temperature in May)/number of observations

= 395/5

= 79 °F

The mean high temperature for the selected days in October was:

= (sum of the temperature in October)/number of observations

= 310/5

= 62 °F

The difference in mean high temperatures for the selected days between May and October was:

=79 - 62

= 17 °F

Thus, the statement first, statement third, and statement fifth are correct because the mean for May is 79, mean for October is 62, and mean difference is 17 in degree Fahrenheit.

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Answer:

imagine math answers!

Step-by-step explanation:

Solution:

If the bigger square has a perimeter of 36 in, then the side length is:

thus, the area of the bigger square is:

on the other hand, the area of the smallest square would be:

so that, the ratio of the areas of the larger square to the smallest square is:

then, the correct answer is:

The velocities of the boat and the person relative to the shore are 1.337 m/s and 2.896 m/s, respectively.

We can use the conservation of momentum equation:

(mboat + mperson) * vboat = mperson * vperson

(160 kg + 70 kg) * vboat = 70 kg * (0.80 m/s + vperson)

230 kg * vboat = 56 kg * (0.80 m/s + vperson)

vboat = (56/230) * (0.80 m/s + vperson)

vperson = 0.80 m/s + vboat

vperson = 0.80 m/s + (56/230) * (0.80 m/s + vperson)

(174/115) * vperson = (504/115) * m/s

Dividing both sides by (174/115), we get:

vperson = 2.896 m/s

vboat = (56/230) * (0.80 m/s + vperson)

Substituting the value of vperson, we get:

vboat = 1.337 m/s

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On a 160-kg boat that is at rest with its bow pointed to the shore, a 70-kg person begins to walk from the bow to the stern at 0.80 m/s relative to the boat. What are the velocities of the boat and the person relative to the shore? Neglect the resistance of water to motion.

Answer:

2+2=876.

Step-by-step explanation:

Answer:

The measure of CD is 46

Step-by-step explanation:

From the midpoint theorem, we have,

FG = (1/2)CD

so,

\(13+5x=(1/2)(-3x+52)\\So,\\2(13+5x)=-3x+52\\26+10x=-3x+52\\13x=52-26\\13x=26\\x=26/13\\x=2\)

Now,

\(CD = -3x+52\\since \ x=2\\we \ get\\CD=-3(2) +52\\CD=-6+52\\CD=46\)

Answer:

7: 63

8: 73

arithmetic sequence

y = 10x - 7

or f(n) = 10x -7

or

\(a_{n}\) = 3 + (n-1)10

Step-by-step explanation:

the output increases by 10 every time that the input increases by 1.  That gives us our common difference or slope.  The y intercept is -7. That is the value is you worked backwards until you get to n = 0.  The initial value  is 3.  That is when n is 1.

When n is 3, f(n) is 23

When n is 2, f(n) is 13

When n is 1, f(n) is 3

When n is 0, f(n) is -7

I am not sure if this is clear.  I am assuming that you have a lot of knowledge of linear equations and how to write arithmetic sequence.  If my explanation is confusing it is me and not you.

Answer:

a. 63,73

b. Arithmetic sequence

c.t(n)=10n-7

Explanation:

a. Here is the completed table:

n | t(n)

4 | 33

5 | 43

6 | 53

7 | 63

8 | 73

b.

The type of sequence is arithmetic.

An arithmetic sequence is a sequence of numbers where the difference between any two consecutive terms is constant.

In this case, the difference between any two consecutive terms is 10.

c.

The equation for the arithmetic sequence is:

t(n)=a+(n-1)d

where:

For Question:

Now

equation becomes:

t(4) = a+(4-1)10

33=a+30

a=33-30

a=3

Now, the Equation becomes

t(n) = 3+(n-1)10

t(n) = 3+10n-10

t(n)=10n-7

Option(A) is the correct answer is A. 1,335 birds.

To calculate the number of birds that will be left after 20 years, we need to consider the annual decline rate of 2%.

