Under what situation can an object experience multiple forces, but yet experience no acceleration
a
An object can experience multiple forces, so long as the net force is zero
b
An object can experience multiple forces, so long as they all act in the same direction
c
An object can experience multiple forces, so long as the mass is proportional
d
An object can experience multiple forces, so long as they are all the same type of force

1. The speed (in m/min) of diffusion of onion molecules in air is 16.14 m/min

2. The speed (in m/s) of diffusion of onion molecules in air is 0.27 m/s

Speed is simply defined as the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

With the above formula, we can obtain the speed of the diffuse molecules. Details below

Speed = distance / time

Speed = 22.6 / 1.40

Speed = 16.14 m/min

Speed = distance / time

Speed = 22.6 / 84

Speed = 0.27 m/s

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Answer:

The adapted expression for average acceleration is \(a = \frac{v}{t'}\).

Explanation:

Let be \(v = v_{o} + a\cdot t\), which can be adapted by using the following substitution:

\(t = t'-t_{o}\)

Where:

\(t'\) - Final instant, measured in seconds.

\(t_{o}\) - Initial instant, measured in seconds.

\(v = v_{o}+a\cdot (t-t_{o})\)

Where:

\(v\) - Final velocity, measured in meters per second.

\(v_{o}\) - Initial velocity, measured in meters per second.

\(a\) - Average acceleration, measured in meters per square second.

Now, average acceleration is cleared:

\(a = \frac{v-v_{o}}{t'-t_{o}}\)

Given that \(t_{o} = 0\,s\) and \(v_{o} = 0\,\frac{m}{s}\), then:

\(a = \frac{v}{t'}\)

Answer:

a = (v-v0)      

     ____      where v = final velocity, v0

         t

Explanation:

Using algebra, , where v = final velocity, v0 = initial velocity, and t = time. So,

= -9.3 m/s2.

Answer:

A physical property is any property that is measurable, whose value describes a state of a physical system.

Explanation:

How this helps.

the temporary change in which only physical properties like shape,size,colour are changed is called physical properties

The magnetic field strength at a point 2.2 mm radially from the center of the wire leading to the capacitor is approximately 27.27 µT.

To calculate the magnetic field strength at a point 2.2 mm radially from the center of the wire leading to the capacitor, we can use Ampère's Law. The current (I) is 15 A, and the distance (r) from the center of the wire is 2.2 mm or 0.0022 m. Ampère's Law states that the magnetic field (B) around a current-carrying wire is given by:
B = (μ₀ * I) / (2 * π * r),
where μ₀ is the permeability of free space, which is approximately 4π x 10⁻⁷ Tm/A.
Plugging in the values, we get:
B = (4π x 10⁻⁷ Tm/A * 15 A) / (2 * π * 0.0022 m).
Simplifying the expression:
B ≈ (60 x 10⁻⁷ Tm) / 0.0022 m = 27.27 x 10⁻⁶ T.
Please note that this calculation assumes an idealized situation with an infinitely long, straight wire carrying the current to the 1.2 cm-diameter parallel-plate capacitor.

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It is usually best to reduce speed to suggested limit when  a driver gets to a speed hump and is denoted as option D.

This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.

Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.

Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.

This therefore the reason why reducing speed to suggested limit is the most appropriate choice.

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Answer:

trust the process

Explanation:

quadratic formula, use synthetic division also use the p-q method for the roots and factoring.

Answer:

Explanation:

F = ma and

\(a=\frac{v}{t}\)

We have F, we have m, but in order to solve for v, we need a.

30.0 = 3.00a so

a = 10.0 m/s/s. Plug that in for a in the second equation and solve for v:

\(10.0=\frac{v}{3.00}\) so

v = 10.0(3.00) so

v = 30.0 m/s

Answer:

Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. A rocket engine produces thrust through action and reaction. The engine produces hot exhaust gases which flow out of the back of the engine. In reaction, a thrusting force is produced in the opposite reaction.

Answer:

I think its A

Explanation:

if its every 3 seconds wouldnt it be 3.0 Hz

The generalization that can be made about the relative speeds that the sun and the stars move through the sky over the course of a day is that the sun appears to move much slower than the stars. This is because the sun is much closer to Earth than the stars, so its movement is more noticeable.

The stars, on the other hand, are much farther away and their movement is less noticeable.

Another way to think about this is to consider the fact that the Earth is rotating on its axis. As the Earth rotates, the sun appears to move across the sky at a relatively slow speed because it is close to Earth. The stars, however, are much farther away and their movement is not as noticeable. This is why the stars appear to move much faster than the sun over the course of a day.

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B - Broken cable to the anodes. If the cable to the anodes is broken, there would be no current flow through the anodes, resulting in a zero current output.

However, the impressed current system would still be generating the normal DC voltage. The other options would cause a disruption in the system's ability to generate the normal DC voltage and would not result in a zero current output. The explanation:  1. A faulty transformer would result in no DC voltage output, so it's not the correct answer. 2. A broken cable to the anodes would lead to a normal DC voltage but zero (0) current output because the circuit is interrupted, making this the correct answer. 3. No AC supply would mean no power to the system, so both voltage and current would be zero (0), which doesn't match the question's requirements. 4. Faulty rectifying elements would typically result in irregular or no DC voltage output, so this option is not correct either.

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Answer:

Direction

Explanation: Hope this helps!

Answer:

nvm its direction :))

Explanation:

Speed and velocity both represent a way to measure the change in position of an object relative to time. In fact, for a straight line motion, the speed and velocity of an object are the same (since distance and displacement will be the same). Speed and velocity are measured in the same units: meters per second or m/s.

Velocity is a measure of both speed and direction of motion. Velocity is a vector, which is a measurement that includes both size and direction. Velocity can be represented by an arrow, with the length of the arrow representing speed and the way the arrow points representing direction.

Answer:

true they can no longer be contained

 Here  the answer = 0.0080 .

Based on stokes law,

 v = g * D^2 *(d p - d m) / (18 V)

v = terminal velocity

D =  diameter of particle

V  =  Viscosity

dp =  density of particle

dm =  density of medium.

Here density of ball = 1.42 gm/cc

By substituting,

v = 9.81 x 9.52 x 10^-3 ^2 (1420 - 1300) / 18 x 1.0

=5.92x10^-4

 v(t) =0 .99 x Vtrm

  =0 .99 x  0.0059

  = 0.00059 m/s

  v(t)/Vterm =1-e^(-t/r)

  0.99 = 1 - e ^ (-t / 9.52 x 10^-3)

  e ^ (-t / 9.52 x 10^-3) = 0.01

Taking log

 -t / 9.52 x 10^-3 = -4.6

  t = 0.0438 s

Then smaller ball

v = 9.81 x 2.38 x 10^-3 ^2 (1420 - 1300) / 18 x 1.0

= 0.000037 m/s

v(t) / Vterm = 1-e^(-t/r)

0.99 = 1 - e ^ (-t / 2.38 x 10^-3)

e ^ (-t / 2.38 x 10^-3) = 0.01

Taking log

-t / 2.38 x 10^-3 = -4.6

  t = 0.0109 s

Here Reynolds number is,

R= rho vd / mu

= 1420 x  0.00059 x 9.52 x 10^-3 x / 1.0

= 0.0080

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Alpha and beta rays are deflected in opposite directions in a magnetic field because they have opposite charges.

Alpha particles are positively charged while beta particles are negatively charged. When they enter a magnetic field, they experience a force that is perpendicular to their direction of motion and to the direction of the magnetic field. The direction of this force depends on the charge of the particle. Since alpha and beta particles have opposite charges, they experience opposite forces and are deflected in opposite directions.

The magnitude of the force also depends on the velocity of the particle, which is why particles with different energies will be deflected differently. This property of magnetic fields is used in many applications, including in particle accelerators and in medical imaging techniques such as magnetic resonance imaging (MRI). The other options listed in the question are not correct, as the direction of the magnetic force does not depend on the spin of the particle or on the presence of nucleons.

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Overcast and ominous sky windy conditions and a lot of rain. along the shore, large waves. storm swells are some of the weather changes before typhoon.

Tropical cyclones, often known as hurricanes or typhoons, are powerful circular storms that form over warm tropical waters and are distinguished by low air pressure, strong winds, and torrential rain.

Storm precursors start to show up. The ocean surf is around 4m (13 feet) in height and is coming in 7 seconds apart. The barometer is dipping slightly, the wind is blowing at 18–20 kmph. Large, white cirrus clouds may be seen gathering over the horizon. The horizon is gradually being engulfed by the approaching cloud cover.

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Answer:

option 3 potential chemical energy

To find the slope of the position-time relationship for the bowling ball using the "rise over run" algorithm, you'll first need the coordinates obtained in part b. The slope represents the rate of change of position with respect to time, and in this context, it is equal to the ball's velocity.

Using the "rise over run" algorithm, the slope (velocity) can be calculated by dividing the change in position (rise) by the change in time (run). In this case, the coordinates represent the position and time values, with the first coordinate being the initial position and time, and the second coordinate being the final position and time.

Assuming you have two coordinates (x1, y1) and (x2, y2), where x values represent time and y values represent position:

Slope = (y2 - y1) / (x2 - x1)

Once you have the coordinates from part b, plug the values into the formula above to calculate the slope. This will give you the velocity of the bowling ball, which represents the relationship between the position and time for the given motion.

For example, if the coordinates from part b are (0.4 s, 2.5 m) and (0.8 s, 5 m), the slope would be:

Slope = (5 m - 2.5 m) / (0.8 s - 0.4 s) = 2.5 m / 0.4 s = 6.25 m/s

In this example, the slope (velocity) of the position-time relationship for the bowling ball is 6.25 m/s.

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Answer:

v = 17.30 m / s

Explanation:

For this exercise we will use Newton's second law

at the bottom of the loop and stopped

           ∑ F = 0

           N-W = 0

           N = W

            W = 770 N

the mass of the body is

            W = mg

             m = W / g

            m = 770 / 9.8

            m = 78.6 kg

on top of the loop and moving

           ∑ F = m a

           N + W = m a

note that the three vectors go in the same vertical direction down

the centripetal acceleration is

           a = v² / r

we substitute

           N + W = m v² / r

           v = \(\sqrt{(N+W) \frac{r}{m} }\)

let's calculate

          v = \(\sqrt{ (350+770) \frac{21}{78.6} }\)

          v = 17.30 m / s

We will have the following:

1. 143 g = 0.143 kg:

2. 110 g = 0.110 kg:

3. 410 g = 0.410 kg:

4. 46 g = 0.046 kg:

From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.

a) The isocost curve equation is G = (20000 - 100C)/500. b) The isocost curve equation is G = (30000 - 100c)/500. c) The isocost curve equation is G = (20000 - 100C)/375. d)  The isocost curve equation is G = (20000 - 120C)/500.

To draw the isocost curve showing the different combinations of gas and coal, we need to use the cost per unit values for coal and gas, as well as the given expenditure (TC) and the changes in expenditure or prices.

Let's denote the quantity of coal as C and the quantity of gas as G. The cost per unit of coal is 100, and the cost per unit of gas is 500.

(a) Initial expenditure (TC) of 20000:

To find the combinations of gas and coal that can be purchased with an initial expenditure of 20000, we can use the following isocost equation

TC = 100C + 500G

We can rearrange the equation to solve for G in terms of C

G = (TC - 100C) / 500

Now we can plot the isocost curve with TC = 20000 using the equation above.

(b) Expenditure (TC) increases by 50%

If the expenditure increases by 50%, the new expenditure (TC_new) becomes 1.5 × TC = 1.5 × 20000 = 30000.

We can use the same isocost equation as before, but with the new expenditure value:

TC_new = 100C + 500G

Rearranging the equation to solve for G

G = (TC_new - 100C) / 500

Now we can plot the isocost curve with TC_new = 30000.

(c) Gas price reduced by 25%:

If the gas price is reduced by 25%, the new cost per unit of gas (Gas_new) becomes 0.75 × 500 = 375.

We can use the original isocost equation, but with the new cost per unit value:

TC = 100C + 375G

Rearranging the equation to solve for G

G = (TC - 100C) / 375

Now we can plot the isocost curve with the reduced gas price.

(d) Coal price rises by 20%

If the coal price rises by 20%, the new cost per unit of coal (Coal_new) becomes 1.2 × 100 = 120.

We can use the original isocost equation, but with the new cost per unit value:

TC = 120C + 500G

Rearranging the equation to solve for G:

G = (TC - 120C) / 500

Now we can plot the isocost curve with the increased coal price.

By plotting these isocost curves on a graph with G on the y-axis and C on the x-axis, we can visualize the different combinations of gas and coal that can be purchased at the given expenditures or price changes.

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Answer:

We show added energy to a system as +Q or -W

Explanation:

The first law of thermodynamics states that, in an isolated system, energy can neither be created nor be destroyed;

Energy is added to the internal energy of a system as either work energy or heat energy as follows;

ΔU = Q - W

Therefore, when energy is added as heat energy to a system, we show the energy as positive Q (+Q), when energy is added to the system in the form of work, we show the energy as minus W (-W).

A company has developed a new material for making optical fibre. The critical angle of this material is much greater than that of glass, Lucite, or any other material currently being used. This product cannot be successful because optical fibres should have a small critical angle.

A small critical angle implies that the total internal reflection can take place easily.

A flexible, transparent fiber composed of plastic or glass transmits light pulses from one end of an optical fiber to the other. High-speed and long-distance services are both possible with a fiber optic network.Typical applications for fiber optic lines in telecommunications include the Internet, telephone, and television. Many of the benefits of fiber optic connections cannot be found in copper lines. The cables have a larger bandwidth and transport data much more swiftly.An optical fiber has several glass components, which might number anywhere from a few to several hundred. A glass covering known as the cladding surrounds the glass fiber core in this instance's fiber cable.

Critical angle is that angle of incidence for which the angle of refraction is 90 degrees.

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Answer:

My believe the answer is

A.) or B.)

Explanation:

Here is why I think A is the answer.

If we use the process of elimination, it would look like this,

a) Porque el aire tiene una temperatura menor que la de su cuerpo; por eso se propaga más rápido.

This makes sense because we all know in winter the weather is very cold and freezing.

b) Porque la temperatura de su cuerpo, siente el aire frio que entra por la ventana.

I feel like this answer is the question, but it could also be an answer, sorry, I'm a little uncertain.

c) Porque el calor de su cuerpo se propaga al medio ambiente, al ser la temperatura del niño mayor que la del aire exterior.

This answer has nothing to do with the question, plus it is very false, our body heat is not enough to overcome the very cold temperature from outside.

d) Porque la temperatura del aire es igual a la temperatura del cuerpo.

This is false because again our body heat is not even compared to the freezing cold temperatures from the winter.

Answer:

If the resistors are in series then each resistor

carries the "same current" - the first option

The water speed in each pipe is approximately 0.023 m/s.

We can use the continuity equation to determine the water speed in each pipe:

A₁v₁ = A₂v₂

where A₁ and A₂ are the cross-sectional areas of the two pipes, and v1 and v₂ are the water speeds in each pipe.

Assuming that the pipes are circular, the cross-sectional area of each pipe can be calculated using the formula for the area of a circle:

A = π\(r^2\)

where r is the radius of the pipe. Since the diameter of each pipe is 3.3 m, the radius is 1.65 m.

Therefore, the cross-sectional area of each pipe is:

A = π\(r^2\) = π(1.65 m\()^2\) = 8.56 \(m^2\)

Now, let's assume that the total water flow rate is Q = 800 L/s. This means that each pipe carries half of the total flow rate, or Q/2 = 400 L/s.

To convert the flow rate from liters per second to cubic meters per second, we divide by 1000:

Q = 0.8 \(m^3\)/s

Using the continuity equation, we can solve for the water speed in each pipe:

A₁v₁ = A₂v₂

8.56 \(m^2\) × v = 8.56 \(m^2\) × v₂

v₁ = v₂

Q/2A₁  = Q/2A₂

v₁ = v₂ = Q/2A₁= Q/2A₂

v₁ = v2 = (0.8 \(m^3/s\)) / (2 × 8.56\(m^2)\)

v₁ = v2 = 0.023 m/s

Therefore, the water speed in each pipe is approximately 0.023 m/s.

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Answer:

The workdone by the Frictional force is 10. 26 Joules.

Explanation:

Parameters: Frictional force = 3.8 N

Distance = 2.7m

Workdone = ? Joules

Workdone = Frictional force × Distance travelled

= 3. 8 × 2. 7

= 10.26 Joules.

The workdone by the frictional force when brought to rest after travelling a distance of 2. 7m is 10. 26 Joules.

The 3.00 kg particle needs to be placed at coordinates

(-0.330 m, -0.950 m) to achieve the desired center of mass.

The coordinates for placing the 3.00 kg particle to achieve the desired center of mass are (-0.330 m, -0.950 m).The center of mass of a system of particles is determined by the distribution of mass and their respective positions. The center of mass coordinates can be calculated using the formula:

\(x_c_m\) = (\(m\)₁\(x\)₁ + \(m\)₂\(x\)₂ + \(m\)₃\(x\)₃) / (\(m\)₁ + \(m\)₂ +\(m\)₃)

\(y_c_m\) = (\(m\)₁\(y\)₁ + \(m\)₂\(y\)₂ + \(m\)₃\(y\)₃) /(\(m\)₁ + \(m\)₂ +\(m\)₃)

By substituting the given values and solving the equations, the required coordinates for the 3.00 kg particle can be determined. Placing the particle at (-0.330 m, -0.950 m) will ensure that the center of mass of the three-particle system matches the specified coordinates.

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