Answers
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is \(\vec B = 2, -3\)
Explanation:
Looking at the graph in the diagram we see each unit is equal to 1 both in the x axis and in the y- axis
Now the value of B along the x axis is
\(B_x = 2\)
and along the y axis the value is
\(B_y = -3\)
Hence the vector B is
\(\vec B =(B_x , B_y)= ( 2, -3)\)
Related Questions
Classify the following as a type of kinetic or potential energy. Check the
appropriate box.
Help please..
Answers
Answer:
Kinetic and potential
potential (didnt say its moving)
Kinetic and potential
kinetic
kinetic
kinetic
potential
kinetic and potential
kinetic (might have potential)
kinetic
Use your knowledge of conjunction, disjunction, negation and truth tables to determine whether the argument is valid or invalid or unknown.
~( R · S )
~ R · P / ~ S
Answers
Using truth tables, we determined the validity of the argument ~(R · S) ~ R · P / ~ S. By examining the truth values of the expression ~ S · P, we found that it can be both true and false in different scenarios. Therefore, the argument is invalid.
To determine the validity of the argument ~(R · S) ~ R · P / ~ S, we can use truth tables. First, let's assign truth values to the variables:R: T (true) or F (false)
S: T (true) or F (false)
P: T (true) or F (false)Next, we can construct a truth table for the given argument:
R | S | P | ~(R · S) | ~ R | ~ S | ~(R · S) ~ R | ~ S · P |
--------------------------------------------------------
T | T | T | F | F | F | F | F |
T | T | F | F | F | F | F | F |
T | F | T | T | F | T | T | T |
T | F | F | T | F | T | T | F |
F | T | T | T | T | F | F | T |
F | T | F | T | T | F | F | F |
F | F | T | T | T | T | T | T |
F | F | F | T | T | T | T | F |By examining the truth values of the last column, ~ S · P, we can see that there are cases where it evaluates to both true and false. Therefore, the argument is invalid because it does not hold true in all possible scenarios.
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A student is on a balcony 15.6 m above the street. She throws a ball vertically downward at 10.7 m/s.
What is the velocity of the ball as it strikes the ground?
Answers
Answer:
20.65 m/s
Explanation:
You are gonna wanna use a calculator for this one
so we will write all the known variables:
h = 15.6 m
initial velocity (u) = 10.7 m/s
acceleration (a) = 10 m/s/s (gravity)
From the third equation of motion:
v² - u² = 2ah
v² - (10.7)² = 2(10)(15.5)
v² - (10.7)² = 312
v² = 312 + 114.49
v² = 426.49
v = 20.65 m/s
A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ
Answers
The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)
How do I determine the kinetic energy?We'll begin by obtaining the velocity of the flywheel. This is shown below:
Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?v = at
v = 0.6 × 60
v = 36 m/s
Finally, we shall determine the kinetic energy of the flywheel. Details below:
Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 50 × 36²
KE = 25 × 1296
KE = 32400 J
Divide by 1000 to express in KJ
KE = 32400 / 1000
KE = 32.4 KJ
Thus, the kinetic energy is 32.4 KJ (Option D)
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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
Answers
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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Pls help and explain how to get the answer
Answers
(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.
(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².
What is the gravitational force exerted on each object?The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;
Fg = Gm₁m₂ / R²
where;
G is universal gravitation constantm₁ is the mass of the rockm₂ is the mass of pebbleThe acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.
Force on the rock;
F = mg
where;
g is acceleration due to gravityF = 6.6 kg x 9.8 m/s²
F = 64.68 N
The force on the pebble;
F = mg
F = 5.6 x 10⁻⁴ x 9.8
F = 5.488 x 10⁻³ N
Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².
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RHETORICAL ANALYSIS: How does Robinson use language in effective and engaging ways to develop his argument to his younger self-and, in the process, to young readers in the present? In your response, consider such techniques as metaphor, repetition, and sentence structure.
Answers
In "The Argonauts," Robinson effectively utilizes language techniques such as metaphor, repetition, and sentence structure to develop his argument to his younger self and engage young readers in the present. Through these techniques, Robinson creates a powerful and relatable narrative that resonates with his audience.
Robinson employs metaphors to convey complex ideas in a compelling and accessible manner. For instance, he compares his struggle with identity and gender to the mythical journey of the Argonauts, making it relatable and captivating for young readers. This metaphorical language enables readers to grasp the profound emotions and challenges he faced during his own personal journey.
Repetition is another technique Robinson employs to reinforce key ideas and create a rhythmic and memorable reading experience. By repeating certain phrases or concepts, he emphasizes their significance and invites readers to reflect on them. This repetition serves to engage young readers by encouraging them to contemplate their own experiences and perspectives.
Furthermore, Robinson carefully structures his sentences to create a sense of rhythm and flow, enhancing the overall readability and impact of his argument. Short, concise sentences create moments of clarity and emphasis, while longer, more descriptive sentences evoke a contemplative and introspective tone. This varied sentence structure adds depth and nuance to his narrative, captivating young readers and keeping them engaged throughout.
In conclusion, through the effective use of metaphor, repetition, and sentence structure, Robinson engages and captivates young readers, inviting them to reflect on their own identities and experiences. His language choices not only develop his argument to his younger self but also establish a connection with present-day young readers, making his work both impactful and relatable.
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(6) Two long, straight, parallel wires carry currents that are directed perpendicular to the page as shown in Figure. Find the value and direction of hy in terms of I to have net magnetic field equal zero at the origin.
Answers
The point at which the net magnetic field will be zero, the magnetic field due to first wire must be equal and opposite in direction to the magnetic field due to the second wire.
Magnetic field between two the parallel wiresThe magnetic field between two parallel wires is determined as follows;
B = μI/2πd
where;
B is magnetic field strengthI is the current in one wired is the distance between the parallel wires.From the formula above we can conclude that, the point at which the net magnetic field will be zero, the magnetic field due to first wire must be equal and opposite in direction to the magnetic field due to the second wire.
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what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answers
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
The time taken by a mass projected vertically
upwards to reach the maximum height (with air
resistance not neglected) is 10 sec. The time of
descent of the mass from the same height will be
Answers
Answer:
10s
Explanation:
The time to get to the maximum would be the same as the time to get down to the maximum unless somehow gravity’s changes during the duration it goes up to and from maximum height.
Relationship between SI unit for area and other units of area
Answers
The SI unit for area is the square meter (m²). It is a fundamental unit of measurement in the International System of Units (SI). Here are some common units of area and their relationships to the square meter:
Square kilometer (km²): 1 km² is equal to 1,000,000 square meters (1 km² = 1,000,000 m²). It is used for large-scale measurements, such as land area or geographical regions.
Hectare (ha): 1 hectare is equal to 10,000 square meters (1 ha = 10,000 m²).
Square centimeter (cm²): 1 cm² is equal to 0.0001 square meters (1 cm² = 0.0001 m²).
Square millimeter (mm²): 1 mm² is equal to 0.000001 square meters (1 mm² = 0.000001 m²).
Acre: 1 acre is equal to approximately 4046.86 square meters.
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A 45.7 kg woman starts from rest at the bottom of a flight of stairs that has
a total height of 2.54 meters. She reaches the top of the stairs
in 5.00 seconds. How much power does she generate if she is moving at
2.63 m/s at the top of the stairs? Use g = 9.8 m/s2, and only include 3
numbers in your answer.
Answers
Answer:
The power generated by the woman is 259 W
Explanation:
Given;
mass of the woman, m = 45.7 kg
initial velocity of the woman, u = 0
total height ascended by the woman, h = 2.54 m
time of the woman's motion, t = 5.0 s
final velocity of the woman, v = 2.63 m/s
acceleration due to gravity, g = 9.8 m/s²
The potential energy of the woman due to the height she ascended;
P.E = mgh
P.E = 45.7 x 9.8 x 2.54
P.E = 1137.564 J
The kinetic energy of the woman due to her final velocity;
K.E = ¹/₂mv²
K.E = ¹/₂ x 45.7 x (2.63)²
K.E = 158.051 J
The total mechanical energy of the woman at the top of the stairs;
M.E = P.E + K.E
M.E = 1137.564 J + 158.051 J
M.E = 1295.615 J
The power generated by the woman;
Power = Energy/time
Power = 1295.615 J / 5 s
Power = 259.123 W
Power = 259 W
You are pulling a wagon with a mass10kg and it’s moving forward at a constant rate. Your friend gets into the wagon and it’s slows down. What can you do to get the wagon moving faster?
Answers
Explanation:
Without changing the constant speed, your friend can empty the contents of the wagon, or decrease the overall rate, or the terrain the wagon is traveling on, all of these would increase the wagon's speed. Also, you could try applying a heavier pulling force, like using a horse instead of yourself, or you and a horse to get going faster.
Hope this helps!
A car driving down a road runs of gas and will eventually stop because of:
A. Friction
B. Thrust
C. It will remain in motion forever
OD. Gravity
Answers
Two concurrent forces have maximum resultant of 45N anda minimum resultant of 5N.What is magnitude of each of these forces
Answers
34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answers
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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what happens to the resistance of two resistors when connected in series circuit
Answers
Answer:
increases as more components are added.
A object spins through an angular displacement of 10 radians and has an angular acceleration of 2.3 rad/sec-squared. Assuming it began spinning from rest, over what time interval did the acceleration occur?
Answers
Answer:
The acceleration of the object occurred at 2.95 s
Explanation:
Given;
initial angular velocity of the object, ω = 0
angular acceleration, α = 2.3 rad/s²
angular displacement of the object, θ = 10 radians
The time of the motion is given by the following kinematic equation;
θ = ω + ¹/₂αt²
θ = 0 + ¹/₂αt²
θ = ¹/₂αt²
\(t^2 = \frac{2 \theta}{\alpha}\\\\t = \sqrt{\frac{2 \theta}{\alpha}}\\\\t = \sqrt{\frac{2 *10}{2.3}}\\\\t = 2.95 \ s\)
Therefore, the acceleration of the object occurred at 2.95 s
Physical Science
The sun is composed mainly of oxygen.
O True
O False
Answers
Answer:
false
Explanation:
Because the sun has ultraviolet rays
Answer:
False.
Explanation: The sun is mainly composed of hydrogen, it's 92% composed of hydrogen.
what is the mass of an object that is experiencing a net force of 200N and an acceleration of 500m/s2
Answers
Answer:
F=200N
a=500m/s2
Mass=?
Explanation:
F=ma
200=m*500
200/500=m
Mass=0.4kg
Wha is the definition of health?
Answers
Two adjacent students stand on stationary skateboards, face each other, and
push apart. The skateboarder on the left weighs 55 kg, the one on the right is
65 kg. If the lighter skateboarder moves at 4.2 m/s, determine the speed and
direction of the heavier skateboarder.
Answers
with an armature resistance of 0.03 2 and a field resistance of
41.67 2. The motor has compensating windings, so armature
reaction can be ignored. Mechanical and core losses may be
assumed to be negligible for the purposes of this problem. The
motor is assumed to be driving a load with a line current of 126 A
and an initial speed of 1103 r/min. To simplify the problem,
assume that the amount of armature current drawn by the motor
remains constant.
A. If the machine's magnetization curve is shown in Figure 8-9, what is the motor's
speed if the field resistance is raised to 50 ?
B. Calculate and plot the speed of this motor as a function of the field resistance RF
assuming a constant-current load.
R₁ = 0.03 2
EA
IA
IF
IL
RF + Radj
LF
+
250 V
Answers
A. The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min
A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:
EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.
Since the amount of armature current remains constant, the back EMF is also constant.
Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:
IF = (250 V - EA)/(RF + R₁)
At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.
If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.
Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:
kϕN/IF1 = kϕN/IF2
N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min
Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:
N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min
where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.
Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.
A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.
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Pls answer. Will rate 5 start and give a Thanks or Brainliest.
What are the characteristics of the Sun? (Select all that apply.)
Group of answer choices
The Sun is the center of our solar system and radiates energy.
The Sun is a medium-sized star compared to other stars in the universe.
The Sun has planets and dwarf planets that orbit it.
The Sun is composed of helium and hydrogen.
The Sun is near the end of its life.
Answers
The Sun is composed of helium and hydrogen. Option C.
The photosphere chromosphere and corona are all part of the Sun's atmosphere. Although the corona is sometimes called the solar atmosphere it is actually the sun's upper atmosphere. The sun's atmosphere includes features such as sunspots, coronal holes, and solar flares the sun is a star.
It's a huge spinning ball of hot gas. The sun is like a star in the night sky. Because we are so close it appears much larger and brighter than other stars. The sun is the center of the solar system and accounts for most of the mass of the solar system. Compared to the billions of other stars in the universe, the sun stands out. But for the Earth and the other planets orbiting around it, the Sun is a powerful focal point.
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An object with a kinetic energy of 250j has a mass of 32 kg what is the velocity of the object?
Answers
Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².
Deinition of Kinetic energyKinetic energy is the energy possessed by a body or system due to its movement.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
Where:
Ec is kinetic energy, which is measured in Joules (J).m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Velocity of the objectIn this case, you know:
Ec= 250 Jm= 32 kgv= ?Replacing in the definition of kinetic energy:
250 J = 1/2× 32 kg×v²
Solving:
250 J÷ (1/2× 32 kg) = v²
15.625 J÷kg = v²
√15.625 J÷kg = v
3.95 m/s² = v
Finally, the velocity of the object is 3.95 m/s².
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A) Determine the x and y-components of the ball's velocity at t = 0.0s, 2.0, 3.0 secs.
B) What is the value of g on Planet Exidor?
C) What was the ball's launch angle?
Answers
The kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.
a) the position are
time (s) x (m) y(m)
0 0 0
2.0 3.6 1.2
3.0 5.4 0.9
b) The aceleration is g = 0.6 m / s²
c) The launch angle θ = 33.7º
given parameters
the initial velocity of the body vₓ = 1.8m / s and v_y = 1.2 m / s the movement times t = 1.0s, 2.0s and 3.0 sto find
a) position
b) acceleration
c) launch angle
Projectile launch is an application of kinematics to the movement of the body in two dimensions where there is no acceleration on the x axis and the y axis has the planet's gravity acceleration
b) To calculate the acceleration of the plant acting on the y-axis, we use that the vertical velocity of the body at the highest point is zero.
v_y = v_{oy} - g t
where v and v({oy} are the velocities of the body, g the acceleration of the planet's gravity and t the time
0 = v_{oy} - gt
g = v_{oy} / t
from the graph we observe that the highest point occurs for t = 2.0 s
g = 1.2 / 2.0
g = 0.6 m / s²
a) The position is requested for several times
X axis
in this axis there is no acceleration so we can use the uniform motion relationships
vₓ = x / t
x = vₓ t
where x is the position, vx is the velocity and t is the time
we calculate for the time
t = 0.0 s
x₀ = 0
t = 2.0 s
x₂ = 1.8 2
x₂ = 3.6 m
t = 3.0 s
x₃ = 1.8 3
x₃ = 5.4 m
Y axis
In this axis there is the acceleration of the planet, let us use for the position the relation
y = v_{oy} t - ½ g t²
t = 0.0 s
y₀ = 0
y₀ = 0 m
t = 2.0 s
y₂ = 1.2 2 - ½ 0.6 2²
y₂ = 1.2 m
t = 3.0 s
y₃ = 1.2 3 - ½ 0.6 3²
y₃ = 0.9 m
c) the launch angle use the trigonometry relation
tan θ = \(\frac{v_y}{v_x}\)
θ = tan⁻¹ \(\frac{v_y}{v_x}\)
θ = tan⁻¹ \(\frac{1.2}{1.8}\)
θ = 33.7º
measured counterclockwise from the positive side of the x-axis
With the kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.
a) the position are
time (s) x (m) y(m)
0 0 0
2.0 3.6 1.2
3.0 5.4 0.9
b) The aceleration is g = 0.6 m / s²
c) The launch angle θ = 33.7ºto)
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A projectile is fired from the top of a 120 m tall building with an initial velocity of Vi = 72.0 m/s and an initial angle theta i =25.0° above the horizontal. Answer the following questions.[Use g= 9.80 m/s^2]Question 12What is the distance traveled by the projectile in the horizontal direction?Round your answer to 3 significant figures.Question 13What is the speed of the projectile the moment it touches the ground?Round your answer to 3 significant figures.
Answers
Given data
(12)
*The given height of the building is h = 120 m
*The given initial velocity is v_i = 72.0 m/s
*The angle above the horizontal is
\(\theta=25^0\)*The value of acceleration due to gravity is g = 9.80 m/^2
The initial horizontal velocity of the projectile is calculated as
\(\begin{gathered} v_x_{}=v_i\cos \theta \\ =(72.0)\cos 25^0 \\ =65.25\text{ m/s} \end{gathered}\)The initial vertical component velocity of the projectile is calculated as
\(\begin{gathered} v_y_{}_{}=v_i\sin \theta \\ =(72.0)\sin 25^0 \\ =30.42\text{ m/s} \end{gathered}\)The time taken by the projectile is calculated by the kinematic equation of motion as
\(H=v_yt+\frac{1}{2}gt^2\)Treating the vertically upward direction to be a negative and the vertically downward direction to be positive.
Substitute the known values in the above expression as
\(\begin{gathered} 120=-(30.42)t+\frac{1}{2}(9.8)t^2 \\ t=8.95\text{ s} \end{gathered}\)The expression for the distance traveled by the projectile is given as
\(D=v_x\times t\)Substitute the known values in the above expression as
\(\begin{gathered} D=(65.25)\times(8.94) \\ =583.33\text{ m} \\ =584\text{ m} \end{gathered}\)Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
Answers
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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What is the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) such that they would contain the same number of wavelengths of 646nm light
Answers
Answer: The ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.
Explanation:
Given: Refractive index of glycerine = 1.473
Refractive index of crystalline quartz = 1.544
Formula used is as follows.
\(2nt = m \lambda\)
For crystalline quartz: \(2n_{q}t_{q} = m \lambda_{q}\)
For glycerine: \(2n_{g}t_{g} = n \lambda_{g}\)
Here, m = n and \(\lambda_{q} = \lambda_{g}\)
So, the ratio of both these values can be written as follows.
\(\frac{2n_{q}t_{q}}{2n_{g}t_{g}} = \frac{m \lambda_{q}}{n \lambda_{g}} = 1\)
So, \(n_{q}t_{q} = n_{g}t_{g}\)
\(\frac{t_{q}}{t_{g}} = \frac{n_{g}}{n_{q}} = \frac{1.473}{1.544}\)
\(\frac{t_{q}}{t_{g}} = 0.954\)
Thus, we can conclude that the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.
Which of these does NOT use a reed?
O Flute
Clarinet
Oboe
Bassoon
Answers
The answer is: Flute. Hope this helps :)