Answer:
We define a vector as an object with a length and a direction.With no length, the zero vector is not pointing in any particular direction, so it has an undefined direction.
Explanation:
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a 1.0-g bead is at (-2.0 cm, 3.0 cm), a 3.0-g bead is at (2.0 cm, -5.0 cm), and a 3.0-g bead is at (4.0 cm, 0.0 cm). what are the coordinates of the center of mass (or center of gravity) of this system of beads?
The coordinates of the center of mass of this system of beads are (2.0 cm, -1.0 cm).
To find the coordinates of the center of mass of this system of beads, we need to use the formula:
xcm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)
ycm = (m1y1 + m2y2 + m3y3) / (m1 + m2 + m3)
where xcm and ycm are the coordinates of the center of mass, m1, m2, and m3 are the masses of the beads, and x1, y1, x2, y2, x3, and y3 are their respective coordinates.
Plugging in the values we have:
xcm = (1.0 g * (-2.0 cm) + 3.0 g * 2.0 cm + 3.0 g * 4.0 cm) / (1.0 g + 3.0 g + 3.0 g) = 2.0 cm
ycm = (1.0 g * 3.0 cm + 3.0 g * (-5.0 cm) + 3.0 g * 0.0 cm) / (1.0 g + 3.0 g + 3.0 g) = -1.0 cm
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The instant before a tennis racquet hits a 0.057 kg tennis ball, the velocity of the ball is 55 m/s west. The instant after
the batter hits the ball, the ball's velocity is 45 m/s east. The racquet and ball are in contact for 1.5 x 10-2
S.
Determine the acceleration of the tennis ball while it is in contact with the racquet. State direction clearly.
670 m/s2 [E]
6700 m/s? [E]
670 m/s2 [W]
6700 m/s2 [W]
Answer: 6700m/s^2 E
Explanation:
Given the following :
Velocity of ball before being hit by a racquet = initial velocity(u) = 55m/s W
Velocity of the ball after being hit = final Velocity (v) = 45m/s E
Time of contact between ball and racquet (t) = 1.5 × 10^-2
The acceleration of a body is the change in Velocity of a body with time. It given by:
Acceleration (a) = [final Velocity(v) - initial velocity(u)] / time(t)
The westward direction is towards the left and thus Velocity takes a negative value, similarly, if it's towards the right, Velocity takes a positive value.
Therefore,
a = [45 - (-55)] / 1.5×10^-2
a = [45 + 55] / 0.015
a = 100 / 0.015
a = 6666.6666 m/s^2
a = 6700m/s^2 E
Since the value of acceleration is positive, the direction is towards the East (acceleration is in the direction of the ball's final Velocity).
The ratio of the potential difference across a conductor to the current in the conductor is called
A) conductivity
B) resistance
C) charge
D) power
Answer:
The ratio of the potential difference across a metallic conductor to the current in the conductor is known as.
B. Resistance.
Explanation:
According to ohms law " the current passing through a conductor is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant".
What is resistance ?
Resistance is a measure of the opposition to current flow in an electrical circuit
what is a resistor ?
a resistor is a n electric conductor which forms resistance to free flow of electric current, the resistance is measured in Ω
The ratio of the potential difference across the conductor to the current is called resistance
What is Resistance?It is defined as the ratio of the potential difference across the conductor to the current. The resistance is measured in Ω.
\(R = \dfrac VI\)
Where,
\(R\) - resistance
\(V\)- voltage (Potential difference)
\(I\) - current
Therefore, the ratio of the potential difference across the conductor to the current is called resistance.
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Unpolarized light is incident onto three polarizers with their transmission axes oriented in such a way that the first and the last make a 39 angle between them, and the middle one makes the same angle with the first and the last one. Find the percentage of the incident light which passes through these three polarizers.
Answer:
I₃ = I₀ 0.395
Explanation:
Polarized light passing through a polarizer must comply with Malus's law
I = I₀ cos² θ
Before starting, let's analyze the angle between the polarizers, the second has the same angle with the first and the third, so it is at the midpoint
θ₂ = 39/2 = 19.5
now let's analyze the light that passes through each polarizer, as the incident is unpolarized through the first polarizer half the intensity comes out
I₁ = I₀ / 2
the second polarizer comes out
I₂ = I₁ cos² 19.5
I₂ = I₀ / 2 cos² 19.5
through the third polarized the intensity passes
I₃ = I₂ cos² 19.5
I₃ = (I₀ /2 cos² 19.5) cos² 19.5
I₃ = I₀ 0.395
categorize we evaluate the current with an equation developed in this section, so we categorize this example as a substitution correct: your answer is correct. problem. combine imax
Example categorized as correct substitution problem using equation from section to evaluate current.
This means that the given problem involves replacing variables in an equation with given values and solving for the unknown variable. The solution obtained using this method is deemed correct according to the equation developed in the section. The use of equations in problem-solving is a common practice in various fields, including mathematics, physics, and engineering. By categorizing problems, it becomes easier to identify the appropriate methods to use in solving them, which can improve problem-solving efficiency and accuracy. Example categorized as correct substitution problem using equation from section to evaluate current. Imax is the maximum current and the answer obtained is deemed correct according to the equation developed in the section.
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(Newton's Law of Cooling): The mathematical formulation of Newton's empirical law of cooling/warming of an object is given by the linear first-order differential equation
dt
dT
=k(T−T
s
), where k is a constant of proportionality, T(t) is the temperature of the object at any time t≥0, and T
s
is the surrounding environmental temeperature, that is, the temperature of the medium around the object. (i). Assuming that T
s
is constant, find the temeperature of the object as a function of time if T(0)=T
0
. (ii). Then what is the temepretauer of the object after 5 minutes?
Newton's Law of Cooling is described by the first-order linear differential equation dt/dT = k(T - Ts), where T(t) is the temperature of the object at time t, Ts is the surrounding environmental temperature, and k is the constant of proportionality.
The temperature of an object, governed by Newton's Law of Cooling
(i) To find the temperature of the object as a function of time, we first solve the differential equation dt/dT = k(T - Ts). This is a separable differential equation, and the solution can be obtained by rearranging and integrating:
dt/dT = k(T - Ts)
dt = k(T - Ts) dT
∫ dt = ∫ k(T - Ts) dT
t = k * ∫ (T - Ts) dT
t = k * (T^2/2 - Ts*T) + C
Now, we apply the initial condition T(0) = T0. At t=0, the temperature of the object is T0:
T(0) = T0
k * (\(T0^2\)/2 - Ts*T0) + C = T0
C = T0 - k * (\(T0^2\)/2 - Ts*T0)
C = T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2
C = T0 - k * (\(T0^2\) - 2 * Ts * T0) / 2
So, the equation becomes:
t = k * (\(T^2\)/2 - Ts*T) + (T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2)
(ii) Now, we can find the temperature of the object after 5 minutes (t = 5 minutes). We'll use the initial condition T(0) = T0 and the formula obtained in part (i):
t = 5 minutes = 5/60 hours = 1/12 hours
T(t) = Ts + (T0 - Ts) * exp(-kt)
T(1/12) = Ts + (T0 - Ts) * exp(-k * (1/12))
This equation gives us the temperature of the object after 5 minutes, considering the given initial temperature T0 and the surrounding environmental temperature Ts.
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Prove that the equations PV/T=C1 for m constant and V/m=C2 for T and P constant lead to PV/mT=a constant.
To prove that the equations PV/T = C1 for m constant and V/m = C2 for T and P constant lead to PV/mT=a constant, we need to manipulate both equations.
First, we can multiply both sides of the equation PV/T = C1 by m, to get: PV/T x m = C1 x m
Rearranging this equation to isolate V/T on one side, we get: V/T = C1m/P
Now, we can substitute V/T in the equation V/m = C2 for T and P constant, to get: C1m/P = C2
Finally, we can multiply both sides of this equation by mT, to get: PV/mT = C1m x C2/P
Since C1m/P and P are both constants, we can conclude that PV/mT = a constant.
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Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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To obtain the number of meters from a distance measured In centimeters, you must ____ by the number _____
Answer:
Divide by the number 100
Explanation:
Since there are 100 centimeters in 1 meter, we can see that if you are given a number in centimeters, the number of meters is that number divided by 100. Hope this helps!
Answer:
Divide by 100
Explanation:
Learning Goal: As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation ene
Higher temperatures increase the average kinetic energy of molecules, allowing a larger percentage to possess the required activation energy in a chemical reaction, leading to faster reaction rates.
As temperature increases, the average kinetic energy of molecules within a substance also increases. This is due to the fact that temperature is a measure of the average energy of motion of the particles. In a chemical reaction, the rate of reaction is determined by the collision of molecules and their ability to overcome the activation energy barrier.
When the temperature rises, a larger proportion of molecules possess sufficient energy to surpass the activation energy threshold. This is because the higher kinetic energy allows more molecules to reach or exceed the necessary energy level for the reaction to occur. As a result, a larger number of successful collisions take place, leading to a faster reaction rate.
The increased kinetic energy not only provides the necessary energy for the reactant molecules to collide effectively but also promotes a greater frequency of collisions. The higher the temperature, the more rapid and energetic the molecular motion becomes, leading to more frequent collisions and an increased likelihood of successful reactions.
In summary, as temperature rises, the average kinetic energy of molecules increases. This elevated kinetic energy enables a greater percentage of molecules to possess the required activation energy, leading to more frequent and successful collisions in a chemical reaction. Consequently, the reaction proceeds at a faster rate.
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The question probable may be:
Learning Goal: As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required actevation energy, and the reaction goes faster. Explain.
if the loop is pulled away from the wire at speed v , what emf is induced in it? express your answer in terms of the variables i , a , b , v , and appropriate constants.
The emf induced in the loop is emf = v*A/a
The emf induced in a loop of wire is given by Faraday's Law of Electromagnetic Induction, which states that the emf induced in a loop is proportional to the rate of change of magnetic flux through the loop.
If the loop is pulled away from the wire at speed v, then the magnetic flux through the loop is changing. The magnitude of the induced emf can be calculated using the formula:
emf = - d(phi)/dt
where phi is the magnetic flux through the loop, and the negative sign indicates that the emf induced opposes the change in magnetic flux.
The magnetic flux through the loop is given by:
phi = B*A
where B is the magnetic field strength, and A is the area of the loop.
Since the loop is being pulled away from the wire, the magnetic field strength experienced by the loop decreases with time, because the loop is moving away from the source of the magnetic field.
The rate of change of magnetic field strength can be expressed as:
dB/dt = -v/a
where a is the distance between the wire and the loop, and the negative sign indicates that the magnetic field strength is decreasing.
Substituting this expression for dB/dt into Faraday's Law, we get:
emf = -d(phi)/dt = -d(BA)/dt = -AdB/dt = -A*(-v/a) = v*A/a
Therefore, the emf induced in the loop is:
emf = v*A/a
where v is the speed at which the loop is being pulled away from the wire, A is the area of the loop, and a is the distance between the wire and the loop.
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Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field what is the force applied to the ball ?
From Newton's second law of motion, the magnitude of the force applied is 1022.4 N
What is Force ?Force can simply be defined as a pull or push. It is the product of mass and acceleration and it is a vector quantity.
Given that Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field.
The force F applied to the ball = mass × acceleration. That is,
F = ma
Where
m = 0.527 kgv = 19.4 m/st = 0.01 sF = ?a = ?Acceleration a = v/t
a = 19.4/0.01
a = 1940 m/s²
Force F = ma
F = 0.527 × 1940
F = 1022.4 N
Therefore, the force applied to the ball is 1022.4 N
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construction, principal and working of electric motor
What is the acceleration of the object?
which type of energy does a ball falling through the air have?
Answer:
the answer would be kinetic energy
7. A 1000-kg car comes to a stop without skidding. The car's brakes do 50,000 J of work
to stop the car. Which of the following was the car's velocity when the brakes were
initially applied?
Answer:
10 m/s
Explanation:
If you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1233 kg, how strong is the force of gravity between you and the car ?
Answer:
5.03×10¯⁷ N
Explanation:
From the question given above, the following data were obtained:
Mass of the person (M₁) = 55 Kg
Mass of the car (M₂) = 1234 Kg
Distance apart (r) = 3 m
Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²
Force (F) =?
The force between the person and his car can be obtained as follow:
F = GM₁M₂ / r²
F = 6.673×10¯¹¹ × 55 × 1234 / 3²
F = 6.673×10¯¹¹ × 67870/ 9
F = 5.03×10¯⁷ N
Thus, the force between the person and his car is 5.03×10¯⁷ N
a 5.00 N salmon named sammy, swims 20 M upstream against a current that provides a resistance of 1.50 N. This portion of the stream rises at an angle 10 degrees with respect to the horizontal.
a) how much work is done by the sammy against the current?
b) what is the gain in PE by sammy?
c) what is the total work that must be done by sammy?
d) if sammy takes 40 S to swim the distance, what power does sammy have to exert to do so?
a) 67.96 J work is done by the Sammy against the current.
b) 3.46 m is the gain in PE by Sammy.
c) 85.06 J is the total work that must be done by Sammy.
d) If Sammy takes 40 S to swim the distance, 85 power does sammy have to exert to do so.
a) The work done by Sammy against the current is given by the formula:
Work = force × distance × cos(theta)
where force is the net force acting on the salmon, distance is the distance travelled by the salmon, theta is the angle between the force and the direction of motion.
Here, the net force acting on Sammy is:
force = 5.00 N - 1.50 N = 3.50 N
The distance travelled by Sammy is 20 m. The angle between the force and the direction of motion is 10 degrees.
Therefore, the work done by Sammy against the current is:
Work = (3.50 N) × (20 m) × cos(10 degrees)
= 67.96 J (Joules)
b) The gain in potential energy by Sammy is given by the formula:
PE = mgh
where m is the mass of the salmon, g is the acceleration due to gravity, and h is the height gained by Sammy.
Here, the height gained by Sammy is the vertical distance travelled while swimming upstream against the current. This distance is given by:
h = distance × sin(theta)
= 20 m × sin(10 degrees)
= 3.46 m
Therefore, the gain in potential energy by Sammy is:
PE = (5.00 N ÷ 9.81 m/s^2) × (3.46 m) × 9.81 m/s^2
= 17.10 J (Joules)
c) The total work that must be done by Sammy is the sum of the work done against the current and the gain in potential energy:
Total work = Work against current + PE gain
= 67.96 J + 17.10 J
= 85.06 J (Joules)
d) The power that Sammy must exert to swim upstream against the current is given by the formula:
Power = work ÷ time
where work is the total work done by Sammy, and time is the time taken to swim the distance.
Here, the total work done by Sammy is 85.
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Say you are looking through a telescope at the planet Saturn with an eyepiece with a 20 mm focal length. You would like to replace it with a new eyepiece so that Saturn's image appears twice as large (while the objective stays the same). Which new eyepiece should you choose? 80 mm 10 mm 40 mm None of these, since the eyepiece focal length doesn't affect magnification. 5 mm
The new eyepiece you should choose is 10 mm.
The magnification of a telescope is determined by the ratio of the focal length of the objective lens (or mirror) to the focal length of the eyepiece. In this case, you want Saturn's image to appear twice as large, which means you need to double the magnification. Since the objective lens remains the same, the change in magnification can only be achieved by changing the focal length of the eyepiece.
Using the formula for magnification:
Magnification = (Focal length of objective) / (Focal length of eyepiece)
To double the magnification, the new focal length of the eyepiece should be half of the original focal length, which is 10 mm.
Therefore, by choosing the 10 mm eyepiece, you will achieve the desired magnification to make Saturn's image appear twice as large while keeping the objective unchanged.
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which statement is true regarding the resolution of a grating? a. resolution increases with wavelength b. resolution decreases with number of grooves per mm c. resolution increases with number of grooves per mm d. resolution is not determined by the monochromator e. resolution increases with slit width
The correct statement regarding the resolution of a grating is that the resolution increases with the number of grooves per mm, the correct option is (c).
The resolution of a grating is defined as the ability to separate two closely spaced spectral lines or wavelengths. It is determined by the number of grooves per unit length on the grating surface, as well as the wavelength of the incident light and the angle of incidence.
A higher number of grooves per mm means that the grating will disperse the incoming light into more angles, resulting in higher resolution. Therefore, the number of grooves per mm is the primary factor that determines the resolution of a grating, the correct option is (c).
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The complete question is:
Which statement is true regarding the resolution of a grating?
a. resolution increases with wavelength
b. resolution decreases with number of grooves per mm
c. resolution increases with number of grooves per mm
d. resolution is not determined by the monochromator
e. resolution increases with slit width
A narrow beam of light is travelling through a transparent liquid. It meets the surface as shown, at
an angle of incidence of 40°. The refractive index of the liquid is 1.5.
air
liquid
40
What is the angle of refraction as the light enters the air?
A 25
B 27
C 60°
D 75
Answer:
the correct answer is B) 27.
Explanation:
To find the angle of refraction, you can use the formula:
n1 * sin(angle of incidence) = n2 * sin(angle of refraction)
where n1 and n2 are the refractive indices of the two media (in this case, air and the liquid), and the angles are measured from the normal to the surface.
Plugging in the values from the problem, we have:
1 * sin(40) = 1.5 * sin(angle of refraction)
Solving for the angle of refraction, we get:
angle of refraction = sin^-1(1/1.5 * sin(40))
Using a calculator or a table of trigonometric functions, we can find that the value of sin^-1(1/1.5 * sin(40)) is approximately 27.3 degrees.
Therefore, the correct answer is B) 27.
In an isolated system, a red ball of mass m moves to the right with speed v. It strikes a green ball, of
mass 2m, which was initially stationary. After the collision, the red ball remains stationary. How does
the green ball move?
A. To the left, with speed v/2
B. To the right with speed 2v
C. To the right, with speed v/2
D. To the left with speed 2v
The green ball moves to the right with speed v/2. Here option C is the correct answer.
The collision between the two balls can be analyzed using the principles of conservation of momentum and conservation of kinetic energy.
Conservation of momentum states that the total momentum of a system remains constant if no external forces act on the system. In this case, the initial momentum of the system is:
p_initial = mv + 0 = mv
where the first term represents the momentum of the red ball and the second term represents the momentum of the green ball, which is initially zero since it is at rest.
After the collision, the red ball is stationary, so its momentum is zero. The momentum of the green ball can be calculated as follows:
\(p_{\text{final}} = 0 + 2mv_{\text{final}} = 2mv_{\text{final}}\)
where v_final is the speed of the green ball after the collision.
Conservation of momentum requires that the initial and final momenta are equal, so:
\(p_{\text{initial}} = p_{\text{final}} \quad\)
\(\quad mv = 2mv_{\text{final}}\)
Solving for v_final, we get:
v_final = v/2
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A train starting from rest moves with a uniform acceleration of 0.2 ms-2 for 5 minutes. Calculate the final velocity and the distance travelled in this time.
Answer:
Final velocity = 60 m/s
Distance travelled = 9000 m
Explanation:
Applying,
For Final velocity,
v = u+at ............... Equation 1
Where v = final velocity, u = initial velocity, a = acceleration, t = time.
From the question,
Given: u = 0 m/s(at rest), a = 0.2 m/s², t = 5 minutes = (5×60) = 300 s
Substitute these values into equation 1
v = 0+0.2(300)
v = 60 m/s.
Also for distance,
Applying,
s = ut+1/2at²................ Equation 2
Where s = distance travelled.
subtitute thes values above into equation 2
s = (0×300)+(0.2×300²)/2
s = 9000 m
as the block slides down the ramp, what happens to its kinetic energy k , potential energy u , and total mechanical energy e ? as the block slides down the ramp, what happens to its kinetic energy , potential energy , and total mechanical energy ? k decreases; u increases; e stays the same k decreases; u increases; e increases k increases; u increases; e increases k increases; u decreases; e stays the same
As the block slides down the ramp, its kinetic energy (k) increases, its potential energy (u) decreases, and the total mechanical energy (e) stays the same.
what is kinetic energy?Kinetic energy is the energy an object possesses due to its motion. It is defined as the amount of energy an object has due to its velocity and can be calculated using the following formula:
\(KE = 0.5 * m * v^2\)
where KE is the kinetic energy, m is the mass of the object, and v is its velocity. The units of kinetic energy are joules (J) in the SI system.
Kinetic energy is an important concept in understanding the motion and behavior of objects, particularly in collisions and in studying the laws of thermodynamics. The concept of kinetic energy is also used in engineering, such as in the design of machines and in the calculation of the energy required to perform various tasks.
In this situation, the block is undergoing a gravitational potential energy to kinetic energy transformation. As the block moves downward, its potential energy due to its height above the ground decreases, and this decrease in potential energy is transformed into an increase in kinetic energy as the block gains speed. However, since the block is not subjected to any friction, air resistance, or other non-conservative forces, the total mechanical energy of the system (the sum of its kinetic energy and potential energy) stays constant.
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Formulate a weekly schedule that shows evidence of three different activities beneficial for your muscular system.
(please hurry but also don't work too hard that it's a huuuuuuuge paragraph)
Answer:
Monday - Jog.
Tuesday - Eat at a Salad Bar.
Wednesday - Bike ride.
Thursday - gym.
Friday - Kale Smoothie.
Explanation:
A spring-loaded ballistic cart measuring 0.5 kg is in contact with a second 0.8 kg cart. The carts are
initially at rest on a level surface. The spring is released and the lighter cart is observed to move at +0.4
m/s afterward. What is the velocity of the other cart?
A spring-loaded ballistic cart is in contact with a second cart. The velocity of the other cart is 0.25 m/s.
What is the conservation of linear momentum?When there is no external force acting on the system, the initial momentum is equal to the final momentum.
Momentum is equal to the product of mass and its velocity.
According to the conservation of linear momentum,
m₁v₁ +m₂v₂ = m₁u₁ +m₂u₂
u and v represents the initial and final velocity. 1 and 2 represents the first and second cart.
Given is m₁ = 0.5 kg, m₂ =0.8kg, u₁ =u₂ =0 m/s and v₁ = 0.4 m/s.
Substituting the values in the conservation of momentum equation, we get the velocity of second cart is
0.5 x 0.4 + 0.8 x v₂ = 0.5 x 0 + 0.8 x 0
v₂ = +0.25 m/s (in the direction of first cart)
Thus, the velocity of the other cart is 0.25 m/s.
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A baseball with a mass of 0. 15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8. 0 x 103 seconds. The
ball moves off with a speed of 50 meters/second in the opposite direction. What is the value of the force?
The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.
When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:
F = ΔP / ΔT
where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.
Now, let's apply the given values to the above equation.
Final momentum (p2) = mass × final velocity (v2)
p2 = 0.15 kg × (-50 m/s)
p2 = -7.5 kg.m/s
Initial momentum (p1) = mass × initial velocity (v1)
p1 = 0.15 kg × (40 m/s)
p1 = 6 kg.m/s
Change in momentum (ΔP) = p2 - p1
ΔP = -7.5 kg.m/s - 6 kg.m/s
ΔP = -13.5 kg.m/s
Time of collision (ΔT) = 8.0 × 10³ s
Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:
F = ΔP / ΔT
F = -13.5 kg.m/s ÷ 8.0 × 10³ s
F = -1.7 × 10⁻³ N
Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.
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Does adding electrons change the mass
Which type of wave moves both energy and the particles in the same direction as the medium?
Answer:
Longitudinal waves
Explanation:
With sound waves, the energy travels along in the same direction as the particles vibrate. This type of wave is known as a longitudinal wave , so named because the energy travels along the direction of vibration of the particles.
Why does a small piece of steel rod sinks while a large steel oil tanker floats?
Plss help thanks! pls include EXPLANATION and EXAMPLES that I can proof to people that has no knowledge
Answer:
Too what i know its because of the air
Explanation:
The steel rod is more dense and doesnt have air whil'st the oil tanker is less dense with lots of air