Chemistry College

Water with a flowrate of 1 m3/min and benzene concentration of 150 mg/L flows through a 10 meter long, 0.1 m diameter steady state and conservative PFR, after which it is fed into a CMFR with a volume of 100 m3. A second water stream with a flowrate of 0.5 m3/min and benzene concentration of 150 mg/L is also fed into the CMFR. The CMFR is steady state and conservative. Calculate the effluent concentration of the CMFR.

Answers

Answer 1

Answer:

the effluent concentration of the CMFR is 150 mg/L

Explanation:

Given that;

flowrate of first water Q₁ = 1 m³/min

benzene concentration C₁ = 150 mg/L

flowrate of second water Q₂ = 0.5 m3/min

benzene concentration C₂ = 150 mg/L

To Calculate the effluent concentration of the CMFR, we use the expression;

$C_{effluent}$ = (Q₁C₁ + Q₂C₂) / Q₁ + Q₂

we substitute

$C_{effluent}$ = (1 × 150 + 0.5 × 150) / 1 + 0.5

$C_{effluent}$ = 225 / 1.5

$C_{effluent}$ = 150 mg/L

Therefore, the effluent concentration of the CMFR is 150 mg/L

Related Questions

If I have 20 ml of 0.10 M acetic acid mixed with 15 ml of 0.10 M sodium acetate and 15 ml of water how do I find the pH?

Answers

The buffer solution has a pH of 5.36.

How to find pH?

To find the pH of this buffer solution, use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa = dissociation constant of acetic acid, [A⁻] = concentration of acetate ions, and [HA] = concentration of acetic acid.

Calculate the concentrations of acetate ions and acetic acid in the solution.

The initial moles of acetic acid are:

moles of acetic acid = volume of acetic acid x concentration of acetic acid

moles of acetic acid = 0.020 L x 0.10 mol/L

moles of acetic acid = 0.002 mol

After mixing with sodium acetate, the total volume of the solution is 50 mL, so the concentration of acetic acid and acetate ions are:

[HA] = moles of acetic acid / total volume of solution

[HA] = 0.002 mol / 0.050 L

[HA] = 0.040 M

[A⁻] = concentration of sodium acetate

[A⁻] = 0.10 M

The dissociation constant of acetic acid is pKa = 4.76.

Now, substitute these values into the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

pH = 4.76 + log(0.10/0.040)

pH = 4.76 + 0.60

pH = 5.36

Therefore, the pH of the buffer solution is 5.36.

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Draw a plausible transition state for the bimolecular reaction of nitric oxide with ozone. Use dashed lines to indicate the atoms that are weakly linked together in the transition state.No(g) + o3(g) --> NO2(8) + O2(g)

Answers

One weakly bound intermediate is formed between the oxygen atom of O3 and one of the nitrogen atoms of NO, and another weakly bonded is formed between the oxygen atom of O3 and the nitrogen atom of NO.

Draw a plausible transition state for the bimolecular reaction of nitric oxide with ozone.

The bond between nitrogen and oxygen in NO is partially broken, while the bond between the two oxygen atoms in O3 is also partially broken. The bonds between nitrogen and oxygen in NO2 and between the two oxygen atoms in O2 are partially formed.

How do ozone and nitric oxide interact?

Nitric oxide and ozone then easily combine to form nitrogen dioxide and oxygen. No net ozone gain occurs as a result of the technique mentioned above. Concentrations are higher in the troposphere than can be explained by these processes alone.

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A reaction mixture in a 3.51 l flask at a certain temperature initially contains a mixture of 0.864 grams of h2 and 103.7 grams of i2. at equilibrium, the flask contains 92.3 grams if hi. calculate the equilibrium constant for this reaction at this temperature. show your work.

Answers

The equilibrium constant for this reaction Kc is 153.

Data;

mass of hydrogen = 0.864gmass of iodine = 103.7gmass of hydrogen iodide = 92.3gvolume of mixture = 3.51L

Number of Moles

Let us calculate the number of moles of each of the entity.

Number of moles of hydrogen

$n = \frac{mass}{molar mass}\\n = \frac{0.864}{2} = 0.432 moles$

Number of moles of Iodine

$n = \frac{103.7}{253.8} = 0.409 moles$

Number of moles of HI

$n = \frac{92.3}{127.9} = 0.722 moles$

Equation of Reaction

$H_2 + I_2 \to 2HI$

0.432 0.409 0 (Before reaction starts)

(0.432 - x) (0.409 -x) 2x (After the reaction)

$2x = 0.722 moles \\x = 0.361 moles$

At Equilibrium

At equilibrium moles of H2 would be

$0.432 - x = 0.432 - 0.361 = 0.071 moles$

The concentration of hydrogen would be

$conc. = \frac{moles}{volume}\\conc. = \frac{0.071}{3.51}\\ conc. = 0.020M$

The concentration of iodine would be

$conc. of I_2 = \frac{0.409 - 0.361}{3.51}= 0.01367M$

The concentration of hydrogen iodide would be

$conc. = \frac{0.722}{3.51}\\ conc. = 0.206M$

Equilibrium Constant

This is given by

$K_c = \frac{[HI]^2}{[H_2][I_2]}$

substituting the value of the concentration

$K_c = \frac{[0.20]^2}{[0.020][0.01367]}\\K_c = 153$

From the calculations above, the equilibrium constant for this reaction Kc is 153.

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The decomposition of cyclohexane to benzene and Martialism is a high mass transfer limited period on the planet. The reaction will be carried out in a tubular reactor with an internal diameter of 5 cm and a length of 20 m; the pipes are filled with cylindrical pellets 0.5 cm in diameter and 0.5 cm in length. The pellets are only covered with the outer surface coating. The filled bed porosity is 40%. The inlet flow rate is 60 dm3/min.

Plot the tubular length vs. conversion graph when the inlet gas stream contains 5% cyclohexane and 95% hydrogen at 2 atm and 500°C. What would be the required tubular length for 99.9% conversion?

For cyclohexane diffusion in hydrogen, use the Fuller, Schettler, and Giddings Correlation given below.

Answers

The required tubular length for 99.9% conversion is 116.84 meters.

On Earth, the rate at which cyclohexane reacts with benzene and methylcyclopentane is constrained by high mass transfer.

A tubular reactor with an internal diameter of 5 cm and a length of 20 m will be used to conduct the reaction, and cylindrical pellets with dimensions of 0.5 cm in diameter and 0.5 cm in length will be placed within the reactor's pipes.

Only the exterior surface of the pellets are coated.

The packed bed has a 40% porosity and a 60 dm3/min intake flow rate.

When the intake gas stream includes 5% cyclohexane and 95% hydrogen at 2 atm and 500°C, the tubular length vs. conversion graph should be drawn.

The graph may be used to identify the minimum length of tube necessary for 99.9% conversion.

For cyclohexane diffusion in hydrogen, the Fuller, Schettler, and Giddings Correlation is as follows:

a = 0.8854,

b = 1.764102,

C = 6.0231023.

The tube length vs. conversion graph may be displayed at 2 atm and 500°C when the incoming gas stream includes 5% cyclohexane and 95% hydrogen.

The following equation may be used to determine the rate of reaction:

ra=2.31011 exp[-88580/RT]C_A(1X)/3

The mole balancing equation for an isothermal tubular reactor is given as

dX/dL = -ra/C A,

where X is the conversion and L is the length.

To determine the length of the tubular reactor needed for a specific conversion X, we can integrate the aforementioned equation from X = 0 to X = X.

We must numerically calculate the following equation to obtain the necessary tube length for 99.9% conversion:

∫0.999L0−ra/CA

dL=0.999XEq L

for X=0.999

After rearranging the equation above, we get:

0.999L0ra/CA

dL=XX Eq

The aforementioned equation is integrated to give us

L = 116.84 m.

Therefore, the required tubular length for 99.9% conversion is 116.84 meters.

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What part of the scientific method involves controlling variables while testing a hypothesis? (2 points) Select one: a. Analyzing data b. Conducting an experiment c. Drawing a conclusion d. Making observations

Answers

Answer:

Explanation:

best choice, makes the most sense

In the scientific method, conducting an experiment involves designing and performing controlled experiments to test a hypothesis and the correct option is option B.

Scientists manipulate the independent variable while controlling other variables (dependent and controlled variables) to observe and measure the effect on the dependent variable.

By controlling variables, scientists can isolate the factors that influence the outcome, ensuring that any observed changes are a result of the manipulated variable and not other unrelated factors. This step allows for the collection of reliable data, which is essential for drawing meaningful conclusions based on the evidence gathered from the experiment.

Thus, the ideal selection is option B.

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7: How many times can a cell divide?

Answers

Explanation:

60 times and it matters why they need to in order to divide

Give the systematic name for each of the following organic molecules and enter it in the space provided. Be sure to include appropriate punctuation.

Answers

Systematic name : 5-chloro-2-pentanol (or 5-chloropentan-2-ol)

Systematic name : 1,2-difluoro-3-heptanol (or 1,2-difluoroheptan-3-ol).

What is pentanol used for?

The active site of numerous reactions is the hydroxyl group (OH). Pentyl butyrate, which has an apricot-like aroma, is the ester that results from the reaction of 1-pentanol and butyric acid. Amyl acetate, also known as pentyl acetate, is the ester that is created when 1-pentanol and acetic acid are combined.

A research evaluating the efficacy of diesel fuel blends with different amounts of pentanol as an additive was done in 2014. Higher pentanol concentrations resulted in higher gaseous emissions at the expense of lower particulate emissions.

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The typical dosage of statin drugs for the treatment of high cholesterol is 10 mg. Assuming a total blood volume of 4.5 L, calculate the concentration of drug in the blood in units of % (w/v)

Answers

Answer:

1.904 ppm

Explanation:

Concentration of drug in units of ppm = mass of solute / (mass of solution ) × 1000000

mass of blood = density of blood × volume = 1.05 g / ml × 5000 ml = 5250 g

mass of solution = mass of blood + mass of solute ( statin) = 5250 + 0.01 g = 5250.01 g

Concentration of drug in units of ppm = (0.01 g / 5250.01 g) × 1000000 = 1.904 ppm

I hope this helps!!

The rate of the reaction is 1.6*10-2 M/s when the concentration of A is 0.15 M. Calculate the rate constant if the reaction is (a) first order in A and (b) second order in A.

Answers

Answer:

$k_1=0.107s^{-1} \\\\k_2=0.711M^{-1}s^{-1}$

Explanation:

Hello there!

In this case, according to the given information and the attached picture in which we can see the units of the rate constant, it turns out possible for us to realize the two called rate laws are:

$r=k[A]\\\\r=k[A]^2$

The former is first-order and the latter second-order; in such a way, we solve for the rate constant in both cases to obtain the following:

$k=\frac{r}{[A]}=\frac{1.6x10^{-2}M/s}{0.15M}=0.107s^{-1} \\\\k=\frac{r}{[A]^2}=\frac{1.6x10^{-2}M/s}{(0.15M)^2}=0.711M^{-1}s^{-1}$

Regards!

The rate of the reaction is 1.6*10-2 M/s when the concentration of A is 0.15 M. Calculate the rate constant

Identify the substance that has formula mass of 133.5amu.
(a) MgCI
b)SCI
c)BCI
D) AICI

Answers

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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What is the number of moles in .025g (NH4)2Cr2O7?

Answers

Answer:

252.06492

Explanation:

How many grams (NH4)2Cr2O7 in 1 mol? The answer is 252.06492.

We assume you are converting between grams (NH4)2Cr2O7 and mole.

You can view more details on each measurement unit:

molecular weight of (NH4)2Cr2O7 or mol

The SI base unit for amount of substance is the mole.

1 grams (NH4)2Cr2O7 is equal to 0.0039672319337415 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams (NH4)2Cr2O7 and mole.

Type in your own numbers in the form to convert the units!

What is the balanced chemical
reaction for the synthesis of
carbon with hydrogen?

Answers

The balanced chemical reaction for the synthesis of carbon with hydrogen is CH₄ = C + 2H₂

Balanced chemical equation explained

Balance chemical equation refers to chemical reactions in which the moles and atoms on both the reactant side and product side are the same.

It is a way of balancing chemical equation in which the atoms of each chemicals on the product and reactant are the same.

The balanced chemical reaction for the synthesis of carbon with hydrogen is CH₄ = C + 2H₂

In this reaction, one molecule of methane is formed by combining one atom of carbon with two molecules of hydrogen gas.

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Which portion of a molecule of F2O has partial positive charge?
Question 3 options:

A)

The F atoms

B)

The central O atom

C)

The partial charge on each atom is zero

D)

The partial charge on each atom is negative

Answers

The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B

The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of $F_2O$, fluorine (F) is more electronegative than oxygen.

Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.

In $F_2O$, each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.

Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.

Option B

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What mass (grams) of antimony(III) chloride would be produced by reacting with 112 liters of chlorine measured at STP?

Answers

Answer:

radius = 16 in ; height = 27 in

1.) How many photons are produced in a laser pulse of 0.643 J at 575 nm?
2.)A certain rifle bullet has a mass of 5.01 g. Calculate the de Broglie wavelength of the bullet traveling at 1649 miles per hour. Consult the table of physical constants as needed.
3.) What element forms an ion with an electronic configuration of [Ne] and a −2 charge?

Answers

Answer:

A typical laser pulse used in MALDI is about 60 microjoules/pulse at 337 nm. At 337 nm the power is about 6 x 10^-19 J/photon. Doing the math suggests that of 10^14 photons are in a typical desorption pulse

Explanation:

pls help I’ll give brainly

Answers

Agrias the answer is

What is the molar mass of a gas that diffuses three times faster than oxygen under similar conditions

Answers

Answer:

288 g/mol

Explanation:

What is diffusion?

• It is a process whereby the random motion of particles move from a region of higher concentration to a region of lower concentration.

Graham's law of diffusion of gas

• states that at constant conditions of temperature and pressure, the rate of diffusion of gases is inversely proportional to the square root of their molar masses

$\boxed{ \frac{Rate_1}{Rate_2} = \sqrt{ \frac{M_2}{M_1} } } $

Calculations

Oxygen exist as O₂ at room temperature, thus its molar mass is 2(16)= 32.

Let the rate of O₂ be Rate₁, while the rate and molar mass of the unknown gas be Rate₂ and M₂ respectively.

Since O₂ diffuses 3 times as fast as the unknown gas,

Rate₁= 3(Rate₂)

$\frac{Rate_1}{Rate_2} = 3 $

$ 3 = \sqrt{ \frac{M_2}{32} } $

$ \sqrt{ \frac{M_2}{32} } = 3$

Square both sides:

$ \frac{M_2}{32} = 3^{2} $

$ \frac{M_2}{32} = 9$

Multiply both sides by 32:

M₂= 9(32)

M₂= 288

What is the molar mass of a gas that diffuses three times faster than oxygen under similar conditions

Question 18 (1 point)
What is the pH of a buffer that is 0.086 M HF and 0.386 M LiF? The K₂ for HF is 3.5
x 10-4.
Your Answer:
Answer

Answers

The pH of a buffer that is 0.086 M HF and 0.386 M LiF when the K₂ for HF is 3.5x 10-4 is 2.802

The pH of a buffer solution is given by Henderson Hasselback equation.

pH=pKa+log[A-]/[HA]

Substituting the values, we get

pH=-log(3.5x10^-4)+log(0.086/0.386)

pH=-log(3.5x10^-4)-0.653

pH=3.455-0.653

pH=2.802

pH is the potenz of hydronium ion.It tells the acidic strength of a compound.Buffer solution resists the change in pH on the addition of weak acid or base and conjugate of weak acid or base.It is used in acid-base chemistry.Buffer solutions are used for keeping the pH at a constant value.

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areas and organisms where carbon is stored

Answers

Answer:

Carbon is stored on our planet in the following major sinks (1) as organic molecules in living and dead organisms found in the biosphere; (2) as the gas carbon dioxide in the atmosphere; (3) as organic matter in soils; (4) in the lithosphere as fossil fuels and sedimentary rock deposits such as limestone, dolomite

What happens to the number of protons in a cation?

Answers

Answer:

number of protons is more than the number of electrons.

Explanation:

A cation is a positively charged ion.

An ion is an atom that has lost or gained electron(s). In an ion, the number of protons and electrons are not the same.

Number of protons is the number of positively charged particles

Number of electrons is the number of negatively charged particles.

For a cation, which is positively charged, the number of protons is more than the number of electrons.

Therefore, in cations, we have more protons than electrons.

100 POINTS & BRAINLIEST !!!! PLEASE HELP

Answers

Carbon, C, P Block, 2, 6, 12.0107u. 6 protons, 6 electrons, 6 neutrons

Helium, He, S Block, 1, 2, 4.0026u, 2 protons, 2 electrons, 2 neutrons

Germanium, Ge, P Block, 4, 32, 72.64u, 32 protons, 32 electrons, 41 neutrons

Oxygen, O, P Block, 2, 8, 16u, 8 protons, 8 electrons, 8 neutrons

Scandium, Sc, D Block, 4, 21, 44.9559u, 21 protons, 21 electrons, 24 neutrons

Tellurium, Te, P Block, 5, 52, 127.60u, 52 protons, 52 electrons, 76 neutrons

Hydrogen, H, S Block, 1, 1, 1.008u, 1 proton, 1 electron, 0 neutrons

Iron, Fe, D Block, 4, 26, 55.845u, 26 protons, 26 electrons, 30 neutrons

Beryllium, Be, S Block, 2, 4, 9.012u, 4 protons, 4 electrons, 5 neutrons

Vanadium, V, D Block, 4, 23, 50.942u, 23 protons, 23 electrons, 28 neutrons

Silver, Ag, D Block, 5, 47, 108u, 47 protons, 47 electrons, 61 neutrons

Gallium, Ga, P Block, 4, 31, 69.723u, 31 protons, 31 electrons, 39 neutrons

Bromine, Br, P Block, 4, 35, 79.904u, 35 protons, 35 electrons, 45 neutrons

Fluorine, F, P Block, 2, 9, 18.998u, 9 protons, 9 electrons, 10 neutrons

Manganese, Mn, D Block, 4, 25, 54.938u, 25 protons, 25 electrons, 30 neutrons

Strontium, Sr, S Block, 5, 38, 87.62u, 38 protons, 38 electrons, 50 neutrons

Francium, Fr, S Block, 7, 87, 223u, 87 protons, 87 electrons, 136 neutrons