URGENT SOMEBODY PLZ HELP

URGENT SOMEBODY PLZ HELP

Answers

Answer 1

First one is B (43) and the second one is C (35)!


Related Questions

In a survey conducted by the marketing agency 11mark, 241 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom (confessions included texting and answering phone calls).
(a) What is the sample in this study? What is the population of interest?
(b) What is the variable of interest in this study? ls it qualitative or quantitative?
(c) Based on the results of this survey, obtain a point estimate for the proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom.
(d) Explain why the point estimate found in part (c) is a statistic. Explain why it is a random variable. What is the source of variability in the random variable?
(e) Construct and interpret a 95% confidence interval for the population proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom.
(f) What ensures that the results of this study are representative of all adults 19 years of age or older?

Answers

Answer: kindly check explanation

Step-by-step explanation:

A) The sample is a fraction of the total population used in the study.

The sample is 1000 19 years of age or older U.S adult.

The population : all U.S adults aged 19 or older.

B.) Confession about bringing cell phone to the bathroom and it is a qualitative variable

C.) point estimate (p) :

Total number of sample = 1000

Number who confessed to bring cellphone = 241

p = 241/ 1000

= 241/1000 = 0.241

D.) The point estimate was deduced from the sample information and not the population. Random selection because selection is unbiased.

E.) 95% confidence interval (CI)

95% CI = (1 - 0.95) = 0.05

For a two-tailed test : 0.05 / 2 = 0.025

Z - score = 1.96

Error : (√[p(1 - p) / n])*z

1.96 * √0.241(1-0.241)/1000

1.96* √0.000182919

1.96 * 0.0135247

= 0.0265085

Boundary :

(0.241 - 0.0265085), (0.241 + 0.0265085)

(0.2144915, 0.2675085)

F) The sample can be said to be representative of the total population since the sampling was performed and participants were chosen at random.

given that a and b are 4 × 4 matrices, deta=2, and det(2a−2bt )=1, find detb a 1/8 b 1/4 c 1/2 d 2 e 4

Answers

The value of det(b) cannot be determined based on the given information.

How to determine the value of det(b)?

To find det(b) based on the given information, let's analyze the equation det(2a - 2bt) = 1.

We know that det(2a - 2bt) = (2\(^n\)) * det(a - bt), where n is the size of the matrix (in this case, n = 4).

Given that det(a) = 2, we can rewrite the equation as follows:

(2\(^n\)) * det(a - bt) = 1

Substituting n = 4 and det(a) = 2, we have:

(2\(^4\)) * det(a - bt) = 1

16 * det(a - bt) = 1

Now, we are given that det(a - bt) = 1, so we can rewrite the equation as:

16 * 1 = 1

This equation is not possible, as it contradicts the given information.

Therefore, there is no specific value that can be determined for det(b) based on the provided information.

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Pls answer b and c for my brother

Pls answer b and c for my brother

Answers

Answer:

B and C

Step-by-step explanation:

Answer:

this was hard

Step-by-step explanation:

1b. 7 1/2

2b. 9 3/4

3b. 6 1/2

4b. 2 2/3

5b. 3 1/3

6b. 9 3/4

7b. 8 6/7

8b. 5 2/3

9b. 3 3/5

10b. 28

1c. 8 4/5

2c. 8 2/3

3c. 5 2/3

4c. 2 1/3

5c. 5 1/2

6c. 2 3/7

7c. 7 4/5

8c. 8 1/2

9c. 2 3/4

10c. 122

The domain of a certain exponential function is all real numbers. The range of the function is all real
numbers greater than -3. The graph of the function has a horizontal asymptote at y = -3.
Select a graph or graphs to fit the description of the function.

Answers

One exponential function with the given features is y = 2^x - 3, and is graphed at the end of the answer.

How to define the exponential function?

An exponential function is defined as follows:

y = a(b)^x + c.

In which:

a is the initial value.b is the rate of change.c is the horizontal asymptote.

The graph of the function has a horizontal asymptote at y = -3, hence:

c = -3.

For a and b, they can assume any non-negative values, hence we attribute these following values:

a = 1, b = 2.

The graph is given at the end of the answer.

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The domain of a certain exponential function is all real numbers. The range of the function is all realnumbers

The Number of students in a chess club decrease from 30 to 14. What is the percent decrease? Round your answer to the nearest percent.

The percent decrease is:

Answers

Answer:

53%

Step-by-step explanation:

percent change= amount of change/ original amount

that decimal (0.53) turns into a decimal.

Question 29 of 40
A car wash team at a fund-raiser can wash 1 car in 8 minutes. How many
cars can the team wash in 48 minutes?
A. 7 cars
B. 56 cars
C. 384 cars
D. 6 cars

Answers

Answer:

6 how do you not know this?

Step-by-step explanation:

8 = 1

16 = 2

24 = 3

32 = 4

40 = 5

48 = 6

maths. the more you know

57. FINANCIAL LITERACY Cleavon has money in an account that eams 3% simple interest. The formula for computing simple interests I = Prt, where I is the interest earned, P represents the principal that he put into the account, r is the
interest rate (in decimal form), and t represents time in years,

a. Cleavon makes a deposit of $2c and leaves it for 2 years. Write a monomial that represents the interest earned,

b. If c represents a birthday gift of $250, how much will Cleavon have in this account after 2 years?

Answers

financial lieutenant is the way periodt so do that

Find the area of hexagon DEFGHI.

Find the area of hexagon DEFGHI.

Answers

Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

Find the area of hexagon DEFGHI.

Answer The Following True Or False: The Periods Of The Six Trigonometric Functions: Sinx,Cosx,Secx,Cscx,Tanx,Cotx Are All 2π. True False

Answers

This implies that the value of the function will begin to repeat every 2π radians. The period of the tangent function, tan(x), and cot(x) are π. This implies that the value of the function will begin to repeat every π radians.Answer: True.

The statement "The periods of the six trigonometric functions: sin x, cos x, sec x, csc x, tan x, cot x are all 2π" is True. The period of a trigonometric function is the length of the interval required to complete one full cycle of the function. It is the shortest length of an interval such that the function returns to its initial value after this length.The period of the sine function, cos(x), sec(x), and csc(x) are 2π. This implies that the value of the function will begin to repeat every 2π radians. The period of the tangent function, tan(x), and cot(x) are π. This implies that the value of the function will begin to repeat every π radians.Answer: True.

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It is believed that it does not matter where you by your car from, whether from company A or company B, all take the same average time until they are broken down. - A sample of 42 taken from company A showed an average time to breakdown of 12 years with standard deviation of 4 years. - A sample of 51 taken from company B showed an average time to breakdown of 10 years with standard deviation of 6 years. With α=0.01, test if the belief is true assuming σ
1


2

.

Answers

A hypothesis test is conducted to determine whether there is a significant difference in the average time until breakdown for cars from company A and company B.

To test the hypothesis, we employ a two-sample t-test since we do not know the population standard deviations. The null hypothesis (H₀) states that the average time until breakdown for cars from company A (μ₁) is equal to the average time until breakdown for cars from company B (μ₂), while the alternative hypothesis (H₁) states that μ₁ is not equal to μ₂.

The test statistic is calculated using the formula:

t = (x₁ - x₂) / √[(s₁²/n₁) + (s₂²/n₂)]

where x₁ and x₂ are the sample means, s₁ and s₂ are the sample standard deviations, and n₁ and n₂ are the sample sizes. Plugging in the given values, we get:

t = (12 - 10) / √[(4²/42) + (6²/51)]

After calculating the test statistic, we compare it to the critical value from the t-distribution with degrees of freedom determined by the sample sizes and significance level α=0.01. If the test statistic falls in the critical region (i.e., outside the critical value range), we reject the null hypothesis in favor of the alternative hypothesis, suggesting a significant difference in the average time until breakdown between the two companies.

In conclusion, by performing the hypothesis test, we can determine whether there is sufficient evidence to reject the belief that both companies have the same average time until car breakdown.

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for the probability distribution of a discrete random variable x, the sum of all values of x must be

Answers

For the probability distribution of a discrete random variable x, the sum of all values of x must be equal to 1.

We have,

The sum of all values of a discrete random variable x in its probability distribution should be equal to 1 because the probability distribution represents the likelihood of each possible value occurring.

In other words, the probabilities assigned to each value of x should account for all possible outcomes and collectively add up to the total probability of 1, which represents the certainty or 100% likelihood of an event occurring.

In a probability distribution, each value of x has an associated probability assigned to it.

These probabilities must satisfy two conditions: they must be non-negative (greater than or equal to 0) and their sum must be equal to 1. This ensures that the total probability accounts for all possible outcomes and covers the entire sample space.

By summing up the probabilities for all values of x in the probability distribution, we can verify if they add up to 1. If the sum is not equal to 1, it implies that there is an error in the probability distribution, and it needs to be adjusted to meet the requirement of a valid probability distribution.

Thus,

For the probability distribution of a discrete random variable x, the sum of all values of x must be equal to 1.

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The complete question:

For the probability distribution of a discrete random variable x, the sum of all values of x must be?

Last week, Sue bought 10 shirts and 4 hats for a total of $116.
Today, Sue bought 21 shirts and 15 hats for a total of $270.
Assuming neither item has changed in price, what is the cost of a shirt in dollars?

Answers

The solution is, the cost of a shirt in dollars is $10.

What is equation?

An equation is a  mathematical statement that is made up of two expressions connected by an equal sign.  In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

here, we have,

given that,

Sue bought 10 shirts and 4 hats for a total of $116.

Today, Sue bought 21 shirts and 15 hats for a total of $270.

let, cost of shirt = x

cost of hat = y

so, we get,

10x+4y = 116

21x+15y = 270

solving we get,

x=10

y=4

Hence, The solution is, the cost of a shirt in dollars is $10.

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When Jose had cable TV, he had 120 channels. He switched to satellite TV, and now he has 300 channels. What is the percent increase in the number of channels Jose has to watch? Round to the nearest percent.

Answers

The percent increase in the number of channels Jose has to watch is 150%.

What is percent?

To find the percent increase in the number of channels Jose has to watch, we need to find the difference between the new number of channels and the old number of channels, divide that by the old number of channels, and then multiply by 100 to get the percentage increase.

The difference between the new and old number of channels is 300 - 120 = 180.

Dividing that by the old number of channels and multiplying by 100 gives us:

(180/120) x 100% = 150%

Therefore, the percent increase in the number of channels Jose has to watch is 150%. This means that Jose now has 150% more channels to watch than he did before he switched to satellite TV.

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PLEASE HELP!!!! I WILL GIVE BRAINEST

PLEASE HELP!!!! I WILL GIVE BRAINEST

Answers

Answer:

A. V= area of base x height 1/3

(20x15)x30x1/3= 3000cm

B.65cm

C.CTCN is the angle between

tan<TCN= TN/NC=12/5

=67.380

D. 10\sqrt(10)

e.tan<TMN=TN/MN=3

<TMN=71.57

A student said we cannot subtract 1.97 from 20 because 1.97 has two decimal digits and 20 has none. Do you agree with his statement? Explain or show your reasoning.

Answers

Answer:

No

Step-by-step explanation:

everything has a infinite amount of zeroes behind the decimal point or where it ends at least

Just add a decimal after 20 because it is a whole number.
20.00 - 1.97 = 18.03
Just remember to line up your decimals when subtracting.

One unit of A is composed of two units of B and three units of C. Each B is composed of one unit of F. C is made of one unit of D, one unit of E, and two units of F. Items A,B,C, and D have 20,50,60, and 25 units of on-hand inventory, respectively. Items A,B, and C use lot-for-lot (L4L) as their lot-sizing technique, while D,E, and F require multiples of 50,100 , and 100 , respectively, to be purchased. B has scheduled receipts of 30 units in period 1. No other scheduled receipts exist. Lead times are one period for items A, B, and D, and two periods for items C,E, and F. Gross requirements for A are 20 units in period 1,20 units in period 2, 60 units in period 6, and 50 units in period 8. Find the planned order releases for all items.

Answers

The planned order releases for each item are as follows: A: 20 units in period 1, B: 10 units in period 1, C: 40 units in period 3, D: No planned order release, E: 100 units in period 5, F: 100 units in period 5

To determine the planned order releases for all items, we need to calculate the net requirements for each period based on the given information. We will start with the highest-level item and work our way down the bill of materials.

Item A:

Period 1: Gross requirement of 20 units.

Since A uses lot-for-lot (L4L) as the lot-sizing technique, we release an order for 20 units of A.

Item B:

Item B is a component of A, and each A requires 2 units of B.

We need to calculate the net requirements for B based on the planned order release for A.

Period 1: Gross requirement of 20 units * 2 (requirement multiplier for B) = 40 units.

B has a scheduled receipt of 30 units in period 1.

Net requirement for B in period 1: 40 units - 30 units = 10 units.

Since B also uses L4L as the lot-sizing technique, we release an order for 10 units of B.

Item C:

Item C is a component of A, and each A requires 3 units of C.

We need to calculate the net requirements for C based on the planned order release for A.

Period 1: Gross requirement of 20 units * 3 (requirement multiplier for C) = 60 units.

C has a lead time of two periods, so we need to account for that.

Net requirement for C in period 3: 60 units - 20 units (scheduled receipt for A in period 1) = 40 units.

Since C uses L4L as the lot-sizing technique, we release an order for 40 units of C.

Item D:

Item D is a component of C, and each C requires 1 unit of D.

We need to calculate the net requirements for D based on the planned order release for C.

Period 3: Gross requirement of 40 units * 1 (requirement multiplier for D) = 40 units.

D has a lead time of one period, so we need to account for that.

Net requirement for D in period 4: 40 units - 60 units (scheduled receipt for C in period 3) = -20 units (no requirement).

Since the net requirement is negative, we do not release any planned order for D.

Item E:

Item E is a component of C, and each C requires 1 unit of E.

We need to calculate the net requirements for E based on the planned order release for C.

Period 3: Gross requirement of 40 units * 1 (requirement multiplier for E) = 40 units.

E has a lead time of two periods, so we need to account for that.

Net requirement for E in period 5: 40 units - 0 units (no scheduled receipt for E) = 40 units.

Since E requires a multiple of 100 to be purchased, we release an order for 100 units of E.

Item F:

Item F is a component of B and C, and each B requires 1 unit of F, while each C requires 2 units of F.

We need to calculate the net requirements for F based on the planned order releases for B and C.

Period 1: Gross requirement for B = 10 units * 1 (requirement multiplier for F) = 10 units.

Period 3: Gross requirement for C = 40 units * 2 (requirement multiplier for F) = 80 units.

F has a lead time of two periods, so we need to account for that.

Net requirement for F in period 5: 10 units + 80 units - 0 units (no scheduled receipt for F) = 90 units.

Since F requires a multiple of 100 to be purchased, we release an order for 100 units of F.

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Due in thirty minutes pls help thx for the help

Due in thirty minutes pls help thx for the help

Answers

Answer: guys i cant be the only one who doesnt understand story questions.

Step-by-step explanation:

write the miles version of 80km

Answers

Answer:

49.7 mph

Step-by-step explanation:

divide the length value by 1.609

what's 3.7 as a mixed number

Answers

Answer:3 7/10

Step-by-step explanation:

Answer 3 7/10  or three and seven tenths

Step-by-step explanation:

In which quadrant does the terminal side of the angle 257° lie?
O Quadrant I
Quadrant II
Quadrant III
Quadrant IV

Answers

SOLUTION :-

The Angle 257° will lie in the Quadrant III .

STEP-BY-STEP EXPLANATION :-

We have been asked to find .

• In which quadrant does the terminal side of the angle 257° lie ?

As we know that in the first quadrant angle is from 0 to 90 ° .

In the second quadrant angle is from 90 to 180°.

In the third quadrant angle is from 180 to 270° .

In the fourth quadrant angle is from 270 to 360° .

Hence,The Angle 257 will lie in the third Quadrant .....

Hope this helps !!

At 0845 hours, a lorry leaves Town A for Town B at an average speed of 52 km/h. It arrives at Town S at 1230 hours. On the return journey, the lorry leaves Town B at 1455 hours and arrives at Town A at 1815 hours. Find the average speed of the lorry on the return journey.​

Answers

The average speed of the lorry on the return journey is 58.5 km. If At 0845 hours, a lorry leaves Town A for Town B at an average speed of 52 km/h. It arrives at Town S at 1230 hours. On the return journey, the lorry leaves Town B at 1455 hours and arrives at Town A at 1815 hours.

Define speed.

The speed of an object can be determined by calculating the distance it covers in a given length of time. For instance, if a car goes 70 miles in an hour, it is doing so at a pace of 70 miles per hour (miles per hour).

Given,

At 0845 hours, a lorry leaves Town A for Town B at an average speed of 52 km/h. It arrives at Town S at 1230 hours.

On the return journey, the lorry leaves Town B at 1455 hours and arrives at Town A at 1815 hours.

distance = speed × time

Average speed from town A to town B is 52 km/h at 3 3/4 hrs.

Distance = 52 km/h × 3 3/4 hrs ...eq1

Let speed in return journey = r

Then distance = r × 3 1/3 hrs ...eq2

From eq1 & eq2

52 ×3 3/4 = r × 3 1/3

52 ×15/4 = r × 10/3

r = (52×15×3)/(4×10) km

r = (13×3×3)/2 km

r = 117/2 km

r = 58.5 km

The average speed of the lorry on the return journey is 58.5 km.

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please help, my time is running out

please help, my time is running out

Answers

Answer: 40 ?

Step-by-step explanation:

Which equation has exactly one solution in common with the equation y=6x-2?

A. 18x - 3y = 6
B. 1/2y = 3x - 2
C. 2y = 4x - 12
D. 18x - 12 = 3y

Answers

Answer:

A. 18x - 3y = 6

Step-by-step explanation:

By taking 3 common from the terms 18x and 3y we get,

3 (6x-3y) = 6

or, 6x - y = 6/3

or, 6x - y = 2

And,

The equation becomes,

y = 6x - 2

The equation has exactly one solution in common with the equation y=6x-2 will be 18x - 3y = 6. The correct option is A.

What is a system of equations?

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations or an equation system.

An equation is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

By taking 3 commons from the terms 18x and 3y we get,

3 (6x-3y) = 6

6x - y = 6/3

6x - y = 2

The equation becomes,

y = 6x - 2

Therefore, the equation has exactly one solution in common with the equation y=6x-2 will be 18x - 3y = 6. The correct option is A.

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Using a trial and improvement method, find x correct to 1 decimal place.
3x² - x = 30

Using a trial and improvement method, find x correct to 1 decimal place.3x - x = 30

Answers

Answer:

x = 10/3

x = -3

Step-by-step explanation:

3x² - x = 30

3x² - x - 30 = 0

multiply 3 and -30 which =

-90

what are 2 numbers that when multiplied make

-90

and that when added make

-1

(-1 is the number in -x in the equation)

they are the numbers 9 and 10

namely -10 and +9

3(x-10/3)(x+9/3)=0

divide both sides by 3

(x-10/3)(x+9/3)=0

then split factors being multiplied

(x-10/3)=0

(x+9/3)=0

x = 10/3

x = - 9/3 = -3

Here’s the answer to your question x = 3.3, -3

A triangle with angles 89.9°, 50.1°, and 40.0° what type of triangle is it

Answers

Answer:

Triangle=89.9 + 50.1 + 40(flat)= 140+40=180 and 180 is a straight angle ABC

                \           /

            89.9+50.1=140

Ellora wants to accumulate $150000.00 in an RRSP by making annual contributions of $5000.00 at the beginning of each year. If interest is 5.5% compounded quarterly, calculate how long she has to make contributions.
a. 18.202125 
b. 18.676765 
c. 17.455483 
d. 17.585794 
e. 18.076686

Answers

Option A is the correct answer. Ellora wants to accumulate 150,000 in an RRSP by making annual contributions of 5,000 at the beginning of each year. If interest is 5.5% compounded quarterly, calculate how long she has to make contributions.

First, we have to find the interest rate per quarter, which will be
\(5.5% / 4\)= 1.375%.
The formula for the future value of an annuity is: 
\(FV = (C * [(1 + r)^n - 1] / r)\),

For Ellora, \(FV = $150,000, C = $5,000, and r = 1.375%.\)
Substituting these values into the formula gives:
\(150,000 = 5,000 * [(1 + 0.01375)^n - 1] / 0.01375\)
Simplifying this equation gives:
\(30 = [(1.01375)^n - 1]\)

We can solve this using logarithms:
\(ln 30 = ln [(1.01375)^n - 1]\)
\(ln 30 = n * ln 1.01375 - ln 1.01375e^(ln 30) / e^(-ln 1.01375) = n18.202125 = n\)

Therefore, it will take Ellora 18.202125 years to accumulate 150,000 in her RRSP through \($5,000\)annual contributions made at the beginning of each year with interest of \(5.5%\) compounded quarterly.


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write an equation for the horizontal line that passes through

Answers

the equation of the horizontal line passing through (-3, 4) is y = 4.

The equation of a horizontal line is of the form y = c, where c represents the y-coordinate of any point on the line. In this case, we are given that the line passes through the point (-3, 4). Since the line is horizontal, the y-coordinate remains constant for all points on the line.

Therefore, the equation of the horizontal line passing through (-3, 4) is y = 4. This means that no matter what x-value we choose, the y-value will always be 4.

In other words, all the points on this line will have a y-coordinate of 4.

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Complete question is below

Write the equation of the horizontal line that passes through (-3, 4).

The equation for the horizontal line that passes through a given point is y = b.

A horizontal line is a straight line that is parallel to the x-axis. The equation of a horizontal line is of the form y = c, where c is a constant. Since the line is horizontal, the value of y remains constant for all values of x. Therefore, the equation of a horizontal line passing through a given point (a, b) is y = b.

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An online news report claims that 50% of online news readers work in the business industry. to test this claim, a researcher takes an srs of 25 online news readers. nine of them work in the business industry. a simulation of 65 trials was conducted under the assumption that 50% of online news readers really do work in the business industry. a dotplot titled online readers and the business industry has number of readers from the food industry on the x-axis, and frequency on the y-axis. 8, 1; 9, 2; 10, 6; 11, 9; 12, 13; 13, 15; 14, 9; 15, 6; 16, 2; 17, 0; 18, 1; 19, 1. based on this dotplot and the sample of 25 online news readers, which conclusion can be drawn? since 0.36 of the sample works in the business industry, 0.36 is the true probability that an online news reader works in the business industry. it is most likely that, out of 25 online readers, between 12 and 13 work in the business industry. because there appear to be outliers present that are greater than 16, we can conclude that more than 50% of online readers work in the business industry. there is about a 0.046 chance that 9 or fewer online readers work in the business industry. this is unusual and is convincing evidence that less than 50% of online readers work in the business industry.

Answers

The dot plot backs up the null hypothesis that 50% of online news readers work in business.

According to the dot plot and the sample of 25 online news readers, between 12 and 13 online readers work in the business industry. This conclusion can be drawn based on the dot plot's highest frequency, which is between 12 and 13.

However, concluding that 0.36 is the true probability of an online news reader working in the business industry is incorrect. Because the sample of 25 online news readers is not representative of the entire population of online news readers, using the sample proportion as the true probability is inappropriate.

Furthermore, the dotplot does not provide sufficient evidence to conclude that more than half of online readers work in the business industry. The null hypothesis is that 50% of online news readers work in the business industry, and the simulation of 65 trials under this assumption suggests that 9 or fewer online news readers working in the business industry is not uncommon.

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(3-6 arithmetic sequences as linear functions)
1. -4, -2, 0, 2, ...
2. 1/2, 5/8, 3/4, 13/16

Answers

1.  -4, -2, 0, 2... is an arithmetic sequences with a common difference of 2.

2.1/2, 5/8, 3/4, 13/16... is not an arithmetic sequences.

What is mean by arithmetic sequence?

An arithmetic sequence is a list of numbers with a definite pattern. If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence.

The constant difference in all pairs of consecutive or successive numbers in a sequence is called the common difference, denoted by the letter d.

We use the common difference to go from one term to another.

Take the current term and add the common difference to get to the next term, and so on. That is how the terms in the sequence are generated.

If the common difference between consecutive terms is positive, we say that the sequence is increasing.On the other hand, when the difference is negative we say that the sequence is decreasing.

The given sequence can only be an arithmetic sequences if they have same common difference

1.

2-0 = 2

0 - (-2) = 2

-2 -(-4) = 2

Thus, the given sequence is an arithmetic sequences with a common difference of 2.

2.

13/16-3/4 = 1/16

3/4 -5/8  = 1/8

5/8 - 1/2 = 1/8

Thus, the given sequence is not an arithmetic sequences.

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Complete question:

Arithmetic Sequences as Linear Functions.

Determine whether each sequence is an arithmetic sequence. Write yes or no.

1. -4, -2, 0, 2, ...

2. 1/2, 5/8, 3/4, 13/16 ...

Sal purchase b bowls fr $7.50 and paid $15 for shipping. The total cost of Sals purchase was $75. How many bowls did he buy?

Answers

Answer: 8

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

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