Uma lousa digital possui uma forma retangular e tem sua largura expressa pelo polinômio b+2. Sendo sua área igual ao polinômio B ao quadrado + 5b+ 6, qual é o polinômio que expressa a altura dessa lousa?

The greatest number of 24 inch pieces the carpenter can cut from 6 boards of wood is 51.

A carpenter needs to cut 24-inch pieces of wood from a board that is 17 feet in length.

Therefore, the greatest number of 24 inches pieces the carpenter can cut from 6 of these boards of wood can be calculated as follows:

let's convert from feet to inches.

17 feet = 204 inches

1 board = 204 inches

6 board = ?

cross  multiply

length of 6 board = 204 × 6

length of 6 board = 1224 inches

Hence,

greatest number of 24 inch that can be cut from 6 boards = 1224 / 24

greatest number of 24 inch that can be cut from 6 boards = 51

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The number of possible passwords for a length of 5 to 7 characters, where each character can be any alphanumeric value, is 218,340,105,584. If each password must contain at least one digit, then the number of possible passwords is 577,311,447,520.

There are 62 possible alphanumeric characters (26 uppercase letters + 26 lowercase letters + 10 digits). Therefore, the total number of possible passwords for a length of 5 to 7 characters is:

Total number of passwords = 62^5 + 62^6 + 62^7 = 218,340,105,584,896

If each password must contain at least one digit, then there are 10 choices for the first character, and 62 choices for each of the remaining four to six characters. Therefore, the total number of possible passwords is:

Total number of passwords = 10 * 62^4 + 10 * 62^5 + 10 * 62^6 = 577,311,447,520.

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Answer: Moe is wrong.

Step-by-step explanation:

Moe is incorrect because 25 divided by 5 equals 5 (constant of proportionality) but 12 divided by 3 does not equal 5 (it equals 4)

Answer:

D

Step-by-step explanation:

Answer:

A is the right answer of your question but....

I m little bit doubtful about that

To find the area of the polyhedron, we find the area of all faces of the polyhedron or the area covered by the net of the polyhedron

Considering all the options the lateral surface area is the area of the polyhedron without the area of the base. Therefore the surface area of a polyhedron can also be defined as the lateral surface area which is the area of every other face of the polyhedron except the base and then adding it to the area of one of the bases.

so option C

Answer: A

Step-by-step explanation: I would say A because the angle is greater than 90 degrees

Answer:

We have supplementary angles.

76 + 3x + 2 = 180

3x + 78 = 180

3x = 102

x = 34

Answer:

9x/y³

Step-by-step explanation:

The simplification of the expression 9x⁰y⁻³ will be 9/y³.

Index (indices) in Maths is the power or exponent which is raised to a number or a variable.

In another word the mathematics of power or exponent of any number is called indices.

As per the given expression,

9x⁰y⁻³

By the law of indices that, \(x^{-m}\) = 1/\(x^{m}\)

9x⁰y⁻³ = 9x⁰ × 1/y³

⇒ 9(1)/y³ = 9/y³

Hence "The simplification of the expression 9x⁰y⁻³ will be 9/y³".

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Answer:

Sorry, I tried.

Hope this helps.

Step-by-step explanation:

The chosen topic is not meant for use with this type of problem. Try the examples below.

6x2+3y2=126x2+3y2=12 , x+y=2x+y=2

x+2y=4x+2y=4 , x−y=−3x-y=-3

x2−y=2x2-y=2 , 2x−y=−12x-y=-1

The sides that are parallel include AB and DC.

In geometry, parallel sides refer to two or more sides of a polygon or a pair of lines that never intersect and remain equidistant from each other at all points.

Parallelogram: A parallelogram is a quadrilateral with two pairs of parallel sides. Opposite sides of a parallelogram are parallel and congruent (equal in length).

Rectangle: A rectangle is a special type of parallelogram where all four angles are right angles (90 degrees). Opposite sides of a rectangle are parallel and congruent.

Rhombus: A rhombus is another type of parallelogram in which all four sides are congruent. Opposite sides of a rhombus are parallel.

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Answer:

Both are TRUE.

Step-by-step explanation:

The sum of 2 rational numbers is always rational.

The sum of 2 irrational numbers is always irrational.

The sum of two rational numbers is always rational the sum of two irrational numbers is always irrational.

Rational number are real numbers that can be expressed as a ratio of two integers.

Irrational number are real numbers that cannot be expressed as a ratio of two integers.

Now, to prove that,

The sum of two rational numbers is always rational.

Let us take an example,

Suppose two rational numbers sqrt(16) and sqrt(36),

So, there sum is given as,

sqrt(16) + sqrt(36) = 4 + 6

sqrt(16) + sqrt(36) = 9

which is rational.

Hence, the sum of two rational numbers is always rational.

The sum of two irrational numbers is always irrational

Let us take an example,

Suppose two irrational numbers sqrt(7) and pi,

So, there sum is given as,

sqrt(7) + pi = 5.7857...

This cannot be reduced to any kind of fraction

So, we will get an irrational number.

Thus, the sum of two irrational numbers is always irrational.

Hence, the sum of two rational numbers is always rational the sum of two irrational numbers is always irrational.

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Answer:

Hollerith tabulating machine

Step-by-step explanation:

The Hollerith tabulating machine was invented by Herman Hollerith in other to assist in the data processing of the United States 1890 election. This machine was used to read and summarize the information stored on punchcards. This machine paved the way for the development of enhanced models which were employed for accounting and some other aspects related to business management.

Answer:

p < -9/2 or p < -4.5

Step-by-step explanation:

-3 > 2/3p

-3 * 3> 2p

-9/2 > p

-9/2 > p or -4.5 > p

Given:

The inequality is:

\(y<\sqrt{x+3}+1\)

To find:

The domain and range of the given inequality.

Solution:

We have,

\(y<\sqrt{x+3}+1\)

The related equation is:

\(y=\sqrt{x+3}+1\)

This equation is defined if:

\(x+3\geq 0\)

\(x\geq -3\)

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

\(\sqrt{x+3}\geq 0\)

\(\sqrt{x+3}+1\geq 0+1\)

\(y\geq 1\)

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

Therefore, the correct option is A.

Answer:

8436

Step-by-step explanation:

19(|12+25|)(12)

=8436

To match decimal values with their corresponding hexadecimal values, we need to convert the decimal numbers into their hexadecimal equivalents using division and remainders.

To match each decimal value on the left with the corresponding hexadecimal value, we need to convert the decimal numbers into their hexadecimal equivalents.

Here are a few examples:

1. Decimal 10 = Hexadecimal A

To convert 10 to hexadecimal, we divide it by 16. The remainder is A, which represents 10 in hexadecimal.

2. Decimal 25 = Hexadecimal 19

To convert 25 to hexadecimal, we divide it by 16. The remainder is 9, which represents 9 in hexadecimal. The quotient is 1, which represents 1 in hexadecimal. Therefore, 25 in decimal is 19 in hexadecimal.

3. Decimal 128 = Hexadecimal 80

To convert 128 to hexadecimal, we divide it by 16. The remainder is 0, which represents 0 in hexadecimal. The quotient is 8, which represents 8 in hexadecimal. Therefore, 128 in decimal is 80 in hexadecimal.

Remember, the hexadecimal system uses base 16, so the digits range from 0 to 9, and then from A to F. When the decimal value is larger than 9, we use letters to represent the values from 10 to 15.In conclusion, to match decimal values with their corresponding hexadecimal values, we need to convert the decimal numbers into their hexadecimal equivalents using division and remainders.

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TLDR: 88%

The probability of neither event happening is the complement of the probability of either event happening, which is 100 - 12 = 88.

Cheers,

qxxi

Answer: c

Step-by-step explanation:

The shaded part is 3 column

There are 10 columnn in total.

The number of grids are 100 and shaded grids are 30

Thus the fraction of shaded portion is:

3/10.

