The success of completely separating the methanol from the water is
Alcohol.
Why do you think it was unsuccessful?Because water is a polar solvent and methanal is also a Polar compoundBoth Water and Methanal are miscible, they cannot be separated.Polar Compounds only dissolve in Polar solvents.It is possible due to the electrical charges tugging on various solute molecule parts. The negatively charged side of a solvent molecule attracts the positively charged ions of the solid compound and vice versa. The polar compound can then be dissolved in the polar solvent thanks to this. The ions are evenly dispersed throughout the solvent as a result of this activity. Regarding the solvent's polarity, it essentially develops as a result of the bonds between atoms with various electronegativity values, which result in the formation of the molecule.When carbon forms multiple bonds to other elements, these bonds are polar. Both the carbon-oxygen double bond in formaldehyde (methanal) and the carbon-nitrogen triple bond in acetonitrile (cyanomethane) are polar.
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LAB: SOIL PARTICLES
You have learned that soil is made of weathered rock, water, air, and organic material. The size of particles is an important soil characteristic. According to the United States Department of Agriculture (USDA), there are three main particle sizes—sand, silt, and clay. Clay is particles smaller than 0.002 mm. Sand is particles larger than 0.05 mm. Particles in between are silt. The size of particles in soil determines how much water the soil will hold. Small particles hold more water than large particles.
Soil usually settles into different layers called horizons. The arrangement of horizons is the soil profile. In this experiment, you will observe how particle size affects the soil profile.
Describe how particle size affects the settling of soil.
Which type of soil do you think will settle to the bottom of the container faster?
1 1/2 cups potting soil
1 1/2 cup sand
3 wide-mouthed juice bottles with lids
Masking tape
Pen
Water
Make masking tape labels for each juice bottle. Label one "soil" and the other "soil and sand."
Fill both bottles 3/4 full of water.
Slowly pour 1 cup of soil into the water in the "soil" bottle. Observe the behavior of the soil particles.
Fill the "soil" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Slowly pour 1 cup of sand into the water in the "sand" bottle. Observe the behavior of the soil particles.
Fill the "sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Add the 1/2 cup of sand to the remaining 1/2 cup of soil. Mix thoroughly with the spoon.
Slowly pour the sand and soil mixture into the water in the "soil and sand" bottle. Observe the behavior of the particles.
Fill the "soil and sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Leave both bottles undisturbed for 8 hours.
Look at the bottles again after 8 hours and record your observations.
Data
What did you notice about the way the soil particles sank in the water? How was it different from the way the soil and sand particles sank?
What does the soil look like in the "soil" bottle? How is it different from the soil in the "soil and sand" bottle?
In the "soil and sand" bottle, which type of soil is on the bottom? Why?
The amount of each size particle in soil is the particle size distribution. Do you think this is a good way to determine particle size distribution? Why or why not?
State whether your hypothesis was supported or disproved, and then explain why it was supported or disproved using your data. Summarize your observations and answer one or more of the following questions: How does this lab relate to what I have been learning? How does this experiment relate to things I have seen in my own life? What could be done to improve this experiment?
Heading and title
Hypothesis, procedure, data, post lab, and conclusion section headings
Each section is thorough and complete
Lab report typed into a word processor (such as Microsoft Word) and saved
Typed lab document uploaded to Ignitia and submitted
1. I noticed that the soil particles settled out of the water with the larger, heavier particles settling out first and on the bottom, and each layer has smaller and lighter particles in it.
2. Sand settled on the bottom because they are heavier and have more mass than the smaller particles such as silt and clay.
3. Yes, this is a good way to determine particle size distribution. The method used in the experiment allows for the separation of soil particles based on their size and weight, which is a good indicator of their distribution in the soil sample.
4. The results in this experiment may look different when done in different locations because the particle size distribution of soil can vary depending on the location, climate, and geology of the area. Soils in different locations may have different compositions, including different amounts of sand, silt, and clay, which can affect the results of the experiment. Additionally, the sedimentation rate of the particles can also be influenced by factors such as the temperature, the presence of organic matter, and the presence of clay minerals, which can further affect the results.
5. Give an equation to show the reaction of bromoethane with an aqueous solution of potassium hydroxide6. Give an equation to show the reaction of chloropropane with ammonia
Bromoethane and aqueous KOH reaction:
When a bromoethane is treated with aqueous KOH, one of the products of the reaction is a primary alcohol, ethanol.
The reaction:
CH3CH3Br + KOH (aq) ==> CH3CH2OH + KBr
think back to our hypotheses of chapter 12 regarding melting points (that some force kept the material together). given those hypotheses, what would you predict about the forces that hold atoms of cesium together in the solid metal compared to the forces that hold atoms of lithium together? explain why.
Based on the hypotheses discussed in Chapter 12 regarding melting points and the forces that hold materials together, we can make a prediction about the forces holding atoms of cesium and lithium together in their solid metal forms.
One hypothesis suggests that stronger forces between atoms result in higher melting points. Another hypothesis proposes that metals are held together by metallic bonds, where positively charged metal ions are surrounded by a sea of delocalized electrons.
Considering these hypotheses, we can infer that cesium atoms would be held together by stronger forces compared to lithium atoms in their solid metal forms. This is because cesium is located further down the periodic table, belonging to Group 1 (alkali metals), whereas lithium is in Group 2 (alkaline earth metals). As we move down a group in the periodic table, the atomic radius generally increases, leading to weaker forces of attraction between atoms.
Therefore, the larger atomic size of cesium compared to lithium would result in weaker interatomic forces, making cesium's solid metal form have a lower melting point compared to lithium.
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Select the ice age, 1750's, and today tabs and record the changes in greenhouse gases and temperature. Greenhouse Gas Concentration Carbon Dioxide Concentration (CO2) Methane Concentration (CO4) Nitrous Oxide Concentration (N2O) Temperature Ice Age 1750 Today
The term "greenhouse" can refer to two different concepts: the physical structure known as a greenhouse and the greenhouse effect in the Earth's atmosphere.
Greenhouse gases are gases that trap heat in the Earth's atmosphere, contributing to the greenhouse effect and influencing the Earth's climate. They include:
1. Carbon Dioxide (CO2): This is the most significant greenhouse gas emitted by human activities. It is released through the burning of fossil fuels (such as coal, oil, and natural gas), deforestation, and other industrial processes.
2. Methane (CH4): Methane is produced by natural processes (such as wetlands and termites) as well as human activities such as agriculture (rice cultivation, livestock farming), fossil fuel production, and waste management (landfills).
3. Nitrous Oxide (N2O): Nitrous oxide is emitted through agricultural and industrial activities, including the use of synthetic fertilizers, fossil fuel combustion, and biomass burning.
4. Fluorinated Gases: This category includes hydrofluorocarbons (HFCs), perfluorocarbons (PFCs), and sulfur hexafluoride (SF6), which are synthetic gases used in various industrial applications, including refrigeration, air conditioning, and electronics.
These greenhouse gases trap heat radiated from the Earth's surface, preventing it from escaping into space and leading to a warming effect known as global warming.
Ice Age:
During the Ice Age, greenhouse gas concentrations were significantly lower compared to the present day. Unfortunately, specific measurements for carbon dioxide (CO2), methane (CH4), and nitrous oxide (N2O) concentrations during the Ice Age are not available.
1750:
In the 1750s, greenhouse gas concentrations were still relatively low, but human activities were starting to have an impact. Again, precise measurements for CO2, CH4, and N2O concentrations during this period are not available.
Today:
The current atmospheric CO2 concentration is over 410 parts per million (ppm). Methane concentrations have risen to over 1,800 parts per billion (ppb), and nitrous oxide concentrations have increased to over 330 ppb. These increased greenhouse gas concentrations have contributed to a warming effect on the Earth's climate. Global average temperatures have also risen compared to pre-industrial times, with an increase of about 1.1 degrees Celsius.
To obtain the most accurate and up-to-date information on greenhouse gas concentrations and temperature.
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a glass of cold milk sometimes forms a coat of water on the outside of the glass (often referred to as 'sweat'). how does most of the water get there?
Answer: A glass of cold milk sometimes forms a coat of water on the outside of the glass (Often referred to as 'sweat'). How does most of the water get there? Water evaporates from the milk and condenses on the outside of the glass. The glass acts like a semi-permeable membrane and allows the water to pass, but not the milk.
Explanation: Hope this helps
NaCl solution is an example of a/an ____________.A. ConductorB. MetalloidC. InsulatorD. Nonmetal
When NaCl is placed in water, it becomes an aqueous solution, one thing that occurs in this situation is that NaCl, which is an ionic compound, will dissociate into Na+ and Cl-, this dissociation into ions will cause the solution to become a good conductor of electricity. Therefore the correct answer will be letter A
Which of these compounds would you predict
to have the highest boiling point?
C₂H6
C5H12
C6H14
CH10
C3H8
Answer:c6h14
Explanation:
willy
THINK
ABOUT Theory
According to kinetic-molecular theory, which of the following would not be considered an ideal gas?
Check all that apply.
a gas at very high temperatures, when gas particles are moving very quickly
a gas at very low volumes, when gas particles are very close together
a gas at very low temperatures, when gas particles have very little kinetic energy
a gas at very low pressures, when gas particles are very far apart
a gas with highly polar molecules that have very strong intermolecular forces
DONE
The term ideal gases means the gases that obey the kinetic theory of gases.
What is an ideal gas?The term Ideal gas is based on the idea of the kinetic molecular theory. These are the gases that obey the kinetic theory of gases.
This, from the kinetic theory of gases, an ideal gas is;
a gas at very high temperatures, when gas particles are moving very quicklya gas at very low pressures, when gas particles are very far apartLearn more about the kinetic theory of gases:https://brainly.com/question/2624226
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According to kinetic-molecular theory, the following wouldn't be considered an ideal gas are: options B, C, and E.
What is the kinetic-molecular theory?Kinetic-molecular theory of gases states that all gas particles would exhibit a perfectly elastic collision and are constantly in motion.
According to kinetic-molecular theory, the following wouldn't be considered an ideal gas are:
A gas that is at very low volumes, when gas particles are very close together.A gas that is at very low temperatures, when gas particles have very little kinetic energy.A gas that is with highly polar molecules with very strong inter-molecular forces.Read more on kinetic-molecular theory here: https://brainly.com/question/4979154
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Determine if each object is an insulator or a conductor.
radiator
Intro
winter coat
ice chest
frying pan
oven mitt
ceramic baking dish
Conductor
Insulator
sceince problem i need help
a solution has a concentration of 0.245 m mg(clo4)2. to 500.0 ml of this solution was added 17.5 g of mg(clo4)2, 223.2 g/mol. assuming the volume of the solution remains constant, what is the new solution concentration?
The new concentration of the above solution would be 0.76 mol/L.
The most common way to solve this problem is to use the formula
c1V11=c2V2
In your problem,
c1 = 4.2 mol/L; V1 = 45.0 mL
c2 = ?;
V2 = 250 mL
c2=c1×V1V2 = 4.2 mol/L × 45.0mL250ml = 0.76 mol/L
This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
The amount of solvent which has been digested in a given volume of solvent or solution is evaluated by the optimizer concentration. A solution that includes a considerable amount of dissolved solute is said to be concentrated. A solution is said to be dilute if it only contains a little amount of dissolved solute.
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: Which type of line is shown on the map? isobar
isotherm
radar
humidity
Answer:
isobar
Explanation:
edge 23
the primary difference between enhancers and promoter-proximal elements is that enhancers _____.
Answer:
Enchancers are transcription factors
I hope that helps you
1. Al +
LINO2 + _______ + _________
answer; the last two is me and u :
The system below was at equilibrium in a
9.0 L container. What change will occur
for the system when the container is
shrunk to 3.0 L?
51.8 kJ + H₂(g) + 1₂(g) = 2HI(g)
Hint: How many moles of gas are on each side?
A. The reactions shifts to the right (products) to produce
fewer moles of gas.
B. There is no change because there are the same
number of moles of gas on both sides.
C. The reactions shifts to the left (reactants) to produce
more moles of gas.
The number of moles of gas is the same on both sides, the change in volume will not affect the equilibrium position of the reaction. The answer is B) There is no change because there are the same number of moles of gas on both sides.
To determine the change that will occur when the container is shrunk from 9.0 L to 3.0 L for the given reaction:
51.8 kJ + H₂(g) + I₂(g) → 2HI(g)
We need to consider the number of moles of gas on each side of the reaction.
On the left side, there are 2 moles of gas (H₂ and I₂), while on the right side, there are 2 moles of gas (2HI). Both sides have an equal number of moles of gas.
Therefore, the correct answer is B) There is no change because there are the same number of moles of gas on both sides.
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Pb(NO3)2+K2CrO4 →PbrCrO4 +2KNO3 classify the chemical reaction
Find the formula mass of the compound, then divide the individual element total by the total mass-move the decimal over two to change it to percentage SiF4
Answer:
Explanation:
Here, we start by calculating the formula mass of the compound
We can get this by using the atomic masses of the elements
The atomic mass of silicon is 28 amu
The atomic mass of fluorine is 19 amu
The formula mass of the given compound is thus:
\(28\text{ + 4\lparen19\rparen = 104 g/mol}\)Now, we divide the individual total mass by element by the formula mass
For Silicon, we have:
\(\frac{28}{104}\text{ = 0.27}\)For Fluorine, we have:
\(\frac{76}{104}\text{ = 0.73}\)Rank the following atoms according to decreasing first ionization energy. (i.e. 1 = highest and 4 = lowest)
Options are Al, P, Mg, K?
The decreasing order of ionization energy will be Mg >Al >P>K.
Ionization energy sometimes referred to as ionization potential, would be the amount of energy it takes to eliminate an electron from a single, isolated atom or molecule.
On moving top to bottom in the periodic table, ionization energy will decrease rapidly.
Al =13 (group 3)
P =15 (group 5)
Mg =12 (group 2)
K =19 (group 1)
The decreasing order of ionization energy will be Mg >Al >P>K.
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Which of the following is a result of
differentiation?
a. An organism grows larger.
b. Cells in an embryo increase in number.
c. Cells in an embryo become different from
one another.
d. An organism reproduces.
The result of the cell differentiation is that cells in an embryo become different from one another. Option C
What is cell differentiation?When we are talking about cell differentiation we mean the process by which the cells of the organisms would become different from each other. That is is the manner in which the cell would become to carry out the functions that are different from each other.
We should note that the embryo is just formed as a mass of cells that must be able to differentiate so that each of the cells can be able to perform an assigned task.
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Rank the following 0.10 M solutions in order of increasing pH.
a. HI, HF, NaF, NaI
b. NH4Br, HBr, KBr, NH3
c. C6H5NH3NO3, NaNO3, NaOH, HOC6H5, KOC6H5, C6H5NH2, HNO3
The solutions can be ranked in increasing pH as follows:
(a) HI, HF, NaF, NaI
(b) HBr, NH4Br, KBr, NH3
(c) HNO3, HOC6H5, C6H5NH2, NaNO3, NaOH, KOC6H5, C6H5NH3NO3.
NaI and NaF are salts of strong bases and weak acids, so they will have a neutral or slightly basic pH. HF is a weak acid, so it will have a slightly acidic pH. HI is a strong acid, so it will have a strongly acidic pH.
HBr is a strong acid, so it will have an acidic pH. NH4Br is a salt of a weak acid (NH4+) and a strong base (Br-), so it will have a slightly acidic pH. KBr is a salt of a strong acid and a strong base, so it will have a neutral pH. NH3 is a weak base, so it will have a slightly basic pH.
HNO3 is a strong acid, so it will have a strongly acidic pH. HOC6H5 is a weak acid, so it will have a weakly acidic pH. C6H5NH2 is a weak base, so it will have a slightly basic pH. NaNO3 is a salt of a strong acid and a strong base, so it will have a neutral pH. NaOH is a strong base, so it will have a strongly basic pH. KOC6H5 is a weak base, so it will have a weakly basic pH. C6H5NH3NO3 is a salt of a weak base (C6H5NH3+) and a strong acid, so it will have a strongly basic pH.
In conclusion we can see that (a) HI, HF, NaF, NaI (b) HBr, NH4Br, KBr, NH3 (c) HNO3, HOC6H5, C6H5NH2, NaNO3, NaOH, KOC6H5, C6H5NH3NO3.
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Why is it unlikely for an atom to become charged by changing the number of protons?
Answer:
atoms are a part of the universe so they are like a ball, you can't put anything on top or it will fall
Explanation:
35. 124.31 g of silver nitrate reacts with 52.89 g of sodium chloride.
g
a. What is the mass of the products?
Answer: Thus mass of products is 177.2 g
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical reaction is:
\(AgNO_3+NaCl\rightarrow NaNO_3+AgCl\)
mass of silver nitrate \((AgNO_3)\) = 124.31 g
mass of sodium chloride \((NaCl)\) = 52.89 g
mass of reactants = mass of silver nitrate \((AgNO_3)\) +
mass of sodium chloride \((NaCl)\) = 124.31 g + 52.89 g = 177.2 g
Thus mass of products = mass of reactants = 177.2 g
how wide does this grating need to be to allow you to resolve the two lines 589.00 and 589.59 nanometers, which are a well known pair of lines for sodium, in the second order ( m
A. n = 105 lines/mm = 105000 lines/m
d*sin θ = m*λ
(1/105000) * sin θ = 1*498*10^-9 ⇒ θ = 3.0 degree
Also (1/105000) * sin θ = 1*569*10^-9 ⇒ θ = 3.43 degree
Δθ = 3.43° – 3.0°
Δθ = 0.43°
b) Chromatic Resolving power, R = λ / Δλ
λ / Δλ = m (width) n
589 /0.59 = 2 (width) (105000)
Width = 4.75 mm
Diffraction gratings can split beams of different wavelengths into a spectrum of related lines through the principle of diffraction. In certain directions, only waves of certain wavelengths have obtained the rest are destroyed by their respective interference. other.
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NH4+H2O →NH3+H3O
Which one is acting weaker base?
Answer:
NH3
Explanation:
In solution, they are in equilibrium. NH4+ acts as a bronsted Lowry acid and donates an H to become NH3, and NH3 acts as a bronsted lowry base and accepts an H. In this pair, NH3 is a weak base, which gets its basic character due to the presence of lone pair of nitrogen and its ability to donate it.
What is the balanced equation for: potassium manganate vii reacting to produce potassium manganate vi oxide and manganese iv oxide and oxygen.
The balanced equation for the reaction you described is as follows:
2 KMnO₄ → K₂MnO₄ + MnO₂ + O₂
In this reaction, potassium manganate(VII) (KMnO₄) reacts to produce potassium manganate(VI) oxide (K₂MnO₄), manganese(IV) oxide (MnO₂), and oxygen (O₂).
Let's break down the reaction and explain it further:
The reactant, potassium manganate VII (KMnO₄), is a strong oxidizing agent. It contains manganese in its highest oxidation state (+7). When it undergoes a reaction, it is reduced to a lower oxidation state.
The products of the reaction are potassium manganate VI oxide (K₂MnO₄), manganese IV oxide (MnO₂), and oxygen (O₂).
Potassium manganate VI oxide (K₂MnO₄) is formed by the reduction of potassium manganate VII. The oxidation state of manganese in K₂MnO₄ is +6.
Manganese IV oxide (MnO₂) is also formed as a product. In this compound, manganese has an oxidation state of +4.
Finally, oxygen gas (O₂) is produced as a byproduct of the reaction.
Overall, this reaction involves the reduction of potassium manganate VII, resulting in the formation of potassium manganate VI oxide, manganese IV oxide, and the release of oxygen gas.
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How many moles are in 7.36 x 1025 molecules of H2O?
Answer:
There are 122.1982401 moles of H2O in \(7.36*10^{25}\) molecules of H2O
Explanation:
We know,
\(6.023*10^{23}\) molecules of H2O contains 1 mole H2O
1 molecules of H2O contains \(\frac{1}{6.023*10^{23}}\) mole H2O
∴ \(7.36*10^{25}\) molecules of H2O contains \(\frac{1}{6.023*10^{23}}*(7.36*10^{25})\) moles of H2O
= 122.1982401 moles of H2O
∴ There are 122.1982401 moles of H2O in \(7.36*10^{25}\) molecules of H2O
The different possible ways for arranging the particles of a system are called _____. The greater the number of these states, the _____ the entropy of the system
The different possible ways of arranging the particles of a system are called states. The greater the number of these states, the higher the entropy of the system.
By ascribing definite values to a satisfactory amount of variables, one can define the state of a system. In simple terms, it is the description of a system condition in terms of properties that are measurable or observable, for example, pressure, temperature, etc.
Entropy is a measure of the disorder or randomness in a system, and an increase in the number of states corresponds to an increase in entropy. The S.I. unit for entropy is joules per kelvin. Entropy is a measurable physical property. In a thermodynamic system, it is an extensive property.
Example: There is an increase in entropy when a block of ice melts.
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Science chemistry Question:
Are you doing a quiz?
A central atom is found to have one double bond, one single bond, and one non-bonding pair of electrons. how many electron domains does the central atom have?
Answer:
A central atom is found to have one double bond, one single bond, and one non-bonding pair of electrons
I WILL GIVE BRAINLEST IF YOU ANSWER THIS QUESTION QUICKLY!!!
what is an orbital?
Answer:
Electric Patterns and has many different variations.
Explanation: