two tuning forks having frequencies of 454 and 460 hz are struck simultaneously. what average frequency (in hz) will you hear?

Answers

Answer 1

The average frequency of the two forks will be 457 Hz.

Frequency:

In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. When a body in periodic motion goes through a series of events or positions before returning to its initial state, it is said to have experienced one cycle or one vibration.

Average Frequency;

Mathematically,

                           \(f_{Avg}=\frac{f_{1}+f_{2} }{2}\)

Given,

         \(f_{1} = 454 Hz\)

         \(f_{2}=460 Hz\\\)

Using the Average frequency formula,

                         \(f_{Avg}=\frac{f_{1}+f_{2} }{2}= \frac{454+460}{2}\)

                       

                        \(f_{Avg}=\frac{914}{2}\)

                 

                         \(f_{Avg}=457Hz\)                       

Hence,

         The average frequency of the two forks will be 457 Hz.

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Related Questions

what is velocity vs time. i need help with my test on edge

Answers

Answer:

See below

Explanation:

It is a graph on the x -y coordinate system with (generally ) the y-axis is labelled 'velocity'   and the x - axis is 'time'   <==== with this, you can look at the time and find the velocity at that time on the graph

When electrons are accelerated by 2450v in an electron microscope they will have wavelengths of
a)8.113nm
b)0.622nm
c)0.811nm

Answers

I think the answer is A I’m
Not sure tho

3. If the net work done on an object is negative, then the object's kinetic energy
a. decreases.
b. remains the same.
c. increases.
d. is zero.

Answers

Answer:

I think the answer is B I hope this helps also Im sorry If I'm wrong

A child (m = 30. 5 kg) is sitting in a boat (m = 53. 0 kg); both are at rest together. He throws a rock (m = 5. 61 kg) into the lake horizontally at a speed of 10. 50 m·s-1

Answers

The velocity of the child and the boat after throwing the rock is 0.705 m/s in the opposite direction of the rock.

Let us solve the given problem by the application of the law of conservation of momentum. Since the system was at rest initially, therefore, its momentum before throwing of the rock is zero.Now let's see the momentum of the system after throwing of the rock. According to the law of conservation of momentum,The total momentum of the system remains conserved and zero. Hence the momentum of the boat and the child will be equal and opposite to the momentum of the rock.momentum of the rock = mvwhere,m = 5.61 kgv = 10.5 m/smomentum of the rock = 5.61 × 10.5 = 58.965 N sAs per the law of conservation of momentum, the total momentum of the system remains conserved and zero.After throwing the rock, the momentum of the boat and the child in the opposite direction is given by;momentum of the boat and the child = 58.965 N sBut the child and the boat were at rest initially, so their momentum was zero.Therefore, the momentum of the child and the boat together after throwing the rock is equal and opposite to the momentum of the rock.The momentum of the child and the boat is given by;momentum of the child and the boat = - 58.965 N s (opposite direction)We know that momentum is the product of mass and velocity.i.e., p = mvWhere, p = momentumm = massv = velocityThe mass of the child is m1 = 30.5 kgThe mass of the boat is m2 = 53 kg The mass of the child and the boat is given by; m1 + m2 = 30.5 + 53 = 83.5 kgLet the velocity of the child and the boat be V. Therefore the momentum of the child and the boat is given by;Momentum of the child and the boat = (m1 + m2)VLet's apply the principle of the law of conservation of momentum to calculate the velocity of the child and the boat after throwing the rock. The momentum of the rock before throwing = momentum of the rock after throwing. The momentum of the child and the boat before throwing = the momentum of the child and the boat after throwing. Therefore, the equation will be;momentum of the rock before throwing = momentum of the child and the boat after throwing

5.61 × 0 = (m1 + m2)V + (-58.965)83.5V = 0.705 m/s.

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a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)

Answers

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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Which event typically causes upwelling? Wind blows warm water away from the shore. Warm water rises to the surface of the ocean. Neap tides move cold water away from the shore. Cold water falls to the bottom of the ocean and pushes warm water up.