The decimal form is 0.3.

3 bottom sections:

10 x 20 = 200

5x 20 = 100

10 x 20 = 200

Bottom area = 200 + 200 + 100 = 500 square feet.

Short side: 3 x 20 = 60

Deep end wall : 6 x 20 = 120

Side wall : (24 x6) - (10x3) - (1/2 x 4x3) = 144-30-6 = 108

2 side walls: 108 x 2 = 216

Total area : 500 + 216 + 60 + 120 = 896 square feet

Divide total area by area of 1 gallon:

896/400 = 2.24 gallons

It will take 2.24 gallons of paint

The best cell (or measurement) interval for these 400 observed values with a range of 65 kg, a high of 360kg, and a low of 295kg is 3.25 kg.

The interval with the cells (or measurement) for a range of 400 observed values with a high of 360kg and a low of 295kg can be found as follows.Let's find the range of observed values first.

To find out the range, you need to subtract the smallest value (low) from the largest value (high) as given;

Range = High - Low = 360 - 295 = 65 kg

Now, we need to decide on the cell or measurement interval for these 400 observed values.

The measurement interval should not be too small or too large. If it is too small, the data may be over-detailed, and if it is too large, it may lose the essential information that we need.

Therefore, the measurement interval needs to be optimal and sufficient enough to provide the required information.Therefore, we need to calculate the number of intervals that would be suitable for this range.

One of the common ways to calculate the number of intervals is by using the square root of the number of observed values. So the number of intervals is:

No. of Intervals = sqrt (number of observed values) = sqrt(400) = 20 intervals

Now, we need to calculate the size of each cell or measurement interval

Size of interval = Range/No. of intervals = 65/20 ≈ 3.25 kg

Therefore, the best cell (or measurement) interval for these 400 observed values with a range of 65 kg, a high of 360kg, and a low of 295kg is 3.25 kg.

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We're 95% confident that the true population mean is between 31.361 and 37.039 minutes, with a margin of error of 2.839 minutes.

To find the t-value from the t-distribution table, we need to know the degrees of freedom. Since we have a sample size of 22, the degrees of freedom are 22-1=21. Looking up the t-value with 21 degrees of freedom and a 95% confidence level, we get 2.080.

Plugging in this value, we get:

CI = 34.2 ± 2.080*(7.1/√22)

CI = 34.2 ± 2.839

Therefore, the 95% confidence interval for the population mean commute time to work is (31.361, 37.039). This means that if we were to take many random samples of size 22 from the population and construct a 95% confidence interval for each sample, 95% of those intervals would contain the true population mean.

The margin of error of y is the amount added and subtracted from the sample mean to get the upper and lower bounds of the confidence interval. In this case, the margin of error is 2.839 minutes.

This means that we're 95% confident that the true population mean commute time to work is between 31.361 and 37.039 minutes, with a margin of error of 2.839 minutes.

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No, applying gradient boosting linear regressor multiple times does not necessarily give the same result as linear regression.

Gradient boosting is an iterative machine learning algorithm that involves combining multiple weak models, such as decision trees, to create a strong predictive model. In each iteration of the algorithm, a new model is trained to predict the errors of the previous models, and the final prediction is the sum of the predictions of all the models.

On the other hand, linear regression is a parametric method that involves fitting a linear equation to the data, where the coefficients of the equation are estimated using the least squares method. While gradient boosting linear regression and linear regression both aim to predict a target variable based on a set of input variables, they use different approaches and assumptions, and their results may not be the same.

In particular, gradient boosting can be more effective than linear regression when the relationship between the input variables and the target variable is nonlinear or when there are complex interactions between the input variables. However, linear regression can be more interpretable and easier to implement than gradient boosting in some cases.

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Answer:

Yes,

\(y^{6} x\)

Step-by-step explanation:

\(y^{5} xy = y^{5} *y*x = y^{6} x\)

Answer: 22( w + 2 ) =77 and the amount of the water bottle would be 1.50

Step-by-step explanation: i dont know what to write??

1. P(X + Y ≤ 2) = -e⁻² - 2e⁻², 2. Marginal PDF for X: fₓ(x) = -2e⁻ˣ and marginal PDF for Y: fᵧ(y) = 2e⁻ʸ - 2e⁻ˣ⁻ʸ.

1. To find P(X + Y ≤ 2), we need to integrate the joint PDF over the region where X + Y is less than or equal to 2. Since X and Y are non-negative random variables, the region of interest is the triangle bounded by the lines X = 0, Y = 0, and X + Y = 2. Integrating the joint PDF over this region gives:

P(X + Y ≤ 2) = ∫∫ fₓᵧ(x, y) dx dy

The integral bounds can be determined by considering the constraints 0 ≤ X ≤ Y ≤ ∞:

0 ≤ x ≤ y

0 ≤ y ≤ ∞

Setting up the integral,

P(X + Y ≤ 2) = ∫[0,∞] ∫[x,2-x] 2e⁻ˣ⁻ʸ dy dx

Solving the integral,

P(X + Y ≤ 2) = ∫[0,∞] -2e⁻ˣ⁻ʸ ∣ x to 2-x dx

Simplifying the integral bounds,

P(X + Y ≤ 2) = ∫[0,∞] -2e⁻ˣ⁻²⁻ˣ + 2e⁻²⁻ˣ dx

Evaluating the integral,

P(X + Y ≤ 2) = -e⁻²⁻ˣ - 2e⁻²⁻ˣ ∣ 0 to ∞

As x approaches infinity, e⁻²⁻ˣ approaches 0, so the second term in the integral becomes zero.

P(X + Y ≤ 2) = -e⁻²⁻⁰ - 2e⁻²⁻⁰

P(X + Y ≤ 2) = -e⁻² - 2e⁻²

Therefore, P(X + Y ≤ 2) = -e⁻² - 2e⁻².

2. To find the marginal PDFs for X and Y, we integrate the joint PDF over the respective variable while treating the other variable as a constant. The marginal PDF for X, denoted as fₓ(x), is obtained by integrating the joint PDF fₓᵧ(x, y) over the range of Y:

fₓ(x) = ∫[x,∞] fₓᵧ(x, y) dy

Substituting the given joint PDF,

fₓ(x) = ∫[x,∞] 2e⁻ˣ⁻ʸ dy

Simplifying the integral,

fₓ(x) = -2e⁻ˣ⁻ʸ ∣ x to ∞

As y approaches infinity, e⁻ˣ⁻ʸ approaches 0, so the integral becomes,

fₓ(x) = -2e⁻ˣ⁻ˣ

Simplifying further,

fₓ(x) = -2e⁻ˣ

Therefore, the marginal PDF for X is fₓ(x) = -2e⁻ˣ.

Similarly, the marginal PDF for Y, denoted as fᵧ(y), is obtained by integrating the joint PDF fₓᵧ(x, y) over the range of X,

fᵧ(y) = ∫[0,y] fₓᵧ(x, y) dx

Substituting the given joint PDF,

fᵧ(y) = ∫[0,y] 2e⁻ˣ⁻ʸ dx

Simplifying the integral,

fᵧ(y) = 2e⁻ˣ⁻ʸ ∣ 0 to y

fᵧ(y) = 2e⁻ʸ - 2e⁻ˣ⁻ʸ

Therefore, the marginal PDF for Y is fᵧ(y) = 2e⁻ʸ - 2e⁻ˣ⁻ʸ.

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Complete question - Let the random variables X and Y have the joint PDF given below:

fₓᵧ(x, y) = 2e⁻ˣ⁻ʸ when 0 ≤ X ≤ Y ≤ ∞

fₓᵧ(x, y) = 0 otherwise.

1. Find P(X + Y ≤ 2)

2. Find the marginal PDF for X and Y.

Answer:

7, 14, 21

Step-by-step explanation:

We can get the multiples of 7 by multiplying them by numbers 1, 2, 3, ... and so on.