Urgent! I will mark you brainliest and rate you five stars for the correct answer! :)

Answer:

7

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of each other. For example, if line A has a slope of 2, then line B, perpendicular to line A, will have a slope of -0.5.

Answer:

Step-by-step explanation:  will u be my friend

Answer:

2^r=x

Step-by-step explanation:

Answer:

142 cm^2

Step-by-step explanation:

Okay, we can first break this down into 3 different rectangles.

3 x 5 rectangle

16 x 7 rectangle

3 x 5 rectangle.

From here, we just multiply these out and add them. 15 + 15 + 112 = 142. So our answer is 142 cm^2  

Answer:

142 cm²

Explanation:

to find the surface area, you need to find the area of all of the boxes within the image above add them all together.

Starting in the middle row and working from left to right it is,

7×3+7×5+7×3+7×5

21+35+21+35=112

Than the bottom and top box is

3×5+5×3

15+15=30

Than you add both of them together,

112+30=142

In the test score of Mr. Singh student, the measure of mean best represent the test data. The value of mean and median is 69.5 and 89.5 respectively.

The mean of the data is the average value of the given data. The mean of the data is the ratio of sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Test score of Mr. Singh's student are,

Scores: 89, 99, 80, 5, 90, 0, 100, 95

\(\overline X=\dfrac{89+99+80+5+90+0+100+95}{6}\\\overline X=69.75\)

Thus the mean of the test score is 69.75.

Arrange the test score in ascending order as,

Score; 0,  5, 80, 89, 90, 95,  99, 100

In the above arranged data, we have two middle values as, 89 and 90. Thus the median of the test score is,

\(m=\dfrac{89+90}{2}\\m=89.5\)

Thus the median of the test score is 89.5.

The data is not skewed for the test score. Thus the mean value of center tenancy represent best the test data.

Thus, In the test score of Mr. Singh student, the measure of mean best represent the test data. The value of mean and median is 69.5 and 89.5 respectively.

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Answer:

The Median should be 89.5

And the mean should be 69.75

Step-by-step explanation:

I hope that helped

in order for the solution to be defined for all t, we must have: y₀ - 3 = 0 or y₀ = 3. This means that there is only one value of y₀ for which the solution is defined for all t, namely y₀ = 3.

To solve the initial value problem (t – 1)y' + y = t² – t, y(0) = y₀, we first need to find the integrating factor:

μ(t) = e^∫(t-1) dt = e^(t-t²/2)

Multiplying both sides of the differential equation by the integrating factor, we get:

e^(t-t²/2)(t-1)y' + e^(t-t²/2)y = e^(t-t²/2)(t²-t)

Applying the product rule to the left-hand side and simplifying, we get:

(d/dt)(e^(t-t²/2)y) = e^(t-t²/2)(t²-t)

Integrating both sides with respect to t, we get:

e^(t-t²/2)y = ∫e^(t-t²/2)(t²-t) dt + C

We can evaluate the integral on the right-hand side using integration by parts, letting u = t^2-t and dv = e^(t-t²/2) dt. This gives us:

e^(t-t²/2)y = (t-1)e^(t-t²/2) - ∫(2t-1)e^(t-t²/2) dt + C

We can again evaluate the integral on the right-hand side using integration by parts, letting u = 2t-1 and dv = e^(t-t²/2) dt. This gives us:

e^(t-t²/2)y = (t-1)e^(t-t²/2) - (2t-1)e^(t-t²/2) + 2∫e^(t-t²/2) dt + C

Simplifying, we get:

e^(t-t²/2)y = (1-t)e^(t-t²/2) + 2e^(t-t²/2) + C

Dividing both sides by e^(t-t²/2) and solving for y, we get:

y = 1-t + 2e^(t²/2-t) + Ce^(-t+t²/2)

Using the initial condition y(0) = y₀, we can find the value of the constant C:

y₀ = 1 + 2 + C

C = y₀ - 3

Substituting this value of C back into the solution, we get:

y = 1-t + 2e^(t²/2-t) + (y₀ - 3)e^(-t+t²/2)

To show that there is only one value of y₀ for which the solution is defined for all t, we need to consider the behavior of the second and third terms in the solution:

2e^(t²/2-t) and (y₀ - 3)e^(-t+t²/2)

For the second term, we can see that as t becomes large, the exponential term e^(t²/2-t) grows faster than any polynomial, and the term 2e^(t²/2-t) approaches infinity.

For the third term, we can see that as t becomes large, the exponential term e^(-t+t²/2) approaches 0, and the term (y₀ - 3)e^(-t+t²/2) approaches 0.

Therefore, in order  for the solution to be defined for all t, we must have:

y₀ - 3 = 0 or y₀ = 3

This means that there is only one value of y₀ for which the solution is defined for all t, namely y₀ = 3

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The quadrilateral that has diagonals that always bisect its angles and also bisect each other is a (1) rhombus.

In a Rhombus, the diagonals are perpendicular bisectors of each other, and they bisect each other at their point of intersection, dividing the rhombus into four congruent triangles.

Each angle of a rhombus is = 180° divided by number of sides, so each angle of a rhombus is 90°.

In a rectangle, the diagonals bisect each other, but they do not necessarily bisect the angles of rectangle.

In a parallelogram, the diagonals bisect each other, but they do not necessarily bisect the angles of parallelogram.

In an isosceles trapezoid, the diagonals do not bisect each other.

Therefore, the correct answer is option (1) rhombus.

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The given question is incomplete, the complete question is

Which quadrilateral has diagonals that always bisect its angles and also bisect each other?

1) rhombus

2) rectangle

3) parallelogram

4) isosceles trapezoid.

Answer: D) g(x)= 2^1/2x -2

Step-by-step explanation:

The distance between two locations on the same line of latitude can be calculated by summing the total distance between the points in degrees and multiplying it by the statute miles per degree for the shared line of latitude.

To calculate the distance in miles between two locations on the same line of latitude, we first need to find the total distance between the points in degrees. In the case of location A, which is 60°N, 30°W, and location B, which is 60°N, 50°E, the total distance between the two points is 80 degrees (50°E - 30°W).

Next, we need to multiply the sum of the degrees by the statute miles per degree for the shared line of latitude. Since the line of latitude is 60°N, we need to determine the statute miles per degree at that latitude.

The Earth's circumference at the equator is approximately 24,901 miles, and since a circle is divided into 360 degrees, the distance per degree at the equator is approximately 69.17 miles (24,901 miles / 360 degrees).

Multiplying the total distance in degrees (80 degrees) by the statute miles per degree (69.17 miles), we find that the distance between the two locations is approximately 5,533.6 miles.

Similarly, for location C, which is 30°S, 60°W, and location D, which is 30°S, 90°E, the total distance between the points is 150 degrees (90°E - 60°W). Since the line of latitude is 30°S, we use the same statute miles per degree value (69.17 miles).

Multiplying the total distance in degrees (150 degrees) by the statute miles per degree (69.17 miles), we find that the distance between the two locations is approximately 10,375.5 miles.

Therefore, the distance between locations A and B is approximately 5,533.6 miles, and the distance between locations C and D is approximately 10,375.5 miles, when calculated using the given method.

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The median better describes the weight of a plain M&M because the distribution is likely to be skewed.

Explanation: When determining which measure of central tendency is better suited for describing the weight of a plain M&M, we consider the shape of the distribution. The median is generally preferred when the distribution is skewed.

In the case of the weight of plain M&M candies, it is likely that the distribution is not perfectly symmetric. There may be some variation in the weight, and it is possible that there are outliers or extreme values that could skew the distribution. Since the median is less affected by outliers or extreme values compared to the mean, it is a more appropriate measure of central tendency in this situation.

The median represents the middle value in a dataset when it is sorted in ascending or descending order. It divides the dataset into two equal halves. By using the median to describe the weight of plain M&Ms, we can obtain a central value that is less influenced by extreme values. This provides a more representative measure of the typical weight of an M&M in cases where the distribution is likely to be skewed.

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Answer:

a. 754cm³ (3 s.f.)

b. 415cm² (3 s.f.)

Step-by-step explanation:

Formulas (for easier reference):

Volume of cone: \(\pi\)r²\(\frac{h}{3}\)

Volume of hemisphere: \(\frac{2}{3}\)\(\pi\)r³

Surface area of cone without base: \(\pi\)rl

Surface area of hemisphere without base: 2\(\pi\)r²

We can just apply the formulas for the question:

Volume of toy = (\(\pi\) × 6² × \(\frac{8}{3}\)) + (\(\frac{2}{3}\) × \(\pi\) 6³)

                        = 96\(\pi\) + 144\(\pi\)

                        = 240\(\pi\)

                        = 754cm³ (3 s.f.)

Surface area of toy = (\(\pi\) × 6 × 10) + (2 × \(\pi\) × 6²)

                                = 60\(\pi\) + 72\(\pi\)

                                = 132\(\pi\)

                                = 415cm² (3 s.f.)

Answer:

d

Step-by-step explanation:

The time taken by a student to finish a statistics exam can be modeled using the following cumulative distribution function: F(x) = 1 - e^-0.9, x > 0

Suppose that the time taken for a student to finish the exam is constant from student to student.

Then the mean number (to the nearest whole number) of students who will finish the exam in less than 1 hour for 12 students randomly selected is 7

.Step-by-step explanation:

The cumulative distribution function is given by, F(x) = 1 - e^-0.9, x > 0

Now, let X be the time taken by a student to finish the statistics exam

Then, X ~ Exp (0.9 )

We know that the cumulative distribution function (CDF) of the exponential distribution with parameter λ is given by,F(x) = P(X ≤ x) = 1 - e^(-λx) , x > 0Here, λ = 0.9.

Therefore, the CDF of X is given by,F(x) = P(X ≤ x) = 1 - e^(-0.9x) , x > 0

The probability that a student finishes the exam in less than 1 hour is, P(X ≤ 1) = F(1) = 1 - e^(-0.9) ≈ 0.5271

This means that out of 12 students randomly selected,

The expected number of students who finish the exam in less than 1 hour is,μ = np= 12 × 0.5271≈ 6.3252

Hence, the mean number (to the nearest whole number) of students who will finish the exam in less than 1 hour for 12 students randomly selected is 7.

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Answer:

7/12, 7/10, 5/6

Step-by-step explanation:

Answer:

7/12, 5/6, 7/10

Step-by-step explanation:

Just change it to decimal point it will be easier

Answer:

(-4,1)

Step-by-step explanation:

Factoring, Guess and check.

Multiply the numerator by numberator and denominator by denominator.

a/b multiplied by c/d is ac / bd.

Answer:

Multiply the top numbers

Multiply the bottom numbers

Simplify if needed

Example:

4/5×6/8= 24/40=3/5

Answer:

Line kinda flat, going up (from left to right) goes right through the 3 on the y-axis. Through the points (0,3) and (5,5) The third image.

Step-by-step explanation:

The slope of 2/5 means go UP2 and OVER5. Only one graph has a line the goes UP2 and OVER5.

One line actually goes down (from left to right), that has a negative slope. So that's not it.

The first image is positive slope, but if you look at the two points, you go UP5 and OVER2 so that is wrong also. That is the slope 5/2.

The last image has slope 2/7, bc you go UP2 OVER7 to get from one point to the next. It is wrong also.

Only the third image, Line kinda flat, going up (from left to right) goes right through the 3 on the y-axis. Through the points (0,3) and (5,5) has a slope of 2/5

Q=4P

Step-by-step explanation:

4=4(1)

32=4(8)

60=4(15)

Step-by-step explanation:

Angle M = Angle R

47x - 17 = 32x + 28

15x = 45

x = 3

Angle M = 47(3) - 17 = 124°

Angle R = Angle M = 124°

Angle Q = 180 - Angle M = 56°

Angle N = Angle Q = 56°

Answer:

\(The\) \(answer\) \(is\) \(B\) = Both the mean and median will increase, but the mean will increase by more than the median

- written in \(2/5/2021\)

a. The probability of drawing a red ball from Box 1 is 30%.

b. If a red ball is drawn from Box 1, the probability of drawing another red ball from Box 2 on the second round is 60%.

c. If the first draw from Box 1 was black, the conditional probability of drawing a red ball from Box 3 on the second draw is 80%.

d. The probability of drawing two red balls at both draws, without any prior information, is 46%.

e. The probability of drawing a red ball at the first draw and a black ball at the second draw, without any prior information, is 21%.

a. The probability of drawing a red ball from Box 1 can be calculated by dividing the number of red balls in Box 1 by the total number of balls in Box 1. Therefore, the probability is 3/(3+7) = 3/10 = 0.3 or 30%.

b. Since a red ball was drawn from Box 1, we only consider the balls in Box 2. The probability of drawing a red ball from Box 2 is 6/(6+4) = 6/10 = 0.6 or 60%. Therefore, the probability of drawing another red ball when the first ball drawn from Box 1 is red is 60%.

c. If the first draw from Box 1 was black, we only consider the balls in Box 3. The probability of drawing a red ball from Box 3 is 8/(8+2) = 8/10 = 0.8 or 80%. Therefore, the conditional probability of drawing a red ball from Box 3 when the first ball drawn from Box 1 was black is 80%.

d. Before any draws, the probability of drawing two red balls at both draws can be calculated by multiplying the probabilities of drawing a red ball from Box 1 and a red ball from Box 2. Therefore, the probability is 0.3 * 0.6 = 0.18 or 18%. However, since there are two possible scenarios (drawing red balls from Box 1 and Box 2, or drawing red balls from Box 2 and Box 1), we double the probability to obtain 36%. Adding the individual probabilities of each scenario gives a total probability of 36% + 10% = 46%.

e. Before any draws, the probability of drawing a red ball at the first draw and a black ball at the second draw can be calculated by multiplying the probability of drawing a red ball from Box 1 and the probability of drawing a black ball from Box 2 or Box 3. The probability of drawing a red ball from Box 1 is 0.3, and the probability of drawing a black ball from Box 2 or Box 3 is (7/10) + (2/10) = 0.9. Therefore, the probability is 0.3 * 0.9 = 0.27 or 27%. However, since there are two possible scenarios (drawing a red ball from Box 1 and a black ball from Box 2 or drawing a red ball from Box 1 and a black ball from Box 3), we double the probability to obtain 54%. Adding the individual probabilities of each scenario gives a total probability of 54% + 10% = 64%.

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Answer:

28$ games and 45$ for rides so 73$

Step-by-step explanation:

Answer:

he would pay $73.40 for 8 games and 10 rides

Step-by-step explanation:

multiply 3.50 by 8 since it costs him 3.50 per each ride. when calculated u get 28.40.then when calculated multiply 4.50 by ten since that is how much each ride costs. the total should be 45.00. now add 28.40 to 45.00 to get ur answer

The net pay amount for January would be $86,761.

Given the following information: Gross earnings in Vaughn Company were $114,000. All earnings are subject to 7.65% FICA taxes. Federal income tax withheld was $16,500, and state income tax withheld was $2,000.To calculate the net pay for January, first, we have to calculate the deductions:Gross earnings are:$114,000The FICA taxes for the earnings will be:7.65% of $114,000 = 0.0765 × $114,000 = $8,739State income tax withheld was $2,000Federal income tax withheld was $16,500Deductions are: 8,739 + 2,000 + 16,500 = $27,239The net pay amount for January would be:$114,000 - $27,239 = $86,761Answer: $86,761.

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\(\huge\text{Hey there!}\)

\(\large\textsf{b - 6a}\\\large\textsf{= \boxed{\textsf{44}} - 6\boxed{\textsf{(3)}}}\\\large\textsf{= 44 - 18}\\\large\textsf{= 26}\\\\\\\huge\boxed{\text{Therefore, your answer: \boxed{\textsf{26}}}}\huge\checkmark\\\\\\\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\\\frak{Amphitrite1040:)}\)

Conclusion: The speed of the cyclist is 11 km/hr and the speed of the walker is 3 km/hr.

The speed of the cyclist is 11 km/hr and the speed of the walker is 3 km/hr.
To calculate the speed of the cyclist and the speed of the walker,

we need to use the formula for speed, which is distance divided by time.
The cyclist travels 8 km in the same time that the walker travels 3 km, so the time taken is the same for both. Let's call this time t.

The speed of the cyclist is 8 km/t and the speed of the walker is 3 km/t. To find the speed of the cyclist, we need to add 8 km to the speed of the walker.

Therefore, the speed of the cyclist is 11 km/hr and the speed of the walker is 3 km/hr.
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2)0000==============]

The quadratic equation exists \($x^{2}+3 x+2=0$\).

If a quadratic equation exists \($a x^{2}+b x+c=0$\), the utilizing the quadratic equation the solutions for x will be given by

\($x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$$\)

The solution for x exists

\($x=\frac{-3 \pm \sqrt{3^{2}-4(1)(2)}}{2(1)}\)

Comparing equations (1) and (2) we get, a = 1, b = 3 and c = 2.

Therefore, the quadratic equation exists \($x^{2}+3 x+2=0$\).

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Answer:

One guy said it was B. but I'm going with A.

Step-by-step explanation:

Ramiya is using the quadratic formula to solve a quadratic equation. her equation is x = startfraction negative 3 plus or minus startroot 3 squared minus 4(1)(2) endroot over 2(1) endfraction after substituting the values of a, b, and c into the formula. which is ramiya’s quadratic equation?

Answer:

3 degrees

Step-by-step explanation:

(5/10)*6

3

Answer:

7.8

Step-by-step explanation: