use particle theory to explain why solids and liquids cannot be compressed (squashed into a smaller volume).

Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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The focal length of the concave mirror is approximately option B. 8.20 cm,

To solve this problem, we can use the mirror equation, which relates the object distance (d_o), image distance (d_i), and the focal length (f) of a concave mirror. The equation is:

1/f = 1/d_o + 1/d_i

Given the object distance (d_o) is 12.2 cm and the image distance (d_i) is 25.0 cm, we can plug in these values to find the focal length (f):

1/f = 1/12.2 + 1/25.0

To solve for f, first find the common denominator and combine the fractions:

1/f = (25 + 12.2) / (12.2 * 25) = 37.2 / 305

Now, take the reciprocal of both sides to isolate f:

f = 305 / 37.2

After calculating, we get:

f ≈ 8.20 cm

Thus, the focal length of the concave mirror is approximately 8.20 cm, Therefore the correct option to option b.

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The liquid's surface tension in N/m is determined as 0.25 N/m.

Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Mathematically, the formula for surface tension of a liquid is given as;

γ = F/L

γ = F/2x

where;

From Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.

F = kx

where;

The final equation for the surface tension of the liquid film becomes;

γ = F/2x

γ = kx/2x

γ = k/2

γ = (0.5 N/m) / 2

γ = 0.25 N/m

Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.

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The fuel efficiency of the vehicle is 5.71%.

The fuel efficiency of the vehicle is determined from the ratio of volume of fuel used to the total distance traveled.

Distance traveled by the vehicle = 350 km

Volume of fuel used = 20 L

e = (20 / 350) x 100

e = 5.71%

Thus, the fuel efficiency of the vehicle is 5.71%.

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Answer: 17.5

Explanation:

1. i did the same problem and got it right
2. you don't do "kmpl" but rather you have to do "km/l" which represents the kilometers over the liters

Answer:

n/A = 1*10^10 /cm^2

Explanation:

a) Each open ion can be considered as a resistor in the circuit. Then, you have that the equivalent resistance is:

\(\frac{1}{R_{eq}}=\frac{1}{R}+\frac{1}{R}+\frac{1}{R}+...=\frac{n}{R}\\\\R_{eq}=\frac{R}{n}\)     (1)

(you assume the resistance are in parallel)

R: resistance of an axon's membrane =  1×10^ 11Ω.

Req: equivalent resistance = ?

n: number density of open ion channels

Next, you take into the Ohm's law:

\(I=\frac{V}{R_{eq}}\)    (2)

I: current

V: voltage acroos the membrane = 50mV

you replace the equation (1) into the equation (2):

\(I=\frac{Vn}{R}\)     (3)

But yo know that the current is also

I = JA       (4)

J: current density = 5mA/cm^2

A: cross sectional area of the axon's membrane

You replace equation (4) into the equation (3), an d you solve for n/A

\(JA=\frac{Vn}{R}\\\\\frac{n}{A}=\frac{JR}{V}\)

Then, you replace the values of the parameters:

\(\frac{n}{A}=\frac{JR}{V}=\frac{(5mA/cm^2)(1*10^{11}\Omega)}{50mV}\\\\\frac{n}{A}=1*10^{10}\frac{ions}{cm^2}\)

hence, the density of ion channels is 1*10^10 /cm^2

Using ohm's law and the characteristics of series and parallel circuits, we find that the correct answer is B: Voltage on the voltmeter 1.5 V

given parameters

    * The element X has a resistance Rₓ = R

    * Element Y with resistance R_y = R / 2

     * The voltmeter with internal resistance R_v = R

    * Battery voltage V = 6V

    * the circuit is in the diagram

To find

     The Voltmeter reading.

For this exercise we use ohm's law which establishes a linear relationship between voltage and current

      V = i R

Let's solve the circuit in parts:

1 part.  We reduce the part in parallel, finding its equivalent resistance

            R_ {eq1}

The equivalent resistance between Y element and the voltmeter that is in parallel, therefore their equivalent resistance is

         \(\frac{1}{R_{eq1} } = \frac{1}{R_y} + \frac{1}{R_v}\)

         \(\frac{1}{R_{eq1} }= \frac{1}{\frac{R}{2} } + \frac{1}{R} = \frac{3}{R}\)

         \(R_{eq1} = \frac{R}{3}\)

Now element X and this equivalent resistance are in series ( see attached), so the equivalent resistance of the entire circuit is

        R_{eq} = Rₓ + R_{eq1}

we substitute

       R_{eq} = \(R + \frac{R}{3} = \frac{4}{3} \ R\)

2 part. We look for the current of the circuit, usin the ohm's Law

        V = i R_{eq}

        i = \(\frac{V}{R_{eq} }\)

        i = \(\frac{6}{\frac{4R}{3} } = \frac{18}{4R}\)

        i = 4.5 / R

In a series circuit the current is constant and the total voltage is the sum voltage of each element, so the voltage in the parallel R_{eq1}

        V₂ = I R_{eq1}

        V₂ = \(\frac{4.5}{R} \ \frac{R}{3}\)4.5 / R R / 3

        V₂ = 1.5 V

3 part. The voltmeter and the Y element  are in parallel, so the voltage in the two elects is the same,  consequently the voltage of the voltmeter (V_v)

          V_v = V₂ = 1.5 V

Using ohm's law and the properties of series and parellel circuits we find the voltage across the voltmeter

           V_v = 1.5 V

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Answer:

u dont have a question

Explanation:

?? bc i would gladly help u

Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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The distance traveled by the sperm whale traveling at an initial speed of 1.10m/s to 2.44m/s is 23.7m.

The distance traveled by the sperm whale can be estimated using one of the equations of motion as follows:

v² = u² + 2as

Where;

According to this question, a sperm whale can accelerate at about 0.100 m/s² when swimming on the surface of the ocean. The distance traveled by the whale can be calculated as follows:

2.44² = 1.10² + 2(0.10)(s)

5.95 = 1.21 + 0.2s

4.74 = 0.2s

s = 23.7m

Therefore, 23.7m is the distance of the sperm whale.

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Answer: NO, there are many examples of non-conservative forces.

Explanation: Conservatives forces are special forces whose work is zero in a closed path.

The period of the pendulum, given that the pendulum has an angular velocity about the pivot point of 0.66 radians/sec is 9.52 seconds

First, we shall list out the given parameters from the question. This is shown below:

The period and angular velocity are related according to the following formula:

ω = 2π/ T

Inputting the given parameters, we can obtain the period of the pendulum as follow:

0.66 = (2 × 3.14) / T

0.66 = 6.28 / T

Cross multiply

0.66 × T = 6.28

Divide both sides by 0.66

T = 6.28 / 0.66

T = 9.52 seconds

Thus, we can conclude that the period of the pendulum is 9.52 seconds

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The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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Explanation:

The vertical displacement of the wave is measured from the

equilibrium to the crest and is called the frequency.

crest to the trough and is called the amplitude.

trough to the trough and is called the wavelength.

equilibrium to the crest and is called the amplitude.

HØPÊ ĮŤ ÌŠ helpful

Answer:

The evaporation of water is an example of a change in Pysical Change .

Answer:

Vf = 39.2 m/s

h = 78.4 m

Explanation:

Using first equation of motion for vertical motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

g = 9.8 m/s²

t = time taken = 4 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(4 s)

Vf = 39.2 m/s

Now, we use second equation of motion

h = Vi t + (1/2)gt²

where,

h = height covered = ?

Therefore,

h = (0 m/s)(4 s) + (1/2)(9.8 m/s²)(4 s)²

h = 78.4 m

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer: Friction Forces

Explanation: (I took the same test and got the answer)

_________________________________________

I hope this helps!

Answer:

False.

Explanation:

provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.

Protons have positive charge

Electrons have negative charge

• 22 protons (+22) + 18 electrons (-18 )

22 - 18 = 4 (positive)

• 12 -10 = 2

• 17 - 10 = 7

• 2 - 1 = 1

From most positive to most negative overall charges.

7 - 4 - 2 - 1

A passenger on the Ferris wheel normally weighs 585 N,  the angular velocity  this will occur at is mathematically given as

w=0.867 1/s.

Generally, the equation for Linear velocity is mathematically given as

\(V=\sqrt{Rg}\)

Therefore

\(V=\sqrt{13 *9.8}\)

V= 11.28m/s

In conclusion,  angular velocity  is

v/r=w

Hence

w=11.28m/s/ 13 m

w=0.867 1/s.

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These locations, where the potential difference between Vab and Vcb is 0 and 258v, respectively, have a uniform electric field with a magnitude of 3230 n/c.

The potential difference, also referred to as voltage, is equal to the amount of current multiplied by the resistance. One Joule of energy is consumed by a charge when it moves between two points in a circuit at a potential difference of one Volt. respectively, have a uniform electric field with a magnitude of 3230 n/c. An electric field is a type of physical field that exists around electrically charged particles and which influences the behaviour of all other charged particles nearby (or E-field).

whereas Vcb = E/d = 3230*0.08 = 258v, Vba = E/d = 0

Vba = E/d = 0

Vcb = E/d = 3230*0.08 = 258v

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In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.

The period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,

Period of oscillation = 1.80s.

From here, finding the frequency is simple as, Frequency = 1/Period. Hence,

Frequency = 1/1.80

= 0.555 Hz (3 sf).

The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.

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Answer:

d I think? not sure I don't know much abt the ocean

The magnitude of the electric field between the plates, from least to greatest is shown by option C.

We know that when two plates that are conducting are arranged in such a way that a gap is left in between them, the we have a capacitor. The electric potential of the capacitor would have a lot to do with the distance of the separation of the plates.

As such, the closer the plates are together, the greater the electric potential of the plates and the more the plates are apart, the lesser the electric potential of the plates.

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer:

Chemical energy to sound energy to heat energy

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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