Answers

Upwelling is the phenomenon that removes the warmer water from the surface.

The correct option is C.

The cause of the upwelling is as follows:-

Movement of wind from the oceanic side

The wind moves from the ocean to replace the surface warm water with the nutrient-rich colder water.

Hence the correct option is C that is Neap tides move cold water away from the shore.

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Answer: A

Explanation: edge 2022 trust the process

A 40.0-kilogram child exerts a 100.-newton force on a 50.0-kilogram object. The magnitude of the force that the object exerts on the child is

answer choices
- 0.0 N
- 80.0 N
- 100. N
- 125 N

Answers

The magnitude of the force that the object exerts on the child is 100 N.

option C is the correct answer.

What is Newton's third law of motion?

Newton's third law of motion states that for every action there is an equal and opposite reaction. In other words, action and reaction are equal and opposite.

Mathematically, Newton's third is given as;

Fa = Fb

where;

Fa is the applied forceFb is the reaction experienced by the object

If the child exerts 100 N force on the object, the reaction of the object or the upward force exerted on the child by the object is 100 N in opposite direction.

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PLZZ HELP!!!
When a star is undergoing nuclear fusion what type of radiation will be found?

Answers

Answer:

I think the correct answer would be the third option. As the elements around the star begins to emit more and more electromagnetic radiation, the rocky materials are pulled in by the electromagnetic radiation. They are being drawn closer to the star and there would be a very high chance of a nuclear

Explanation:

1. While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is theautomobile's acceleration? (Remember that a negative value indicates a slowing down.)

Answers

Given data

*The initial speed of the driver is u = 24 m/s

*The final speed of the driver is v = 15 m/s

*The given time is t = 12 s

The formula for the automobile's acceleration is given as

\(a=\frac{v-u}{t}\)

Substitute the values in the above expression as

\(\begin{gathered} a=\frac{15-24}{12} \\ =-0.75m/s^2 \end{gathered}\)

An Indy car racer traveling at 15.0 meters per second slows as he makes a pit stop. If he decelerates at 2.5 meters per second squared, he was
away from the pit when he started braking.
meters

Answers

Answer:

x = 45 [m]

Explanation:

To solve this problem we must use the following kinematics equation:

\(v_{f}^{2} = v_{i}^{2}-(2*a*x)\)

where:

Vf = final velocity = 0

Vi = initial velocity = 15 [m/s]

a = desacceleration = 2.5 [m/s^2]

x = distance [m]

Note: the negative sign in the equation above, is because the car slows down.

0^2 = 15^2 - (2*2.5*x)

2*2.5*x = 15^2

x = 45 [m]

Identify the major ionic species present in an aqueous solution of FeCl3.
O Fest, ali
O Fe3+, 30-
O Fe2+ 3 CH-
O Fer. 30
Question 3

Answers

I think the answer is Fe3+

The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.

What is ion?

Conventionally, the charge of an electron is thought to be negative; this charge is equal to and opposite to the charge of a proton, which is thought to be positive. Because the total number of electrons in an ion is more than the total number of protons, the net charge of an ion is not zero.

A negatively charged ion called an anion has more electrons than protons compared to a positively charged ion called a cation. Electrostatic force causes opposite electric charges to be drawn towards one another, causing cations and anions to attract one another and easily form ionic compounds.

Hence, The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.

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The voltage between two points in a circuit is 5 V. If the resistance between
the points is 80 s2, what is the current, according to Ohm's law?
O A. 85.0 A
O B. 0.063 A
O C. 400 A
O D. 16.0 A

Answers

Answer:

B

Explanation:

i worked it out on a diffrent sheet so its hard to explain

The current, according to Ohm's law if, if The voltage between two points in a circuit is 5 V and the resistance between the points is 80 ohms, is 0.063 A so, option B is correct.

What is current?

Electric currents can be created by the movement of any electric charge carriers, including ions (atoms that have gained or lost one or more electrons), holes, or subatomic charged particles (such electrons with a negative charge or protons with a positive charge) (electron deficiencies that may be thought of as positive particles).

Given:

The voltage between two points in a circuit is 5 V,

If the resistance between the points is 80 ohms,

Calculate the current using Ohm's law as shown below,

Current = The voltage between two points / the resistance between the points

Current = 5 / 80

Current = 0.0625

Current = 0.063 A,

Thus, the current according to Ohm's law is 0.063 A.

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Cyclist A and B cycled atan average speed of 15 km/h and 20 km/h respectively from the same starting point X on the same route. Cyclist B started his journey 6 mins after cyclist A had started. i) What were the distances travelled by cyclist A and B 1 h cyclist A had started his journey from point X? ii) Dis cyclist B overtake cyclist A within the first hour of cyclist A's journey?

Answers

Answer:

i. Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

  Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii. cyclist B overtake cyclist A 6 km from the same starting point X.

Explanation:

From the question,

- Cyclist A and B cycled at an average speed of 15 km/h and 20 km/h respectively.

- Cyclist B started his journey 6 mins after cyclist A had started.

Let the cyclist A time be t.

Then, we can write that

For Cyclist A

Speed = 15 km/h

Time = t mins

For Cyclist B

Speed = 20 km/h

Time = (t - 6) mins

i) To determine the distances travelled by cyclist A and B 1h cyclist A had started his journey,

For Cyclist A

Speed = 15km/h

Time = 1h = 60 mins

From the formula

Speed = Distance / Time

Then,

Distance = Speed × Time

Putting the values into the equation,

Distance = 15km/h × 1h

Distance = 15 km

∴ Cyclist A travelled 15 km 1 h cyclist A had started his journey from point X

For cyclist B

Speed = 20km/h

Time = 1h - 6mins = 60mins - 6mins = 54mins = 54/60 hour = 0.9 h

Also, from

Distance = Speed × Time

Putting the values into the equation

Distance = 20km/h × 0.9h

Distance = 18 km

∴ Cyclist B travelled 18 km 1 h cyclist A had started his journey from point X

ii) To determine the distance cyclist B overtake cyclist A, that is, when the distance covered by cyclist A equals that covered by cyclist B.

First, we will determine the time at which the distances covered by both cyclists were equal.

From

For Cyclist A

Speed = 15 km/h

Time = t hour  

Distance = Speed × Time

Distance = 15t km

For Cyclist B

Speed = 20 km/h

Time = (60t - 6) mins = (t - 0.1) hour

Distance = 20 × (t - 0.1) = (20t - 2) km

Equate the distances

15t = 20t - 2

15t - 20t = -2

-5t = -2

5t = 2

t = 2/5

t = 0.4 hour

Hence, cyclist B overtake cyclist A 0.4 hour after cyclist A had started.

For the distance cyclist B overtake cyclist A,

From

Distance = (20t - 2) km

Distance = (20×0.4 - 2) km

Distance = (8 - 2) km

Distance = 6 km

Hence, cyclist B overtake cyclist A 6km from the same starting point X.

What kind of force are you using when you squish a marshmallow?

Answers

Answer:

Compression

Explanation:

I would think it would be compression because you are compressing the marshmallow, and pushing it down until its compact.

Answer: Compression, I to had to get an answer for this but imma help you out :)

a bullet of mass 0.00105 kg and speed v passes completely through a pendulum bob of mass 85.1 kg. the bullet emerges with a speed v/2. the pendulum bob is suspended by a stiff rod of length 1.04 m and negligible mass. the acceleration of gravity is 9.8 m/s 2 . v v/2 m l what is the minimum value of v such that the pendulum bob will barely swing through a complete vertical circle? answer in units of m/s.

Answers

The minimum value of v for the pendulum bob to barely swing through a complete vertical circle is approximately 6.27 m/s.

To determine the minimum value of v, we need to consider the energy conservation principle. When the bullet passes through the pendulum bob, there is a transfer of kinetic energy. Initially, the bullet has kinetic energy given by (1/2)mv², where m is the mass of the bullet and v is its speed. After passing through the bob, the bullet emerges with a speed of v/2, so its kinetic energy is now (1/2)m(v/2)². The energy transferred to the bob is the difference between these two kinetic energies.

This energy transferred to the bob is then converted into gravitational potential energy as the bob swings through a vertical circle. At the highest point of the swing, when the bob momentarily comes to rest, all of the initial kinetic energy has been converted into potential energy. Therefore, we can equate the transferred energy to the gravitational potential energy: (1/2)m(v/2)² = mgh, where h is the maximum height of the swing.

By substituting the given values, solving for v, and considering that h = 2L (twice the length of the rod), where L is the length of the rod, we can find the minimum value of v to be approximately 6.27 m/s.

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Light is energy that we can see. It travels through space as waves. The picture
below shows how light can be changed from traveling in a straight line. Which
description accurately tells what is happening in the picture?
a) The light from the pencil is being refracted as it travels
from air to water
b) The light from the pencil is being reflected as it bounces
off the cup
C) The light from the pencil is being diffused as it scatters
around the water

Answers

The light from the pencil is being refracted as it travels from air to water.

option A.

What is electromagnetic wave?

An electromagnetic wave is a type of wave that do not require material medium for its propagation.

These waves are characterized by their frequency, wavelength, and amplitude.

Examples of electromagnetic waves include;

radio waves microwaves infrared radiationvisible lightultraviolet radiationX-rays gamma rays

So light is an example of electromagnetic wave and it undergoes refraction, or bending when it hits an obstacle.

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A rock climber is about to haul up 100 N (about 22.5 pounds)
A rock climber is about to haul up 100 N (about 22.5 pounds) of equipment that has been hanging beneath her on 40 meters of rope that weighs 0.8 newtons per meter. How much work will it take?

Answers

8000 Joules is the amount of work required to haul up the equipment.

Work to haul equipment?

To calculate the work required to haul up the equipment, we need to consider two components: the work done against gravity and the work done against the weight of the rope.

Work against gravity:

The force due to gravity is given by the weight of the equipment, which is 100 N. The distance over which the force is applied is the height the equipment is being hauled, which is 40 meters. The work done against gravity can be calculated using the formula:

Work = Force × Distance

Work against gravity = 100 N × 40 m = 4000 N·m or 4000 J (Joules)

Work against the weight of the rope:

The weight of the rope can be calculated by multiplying the weight per meter (0.8 N/m) by the length of the rope (40 m):

Weight of the rope = 0.8 N/m × 40 m = 32 N

Since the rope is being hauled up, the work done against the weight of the rope is the same as the work done against gravity. Therefore, the work against the weight of the rope is also 4000 J.

The total work required to haul up the equipment is the sum of the work against gravity and the work against the weight of the rope:

Total work = Work against gravity + Work against rope weight

Total work = 4000 J + 4000 J

Total work = 8000 J

Therefore, it will take 8000 Joules of work to haul up the equipme

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500 g of water at 90°C is cooled in a freezer. If all the water is converted to ice, what is the amount of heat released when the water is cooled to a temperature of 0°C and becomes ice?

[Specific heat capacity of water = 4200 J kg^-1 °C^-1, specific latent heat of fusion of ice = 3.34 × 10^5 J kg^-1]


*can u show me how u get the answer? the answer must be 356000 J​

Answers

Answer:

356 000 J

Explanation:

Total Energy released

= Energy released when water cools to 0 + Energy released when water is converted to ice at 0

= mcT + ml

= (0.5)(4200)(90-0) + (0.5)(334 000)

= 189 000 J + 167 000 J

= 356 000 J

Which is true? if the angle between them is smaller than that given by Rayleigh's criterion. Two objects are resolvable Two objects are resolvable if the angle between them is equal to that given by Rayleigh's criterion. O Two objects are resolvable if the angle between them is greater than that given by Rayleigh's criterion.

Answers

The correct statement is: Two objects are resolvable if the angle between them is smaller than that given by Rayleigh's criterion.

Rayleigh's criterion, also known as the Rayleigh criterion of resolution, provides a criterion for determining the minimum angle at which two objects can be resolved as separate entities in an optical system, such as a telescope. According to Rayleigh's criterion, two point sources are just resolvable if the central maximum of the diffraction pattern produced by one source coincides with the first minimum of the diffraction pattern produced by the other source.

In practical terms, this means that if the angle between the objects is smaller than the angle determined by Rayleigh's criterion, they will appear as separate and distinct objects. On the other hand, if the angle between the objects is equal to or greater than the angle given by Rayleigh's criterion, they will blend together and cannot be resolved as separate entities.

Therefore, for two objects to be resolvable, the angle between them must be smaller than the angle specified by Rayleigh's criterion. This criterion defines the limit of resolution and is influenced by factors such as the wavelength of light and the aperture size of the optical system.

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The equation of a wave is represented by: Y = 0.005sin 2π(0.5x – 200t) where x and y are in meters and t in seconds. Find its i. Amplitude ii. Angular speed iii. Frequency iv. Period v. Wave number vi. Wavelength vii. speed.

Answers

Answer:

See solution below

Explanation:

The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)

A is the amplitude

λ is the wavelength

f is the frequency

t is the time

Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)

i) A = 0.005m

Amplitude is 0.005m

ii) ω = 2πf

ω = 2π(200)

ω = 400π rad/s

iii) ω = 2πf

400π = 2πf

200 = f

Swap

f = 200Hertz

iv) Period = 1/f

Period = 1/200

Period = 0.005secs

v) wave number  =

vi) Wavelength λ

0.5x = x/λ

0.5 = 1/λ

λ  = 1/0.5

λ = 2m

vii) velocity - fλ

velocity = 200 * 2

velocity = 400m/s

__________ receptors detect presence of acids in substances, whereas __________ receptors detect sodium in substances. a. sour . . . salt b. sweet . . . bitter c. bitter . . . salt d. sweet . . . sour please select the best answer from the choices provided a b c d

Answers

The correct option is A.

Sour receptors help in the detection of the presence of acids in substances, whereas salt receptors help in the detection of sodium in substances.

A sour type of taste is considered as a quality of primary task that makes an innate rejection type of response in humans as well as in many other animals. Generally, Acidic stimuli are certain unique sources of a sour taste as whenever a  rejection response might serve a discouragement of ingestion of foods which is spoiled by microorganisms that produce acids. The mechanisms by which an acid excites receptor cells of taste (TRCs) are actually complicated by the variability of wide species and are within species that are apparently different kinds of mechanisms for the case of strong and weak acids in substances.

The presence of epithelial sodium channels mediates the mechanism of salt taste. Usually, these receptors are open, and whenever foods are ingested with a high concentration of salt, sodium starts to flow into the cell which causes depolarization. This change occuring in the membrane potential then opens to voltage-gated sodium as well as calcium channels. The calcium influx is in an increased state that causes releasing of serotonin which is filled by vesicles. The serotonin aids in the acting of afferent taste as by axon which causes depolarization and action potentials.

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Love waves are a type of surface wave. they are similar to s waves in that they?

Answers

S-wave motion is identical to that of love waves, but there is no vertical displacement. In a horizontal plane and at a right angle to the direction of propagation, they cause the ground to move side to side.

After British mathematician A. E. H. Love, who developed the mathematical model for this wave type in 1911, one type of surface wave is known as a Love wave. Motion is only horizontal in a love wave. Love waves are horizontally polarized surface waves in the field of elastic dynamics, and they are named after Augustus Edward Hough Love. The interference of numerous shear waves (S-waves), which are guided by an elastic layer and joined to an elastic half space on one side while encroaching on a vacuum on the other, results in the Love wave.

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A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c

Answers

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Stopping distance of vehicles When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity (v0) and the braking capacity, or deceleration that is caused by braking. A car travelling at speed 72km/hr suddenly applies the brake with the deceleration of 5m/s2. Find the stopping distance of the car.

Answers

Answer:

Stopping distance = 40m

Explanation:

Given the following :

Initial speed of vehicle before applying brakes = 72km/hr

Converting km/hr to m/s:

72km/hr = [(72 * 1000)m] / (60 * 60)

72km/hr = 72,000m / 3600s

72km/hr = 20m/s

Deceleration after applying brakes (-a) (negative acceleration) = - 5m/s^2

From the 3rd equation of motion:

v^2 = u^2 + 2as

Where v = final Velocity ; u= Initial Velocity ; a = acceleration and s = distance

Final velocity when the car stops will be 0

Therefore ;

v^2 = u^2 + 2as

0 = 20^2 + 2(-5)(s)

0 = 400 - 10s

10s = 400

s = 400/10

s = 40m

Therefore, the stopping distance of the car = 40 meters

A 2 kg object is moving to the right with a speed of 1 m/s when it experiences an impulse of 4 ns.

Answers

The object's velocity after the force ends equals 3.0 m/s, moving to the right.

Velocity is described as a vector measurement of the charge and path of motion. Placed truly, speed is the velocity at which something moves in one course. The velocity of an automobile travelling north on a chief parkway and the velocity of a rocket launching into the area can each be measured using speed.

The distinctive styles of velocities are uniform speed, variable velocity, common pace and immediate pace. Uniform velocity: A body is stated to be shifting with uniform speed if its average pace among any two factors along its course is equal in importance as well as path.

The SI unit of velocity is metre per/sec (m/s). as an alternative, the speed magnitude can also be expressed in centimetres per 2nd (cm/s).

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How tightly packed molecules (particles) are packed in a solid, liquid or gas is the
weight
volume
density

Answers

Answer:

I believe it's the weight

Explanation:

I believe it’s the density
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7. Navy use SONAR method to locate the position of submarine under water. The waves used in SONAR are A transverse waves. B electromagnetic waves. C. audible to human ear. D.audible to navy only.​

Answers

Answer:

A. transverse waves

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A weight lifter does 2940 J of work to lift a 150kg barbell over his head. If he does so in 5 seconds, how much power did he exert?

A weight lifter does 2940 J of work to lift a 150kg barbell over his head. If he does so in 5 seconds,

Answers

Explanation:

W = 2940 J

m = 150 kg

t = 5 s

find P =?

P = W/t = 2940/5 = 588 watts

Power Is how much you need to work for every second, power formula is:

\(\huge \boxed{ {\sf P = \frac{W}{t} }}\)

With:

P = Power (watts)

W = Work (joule)

t = times (secon)

_________

Data Given:

Work = 2940 Joule

t = 5 Second

______

Power = ?

______

Answer:

= W/t

= 2940/5

= 2940 ÷ 5

= 588 Watts

The Power he exert is 588 watts

Will give brainiest if right

Will give brainiest if right

Answers

Answer:

acceleration at first = \(\frac{2-0}{6-2}\) = 0.5m/s^2 at 2-6 seconds at

2-5 s = \(\frac{1.5-0}{5-2}\) = 0.5m/s^2

            displacement

0-2 s = 0 m

2-6 s = 2m/s x 4s = 8m

6-7 s = 2m/s x1s = 2m

total displacement= 10m

Explanation:

Which of the following situations will not generate stress?
a.
Driving in traffic
b.
Sleeping
c.
Opening a birthday present
d.
Watching a soap opera

Answers

B sleeping because your body is allowed to relax and when you fall asleep everything slows down including your heart rate (that is why sometimes you will just randomly wake up in the middle of the night because your heart rate is very low)

Answer:

Sleeping

Explanation:

Driving in traffic is stressful because you may be late for wherever you are going,

Opening a birthday present is stressful because you don't know what is inside until you open it.

Watching a soap opera is stressful because you do not know what will happen next,

Sleeping is not stressful as long as you don't bring stressful topics to bed.

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