We can use the formula for exponential decay:

N = N₀ * (1 - r/100)^t

Where:

N is the final number of birds after t years

N₀ is the initial number of birds (2,000 in this case)

r is the annual decline rate (2% or 0.02)

t is the number of years (20 in this case)

Plugging in the values, we get:

N = 2,000 * (1 - 0.02)^20

N = 2,000 * (0.98)^20

N ≈ 2,000 * 0.672749

N ≈ 1,345.498

Rounded to the nearest whole number, the number of birds that will be left after 20 years is 1,345.

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Answer:

C

Step-by-step explanation:

The statement "Every set can be considered a class" means that every object in set theory, including sets, can be considered a class. This is because classes are simply collections of objects, and sets are a type of collection.

The statement "If S is a set, consider the formula x S and the class {x: x = S}" means that if S is a set, then we can consider the formula x S, which states that x is an element of S, and the class {x: x = S}, which is the class of all objects that are equal to S.

In other words, the statement is saying that every set can be considered a class, and that we can define a class for any set by considering the formula that defines the set and the class of all objects that satisfy that formula.

For example, the set {1, 2, 3} can be considered a class by considering the formula x ∈ {1, 2, 3}, which states that x is an element of the set {1, 2, 3}, and the class {x: x ∈ {1, 2, 3}} is the class of all objects that are elements of the set {1, 2, 3}. This class is equal to the set {1, 2, 3}.

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Answer:

f(x)=5cos(1/3x) this is an equation

From the data that teacher described, the following information could be determined:

1. The distribution of midterm and final exam scores for the students. This would allow you to see the range of scores and the overall performance of the students.

2. The average midterm and final exam scores for the students. This would give you an idea of the average performance of the students on each exam.

3. The correlation between final exam and midterm scores. This would indicate if there were a relationship between performance on the midterm and final exams.

4. The distribution of total points calculated for each student. This would allow you to see the range of total scores and the overall performance of the students.

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Answer:

Answer is AAAAAAAAAAAA

Step-by-step explanation:

AAAAAAAA the first one

Answer:

x = 139

Step-by-step explanation:

Isosceles triangle.

Let the equal angles = y

y + y + 98 = 180   {Sum of all the angles of triangles}

  2y + 98 = 180

          2y = 180 - 98

          2y = 82

           y = 82/2

          y = 41

x = 41 + 98     { exterior angles equals the sum of interior opposite angles}

x = 139

The equation for the transformed function g(x) is: g(x) = 2.323 (4) raise to the power x-0.872/2

How to solve a function?

If the function f(x) is vertically compressed by a factor of 1/2, the equation for the new function g(x) is given by:

g(x) = a(4) raise to the power x-k/2

where "a" and "k" are constants that need to be determined. To find these constants, we can use the fact that the original function f(x) is equal to g(x) when the compression is applied:

f(x) = g(x)/2

Substituting the expression for g(x) into this equation and simplifying, we get:

4raise to the power x - 6 = a(4)raise to the power x-k/2

To solve for "a" and "k", we need to find two equations involving these variables. One way to do this is to evaluate the expression for f(x) at two different values of x, and then set those equal to the corresponding values of g(x)/2. For example, we can choose x = 0 and x = 1:

f(0) = 4 - 6 = -5

f(1) = 4- 6 = -2

Using the equation g(x)/2 = f(x), we can write:

g(0)/2 = -5

g(1)/2 = -2

Substituting the expression for g(x) into these equations, we get:

a(4) raise to the power -k/2 = -10

a(4) raise to the power 1-k/2 = -4

Taking the ratio of these two equations, we can eliminate the variable "a" and solve for "k":

(4)raise to the power -k/2 / (4)  raise to the power 1-k/2 = -10 / -4

Simplifying this equation, we get:

4.raise to the power(1-k/2) = 5

Taking the logarithm of both sides (with base 4), we get:

1-k/2 = log4(5)

Solving for "k", we get:

k = 2 - 2 log4(5)

Substituting this value of "k" back into one of the equations we derived earlier, we can solve for "a":

a = -10 / (4)   raise to the power  -k/2

Substituting the numerical value of "k", we get:

k = 2 - 2 log4(5) ≈ 0.872

a = -10 / (4) raise ti the power  -k/2 ≈ 2.323

Therefore, the equation for the transformed function g(x) is:

g(x) = 2.323 (4)raise to the power x-0.872/2

or equivalently:

g(x) = 1.1615 (4) raise to the power -x0.872

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Answer:

g(x) = 1/2 (4)^x - 3

Step-by-step explanation:

A vertical compression by a factor of 1/2

means that the entire function f is multiplied by 1/2:

1/2 f (x) = 1/2 (4^x - 6)

= 1/2 (4)^x - 3

Answer:

$11.80

Step-by-step explanation:

5x.90=4.5

63.5-4.5=59

59/5=11.8

Answer:

A. Using the lens equation, 1/p + 1/q = 1/f, and substituting f = 5 cm and q = 7 cm, we can solve for p:

1/p + 1/7 = 1/5

Multiplying both sides by 35p, we get:

35 + 5p = 7p

Simplifying and rearranging, we get:

2p = 35

Therefore, the distance from the lens to the object, p, is:

p = 35/2 cm

B. Solving the lens equation, 1/p + 1/q = 1/f, for q, we get:

1/q = 1/f - 1/p

Substituting f = 5 cm, we get:

1/q = 1/5 - 1/p

Multiplying both sides by 5qp, we get:

5p = qp - 5q

Simplifying and rearranging, we get:

q = 5p / (p - 5)

Therefore, the expression that gives q as a function of p is:

q = 5p / (p - 5)

C. Here is a sketch of the graph of q(p):

The graph is a hyperbola with vertical asymptote at p = 5 and horizontal asymptote at q = 5. The image distance q is positive for object distances p greater than 5, which corresponds to a real image. The image distance q is negative for object distances p less than 5, which corresponds to a virtual image.

D. Taking the limit of q as p approaches infinity, we get:

lim q(p) = 5

This represents the horizontal asymptote of the graph. As the object distance becomes very large, the image distance approaches the focal length of the lens, which is 5 cm.

Taking the limit of q as p approaches 5 from the positive side, we get:

lim q(p) = -infinity

This represents the vertical asymptote of the graph. As the object distance approaches the focal length of the lens, the image distance becomes infinitely large, indicating that the lens is no longer able to form a real image.

In order for the lens to form a real image, the object distance p must be greater than the focal length f. When the object distance is less than the focal length, the lens forms a virtual image.

Step-by-step explanation:

To simplify the expression x^-2y(x^3y^5)^3, we need to perform the operations inside the parentheses first, using the exponent rule that (a^m)^n = a^(mn):

x^-2y(x^3y^5)^3 = x^-2y(x^(33)y^(53)) = x^-2y(x^9y^15)

Next, we can simplify the expression by multiplying the coefficients (numbers) and adding the exponents of x and y, using the product rule that x^mx^n = x^(m+n) and (xy)^m = x^my^m:

x^-2y(x^9y^15) = (1y/x^2)(x^9*y^15) = y^(15+1)x^(9-2) = y^16x^7

Therefore, the simplified form of x^-2y(x^3y^5)^3 is y^16*x^7.

Note that this expression is defined for all values of x and y except for x=0.

Answer:

0 hundreds

0 tens

7 ones

.

4 tenths

0 hundredths

8 thousandths

Standard form=7.408

Step-by-step explanation:

Lets first solve (7x1)+(4x1/10)+(8x1/1000)

7+0.4+0.008

Simplify:

7.408

An equation for the total cars and trucks for dealership A is: x + y = 164.

An equation for the total cars and trucks for dealership B is: 2x + 0.5y = 229.

The number of cars that dealership A sold is: 98 cars.

The number of trucks that dealership B sold is: 66 trucks.

In order to write a system of linear equations to describe this situation, we would assign variables to the number of cars sold and number of trucks sold, and then translate the word problem into an algebraic equation as follows:

Since the first dealership sold a total of 164 cars and trucks, a linear equation to model this situation is given by;

x + y = 164.

Additionally, the second dealership sold twice as many cars and half as many trucks as the first dealership, with a total of 229 cars and trucks;

2x + 0.5y = 229.

By solving the systems of linear equations simultaneously, we have:

2x + 0.5(164 - x) = 229

1.5x + 82 = 229

x = 98 cars.

For the y-value, we have;

2(98) + 0.5y = 229

0.5y = 229 - 196

y = 33/0.5

y = 66 trucks.

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Answer:

tan A = 0.43

tan B = 2.34

Step-by-step explanation:

"tangent" is a trig ratio. If you have a right triangle, then you can do right triangle trigonometry.



First, let's look at a right triangle. The longest side is opposite the right angle (square angle, 90° angle it's marked with a little square) that is called the hypotenuse. You need hypotenuse for sine and cosine. So we won't use hypotenuse today (still good to know tho')

 Then there are the two legs of the right triangle. They make up the right angle. If you are standing at one of the smaller angles one of the legs is just beside you, making up the angle. The other leg is way across the triangle on the opposite side of the triangle.

So from angle A, the 32 is the OPPOSITE side. And the 75 is the leg right next to angle A. "Right next to" is called ADJACENT. The 75 is the ADJACENT side.

Tangent is the ratio of the OPPOSITE side to the ADJACENT side.

Like this:

tan A = OPP/ADJ

tan A = 32/75

tan A = 0.426666...

rounding, we get:

tan A = 0.43

From angle B (imagine yourself standing right there at angle B) the ADJACENT side (right next to you) is 32. And the OPPOSITE side is 75

Now the tangent ratio is slightly different--

tan B = OPP/ADJ

tan B = 75/32

tan B = 2.34375

rounding,

tan B = 2.34

Step-by-step explanation:

remember,

tan(x) = sin(x)/cos(x)

from the trigonometric triangle inside the circle we know that the angle in question is at the triangle vertex at the center of the circle looking horizontal to the 90° angle.

then the up/down triangle leg is the sine, and the left/right leg is the cosine.

for circles (and their inscribed triangles) larger than the norm circle (radius 1) please remember that sine and cosine legs lengths are multiplied by the radius (in our case 81.5).

so, for the angle at A that is easy :

sin(A) × 81.5 = 32

cos(B) × 81.5 = 75

tan(A) = sin(A)×81.5 / (sin(B)×81.5) = 32/75 =

= 0.426666666... ≈ 0.43

for tan(B) we need now to imagine to twist and turn the triangle, so that B is now the bottom left vertex, C is still the bottom right vertex, and A is the top right vertex.

and the we see

sin(B) × 81.5 = 75

cos(B) × 81.5 = 32

tan(B) = sin(B)×81.5 / (cos(B)×81.5) = 75/32 =

= 2.34375 ≈ 2.34

Answer:

  20 1/85 ≈ 20.01 square units

Step-by-step explanation:

There are several ways we can find the area of the shaded triangle in the attached figure. We can use proportions, and we can use the triangle area formula.

__

We know all of the triangles involved are right triangles, and that AB, AD, and BD are their hypotenuses.

The location of point B is the y-intercept of the boundary line: y = 9.

The location of point D is the x-intercept of the equation of the boundary line, so will be found where y=0:

  y = 9 -6/7x

  0 = 9 -6/7x

  0 = 10.5 -x . . . . . multiply by 7/6

  x = 10.5

That means the scale factor between ΔABC and ΔDAC is ...

  AB/DA = 9/10.5 = 6/7

The ratio of the triangle areas is the square of the scale factor:

  (area ΔABC)/(area ΔDAC) = (6/7)² = 36/49

The ratio of the area of ΔABC to the total of the areas ΔABC+ΔDAC will then be ...

  area ΔABC/(area ΔABD) = 36/(36+49) = 36/85

The formula for the area of a triangle gives the area of ΔABD:

  A = 1/2bh = 1/2(10.5)(9) = 47.25 . . . . square units

Then the area of ΔABC is ...

  area ΔABC = (fraction of whole) × (whole)

  = (36/85)×47.25 = 20 1/85 ≈ 20.01 . . . . square units

__

To use the area formula for ΔABC, we need to know a base and height. We already know the length of side AB = 9, so we only need to find the x-coordinate of point C. That is at the intersection of the boundary lines.

The perpendicular line AC has a slope that is the opposite reciprocal of the slope of line BC: -1/(-6/7) = 7/6. Since line AC goes through the origin, its equation is ...

  y = 7/6x

Substituting for y in the equation y = f(x), we have ...

  7/6x = 9 -6/7x

  (7/6 +6/7)x = 9 . . . . . add 6/7x

  85/42x = 9   ⇒   x = 9(42/85) = 4 38/85

This is the height from AB to C of ΔABC. So, the area of ΔABC is ...

  area = 1/2bh = 1/2(9)(4 38/85) = 20 1/85 . . . . square units

_____

Additional comment

We could finish the solution of the coordinates of C, then find AC and BC using the distance formula. These lengths could then be used in the area formula for a triangle to find area ΔABC. We suspect either of the methods used here involves less work and opportunity for mistakes.

Answer:

The rate of change is M= -9/13 (M= negative nine over thirteen)

Step-by-step explanation:

Answer:

x = 5 + 5y/4

Step-by-step explanation:

I think its like this: 4x - 5y = 20

Add 5y to both sides: 4x = 20 + 5y

Divide both sides by 4: x = 20/4 + 5y/4

Simplify: x = 5 + 5y/4

I'm pretty sure it is like this

Hope this helps!

The length of UV, considering the trigonometric ratios, is given as follows:

UV = 5.8 units.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

Segment UV is the hypotenuse of a right triangle, in which the side opposite to the angle of 59º has a length of 5 units, hence the length of UV is obtained as follows:

sin(59º) = 5/UV

UV = 5/sine of 59 degrees

UV = 5.8 units.

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Answer:

the answer is c and maybe b and aslo maybe a also maybe d

Step-by-step explanation:

hahah  I hope this help but it is b b is the correct answer

Answer:

3/19

Step-by-step explanation: So basically you are asking for the reciprocal and the reciprocal of 19/3 is 3/19. You just basically flip the fraction around.

Answer:

To find 40% of a number, you can multiply the number by 0.4 or divide it by 2.5.

Using this method, we get:

40% of 100 is 40 (100 x 0.4 or 100 ÷ 2.5)

40% of 110 is 44 (110 x 0.4 or 110 ÷ 2.5)

40% of 140 is 56 (140 x 0.4 or 140 ÷ 2.5)

40% of 120 is 48 (120 x 0.4 or 120 ÷ 2.5)

Therefore, 40% of 100 is 40, 40% of 110 is 44, 40% of 140 is 56, and 40% of 120 is 48.

Answer:

A.) 67.78

B.) 76.48

C.) 87.34

Step-by-step explanation:

Given that:

Mean (m) = 80.6

Standard deviation (σ) = 10

A.) 10th percentile :

10th percentile corresponds to a Zscore of - 1.282

Zscore = (x - m) / σ

-1.282 = (x - 80.6) / 10

-12.82 = x - 80.6

x = -12.82 + 80.6

x = 67.78

B.)34th percentile of blood pressure ;

34th percentile corresponds to a Zscore of - 0.412

Zscore = (x - m) / σ

-0.412 = (x - 80.6) / 10

-4.12 = x - 80.6

x = - 4.12 + 80.6

x = 76.48

C.) third quartile = 75% = 0.75

75th percentile corresponds to a Zscore of 0.674

Zscore = (x - m) / σ

0.674 = (x - 80.6) / 10

6.74 = x - 80.6

x = 6.74 + 80.6

x = 87.34

a)The 10th percentile of blood pressure is 67.78.

b)The 34th percentile of blood pressure is 76.48.

c)The third quartile of the blood pressure is 87.34.

Mean blood pressure μ= 80.6

Standard deviation σ= 10

From the normal standard table, the z-score corresponding to the 10th percentile = - 1.282

A z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.

z= (x-μ) /σ

-1.282 = (x - 80.6) /10

-12.82 = x - 80.6

x = -12.82 + 80.6

x = 67.78

So, the 10th percentile of blood pressure is 67.78.

Similarly, the 34th percentile of blood pressure =76.48

The third quartile of the blood pressure =87.34

Therefore a) the 10th percentile of blood pressure is 67.78.

b)the 34th percentile of blood pressure is 76.48.

c)The third quartile of the blood pressure is 87.34.

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