Answer:
\(v'=v_2-v_1=5\frac{km}{h}\)
Explanation:
The relative speed between the trains is given by:
\(v'=v_2-v_1\)
v1: speed of the first train
v2: speed of the second train
To find the relative velocity you write the equation of motion of both train by taking into account the information of the statement. The trains have constant velocity. Furthermore, the second train stars 10 km behind the other one. hence you have:
\(x=10+v_1t\\\\x=v_2t\)
for t = 2 hours, the positions of both trains are equal, thus you have:
\(10+v_1t=v_2t\)
you factor v2 - v1 from the last equation and replace t = 2h:
\(10=v_2t-v_1t\\\\10=(v_2-v_1)t\\\\v_2-v_1=\frac{10}{t}=\frac{10}{2}=5 \frac{km}{h}\)
Hence, you have that the relative velocity is:
\(v'=v_2-v_1=5\frac{km}{h}\)
Why does temperature increase when heat is lost?
Answer:
Since kinetic energy is one of the forms of internal energy, the release of heat from an object causes a decrease in the average kinetic energy of its particles. This means that the particles move more sluggishly and the temperature of the object decreases.
Explanation:
A box of mass 60 kg is at rest on a horizontal floor that has a static coefficient of friction of 0.6 and a kinetic coefficient of 0.25
a)The minimum force necessary to start moving the box
b) The friction force and the acceleration of the box if a horizontal force of 400 N is applied
Answer:
a) F = 353.2 N
b) \(F_{f} = 147.2 N \)
a = 4.21 m/s²
Explanation:
a) The minimum force necessary to start moving the box s given by:
\(\Sigma F = 0\)
\( F - \mu_{s}N = 0 \)
\( F = \mu_{s}mg \)
Where:
F: is the force applied to move the box
μs: is the static coefficient of friction = 0.6
m: is the mass = 60 kg
g: is the gravity = 9.81 m/s²
\( F = 0.6*60 kg*9.81 m/s^{2} = 353.2 N \)
b) The acceleration is:
\( F - F_{f} = ma \)
\( F - \mu_{k}mg = ma \)
\( a = \frac{F - \mu_{k}mg}{m} = \frac{400 N - 0.25*60 kg*9.81 m/s^{2}}{60 kg} = 4.21 m/s^{2} \)
Now, the friction force is:
\( F_{f} = \mu_{k}mg = 0.25*60 kg*9.81 m/s^{2} = 147.2 N \)
I hope it helps you!
Name three other objects around you now that are displaying a balanced force
Answer:
Examples of balanced forces
Resting against a wall.
Lying down.
Aircraft in a steady-flight.
Floating in water.
Standing in ground.
Tug of war equally balanced teams.
Fruit hanging from a tree.
Ball hanging from a rope.
At what conditions acceleration of a body is zero?
Answer:
when there is uniform velocity the acceleration of a body is zero
Marco is playing around with blurring what is behind and in front of the main subjects in his photographs. What kind of effect or feeling might this create? A. a sense of texture and contrast among the different elements B. an excess of tension and confusion with the different elements C. a line of perfect symmetry D. a monotonous and calming effect
Blurring the background and foreground of the main subjects in photographs can create a calming effect, option D.
In what type of photography is the technique of blurring is commonly used?This technique is often used in portrait photography to make the subject stand out and appear more prominent. By blurring the surrounding elements, the viewer's focus is drawn towards the subject, creating a sense of serenity and isolation. This effect is particularly effective when the background and foreground are busy or distracting. However, it is important to note that the impact of this technique on the viewer can also depend on the specific composition and context of the photograph. Blurring the background and foreground is not likely to create a monotonous and calming effect (option D), as the blurred elements can still convey a sense of movement or depth, which can be visually engaging.
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The brakes are not used like an on/off switch because:
A. Engine revolutions per minute are affected
B. The brake light will not come on
C. Brake damage could occur
D. The wheels could lock up
The brakes are not used like an on/off switch because the wheels could lock up.Option D correctly identifies the consequence of using the brakes as an on/off switch.
If the brakes are abruptly applied and released without proper modulation, there is a risk of the wheels locking up. This can lead to a loss of control over the vehicle and potentially result in skidding or accidents.
Proper braking technique involves gradual and controlled application of the brakes, allowing for the transfer of weight to the front wheels and gradual deceleration. This allows the tires to maintain traction with the road surface and ensures stability during braking.
Options A, B, and C are not the primary reasons why the brakes should not be used like an on/off switch. While excessive and abrupt braking can affect engine RPM (Option A), it is not the main concern. The brake light (Option B) is a safety feature that indicates when the brakes are applied, but it is not the primary reason for avoiding on/off switching. Brake damage (Option C) can occur with excessive heat buildup due to prolonged and aggressive braking, but it is not directly related to the on/off switching behavior described in the question.
Overall, the main reason to avoid using the brakes like an on/off switch is to prevent the wheels from locking up, which ensures safer and more controlled braking.
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Question 7 (1 point)
What is the momentum of a 2400-kg truck traveling at 10 meters per second, due east?
Answer:
24000 kg*m/s
Explanation:
Given
Mass= 2400-kg
Velocity= 10m/s
We know that
Momentum
P=mv
subsitute
P=2400*10
P= 24000 kg*m/s
Hence the momentum is 24000 kg*m/s
sonet’s extraordinary ____ results from its use of a double-ring topology over fiber-optic cable.
SONET, or Synchronous Optical Network, is a high-speed communication technology used for transmitting large volumes of data over fiber-optic cables. SONET's extraordinary performance results from its use of a double-ring topology, which provides a high level of redundancy and fault tolerance.
In a double-ring topology, two separate rings are formed, with data being transmitted in opposite directions on each ring. This redundancy ensures that if one ring is broken or damaged, data can still be transmitted through the other ring, ensuring uninterrupted communication.
Additionally, SONET uses fiber-optic cables, which have a much higher bandwidth than traditional copper cables, enabling faster data transmission rates. The use of fiber-optic cables also ensures that data is transmitted over long distances without any loss of signal strength, making it ideal for long-haul communication.
Overall, SONET's extraordinary results are due to its combination of a double-ring topology and fiber-optic cables, which provide a high level of reliability, fault tolerance, and fast data transmission rates, making it a popular choice for high-speed data communication networks.
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With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another
The speed of the car at the bottom of the hill is obtained as, \(v = \sqrt{2gh}\)
According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.
\(K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}\)
where;
v is the speed of the car at the bottom of the hillh is the height of the hillg is acceleration due to gravityThus, the speed of the car at the bottom of the hill is obtained as, \(v = \sqrt{2gh}\)
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According to eq. 6. 134, the x-velocity in fully developed laminar flow between parallel plates is given by u = 1 2μ ( ∂p ∂x) (y2 − h2) the y-velocity is υ = 0. Determine the volumetric strain rate, the vorticity, and the rate of angular deformation. What is the shear stress at the plate surface?
The volumetric strain rate is zero, the vorticity is -1/2μ (∂p/∂x) y, the rate of angular deformation is 1/2μ (∂p/∂x) y, and the shear stress at the plate surface is -1/2 (∂p/∂x) \(h^2\).
Given:
x-velocity: u = 1/2μ (∂p/∂x) (\(y^2 - h^2\))
y-velocity: υ = 0 (no variation in y-direction)
where,
μ = dynamic viscosity
p = pressure
x, y = coordinates
h = distance between the plates
To determine the volumetric strain rate, we can start by considering the continuity equation for incompressible flow, which states that the product of velocity and cross-sectional area is constant:
u × (h-y) = Q/A
where A is the cross-sectional area and Q is the volumetric flow rate.
Taking the derivative of both sides with respect to time and simplifying, we get:
dQ/dt = -u × dA/dy
Since the y-velocity is zero, we have dA/dy = 0, so:
dQ/dt = 0
This means that the volumetric flow rate is constant and there is no change in volume with time. Therefore, the volumetric strain rate is zero.
The velocity vector's curl is used to define the vorticity.
ω = ∇ x v
where ∇ is the del operator. For two-dimensional flow, the vorticity is a scalar and can be expressed as:
ω = (∂υ/∂x) - (∂u/∂y)
Substituting the given values for u and υ, we get
ω = 0 - (∂/∂y)[1/2μ (∂p/∂x) (\(y^2 - h^2\))]
Simplifying and integrating with respect to y, we get:
ω = -1/2μ (∂p/∂x) y
The formula for angular deformation rate is:
D = (∂u/∂y + ∂υ/∂x) = ∂u/∂y
Substituting the given value for u, we get:
D = (∂/∂y)[1/2μ (∂p/∂x) \((y^2 - h^2)\)]
Simplifying and integrating with respect to y, we get:
D = 1/2μ (∂p/∂x) y
To find the shear stress at the plate surface, we can use the following relation:
τ = μ (∂u/∂y)|y=h
Substituting the given value for u, we get:
τ = μ (∂/∂y)[1/2μ (∂p/∂x) (\(y^2 - h^2\))]|y=h
Simplifying, we get:
τ = -1/2 (∂p/∂x) \(h^2\)
Therefore, the volumetric strain rate is zero, the vorticity is -1/2μ (∂p/∂x) y, the rate of angular deformation is 1/2μ (∂p/∂x) y, and the shear stress at the plate surface is -1/2 (∂p/∂x) \(h^2\).
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Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of both objects was tripled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?
Answer:
The new force of attraction would be 36 units
Explanation:
Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
This statement can be expressed with the formula:
\(\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\)
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: \(6.67\cdot 10^{-11}~Nw*m^2/Kg^2\)
Now suppose two given objects attract with a force of F=16 units, thus:
\(\displaystyle G{\frac {m_{1}m_{2}}{r^{2}}}=16\)
And now the masses of both objects is tripled, i.e., m1'=3m1, m2'=3m2, and the distance between them is doubled, r'=2r. The new force is:
\(\displaystyle F'=G{\frac {3m_{1}3m_{2}}{(2r)^{2}}}\)
Operating:
\(\displaystyle F'=G{\frac {9m_{1}m_{2}}{4r^{2}}}\)
\(\displaystyle F'=\frac{9}{4}G{\frac {m_{1}m_{2}}{r^{2}}}\)
Substituting the value of the initial force:
\(\displaystyle F'=\frac{9}{4}\cdot 16\)
\(F'=36\ units\)
The new force of attraction would be 36 units
Use the following terms to create a concept map: gravity, free fall, terminal velocity, projectile motion, air resistance.
Answer :Gravity is the force that attracts two objects towards each other; when an object falls under the influence of gravity alone, it is said to be in free fall and will accelerate at a constant rate; as the velocity of a falling object increases, air resistance will begin to slow it down until it reaches terminal velocity; when an object is thrown or launched, it follows a curved path known as projectile motion which is influenced by both gravity and air resistance.
A uniform cylinder of radius R, mass M, and length L rotates freely about a horizontal axis parallel and tangent to the cylinder, as shown below. The moment of inertia of the cylinder about its symmetrical axis is Icm=MR2/2. The moment of inertia of the cylinder about this axis is
A. MR2/2
B. 2MR2/3
C. MR2
D. 3MR2/2
E. 7MR2/5
The moment of inertia of the cylinder about the horizontal axis parallel and tangent to the cylinder is 3MR²/2.
The moment of inertia (Icm) of the cylinder about its symmetrical axis is calculated using the formula MR^2/2, where M represents the mass of the cylinder and R represents its radius.
To find the moment of inertia of the cylinder about the axis parallel and tangent to the cylinder, we can use the parallel axis theorem. According to the parallel axis theorem, the moment of inertia about an axis parallel to and at a distance 'd' from the axis passing through the center of mass is given by:
I = Icm + Md^2
In this case, the axis of rotation is parallel and tangent to the cylinder, so the distance 'd' from the axis passing through the center of mass is equal to the radius 'R'. Substituting the values into the equation:
I = Icm + MR^2
I = MR^2/2 + MR^2
I = (1/2 + 1)MR^2
I = (3/2)MR^2
Therefore, the moment of inertia of the cylinder about the given axis is (3/2)MR^2.
The correct answer is (D) 3MR^2/2.
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the total charge on each plate and the separation between the plated is held constant while the area of each plate is doubled. what happens to the electric field between the plates, the potential difference across the plates, ad the stored energy in the capacitor
When the area of each plate is doubled while keeping the charge and separation constant, the electric field decreases, the potential difference remains the same, and the stored energy in the capacitor increases four times.
When the area of each plate of a capacitor is doubled while keeping the total charge on each plate and the separation between the plates constant, the following changes occur:
1. Electric Field: The electric field between the plates decreases. The electric field (E) between the plates of a capacitor is inversely proportional to the area (A) of the plates. As the area is doubled, the electric field is halved, assuming the other factors remain constant.
2. Potential Difference: The potential difference (V) across the plates remains the same. The potential difference across the plates of a capacitor depends on the charge (Q) and the capacitance (C), which is determined by the geometric and material properties of the capacitor. Since the total charge and separation between the plates are held constant, the potential difference remains unchanged.
3. Stored Energy: The stored energy in the capacitor increases four times. The energy stored in a capacitor (U) is directly proportional to the area of the plates (A). When the area is doubled, the stored energy is quadrupled (increases by a factor of four).
Therefore, when the area of each plate is doubled while keeping the charge and separation constant, the electric field decreases, the potential difference remains the same, and the stored energy in the capacitor increases four times.
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A straight wire, 25 m long, is mounted on an airplane flying at 125 m/s. The wire moves in a perpendicular direction through Earth’s magnetic field (B =5.0X10^-5 T). What EMF is induced in the wire
The induced EMF in the wire is 0.15625 volts when the wire moves in a perpendicular direction through Earth’s magnetic field.
What is induced electromotive force?Induced EMF (electromotive force) is a voltage that is produced in a conductor when it is moved through a magnetic field or when there is a change in the magnetic field around the conductor.
The EMF induced in the wire is given by the equation:
EMF = BLv
where B is the strength of the magnetic field, L is the wire length, and v is the velocity of the wire relative to the magnetic field.
Substituting the given values, we get:
EMF = (5.0 x 10⁻⁵ T) * (25 m) * (125 m/s)
EMF = 0.15625 V
The magnitude of the induced EMF depends on the strength of the magnetic field, the speed at which the conductor is moving, and the angle between the magnetic field and the direction of motion of the conductor. This phenomenon is known as electromagnetic induction.
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Alkaline earth metals have a low density
true
false
true
Explanation:
this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons
among the different forms of electromagnetic radiation emitted by the sun, which form is absorbed by plants for photosynthesis? microwaves ultraviolet visible light gamma rays infrared
Visible light , The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.
What is photosynthesis?Photosynthesis is a mechanism used by plants and other living organisms to convert light energy into chemical energy that can then be released through cellular respiration to power the organism's activities.Photosynthesis is the process through which plants turn carbon dioxide, water, and sunlight into oxygen and sugar-based energy.The process through which green plants use sunlight to create their own nourishment is known as photosynthesis. Life on Earth depends on photosynthesis. There would be no green vegetation if it did not exist, and there would be no creatures if it did not exist.Photosynthesis is primarily used to convert solar energy into chemical energy, which is then stored for use at a later time. The majority of the life systems on the planet are powered.To learn more about photosynthesis, refer to:
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Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.
The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.
The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].
Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.
Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).
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A stone is thrown upward from a cliff that is 100.0 meters high. It is thrown straight up in the air with an initial velocity of 15.0m/s. Physics students are required to determine the time it takes a stone to reach the ground below. Which of the following times is the most consistent with this scenario?
A. 1.50 seconds
B. 3.00 seconds
C. 3.22 seconds
D. 6.22 seconds
Physics students are required to determine the time it takes a stone to reach the ground below. The most consistent time with the scenario is 3.22 seconds. So, the correct answer is option C. 3.22 seconds.
When a stone is thrown upward, it follows a parabolic trajectory and eventually falls back down to the ground. The time it takes for the stone to reach the ground can be determined by analyzing its vertical motion.
The stone is thrown upward with an initial velocity of 15.0 m/s. As it moves upward, it slows down due to the force of gravity until it reaches its highest point and starts to fall back down. The total time it takes for the stone to reach the ground is the sum of the time it takes for the stone to reach its highest point and the time it takes to fall from the highest point to the ground.
The time it takes for the stone to reach its highest point can be calculated using the equation:
Time = (Final velocity - Initial velocity) / Acceleration
In this case, the final velocity is 0 m/s because the stone comes to a stop at the highest point. The acceleration is -9.8 \(m/s^2\) (assuming the positive direction is upward and the acceleration due to gravity is negative).
Using the equation, we find that the time it takes for the stone to reach its highest point is approximately 1.53 seconds. Since the stone takes an equal amount of time to fall from its highest point to the ground, the total time is approximately 3.06 seconds.
Among the given options, the most consistent time with this scenario is 3.22 seconds (option C), which is the closest to the calculated value of 3.06 seconds.
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What determines the speed of an electromagnetic wave?.
Hi!The speed of a wave is a product of its wavelength and frequency. Because all electromagnetic waves travel at the same speed through space, a wave with a shorter wavelength must have a higher frequency, and vice versa. This relationship is represented by the equation: Speed = Wavelength × Frequency.
Which of the following statements about developing a personal fitness program is NOT true?
A When developing a personal fitness program, it is important to implement strategies that will help
maintain the program as well as give it a successful start
B. Personal factors such as age, health concerns, and likes are important to consider when developing
a personal fitness program
C. The starting skill level of the physical activities included in a personal fitness program should be
determined from other individuals' fitness programs
D. The FITT principle should be used when developing a personal fitness program,
Please select the best answer from the choices provided
A
B
Save and Exit
Next
Answer:
C
Explanation:
The starting skill level of the physical activities included in a personal fitness program should be determined from other individuals' fitness programs is a statement which is not true. Everyone starts their personal fitness journey at a different level which should be regarded . A fitness test should be taken to determine where an individual should start their new lifestyle.
Answer:
C. I got it right :)
Explanation:
Electrical current is defined as _____.
the strength of the electric field
the movement of charge past a certain point per unit time
the potential of the battery
the conservation of charge
Answer:
the strength of the electric field
A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s
2
untit it reaches a speed of 30.0 m/s. Then the vehicle travels for 37.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the self-driving car in motion (in s)? (b) What is the average velocity of the seif-driving car for the motion described? (Enter the magnitude in m/s.) m/s
The self-driving car is in motion for 57.0 seconds and has an average velocity of approximately 24.74 m/s.
(a) The motion of the self-driving car consists of three parts:
1. Acceleration of the self-driving car from rest to a final velocity
2. Motion of the self-driving car at a constant speed
3. Deceleration of the self-driving car to bring it to a stop
Using the first equation of motion: v = u + at. Here,
initial velocity (u) is 0m/s,
acceleration (a) is 2.00m/s²,
final velocity (v) is 30.0m/s.
Substituting the given values, we get: 30.0 m/s = 0 m/s + (2.00 m/s²)t
(2.00 m/s²)t = 30.0 m/s
t = 30.0/2.00
t = 15.0 s
Hence, the time taken for the car to accelerate from rest to 30.0 m/s is 15.0 seconds. Next, the car travels for 37.0 s at a constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00s.
Therefore, the car is in motion for: 15.0 s + 37.0 s + 5.0 s = 57.0 s
(b) The average velocity of the self-driving car is given by the formula: v_avg = Total displacement / Total time
We know that the car travels a total distance of: d1 = Distance covered during acceleration
d2 = Distance covered at a constant speed
d3 = Distance covered during deceleration
Now, during acceleration, using the third equation of motion, we can calculate the distance covered as:
d1 = ut + 1/2 at². Here, initial velocity (u) is 0m/s, acceleration (a) is 2.00m/s², time (t) is 15.0s.
Substituting the given values, we get d1 = 0 + 1/2 × 2.00 m/s² × (15.0 s)²
d1 = 225.0 m
Similarly, during deceleration, using the third equation of motion, we can calculate the distance covered as:
d3 = ut' + 1/2 a't'². Here, the initial velocity (v) is 30.0m/s, the final velocity is 0 as the car comes to stop, time (t') is 5.00s, and acceleration (a') can be calculated using:
v = u + a't'
0 = 30+ a'x5
a' = -6 m/s² (negative as decelerating)
Substituting the given values, we get:
d3 = 30.0 m/s × 5.00 s + 1/2 × (-6.00 m/s²) × (5.00 s)²
d3 = 75.0 m
Now, distance covered during constant speed: d2 = v × t
Here, speed (v) is 30.0m/s, and time (t) is 37.0s. Substituting the given values, we get: d2 = 30.0 m/s × 37.0 s
= 1110.0 m
Therefore, the total distance covered is d = d1 + d2 + d3
= 225.0 m + 1110.0 m + 75.0 m
= 1410.0 m
Using the formula of average velocity, we get: v_avg = 1410.0 m / 57.0 s
= 24.74 m/s
Thus, the average velocity of the self-driving car for the motion described is 24.74 m/s.
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Order the following objects from smallest to largest, according to their radii.White DwarfStarBlack HoleNeutron Star
Ordering the objects from smallest to largest according to their radii, we have:
1. Black Hole
2. Neutron Star
3. White Dwarf Star
Two components make up black holes. You can see the event horizon as the surface, but it is actually just the location where gravity becomes too powerful for anything to escape. The singularity is then located at the center.
Any member of a class of highly dense, compact stars assumed to be predominantly made of neutrons is a neutron star. The average diameter of a neutron star is 20 km (12 miles).
After using up all of their nuclear fuel, stars like the Sun become white dwarfs. This kind of star expels the majority of its outer material as it nears the conclusion of its nuclear burning cycle, forming a planetary nebula. The star's scorching core is all that is left.
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the impact of a collision at 60 mph is how many times greater than at 30 mph?
Answer:
four times as great
Explanation:
If we use the simple physics equations: F=ma, and (Vf^2-V0^2)/2d
we can see that since the final velocity of a crash is 0, the equation becomes F=m(V^2/2d). Assuming that we have the same distance to stop, when you double the velocity, the impact force is increased by four.
How much net force is required make a 10 kg box accelerate at a rate of 5 m/s2?
O2N
0 50 N
0 15 N
0 100 N
NEED HELP PLEASE ASAP
The energy output of a fan is 36 kWh. The fan is 75% efficient.
How much energy is lost to the surroundings?
12 kWh
36 kWh
48 kWh
84 kWh
Answer:
The energy output of a blender is 1.4 kWh. If the blender is 85% efficient, how much energy is lost to the surroundings?
⇒ 0.25 kWh
A motorcyclist starts from rest and reaches a speed of 6m/s after travelling with constant acceleration for 3s. What is his acceleration?
As given, the motorcyclist starts from rest and reaches a speed of 6 m/s
after traveling with uniform acceleration for 3 seconds.
Here, initial velocity u=0
Final velocity v=6 m/s
Time t=3 sec.
Let the acceleration of the motorcycle be a.
On using the equation of motion, v=u+at
6=0+3×a
Or 3a=6
Or a=63
Or a=2 m/s2
→Therefore, the acceleration in a motorcycle is 2 m/s2.←
How are velocity and force similar?
Answer: Force
In physical science, a force is something that acts on an object by pushing or pulling it. If the force is strong enough, it changes the position or shape of the object. Forces such as friction, air resistance and simple physical contact touch the object directly, while forces like gravity, magnetism and electrostatics act on the object from a distance. Force is a vector quantity, meaning you can measure both its strength and its direction. The formula to find the measure of a force is force = mass times acceleration, written as f = ma.
Velocity
The faster something is moving, the higher its velocity.
When an object is moving, one way to measure how fast it is moving is by finding its velocity, which is the rate at which it is changing position. Like force, velocity is a vector quantity, so it includes direction. To find the average velocity of an object, divide the change in its position by the time the movement took, and state its direction. For example, if a car is driving north and in one hour's time it travels 30 miles, its velocity is 30 miles per hour, north.
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a tungsten and coil has a resistance of 12 ohm at 15 degree celsius is the temperature coefficient of resistance of tungsten is 0.004 calculate the equal resistance at 80 degree Celsius
Answer:
The resistance of the tungsten coil at 80 degrees Celsius is 15.12 ohm
Explanation:
The given parameters are;
The resistance of the tungsten coil at 15 degrees Celsius = 12 ohm
The temperature coefficient of resistance of tungsten = 0.004/°C
The resistance of the tungsten coil at 80 degrees Celsius is found using the following relation;
R₂ = R₁·[1 + α·(t₂ - t₁)]
Where;
R₁ = The resistance at the initial temperature = 12 ohm
R₂ = The resistance of tungsten at the final temperature
t₁ = The initial temperature = 15 degrees Celsius
t₂ = The final temperature = 80 degrees Celsius
α = temperature coefficient of resistance of tungsten = 0.004/°C
Therefore, we have;
R₂ = 12×[1 + 0.004×(80 - 15)] = 15.12 ohm
The resistance of the tungsten coil at 80 degrees Celsius = 15.12 ohm.