Use three-point Gauss quadrature to evaluate the following integrals. You can use Table 4.1 in the textbook for values of weight and sampling coordinate. a. . So 2x2 +1° dx b. St, cos? x dx Table 4.1 Position of Gauss points and corresponding weights. ngp Location, Weights, W 1 0.0 2.0 2 +1/V3 = +0.5773502692 1.0 3 +0.7745966692 0.0 0.555 555 5556 0.888 888 8889 4 +0.8611363116 +0.3399810436 0.347 854 8451 0.652 145 1549 5 +0.9061798459 +0.5384693101 0.0 0.236 926 8851 0.478 628 6705 0.568 888 8889 6 +0.9324695142 +0.6612093865 +0.2386191861 0.171 324 4924 0.360 761 5730 0.467 913 9346

Answer:

We well know that water is a conductor of charges. So, when it is between capacitor plates, the charges flow from positive plate to negative plate hence discharge occurs

Explanation:

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The offset in the beq instruction will be 16.

In the given code snippet, the beq instruction is used for branching. It compares the values in registers $s0 and $0 (which holds a value of 0) and branches to the "increment" label if they are equal. The immediate field in the beq instruction represents the offset or the relative address of the target instruction.

Based on the provided code snippet, the target instruction for the beq is the "increment" label, which is located after the beq instruction. The offset is calculated by subtracting the address of the beq instruction from the address of the target instruction.

Given that the address of the beq instruction is 0x10000000 and the address of the target instruction ("increment" label) is 0x10000016, the offset can be calculated as:

Offset = Address of target instruction - Address of beq instruction

Offset = 0x10000016 - 0x10000000

Offset = 0x16

Therefore, the offset in the beq instruction (the 16-bit immediate field) is 0x16, which corresponds to 22 in decimal.

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They were made of stone blocks that were held together with lime mortar. Some were plastered over and painted.

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Answer:

Investigation or empircial research

Explanation:

gimme brainliest pls

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

A 176.19 kW heater would be required to heat the water in the pool from 70 degrees F to 72 degrees F in 1 hour, assuming the heater is 100% efficient.

To calculate the size of the heater required to heat the water in the pool, we need to use the following formula:

Q = m x c x ΔT

where

Q is the amount of heat required,

m is the mass of the water being heated,

c is the specific heat of water, and

ΔT is the change in temperature.

First, we need to calculate the mass of the water in the pool.

One gallon of water weighs 3.79 kg hence 20 000 gallons will be 75 800 kg

Q = m x c x ΔT

Q = 75,800 kg x 4.184 J/g°C x (72°F - 70°F)

Q = 75,800 kg x 4.184 J/g°C x 2°F

Q = 634,294.4 joules

Now, we need to calculate the power of the heater required to deliver this amount of heat in 1 hour (3600 seconds):

Power = Q / t

Power = 634,294.4 joules / 3600 seconds

Power = 176.19 kW

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Answer:

so hard it is

Explanation:

I don't know about this

please mark as brainleast

byýyy

Genetically engineered organisms represent the highest percentage of corn grown in the United States are Soybeans, cotton, and canola. Well they are also significantly genetically engineered crops.

Genetically engineered (GE) organisms, or genetically modified organisms (GMOs), are organisms whose genetic material has been altered through biotechnology. In the United States, the most prevalent GE crop is corn, with approximately 92% of corn being genetically engineered as of 2020.

This is followed by soybeans, cotton, and canola, with 94%, 94%, and 90% GE rates, respectively. GE crops are popular due to their increased resistance to pests, herbicides, and environmental conditions, as well as their ability to produce higher yields. These factors contribute to the widespread adoption of genetically engineered crops in the United States.

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Answer:

The discharge temperature is 259.82 K

Explanation:

In this question, we are concerned with calculating the discharge temperature

Please check attachment for complete solution

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Answer:

sry but it's kinda hard

Answer:

The type of succession is:

Primary succession

Explanation:

This is a type of succession that occurs after a volcanic eruption or earthquake; it involves the breakdown of rocks by lichens to create new, nutrient rich soils.

Primary succession is one of the two types of succession we have. It begins on rock formations, such as volcanoes or mountains, or in a place with no organisms or soil.

Answer:

they were updated rather than being created

Answer:

Invention is about creating something new, while innovation introduces the concept of “use” of an idea or method.

The pipe that presents water at a particular pressure to all branching pipes in a pipeline system is called the main or feeder pipe. This pipe is responsible for delivering the water from the source to all the branching pipes, which then distribute the water to the desired locations. The main or feeder pipe is typically larger in diameter than the branching pipes to accommodate the larger volume of water flow.

The pipe that presents water at a particular pressure to all branching pipes is called the "header" pipe. In a pipeline system, the header pipe is typically a large diameter pipe that connects to the main water source and supplies water to the entire system. The header pipe is designed to maintain a certain pressure throughout the system, which ensures that all of the branching pipes receive a consistent flow of water.The header pipe is usually located at the highest point in the system to take advantage of gravity to maintain the pressure. Additionally, the header pipe is designed to minimize friction losses and ensure that the flow of water through the system is as efficient as possible.The header pipe may also be equipped with various valves, meters, and other components to monitor and control the flow of water through the system. These components help to maintain the pressure and flow of water at optimal levels and ensure that the pipeline system operates efficiently and reliably. The pipe that presents water at a particular pressure to all branching pipes in a pipeline system is called the "main distribution pipe" or "primary feed pipe." This large diameter pipe ensures a consistent flow of water from the main source to the branching pipes, maintaining adequate pressure throughout the system.

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The flow of water from a main source enters a pipeline system through a large diameter pipe.

The pipe that presents water at a particular pressure to all branching pipes is called the "main distribution pipe" or "main supply line".

This main distribution pipe maintains consistent water pressure and ensures adequate water flow to all connected branching pipes within the system.

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Wood is a composite type of CMC. What is Wood. Wood is a natural composite that is formed from cellulose fibers embedded in a matrix of lignin.

It is a natural material that has been used for thousands of years to make structures, furniture, and other useful items. What are Composites. Composite materials are made up of two or more materials with distinct and they can be made by combining any type of material. The goal of combining different materials is to create a new material with better overall properties than any of the individual components. Wood is made up of cellulose fibers embedded in a matrix of lignin. Wood, which is a natural composite, is an example of a composite made up of organic materials. CMC (Ceramic matrix composites) and MMC (Metal matrix composites) are the other two composite types.
Wood is a natural composite material and does not fall under the categories of (a) CMC (Ceramic Matrix Composite), (b) MMC (Metal Matrix Composite), or (c) PMC (Polymer Matrix Composite).

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The theoretical density of diamond given that the C-C distance and bond angle are 0.154 nm and 109.5° respectively is; 3.54 g/cm³

The first thing we will do is to get the unit cell edge length from the given C - C distance.

From the structure of diamond;

Φ = ¹/₂ * bond angle

Φ = ¹/₂ * 109.5°

Φ = 54.75°

Thus;

θ = 90° - 54.75°

θ = 35.25°

Let the height from a point to the base of the cube of the structure be x. Thus;

x = a/4 = y sin θ

where a is unit cell edge length and y is C -C length. Thus;

a = 4y sin θ

a = 4 * (0.154 * 10⁻⁹) * sin 35.25°

a = 3.56 * 10⁻⁸ cm

The unit cell volume is;

V_c = a³

Thus; V_c = (3.56 * 10⁻⁸)³

V_c = 4.51 * 10⁻²³ cm³

Now, there are 8 equivalent atoms per unit cell and as such density is calculated from;

ρ = (n * A_c)/(V_c * N_a)

A_c is atomic weight of diamond = 12.01 g/mol

N_a is avogadro's number = 6.022 * 10²² atoms/g

Thus;

ρ = (8 * 12.01)/(4.51 * 10⁻²³ * 6.022 * 10²²)

ρ = 3.54 g/cm³

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The plant will need to perform 9,100,000 processing and assembly procedures altogether.

Shape operations, property-enhancing operations, and surface processing operations are the three distinct categories of processing operations. By using mechanical force, heat, or other forms and combinations of energy, shaping operations change the work material's geometry.

There are 250 components in each product.

Parts purchased as a percentage equal 65%.

250 - (65% x 250) = 87.5 is the number of components that will be produced in the new facility.

Eight processing steps are needed to manufacture each component.

The new factory's processing procedures per component totaled 8 x 87.5, or 700.

13 x 1000 x (700 + 1) = 9,100,000 is the total number of processing and assembly procedures needed for the 13 different models.

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The maximum Speed of the Sprinter from the velocity time graph of his motion is; 11.98 m/s

We are given;

Initial Speed; u = 2.5 s

Total distance; d = 100 m

Total time; T = 9.6 s

The total distance is;

d = ¹/₂(9.6 + (9.6 - 2.5) * v

where v is maximum speed.

Thus;

¹/₂(9.6 + (9.6 - 2.5) * v = 100

16.7v = 200

v = 200/16.7

v = 11.98 m/s

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Answer:

Ra = 3,000 lb

Ma = 26,125 lb-ft

Explanation:

Solution:-

- We are given a cantilever horizontal beam with a span of 20 ft subjected to distributed loads.

- We will use the following conventions and define our coordinate system:

- Denote positive direction ( + ) directed "vertically upward" and "anticlockwise".

- Denote negative direction ( - ) directed "vertically downward" and "clockwise".  

- We will denote a reaction force ( Ra ) and reaction moment ( Ma ) exerted by the wall support at point A on the beam in positive directions, respectively. These reactions are consequence of the distributed load acting on the horizontal beam.

-  First step is to analyze the distributed load. We will make 4 sections of the distributed loads and write down the shapes of each distributions as follows:

     Section                    Load ( Lb/ft)                     Distribution

           1                               750                             Rectangular

           2                              750                         Right angle triangle

           3                              450                         Right angle triangle

           4                              450                             Rectangular

- We will proceed with load-transformation. In load transformation we convert the distributed load into a " point load "  and determine the "location of transformed load " using distribution pattern of each section.

- We will now determine the point load and location of each point load for the respective section from point ( A ) as follows:

       Section 1:

                        P1 = Load_1 * distribution span_1

        From above table, Load_1 = 750 lb/ft.

        Distribution is rectangular, spanning L1 = 3ft

                         P1 = ( 750 lb/ft ) * ( 3ft )

                         P1 = 4500 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of rectangle x1 = 3ft from point A.  

          Section 2:

                        P2 = Load_2 * distribution span_2*0.5

        From above table, Load_2 = 750 lb/ft.

        Distribution is right angle triangle, spanning ( L2 )

                         P2 = 0.5* ( 750 lb/ft ) * ( L2 )

                         P2 = 375*L2 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of right angle triangle is x2 = 6ft + L2/3 from point A.              

          Section 3:

                         P3 = Load_3 * distribution span_2*0.5

        From above table, Load_3 = 450 lb/ft.

        Distribution is right angle triangle, spanning ( L3 )

                         P3 = 0.5* ( 450 lb/ft ) * ( L3 )

                         P3 = 375*L3 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of right angle triangle is x3 = 6ft + L2 + 2*L3/3 from point A.              

- Before we proceed further, we need to determine the spanning lengths of right angle triangles for distributed loads for sections 2 and 3. From the given figure we can form two equations as follows:

                       L2 + L3 = 9 ft    .... Eq 1

- The second equation can be determined by the concept of similar triangles to relate L2 and L3 as follows:

                       L2 = L3* ( 750 / 450 )

                       L2 = 5*L3 / 3   ... Eq 2

- Solve the two equations simultaneously for L2 and L3, we get:

                       L2 = 4.625 ft, L3 = 4.375 ft

- The corresponding point loads and locations are as such:

                      P2 = 1734.375 lb , x2 = 7.5416667 ft

                      P3 = 984.375 lb , x3 = 13.541667 ft

Note: The division of 750 lb/ft and 450 ft/lb loads in section 2 and section 3 can be mistaken to be equal and setting L2 = L3 = 4.5 ft. Remember to take care of such situations.

        Section 4:

                        P4 = Load_4 * distribution span_4

        From above table, Load_4 = 450 lb/ft.

        Distribution is rectangular, spanning L4 = 5ft

                         P4 = ( 450 lb/ft ) * ( 5ft )

                         P4 = 2,250 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of rectangle x4 = 6ft + 9ft + L4/2 = 17.5 ft from point A.  

- Second step: Apply the static equilibrium conditions on the horizontal beam.

       Force Balance: Sum of forces in vertical direction = 0

                   ∑ \(F_y,net = 0 = R_A + P3 + P4 - P1 - P2\)

                    \(R_A = 4,500 + 1,734.375 - 984.375 -2,250\\\\R_A = 3,000 Lb\)

      Moment Balance: Sum of moments about A = 0

      ∑ \(M_n_e_t = 0 = M_A + P3*x3 + P4*x4 - P1*x1 - P2*x2\)

                      \(M_A = -(984.375)*(13.541667) - (2250)*(17.5) + (4500)*(3) + (1734.375)*\\(7.54166667)\\\\M_A = -26,125 Lb.ft\)

Answer: The reaction force at point A is directed vertically upward ( Ra = 3,000 Lb ) and the reactive moment is directed clockwise at point A ( Ma = 26,125 Lb-ft ).

Answer: a thicker line

Explanation:

Answer:

1. All engines  exhibit wear over time ⇒ Synthetic Improves engine protection by resisting oil breakdown.

Synthetic oil does not breakdown so easily which means that it protects the engine more and protects it from wearing.

2. Engines are cold at start-up and not while running ⇒ Synthetic provides maximum protection in extreme hot and cold temperature conditions.

By providing protection for the engine during cold and hot conditions, the engine will not be too cold when the car is started up.

3.  If oil is thicker, engines lose power and efficiency ⇒ Synthetic has greater resistance to oil thickening to maintain engine efficiency.

Part of the characteristics of synthetic oil is that it does not get as thick as regular oil which means that the adverse effects of thick oil are spared on the engine.

Answer:

the 4th one

Explanation:

no id you can't drive

The drag at the point where the aircraft just lands on the ground is approximately 66987 N.

Drag = \(\frac{1}{2}*density*velocity^{2} *coefficient of drag*wing area\)

where:

density = atmospheric density at the landing altitude

velocity = landing speed of the aircraft in meters/second

Convert the landing speed from miles per hour to meters per second:

196.4 mi/hr = (196.4*1609.34 m) / (3600 s) = 87.8 m/s

Calculate the atmospheric density at the landing altitude using the following formula:

density = \(\frac{pressure}{specific gas constant * temperature}\)

where:

specific gas constant for dry air = 287.058 J/(kg*K)

temperature = standard temperature at sea level - temperature lapse rate * altitude

Assuming a temperature lapse rate of 0.0065 K/m and a standard temperature at sea level of 288.15 K, we can calculate the temperature at the landing altitude as follows:

temperature = 288.15 K - 0.0065 K/m * 668 m = 283.7 K

Substituting these values into the density formula, we get:

density = 98.8 kPa / (287.058 J/(kg*K) * 283.7 K) = 1.036 kg/m³

Finally, we can calculate the drag using the drag formula:

Drag = (1/2) * 1.036 kg/m³ * (87.8 m/s)² * 0.034 * 429.1 m² = 66987 N

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Condensation polymerization is the type of polymer chemistry process that leads to the production of a byproduct. This is because of the elimination of a small molecule as a byproduct during the polymerization reaction.

Among the different types of polymer chemistry processes, condensation polymerization is the one that leads to the production of a byproduct. This is because, in this process, the polymerization reaction involves the elimination of a small molecule, such as water or alcohol, as a byproduct. The monomers used in this process typically have functional groups, such as carboxylic acid and alcohol, that can react with each other to form a polymer chain. As the reaction progresses, the byproduct is formed and released.

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The correct option is: d) Condensation polymerization. The type of polymer chemistry process that leads to the production of a byproduct is condensation polymerization.

Condensation polymerization involves the reaction between two different types of monomers, leading to the release of a small molecule, such as water or HCl, as a byproduct. In contrast, radical polymerization, termination polymerization, and monomer radicalization do not typically produce byproducts during their processes.

This process typically involves the reaction between two functional groups on the monomers, leading to the formation of a polymer chain and a small byproduct molecule. In contrast, radical, termination, and monomer radicalization polymerizations do not produce byproducts during the polymerization process.

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You must take into account techniques for huge data set restoration for labs employing high-end RAID servers (like Digital Intelligence F.R.E.D.C. or F.R.E.D.M.).

The data storage virtualization method known as RAID, or redundant array of independent discs, combines many physical disc drive components into one or more logical units for data redundancy, performance improvement, or both.It is a technique for protecting data in the event of a drive failure by storing the identical data in several locations on numerous hard discs or solid-state drives. A RAID system has two or more parallel-operating discs. These can be hard drives, although SSD technology is becoming more popular (Solid State Drives).

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Answer:a

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Solution :

The correct size of the arc of a welding process depends upon the application and the electrode. As a rule, the arc length should not be more than a diameter of the core of the electrode.

As for the electrode of diameter size of 5/32" or 4 mm, the arc length should be more than its core diameter. Also for 5/32 " diameter electrode, the welding time for the one electrode must be one minute as well as the length of the weld be the same as the length of the electrode consumed.