We already know from Newton's First Law that an object's inertia prevents it from changing velocity unless it experiences a net force, so once the forces are balanced, the skydiver continues at a constant velocity until they open their parachute.
How do Newton's laws apply to skydiving?According to Newton's Second Law, an object's acceleration equals the force of gravity divided by the object's mass. The skydiver first falls or accelerates down as a result of inertia and gravity. The sky diver falls at terminal velocity after opening the parachute, and the velocity becomes constant.The falling skydiver's net force and acceleration are both upward. A downward falling object would slow down if an upward net force was applied to it. As a result, the skydiver slows down. As the speed decreases, so does the amount of air resistance, until the skydiver reaches terminal velocity once more.To learn more about : Newton's Law
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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Find equivalent resistance??
Answer:
Req = 50 Ω
Explanation:
The equivalent resistance is basically the sum of all the resistances in a circuit.
The sum of these resistances will depend whether these resistance are in series or parallel.
If the resistances are on series, the expression to use is:
R = R₁ + R₂ + R₃ + .......Rₙ (1)
If the resistances are on parallel then the expression to use is:
1/R = 1/R₁ + 1/R₂ + ........1/Rₙ (2)
Now, according to the picture, we have R₁ and R₄ in series, so here we have to use (1):
R₁₄ = 10 + 30 = 40 Ω
R₂ and R₃ are in parallel so we use (2):
1/R₂₃ = 1/20 + 1/20 = 2/20 = 1/10
R₂₃ = 10 Ω
Finally, R₁₄ and R₂₃ are in series (Because of the sum of the resistance in each side, they are now forming one resistance in each side), therefore, we use (1) again to get the equivalent resistance of the whole circuit:
Req = 10 + 40
Req = 50 ΩHope this helps
Four long wires are each carrying 6.0 A. The wires are located
at the 4 corners of a square with side length 9.0 cm. All of
these wires are carrying current out of the page. The
magnetic field (in T) at one corner of the square is:
Answer:
\(B_T=2.0*10^-5[-\hat{i}+\hat{j}]T\)
Explanation:
To find the magnitude of the magnetic field, you use the following formula for the calculation of the magnetic field generated by a current in a wire:
\(B=\frac{\mu_oI}{2\pi r}\)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
I: current = 6.0 A
r: distance to the wire in which magnetic field is measured
In this case, you have four wires at corners of a square of length 9.0cm = 0.09m
You calculate the magnetic field in one corner. Then, you have to sum the contribution of all magnetic field generated by the other three wires, in the other corners. Furthermore, you have to take into account the direction of such magnetic fields. The direction of the magnetic field is given by the right-hand side rule.
If you assume that the magnetic field is measured in the up-right corner of the square, the wire to the left generates a magnetic field (in the corner in which you measure B) with direction upward (+ j), the wire down (down-right) generates a magnetic field with direction to the left (- i) and the third wire generates a magnetic field with a direction that is 45° over the horizontal in the left direction (you can notice that in the image attached below). The total magnetic field will be:
\(B_T=B_1+B_2+B_3\\\\B_{T}=\frac{\mu_o I_1}{2\pi r_1}\hat{j}-\frac{\mu_o I_2}{2\pi r_2}\hat{i}+\frac{\mu_o I_3}{2\pi r_3}[-cos45\hat{i}+sin45\hat{j}]\)
I1 = I2 = I3 = 6.0A
r1 = 0.09m
r2 = 0.09m
\(r_3=\sqrt{(0.09)^2+(0.09)^2}m=0.127m\)
Then you have:
\(B_T=\frac{\mu_o I}{2\pi}[(-\frac{1}{r_2}-\frac{cos45}{r_3})\hat{i}+(\frac{1}{r_1}+\frac{sin45}{r_3})\hat{j}}]\\\\B_T=\frac{(4\pi*10^{-7}T/A)(6.0A)}{2\pi}[(-\frac{1}{0.09m}-\frac{cos45}{0.127m})\hat{i}+(\frac{1}{0.09m}+\frac{sin45}{0.127m})]\\\\B_T=\frac{(4\pi*10^{-7}T/A)(6.0A)}{2\pi}[-16.67\hat{i}+16.67\hat{j}]\\\\B_T=2.0*10^-5[-\hat{i}+\hat{j}]T\)
NaCl solid is an example of a/an
A. Insulator
B. Conductor
OC. Nonmetal
D. Metalloid
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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I need help! what are some sentences that help me explain Explain the process that creates wind?
Answer:
Explanation:
Wind is air in motion. It is produced by the uneven heating of the earth's surface by the sun. Since the earth's surface is made of various land and water formations, it absorbs the sun's radiation unevenly. Two factors are necessary to specify wind: speed and direction.
The coefficient of Kinetic friction between rubber tire of a wet concrete road is 0.5 (a) Find the minimum time in which a car whose initial velocity is 50 km/h can cover to a stop on such a road (b) What distance will the car cover in this time?
(a) The minimum time in which a car can cover to a stop on such a road is 2.83 s.
(b) The distance travelled by the car is 19.7 m.
What is the acceleration of the car?
The acceleration of the car is calculated by applying Newton's second law of motion.
F = ma = -μmg
ma = -μmg
a = -μg
where;
μ is the coefficient of kinetic frictiong is acceleration due to gravitya is the acceleration of the cara = -0.5 x 9.8 m/s²
a = -4.9 m/s²
The minimum time in which a car whose initial velocity is 50 km/h can cover to a stop on such a road is calculated as;
v = u + at
where;
v is the final velocity when the car stops = 0u is the initial velocity = 50 km/h = 13.89 m/sa is acceleration of the car, = -4.9 m/s²t is time of motion0 = u - at
at = u
t = u / a
t = ( 13.89 ) / ( 4.9)
t = 2.83 seconds
The distance travelled by the car is calculated as;
v² = u² + 2as
0 = 13.89² - 2 (4.9)(s)
9.8s = 192.9
s = 192.9 / 9.8
s = 19.7 m
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Q5:
What is Tom's displacement if he went
from a position of 10 meters to a position of 4
meters?
resonance occurs in an AC series circuit when which of the following condition is met ?
A,Resistant equal compactive resistance
B, comparative resistance equal zero
C, resistance equals inductive resistance
Answer:
capacitive reactance equals inductive reactance
The helium-filled balloons below are carrying negative electric charges, as shown. Attach two of the balloons to the hooks below to show what would happen if a red balloon and a blue balloon were brought near each other. Plzz help
Answer:
these are in the hooks the balloons repel each other if the hooks are isolated.
Explanation:
In electrostatics, charges of the same sign repel and of a different sign attract each other.
With this explanation we analyze the situation presented, they indicate that the balloons have a negative taste, so when these are in the hooks the balloons repel each other if the hooks are isolated.
If the hooks are connected to Earth, the poop of the balloons is neutralized, so there is neither attraction nor repulsion.
Answer:
Here you go : )
Explanation:
The uniform electric field of a parallel plate capacitor means that the equipotential lines are spaced evenly between the plates. For example if one plate is at 10 V and the other is at -10 V, and the plates are separated by 1 millimeters, you could draw equipotential lines separated by 1 micro meters and each would differ by 0.02 Volts. How much work would it take to move an electron 5 micro meters in the direction of the negative plate? Express your answer in 10^-20 units.
In order to find how much work needs to be applied, we need to use the formula
\(W=q\Delta V\)Since we are dealing with an electron, the charge is 1.60217663 × 10^-19
Since we are trying to find the how much work we have to do if we are moving 5 micro meters, we need to multiply 5 by 0.02 Volts to get a change in voltage of .1 Volts.
W= 1.60217663 × 10^-19 * .1 = 1.60217663 × 10^-20 Joules
what could be the possible answer to the question ?
thankyou ~
The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
The value of F₀ so that string 1 remains vertical is approximately 0.377·M·gHow can the equilibrium of forces be used to find the value of F₀?Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
\(T_1 = \mathbf{\dfrac{M \cdot g}{2}}\)
Which gives;
\(M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}\)
\(T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})} = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}\)
F₀ = T₂·sin(37°)
Which gives;
\(F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2} \approx \mathbf{0.377 \cdot M \cdot g}\)
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2.
A toy plane's is flying 55° going 8 m/s. If the wind is pushing with a velocity of 3 m/s at 30°,
find the total velocity and direction of plane.
Answer:
Vp = velocity of plane
Vpx = Vp cos 55 = 8 * .57 = 4.59 m/s velocity of plane along x-axis
Vpy = Vp sin 55 = 8 * .82 = 6.55 m/s velocity of plane along y-axis
If Wx = -3 m/s then
Vx = 4.59 - 3 = 1.59 m/s
Vy = 6.55 m/s wind does not affect vertical speed
tan theta = Vy / Vx = 6.55 / 1,59 = 4.12
theta = 76.4 deg above x-axis
V = (1.59^2 + 6.55^2)^1/2 = 6.74 m/s
A monk is sitting atop a mountain in complete rest in meditation. What is the kinetic Energy of the monk? (assume mass of 65 kg and the mountain's height was 1000 m)
Answer:
no kinetic energy
hope this helps! :-D
Explanation:
the monk is not moving
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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A student notices that he does better on tests if he sleeps for at least 8 hours. He decides that for the next 3 tests he has in science class, he will sleep different amounts of times and see how he does on his tests. For his next science test, he sleeps only 4 hours the night before, 6 hours before the next test, and 8 hours before the final exam. The chart shows his data. grade Test 1 2 3 Hours of Sleep 4 6 8 Grade 56 75 80 What is the dependent variable?
The dependent variable in the experiment in which a student sleeps different intervals of time to get different grades is the grade
In this experiment,
Independent variable = Hours of sleepDependent variable = GradesControl variable = The studentAn independent variable is the variable that can be altered by the researcher to get different results. The dependent variable is the variable that gets altered due to the change in independent variable.
Therefore, the dependent variable is the Grades
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Nowton's third law refers to 'action reaction forces*. These forces are
always:
equal in magnitude but opposite in direction
Identify and draw the forces that act on the pencil. Be certain to draw each force at the correct location (the point at which the force acts on the pencil). The black dot represents the center of gravity of the pencil. Draw the vectors starting at the points where the forces act on the pencil.
A force is a push or pull upon an object resulting from the object's interaction with another object.
What is force?Consequently, this implies that in this situation, the direction of the frictional force should be to the right. Let me now just illustrate this scenario. Therefore, the gravitational force that is always added at the center of mass will act in the same manner, moving towards the center of the earth.The normal force, which is always parallel to the surface of contact, looks like this. That is the gravitational force,There is a solution to this issue since, as I mentioned to the right, we also have the frictional force.A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.To learn more about force refer to:
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The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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explain the term tenscopo
Answer: Here you go, i hope this kinda helps.
Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".
Watson Assistant replies to user's questions based on a confidence score.
Sometimes the customer's question could be interpreted in two or three different ways.
For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:
Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?
Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.
What does CWT stand for?
hundredweight cwt is a standard unit of weight or mass used in certain commodities trading contracts.
Answer:
hundredweight
Explanation:
Two objects are held close together. When they are released, they move toward one another. Which conclusion is supported by this evidence? O The objects are both positively charged. O The objects are both negatively charged. O The objects have no charge. O The objects have opposite charges. Mark this and return Save and Exit 02:48:18 Next Submit
Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is the objects have opposite charges.
An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.
In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.
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The centripetal acceleration of a point on a wheel is 72 m/s2. The wheel is spinning with a
tangential velocity of 4.3 m/s. What is the radius of the wheel?
The radius of the wheel with a tangential velocity of 4.3 m/s and centripetal acceleration of 72 m/s² is 0.25 meter.
What is centripetal acceleration ?The acceleration of an object ,moving through a circular path is called the centripetal acceleration. It is related to the velocity and radius of curvature of the circular path as follows:
a = v²/r.
The tangential velocity or angular velocity is the rotational analogue of the linear velocity.
given that, tangential velocity v = 4.3 m/s
centripetal acceleration a = 72 m/s²
Then, radius of the wheel is calculated as follows:
r = v²/a
r = (4.3 m/s × 4.3 m/s)72 m/s²
= 0.25 meter.
Therefore, the radius of the rotating wheel is 0.25 meter.
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The equation below can be used to find the specific heat capacity of a substance. What is the specific heat capacity if it takes 1000 J of energy to heat 25 g of this substance by 100°C? Give your answer in J/kg°C.
Answer:
400J/kg°C
Explanation:
The specific heat capacity will be 400 J/kg °C. Specific heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
What is specific heat capacity ?The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly
Mathematically, specific heat capacity is given by;
\(\rm C = \frac{E}{m \times \theta }\)
The given data in the problem is;
The specific heat of the substance is,C in J/kg °C.
The energy is,E =1000 JIs
The mass is,m= 25 g
\(\rm \theta\) Is the temperature difference = 100 °C.
On substituting the given data;
\(\rm C = \frac{E }{m \times \theta } \\\\ C = \frac{1000}{25\times 10^{-3} \times 100 } \\\\ C = 400 \ J/kg^0C.\)
Hence, the specific heat capacity will be 400 J/kg °C.
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A potential difference of 71 mV is developed across the ends of a 12.0-cm-long wire as it moves through a 0.27 T uniform magnetic field at a speed of 6.0 m/s. The magnetic field is perpendicular to the axis of the wire.
Required:
What is the angle between the magnetic field and the wire's velocity?
Answer:
Explanation: please see attached file I attached the answer to your question.
The angle between the magnetic field and the wire's velocity is 33.2 degrees.
Calculation of the angle:Since the potential difference = 71mv = 71 *10 ^-3 V
The length is 12 cm = 0.12m
The magnetic field i.e. B = 0.27T
The speed or v = 4 m/s
here we assume \(\theta\) be the angle
So,
e = Bvl sin\(\theta\)
So,
\(Sin\theta\) = e/bvl
= 71*10^-3 / 0.27 *4*0.12
= 0.5478
= 33.2 degrees
Therefore, the angle should be 33.2 degrees
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a power transmission line is used to transmit 100 kw of power at a voltage of 10 kv with a loss of 1 kw. if the voltage is increased to 200 kv, what is power loss (in watts) to transmit the same amount of power?
To transmit the same amount of electricity, there is a 2.5 W power loss.
What is power loss?A power loss is the difference in power between a device, piece of equipment, pump set, or process' input and output (Pv). Pumps, equipment, and procedures, as well as electrical and electronic devices, turn this undesirable loss into heat.
Consumers receive electric energy in different units than what power plants create. A fraction of the units is lost in the distribution network. This difference between the distributed and created units is referred to as transmission and distribution loss.
According to Ohm's law, power can be defined as
P = VI
Here,
V = Voltage
I = Current
replacing
100kW = 10WI
I = \(\frac{100}{10}\)
I = 10 Amp
Now we can find the resistance
R = \(\frac{P_{LOSS} }{I^{2} }\)
Replacing,
R = \(\frac{1000}{10^{2} }\)
R = 10Ω
In the second state when the voltage is 200kv, we have,
I = \(\frac{100*10^{3} }{200*10^{3} }\)
I= \(\frac{100000}{200000}\)
I= 0.5 A
Now power loss,
\(P_{t}\) = \(I^{2}\)R
\(P_{t}\) = (\(0.5^{2}\)) (10)
\(P_{t}\) = 0.25 *10
\(P_{t}\) =2.5 W
As a result, 2.5W is needed to transport the same amount of electricity.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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PLEASE SEND GIVE THE ANSWER AS FAST AS POSSIBLE
Q1) State similarities & difference between the laboratory thermometers & the clinical thermometers
Q2) Give two examples for conductors & insulators.
Q3) Give reason: Wearing more layers of clothing during winter keeps
us warm
Answer:
(1): Similarities Both thermometers are used to measure temperature and both of them use mercury,Differences Clinical thermometer is used to measure human body temperature whereas laboratory thermometer is used to measure temperature of other object which has higher temperature than human body temperature
(2)Examples of conductors include metals, aqueous solutions of salts, Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.
(3)Air acts as insulator of heat. This layer prevents our body heat to escape in the surroundings. More layers of thin clothes will allow more air to get trapped and as a result we will not feel cold. So wearing more layers of clothing during winter keeps us warmer than wearing just one thick piece of clothing
Explanation:
Which is an SI base unit that makes up part of the unit of energy?
candela
ampere
kelvin
kilogram
The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole
The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²
Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
Learn more about the unit of measurement from here
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