we give 65 joules as heat to a gas, which then expands isobarically. the gas molecules rotate but do not oscillate. by how much does the internal energy of the gas increase
Answers
ΔEint = 46.42 J is the correct answer.
According to the Kinetic Molecular Theory of Gases,
Referring to equation , we have
ΔEint=nCVΔT= 5/2nRΔT
Q=nCPΔT = 7/2nRΔT
Dividing the equations, we obtain
ΔEint/Q = 5/7
Thus, the given value Q=65 J leads to ΔEint = 46.42 J
What is Kinetic Theory?
1) Gases are made up of a lot of tiny particles spaced far away from one another.
2) The gas molecules clash elastically with the container wall as well as with one another.
3) Gas molecules have kinetic energy and are constantly moving randomly.
4) The attraction between gas molecules is extremely weak and is regarded as negligible.
5) The average kinetic energy of gas molecules is precisely proportional to the temperature of the gas.
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Related Questions
A crew member of a spaceship measures the length of the ship to be 200 m . However, an observer on a nearby space station measures the ship's length to be 140 m . What is the speed of the spaceship relative to the space station
Answers
The speed of the spaceship relative to the space station is approximately 2.6 x 10^8 m/s.
This question involves the concept of length contraction, which is a consequence of the theory of relativity. According to this theory, when an object is moving relative to an observer, its length appears to be shorter than its rest length.
In this case, the crew member on the spaceship measures the ship's length to be 200 m, which is the rest length of the ship (i.e., the length as measured by an observer who is at rest relative to the ship). However, the observer on the nearby space station measures the ship's length to be 140 m, which means that the length of the ship appears to have contracted by a factor of (140/200) = 0.7.
The formula for length contraction is given by L' = L * sqrt(1 - v^2/c^2), where L is the rest length of the object, L' is its length as measured by an observer moving at a speed v relative to the object, and c is the speed of light.
In this case, we can solve for v by rearranging the formula: v = c * sqrt(1 - (L'/L)^2). Plugging in the values, we get:
v = c * sqrt(1 - (140/200)^2)
= c * sqrt(1 - 0.49)
= c * 0.866
≈ 2.6 x 10^8 m/s
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Compare the interaction between light and two different materials: a reflective glass mirror and a transparent glass block. How did the light behave differently
Answers
When a material is reflective, it would cause the light that meets it to bounce off while a transparent material would make the light to pass through it.
What is light?Light is a form of energy that produces a sensation that is visible to the optical eye. We know that a material is said to be transparent if the material can allow light to pass through it. A material is said to be reflective when it bounces off the rays of light that fall on it.
We can see that when light interacts with the transparent material, the light can pass through the material. If the light interacts with the reflective material then the light rays are seen to bounce off the light rays.
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What is the power of a toaster if it can perform 3500 j of work In 3 minutes
Answers
Answer:
Around 20 watts, or 19.4W exactly
Explanation:
to calculate the power in a time frame you use
Joules/Time(Seconds) = W (your power)
So, we take 3500 joules / 3min (180sec)
3500/180 = 19.4W, if your question asks you to round up/down, round up to 20W of power! good luck!
A boy walks towards a stationary plane mirror at a speed of 12ms^1 what is the relative speed of approach of the boy and his image? (a)zero (b)1.2ms^-1 (c) 2.4ms^-1 (d)1.44ms^-1
Answers
Answer:
a
Explanation:
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What if the Earth was moved out to Jupiter's orbit which is about 5
times further from the Sun that Earth. How would the Sun's effect on
the Earth change at that distance?
25 times less gravitational force
0.5 times less gravitational force
5 time less gravitational force
Answers
Answer:
25.0 less force
Explanation:
c)
If from rest, Amirul starts to walk to Boon Chun's house and reach there in 30 seconds, what is
his acceleration?
Answers
Answer\(:0.178\ m/s^2\)
Explanation:
Given
Amirul starts from rest(u=0) to reach Boon chun house which is 80\ m away from School
acceleration of Amirul is given by
\(s=ut+\frac{1}{2}at^2\)
Where
s=displacement
u=intial velocity
a=acceleration
t=time
here \(t=30\ s\)
Substituting values we get
\(80=0+\frac{1}{2}\times a\times (30)^2\)
\(a=\frac{2\times 80}{900}\)
\(a=\frac{160}{900}=0.178\ m/s^2\)
A low energy photon hits
the electron in the image.
What happens to the
electron if the energy is
below the threshold for
absorption?
Answers
A low energy photon hits the electron in the image therefore the photon will bounce off the electron if the energy is below the threshold for absorption.
What is a Photon?This is referred to as a particle representing a quantum of light or other electromagnetic radiation and it carries energy proportional to the radiation frequency but has zero rest mass.
When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level and bounces of if the energy is below the threshold for absorption.
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As the name states, the cars of a roller coaster really do coast along the tracks. A motor pulls the cars up a high hill at the beginning of the ride. After the hill, however, the motion of the car is a result of gravity and inertia. As the cars roll down the hill, they must pick up the speed that they need to whiz through the rest of the curves, loops, twists, and bumps in the track. To learn more about designing roller coasters, read the interview with Steve Okamoto.
How did you become a roller coaster designer?
I have been fascinated with roller coasters ever since my first ride on one. I remember going to Disneyland as a kid. My mother was always upset with me because I kept looking over the sides of the rides, trying to figure out how they worked. My interest in finding out how things worked led me to study mechanical engineering. What sort of training do you have I earned a degree in product design. For this degree, I studied mechanical engineering and studio art. Product designers consider an object's form as well as its function.They also take into account the interests and abilities of the
product's consumer. Most rides and parks have some kind of theme, so I must consider marketing goals and concerns in my designs.
What is the nature of your work?
To design a roller coaster, I study site maps of the location. Then, I go to the amusement park to look at the actual site.Because most rides I design are for older parks (few parks are built from scratch), fitting a coaster around, above, and in
between existing rides and buildings is one of my biggest challenges. I also have to design how the parts of the ride will work together. The towers and structures that support the ride have to be strong enough to hold up a track and speeding cars that are full of people. The cars themselves need special wheels to keep them locked onto the track andseat belts or bars to keep the passengers safely inside. It's
like putting together a puzzle, except the pieces haven't
been cut out yet.
What advice do you have for a student who is interested in designing
roller coasters?
Studying math and science is very important. To design a successtulcoaster, I have to understand how energy is converted from one form to another as the cars move along the track. I have to calculate speeds and accelerations of the cars on each part of the
track. They have to go fast enough to make it up the next hill! I rely on my knowledge of geometry and physics to create the roller coaster's curves.loops, and dips. Sammrazie in two paragraphs
Answers
The summary of the interview with Steve Okamoto a roller coaster designer highlighted how he developed a fascination for rollercoasters and how he successfully learned how to build them.
What is the summary of the interview with Steve Okamoto?The summary of the interview with Steve Okamoto is given below.
In an interview with Steve Okamoto, a roller coaster designer, he explained that his fascination with roller coasters began at a young age, and his interest in finding out how they worked led him to study mechanical engineering and product design. As a roller coaster designer, Okamoto's work involves studying site maps, designing how the parts of the ride will work together, and fitting coasters around existing rides and buildings. He also has to consider marketing goals and concerns in his designs, as most parks have some kind of theme. Okamoto recommends that students interested in designing roller coasters should focus on studying math and science, and understanding how energy is converted from one form to another as the cars move along the track.
Overall, Okamoto's work as a roller coaster designer involves a combination of mechanical engineering, product design, and consideration for marketing goals and existing park infrastructure. To design a successful roller coaster, he relies on his knowledge of math, science, geometry, and physics to calculate speeds, accelerations, and the coaster's curves, loops, and dips. His advice for students interested in designing roller coasters is to focus on studying math and science, and understanding how energy is converted throughout the coaster's track.
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The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)
Answers
Answer:
\(\boxed{ V_{2}= 0.03189 m^3}\)
Explanation:
According to Charles Law
=> \(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)
Where \(V_{1}\) = 0.0279 m³, \(T_{1}\) = 280 K and \(T_{2}\) = 320 K
=> \(\frac{0.0279}{280} = \frac{V_{2}}{320}\)
=> \(V_{2}\) = 0.03189 m³
An object is traveling at a constant velocity of 8 m/s when it experiences a constant acceleration of 3.5 m/s2 for a time of 40 s. What will its velocity be after that acceleration? *
Answers
Answer:
140 m/s
Explanation:
v = u + at
v = 8 + 3.5(40) = 140 + 8 = 140
A 2.0 kg object is moving to the right in the positive x direction with a speed of 1.4 m/s.
Object experiences the force shown in (Figure 1). What is the object's speed after the force ends?
Figure 1
The plot shows the horizontal component of the force applied to the object in newtons as a function of time in seconds. The magnitude stays at value 0 newtons from 0 seconds for a while, then jumps to 2 newtons and stays at this value for one half of asecond. At the end of this time, it drops back to 0 newtons and stays at this value.
Answers
The object's speed after the force ends is 1.5 m/s.
Velocity is a vector quantity that describes the rate and direction of an object's motion. It is defined as the displacement of an object per unit of time and in a specific direction.
To find the object's speed after the force ends, we need to use the force to calculate the object's acceleration, and then use the acceleration to calculate the object's final velocity.
The force-time plot in Figure 1 can be broken down into three parts:
1. The force is 0 N from 0 to 1 s.
2. The force is 2 N from 1 to 1.5 s.
3. The force is 0 N from 1.5 s onwards.
Using Newton's second law (F=ma), we can calculate the object's acceleration during each of these time intervals:
1. For the first time interval (0 to 1 s), the force is 0 N, so the acceleration is also 0 m/s^2.
2. For the second time interval (1 to 1.5 s), the force is 2 N and the mass of the object is 2.0 kg, so the acceleration is:
a = F/m = 2 N / 2.0 kg = 1 m/s^2
3. For the third time interval (1.5 s onwards), the force is 0 N, so the acceleration is also 0 m/s^2.
To find the object's speed after the force ends, we can use the following kinematic equation:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement.
We can assume that the displacement of the object during the time intervals in Figure 1 is negligible, since the force is applied horizontally and the object is already moving horizontally. Therefore, we can ignore the displacement term in the equation.
For the first time interval (0 to 1 s), the object's initial velocity is 1.4 m/s, so we can calculate the final velocity after 1 second as:
v^2 = u^2 + 2as = (1.4 m/s)^2 + 2(0 m/s^2)(1 s) = 1.96 m^2/s^2
v = sqrt(1.96 m^2/s^2) = 1.4 m/s
For the second time interval (1 to 1.5 s), the object's initial velocity is 1.4 m/s, and the acceleration is 1 m/s^2. We can calculate the final velocity after 0.5 seconds as:
v^2 = u^2 + 2as = (1.4 m/s)^2 + 2(1 m/s^2)(0.5 s) = 2.2 m^2/s^2
v = sqrt(2.2 m^2/s^2) = 1.5 m/s
For the third time interval (1.5 s onwards), the object's final velocity is the same as its velocity at the end of the second time interval (1.5 m/s), since there is no further acceleration.
Therefore, the object's speed after the force ends is 1.5 m/s.
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PLEASE HELPPP ASAP !!!!!!!!!!!!
Answers
Answer:
The answer would be the last option (the one with the arrow pointing sideways)
Explanation:
The arrow lost it's acceleration and is starting to go downwards but it isn't a straight slope down
in a large vacuum chamber, monochromatic laser light passes through a narrow slit in a thin aluminum plate and forms a diffraction pattern on a screen that is 0.620 mm from the slit. when the aluminum plate has a temperature of 20.0 ∘c∘c, the width of the central maximum in the diffraction pattern is 2.32 mmmm .
Answers
Without the information regarding the slit width or the coefficient of linear expansion of aluminum, it is not possible to determine the relationship between the slit width and the wavelength of the laser light.
In a large vacuum chamber, when monochromatic laser light passes through a narrow slit in a thin aluminum plate, it creates a diffraction pattern on a screen located 0.620 mm from the slit. The width of the central maximum in the diffraction pattern is measured to be 2.32 mm when the aluminum plate is at a temperature of 20.0 °C.
Diffraction refers to the bending of light waves around obstacles or through narrow openings. When light passes through a narrow slit, it spreads out and forms a pattern of bright and dark regions on a screen placed at a certain distance from the slit.
The width of the central maximum in the diffraction pattern can be determined using the formula:
w = (λ * D) / (s * L)
where:
w is the width of the central maximum
λ is the wavelength of the laser light
D is the distance between the slit and the screen
s is the width of the slit
L is the distance between the slit and the aluminum plate
In this case, we are given the width of the central maximum (w) as 2.32 mm, the distance between the slit and the screen (D) as 0.620 mm, and the temperature of the aluminum plate as 20.0 °C.
To find the wavelength of the laser light (λ), we need to use the formula:
λ = (2 * s * L) / w
Since the slit width (s) is not given, we cannot find the exact value of the wavelength. However, we can determine the relationship between the slit width and the wavelength.
By rearranging the formula, we get:
s = (w * λ) / (2 * L)
Since the temperature of the aluminum plate is given as 20.0 °C, we can use the coefficient of linear expansion of aluminum to calculate the change in length of the plate due to temperature. However, since we don't have the coefficient of linear expansion for aluminum or the initial length of the plate, we cannot calculate the change in length or the slit width accurately.
Without the information regarding the slit width or the coefficient of linear expansion of aluminum, it is not possible to determine the relationship between the slit width and the wavelength of the laser light.
The given information is insufficient to calculate the wavelength of the laser light or the exact relationship between the slit width and the wavelength. Additional information is required to obtain a more accurate answer.
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IP Silver pellet with a ma of 1. 2 g
g
and a temperature of 88 ∘C
∘
C
are added to 270 g
g
of water at 18 ∘C
∘
C
Answers
Hence, the value of Tfinal will be =18.01786 C
The temperature of the final mixture can be calculated using the law of conservation of energy, which states that the total energy of a system remains constant.
The change in energy of the water is equal to the heat absorbed by the water from the silver pellet.
Q = mcΔT
where Q is the heat absorbed,
m is the mass of the water,
c is the specific heat capacity of water,
and ΔT is the change in temperature.
The heat absorbed by the water can be calculated as follows:
Q = mcΔT = 270 g * 4.18 J/g°C * (Tfinal - 18°C) = mcΔT
The heat absorbed by the water can be calculated as follows:
Q = mcΔT = 1.2 g * 0.24 J/g°C * (88°C - Tfinal) = mcΔT
Solving for Tfinal, we get:
Tfinal = 18°C + (Q / mc)
= 18°C + [1.2 g * 0.24 J/g°C * (88°C - Tfinal)] / [270 g * 4.18 J/g°C]
=18 + [1.2*0.24*(88-18)]/[270*4.18]
=18+(20.16/1128.6)
=18+0.01786
=18.01786 C
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(b) What is the probability that the electron can be detected in the middle one third of well, region (b)
Answers
In order to determine the probability that an electron can be detected in the middle one-third of a well region, we need to take into account the wave function and the boundary conditions.The wave function represents the probability density of finding the electron in a particular location within the well. The boundary conditions are determined by the geometry of the well, which can be rectangular, triangular, or other shapes.
The Schrodinger equation is used to calculate the wave function and determine the probability density of finding the electron in a particular location. The wave function is a complex function that describes the position and momentum of the electron. It is also used to calculate the energy of the electron in the well.The probability of finding the electron in the middle one-third of the well can be determined by integrating the probability density over the middle one-third of the well region. This will give us the probability of finding the electron in that region. The integral can be evaluated using numerical methods or analytical methods, depending on the complexity of the wave function and the boundary conditions.In general, the probability of finding the electron in the middle one-third of the well will depend on the shape of the well, the energy of the electron, and the boundary conditions. For example, if the well is rectangular and the electron is in the ground state, then the probability of finding the electron in the middle one-third of the well will be high. However, if the well is triangular and the electron is in an excited state, then the probability of finding the electron in the middle one-third of the well will be lower.For such more question on probability
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the Arabic word of force is
I need an help
Answers
فرض
Please mark my answer as brainlist..
On monday, hank drove to work at an average speed of 70\:km/h70km/h and arrived 11 minute late. on tuesday, he left at the same time and took the same route. this time he drove at an average speed of 75\:km/h75km/h and arrived 11 minute early. how long is his route to work
Answers
Hank's distance to work is 17.5 kilometers long.He drove at an average speed of 70 km/h on Monday and arrived 11 minutes late.He drove at an average speed of 75 km/h on Tuesday and arrived 11 minutes early.
What is the distance of Hank's route to work?To find the distance of Hank's route, we can use the concept of average speed and time. Since the time taken to travel on both days is the same (11 minutes), the difference in arrival time can be attributed to the difference in speed. The speed difference is 5 km/h (75 km/h - 70 km/h). Considering that the time difference is 22 minutes (11 minutes late on Monday and 11 minutes early on Tuesday), we can use the formula: Speed = Distance / Time. Solving for the distance, we get 17.5 kilometers (5 km/h * 22 minutes / 60 minutes).
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A man standing on a lift throws a ball upwards with the maximum initial velocity he can and is found to be equal to 55 m/s. After what time the ball returns to his hand if (a) the lift is stationary, (b) the lift is moving up with a uniform velocity of 7 m/s, (c)the lift is moving down with a velocity of 7 m/s. Also given g = 9.8 m/s2
Answers
5
Drag each tile to the correct box.
Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocity for each leg of the trip.
Then arrange the legs of the trip from highest velocity to lowest:
Leg Distance (km) Time (min)
A 18
9
B 25
15
C С 24
8
D
48
12
E
15
7
leg A
leg B
leg C
leg D
leg E
Reset
Next
Answers
2) C
3) E
4) A
5) B
Answer:
1) D
2) C
3) E
4) A
5) B
Explanation:
Hope this help!
Calculate the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15. 0 seconds. Express the power both in
units of watts and horsepower.
Answers
The power required to move the automobile to the top of the hill is 130,666.67 watts or 175.41 horsepower.
The power required to move an object can be calculated using the formula: power = work / time.
First, let's calculate the work done in lifting the automobile to the top of the hill. The work done against gravity is given by the formula: work = force × distance.
The force required to lift the automobile is equal to its weight. The weight of an object is given by the formula: weight = mass × acceleration due to gravity.
Substituting the given values, we have: weight = 2,000 kg × 9.8 m/s^2 (acceleration due to gravity) = 19,600 N.
The distance the automobile is lifted is 100 meters.
Therefore, the work done against gravity is: work = 19,600 N × 100 m = 1,960,000 J (joules).
The time taken to reach the top of the hill is given as 15.0 seconds.
Now, we can calculate the power using the formula: power = work / time.
power = 1,960,000 J / 15.0 s = 130,666.67 W (watts).
To convert watts to horsepower, divide the power in watts by 746 (1 horsepower = 746 watts).
power in horsepower = 130,666.67 W / 746 = 175.41 hp (horsepower).
Rounding to two decimal places, the power required to move the automobile to the top of the hill is approximately 130,666.67 watts or 175.41 horsepower.
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The to problem of calculating the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is given
Given, Mass of the automobile, m = 2000 knight of the hill, h = 100 time, t = 15.0 the gravitational potential energy of the automobile when at the bottom of the hill is equal to the work done in lifting it up the hill
.W = mgh= (2000 kg) (9.81 m/s²)
(100 m)= 1,962,000 J
Power is defined as the rate at which work is done, or the work per unit time. Therefore,
Power = Work / Time= 1,962,000 J / 15.0 s
= 130,800 WIn horsepower, Power = (130,800 W) / (746 W/hp)
= 175.3 hp
Therefore, the required power to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is 130,800 W or 175.3 hp.
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The density (in g/cm3) of a solid metal object that has a volume of 1.24 cm3 and a mass of 21.8 g is ________.
Answers
The density of the solid metal object is 17.58 g/cm3.
The density (in g/cm3) of a solid metal object that has a volume of 1.24 cm3 and a mass of 21.8 g is 17.58 g/cm3 (rounded to two decimal places).
Explanation:
We know that density is the mass per unit volume of an object. Hence, to determine the density of a solid metal object, we divide the mass by the volume.
Using the formula: \[\text{Density} = \fraction{\text{Mass}}{\text{Volume}}\]Given that the volume of the object is 1.24 cm3 and the mass is 21.8 g, we substitute the values into the formula: \[\text{Density} = \fraction{21.8 \text{ g}}{1.24 \text{ cm}^3}\]Dividing the numerator by the denominator, we get: \[\text{Density} = 17.58 \fraction{\text{g}}{\text{cm}^3}\]
Therefore, the density of the solid metal object is 17.58 g/cm3.
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pls help me with this question
Answers
Answer:
16 ms2 is the answer for this question
Which term best describes the basic unit that makes up all matter?
O A. Atomic nuclei
O B. Protons
O C. Atoms
O D. Molecules
Answers
Answer:
C. Atoms
Explanation:
The basic unit of matter and the smallest, indivisible unit of a chemical element. It comprises a nucleus (neutrons + protons) that is surrounded by a cloud of electrons.
Question 5 of 34
Which of the following terms applies to motion that is always along the same
straight line?
A. Three-dimensional motion
B. Projectile motion
C. Two-dimensional motion
D. One-dimensional motion
Answers
Answer: D. One-dimensional motion
Explanation:
Answer:
D.one dimensional motion
(Table 310-15(a)(16)):What is the ampacity of No. 8 THHN conductors when installed in a walk in cooler if the ambient temperature is 50F?
Answers
According to Table 310-15(a)(16) of the National Electrical Code (NEC), the ampacity of No. 8 THHN conductors for a temperature of 50°F is 50 amperes.
However, the ampacity of the conductors depends on other factors as well, such as the length of the conductors, the type of insulation used, the number of conductors in the conduit, and the ambient temperature of the location where the conductors are installed. It is important to properly size the conductors based on all these factors to ensure safe and efficient operation of the electrical system.
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Based on the law of conservation of energy, which statement is correct?
Answers
Answer:
You kinda left out the options you want us to choose from.
Resend the question with Full details
Which quantities are scalars?
Answers
Answer:
Speed and distance are examples of scalar quantities.
Answer:
d
Explanation:
easy hope it helps#CARRYONLEARNING!the condition in which certain colors are diminished as depth increases is called:
Answers
The condition in which certain colors are diminished as depth increases is called color attenuation. This refers to a phenomenon where colors become less vibrant and fade as the distance between the observer and the object increases.
This happens due to the scattering of light by particles in the atmosphere, which reduces the intensity of the light and alters the color perception of the viewer.
As a result, the colors of objects that are far away appear less vivid and washed out, while those that are closer look brighter and more saturated. This effect is particularly noticeable in outdoor scenes where the distance between objects is significant.
The degree of color attenuation depends on the distance between the viewer and the object, the angle of incidence of the light, the quality of the atmosphere, and the presence of any obstructions that might block or reflect light.
Color attenuation is a common phenomenon in outdoor photography and can be used to create depth and dimension in images. Photographers often use color correction techniques to compensate for the loss of color and contrast that occurs when shooting at a distance.
In conclusion, color attenuation is the condition in which certain colors are diminished as depth increases. It is caused by the scattering of light by particles in the atmosphere, which reduces the intensity of light and alters the color perception of the viewer. This phenomenon is particularly noticeable in outdoor scenes and is commonly observed in photography.
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who conducted an experiment on conformity in which people were asked to judge the length of lines?
Answers
The experiment on conformity known as the "length of line" experiment was conducted by Solomon Asch in the 1950s.
In this experiment, participants were asked to judge the length of lines that were actually much longer or shorter than a standard line, and were asked to give their answer in a group setting where some other participants were confederates (i.e., actors) who gave obviously incorrect answers. The results of the experiment showed that many participants conformed to the incorrect answers given by the confederates, even when they knew the answers were incorrect. This demonstrated the power of social influence on individuals' perceptions and judgments.
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A materiel that allows electricity to flow easily is called an
Answers
A materiel that allows electricity to flow easily is called an conductor