Un autobús en una autopista lleva una magnitud de la velocidad de 95 km/h, el conductor observa que debido a un derrumbe la carretera está cerrada, en ese instante acciona los frenos, deteniendo el autobús después de recorrer 60 m. a) ¿Cuál es el valor de la aceleración en el autobús?

Answers

Answer 1

Answer:

La aceleración del autobús es -5.80 m/s².

Explanation:

Podemos encontrar la aceleración del autobús usando la siguiente ecuación:

\( v_{f}^{2} = v_{0}^{2} + 2ad \)

Where:

\(v_{f}\): es la velocidad final = 0 (se detiene al final)

\(v_{0}\): es la velocidad inicial = 95 km/h

d: es la distancia recorrida = 60 m

Por lo tanto, la aceleración es:

\( a = \frac{v_{f}^{2} - v_{0}^{2}}{2d} = \frac{0 - (95 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2*60 m} = -5.80 m/s^{2} \)

El signo negativo se debe a que el autobús está desacelerando (hasta que se detiene).

Entonces, la aceleración del autobús es -5.80 m/s².

Espero que te sea de utilidad!                      


Related Questions

If your mass is 72 kg, your textbook's mass is 3.7 kg, and you and your
textbook are separated by a distance of 0.33 m, what is the gravitational
force between you and your textbook? Newton's law of gravitation is
Gm;m2 The gravitational constant G is 6.67 x 10-11 N·m2/kg2.
F gravity
O A. 4.94 x 10-7N
B. 2.45 x 103 N
O C. 5.38 x 10-8N
O D. 1.63 x 10-7N

Answers

Answer:

The answer is 1.63 x 10 -7 N

Explanation:

An appropriate solution is 1.63 x 10 -7 N

Gravitational pressure method: F=G{frac{m_1m_2}{r^2}}

Newton's law of gravitation is Gm;m2

The gravitational regular G is 6.67 x 10-11 N·m2/kg2.

What is gravitational pressure?

Definitions of gravitational pressure. The force of attraction among all masses inside the universe; especially the appeal of the earth's mass for bodies close to its floor.

What law is Newton's regulation of gravitation?

Newton's regulation of typical gravitation states that two bodies in an area pull on every other with a force proportional to their hundreds and the space among them. For large objects orbiting each other—the moon and Earth, for instance—means they without a doubt exert important force on each other.

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A block of cheese is pulled on by a string and remains at rest.
What is the correct free body diagram for the block of cheese?
Choose 1 answer:

Answers

Answer:

Explanation:

- The friction acts leftwards to balance the tension that must be pulling up and to the right.

- The force of gravity is straight down.

- The normal force is perpendicular to the contact surface.

A block of cheese is pulled on by a string and remains at rest.What is the correct free body diagram

The force of gravity is straight down.

What is force of gravity?

On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them.

Gravity is measured by the acceleration that it gives to freely falling objects.

According to the question,

A block of cheese is pulled on by a string and remains at rest until we will not apply an external force.

It also posses force of gravity.

The friction acts leftwards to balance the tension that must be pulling     up and to the right.

The force of gravity is straight down.

The normal force is perpendicular to the contact surface.

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A block of cheese is pulled on by a string and remains at rest.What is the correct free body diagram

An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before
takeoff?
A. 1.6 x 103 meters
B. 1.7 x 103 meters
C. 3.1 x 103 meters
D. 3.3 x 103 meters

Answers

Answer:

A

Explanation:

d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m  ~ 1.6 x 10^3

Which of these units is most appropriate to use when measuring the mass of a person?

Answers

The SI unit of mass is the kilogram

light Incident on air / Glass boundary If the Incident angle IS 42°the Index of refraction of the glass 1.5 what the Refracted angle

Answers

Given

The incident angle is

\(i=42^o\)

The index of refraction is n=1.5

To find

The angle of refraction

Explanation

We know,

\(\begin{gathered} n=\frac{sini}{sinr} \\ \Rightarrow1.5=\frac{sin42^0}{sinr} \\ \Rightarrow sinr=\frac{sin42^o}{1.5} \\ \Rightarrow sinr=0.44 \\ \Rightarrow r=26.10^o \end{gathered}\)

Conclusion

The angle of refraction is 26.10 deg

Consider a system of two charges of magnitude 2 × 10-7 C and 4.5 × 10-7 C which is acted upon by a force of 0.1 N. What is the distance between the two charges?

Answers

To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = (k * |q1| * |q2|) / r^2

where:

F is the force between the charges,

k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),

|q1| and |q2| are the magnitudes of the charges, and

r is the distance between the charges.

Given:

|q1| = 2 × 10^-7 C

|q2| = 4.5 × 10^-7 C

F = 0.1 N

k = 8.99 × 10^9 N m^2/C^2

We can rearrange the equation to solve for r:

r^2 = (k * |q1| * |q2|) / F

Plugging in the values:

r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N

r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1

r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1

r^2 = 80.91 * 10^(-7 + 9 - 1)

r^2 = 80.91 * 10^1

r^2 = 809.1

Taking the square root of both sides:

r = √809.1

r ≈ 28.46

Therefore, the distance between the two charges is approximately 28.46 units.

can someone help with the vocabulary of the relative age of rocks

can someone help with the vocabulary of the relative age of rocks

Answers

I don’t think this is physics but I’ll help you out , ok well this is just basic vocab so your answers will be

5.b
6.h
7.g
8.e
9.c
10.d
11.a
12.f

what is diffrence between damping and undamping?​

Answers

Answer:

Oscillation whose amplitude reduce with time are called damped oscillation. This happen because of the friction. In oscillation if its amplitude doesn't change with time then they are called Undamped oscillation

Damped and undamped vibration refer to two different types of vibrations. The main difference between damped and undamped vibration is that undamped vibration refer to vibrations where energy of the vibrating object does not get dissipated to surroundings over time, whereas damped vibration refers to vibrations where the vibrating object loses its energy to the surroundings.

A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?

Answers

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

What is Speed ?

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

h = 52 mu = 0Range R = 35 mg = 9.8 m/s²

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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Suppose that you drop a 10 Kg object from a table and gains a kineticenergy of 100 J right before it hits that ground. How high was the table?Use g = 10 m/s2

Answers

KE when it hits the ground = PE before it's dropped

PE = mgh

KE = mv^2/2 = 100J

100 J = mgh

100 = 10*10*h

h = 100/100

h = 1 m

why did you test the resistance of the wire

Answers

Answer:

What????

Explanation:

is there more to the problem???


What is the mass of a truck if it produces a force of 13,607 N while accelerating at a rate of 2.9 m/s²?

Answers

Newton's Second Law.

We have the following data, provided in the exercise:

Mass (m) = ?

Force (F) = 13607 N

Acceleration (a) = 2.9 m/s²

To calculate the mass, we solve the following formula:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}\)\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}\)

We substitute the data in the clear formula.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }\)

We break down the units of Newton = Kg * m/s².

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }\)

The mass of the truck is: 4692.07 Kilograms (Kg).

What is nature of light Definition
What is the sources of light
What is the behaviours of light
Reflection and refraction
Colours and light
Concave and convex mirrors
Please help fast
(25 points)

Answers

Answer:

1.Light is a transverse, electromagnetic wave that can be seen by the typical human.

2.The Sun is the major source of light for the earth.

3.An inclusive list of the basic categories of behavior for light would most likely include transmission, absorption, reflection, refraction, diffraction, scattering, polarization and interference.

4.Spherical mirrors contain curved surfaces which are painted on either one of the sides. When an inward surface of a spherical mirror is painted, then this type of mirror is considered a convex mirror. In the meantime, when the outward surface of the spherical mirror is painted, this mirror is called a concave mirror.

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A flat plate with surface area of 1.8 m2m2 is sliding on a horizontal table with 3.7 mmmm thick oil layer on top. Force applied on the plate in the direction of movement is 2.2 NN. Dynamic viscosity of the oil is 0.89 x10-³ Ns/m².​

Answers

The velocity gradient across the 3.7 mm thick oil layer on the flat plate sliding on the horizontal table is 0.594 m/s/m.

Given:

Surface area of the plate (A) = 1.8 m^2

Thickness of the oil layer (h) = 3.7 mm = 0.0037 m

Force applied on the plate (F) = 2.2 N

Dynamic viscosity of the oil (η) = 0.89 x 10^-3 Ns/m^2

To calculate the velocity gradient across the oil layer, we can use the equation:

τ = η * du/dy

where τ is the shear stress, η is the dynamic viscosity, and du/dy is the velocity gradient.

Since the force (F) applied on the plate is responsible for the shear stress, we can write:

τ = F / A

Substituting the given values, we have:

F / A = η * du/dy

Solving for du/dy, we get:

du/dy = (F / A) / η

Substituting the values, we have:

du/dy = (2.2 N) / (1.8 m^2 * 0.89 x 10^-3 Ns/m^2)

du/dy = 0.594 m/s/m

Therefore, the velocity gradient across the oil layer is 0.594 m/s/m.

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Kinetic energy is the enrgy that a moving object has because of its motion , true or false?

Answers

Answer:

the correct answer is true

Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wavelengths Radiation through the same region

Answers

Answer:

Unequal Wavelengths

Explanation:

Got it right on the exam

Unequal wavelengths limit interference between waves because the waves will have different frequencies and will not be able to form a stable interference pattern. When waves of different wavelengths interact, they will interfere constructively and destructively at different points, creating an unpredictable pattern.

Answer:

Unequal wavelengths

Explanation:

Got it correct on the quiz.

Demario's biology class has a quiz every other Friday. This is the third time Demario has been so worried about other personal matters that he hasn’t done quite as well on the quizzes as he might have otherwise. What has Demario upset is the fact that the professor leaves the room while the students take the quiz, and over half the class is taking the opportunity to cheat. Demario knows personally several of the other students in the class, and some of the ones Demario hangout with are among those who are cheating. Demario knows that a failure to speak to the professor about the cheating will result in his own grade being lower, since the school grades on the curve system. But if Demario does say something to the professor he will be doing his friends and the others a great harm, since cheating is taken very seriously at the school and can lead to expulsion. If Demario doesn’t “turn in” the classmates, the only other alternative is he will get a worse grade than he deserves. He will also be labled as a snitch among is peers and a cheater at the school, either of which Demario has never done. Further, if the professor somehow discovers that Demario is hiding the cheating of others, Demario will be considered an accessory to the cheating, and may be reprimanded for not turning others in, since the school operates on an honor system.

Critical thinking About Ethics Right vs Wrong

What should Demario do?
Should Demario cheat?
Should Demario turn in the cheating classmates?
Should Demario say nothing and not cheat himself?
Be specific in your answer about exactly what Demario should do. (Remember to use one of the three moral theories to solve this dilemma.)

Answers

1. It is unethical for Demario to cheat

2. Demario should not engage in cheating himself

3. Demario should not turn in cheating classmates without careful consideration

4. Reporting classmates may harm relationships, create animosity, and potentially lead to severe disciplinary actions.

What is ethics?

A virtue ethics perspective may also be useful in this circumstance. Demario should make an effort to respect moral principles like honesty, fairness, and integrity while taking the potential repercussions into account and exhibiting empathy for his fellow students.

By employing this strategy, Demario behaves responsibly, deals with the problem subtly, encourages fairness in the educational setting, and upholds his or her own moral standards.

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if lens behave like prism and disperse light then why person using glass on eye can't see colour being dispersed?​

Answers

Answer:

A prism can disperse light into different colors when the light enters the prism at a "fixed" angle - light coming in, perhaps, thru a narrow slit

If light can enter at all angles, then dispersion occurs at all angles and no dispersion can be seen

A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is 0=2.95 m/s. Knowing that at the time of the release the balloon was 37.8 m above the ground, determine the time it takes for the bag to reach the ground from the moment of its release. Use =9.81 m/s2.

A small bag of sand is released from an ascending hotair balloon whose constant, upward velocity is 0=2.95

Answers

The time taken is approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.

To determine the time it takes for the bag of sand to reach the ground, we can use the kinematic equation for vertical motion. The equation is given as:

h = ut + (1/2)gt^2

Where:

h = height (37.8 m)

u = initial velocity (0 m/s)

g = acceleration due to gravity (-9.81 m/s^2, considering downward motion)

t = time

Since the balloon is ascending with a constant upward velocity of 2.95 m/s, the initial velocity of the bag is also 2.95 m/s in the upward direction. Therefore, we need to consider the initial velocity as negative.

Substituting the known values into the equation, we have:

37.8 = (-2.95)t + (1/2)(-9.81)t^2

Simplifying the equation further, we get:

-4.905t^2 - 2.95t + 37.8 = 0

Solving this quadratic equation for time, we find two solutions: t = 2.08 s and t = -3.61 s. Since time cannot be negative, we discard the negative value.

Therefore, it takes approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.

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How to solve for initial velocity with only height final velocity and acceleration

Answers

Answer:

Height and Velocity Functions

Ascertain the height from which the object fell. Multiply the height by 2, and divide the result by the object's acceleration due to gravity. If the object fell from 5 m, the equation would look like this: (2*5 m)/(9.8 m/s^2) =1.02 s^2.

Explanation:

if IT helped uh please mark me A BRAINLIEST :-/

explain magnetic flux

explain magnetic flux

Answers

Magnetic flux is a measurement of the total magnetic field, which passes through a given area. If it is a useful tool, for helping describe the effects of the magnetic force on some thing occupying a given area.

Which of the vectors in the graph below is the negative of the vector v?

Which of the vectors in the graph below is the negative of the vector v?

Answers

Answer:

D

Explanation:

Answer:

A. D

Explanation:

What is the unit of measurement of mass and weight? ​

Answers

the unit of measurement for mass & weight is kilograms (kg)

Answer:

kilogram

In the International System of Units (SI), the kilogram is the basic unit of mass, and the newton is the basic unit of force. The non-SI kilogram-force is also a unit of force typically used in the measure of weight.

The pressure at the bottom of a full barrel of water is Poriginal . Determine what happens to the pressure when the radius or height of the barrel is changed and water is added to make the barrel full again.

Answers

Answer:

a)   P' = P_original, b)  P ’= P_original + ρ  g Δh

Explanation:

The expression for nanometric pressure is

          P = ρ g h

where ρ  is the density of the liquid and h is the height

a) we change the radius of the barrel, but keeping the same height

as the pressure does not depend on the radius it remains the same

        P' = P_original

b) We change the barrel height

         h ’≠ h

we substitute in the equation

      P ’= ρ  g h’

      h ’= h + Δh

      P ’= ρ  g (h + Δh)

      P ’= (ρ  g h) + ρ  g Δh

      P ’= P_original + ΔP

In this case, the pressure changes due to the new height,

*if it is higher than the initial one, the pressure increases

*if the height is less than the initial one, the pressure is less

What kind of force is the force of gravity?

Answers

Answer:

Its a Universal Force

Explanation:

Conservative force, i.e work done in close circle is zero

If 600 J of energy of chemical energy is contained inside the gasoline in a gas tank, how much work can the engine perform on the car? What kinetic energy can be achieved?

Answers

Kinetic energy will be 600J. According to law of conservation energy: All the energy in a system will simply change the state, and no more nor less energy will be created or lost during the operation of the system. In this case, then all 600J of energy will be transformed during the operation of car.

This chemical energy, what is it?

kinetic energy, Chemical compounds' bonds contain energy. Chemical reactions have the potential to release chemical energy, frequently in the form of heat; these kinds of reactions are referred to as exothermic. Some of the energy from reactions that need heat input to continue may be stored as chemical energy in newly formed bonds.

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Would a 2021 Ford Mustang GT be light weight or heavy weight?​

Answers

Answer:

Heavy weight

Explanation:

It's a muscle car, its weight its 3,825 lb, and it's classified as heavy for a car.

Answer:

Heavy Weight

Explanation:

A 2021 Mutsang GT could wrigh from 3,532 to 3,868 lbs. This would be considered a Heavy meadium to Heavy muscle car.

No where close to the boat of mopar  the challenger almost weighting up to 4,500lbs

A skydiver of mass 80.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0 m/s. (a) What is her acceleration when her speed is 30.0 m/s

Answers

Answer:

6.22²

Explanation:

Given that

Mass of the skydiver, m = 80 kg

Terminal speed of the skydiver, v(f) = 50 m/s

Speed of the skydiver, v(i) = 30 m/s

Acceleration of the skydiver, a = ?

To solve this, we use the formula

W - k v² = ma, where

W = weight of the skydiver

k = constant

v = speed of the skydiver

m = mass of the skydiver

So, if we substitute the values into it we have

W = mg = 80 * 9.8 = 784 N

784 - k 50² = 80 *0

784 - 2500k = 0

784 = 2500k

k = 0.3136

Now, we use this value of k to find the needed acceleration using the same formula at a speed of 30 m/s

784 - 0.3136 * 30² = 80 * a

784 - 0.3136 * 900 = 80a

784 - 282.24 = 80a

497.76 = 80a

a = 497.76 / 80

a = 6.22 m/s²

Thus, we can conclude that the acceleration when the speed of the skydiver is 30 m/s, is 6.22 m/s²

Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.

Answers

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

What is the  magnitude of the initial acceleration?

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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True or False. A pulley is a system of wheels and ropes.

Answers

The answer for that is true

Answer:

True

Explanation:

a pulley is a wheel on an Axel or shaft that is designed to support movement and chnage of direction of a taut cable or belt

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