ughhh help meeeeplzz

Answer:

4

Step-by-step explanation:

We want xy=54=2*3^3 such that x is at least 2 and y is at least 5. Thus, the possible combinations (x,y) are (2,27), (3,18), (6,9), and (9,6). There are 4 such combinations.

Answer:

The answer is D

Step-by-step explanation:

EDGE2020

The answer is:

A)   F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)

  F(x) is the output, or y values, and the y values on this coordinate plane from (negative infinity, -0.7) to (0.76, 2.5) do not have values above 0. Hence, F(x) is less than 0 over the given intervals.

The distributive property is:

We can use this property to distribute the left hand side:

Now, we just use algebra to solve for x:

The value of x is 0

Answer:

Your answer would be C. 3x+1.50 = 9

Step-by-step explanation:

Sorry if i was a lil late.

The value of x or m∠RSQ is 60 degrees.

What are trigonometric functions?

Trigonometric functions are mathematical functions that relate the angles and sides of a right triangle. They are commonly used in geometry, physics, and engineering to solve problems involving triangles and periodic phenomena.

The basic trigonometric functions are:

Sine (sin): the ratio of the length of the side opposite an angle to the length of the hypotenuse of the triangle.

Cosine (cos): the ratio of the length of the side adjacent to an angle to the length of the hypotenuse of the triangle.

Tangent (tan): the ratio of the length of the side opposite an angle to the length of the side adjacent to the angle.

Since angle R is a right angle, we know that angle ∠RSQ is complementary to angle ∠QRS. Therefore, we can find the measure of angle ∠RSQ by subtracting the measure of angle ∠QRS from 90 degrees:

∠RSQ = 90 - ∠QRS

To find the measure of ∠QRS, we can use the Pythagorean Theorem, since we know that triangle QRS is a right triangle:

\(QR^2 = QS^2 + RS^2\)

Substituting the given values, we have:

\(QR^2 = 98^2 + 84^2\)

\(QR^2 = 22580\)

QR = \(\sqrt{22580}\)

QR ≈ 150.3

Now we can use the trigonometric functions to find the measure of angle ∠QRS:

sin(∠QRS) = RS / QR

sin(∠QRS) = 84 / 150.3

sin(∠QRS) ≈ 0.559

∠QRS = \(sin^{-1}\)(0.559)

∠QRS ≈ 33.8 degrees

Therefore, the measure of angle ∠RSQ is:

∠RSQ = 90 - ∠QRS

∠RSQ = 90 - 33.8

∠RSQ ≈ 56.2 degrees

Rounding to the nearest tenth, we get:

∠RSQ ≈ 60 degrees

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In the attached diagram the perimeter of the hall way is

The perimeter of the hall way is calculated by adding all the sides of the hallway

The perimeter of the hall way  = 2x - 7 + x + 1 + 4x - 9 + x - 2 + x + 2 + 3x - 11 + x - 2 + 3x - 11 + x + 4

adding like terms results to

The perimeter of the hall way  =  17x + (-34)

Finally, the simplified expression is:

17x - 34

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Answer:

Solve the rational equation by combining expressions and isolating the variable x

.

x≈1.89393154

Step-by-step explanation:

please mark brainly

A function f is referred to as being one-to-one if it never accepts the same value again.

Function Definition

Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

To answer to the question, "What is a one-to-one function?"

A one-to-one function is one in which a single element in the range relates to an element in the domain. In other words, there is exactly one image in the range for each element in the domain.

Every element in the range is mapped to exactly one element in its domain via a specific function known as a one-to-one mapping, which ensures that the outputs never duplicate.

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the image of 0 under the mapping w = z³ is also 0.

To find the image of 0 under the mapping w = z³, we substitute z = 0 into the equation:

w = (0)³

Simplifying this expression, we have:

w = 0

what is expression?

In mathematics, an expression refers to a combination of numbers, variables, and mathematical operations that are written in a specific format or notation. It can represent a mathematical calculation, a relationship, or a statement.

Expressions can be simple or complex, and they can involve various mathematical operations such as addition, subtraction, multiplication, division, exponentiation, and more. They can also include functions, constants, and variables.

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Step-by-step explanation:

xylophone : x

yo-yo : y

3x + 3y = 45 —(1)

5x + 6y = 80 —(2)

(1)*2 : 6x + 6y = 90 —(3)

(3)-(2):

6x + 6y = 90

-(5x + 6y) = 80

x =10 — (4)

Sub (4) into (1)

3(10) + 3y = 45

30 + 3y = 45

3y = 45-30

y = 15/3

y = 5

(a) The volume V of the box as a function of x is V = 4x^3-60x^2+200x

(b) The domain of V in interval notation is 0<x<5,

(c) The length L , width W, and height H of the resulting box that maximizes the volume is H = 2.113, W = 5.773, L= 15.773

(d) The maximum volume of the box is 192.421 cm^2.

In the given question,

A box is to be made out of a 10 cm by 20 cm piece of cardboard. Squares of side length cm will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top.

(a) We have to express the volume V of the box as a function of x.

If we cut out the squares, we'll have a length and width of 10-2x, 20-2x respectively and height of x.

So V = x(10-2x) (20-2x)

V = x(10(20-2x)-2x(20-2x))

V = x(200-20x-40x+4x^2)

V = x ( 200 - 60 x + 4x^2)

V = 4x^3-60x^2+200x

(b) Now we have to give the domain of V in interval notation.

Since the lengths must all be positive,

10-2x > 0 ≥ x < 5 and x> 0

So 0 < x < 5

(c) Now we have to find the length L , width W, and height H of the resulting box that maximizes the volume.

We take the derivative of V:

V'(x) = 12x^2-120x+200

Taking V'(x)=0

0 = 4 (3x^2-30x+50)

3x^2-30x+50=0

Now using the quadratic formula:

x=\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

From the equationl a=3, b=-30, c=50

Putting the value

x=\(\frac{30\pm\sqrt{(-30)^2-4\times3\times50}}{2\times3}\)

x= \(\frac{30\pm\sqrt{900-600}}{6}\)

x= \(\frac{30\pm\sqrt{300}}{6}\)

x= \(\frac{30\pm17.321}{6}\)

Since x<5,

So x= \(\frac{30-17.321}{6}\)

x= 2.113

So H = 2.113, W = 5.773, L= 15.773.

d) Now we have to find the maximum volume of the box.

V = HWL

V= 2.113*5.773*15.773

V = 192.421 cm^3

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A)the density of |x| is f(|x|) = 1/(1-0) = 1. B) the density of p|x| is f(p|x|) = 1/(p-0) = 1/p. C) the density of -ln|x| is f(-ln|x|) = 1/(∞-0) = 0. D) the density of sin(x) is f(sin(x)) = 1/(sin(1)-(-sin(1))).

(a) To find the density of |x|, we need to consider the range of values that |x| can take. Since x is uniformly distributed on the interval (-1, 1), the absolute value of x can take values between 0 and 1. The density function of |x| is given by f(|x|) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a = 0 and b = 1. Therefore, the density of |x| is f(|x|) = 1/(1-0) = 1.

(b) To find the density of p|x|, we need to consider the range of values that p|x| can take. Since x is uniformly distributed on the interval (-1, 1), p|x| can take values between 0 and p. The density function of p|x| is given by f(p|x|) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a = 0 and b = p. Therefore, the density of p|x| is f(p|x|) = 1/(p-0) = 1/p.

(c) To find the density of -ln|x|, we need to consider the range of values that -ln|x| can take. Since x is uniformly distributed on the interval (-1, 1), -ln|x| can take values between 0 and ∞. The density function of -ln|x| is given by f(-ln|x|) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a  = 0 and b = ∞. Therefore, the density of -ln|x| is f(-ln|x|) = 1/(∞-0) = 0.

(d) To find the density of sin(x), we need to consider the range of values that sin(x) can take. Since x is uniformly distributed on the interval (-1, 1), sin(x) can take values between -sin(1) and sin(1). The density function of sin(x) is given by f(sin(x)) = 1/(b-a), where a and b are the lower and upper bounds of the interval. In this case, a = -sin(1) and b = sin(1). Therefore, the density of sin(x) is f(sin(x)) = 1/(sin(1)-(-sin(1))).

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Answer:

[911,∞)

Step-by-step explanation:

Given: S be the number of cans collected by Shane.

Since,  Abha collected 178 more cans than Shane did.

Then, the number of cans collected by Abha = S+178

Also, Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling.

So,  

Hence, the solution set of the inequality will be [911,∞)

The shaded part is 3 column

There are 10 columnn in total.

The number of grids are 100 and shaded grids are 30

Thus the fraction of shaded portion is:

3/10.

The decimal form is 0.3.

The required concept that is most useful when explaining the effect of a rotation is the angle. Option A is correct.

Given that,
To determine that which geometric concept is most useful when explaining the effect of a rotation on a segment.

Geometry is the mathematical study of figures and shapes.

here,
When it is to rotate the main geometric concept that must explain is the angle, for the rotation, it must me known how much angle the rotation is initiated.

Thus, the required concept that is most useful when explaining the effect of a rotation is the angle. Option A is correct.

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The Answer: y = 2x + 7

The distance covered is 5 1/2 miles.

The first step is to determine the speed at which Annie walked. Speed is total distance per time.

Speed = distance / time

1/2 ÷ 1/4

1/2 x 4 = 2 miles / hour

Distance covered = time x speed

= 2 x \(2\frac{3}{4}\)

2 x \(\frac{11}{4}\) = \(\frac{11}{2}\) = 5 \(\frac{1}{2}\) miles

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The probability that at most three grafts fail is 0.98 and the probability that at least two grafts fail is 0.1.

To find the probability that at most three grafts fail, we need to find the sum of the probabilities for x = 0, 1, 2, and 3.

Using the given values of f(x), we get:

P(X <= 3) = f(0) + f(1) + f(2) + f(3)

= 0.7 + 0.2 + 0.05 + 0.03

= 0.98

So the probability that at most three grafts fail is 0.98.

To find the probability that at least two grafts fail, we need to find the sum of the probabilities for x = 2, 3, and 4 and subtract it from 1.

Using the given values of f(x), we get:

P(X >= 2) = 1 - (f(0) + f(1)) = 1 - (0.7 + 0.2) = 0.1

So the probability that at least two grafts fail is 0.1

--The question is incomplete, answering to the question below--

"Grafting the uniting of the stem of one plant with the stem or root of another; is widely used commercially to grow the stem of one variety that produces fine fruit on the root system of another variety with hardy root system: Most Florida sweet oranges grow on trees grafted to the root of sour orange variety. The density for X, the number of 'grafts that fail in series of five trials.

For the values of x = 0, 1, 2, 3, and 4 value of f(x) is 0.7, 0.2, 0.05, 0.03, and 0.01 respectively.

Use f(x) to find the probability that at most three grafts fail; that at least two grafts fail."

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To solve this problem, we can use the Poisson distribution formula.

The formula is P(X ≤ 10) = e^(-λ) ∑(k=0 to 10) (λ^k / k!) where λ is the average rate of customers per hour, which is 17.

Substituting the values,

we get P(X ≤ 10) = e^(-17) ∑(k=0 to 10) (17^k / k!)

Using a calculator, we get P(X ≤ 10) = 0.2588 or 25.88%. This means that during a given hour, the probability that 10 or fewer customers will arrive at the drive-thru is 25.88%.

It is important to note that the Poisson distribution assumes that the arrival rate is random and constant. In reality, there may be factors that affect the arrival rate, such as time of day, day of the week, and weather conditions. However, the Poisson distribution can still be a useful tool in predicting customer arrivals and managing staffing levels.

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Answer:

I need the answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

The sample is the part of the population that somebody wants to study. therefore, the sample is the 100 male students interviewed

Answer:

Step-by-step explanation:

answer : C

The complete statement:

The area of Charlene's rhombus is 1/9 (or 1 out of 9) of the area of Jerry's rhombus, which has an area of 135 square inches.

The base of Charlene's rhombus is 5 inches and the height is 3 inches, giving it an area of 15 square inches.

Jerry's rhombus has a base of 15 inches and a height of 9 inches, so its area is given by:

Area of Jerry's rhombus = base × height = 15 inches × 9 inches = 135 square inches.

Now, Charlene's rhombus has a base and height that are 1/3 the base and height of Jerry's rhombus. Therefore:

Base of Charlene's rhombus = (1/3) × 15 inches = 5 inches.

Height of Charlene's rhombus = (1/3) × 9 inches = 3 inches.

The area of Charlene's rhombus can be calculated as:

Area of Charlene's rhombus = base × height = 5 inches × 3 inches = 15 square inches.

To compare the areas of the two rhombuses:

Area of Charlene's rhombus / Area of Jerry's rhombus = 15 square inches / 135 square inches.

Simplifying the fraction, we get:

Area of Charlene's rhombus / Area of Jerry's rhombus = 1/9.

Therefore, the area of Charlene's rhombus is 1/9 (or 1 out of 9) of the area of Jerry's rhombus.

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Step-by-step explanation:

2k=3×4

2k=12

2k/2=12/2

k=6

Answer:

k = 6

Step-by-step explanation:

In Ratio Questions , The Denominator takes the same Ratio as the Numerator and vice versa

so for Question , 4 is double 2

Then k must be double of 3

Then k=2*3 = 6

The equation for ftc's profit is Profit = Sales – (Variable Cost + Fixed Cost)

According to the question,

The fixed cost to produce the doll = $100,000

Variable cost = $31

Selling price during holiday season = $39

Selling price during January = $10

Demand of new toys follows normal distribution

average sales = 60,000

Standard deviation = 15,000

Demand assumed in normal distribution = 60,000

The equation for ftc's profit ;

Let demand be d , production quality be p , fixed cost be x and variable cost be y

Maximum Profit:

Profit = Sales – (Variable Cost + Fixed Cost)

During the holiday season, For 40,000 dolls

Sales = 40,000 * 39 = $1,560,000

profit = $1,560,000 – (x+ y)

Variable Cost = 31*40,000 = 1,240,000

Fixed Cost = $100,000

Total Cost = 1,240,000+100,000 = $1,340,000

Profit = 1,560,000 – 1,340,000

= $220,000

Maximum Profit = $220,000

Average Profit: Off season sale price * Demand =$10*40,000

= $400,000

average sales = ($400,000 + 1,560,000 ) / 2=$1960,000/2

= $980,000

Average profit = 980,000 – 73,000= $972,700

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True. solving quadratic equations by completing the square is a legitimate and commonly used technique in algebra.

This method involves transforming a quadratic equation into a super square form, that could then be effortlessly solved for the variable. The procedure entails including or subtracting a constant term to both sides of the equation to create a perfect rectangular trinomial.

Which may be factored right into a binomial squared. the solution can then be acquired with the aid of taking the square root of both sides and solving for the variable. completing the rectangular is a beneficial method for fixing quadratic equations that can't be factored the usage of other strategies, which includes the quadratic formula.

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Step-by-step explanation:

RAMS SALARY=RS.200×20%

=40+200

=RS.240.00

ANSWER IS OPTION B

The net force must all be equal to zero (0) for an object to be in mechanical equilibrium, in order for the sum of all forces to be equal to each other.

In Classical mechanics, mechanical equilibrium can be defined as a phenomenon in which the net force acting on a physical object or body is equal to zero because it is at rest or in an unaccelerated motion.

A net force can be defined as the vector sum of all the forces that are acting on a physical object or body. This ultimately implies that, a net force is a single (one) force which substitutes the effect of all the forces that are acting on a physical object or body when it is in mechanical equilibrium.

In this context, we can infer and logically deduce that the net force must all be equal to zero (0) for an object to be in mechanical equilibrium, in order for the sum of all forces to be equal to each other.

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Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.

Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.

First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.

Next, we can find the vertex using the formula:

Vertex = (-b/2a, f(-b/2a))

where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:

Vertex = (-b/2a, f(-b/2a))

= (-6/(2*-1), f(6/(2*-1)))

= (3, -14)

So the vertex of the parabola is at the point (3,-14).

Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.

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