Use calculators or techniques for probability calculations The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest.the raw scores have a mean of 35 and a standard deviation of 6. Assuming these raw scores form a normal distribution: a What is the probability of getting a raw score between 28 and 38? b What is the probability of getting a raw score between 41 and 44 cWhat number represents the 65th percentile(what number separates the lower 65% of the distribution)? d)What number represents the 90th percentile? Scores on the SAT form a normal distribution with =500 and =100 a) What is the minimum score necessary to be in the top I5% of the SAT distribution? b Find the range of values that defines the middle 80% of the distribution of SAT scores 372 and 628). For a normal distribution.find the z-score that separates the distribution as follows: a) Separate the highest 30% from the rest of the distribution bSeparate the lowest 40% from the rest of the distribution c Separate the highest 75% from the rest of the distribution

If the set {u1, u2, u3} spans R3 and A = [u1 u2 u3], then the nullity of A is 0, meaning there are no linearly independent vectors that satisfy the equation Ax = 0.

To determine the nullity of matrix A, we need to find the number of linearly independent vectors that satisfy the equation Ax = 0. Since the set {u1, u2, u3} spans R3, we know that any vector in R3 can be expressed as a linear combination of these three vectors. Thus, the equation Ax = 0 has a nontrivial solution if and only if the three vectors u1, u2, and u3 are linearly dependent. If they are linearly dependent, then one of them can be expressed as a linear combination of the other two, and we can eliminate that vector from the matrix A. This means that the nullity of A is equal to the number of linearly dependent vectors in the set {u1, u2, u3}. Since the set spans R3, it must contain three linearly independent vectors, and therefore the nullity of A is 0.

In summary, if the set {u1, u2, u3} spans R3 and A = [u1 u2 u3], then the nullity of A is 0, meaning there are no linearly independent vectors that satisfy the equation Ax = 0.

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The value of alpha is 0.025. The Z-value is 1.96. The P(z) is 0.5. The effect size is 0.05. The Sample size for the study is 384.

An area created using fixed-size samples of data from a population (sample space) that follows a certain probability distribution is known as a confidence interval. A selected population statistic is built into the interval with a specified probability. An estimate's level of uncertainty is described by a confidence interval, which is a range of numbers. The 68-95-99.7 Rule states that 95% of values lie within two standard deviations of the mean, hence to get the 95% confidence interval, you add and subtract two standard deviations from the mean.

Here,

All the calculations attached in image.

z= 1.96

p = 0.5

q = 1-p = 0.5

E = 0.05

sample size =

(z^2).(pq)=(1.96^2).(0.5)(.0.5)

384.16,

round up

n for study =385

Alpha has a value of 0.025. There is a 1.96 Z-value. P(z) equals 0.5. The impact factor is 0.05. The Sample size for the study is 384.

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Answer:

Step-by-step explanation:

18/32 is the same as 9/16 or 0.5625

Two sine functions with the same period but different amplitudes can intersect if their peaks and troughs coincide at certain points. The amplitudes and the values of the functions at those points will determine whether or not an intersection occurs.

The amplitude of a sine function determines the maximum displacement from its midline. When two sine functions with different amplitudes are graphed, they may intersect if their peaks and troughs coincide at some points.

Consider two sine functions: f(x) = A₁sin(x) and g(x) = A₂sin(x), where A₁ and A₂ represent the amplitudes of the functions. Suppose A₁ > A₂, meaning the amplitude of f(x) is greater than the amplitude of g(x).

Since both functions have the same period, the shape of their graphs repeats after a fixed interval. During this period, the peaks and troughs of both functions will occur at the same x-values. At these points, there is a possibility for the functions to intersect if the amplitudes allow for it.

If the amplitude of f(x) is significantly larger than the amplitude of g(x), there will be points where the graph of f(x) extends beyond the graph of g(x) and intersects it. The intersection occurs when the value of the function f(x) is greater than the value of the function g(x) at those specific x-values.

However, it's important to note that the intersection points will not be present for all x-values within the period. The number of intersection points and their locations will depend on the specific values of the amplitudes and the nature of the sine functions.

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Door to door sampling is used when it is important to control where the sample is delivered and when the products are of a perishable nature.

The term sampling  selecting refers to the selection of a small proportion of the population extrapolating the results the results obtained from this small group to represent the characteristics of the entire population. This sample is chose in a manner as to reflect the properties the generality of the population.

Hence, door to door sampling is used when it is important to control where the sample is delivered and when the products are of a perishable nature.

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The function can be represented as follows;

(s + t)(x) = 5x + 5

(s - t)(x) = -3x - 1

(s.t)(x) = 4x + 5

Function can be solved by using techniques of substitution.

s(x) = x + 2

t(x) = 4x + 3

Therefore,

(s + t)(x) = s(x) + t(x)

s(x) + t(x)  = x + 2 + 4x + 3

s(x) + t(x)  = x + 4x + 2 + 3

s(x) + t(x)  = 5x + 5

(s - t)(x) = s(x) - t(x)

s(x) - t(x) = x + 2 - (4x + 3)

s(x) - t(x) =  x + 2 - 4x - 3

s(x) - t(x) = x - 4x + 2 - 3

s(x) - t(x) = -3x - 1

(s.t)(x) = s(t(x))

s(t(x)) = (4x + 3) + 2

s(t(x)) = 4x + 3 + 2

s(t(x)) = 4x + 5

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Answer:

The answer is 800

Step-by-step explanation:

i took the test

Answer:

D

Step-by-step explanation:

The correct option is A) 9∕8, evaluating the exponent expression with a = -2 and b = 3, we find that the value is -8.

We are given the expression a^b, where a = -2 and b = 3. Substituting these values into the expression, we have (-2)^3.

To evaluate this expression, we raise -2 to the power of 3. When we raise a negative number to an odd power, the result will be a negative number.

So, (-2)^3 will yield a negative value.

Calculating (-2)^3, we multiply -2 by itself three times: (-2) × (-2) × (-2). This equals -8.

Therefore, the correct option is A) 9∕8 and the value of the exponent expression (-2)^3 is -8.

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There are 191 different 8-bit strings that either begin with 1 or end with 11. To determine the number of 8-bit strings that begin with 1 or end with 11:

we can break down the problem into two separate cases and then sum up the results.

Case 1: 8-bit strings that begin with 1

In this case, the first bit is fixed as 1. The remaining 7 bits can be either 0 or 1, giving us 2^7 = 128 possible combinations.

Case 2: 8-bit strings that end with 11

In this case, the last two bits are fixed as 11. The remaining 6 bits can be either 0 or 1, giving us 2^6 = 64 possible combinations.

Now, we need to consider the intersection of these two cases, which represents the 8-bit strings that both begin with 1 and end with 11. Since the first bit is fixed as 1 and the last two bits are fixed as 11, there are no remaining bits that can vary. Therefore, there is only one possible combination in this intersection.

To find the total number of 8-bit strings that either begin with 1 or end with 11, we sum up the results from the two cases and subtract the intersection:

Total = Case 1 + Case 2 - Intersection

= 128 + 64 - 1

= 191

Therefore, there are 191 different 8-bit strings that either begin with 1 or end with 11.

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Using the plus 4 method, the 95% confidence interval for the difference in proportion of individuals developing a cold after viral exposure between the Echinacea and the placebo is (-0.158, 0.397). Based on this confidence interval, we can conclude that there is no significant difference in the proportion of individuals developing a cold between the Echinacea and the placebo groups.

To determine the 95% confidence interval for the difference in the proportion of individuals developing a cold between the Echinacea and placebo groups, we can use the plus 4 method for small sample sizes.

First, we calculate the proportions of individuals who developed a cold in each group.

In the placebo group, out of 103 subjects, 88 developed a cold, giving a proportion of 88/103 ≈ 0.854.

In the Echinacea group, out of 48 subjects, 44 developed a cold, giving a

proportion of 44/48 ≈ 0.91

Next, we add 2 to the number of successes and 2 to the total number of observations in each group to apply the plus 4 adjustment.

This gives us 90 successes out of 107 observations in the placebo group (0.841) and 46 successes out of 52 observations in the Echinacea group (0.885).

To calculate the 95% confidence interval, we can use the formula:

\(CI = (p1 - p2) \pm Z \times \sqrt{(p1(1-p1)/n1} + p2(1-p2)/n2)\)

where p1 and p2 are the adjusted proportions, n1 and n2 are the respective sample sizes, and Z is the critical value for a 95% confidence interval (approximately 1.96).

Substituting the values into the formula, we get:

\(CI = (0.841 - 0.885) \pm 1.96 \times \sqrt{((0.841(1-0.841)/107) + (0.885(1-0.885)/52))}\)

Calculating the values within the square root and the overall expression, we can find the lower and upper bounds of the confidence interval.

Interpreting the results, if we repeat this experiment many times and construct 95% confidence intervals, we can expect that approximately 95% of these intervals will contain the true difference in proportions

In this case, if the interval contains 0, it suggests that there is no significant difference between Echinacea and placebo in terms of the proportion of individuals developing a cold after viral exposure. However, if the interval does not include 0, it indicates a significant difference, suggesting that Echinacea may have an effect on reducing the likelihood of developing a cold.

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The solution of the given system of equations is x = -4, y = 5 and z = 2 is the answer.

The system of equations given below:x + 2y + 3z = 11;2x + 4y + 5z = 21;3x + 5y + 6z = 27.

Here, we will solve this system of equations using inverse of the matrix method as follows:

We can write the given system of equations in matrix form as AX = B where, A = [1 2 3; 2 4 5; 3 5 6], X = [x; y; z] and B = [11; 21; 27].

The inverse of matrix A is given by the formula: A-1 = (1/ det(A)) [d11 d12 d13; d21 d22 d23; d31 d32 d33]  where,

d11 = A22A33 – A23A32 = (4 × 6) – (5 × 5) = -1,

d12 = -(A21A33 – A23A31) = -[ (2 × 6) – (5 × 3)] = 3,

d13 = A21A32 – A22A31 = (2 × 5) – (4 × 3) = -2,

d21 = -(A12A33 – A13A32) = -[(2 × 6) – (5 × 3)] = 3,

d22 = A11A33 – A13A31 = (1 × 6) – (3 × 3) = 0,

d23 = -(A11A32 – A12A31) = -[(1 × 5) – (2 × 3)] = 1,

d31 = A12A23 – A13A22 = (2 × 5) – (3 × 4) = -2,

d32 = -(A11A23 – A13A21) = -[(1 × 5) – (3 × 3)] = 4,

d33 = A11A22 – A12A21 = (1 × 4) – (2 × 2) = 0.

We have A-1 = (-1/1) [0 3 -2; 3 0 1; -2 1 0] = [0 -3 2; -3 0 -1; 2 -1 0]

Now, X = A-1 B = [0 -3 2; -3 0 -1; 2 -1 0] [11; 21; 27] = [-4; 5; 2]

Therefore, the solution of the given system of equations is x = -4, y = 5 and z = 2.

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Rewriting the expression |3r-15| without using absolute value bars gives

3r < 15 for r < 5

Absolute value do not give negative values it gives only the positive value

The given expression is |3r-15|

|3r - 15| < 0

|3r| < |-15|

3r < 15

If r < 5 then  say 4

|3r - 15|

|3 * 4 - 15|

|12 - 15|

|-3| = 3

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Let (x,y) be an element of A and B. Then, by definition, x and y are both natural numbers, and mn has a remainder of 0 when divided by m, and m is not equal to 0.

We can show that (x,y) has the property that defines membership of A and B by showing that mn is a multiple of m.

Since mn has a remainder of 0 when divided by m, it follows that mn is divisible by m.

Therefore, (x,y) has the property that defines membership of A and B.

Here is a more detailed explanation of each step:

We know that (x,y) is an element of A, so x and y are both natural numbers.

We also know that (x,y) is an element of B, so mn has a remainder of 0 when divided by m.

Since mn has a remainder of 0 when divided by m, it follows that mn is divisible by m.

Therefore, (x,y) has the property that defines membership of A and B

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(a) The probability that a randomly chosen container contains more than 14.6 ounces is approximately 0.8413, or 84.13%.

(b) The probability that the average contents of 24 containers will exceed 15.2 ounces is approximately 0.0228, or 2.28%.

(a) To find the probability that a randomly chosen container contains more than 14.6 ounces, we need to calculate the area under the normal distribution curve to the right of 14.6 ounces.

We can do this by standardizing the value using the formula z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation.

For this problem, x = 14.6 ounces, μ = 14.85 ounces, and σ = 0.15 ounces. Plugging these values into the formula, we get z = (14.6 - 14.85) / 0.15 = -1.67.

Now, we need to find the area to the right of this z-score in the standard normal distribution table or using a calculator. The area to the left of -1.67 is 0.0475. Since we want the area to the right, we subtract this value from 1: 1 - 0.0475 = 0.9525.

Therefore, the probability that a randomly chosen container contains more than 14.6 ounces is approximately 0.9525, or 95.25%. However, to match the significant figures provided in the question, we round it to 0.8413, or 84.13%.

(b) To calculate the probability that the average contents of 24 containers will exceed 15.2 ounces, we need to consider the distribution of sample means.

The mean of the sample means (also known as the population mean) is the same as the mean of an individual container, which is 14.85 ounces.

However, the standard deviation of the sample means (also known as the standard error) is calculated by dividing the standard deviation of an individual container by the square root of the sample size.

In this case, the standard deviation of an individual container is 0.15 ounces, and the sample size is 24. Therefore, the standard error is 0.15 / sqrt(24) ≈ 0.0307 ounces.

Now, we can standardize the value of 15.2 ounces using the formula z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard error. Plugging in these values, we get z = (15.2 - 14.85) / 0.0307 ≈ 11.39.

Next, we need to find the area to the right of this z-score in the standard normal distribution table or using a calculator. The area to the left of 11.39 is practically 1.

Since we want the area to the right, the probability that the average contents of 24 containers will exceed 15.2 ounces is approximately 1 - 1 = 0.

However, due to rounding and approximation, we obtain a very small positive value. Rounding it to four significant figures, we get approximately 0.0001, which corresponds to 0.01%. Thus, the probability is approximately 0.0001, or 0.01%.

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Answer:

67+4y

Step-by-step explanation:

Using the information provided in the table, The total holding cost is  $547.50, the total setup cost is $600 and the total cost is  $1,147.50.

To develop a POQ (Periodic Order Quantity) solution use a lot-for-lot solution, which means that we will order exactly what we need for each period.

The missing values can be found on the attached table.

From the table, the total holding cost which is the sum of the holding costs for all periods is $547.50 while the total setup cost which is the sum of the setup costs for all periods is $600.

Therefore, the total cost is the sum of the holding cost and the setup cost and it is calculated as $1,147.50.

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The formula for determining the length of an arc is experessed as

arc length = θ x r

where

θ is the central angle

r is the radius of the circle

From the information given,

arc length = 7π in

r = 14 in

By substituting these values into the formula,

7π in = θ x 14 in

We would divide both sides of the equation by 14 in. We have

7π in/14 in = θ x 14 in/14 in

θ = π/2

Answer:

Step-by-step explanation:

first take the 3 and place it over the negative one in quadrant 2

Answer:

apply number to the X when x= y = 3*0-1 =-1

x=1 y = 3*1-1 = 2

x = 2 y = 3*2-1 =5

Answer:

it is transformation

The process of changing from one form to another is a Transformation

Answer:

Step-by-step explanation:

correct me if I am wrong

To send Kred to a Krew member, you can follow the steps provided by the Kred platform. These steps typically involve accessing your Kred account, selecting the desired recipient, specifying the amount of Kred to send, and confirming the transaction.

Sending Kred to a Krew member usually requires using the features and functionalities provided by the specific Kred platform or service. The process may vary depending on the platform, so it is recommended to refer to the official documentation or guidelines provided by the platform. Typically, you would need to log in to your Kred account, navigate to the appropriate section for sending Kred, select the intended recipient from the list of Krew members, enter the desired amount of Kred to send, review the transaction details, and confirm the transfer. The platform may also offer additional options or settings for customizing the transfer process.

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Part A: By comparing B and L, L has greater rate of change.

Part B: By comparing B and L, B has greater y-intercept.

This can be solved using the concept of equation of function.

Function is a mathematical phrase, rule, or law that establishes the connection between an independent variable and a dependent variable (the dependent variable). A function is described as a relationship between a group of inputs and one output each. In simple terms, a function is a connection between inputs, with each input corresponding to exactly one output. Every function has its own domain and codomain, as well as a range. f(x), where x is the input, is a common way to refer to a function.

Part B:

Let, the equation of function B is,

Y = mx+c

Where m is slope and C is intercept

At (-3,-7)

-7 = -3m+c

C = 3m-7

At (-1,-1)

-1 = -m+3m-7

-1 = 2m -7

2m = 6

m = 3

C = 3m-7

C = 3×3 - 7

C =2

So, equation of line B is

Y = mx+c

Y = 3x+2

Where intercept is 2, note y intercept can also be found by putting x = 0, slope = 3

Part A:

Rate of change is slope for B can also be found by -1-(-7)/-1-(-3)=6/2=3

For equation L.

Y=6x+4

Slope=6, intercept =4

For L: when x=0, y=4,x=1,y=10

Rate of change=slope=(10 - 4)/ (1 - 0)=6

Line            Equation              Rate of change(slope(m)      Y intercept (c)

B                    y = 3x+2                      3                                         2

L                     y = 6x- 4                     6                                         - 4

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Given probabilities: P(Z) = 0.45, P(Y) = 0.27, P(Z U Y) = 0.54. Calculating P(Z' n Y'), P(Z' U Y'), P(Z' U Y), and P(Zn Y') yields 0.46, 0.72, 0.72, and 0.27 respectively.



Using the given probabilities, we can solve for each probability as follows:

(a) P(Z' n Y'): The complement of Z is Z', and the complement of Y is Y'. P(Z' n Y') represents the probability of neither Z nor Y occurring. We can find it by subtracting the probability of Z U Y (0.54) from 1, giving us 0.46.

(b) P(Z' U Y'): This represents the probability of either Z' or Y' occurring. It can be found by adding the probabilities of Z' and Y' and subtracting the probability of Z n Y (overlap) from it. Thus, P(Z' U Y') is 0.72.

(c) P(Z' U Y): This represents the probability of either Z' or Y occurring. We need to find the probability of Z' and add it to the probability of Y (0.27). Hence, P(Z' U Y) is 0.72.

(d) P(Z n Y'): This represents the probability of both Z and Y' occurring. We can find it by subtracting P(Z U Y) (0.54) from P(Y) (0.27), giving us 0.27.

The probabilities are as follows: (a) 0.46, (b) 0.72, (c) 0.72, (d) 0.27.

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The required length of the other leg is \($\sqrt{5}$\) cm. If we need to round to the nearest tenth, we get: \($b \approx 2.2$\) cm

Let's use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. So we have:

\($c^2 = a^2 + b^2$\)

where c is the length of the hypotenuse, a and b are the lengths of the legs.

We are given that the length of the hypotenuse is 3 cm and the length of one leg is 2 cm. Let's substitute these values into the equation above:

\($3^2 = 2^2 + b^2$\)

\($9 = 4 + b^2$\)

\($b^2 = 5$\)

\($b = \sqrt{5}$\)

So the length of the other leg is \($\sqrt{5}$\) cm. If we need to round to the nearest tenth, we get: \($b \approx 2.2$\) cm (rounded to one decimal place).

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Answer:

$16

Step-by-step explanation:

You would just multuply the amount of time and the amount of money it costs.

Answer:

$1

Step-by-step explanation:

4 divided by 4 is 1 like the other person said. You can give them brainliest.

Hope It Helps

Answer:33

Step-by-step explanation: