Use the diagram to find the measure of angle KHL.

1. The probability P(Z > 1) is approximately 1 - 0.8413 = 0.1587.

2. The probability P(Z < -2) is approximately 0.0228.

Let's calculate the probabilities using the standard normal distribution table.

1. Probability that a tune-up will take more than two hours (120 minutes):
To find P(Z > 1), we look up the value of z = 1 in the standard normal distribution table.

The table provides the area to the left of the z-score. Subtracting this value from 1 gives us the probability to the right of z = 1.

From the standard normal distribution table, we find that the area to the left of z = 1 is approximately 0.8413. Therefore, the probability P(Z > 1) is approximately 1 - 0.8413 = 0.1587.

2. Probability that a tune-up will take less than 66 minutes:
To find P(Z < -2), we look up the value of z = -2 in the standard normal distribution table. The table provides the area to the left of the z-score.

From the standard normal distribution table, we find that the area to the left of z = -2 is approximately 0.0228. Therefore, the probability P(Z < -2) is approximately 0.0228.

These calculations give us the probabilities for the respective scenarios.

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Answer:

0.80

Step-by-step explanation:

I did the math 5 times

The probability that a set of all bulbs work is 0.88.

The total probability rule (also known as the Law of Total Probability) divides probability calculations into discrete steps.

Now, as per the question;

The total number of bulbs be 120 and each bulb is working as independent event.

The reliability of each bulb is 99.9% = 0.999

Let 'p' the probability the bulb will work.

The probability that all will work = p¹²⁰

The probability that all will work = (0.999)¹²⁰ = 0.886

Thus, the probability that all bulb will work is 88.6%.

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there are 17,576 possible permutations if no letters are repeated.

To arrive at this answer, we can use the formula for permutations of n objects taken r at a time, which is n!/(n-r)!. In this case, we have 26 choices for each of the three letters, and 10 choices for each of the four digits, so the total number of permutations is 26 x 25 x 24 x 10 x 9 x 8 x 7 = 17,576,000. However, since we are not allowing any letters to be repeated, we need to divide by the number of ways the three letters can be arranged, which is 3! (since order matters when choosing the letters). Therefore, the final answer is 17,576,000/6 = 17,576.

if a computer password can have 3 different letters followed by 4 digits, and no letters are repeated, there are 17,576 possible permutations. This can be calculated using the formula for permutations and adjusting for the fact that order matters when choosing the letters.

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Answer:

0.375mL/polyethylene

Step-by-step explanation:

Total number of plastic bags = 24 plastic bags

amount of polyethylene created = 9mL

This means that;

24 plastic bags = 9mL of polyethylene

1 plastic bags = x

Cross multiply

24 * x = 9 * 1

24x = 9

x = 9/24

x = 0.375mL/polyethylene

Hence the rate of polyethylene used per plastic bag is 0.375mL/polyethylene

Answer:

180 minutes in 3 hours 225 miles in 3 hours

Step-by-step explanation:

Step-by-step explanation:

Nun much take "w"outside from dis equation

w²-5w= w(w-5)

The probability that a company ships by truck or rail or both is 0.89 or 89%.

We can solve this problem by using the formula for the probability of the union of two events:

P(A or B) = P(A) + P(B) - P(A and B)

where A and B are two events.

In this case, we want to find the probability that a company ships by truck or rail or both, which is equivalent to the probability of the union of the two events "shipping by truck" and "shipping by rail". Let T denote the event "shipping by truck" and R denote the event "shipping by rail".

From the problem statement, we know:

P(T) = 0.82

P(R) = 0.47

P(T and R) = 0.40

Using these probabilities, we can calculate:

P(T or R) = P(T) + P(R) - P(T and R)

= 0.82 + 0.47 - 0.40

= 0.89

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Some examples of equivalent fractions to -3/2 are:

-3/2 = -6/4

-3/2 = -15/10

To find an equivalent fraction to a fraction a/b, we need to multiply/divide both numerator and denominator by the same real number (except for zero).

Then for example if we have -3/2, we can multiply both numerator and denominator by 2, and we will get an equivalent fraction:

(-3*2)/(2*2) = -6/4

Or if we multiply both by 5:

(-3*5)/2*5 = -15/10

These are some examples of equivalent fractions.

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Minimum percentage: 96% of the data set lies between 50 and 100.

The value of k:

Mean – (k) (sd) = lower limit

75 – 5K - 50

75 – 50 = 5k

25 = 5k

K = 5

For the percentage, we are using:

1 – 1/k^2.

1 - 1/ 25 = 24/25 = 96%

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The probability of having exactly 3 universal blood donors show up is 0.1537. On the other hand, the probability of having at most 5 universal blood donors show up is 0.9868.

The given scenario is an example of the binomial probability distribution, as there are only two possible outcomes: universal blood donors or non-universal blood donors.

The probability of the universal blood donor is 0.06.

Let X be a random variable representing the number of universal blood donors among 50 donors.

Then X follows the binomial distribution with n = 50 and p = 0.06.

a. The probability of having exactly 3 universal blood donors show up is given as:

P(X = 3) = (⁵⁰C₃) (0.06)3 (1-0.06)47

P(X = 3) = 0.1537

Therefore, the probability of having exactly 3 universal blood donors show up is 0.1537.

b. The probability of having at most 5 universal blood donors show up is:

P(X ≤ 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X ≤ 5) = (⁵⁰C₀) (0.06)0 (1-0.06)50 + (⁵⁰C₁) (0.06)1 (1-0.06)49 + (⁵⁰C₂) (0.06)2 (1-0.06)48 + (⁵⁰C₃) (0.06)3 (1-0.06)47 + (⁵⁰C₄) (0.06)4 (1-0.06)46 + (⁵⁰C₅) (0.06)5 (1-0.06)45

P(X ≤ 5) = 0.9868

Therefore, the probability of having at most 5 universal blood donors show up is 0.9868.

In conclusion, the probability of having exactly 3 universal blood donors show up is 0.1537. On the other hand, the probability of having at most 5 universal blood donors show up is 0.9868.

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\(~~~~~1-x < 5\\\\\implies -x < 5-1\\\\\implies -x < 4\\\\\implies x > -4\\\\\text{Interval notation:}~ (-4, \infty)\)

According to the information, to estimate the total cost for a 50-kilometer taxi ride by extending the line to a distance of 50 kilometers and reading off the corresponding y-value, which is approximately $105.00.

Distance (km) Total Cost ($)

0 5.00

1 7.00

2 9.00

3 11.00

4 13.00

5 15.00

b. The graph of the total cost C as a function of the distance d up to 10 kilometers is a linear function with a slope of $2.00/km and a y-intercept of $5.00.

The start value of the total cost is $5.00, which is the initial fee charged by the taxi service. The rate of change is $2.00/km, which is the cost per kilometer travelled.

The equation that models the total cost C of using the taxi service for a distance of d kilometers is:

Using the equation from part d, we can calculate the total cost of a 50-kilometer taxi ride:

Alternatively, we could use the graph to estimate the total cost for a 50-kilometer taxi ride by extending the line to a distance of 50 kilometers and reading off the corresponding y-value, which is approximately $105.00.

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Plot it halfway between -2 and -3

For the parallelogram NELR, we get the value of x as 7°.

We are given a parallelogram NELR.

We know that , the adjacent angles of a parallelogram are supplementary.

So, we get that:

∠ N + ∠ E = 180°

Substituting the values, we get that:

7 x + 33 + 11 x + 21 = 180

18 x + 54 = 180

18 x = 180 - 54

18 x = 126

x = 126 / 18

x = 7°

Therefore, for the parallelogram NELR, we get the value of x as 7°.

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Slope of lines 3x - 5y = 2 and 3x + 5y = -2 are m₁ = 3/5 and m₂ = -3/5 respectively.

The slope of a line is defined as the change in y-coordinate with respect to the change in x-coordinate of the line. The net change in the y coordinate is Δy and the net change in the x coordinate is Δx. Therefore, the change in y-coordinate for a change in x-coordinate can be written as

Line slope is a measure of the steepness or direction of a line in the coordinate plane.  

m = Δy/Δx

where,m is the slope

Given,

equations of the line

3x - 5y = 2

Moving 3x to RHS
-5y = -3x + 2

y = (3/5)x - 2/5

comparing with slope intercept equation of the line y = mx + c

slope m₁ = 3/5

Now, equation

3x + 5y = -2

moving 3x to RHS

5y = -3x - 2

y = (-3/5)x - 2

comparing with slope intercept equation of the line y = mx + c

slope m₂ = -3/5

Hence, m₁ = 3/5 and m₂ = -3/5 are slope of lines 3x - 5y = 2 and 3x + 5y = -2 respectively.

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Answer:

36 monkeys where sleeping

The slack for binding constraints s always zero.

Each of the constraints has a stated slack or surplus value. When there are less or equal constraints, it is said that there is "slack," and when there are more constraints, it is said that there is "surplus." The matching slack or surplus value will be equal to zero if a constraint is binding.

Total slack, if positive, is the length of time a work can be put off without pushing back the project's completion deadline.

1. A binding constraint's slack value is always zero (0).

2, A "what-if" scenario is the product of a simulation experiment. This basically refers to the examination of information that could characterize or represent a prospective decision option.

3. The maximin decision criteria are used to make cautious decisions. It enables a decision-maker to weigh the worst-case possibilities for each alternative and then choose the best one from those. The "best" results in the example are 1, 5, -4, -3, 2, and 4 for each alternative. With a payout of 5, D-2 is the greatest choice in this situation.

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The slack for binding constraints s always zero.

What is meant by slack value?
Each of the constraints has a stated slack or surplus value. When there are less or equal constraints, it is said that there is "slack," and when there are more constraints, it is said that there is "surplus." The matching slack or surplus value will be equal to zero if a constraint is binding.

What is meant by positive slack value?
Total slack, if positive, is the length of time a work can be put off without pushing back the project's completion deadline.

1. A binding constraint's slack value is always zero (0).
2, A "what-if" scenario is the product of a simulation experiment. This basically refers to the examination of information that could characterize or represent a prospective decision option.
3. The maximin decision criteria are used to make cautious decisions. It enables a decision-maker to weigh the worst-case possibilities for each alternative and then choose the best one from those. The "best" results in the example are 1, 5, -4, -3, 2, and 4 for each alternative. With a payout of 5, D-2 is the greatest choice in this situation.

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Answer:

3.7 hrs

Step-by-step explanation:

Speed = 15km/ 1 h

Distance = 56 km

Time  = x

15/1 = 56/x

x= 56 / 15 ~  3.7 hrs

I hope im right!!

Answer:2

Step-by-step explanation:x/6+29=41

41-29=12

12/6=2

Answer:

4/14 is equivalent

Step-by-step explanation:

If you multiply 7 and 2 you will get 14

So since you multiply by 2 for the denominator you will have to do the same to the numerator

9514 1404 393

Answer:

  B.  45π cm^3

Step-by-step explanation:

The volume is given by ...

  V = 1/3πr^2h

where r is the radius (half the diameter) and h is the height. With the given numbers, we have ...

  V = (1/3)π(3 cm)^2(15 cm)

  V = 45π cm^3 . . . volume of each cup

Answer:

Step-by-step explanation:

The distance between 2 cities is 175 miles

What is scale on graph?

A scale is a set of numbers that help to measure or quantify objects. A scale on the graph shows the way the numbers or pictures are used in data.

Given data ,

The distance between Louisville and Nashville = 1 3/4 inches

Scale of the map = 1 in : 100 miles

Now , 1 inch = 100 miles on the map

And , 1 3/4 = 7 / 4 inches

So , 7 / 4 inches = ( 7 / 4 ) x 100 miles

                          = 1.75 x 100 miles

                          = 175 miles

Hence , the distance between 2 cities is 175 miles

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The given problem involves the angular kinematics of a train's wheels during its acceleration. Angular kinematics is a branch of physics that deals with the motion of objects in circular motion, and it includes concepts such as angular displacement, velocity, and acceleration. In this problem, we are given a specific scenario where a train is being tested for public use, and its wheels have a radius of 0.30 m and an angular acceleration of 0.20 rad/s2. We are asked to find the angular displacement of the wheels in radians per second after they have made 200 revolutions. To do this, we need to first find the total angular displacement of the wheels, which is equal to the product of the number of revolutions and the angle covered by each revolution. By applying the appropriate formula and converting the angle to radians, we can solve for the angular displacement in radians. The concept of angular kinematics is important in many areas of physics and engineering, including the design and analysis of rotating machinery and vehicles.

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The angular displacement after testing is approximately 12.73 radians per second.

To answer your question, we need to first convert the number of revolutions to radians and then use the given angular acceleration to find the angular velocity.

1. Convert revolutions to radians:
200 revolutions * (2π radians/revolution) = 400π radians

2. Use the angular displacement (θ) and angular acceleration (α) to find the angular velocity (ω):
θ = 0.5 * α * t^2
400π = 0.5 * 0.20 * t^2
Solve for t:
t^2 = (400π) / 0.1
t ≈ 63.66 seconds

3. Calculate angular velocity (ω) using angular acceleration (α) and time (t):
ω = α * t
ω = 0.20 rad/s² * 63.66 s
ω ≈ 12.73 rad/s

The angular displacement after testing is approximately 12.73 radians per second.

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The sampling method in which every nth member of the population is chosen to be a part of the process is known as systematic sampling. The value of n is calculated by dividing the total population by the sample size. It is a statistical method of selecting elements from a population.

Systematic sampling is one of the probability sampling techniques in which a sample is selected from a larger population. It is a form of non-random sampling that allows researchers to establish an ordered, systematic way of selecting subjects from a population.Systematic sampling is often used when there is a large population and a need for simplicity in selecting a sample. This method is advantageous in terms of its ease of implementation and efficient sampling.

A disadvantage of this method is the possibility of a skewed sample if the periodicity of the population is not taken into account.A systematic sample can be obtained by arranging the population elements in a particular order, for instance, alphabetical or chronological order, and then selecting every kth element, where k = population size / sample size. This method of sampling has been proven to be more efficient than other sampling methods when there is a need to cover a large population.

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Let P and Q be two rational numbers

P = a/b

Q = c/d

where a,b,c,d are integers. Also, b and d cannot be zero.

When we multiply P and Q, we get

P*Q = (a/b)*(c/d)

P*Q = (a*c)/(b*d)

Showing that we multiply the numerators together, and the denominators are multiplied together.

The expression a*c is the result of multiplying integers a and c

The expression b*d is the result of multiplying integers b and d

Therefore, multiplying rational numbers involves multiplying integers (we just do two sets of multiplications).

After multiplying P and Q, it's often a good idea to reduce the fraction as much as possible.

Answer:

Multiplication of rational numbers is an extension of the multiplication of integers. It is the multiplication of two fractions with the same denominator. The product of two rational numbers is a rational number.

Step-by-step explanation: