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Ruby is designing a new board game, and is trying to figure out all the
possible outcomes. How many different possible outcomes are there if
she flips a coin, rolls a fair die in the shape of a cube that has six sides
labeled 1 to 6, and spins a spinner with three equal-sized sections
labeled Walk, Run, Stop?
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The relationship between the variables c and b is c = \(\frac{50}{3}b\)

A variation is a relation between a set of values of one variable and a set of values of other variables. Direct variation. In the equation y = mx + b, if m is a nonzero constant and b = 0, then you have the function y = mx (often written y = kx), which is called a direct variation.

if c ∝ b

Then,

c = kb where k is a constant

When c = 50, b = 3

substituting into the equation above,

50 = 3k

k = 50/3

substitute k into the equation

c = \(\frac{50}{3}b\)

In conclusion c is related to b by the equation c = \(\frac{50}{3}b\)

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Answer:

9

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

the ratio is 4:1 on children to childcare workers not the other way around

Answer:

Step-by-step explanation:

Answer: 9 tickets

Step-by-step explanation:

the amount of ice that will melt from the beginning of day 1 to the beginning of day 4 can be found by integrating the rate of melting over that time period.


To find the amount of ice that melts over the time period from t=0 to t=3, we need to integrate the given rate of melting function, M(t)=4-sin^3 t, over that time period. Using the fundamental theorem of calculus, we can find the antiderivative of M(t):

∫M(t)dt = ∫(4-sin^3 t)dt = 4t + (3/4)cos(t) + (1/12)cos^3(t)

Evaluating this antiderivative from t=0 to t=3, we get:

(4(3) + (3/4)cos(3) + (1/12)cos^3(3)) - (4(0) + (3/4)cos(0) + (1/12)cos^3(0))

Simplifying this expression, we get:

12 + (3/4)cos(3) + (1/12)cos^3(3) - (3/4)

Therefore, the amount of ice that will melt from the beginning of day 1 to the beginning of day 4 is approximately 11.56 acre-feet.

we can find the amount of ice that will melt over a given time period by integrating the rate of melting function over that time period. In this case, we found that approximately 11.56 acre-feet of the ice field will melt from the beginning of day 1 to the beginning of day 4.

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The total number of rankings is the product of the number of students at each step. Total number of different rankings possible = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 10! ≈ 3.6 × 10^6.

Given that an introductory statistics class has 4 freshmen and 6 sophomores. The students are ranked based on their performance. Therefore, it is required to find the number of different rankings possible. Step 1: Find the total number of students in the class. Total number of students in the class = number of freshmen + number of sophomores = 4 + 6 = 10Step 2: Find the number of ways to select the first-ranked student. There are 10 students to choose from for the first position. Therefore, the number of ways to select the first-ranked student is 10.Step 3: Find the number of ways to select the second-ranked student. There are 9 students remaining after selecting the first-ranked student. Therefore, the number of ways to select the second-ranked student is 9.Step 4: Find the number of ways to select the third-ranked student.There are 8 students remaining after selecting the first two-ranked students.

Therefore, the number of ways to select the third-ranked student is 8.Step 5: Continue the process until all students are ranked. The total number of rankings is the product of the number of students at each step.Total number of different rankings possible = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 10! ≈ 3.6 × 10^6.

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To stretch a spring 1 ft. from its natural length, a 15 ft-lb work is needed. To stretch a spring 6 in. from its natural length, the required work is 3.75 ft-lb

The work done on a spring is given by the formula:

W = 1/2 . kx²

Where:

k = spring constant

x = spring displacement

From the formula, we know that the work is directly proportional to the square of displacement, or mathematically:

                W ∝ x²

Therefore,

W₁ : W₂ = x₁² : x₂²

Data from the problem

W₁ = 15 ft-lb

x₁ = 1 ft

x₂ = 6 in. = 0.5 ft

Hence,

15 : W₂ = 1² : 0.5²

W₂ = 0.25 x 15 = 3.75 ft-lb

Hence, the required work to stretch the spring 6 in beyond its natural length is 3.75 ft-lb

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Answer:

its only 5 points tho :c

Step-by-step explanation:

The number of regions created when constructing a Venn diagram with three overlapping sets is 8.

In a Venn diagram, each set is represented by a circle, and the overlapping regions represent the elements that belong to multiple sets.

When three sets overlap, there are different combinations of elements that can be present in each region.

For three sets, the number of regions can be calculated using the formula:

Number of Regions = 2^(Number of Sets)

In this case, since we have three sets, the formula becomes:

Number of Regions = 2^3 = 8

So, when constructing a Venn diagram with three overlapping sets, there will be a total of 8 regions formed.

Each region represents a unique combination of elements belonging to different sets.

These regions help visualize the relationships and intersections between the sets, providing a graphical representation of set theory concepts and aiding in analyzing data that falls into multiple categories.

Therefore, the correct answer is 8.

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Answer:

Amount of fresh water = 3.5 * 10^7 cubic kilometers

Step-by-step explanation:

Given the following

Total water on earth = 1.4×10^9 cubic kilometers

If 2.5% of it is fresh water

Amount of fresh water = 2.5% of 1.4×10^9

Amount of fresh water = 0.025 * 1.4×10^9

Amount of fresh water = 0.035 * 10^9

Amount of fresh water = 3.5 * 10^7 cubic kilometers

Answer:

the x-coordinate and y-coordinate change places.

Step-by-step explanation: so you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

Step-by-step explanation:

Answer:

Minimum Unit Cost = $14,362

Step-by-step explanation:

The standard form of a quadratic is given by:

ax^2 + bx + c

So for our function, we can say,

a = 0.6

b = -108

c = 19,222

We can find the vertex (x-coordinate where minimum value occurs) by the formula -b/2a

So,

-(-108)/2(0.6) = 108/1.2 = 90

Plugging this value into original function would give us the minimum (unit cost):

Answer:

c

Step-by-step explanation:

Step-by-step explanation:

Here's your solution

=> area of circle = πr^2

,=> area = (22/7)*6*6

=> area = 113.04 insq

=> area of sector =( πr^2*8°)/360°

=> area of sector = 2.51 insq

=> area of shaded region = 113.04 - 2.51

=> area = 110.53 in.sq

hope it helps

Answer:

\( \triangle \: A'B'C' \: will \: have : \\ \angle \: A' \: at \: point \: ( - 1 ,\: 1). \\ \angle \: B' \: at \: point \: ( 1,\: 3). \\ \angle \: C' \: at \: point \: ( - 3 ,\: 3).\)

The particle has a frequency of 0.032 hertz.

The particle experiments a sinusoidal motion, whose mathematical model is described below:

\(x = x_{o} + A\cdot \cos (\omega\cdot t + \phi)\) (1)

Where:

The frequency (\(f\)), in hertz is defined by this formula:

\(f = \frac{\omega}{2\pi}\) (2)

By direct observation on the formula described in statement we find that \(\omega = 0.2\,\frac{rad}{s}\), then we find the frequency of the particle by (2):

\(f \approx 0.032\,hz\)

The particle has a frequency of 0.032 hertz.

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Answer:

Step-by-step explanation:

here you go mate

step 1

(x^3)4  equation

step 2

(x^3)4  simplify

answer

4x^3

can i get brainliest if you dont mind

The directional derivative of f at P(ln2, ln3) in the direction of (2,2) is e^(-(ln2+ln3)/sqrt(2)).

To compute the directional derivative of the function f(x,y) = e^(-x-y) at point P(ln2, ln3) in the direction of the vector (2,2), we need to first find the gradient of f at P.

The gradient of f is given by:

grad(f) = (-∂f/∂x, -∂f/∂y)

So, we have:

∂f/∂x = -e^(-x-y)

∂f/∂y = -e^(-x-y)

Therefore, the gradient of f is:

grad(f) = (e^(-x-y), e^(-x-y)) evaluated at P(ln2, ln3), this gives us:

grad(f)|P = (e^(-ln2-ln3), e^(-ln2-ln3))

Next, we need to normalize the given direction vector (2,2) to obtain a unit vector. The length of the vector (2,2) is sqrt(2^2 + 2^2) = 2sqrt(2). So, the unit vector in the direction of (2,2) is:

u = (2/sqrt(8), 2/sqrt(8)) = (sqrt(2)/2, sqrt(2)/2)

Finally, the directional derivative of f at P in the direction of u is given by:

D_u f(P) = grad(f)|P · u

where · denotes the dot product.

Substituting the values we have calculated, we get:

D_u f(P) = (e^(-ln2-ln3), e^(-ln2-ln3)) · (sqrt(2)/2, sqrt(2)/2)

Simplifying, we get:

D_u f(P) = e^(-ln2-ln3)·sqrt(2)/2 + e^(-ln2-ln3)·sqrt(2)/2

D_u f(P) = e^(-ln2-ln3)·sqrt(2)

Simplifying further, we get:

D_u f(P) = e^(-(ln2+ln3)/sqrt(2))

Therefore, the directional derivative of f at P(ln2, ln3) in the direction of (2,2) is e^(-(ln2+ln3)/sqrt(2)).

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The solution to the system of equations is x = -3 and y = 2. The y-value of the solution is 2

To find the y-value of the solution to the system of equations, we can solve the system using any suitable method such as substitution or elimination.

Given system of equations:

3x + 5y = 1

7x + 4y = -13

Let's use the method of elimination to solve the system:

Multiply equation 1 by 4 and equation 2 by 5 to make the coefficients of y in both equations equal:

4(3x + 5y) = 4(1) --> 12x + 20y = 4

5(7x + 4y) = 5(-13) --> 35x + 20y = -65

Now, subtract equation 1 from equation 2 to eliminate the y term:

(35x + 20y) - (12x + 20y) = -65 - 4

35x - 12x = -69

23x = -69

x = -69/23

x = -3

Substitute the value of x into equation 1 to find y:

3(-3) + 5y = 1

-9 + 5y = 1

5y = 1 + 9

5y = 10

y = 10/5

y = 2

Therefore, the solution to the system of equations is x = -3 and y = 2. The y-value of the solution is 2.

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False. In a static method of a class, you cannot use the "this" keyword to reference instance variables or instance methods of the same class.

A static method belongs to the class itself, not to any particular instance of the class, so it cannot access instance-specific information. Instead, you would need to use the class name followed by the variable name to access any static or instance variables within a static method of that same class. For example, if the class had an instance variable called "f" and a static method called "myStaticMethod", you could reference the instance variable from within the static method using "ClassName.f". It is important to note that if you attempt to reference an instance variable using "this.f" within a static method, you will receive a compilation error.

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Answer:

There's nothing there just repost it and don't forget the link

Step-by-step explanation:

Good Mornin' Dude  

* inserts Bruno Mars "Uptown Funk"

Answer:

4x3+6x6=48

Step-by-step explanation:

PEMDAS

4x3=12

6x6=36

12+36=48

therefore, the answer is 48

Given:

The equation is

\(\sin\left(x+\dfrac{7\pi}{2}\right)=-\dfrac{\sqrt{3}}{2}\)

To find:

The solutions of given equation over the interval \([0,2\pi]\).

Solution:

We have,

The equation is

\(\sin\left(x+\dfrac{7\pi}{2}\right)=-\dfrac{\sqrt{3}}{2}\)

\(\sin\left(x+\dfrac{7\pi}{2}\right)=-\sin \dfrac{\pi }{3}\)

\(\sin\left(x+\dfrac{7\pi}{2}\right)=\sin (-\dfrac{\pi }{3})\)

If \(\sin x=\sin y\), then \(x=n\pi +(-1)^ny\).

Over the interval \([0,2\pi]\).

\(x+\dfrac{7\pi}{2}=4\pi-\dfrac{\pi }{3}\) and \(x+\dfrac{7\pi}{2}=5\pi+\dfrac{\pi }{3}\)

\(x=\dfrac{11\pi }{3}-\dfrac{7\pi}{2}\) and \(x=\dfrac{16\pi}{3}-\dfrac{7\pi}{2}\)

\(x=\dfrac{22\pi-21\pi }{6}\) and \(x=\dfrac{32\pi-21\pi }{6}\)

\(x=\dfrac{\pi}{6}\) and \(x=\dfrac{11\pi }{6}\)

Therefore, the two solutions are tex]x=\dfrac{\pi}{6}\) and \(x=\dfrac{11\pi }{6}\).

Answer:

C. π/6 & 11π/6

Step-by-step explanation:

If you graph the equation ( Sin (x+7π/2)=-√3/2) and look between 0 & 2π, you'll see that the lines intersect the x-axis at π/6 & 11π/6.

Answer:

x = 69

Step-by-step explanation:

since AB is parallel to CD we can find the value of y with the following equation :

2y - 40 = 66 add 40 to both sides

2y = 110 divide both sides by 2

y = 55

from supplementary angles, we know that the exterior angle's measure is 124

since the sum of two interior angles in a triangle is equal to an exterior angle that is supplementary to the third interior angle

y + x = 124 we found value of y earlier

55 + x = 124 subtract 55 from both sides

x = 69

Answer:

5 > n + 10

8 x 7 < n

n/3 + 1

6 x 8 - 10 < n

n - 1 x n

n x -n + 7

Answer:

(Excluding Xion) Each person will get 2 1/4 brownies

Step-by-step explanation:

9 brownies distributed equally to 4 friends.  If each person gets two brownies, there is one left over.  Divide 1 by 4 and you get 1/4.  1/4 in decimal form is 0.25.  2+0.25=2.25

Or you could just use a calculator to divide 9 by 4 and it would come up with 2.25

Answer:ok123cm.

Step-by-step explanation: