Water enters and leaves a pump in pipelines of the same diameter and approximately the same elevation. If the pressure on the inlet side of the pump is 30 kPa and a pressure of 500 kPa is desired for the water leaving the pump, what is the head that must be added by the pump

The watercraft in the crossing are given with the responsibility to the starboard side to give the way and avoid collision.

The crossing rules are given as the safety rules that are mediated in order to avoid the collision accidents when the two vehicles are crossing the path.

In the sea, the rules are given with the watercraft at the starboard side or the giveaway side to make the way to the other watercraft and avoid collision.

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Answer:

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Explanation:

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The Bernoulli equation is an important principle in fluid mechanics that relates pressure, velocity, and elevation of an incompressible fluid. According to this equation, the sum of the pressure, kinetic energy, and potential energy at any point in a fluid system must remain constant, assuming no external forces or energy losses.

When the velocity of an incompressible fluid increases, the kinetic energy of the fluid increases, which means that the pressure must decrease in order to maintain the constant sum of pressure, kinetic energy, and potential energy. This relationship is known as the Bernoulli principle and is often used to explain the behavior of fluids in motion.

To demonstrate this principle mathematically, we can use the Bernoulli equation in its simplest form, which states:

P + 0.5 * ρ * v^2 + ρ * g * h = constant

Where P is the pressure, ρ is the density, v is the velocity, g is the acceleration due to gravity, and h is the elevation. Assuming no change in elevation, we can simplify this equation to:

P + 0.5 * ρ * v^2 = constant

If we consider a fluid flowing through a horizontal pipe with a decreasing cross-sectional area, we can apply the Bernoulli equation to two points along the pipe: the wider section with lower velocity (point 1) and the narrower section with higher velocity (point 2).

At point 1, we have:

P1 + 0.5 * ρ * v1^2 = constant

At point 2, we have:

P2 + 0.5 * ρ * v2^2 = constant

Since the fluid is incompressible, its density remains constant throughout the system. Therefore, we can subtract the two equations to eliminate the constant and rearrange to solve for the pressure difference:

P2 - P1 = 0.5 * ρ * (v1^2 - v2^2)

Since v2 > v1, we can see that the term (v1^2 - v2^2) is negative, which means that the pressure difference (P2 - P1) must also be negative. This shows that the pressure must decrease in the direction of flow if the velocity increases, assuming no change in elevation.

In summary, the Bernoulli equation demonstrates that for an incompressible substance, the pressure must decrease in the direction of flow if the velocity increases, assuming no change in elevation. This relationship is fundamental to our understanding of fluid dynamics and is used in many engineering applications.

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Answer:

  μ ≈ 0.408

Explanation:

The coefficient of friction is the ratio of friction force to normal force. The normal force is ...

  F = mg = (2500 kg)(9.8 m/s²) = 24.5 kN

Then the coefficient of friction (μ) is ...

  μ = (10 kN)/(24.5 kN) ≈ 0.408

The right components for gsm architecture that consists of the hardware or physical equipment such as digital signal processors, radio transceiver, display, battery, case and sim card is the Mobile station.

In GSM, a cell station includes 4 fundamental additives: Mobile termination (MT) - gives not unusualplace features consisting of: radio transmission and handover, speech encoding and decoding, blunders detection and correction, signaling and get right of entry to to the SIM. The IMEI code is connected to the MT.

Under the GSM framework, a cell tele cell smartphone is called a Mobile Station and is partitioned into  wonderful additives: the Subscriber Identity Module (SIM) and the Mobile Equipment (ME).

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The three types of irony are Verbal Irony, Situational Irony, and Dramatic Irony.

Example of Verbal Irony:

Example of Situational Irony:

Example of Dramatic Irony:

What is Irony?

When something unexpected occurs, it is ironic. The thing opposite to what we anticipate usually occurs, and this is either humorous or dramatic.

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Answer:

Shelf life.

