When a white dwarf gains enough mass to surpass the Chandra-Sekhar limit, type 1a supernovae are produced.
The importance of the Chandrasekhar limit in Type-1a supernovae has been recognised in astrophysics. The Chandrasekhar limit is thought to be crossed by a white dwarf, causing a catastrophic collapse, which is assumed to be the cause of these supernovae. It is believed that Type Ia supernovae (SNIa) are produced when a carbon-oxygen white dwarf in a binary system reaches the Chandrasehkar limit, either as a result of accretion from a donor or mergers. One of the two stars must be a white dwarf in order to cause a type Ia supernova.
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If 20J of heat is extracted from a system change in energy of the system will be
a moon jupiter has nearly circular orbit of radius r and an orbit period of t which of the followinf expressions gives the mass of jupiter
A moon jupiter has nearly circular orbit of radius r and an orbit period of t which of the followinf expressions gives the mass of jupiter is \(M=\frac{4 \pi^2 R^3}{G T^2}\)
The gravitational pull by Jupiter provides the centripetal force on its moon.
\($$\begin{aligned}& G \frac{M m}{R^2}=\frac{m v^2}{R} \\& G \frac{M}{R}=v^2 \\& =\left(\frac{2 \pi R}{T}\right)^2 \text { ItBrgt } M=\frac{4 \pi^2 R^3}{G T^2}\end{aligned}$$\)
However, due to the centripetal force exerted on it, the moon moves in a round path around the earth. Without centripetal force, the moon would not be able to travel in a circular motion; instead, it would move in a straight line perpendicular to its orbit.
The centripetal force required to maintain planets in orbit around the Sun and all kinds of satellites in orbit around the Earth is provided by gravitational attraction. The Moon continues to circle the Earth because to gravity. The velocity of the Moon is continuously shifting in one direction.
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If these results were published in a lab report, which of the following would most likely followthis table?a. A hypothesisb. A statement of the problemc. A conclusiond.An experiment
The given table is the table of result. In a lab report, discussions/conclusions usually follow result. Thus, the correct option is
c. A conclusion
how does energy transfer between objects
Answer:
Object A runs into Object B. The force that object A has will transfer from Object A to Object B. But during this transfer you will loose some energy, therefore object B will not travel as fast.
Explanation:
suppose that you want to build a machine to perform simple tasks. why must you understand all about forces to complete your mission?
Answer:
CAUSE YPU WANT TO
Explanation:
A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?
The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.
Let's break down the distances and calculate the time for each part of the journey:
Distance from the student to the first cliff: 330 meters
Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second
Distance from the first cliff to the second cliff: 990 meters
Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds
Distance from the second cliff back to the student: 990 meters
Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds
Now, we can calculate the total interval between the first and second echo by adding up the individual times:
Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds
Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.
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Note the complete questions is:
A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
This question is incomplete, the complete question is;
A positive charge of magnitude Q1 = 6.5 nC is located at the origin.
A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
Answer:
the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
Explanation:
Given the data in the question;
Q1 = 6.5 nC, Q2 = -3.5 nC
from the image below, to get our angle ∅
tan∅ = opp/adj
tan∅ = 10.5 / 16.5
tan∅ = 0.636363
∅ = tan⁻¹( 0.636363 )
∅ = 32.47°
also, r1 = √( 16.5² + 10.5²)
r1 = √( 272.25 + 110.25 )
r1 = √382.5
r1 = 19.55 cm = 0.1955 m
Now, the x-component of the electric field at point P due to charge Q1 will be;
Ex = E2cos32.47°
= (kQ1/r1²)cos32.47°
we know that; k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²
Q1 = 6.5 nC = 6.5 × 10⁻⁹ C
so we substitute
= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°
= (58.5 / 0.03822025) × 0.843672
= 1291.33 N/C
Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
what is the weight of a 500 g package of spaghetti noodles ? (A) in N (B) in oz
Given:
Weight of the spaghetti noddles = 500 grams
Let's find the weight of the noodles in Newtons(N) and Ounce(oz).
First convert 500g to kg:
\(500g=\frac{500}{1000}=\frac{1}{2}kg\)(A) in N
Where 1 kg = 9.8 N
Thus, we have:
\(\frac{1}{2}kg=\frac{1}{2}\ast9.8=4.9N\)The weight of a 500 g package of spaghetti noodles in Newton is 4.9 N
(B) in oz
Where:
1 gram = 0.035274 ounce
Thus, we have:
\(500g=500\ast0.035274=17.637\text{ oz}\)The weight of a 500g package of spaghetti noodles in Ounce is 17.637 oz
ANSWER:
(A) 4.9 N
(B) 17.637 oz
How much work will a 500 watt motor do in 10 seconds?
Answer:
50j
Explanation:
Watts are units used to measure power. power can be defined as rate of energy transfer
500 watts means - 500 J of energy per second
in 1 second - 500 J of work is done
therefore within 10 seconds - 500 J/s x 10 s = 5000 J
work of 5000 J is carried out in 10 seconds
Answer:
Watts are units used to measure power. power can be defined as rate of energy transfer
500 watts means - 500 J of energy per second
in 1 second - 500 J of work is done
therefore within 10 seconds - 500 J/s x 10 s = 5000 J
work of 5000 J is carried out in 10 seconds
Explanation:
Tom weighs 830 N here on Earth. His suit that he will wear on the moon has a mass of 50 kg. The acceleration due to gravity is 9.81 m/s2 on Earth and 1.67 m/s2 on the moon. What would be the total weight of Tom in his moon suit when he is on the moon?224 N141 N0 N467 N
Given
Tom weighs 830 N here on Earth
Suit has a mass of 50 kg
g = 9.81 m/s2
gm = 1.67 m/s2
Procedure
First let's calculate Tom's mass with the help of the earth's acceleration.
\(\begin{gathered} W=mg \\ m=\frac{W}{g} \\ m=\frac{830N}{9.81m/s^2} \\ m=84.60kg \end{gathered}\)Now let's calculate Tom's weight on the moon as the sum of his weight plus the weight of his suit.
\(\begin{gathered} W=(84.6+50)\cdot1.67 \\ W=224.8N \end{gathered}\)The answer would be 224 N
Answer: 224N
Explanation: Hope this was helpful
Many television signals are transmitted through electromagnetic
waves with frequencies from 3.0 x10^7 Hz to 3.0 x 10⁹ Hz. What is the longest wavelength associated
with this frequency range?
The longest wavelength associated with this frequency range is 10 meters.
What is wavelength ?
Wavelength is a measure of the distance between two consecutive crests or troughs of a wave. It is an important physical quantity that describes the size of a wave. It is typically measured in meters, as it is a measure of physical space. Wavelength is used to describe many types of waves, such as sound waves, light waves, water waves and radio waves. In addition, wavelength is an important factor in determining the frequency of a wave, which is the number of wave cycles per second. Wavelength is inversely related to frequency, meaning that as the wavelength increases, the frequency decreases. Wavelength is also used to describe the different colors of visible light, as each color has a different wavelength.
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What has to happen to make new elements?
I’m not sure what the answers to these questions are for this sheet can u help?
Answer:
Explanation:
b. helmet is aerodynamic; and he is leaning down, which reduces his surface area
c. open parachute exposes more surface area to the air, which increases the drag
9. A and D will float because density is less than 1.0
When he pushes the object down, then lets it go, it bobs back up because of the upward force (upthrust) of the water acting on the object.
How much power is used by a hair dryer if it does 40,000 J of work in 40 seconds?
Answer:
40000÷40=1000 joules is required to work in 40 seconds
These steps are followed when using the half-life of carbon-14 to determine
the age of an object that contains carbon. What is the correct order of these
steps?
A. Use the half-life of carbon-14 to determine the number of half-lives
that have passed.
B. Measure the ratio of parent nuclei to daughter nuclei.
C. Use the number of half-lives that have passed to determine the age
of the object.
A. A,B,C
B. A,C,B
0 0
C. B, A,C
D. C, A, B
Answer: a different one is a.b.c
Explanation: still for ape.x
The correct order to determine the age of the an object using carbon-14 is C, A, B. Thus, option D is correct.
What is half life?
The half-life time is defined as the time taken by the radioactive element to reduce one half of its initial value. It is denoted by t(1/2).
To measure the age of an object, a radioactive isotope called carbon-14 is used. The half-life of carbon-14 is 5,730 years. All the objects in the universe consumes carbon in their lifetime and hence, carbon-14 is used to measure the age of the objects.
The process of determining the age of objects using carbon-14 is called Radiocarbon dating. All living organisms consume carbon in means of food and from atmosphere and when the plant and animals dies, the radioactive carbon atoms start decaying.
When it starts decaying, by using Carbon-14 the age of an object is calculated. The age is estimated by measuring the amount of carbon-14 present in the sample and comparing this carbon with the reference Carbon-14 isotope.
The amount of carbon in preserved plants is identified by:
f(t) = 10e {₋ct}
t = time in years when the plant dies( t= 0)
c = the amount of carbon-14 remaining in preserved plants.
The steps include to find the age of an object is :
1. Use the number of half-lives that have passed to determine the age of the object.
2. Use the half-life of carbon-14 to determine the number of half-lives that have passed.
3.Measure the ratio of parent nuclei to daughter nuclei.
Hence, from these steps the age of an object is determined. Therefore the correct solution is D) C, A, B.
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A material that restricts the flow of electricity or thermal energy is a what
Answer: Insulator
Explanation:
An insulator is a material that restricts the flow of electricity or thermal energy.
Answer:
plastic or wood
Explanation:
A uranium ion and an iron ion are separated by a distance of =61.10 nm. The uranium atom is singly ionized; the iron atom is doubly ionized. Calculate the distance from the uranium atom at which an electron will be in equilibrium. Ignore the gravitational attraction between the particles. = nm An electron sits between a singly ionized uranium ion and a doubly ionized iron ion. The distance from the uranium ion to the electron is designated lowercase r, and the distance between the two ions is designated uppercase R. What is the magnitude of the force on the electron from the uranium ion? magnitude of the force: N
Answer:
Explanation:
Charge on uranium ion = charge of a single electron
= 1.6 x 10⁻¹⁹ C
charge on doubly ionised iron atom = charge of 2 electron
= 2 x 1.6 x 10⁻¹⁹ C = 3.2 x 10⁻¹⁹ C
Let the required distance from uranium ion be d .
force on electron at distance d from uranium ion
= 9 x 10⁹ x 1.6 x 10⁻¹⁹ / r²
force on electron at distance 61.10 x 10⁻⁹ - r from iron ion
= 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²
For equilibrium ,
9 x 10⁹ x 1.6 x 10⁻¹⁹ / r² = 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²
2 d² = (61.10 x 10⁻⁹ - r )²
1.414 r = 61.10 x 10⁻⁹ - r
2.414 r = 61.10 x 10⁻⁹
r = 25.31 nm .
(a) The distance from the uranium atom at which an electron will be in equilibrium is \(2.04 \times 10^{-8} \ m\)
(b) The magnitude of the force on the electron from the uranium ion is \(3.46 \times 10^ 6 \ N\)
The given parameters:
distance between the iron and the uranium, d = 61.1 nmcharge of uranium ion, q₁ = 1.6 x 10⁻¹⁹ Ccharge of doubly ionized atom, q₂ = 2q₁ = 3.2 x 10⁻¹⁹ CThe force on the electron due to uranium ion at distance r is calculated as follows;
\(F _1 = \frac{Kq_1^2}{r^2} \\\\F_1 = \frac{9\times 10^9 \times (1.6\times 10^{-19})^2}{r^2} \\\\F_1 = \frac{2.3 \times 10^{-28}}{r^2}\)
The force on the electron due to uranium ion at distance less than 61.10 nm.
R = 61.10 nm - r
\(F_2 = \frac{9\times 10^9 \times (3.2 \times 10^{-19})^2}{(61.1 \times 10^{-9} \ - \ r)^2} \\\\\F_2 = \frac{9.216 \times 10^{-28}}{(61.1 \times 10^{-9} \ - \ r)^2}\)
At equilibrium, the force between the electron and ions will be equal.
\(\frac{9.216 \times 10^{-28}}{(61.1 \times 10^{-9} \ - \ r)^2}= \frac{2.3 \times 10^{-28}}{r^2}\\\\\frac{4}{(61.1 \times 10^{-9} \ - \ r)^2} = \frac{1}{r^2} \\\\4r^2 = (61.1 \times 10^{-9} \ - \ r)^2\\\\2^2r^2 = (61.1 \times 10^{-9} \ - \ r)^2\\\\2r = 61.1 \times 10^{-9} \ - \ r\\\\3r = 61.1 \times 10^{-9} \\\\r = \frac{61.1 \times 10^{-9}}{3} \\\\r = 2.04 \times 10^{-8} \ m\)
The magnitude of the force on the electron from the uranium ion is calculated as follows;
\(F = \frac{kq_1^2}{r^2} \\\\F = \frac{9\times 10^9 \times 1.6\times 10^{-19}}{(2.04 \times 10^{-8})^2} \\\\F= 3.46 \times 10^6 \ N\)
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4. You currently have TWO 9 volt batteries connected to a 82 resistor. How
much current is flowing through the circuit? *
1.125 A
5 A
72 A
2.25 A
Back
Next
Never submit passwords through Gon
Explanation:
Total voltage = 9 × 2 = 18v
Resistance = 82 Ω
Ohm's law::
V = IR
18v = 82 Ω × I
18v /82 /Ω = I
18/82 Ampere is the current
define holizoic animals
Holozoic food acquisition is defined by the absorption of complex organic materials in the way of most creatures.
Holozoic nutrition refers to when creatures consume solid food. The food might be either plant-based or animal-based.
An animal ingests complicated organic food stuff into its body, helps to digest it, and then absorbs it into the living organisms in this process.
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Look at pic for question pls help
B IS YOUR ANSWER.
Soft sound has small amplitude and louder sound has large amplitude. Since, the second wave has large amplitude, it will have the loudest sound.
When you jump over something is it a balanced force?
Answer:
no..
Explanation:
in balanced force it will or in this case u would stay still or u would move at the same speed.. but when u jumps the speed changes..so this is an unbalanced force
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Vector A has a magnitude of 5 meters and points west vector B has a magnitude of 5 meters pointing east what is the direction and magnitude
The direction and magnitude of the net vector is:
Direction: None Magnitude: 0 meters.How to find the resultant and magnitude of the resultant vectorWhen vector A with magnitude of 5 meters pointing west and
vector B with magnitude of 5 meters pointing east are added,
they will result in a net vector with a magnitude of the difference between the magnitudes of the vectors and a direction equal to the direction of the vector with the largest magnitude.
Since both vectors have the same magnitude (5 meters), the net vector will have a magnitude of 0 meters.
This means that the vectors completely cancel each other out and there is no net vector remaining.
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Check Concepts
4.
35. Which of the following do you calculate
when
you
divide the total distance trav-
eled by the total travel time?
A) average speed
B) constant speed
C) variable speed
D) instantaneous speed
Answer:
I think its A.........
why does a bus look red in the daylight?
Answer:
The red color in the sky at sunset (and sunrise) is due to an effect called Rayleigh scattering.
Explanation:
The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3x10^22 kg, find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon
Explanation:
It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.
The gravitational force is given by :
\(F=\dfrac{Gm_em_m}{r^2}\)
It means \(F\propto \dfrac{1}{r^2}\)
So,
\(\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}\)
r₁ = 3.9x10⁸ km
r₂= 1.5x10⁸ km
So,
\(\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}\)
Hence, the ratio of the gravitational forces exerted by Earth and the Sun on the Moon is 5:13.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiempo alcanzará el coche a la furgoneta? ¿A qué distancia se producirá el encuentro?
Answer:
t = 0.33h = 1200s
x = 18.33 km
Explanation:
If the origin of coordinates is at the second car, you can write the following equations for both cars:
car 1:
\(x=x_o+v_1t\) (1)
xo = 10 km
v1 = 55km/h
car 2:
\(x'=v_2t\) (2)
v2 = 85km/h
For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:
\(x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}\)
\(t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s\)
The position in which both cars coincides is:
\(x=(55km/h)(0.33h)=18.33km\)
Calculate wavelength of tube of length 15, 18, 20 cm.
Answer:In this lesson, the mathematical relationship between the tube's length, the speed of sound through air, and the ... Thus, the length of the air column is equal to one-half of the wavelength for the first harmonic. ... Determine the fundamental frequency (1st harmonic) of an open-end air column that has a length of 67.5 cm.
Explanation:
Think for a moment about an atom of the element lead (atomic number 82) inside the radio that you listen to in the morning. In which of the following places has this atom probably NOT been during the course of its existence
a. a previous generation star
b. a supernova explosion
c. the Sun
d. a cloud of gas and dust which would clump to become a star and a family of planets
e. the Earth's crust
Answer:
c. the Sun
Explanation:
Considering the description made in the question about the atom of a lead with atomic number 82, the place t his atom probably have NOT been during the course of its existence is the SUN
The reason is that SUN is believed to consist of ten significant elements, which are: Hydrogen, Helium, Oxygen, Carbon, Nitrogen, Silicon, Magnesium, Neon, Iron, and Sulfur.
Also, some of the properties of lead show that it won't have existed in the Sun before. For example, it is a poor transmission of heat. Also, it doesn't react with oxygen in the air and doesn't burn as well.
The Lead is not considered to be existing in the sun, during the course of its existence. Hence, option (c) is correct.
In the given problem, the description about the atom of a lead with atomic number 82 is provided. The place of this atom probably have not been during the course of its existence is the sun.
Sun has the major composition of hydrogen and helium. The reason for the non existence of Lead in course of sun is that sun is believed to made by the composition of ten significant elements, which are: Hydrogen, Helium, Oxygen, Carbon, Nitrogen, Silicon, Magnesium, Neon, Iron, and Sulfur.
Also, some of the properties of lead show that it won't have existed in the Sun before. For example: Lead possesses a poor transmission of heat. Also, it doesn't react with oxygen in the air and doesn't burn as well.
Thus, we can conclude that the Lead is not considered to be existing in the sun, during the course of its existence. Hence, option (c) is correct.
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Explain why driver age 16-18 are most likely to be involved in traffic accidents
Answer:Lack of experience.
Explanation:
Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.