Answer:
Visible Spectrum/Electromagnetic spectrum
Explanation:
The visible spectrum is the portion of the electromagnetic spectrum that is visible to the human eye.
Balance the following Equation Show your work.
1.____CaO + ____H2O → ____Ca(OH)2
2. ___HgO → ___Hg + ____O2
3. ___KI + ___Pb(NO3)2 → ____PbI2 + ___KNO3
4. ___Al + ___Cl2 → ___AlCl3
5. ___KBr + ___Cl2 → ___KCl + ____Br2
6. __Mg3(PO4)2 + __NaOH → __Na3PO4 + __Mg(OH)2
7. ___H2O → ___H2 + ___O2
8. ___CH4 + __O2 → __CO2 + __H2O
9. ___C2H6 + ___O2 → ___CO2 + ___H2O
10. ___H2 + ___N2 → ___NH3
Answer:
1) alr balanced
2) 2 2 1
3) 2 1 1 2
4) 2 3 2
5) 2 1 2 1
6) 1 6 2 3
7) 2 2 1
8) 1 2 1 2
9) 2 5 4 6
10) 3 1 2
Stained glass can be useful for _____________________ a. Transmitting light and displaying colorful images. B. Churches to draw in new patrons who want to view its beauty from inside. C. Reflecting and absorbing light, as well as displaying colorful images. D. Creating mirrored images of light and colors on the surrounding walls of a religious structure. Please select the best answer from the choices provided A B C D.
It can be used for transmitting light and displaying colourful images.
Stained glasses are the coloured glasses or the coloured images drawn on the transparent glasses that are majorly used in religious or places with architectural beauty.
What is the use of stained glass?Stained glasses are prepared by adding metallic salts to the glass for decorating purposes and in some patterns to create a beautiful image. The light from the sources is transmitted through them and a colourful image is displayed to the viewers.
The stained glass does not absorb or reflect light as they are not transparent but they transmit the light. They are used in churches to create beautiful images but not to draw the patrons.
Therefore, option a. is correct.
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What is the Noble-gas notation for sodium?
O [Ar]3s¹ 1
O [He]2s²2p 3s¹
[Ne]3s²3p4
O[Ne]3s¹
Answer:
The noble gas notation for sodium is [Ne] \(3s^{1\\\)
Explanation:
From the list below,choose which groups are part of the periodic table?
From the list provided, the following groups are part of the periodic table are Metals, Nonmetals , Semimetals and Conductors .
Metals: Metals are a group of elements that are typically solid, shiny, malleable, and good conductors of heat and electricity. They are located on the left-hand side and middle of the periodic table.
Nonmetals: Nonmetals are elements that have properties opposite to those of metals. They are generally poor conductors of heat and electricity and can be found on the right-hand side of the periodic table.
Semimetals: Semimetals, also known as metalloids, are elements that have properties intermediate between metals and nonmetals. They exhibit characteristics of both groups and are located along the "staircase" line on the periodic table.
Conductors: Conductors are materials that allow the flow of electricity or heat. In the context of the periodic table, certain metals and metalloids are good conductors of electricity.
Therefore, the groups that are part of the periodic table are metals, nonmetals, semimetals, and conductors. The other groups mentioned, such as acids, flammable gases, and ores, are not specific groups found on the periodic table but may be related to certain elements or compounds present in the table.
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The complete question is :
From the list below, choose which groups are part of the periodic table.
metals
acids
flammable gases
nonmetals
semimetals
ores
conductors
he half-life of a radioactive substance is 21 years. If we begin with a sam substance, calculate the value of b to complete the model belo which gi sample remaining after t years. f(t)=85⋅(b) t
Enter your answer for b in the box below, rounded to three decimals.
The value of b in the equation \(\( f(t) = 85 \cdot b^t \)\) represents the decay factor of the radioactive substance. To determine the value of \( b \), we can use the information that the half-life of the substance is 21 years.
The half-life of a radioactive substance is the time it takes for half of the substance to decay. In this case, the half-life is 21 years, which means that after 21 years, the amount of the substance remaining will be half of the initial amount.
We can use this information to set up an equation:
\(\(\frac{1}{2} = b^{21}\)\)
To solve for b, we need to take the 21st root of both sides of the equation:
\(\(b = \left(\frac{1}{2}\right)^{\frac{1}{21}}\)\)
Using a calculator, we can evaluate this expression:
\(\(b \approx 0.965\)\)
Therefore, the value of b in the equation \(\( f(t) = 85 \cdot b^t \)\) is approximately 0.965.
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Consider the following unbalanced equation:
NH3(g) → N₂(g) + H₂(g)
Answer: 2NH3(g) → N₂(g) +3 H₂(g)
Both sides have:
2 nitrogens
6 hydrogens
A calculation based upon _______is only as accurate as the device used for measurement.
Predict the decreasing order of vapor pressure for the following compounds i) CH3CH₂OH; ii) CH3CH₂F; iii) CH3CH3 a) i>ii >iii b)i>iii>ii c)ii> i>iii d) ii > iii >i e) iii > ii >i [(CH₂)₂COL with those
\(CH_3CH_2OH\) is a polar compound and has hydrogen bonding. It has a higher boiling point. It will have the lowest vapor pressure among the three compounds.
Vapor pressure is the pressure produced by the vapors of a liquid in a sealed container when the liquid is heated. It is a property of a liquid that describes the tendency of a liquid to evaporate. It is measured in units of pressure, typically in mmHg or torr. The higher the vapor pressure, the more volatile a compound is. So, the decreasing order of vapor pressure for the given compounds is: \(CH_3CH_3 > CH_3CH_2F > CH_3CH_2OH\)
Here, \(CH_3CH_3\) is a non-polar compound while \(CH_3CH_2F\) and \(CH_3CH_2OH\) are polar compounds. The polar compound has hydrogen bonding, which increases the intermolecular forces between molecules. As a result, the polar compound will have a lower vapor pressure than the non-polar compound.
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Volcanoes can be destructive LOCALLY causing all of the following immediate effects EXCEPT:
O New growth in forests
O Personal damage
O Lack of breathable air
O Disruption of clean water
O Death
Answer:
New growth of trees is an exception
Explanation:
when volcanoes erupt, they release hot magma that is destructive to the environment causing personal damage, lack of breathable air and death.
heat produce cannot in any way help in growth of trees
the fluid component of connective tissue is called ________.
The fluid component of connective tissue is called the extracellular matrix. The extracellular matrix (ECM) is a complex mixture of substances that fills the space between cells in connective tissue.
The extracellular matrix (ECM) is composed of a fluid component and various types of proteins, fibers, and other molecules. It is often referred to as tissue fluid or interstitial fluid. It is a clear, colorless fluid that fills the spaces within the connective tissue and provides a medium for the exchange of nutrients, gases, and waste products between cells and blood vessels.
The fluid in the ECM contains water, ions, small molecules, and dissolved substances such as hormones, enzymes, and nutrients. It also plays a role in maintaining the hydration and structural integrity of the tissue.
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What is the∆S° of 0₂
Answer:0
Explanation: zero because it is the most stable form of oxygen in its standard state
1. what atom has five shells and seven valence electrons
2. Compare the elements Ar and Cl
a. Which has the greater force of attraction
b. which has the greater ionization energy
c. Which is better at keeping its electrons
d. which is better at keeping its electrons
3. Compare the elements N and P
a. Which has the greater force of attraction
b. which has the greater ionization energy
c. Which is better at keeping its electrons
d. which is better at keeping its electrons
1. The atom that has five shells and seven valence electrons is Iodine.
The atomic number of Iodine is 53, having the electronic configuration of 2,8, 18, 18, 7. Iodine thus has 5 shells and 7 valence electrons.
2. Comparison of Ar and Cl
a) Cl has a greater force of attraction- Cl has 7 electrons in the valence shell thus to obtain the noble gas configuration it attracts the electrons.
b) Ar has greater ionization energy- Ionization energy increases along a period.
c) Ar is better at keeping its electrons- Argon is a noble gas and thus has a stable electronic configuration.
d) Ar is better at keeping its electrons- Argon is a noble gas and thus has a stable electronic configuration.
3. Comparison of N and P
a) N has the greater force of attraction- N is smaller than P thus the force of attraction is greater.
b) N has greater ionization energy- ionization energy decreases down the group.
c) N is better at keeping its electrons- due to the smaller size of nitrogen.
d) N is better at keeping its electrons- due to the smaller size of nitrogen.
1) The atom that has five shells and seven electrons is chlorine. Chlorine has a greater force of attraction. The ionization energy is one of the periodic trends in the table.
What is the periodic table?We know that the periodic table has to do with the arrangement of the elements and the way that the elements have been arranged would have a lot to do with the chemical properties of the elements.
Let us note that elements have been arranged into groups and periods. The groups are the vertical columns while the periods are the horizontal rows that we can find in the periodic table as we can see it.
Finally;
Argon has a greater ionization energyArgon keeps its electrons betterNitrogen has a greater force of attractionNitrogen has a greater ionization energyNitrogen keeps its electrons better.Learn more about periodic table:https://brainly.com/question/11155928
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I have multiple questions about this prompt:a) Is the limiting reactant in the reaction: oxygen, hydrogen, or water?b) After the reaction is complete, how many molecules of water will be formed: 10, 5, 7, or 14c) How many molecules of excess reactant will remain after the reaction is complete: 4, 3, 2, or 1d) After the reaction is complete, which of the following will be found in the reaction vessel: oxygen, water, hydrogen (can be more than 1)
Answer:
\(\begin{gathered} a)\text{ Hydrogen} \\ b)\text{ 10} \\ c)2 \\ d)\text{ oxygen, water} \end{gathered}\)Explanation:
a) Here, we want to get the limiting reactant
To get this, we only consider the reactants
This is the left side that contains only hydrogen and oxygen
When we talk of the limiting reactant, we refer to that reactant that would be used up in the formation of the product
Let us take a look at the chamber
We have 10 molecules of hydrogen and 7 molecules of oxygen
To form a molecule of water, we have to use a full molecule of hydrogen and half molecule of oxygen
So, the total number of oxygen present is 7 * 2 = 14
For the hydrogen, we only have 10
14 will outlive 10, so we are left with oxygen
Since hydrogen will be used up and we still have oxygen, then hydrogen is the limiting reactant as it determines the number of molecules of water that will be formed
b) The number of molecules of water formed is the number of hydrogen molecules present. From the count, we have this as 10. That means the number of molecules of water formed is 10
c) From the question, out of the total 14, 10 will be used, remaining 4
A pair makes a molecule. Thus,we have 2 molecules of oxygen left
d) From the question,we know that hydrogen will be used up while oxygen is left. Water is also formed. So we have oxygen and water left in the chamber
In a tug of war, the team on the left pulls with a force of 430 N and the team on the right pulls with a force of 420 N. What is the net force on the rope?
A. 10 N to the right
B. 10 N to the left
C. 420 N to the right
D. 430 N to the left
Answor
c
Explanation:
Solve for missing values using the ideal gas law formula:
1. 10°C, 5. 5 L, 2 mol, __ atm. What is the atm?
2. __ °C, 8. 3 L, 5 mol, 1. 8 atm. What is the temperature in celsius?
3. 12°C, 3. 4 L, __ mol, 1. 2 atm. What is the mole?
The ideal gas law formula is used to determine the missing values in questions. When dealing with problems that require solving for missing values using the ideal gas law formula, always ensure that all values are expressed in the correct units and temperature is converted to kelvin.
The ideal gas law formula is represented as PV = nRT, where P represents pressure, V represents volume, n represents the number of moles of gas, T represents the temperature in kelvin, and R represents the universal gas constant. Solve for missing values using the ideal gas law formula:1. 10°C, 5. 5 L, 2 mol, __ atm.The temperature must be converted to kelvin first: T(K) = T(°C) + 273.15K = 10°C + 273.15 = 283.15KPV = nRT
Rearrange the equation to isolate P: P = nRT / V
Substitute the given values:
P = (2 mol)(0.0821 L•atm/mol•K)(283.15K) / 5.5 L
: P = 8.28 atm
2. __ °C, 8. 3 L, 5 mol, 1. 8 atm.The equation PV = nRT can be rearranged to T = PV / nRThe temperature must be converted to kelvin first: T(K) = T(°C) + 273.15T = PV / nR
Substitute the given values: T = (1.8 atm)(8.3 L) / (5 mol)(0.0821 L•atm/mol•K)T(K) = T +
: T = 332 K or 59°C
The temperature must be converted to kelvin first:
T(K) = T(°C) + 273.15K
= 12°C + 273.15
= 285.15
KPV = nRT
Solve for n by rearranging the equation: n = PV / RT
Substitute the given values: n = (1.2 atm)(3.4 L) / (0.0821 L•atm/mol•K)(285.15K): n = 0.141 mol
The ideal gas law formula is used to determine the missing values in questions. When dealing with problems that require solving for missing values using the ideal gas law formula, always ensure that all values are expressed in the correct units and temperature is converted to kelvin.
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A balloon is filled with air. It has a volume of 720 mL at a temperature of 22° C. You put the
balloon inside your hot oven where the temperature is now 109° C. What is the new volume
of the balloon?
mL
At a temperature of 109° C, the balloon's new volume is roughly 932.6 mL.
What happens to the balloon's volume as the temperature rises?The gas particles take in more heat as the temperature rises. They accelerate and advance apart from one another. Hence, an increase in volume is brought on by a rise in temperature.
We can use Charles's Law to solve this question,
V1/T1 = V2/T2
where, V1 = initial volume
T1 = initial temperature
V2 = final volume
T2 = final temperature,
Now, we have to convert the temperatures to the absolute scale, which is Kelvin (K).
T1 = 22 + 273.15 = 295.15 K
T2 = 109 + 273.15 = 382.15 K
Now, we can substitute values;
V1/T1 = V2/T2
720/295.15 = V2/382.15
Solving this equation,
V2 = (720/295.15) x 382.15
V2 = 932.6 mL
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Newton's Third Law of Motion states that objects exert equal forces on each other in opposite directions.
Which of the following examples best describe Newton's Third Law of Motion?
Answer: a truck crashes into a car
Explanation:
The truck drives in a wrong motion which makes the reaction of it crashing.
Which of the following accurately describes the orbital path of most planets in our solar system?
The orbital path is in a perfect circle.
The orbital path looks circular.
The orbital path is in a large elliptical shape.
The orbital path varies greatly from planet to planet.
find the concentration in (a) mg/l, (b) ppm, (c) ppb, and (d) moles/l (m), respectively, for the following solution: 0.5 g of kcl dissolved in 500 ml of water
The formula for calculating the concentration of a solution in mg/L is as follows:Concentration in mg/L = (weight of solute in mg / volume of solution in L). Concentration in mg/L = (0.5 g × 1000 mg/g) / 0.5 L. Concentration in mg/L = 1000 mg/L.
(b) The formula for calculating the concentration of a solution in ppm is as follows:
Concentration in ppm = (weight of solute in mg / volume of solution in ml) × 10³.
Concentration in ppm = (0.5 g × 1000 mg/g) / 500 ml × 10³.
Concentration in ppm = 1000 ppm.
(c)The formula for calculating the concentration of a solution in ppb is as follows:
Concentration in ppb = (weight of solute in mg / volume of solution in ml) × 10⁶.
Concentration in ppb = (0.5 g × 1000 mg/g) / 500 ml × 10⁶.
Concentration in ppb = 1000000 ppb.
(d) Moles/lThe molecular weight of KCl is 74.55 g/mol.
To calculate the concentration of KCl in moles/liter, we must first convert 0.5 g to moles.
Number of moles = weight / molecular weight.
Number of moles of KCl = 0.5 g / 74.55 g/mol.
Number of moles of KCl = 0.0067 moles.
Concentration in moles/liter = number of moles / volume in L.
Concentration in moles/liter = 0.0067 moles / 0.5 L.
Concentration in moles/liter = 0.013 M (M = moles/L).
Therefore, the concentration of KCl is (a) 1000 mg/L, (b) 1000 ppm, (c) 1000000 ppb, and (d) 0.013 M.
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In a solution of hydrogen in palladium, ____ is used as a solute and ___ is used as a solvent.
Answer:gas, solid
Explanation:ck12
In a solution of hydrogen in palladium, gas is used as a solute and solid is used as a solvent.
What is a Solution?This is defined as a homogenous mixture which comprises of two or more substances. Solute usually dissolves in the solvent to form it.
The hydrogen acts as the solute while the palladium acts as the solvent in this case.
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Gaseous ethane, C2H6, burns in the presence of oxygen
gas according to the balanced equation below.
2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)
How many moles of carbon dioxide can be produced from
1.00 mol of ethane?
04.00 mol CO2
0 0.50 mol CO2
01.00 mol CO2
2.00 mol CO2
Moles of Carbon dioxide(CO2) = 2
Further explanationGiven
Reaction
2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)
Required
moles of carbon dioxide
Solution
The reaction coefficient shows the mole ratio of the compounds in the reaction equation (reactants and products)
From the equation, mol ratio of C2H6 : CO2 = 2 : 4, so mol CO2 :
mol CO2 = (4/2) x mol C2H6
mol CO2 = 2 x 1
mol CO2 = 2
0. A radioactive isotope has a half-life of 273 days. How much of a sample of 100 grams of the isotope would remain after 732 days?
The amount of a sample of 100 grams of a radioactive isotope that would remain after 732 days would be 14.0625 grams.
Given, the Half-life of the radioactive isotope = 273 days.Time elapsed = 732 days.Initial quantity or sample = 100 grams. Let's determine how many half-lives have passed since 732 days: Number of half-lives = (time elapsed) / (half-life)= 732 / 273 ≈ 2.683
Half-life #1: After the first half-life of 273 days, the sample will be halved. Therefore, after 273 days, the quantity remaining will be 1/2 * 100g = 50g
Half-life #2: After the second half-life of 273 days, the sample will be halved again. Therefore, after 546 days, the quantity remaining will be 1/2 * 50g = 25gHalf-life #3: After the third half-life of 273 days, the sample will be halved again.
Therefore, after 819 days, the quantity remaining will be 1/2 * 25g = 12.5gHowever, the time elapsed from 819 days to 732 days is 87 days. This time interval is less than the half-life. As a result, it is critical to calculate the amount that would be left over after 732 days using a different method. Let us consider the remaining amount from 819 days (12.5g) as the new initial quantity for the remaining 87 days. The half-life of the radioactive isotope is 273 days.
Therefore, the rate of decay for each day will be: Rate of decay per day = (1/2)^(1/273)≈ 0.002540401Therefore, the amount of the sample remaining after 87 days (or 0.3195 half-lives) can be calculated using the following formula: Q = Q0(0.5)^(t/h)where Q0 is the original quantity, Q is the remaining quantity after time t, and h is the half-life of the isotope. Q = 12.5g × (0.5)^(0.3195)Q ≈ 6.5625g
Therefore, the total amount of the sample remaining after 732 days can be found by adding up the amounts of the sample remaining from each half-life: Total remaining = 50g + 25g + 6.5625gTotal remaining ≈ 81.5625 the amount of a sample of 100 grams of a radioactive isotope that would remain after 732 days would be 14.0625 grams.
After 732 days, the sample would have decayed by three half-lives (819 days) and an additional 87 days. As a result, 81.5625g of the sample will remain after 732 days. Therefore, 100g - 81.5625g = 18.4375g of the sample would have decayed in 732 days.
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7. Which of the following elements is diatomic?
Mg
Mn
Sn
F
Which organelle stores water, sugar, and waste products in plant cells?
vacuoles
the cell wall
chloroplasts
ribosomes
Answer:
The first one - Vacuoles
Explanation:
Hope this helps. :)
8.) If 396 g of Carbon Dioxide (CO2) are produced, what mass of Oxygen
(02) reacted? *
Answer:
264g
Explanation:
C + O2 -> CO2
_g + _g -> 396g
396÷3=132
C (132g) + O2 (264g) -> CO2 (396g)
Which of the following would convert chemical energy to mechanical energy?
Group of answer choices
Jet Ski
Cars
Humans
All of the above
Which of the following will have a highest electronegativity? *
O Carbon (C)
O Neon (Ne)
O Antimony (Sb)
O Germanium (Ge)
For+the+reaction+H2+++I2+-+2HI+the+equilibrium+constant,+kc+is+49+at+a+fixed+temperature.+Two+mole+of+hydrogen+and+two+moles+of+iodine+are+allowed+to+reach+equilibrium+at+this+temperature.+What+is+the+concentration+of+hydrogen+iodide+at+equilibrium?
Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M respectively.
Solution : Given,
Initial concentration of H_2 and I_2 = 0.11 M
Concentration of H_2 and I_2 at equilibrium = 0.052 M
Let the initial concentration of HI be, C
The given equilibrium reaction is,
H_2(g)+I_2(g)\rightleftharpoons 2HI(g)
Initially 0.11 0.11 C
At equilibrium (0.11-x) (0.11-x) (C+2x)
As we are given that:
Concentration of H_2 and I_2 at equilibrium = 0.052 M = (0.11-x)
The expression of K_c will be,
K_c=\frac{[HI]^2}{[H_2][I_2]}
54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}
By solving the terms, we get:
C = 0.27 M
Thus, initial concentration of HI = C = 0.27 M
Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M
what does Le châteliers principle state?
SEP Construct an Explanation What challenges do the three industries have in making better batteries? What solutions are being suggested?
The three industries commonly associated with battery technology are the automotive, electronics, and renewable energy sectors. Each of these industries faces specific challenges when it comes to developing better batteries.
Automotive Industry:
Energy Density: One of the primary challenges for electric vehicles (EVs) is improving battery energy density, which refers to the amount of energy that can be stored per unit of volume or weight. Higher energy density batteries would allow for longer driving ranges and reduced charging times.Cost: Batteries constitute a significant portion of an electric vehicle's cost. Therefore, reducing the cost of battery production is crucial for making EVs more affordable and competitive with traditional internal combustion engine vehicles.Charging Infrastructure: The limited availability of charging stations and relatively longer charging times compared to refueling a conventional vehicle remain challenges. The industry is focusing on expanding charging infrastructure and developing fast-charging technologies to address this issue.Electronics Industry:
Power Density: Electronic devices, such as smartphones and laptops, require batteries with high power density to support their energy-intensive operations. However, increasing power density while maintaining safety and minimizing size is a challenge.Battery Lifespan: Consumers expect electronic devices to have a longer battery life before needing a recharge. Enhancing battery lifespan through improved materials, design, and management systems is an ongoing pursuit.Environmental Impact: The electronics industry is increasingly concerned about the environmental impact of batteries, particularly regarding the disposal and recycling of lithium-ion batteries. Developing sustainable and eco-friendly battery technologies is a suggested solution.Renewable Energy Industry:
Energy Storage Capacity: Renewable energy sources like solar and wind are intermittent, meaning they are not continuously available. Efficient energy storage solutions are needed to store excess energy produced during peak times and supply it during periods of low or no generation. Integration with the Grid: Integrating renewable energy sources with the existing electrical grid is a challenge due to fluctuations in supply and demand. Advanced battery technologies can help stabilize the grid by providing rapid response and balancing services.Durability and Longevity: Renewable energy projects, such as utility-scale installations, require long-lasting and durable batteries that can withstand frequent charge-discharge cycles without significant degradation. Enhancing battery life and reliability is a focus for the industry.For such more questions on technology
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