I could solve for a and it said this:
Isolate the variable by dividing each side by factors that don't contain the variable.
All real numbers
Interval Notation:
(−∞,∞)
But I can solve for W and B
W = 2b
b = W/2
a = I could solve for a and they put the answer to this (−∞,∞)
Solve the problem. Round to the nearest cent.
Brad wants to have available to buy a car in 5 years. How much must he deposit now at compounded monthly to reach that goal?
Group of answer choices
$22,366.96
$12,395.17
$22,905.95
$12,920.84
Answer:
$10,857.8
Step-by-step explanation:
Brad wants to have $17000 available to buy a car in 5 years. How much should he deposit now at 9% compounded monthly to reach that goal?
A = p(1 + r/n)^nt
P = A / (1 + r/n)^nt
P = 17000 / (1 + 0.09/12)^(12*5)
= 17,0000 / (1 + 0.0075)^60
= 17,000 / (1.0075)^60
= 17,000 / 1.5657
= 10,857.8
P = $10,857.8
A cubical box has length=12cm,and finds the volume of box
Therefore, the volume of the cube is: V=a3=123=1728cm3.
1728 cm ^ 3
Solution : we are given side = 12 cm As we know formula of volume of cube = s ^ 3 ( side * side * side ) So = 12 * 12* 12 = 1728 cm ^ 3.
The volume of a cubical box is given by the formula:
V = l^3
where l is the length of one edge of the cube.
In this case, the length of the box is given as 12 cm. Since it is a cube, all three dimensions are equal, so the length, width, and height are all 12 cm.
Thus, the volume of the box is:
V = 12^3
= 1728 cubic centimeters
Therefore, the volume of the box is 1728 cubic centimeters.
The price of a stock has risen 6% in the last year. If the stock started at $10 per share, what is the price per share right now?
Answer:
the price of per share = 106/100× 10= $10.6
Step-by-step explanation:
price has risen 6% in last year
the stock started at $10 per share
the original price = 100%
risen 6% in the last year = 106 %
the stock per share is $ 10
the price of per share = 106/100× 10= $10.6
Find the slope.
Find the slope
Answer:
The slope is 1
Step-by-step explanation:
for every 1 unit crossed in the X value, 1 is crossed the Y value, which is
1/1 or 1
Answer: 1
Step-by-step explanation:
Let us look at the given line.
➜ The line is going from bottom left to upper right, this is a positive slope
➜ We can use rise/run for a slope of 4/4 = 1/1. See attached.
The radius of a circle is 2 centimeters. What is the circles circumference?
Answer: 4π cm or 12.56 cm
Step-by-step explanation: To find the circumference of this circle, start with the formula for the circumference of a circle which is C = 2πr.
Since the radius is 2 centimeters, we can
plug in 2 centimeters for r in the formula.
So we have (2)(π)(2 cm) which is equal to 4π cm.
So the circumference of this circle is 4π cm.
Remember that π is approximately equal to 22/7 or 3.14 so we can estimate the value of the circumference by plugging in 3.14 for π.
So we have (4)(3.14) which is equal to 12.56.
So the circumference of the circle is
approximately equal to 12.56 cm.
Find the area of the region bounded by the graphs of the equations x=−y2+4y−2 and x+y=2 Online answer: Enter the area rounded to the nearest tenth, if necessary.
To find the area of the region bounded by the graphs of the equations, we first need to determine the points of intersection between the two curves. Let's solve the equations simultaneously:
1. x = -y^2 + 4y - 2
2. x + y = 2
To start, we substitute the value of x from the second equation into the first equation:
(-y^2 + 4y - 2) + y = 2
-y^2 + 5y - 2 = 2
-y^2 + 5y - 4 = 0
Now, we can solve this quadratic equation. Factoring it or using the quadratic formula, we find:
(-y + 4)(y - 1) = 0
Setting each factor equal to zero:
1) -y + 4 = 0 --> y = 4
2) y - 1 = 0 --> y = 1
So the two curves intersect at y = 4 and y = 1.
Now, let's integrate the difference of the two functions with respect to y, using the limits of integration from y = 1 to y = 4, to find the area:
∫[(x = -y^2 + 4y - 2) - (x + y - 2)] dy
Integrating this expression gives:
∫[-y^2 + 4y - 2 - x - y + 2] dy
∫[-y^2 + 3y] dy
Now, we integrate the expression:
[-(1/3)y^3 + (3/2)y^2] evaluated from y = 1 to y = 4
Substituting the limits of integration:
[-(1/3)(4)^3 + (3/2)(4)^2] - [-(1/3)(1)^3 + (3/2)(1)^2]
[-64/3 + 24] - [-1/3 + 3/2]
[-64/3 + 72/3] - [-1/3 + 9/6]
[8/3] - [5/6]
(16 - 5)/6
11/6
So, the area of the region bounded by the graphs of the given equations is 11/6 square units, which, when rounded to the nearest tenth, is approximately 1.8 square units.
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51.8 + (-0.8) i dont like how you suposse to have20 letters
Answer:
51
Step-by-step explanation:
51.8-0.8=51
Answer:
the answer is 51
Step-by-step explanation:
I dont like how you have to have certain amount of charters in general.
List the factor pairs of the number
16
Answer:
The factor pairs are: 1,16 2*8 and 4*4
Step-by-step explanation:
Factor pairs are the pairs of numbers that multiply to 16
1*16 = 16
2*8=16
4*4 = 16
The factor pairs are: 1,16 2*8 and 4*4
Section 3: Translate from English into the language of Propositional Logic. Use the letters provided to stand for simple propositions.
17. Stacy will come with us to see the Gauguin exhibit only if Angelina and Jane don’t both go. (S, A, J)
18. If diamonds are not precious stones, then neither are sapphires. (D, S)
Section 5: Test the following arguments for validity using either the direct or
indirect truth-table method.
34. G ⊃ H / R ≡ G / ~H v G // R • H
The argument is valid. The argument is valid based on the direct truth-table method.
To test the validity of the argument, we can use the direct truth-table method. Let's break down the argument and construct the truth table for the given premises and the conclusion:
Premises:
G ⊃ H
R ≡ G
~H v G
Conclusion:
R • H
Constructing the truth table:
We have three propositions: G, H, and R. Each proposition can have two truth values, true (T) or false (F). Therefore, we need 2^3 (8) rows in the truth table to evaluate all possible combinations.
By evaluating the truth table, we find that in all rows where the premises (1, 2, 3) are true, the conclusion (R • H) is also true. There is no row where the premises are true, but the conclusion is false. Therefore, the argument is valid.
The argument is valid based on the direct truth-table method. This means that if the premises (G ⊃ H, R ≡ G, ~H v G) are true, then the conclusion (R • H) must also be true.
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Consider the degree of each polynomial in the problem. The first factor has a degree of . The second factor has a degree of . The third factor has a degree of . The product has a degree of
The first factor of the expression has a degree of 2.
The second factor has a degree of 3.
The third factor has a degree of 2.
The product has a degree of 7.
\((a^{2} ) (2a^{3} )(a^{2}-8a+9)\)
The given expression of this problem is:
The degree of an expression is deduct by the exponent of each power.
So, the first factor of the expression has a degree of 2, because that's the exponent.
The second factor has a degree of 3.
The third factor has a degree of 2.
Now, to know the degree of the product, we have to solve the expression, and see what is the degree of the resulting polynomial expression:
\((a^{2})(2a^{3})(a^{2} -8a+9)\)
\(2a^{5} (a^{2} -8a+9)\)\(\\2a^{7} -16a^{6}+18a^{5}\)
so, as you can see, the product has a degree of 7.
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Another easy question need fast please
Answer:
30.25
Step-by-step explanation:
All angles of a line must add up to 180. Since we already know that one angle is 90 degrees, we know that the other angles should add up to 90 degrees in order for all of the angles to add up to 180 degrees:
(3x-7)+(x+8)=90
4x+1=90
4x=89
x=22.25
22.25+8= 30.25
Let f: R→ R' be a ring homomorphism of commutative rings R and R'. Show that if the ideal P is a prime ideal of R' and f−¹(P) ‡ R, then the ideal f−¹(P) is a prime ideal of R. [Note: ƒ−¹(P) = {a ≤ R| ƒ(a) = P}]
we are given a ring homomorphism f: R → R' between commutative rings R and R'. We need to show that if P is a prime ideal of R' and f^(-1)(P) ≠ R, then the ideal f^(-1)(P) is a prime ideal of R.
To prove this, we first note that f^(-1)(P) is an ideal of R since it is the preimage of an ideal under a ring homomorphism. We need to show two properties of this ideal: (1) it is non-empty, and (2) it is closed under multiplication.
Since f^(-1)(P) ≠ R, there exists an element a in R such that f(a) is not in P. This means that a is in f^(-1)(P), satisfying the non-empty property.
Now, let x and y be elements in R such that their product xy is in f^(-1)(P). We want to show that at least one of x or y is in f^(-1)(P). Since xy is in f^(-1)(P), we have f(xy) = f(x)f(y) in P. Since P is a prime ideal, this implies that either f(x) or f(y) is in P.
Without loss of generality, assume f(x) is in P. Then, x is in f^(-1)(P), satisfying the closure under multiplication property.
Hence, we have shown that f^(-1)(P) is a prime ideal of R, as desired.
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find the force of gravity (in n) between the mass m1 (6.0x1024 kg) and the mass m2 (7.4x1022 kg). the distance between the object is 380,000 km.
The force of gravity between the two masses is approximately 2.197 x 10^20 Newtons.
To find the force of gravity between two masses, we can use the gravitational force formula:
where:
F = G * (m1 * m2) / r^2
F is the force of gravity (in Newtons),
G is the gravitational constant (6.674 x 10^-11 N*(m/kg)^2),
m1 is the mass of the first object (6.0 x 10^24 kg),
m2 is the mass of the second object (7.4 x 10^22 kg), and
r is the distance between the objects (380,000 km, which needs to be converted to meters).
Step 1: Convert the distance to meters.
1 km = 1,000 m, so 380,000 km = 380,000,000 m.
Step 2: Apply the gravitational force formula.
F = (6.674 x 10^-11 N*(m/kg)^2) * ((6.0 x 10^24 kg) * (7.4 x 10^22 kg)) / (380,000,000 m)^2
Step 3: Calculate the force of gravity.
F ≈ 2.197 x 10^20 N
So, the force of gravity between the two masses is approximately 2.197 x 10^20 Newtons.
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The median house price in Pickering Region increased by 5.8% from Jan 1, 2019 to Jan 1, 2021. A home was purchased in Pickering Region on Jan 1, 2019 for $600,000.
a)Assume this trend continues, write an exponential equation that models the Resale Value of this home over time.
b) At this rate, determine the date when the resale price of the home would reach $1 million (Show your work to accurate to the nearest month)
c) Use your exponential equation to determine the expected resale value of the home on April 1, 2020.
Using an exponential function, we have that:
a) The equation is: \(A(t) = 600000(1.058)^{\frac{t}{2}}\).
b) The house will have a value of $1 million during the year of 2037.
c) The expected value on April 1, 2020, is of $621,520.
What is an exponential function?
An increasing exponential function is modeled by:
\(A(t) = A(0)(1 + r)^t\)
In which:
A(0) is the initial value.r is the growth rate, as a decimal.In this problem, the parameters are given as follows:
A(0) = 600000, r = 0.058 each 2 years.
Hence the exponential function is:
\(A(t) = 600000(1 + 0.058)^{\frac{t}{2}}\)
\(A(t) = 600000(1.058)^{\frac{t}{2}}\)
Item b:
It is the year 2019 + t, for which A(t) = 1000000, hence:
\(A(t) = 600000(1.058)^{\frac{t}{2}}\)
\(1000000 = 600000(1.058)^{0.5t}\)
\((1.058)^{0.5t} = 1.6667\)
\(\log{(1.058)^{0.5t}} = \log{1.6667}\)
\(0.5t\log{1.058} = \log{1.6667}\)
\(t = \frac{\log{1.6667}}{0.5\log{1.058}}\)
\(t = 18.12\)
The house will have a value of $1 million during the year of 2037.
Item c:
April 1, 2020 is one year and 3 months = 1.25 years after January 1, 2019, hence the value of the home will be given by:
\(A(t) = 600000(1.058)^{\frac{t}{2}}\)
\(A(1.25) = 600000(1.058)^{\frac{1.25}{2}}\)
A(1.25) = $621,520.
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What is the following quotient? startfraction rootindex 3 startroot 60 endroot over rootindex 3 startroot 20 endroot endfraction rootindex 3 startroot 3 endroot 3 2 (rootindex 3 startroot 5 endroot) 40
The value of the quotient expression \(\sqrt[3]{60} \div \sqrt[3]{20}\) is \(\sqrt[3]{3}\)
What is quotient?The quotient of numbers or expressions is the division of a number or expression by another
How to determine the quotient?The quotient expression is given as:
\(\sqrt[3]{60} \div \sqrt[3]{20}\)
Write as a single expression by applying the law of indices
\(\sqrt[3]{60 \div 20}\)
Divide 60 by 20
\(\sqrt[3]{3}\)
Hence, the value of the quotient expression \(\sqrt[3]{60} \div \sqrt[3]{20}\) is \(\sqrt[3]{3}\)
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Answer:
A
Step-by-step explanation:
Endgenuity 2022
What whole number does 101.32 get rounded to?
Answer:
101.32 gets rounded to 101.
Why this is your answer:
101 is your answer because...
1. As we can see in the question, it says, "What whole number". That means, we have to see in the decimals in the number "101.32".
2. We can see that In the number "101.32", there is 32 as the decimal number, first we should look at the "tenths" number. Which is 3.
3. As you know, anything 4 and below, stays as it's own number, and 5 and higher, goes to the next whole number. Here, we have 3 as the "Tenths". And according to that rule... You think, what should we do?
4. As we saw that rule, we know that 3 is smaller than 4. That easily means that , The number will get rounded to the whole number it was.
Thanks!
Write 2.1- as a mixed number. Show
your work
Answer:
2⅒
Step-by-step explanation:
0.1 = 1/10
2 ⅒
Answer:
2 1/10
Step-by-step explanation:
To convert the decimal 2.1 to a fraction, just follow these steps:
Step 1: Write down the number as a fraction of one:
2.1 = 2.1
--------
1
Step 2: Multiply both top and bottom by 10 for every number after the decimal point:
As we have 1 numbers after the decimal point, we multiply both numerator and denominator by 10. So,
= (2.1 × 10)
(1 × 10) = 21
------
10
Now you have to simplify, 2 1/10.
Paul & Malachy share a lottery win of £2750 in the ratio 2 : 3. Paul then shares his part between himself, his wife & their son in the ratio 5 : 4 : 1. How much more does his wife get over their son?
Answer:
£330
Step-by-step explanation:
The total ratio between Paul and Malachy is 2 + 3 = 5.
The amount that Paul will receive is:
2/5 * 2750 = £1100
The second ratio is between Paul, his wife and their son in the ratio 5:4:1. The total ratio between Paul, his wife and their son is:
5 + 4 + 1 = 10
The amount that Paul's wife will receive is:
4/10 * 1100 = £440
The amount that their son will receive is:
1/10 * 1100 = £110
Therefore, the amount that the wife will receive over the son is:
440 - 110 = £330
Anita has soccer practice every day after school. On Friday,
practice is only 1 hour. If she practices a total of 9 hours
each week, how long is practice on each of the other 4
days?
Write and solve an equation to answer the question, and then identify which
statement is not true.
A. x represents the practice time on Monday, Tuesday, Wednesday,
and Thursday
B. The equation is 4x + 1 = 9.
C. The first step in solving the equation is to subtract 1 from both
sides of the equation.
O D. The solution is x = 3.
To find the length of practice on each of the other four days, we can solve the equation 4x + 1 = 9, where x represents the practice time on Monday, Tuesday, Wednesday, and Thursday. The solution of an equation is x = 2.
Let x represent the practice time on each of the other four days (Monday, Tuesday, Wednesday, and Thursday). Since the total practice time for the week is 9 hours, we can set up the equation:
4x + 1 = 9
To solve the equation, we need to isolate the variable x. The first step is to subtract 1 from both side of the equation:
4x = 9 - 1
4x = 8
Next, dividing the both sides of the equation by 4 to solve for x:
x = 8 / 4
x = 2
Therefore, the solution to the equation is x = 2, indicating that practice on each of the other four days (Monday, Tuesday, Wednesday, and Thursday) is 2 hours long.
Based on the explanation above, statement C is not true. The first step in solving the equation is to subtract 1 from both sides of the equation, not to subtract 1 from x.
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Could someone help? please the deadline is in 20 min!!!
Answer:
7.$95 8. $112.50
Step-by-step explanation:
7.
50 divided by 100 is 0.5, then times by 90 is 45.
45 plus 50 is 95.
8.
$150/4=$37.50
$150-$37.50=$112.50
For a friend who's struggling
"Omar and Deb each have a digital music player. Deb has 37 more songs on her player than Omar on his player. Write an expression in simplest form that represents the total number of songs on both players.
Will give brainliest!
varables:
O= omar songs\
S= total # of songs
equation:
2o+37= S
Hoped that helped:)
a rectangular piece of land measuring 9.8 by 7.2 is sub divided into small squares each side x km. find the value of x
The calculated value of x is 2
From the question, we have the following parameters that can be used in our computation:
Dimension of the piece of land = 9.8 by 7.2
Using the above as a guide, we have
Area = 9.8 * 7.2
Evaluate
Area = 70.56
For the square with the side length x, we have
Area = x²
So, the number of squares is
Squares = 70.56/x²
Note that the only factors that can divide 9.8 and 7.2 is 2
This means that
Squares = 70.56/2²
Evaluate
Squares = 17.64
So, the area of each square is 17.64 and the value of x is 2
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Please answer for BRAINLIEST!
Answer:
1.5 units squared
Step-by-step explanation:
Area of a Triangle formula: A = 1/2bh
Pythagorean Theorem: a² + b² = c²
Since you are missing the h to find the area of the triangle, you must use Pythagorean to find the 3rd missing side (it is a right triangle so you can use Pythagorean).
Step 1: Use Pythagorean
2.5² = 1.5² + b²
4 = b²
b = 2
Step 2: Switch variables
b (from Pythagorean) = h (height for Area)
Step 3: Solve for Area
A = 1/2(1.5)(2)
A = 1.5
And you have your final answer.
A car started out from Memphis toward Little Rock at the rate of 60 mph. A second car left from the same point 2
hours later and drove along the same route at 75 mph. How long did it take the second car to overtake the first car?
It takes the second car 10 hours to overtake the first car on the same route from Memphis.
To solve this problem, we can use the formula:
distance = rate x time
Let's call the distance traveled by both cars "D" and the time it takes for the second car to overtake the first car "t".
Step 1: Let x be the number of hours it takes for the second car to overtake the first car.
For the first car, we know that:
D = 60t
Since the second car started 2 hours later, it has to travel for a shorter amount of time to cover the same distance as the first car. So for the second car, we have:
D = 75(t-2)
Now we can set these two equations equal to each other and solve for "t":
60t = 75(t-2)
60t = 75t - 150
15t = 150
t = 10
So it took the second car 10 hours to overtake the first car.
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The largest pyramid at giza is a square pyramid. it has a base of 756 feet and a slant height of 612 feet. which represents the two-dimensional net of this pyramid? a rectangular pyramid. the rectangular base is 756 feet by 612 feet. a square pyramid. the square base has side lengths of 756 feet. the triangular sides have a height of 612 feet. a square pyramid. the square base has side lengths of 756 feet. the triangular sides have a height of 612 feet. the triangles connect to the square by their points. 5 connected triangles with a base of 756 feet and height of 612 feet.
The two-dimensional net of this pyramid is the square base has side lengths of 756 feet. the triangular sides have a height of 612 feet.
What is a pyramid?A square pyramid is a 3-dimensional shape with a square base and 4 triangular faces that are joined at a vertex.
The net of a pyramid is made up of one square and four triangles. The rectangle is the base of the pyramid, and the triangles are the lateral faces.
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the answer is B, or #2. hope this helps. Edgen 2022.
Ixl dilations-find the scale factor and center dilation
The scale factor is 2 and center dilation is reduced.
The scale factor is a ratio that describes how much a figure has been enlarged or reduced. It is calculated by dividing the length of the corresponding sides of the original and dilated figures. If the scale factor is greater than 1, then the figure is enlarged, and if it is less than 1, then the figure is reduced.
To find the scale factor in an IXL dilations problem, you need to compare the corresponding sides of the original and dilated figures.
If the original figure has a side length of 4 units, and the dilated figure has a corresponding side length of 8 units, then the scale factor is 8/4=2. This means that the dilated figure is twice as large as the original figure.
The center of dilation is the point about which the figure is enlarged or reduced. It is the fixed point that remains unchanged during the dilation process.
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The expression 3(x+4)-(2x+7) is equivalent to
Answer:
x=5
Step-by-step explanation:
3(x+4)-(2x+7)
use the disturbutive property
3x+12-(2x+7)
distrubute the - sign on the bracket number
3x+12-2x-7
combine the like terms
3x-2x= 1x which is just x
12-7=5
x=5
Answer:
x+5
Step-by-step explanation:
Distribute the 3 and distribute the minus sign (-1).
3(x + 4) - (2x + 7) = 3x + 12 - 2x - 7 = x + 5
The dean of Blotchville University boasts that the average class size there is 20. But the reality experienced by the majority of students there is quite different: they find themselves in huge courses, held in huge lecture halls, with hardly enough seats or Haribo gummi bears for everyone. The purpose of this problem is to shed light on the situation. For simplicity, suppose that every student at Blotchville University takes only one course per semester.
a) Suppose that there are 16 seminar courses, which have 10 students each, and 2 large lecture courses, which have 100 students each. Find the dean’s eye view average class size (the simple average of the class sizes) and the student’s eye view average class size (the average class size experienced by students, as it would be reflected by surveying students and asking them how big their classes are). Explain the discrepancy intuitively.
b) Give a short proof that for any set of class sizes (not just those given above), the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
a) Find the dean’s eye view average class size and the student’s eye view average class size:Given that there are 16 seminar courses, each having 10 students each.Number of students in seminar courses: 16 × 10 = 160There are 2 large lecture courses, each having 100 students each.
Number of students in large lecture courses: 2 × 100 = 200
Dean’s view average class size is the simple average of the class sizes:Let’s find the Dean’s view average class size. There are 18 courses in total.
This can be obtained by dividing the total number of students by the total number of classes.
Student’s view average class size = Total number of students/Total number of classes
= 360/18
= 20
Therefore, the dean’s eye view average class size is 46.67 (approximately) and the student’s eye view average class size is 20.
Now, we need to prove that D 2, then (k/(k + 1)) - (1/n) < 0.
Therefore, we have:
S - D< (c2 - c1)*[(k/(k + 1)) - (1/n)]< 0
Hence, S < D.Therefore, the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
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SOMEONE ANSWER ASAP PLS PLS TYYY!!
Answer:
a b
Step-by-step explanation:
I think it is a and b if am not wrong good luck
is the relation a function?
Answer:
Yes, each x-value is paired with exactly one y-value (no more than that)
Domain: x = -2, x = 1, x = 4, x = 7
Range: y = -3, y = 5, y = 6
No, the inverse is not a function, the x value of 6 would be paired with two y values (-2 and 7)