Explanation:

In Business, an inventory is a term used to describe a list of finished goods, goods still in the production line and raw materials that would be used for the manufacturing of more goods in a bid to meet the unending consumer demands.

Simply stated, an inventory can be classified into three (3) main categories; finished goods, work in progress, and raw materials.

An inventory is recorded as a current asset on the balance sheet because it's primarily the most important source of revenue for a business entity.

Also, the three (3) main cost concept associated with an inventory are;

1. First In First Out (FIFO).

2. Last In First Out (LIFO).

3. Weighted average cost.

Shelf life can be defined as a measure of the length of time that a particular product could be kept or stored without it getting bad or becoming unsuitable for use by the consumers. Thus, the shelf life of a product is largely dependent on its expiration date.

Hence, merchandise without an expiration date like electronics, tools and home goods typically have a longer shelf life.

Answer:

Explanation:

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged.

The maximum speed of mass A is 101 m/s, and the maximum acceleration of mass A is 10202 m/s2. Maximum velocity is the greatest speed that an object may travel at while in motion.

The displacement function's first and second derivatives with respect to time must be determined: x(t) = sin(0.1sin - cos(101t) (100t)

v(t) = 10cos - 101sin(101t) (100t)

v(t) = sqrt[(-101sin(101t))2 + (-10cos(100t))2] where a(t) = -1012cos(101t) + 1000sin(100t).

is equal to sqrt[10201sin2(101t) + 100cos2(100t)].

When sin(101t) = 1 and cos(100t) = 0, which occurs at t = n/101 for any integer n, |v(t)| reaches its greatest value. The greatest velocity is as follows:

Sqrt[10201 + 0] = |v|max = 101 m/s

|a(t)| = sqrt[(-1012cos(101t))2 + (1000sin(100t))2] is the acceleration function.

= sqrt[10210.2cos(101t) + 10210.6sin(100t)]

The highest value of |a(t)| occurs at t = (2n + )/202 and t = n/100 for any integer n, respectively, when cos(101t) = 1 and sin(100t) = 1. Hence, |a|max = sqrt is the maximum acceleration. [10201^2 + 10^6] = 10202 m/s^2

Consequently, mass A's maximum velocity is 101 m/s, while the maximum velocity of mass B is Mass A accelerates at 10202 metres per second.

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According to technician b, in a fuel cell, electrons move from the anode to the cathode. is accurate in its assertion.

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The phrase "system of rules where symbols represent actions" sums up programming languages the best.

Symbols that represent actions are used in a computer language's set of rules. Programming languages are the set of instructions that a computer uses to carry out projects. A programming language is a vocabulary and a set of grammatical rules for telling a computer or other computing equipment to carry out particular tasks.

High-level languages such as BASIC, C, C++, COBOL, Java, FORTRAN, Ada, and Pascal are typically referred to as programming languages. instruction. The principles that specify how a language is structured are known as syntax. In computer programming, syntax refers to the rules that govern how words, punctuation, and symbols are organized in a programming language. To define algorithms or write programs to control a machine's behavior, programmers utilize programming languages.

Therefore the correct answer is option A ) A set of rules where symbols represent actions.

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Active listening involves not only absorbing what is said, but also engaging with the topic in a noticeable way.

This can include asking clarifying questions, summarizing the speaker's points, and expressing empathy or understanding.

Simply sitting quietly and absorbing information is passive listening, rather than active listening. Engaging with the topic and the speaker shows that you are actively participating in the conversation and valuing their input.

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Answer:

The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.

Explanation:

We must estimate the monthly storage change of the lake by considering inflows, outflows, seepage and evaporation losses and precipitation. That is:

\(\Delta V_{storage} = V_{inflow} -V_{outflow}-V_{seepage}-V_{evaporation}+V_{precipitation}\)

Where \(\Delta V_{storage}\) is the monthly storage change of the lake, measured in cubic feet.

Monthly inflow

\(V_{inflow} = \left(30\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)

\(V_{inflow} = 77.76\times 10^{6}\,ft^{3}\)

Monthly outflow

\(V_{outflow} = \left(27\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)

\(V_{outflow} = 66.98\times 10^{6}\,ft^{3}\)

Seepage losses

\(V_{seepage} = s_{seepage}\cdot A_{lake}\)

Where:

\(s_{seepage}\) - Seepage length loss, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{seepage} = 1.5\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{seepage} = (1.5\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{seepage} = 2.86\times 10^{6}\,ft^{3}\)

Evaporation losses

\(V_{evaporation} = s_{evaporation}\cdot A_{lake}\)

Where:

\(s_{evaporation}\) - Evaporation length loss, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{evaporation} = 6\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{evaporation} = (6\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{evaporation} = 11.44\times 10^{6}\,ft^{3}\)

Precipitation

\(V_{precipitation} = s_{precipitation}\cdot A_{lake}\)

Where:

\(s_{precipitation}\) - Precipitation length gain, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{precipitation} = 4.25\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{precipitation} = (4.25\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{precipitation} = 8.10\times 10^{6}\,ft^{3}\)

Finally, we estimate the storage change of the lake during the month:

\(\Delta V_{storage} = 77.76\times 10^{6}\,ft^{3}-66.98\times 10^{6}\,ft^{3}-2.86\times 10^{6}\,ft^{3}-11.44\times 10^{6}\,ft^{3}+8.10\times 10^{6}\,ft^{3}\)

\(\Delta V_{storage} = 4.58\times 10^{6}\,ft^{3}\)

The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.

The volume of water gained and the loss of water through flow,

seepage, precipitation and evaporation gives the storage change.

Response:

Given parameters:

Area of the lake = 525 acres

Inflow = 30 ft.³/s

Outflow = 27 ft.³/s

Seepage loss = 1.5 in. = 0.125 ft.

Total precipitation = 4.25 inches

Evaporator loss = 6 inches

Number of seconds in a month is found as follows;

\(30 \ days/month \times \dfrac{24 \ hours }{day} \times \dfrac{60 \, minutes}{Hour} \times \dfrac{60 \, seconds}{Minute} = 2592000 \, seconds\)

Number of seconds in a month = 2592000 s.

Volume change due to flow, \(V_{fl}\) = (30 ft.³/s - 27 ft.³/s) × 2592000 s = 7776000 ft.³

1 acre = 43560 ft.²

Therefore;

525 acres = 525 × 43560 ft.² =  2.2869 × 10⁷ ft.²

Volume of water in seepage loss, \(V_s\) = 0.125 ft. × 2.2869 × 10⁷ ft.² = 2,858,625 ft.³

Volume gained due to precipitation, \(V_p\) = 0.354167 ft. × 2.2869 × 10⁷ ft.² = 8,099,445.123 ft.³

Volume evaporation loss, \(V_e\) = 0.5 ft. × 2.2869 × 10⁷ ft.² = 11,434,500 ft.³

Which gives;

ΔV = 7776000 - 2858625 + 8099445.123 - 11434500 = 1582823.123

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Answer:

The answer will be B i hope this helps

Answer:

i did not known answer but anobody help you

It is True to state that Materials requirement planning (MRP) enables a firm to make sure that the right amount of each material or component is available at the right time to satisfy its production needs.

Material needs planning is a manufacturing process management system that includes production planning, scheduling, and inventory control. Most MRP systems are software-based, however MRP may also be done by hand.

Material requirements planning (MRP) is a method of determining the materials and components required to produce a product.

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If the diameter of the bar is 0.490 at this load, determine I. the engineering stress and strain, and [2] II. the true stress and strain is 1561. 84 MPa.

Strain is a unitless degree of ways a great deal an item receives larger or smaller from an implemented load. Normal stress happens while the elongation of an item is in reaction to an everyday pressure (i.e. perpendicular to a surface), and is denoted via way of means of the Greek letter epsilon.

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Answer:

Explanation:

We are assuming that there is

a steady state two dimensional conduction

constant properties

uniform volumetric heat generation

From symmetry, we will be determining 6 unknown temperatures.

See attachment for calculation and and tabulation

With T(s) = 300 K, the set of equations were written directly into the IHT work space and solved for nodal temperatures.

The result is seen in the second attachment

Answer:

For most uses you'll want your water heated to 120 F(49 C) In this example you'd need a demand water heater that produces a temperature rise and it will take about 2 hours

To create the requested C program, we need to implement a menu-driven program that allows the user to enter 5 grades, calculate the student's average and letter grade, show the highest and lowest grade, and exit the program. We also need to validate the user's input and randomize the grades between 50-100.


To implement this program, we can use a switch statement that takes the user's input and calls the appropriate function. We can use a loop to repeat the program until the user decides to exit. For the first function, we can use a loop to validate the user's input and make sure it falls within the range of 0-100. For the second function, we can calculate the average of the grades and use a switch statement to assign the appropriate letter grade. For the third and fourth functions, we can use a loop to compare the grades and find the highest and lowest grades.


In conclusion, we can create a C program that meets the requirements of the problem statement by using a switch statement, loops, and appropriate functions. We can also randomize the grades and validate the user's input to ensure accurate results.

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Engineers take periodic site measurements to verify the scale conveys true information

measureants is the amount or extent of something ascertained through use of calibrated instrument called measuring instrument. When measurements are done on site it is called site measurements.

Engineers use the site measurements to scale their sketches hence to ensure the scale is always correct periodic measurements should be taken.

On-site measurements value and sketch measurement value gives the scale which  is the ratio, should be maintained always

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Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

Answer:

Explanation:

It is a device which consists of four layers and two terminals. The construction is almost the same as that of the transistor. But there are certain points which deviate from the construction from the transistor. The differentiating points are-

There is no base terminal in the DIAC

The three regions have almost the same level of doping

It gives symmetrical switching characteristics for either polarity of voltages

DIAC Diode

When you develop a web page, you use an HTML file to provide the structure, content, and formatting for the page. Option C is the correct answer.

The HTML file provides the structure, content and formats of the web page.

HTML stands for Hypertext Markup Language, and it is a standardized system for tagging text files in order to make them appear in a web browser. The web browser then reads the HTML and renders the page accordingly.

HTML tags are used to define the structure and content of the web page. Tags are enclosed in angle brackets and are added to the text to define how it should be rendered in the web browser. For example, the following HTML code structure and content.

<!DOCTYPE html>

<html lang="en">

<head>

<!-- Place to provide metadata, scripts, style, etc.-->

</head>

<body>

   <h1><b>Contenido de mi web<b></h1>

</body>

</html>

ConclusionThus, HTML provides the structure, content and formatting for a web page. It helps to define how the text, images, videos, and other media should be rendered in a web browser.

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The process in question is referred to as the iterative design process. Engineers utilize this method by completing and repeating a sequence of steps in order to continually improve and refine their designs as they work towards achieving the project goal. This approach allows for flexibility and adaptability in the design process, as engineers can make adjustments and modifications based on feedback and testing, ultimately leading to a more successful outcome.

Answer:

Relative roughness = 0.04

Explanation:

Given that:

Diameter = 5 cm

roughness = 2 mm

At inlet:

Minor coefficient loss \(k_{L1} = 0.4\)

At exit:

Minor coefficient loss \(k_{L2} = 1\)

Height h = 4m

Length = 5 m

To find the relative roughness:

Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:

\(e_r = \dfrac{e}{D}\)

\(e_r = \dfrac{0.2 }{5}\)

\(\mathbf{e_r = 0.04}\)

Answer:

improper imput validation

Explanation: